Graph: y
2 + 5
y
X
y
8
6
4
2.
x
-4
-2.
2
4.
6
8
-2
-4
Draw
Click or tap the graph to plot a point.

Explanation:

We have 2 rows and 3 columns, which directly leads to the answer 2 x 3

Always list the number of rows first, followed by the number of columns.

Answer:

Its 3x2

I swear I just took the test

Step-by-step explanation:

[tex]( \sqrt{2} + 1)(5 + \sqrt{2}) \\ = \sqrt{2} (5 + \sqrt{2} ) + 1(5 + \sqrt{2} ) \\ = 5 \sqrt{2} + 2 + 5 + \sqrt{2} \\ = 7 + 6 \sqrt{2} [/tex]

7 + 6√2

Answer:

[tex]\huge\boxed{\sf 7 + 6\sqrt{2}}[/tex]

Step-by-step explanation:

[tex](\sqrt{2} +1)(5+\sqrt{2} )\\\\= \sqrt{2} (5+\sqrt{2} )+1(5+\