Based on the law of conservation of energy, how can we reasonably improve a machine’s ability to do work?

Charge = 0.2 Ah is the correct answer...

Answer:

Explanation:

The Law of Momentum Conservation applies, and the formula for us here specific to this problem is:

[tex][(m_bv_b)+(m_mv_m)]_b=[(m_b+m_m)v_{both}]_a[/tex] and filling in:

[(1.50*4.50)+60.0*0)] = [(1.50 + 60.0)v] and

6.75 + 0 = 61.5v so

v = .110 m/s in the same direction as the ball

Answer:

Explanation:

The formula for this is designed around the fact that momentum must be conserved:

[tex][(m_{ball1}*v_{ball1})+(m_{ball2}*v_{ball2})]_b=[(m_{ball1}+m_{ball2})v_{both}]_a[/tex]

This is because they sitck together after they collide. Filling in:

[(3*10)+(5*2)] = [3 + 5]v and

30 + 10 = 8v so

40 = 8v and

v = 5

They are both moving east at a velocity of 5 m/s since they stuck together.

Answer:

Las estrellas se forman debido a la unión de pequeños elementos y partículas como el hidrógeno y el helio que experimentan una fusión nuclear en el núcleo debido a la intensa presión para formar un nuevo átomo (como dos hidrógeno que se combinan para formar un átomo de helio) que es un proceso. que requiere una gran cantidad de energía para comenzar, por lo que cada reacción de fusión produce una gran cantidad de energía que puede mantener la reacción y equilibra la fuerza gravitacional que atrae las masas de las partículas hacia el centro de la estrella

A medida que la energía de la estrella se irradia, la superficie de la estrella cede la energía en forma de calor y luz de manera que debido a la alta temperatura de las partículas de los átomos de los elementos se mueven muy rápida y energéticamente para emitir fotones rápidamente. (alta frecuencia) que se ve como el alto brillo de la estrella

Explanation:

Answer:

The net force acting on the car is zero.

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 350 Kg

Velocity (v) = constant = 15 m/s

Net Force (F) =?

An object moving with a constant velocity is not accelerating. The acceleration of such object is zero. Thus, the net force acting on the object is also zero. This can further be explained as shown below:

Mass (m) = 350 Kg

Acceleration = 0 (since the velocity is constant)

Net Force (F) =?

Force (F) = mass (m) × Acceleration (a)

F = m × a

F = 350 × 0

F = 0

Thus, the net force acting on the car is zero.

Answer:

[tex]momentum = mass \times velocity \\ = 7.5 \times 1.6 \\ = 12 \: kg {ms}^{ - 1} [/tex]

Mass is 7.5 kg

Velocity is 1.6 m/s

we know that,

momentum = mass × velocity

or; momentum =7. 5 kg × 1. 6 m/s

or; momentum = 12 kgms^1

For 1000 seconds , a current of 0.1 A flows so as to transfer charge of 100C

Answer:

718.02N is the answer to the question

Answer:

A

Explanation:

moving a magnet into a coil of wire in a closed circuit

Craig, move a magnet into a coil of wire in a closed circuit for the discovery of electromagnetism. Option A is correct.

The physical interplay of electric charges, magnetic moments, and the electromagnetic field is known as electromagnetism.

The electromagnetic field can be static, moving slowly, or forming waves.

Craig, move a magnet into a coil of wire in a closed circuit for the discovery of electromagnetism.

Hence, option A is correct.

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Answer:

DONORS: If the material for which it substitutes has more electrons than the original

ACCEPTORS: If the replacement material has fewer electrons than the original material

Fermi level: the point where the probability of finding the last electron is ½

Explanation:

When in a semiconductor material a small fraction of an element is replaced by another with different valences, an excess charge is created.

If the material for which it substitutes has more electrons than the original, there is an excess of electrons, these excess electrons are weakly bound in the material and their orbits are large, in an energy versus moment diagram their energy places them a little more below the conduction band, these materials are called DONORS.

If the replacement material has fewer electrons than the original material, one electron is missing to complete the bonds, so there is a movement of the other electrons, an easier way to analyze this movement of the (n-1) electrons is to suppose that The missing charge has a positive charge and to study its movement, this positive charge is called a hole, its binding energy is small so the orbit of the hole is large, in an energy diagram it is located a little above the band of valence, these are called ACCEPTORS

The Fermi level is defined as the point where the probability of finding the last electron is ½, when the temperature is changed the density of states of the bands changes, therefore the location point moves, but its [probability remains ½

Answer:

The horizontal component of the vector is approximately -16.07

The vertical component of the vector is approximately 19.15

Explanation:

A vector quantity is a quantity that posses both magnitude and direction specifications

The magnitude of the given vector, R = 25 units

The direction of the vector, θ = 130°

Therefore the location of the vector, starting from the origin of the Cartesian plane, is in the second quadrant having an angle of 180° - 130° = 50° to the horizontal

Given that the x-coordinate  is negative in the second quadrant, we have;

The horizontal component of the vector, Rₓ = The x-coordinate of the vector = R×cos(θ)

∴ The horizontal component of the vector, Rₓ = 25 × cos(130°) = -25 × cos(50°) ≈ -16.07

The horizontal component of the vector, Rₓ ≈ -16.07

The vertical component of the vector, [tex]R_y[/tex] = The y-coordinate of the vector = R×sin(θ)

∴ The vertical component of the vector, [tex]R_y[/tex] = 25 × sin(130°) ≈ 19.15

The vertical component of the vector, [tex]R_y[/tex] ≈ 19.15

The vector can be resolved as R = -16.07·i + 19.15·j

Answer:

The horizontal component of the vector ≈ -16.06

The vertical component of the vector ≈ 19.15

Explanation:

The magnitude of the vector, [tex]\left | R \right |[/tex] = 25 units

The direction of the vector, θ = 130°

Therefore, we have;

The horizontal component of the vector, Rₓ = [tex]\left | R \right |[/tex] × cos(θ)

∴ Rₓ = 25 × cos(130°) ≈ -16.06

The horizontal component of the vector, Rₓ ≈ -16.06

The vertical component of the vector, R[tex]_y[/tex] = [tex]\left | R \right |[/tex] × sin(θ)

∴  R[tex]_y[/tex] = 25 × sin(130°) ≈ 19.15

The vertical component of the vector, R[tex]_y[/tex] ≈ 19.15

(The vector, R = Rₓ + R[tex]_y[/tex]

[tex]\underset{R}{\rightarrow}[/tex] = Rₓ·i + R[tex]_y[/tex]·j

∴ [tex]\underset{R}{\rightarrow}[/tex] ≈ -16.07·i + 19.15j)

Answer:

12.0 Volt

Explanation:

Step 1: Given data

Resistance of the ohmic dipole (R): 100 Ohm

Intensity of current (I): 120 mA (0.120 A)

Step 2: Calculate the voltage (V) across this chemical dipole

To calculate the voltage across the ohmic dipole, we will use Ohm's law.

I = V/R

V = I × R

V = 0.120 A × 100 Ohm = 12.0 V

Answer:

C. Electromagnetic wave

Explanation:

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Answer:

C. electromagnetic

Explanation:

because 5g uses higher frequency radio waves a type of electromagnetic radiation which are within the spectrum considered safe.

Answer:a gas at pressure of 0.8 m column of H g

Answer:

Yes, but only if it's sunny.

Explanation:

As you know, solar panels generate energy through the sun's rays of light (better known as sunlight). Therefore, as long as the sun is shining high in the sky, the car will generate electricity and be able to function. If this vehicle was only powered by solar panels, it would not function during the night, in cloudy areas, and/or in dark places (such as parking garages or home garages).

Hope this helps!

The power required to do 180 J of work in 2.4 s is 75 W.

Power can be defined as the rate at which work is done.

To calculate the power, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the power required to do 180 J of work in 2.4 s is 75 W.

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Answer:

Power = 1800 W

Explanation:

Power = work / time

Power = 4500 / 2.5

Power = 1800 W

The magnitude of the frictional force working on the box is 14 N.

According to Newtons's first law, an object will continue in its state of rest or state of uniform motion unless it is acted upon by an unbalanced force. This means that motion or acceleration is caused by an unbalanced force.

Since the box is moving at constant velocity, the frictional force on the box and the force that moves the box forward are exactly equal in magnitude but opposite in direction.

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Answer:

a. 6.5 × 10⁴ mmHg

b. 5.9 × 10⁻⁴ atm

c. 1.0 × 10⁵ Pa

d. 0.97 atm

Explanation:

Transformaremos las siguientes unidades utilizando factores de conversión.

a. 85 atm a mmHg

Usaremos el factor de conversion 1 atm = 760 mmHg.

85 atm × 760 mmHg/1 atm = 6.5 × 10⁴ mmHg

b. 60 Pa a atm

Usaremos el factor de conversion 1 atm = 101325 Pa.

60 Pa × 1 atm/101325 Pa = 5.9 × 10⁻⁴ atm

c. 780 mmHg a Pa

Usaremos el factor de conversion 760 mmHg = 101325 Pa.

780 mmHg × 101325 Pa/760 mmHg = 1.0 × 10⁵ Pa

d. 740 mmHg a atm

Usaremos el factor de conversion 1 atm = 760 mmHg.

740 mmHg × 1 atm/760 mmHg = 0.97 atm

Answer:

elastic collision

Explanation:

Answer:

A

Explanation:

Answer:

[tex]x = 2\sqrt 2[/tex]

Explanation:

Given

[tex]Hypotenuse = 4[/tex]

Required

Find x

Since the triangle is a 45-45-90 triangle, the following relationship exists

[tex]x^2 + x^2 = 4^2[/tex] --- i.e. the other legs are equal

So, we have:

[tex]2x^2 = 16[/tex]

Divide both sides by 2

[tex]x^2=8[/tex]

Take square roots of both sides

[tex]x = \sqrt 8[/tex]

Simplify

[tex]x = 2\sqrt 2[/tex]

Answer:

7√2

Explanation:

Answer:

[tex]V=0.512\ m^3[/tex]

Explanation:

Given that,

The side of a cubic box, s = 0.8 m

We need to find the volume of air in the box.

We know that,

The volume of a cube is given by :

[tex]V=s^3[/tex]

So,

[tex]V=0.8^3\\\\V=0.8\times 0.8\times 0.8\\\\=0.512\ m^3[/tex]

So, the volume of air in the box is [tex]0.512\ m^3[/tex].

Answer:

For Ryan:

[tex]at \: highest \: point : v = 0 \\ velocity = 0 \: {ms}^{ - 1} [/tex]

For the football kicked:

[tex]s = ut - \frac{1}{2} g {t}^{2} \\ for \: range : s = 0 \\ u \sin( \theta) = \frac{gt}{2} \\ t = \frac{2u \sin(\theta) }{g} \\ range(x) = ut \\ x = \frac{ {2u {}^{2} \sin(\theta) }^{} }{g} \\ \frac{50 \times 9.8}{ {2318.9}^{} } = \sin(\theta) \\ \\but \: 0 = u \sin(25) - 2 \times 9.8 \times 50 \\ u = 2318.9 \: {ms}^{ - 1} \\ \theta = 12.2 \degree[/tex]

Answer:

the highest point for the first question is 0 meters per second

the answer for question 2 is 45 degrees

Explanation:

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Answer:

Some galaxies are given descriptive names (e.g. "Andromeda", "Whirlpool") if they are particularly distinctive in location or appearance. But most galaxies are known from their designation in a catalogue. One of the earliest catalogues of objects in the sky was made by Charles Messier.

4.9 eV is the correct answer

Hope it helps you ^ _ ^

Answer:

Explanation:

Work done = Force * Displacement

There is no displacement vertical so only the horizontal part of force did work.

The horizontal force = Force * cos(angle with floor)

Work done = 40*cos(40°)*2

= 61.28 J

As cos(65°) is less than cos(40°), work done will be less at 65°.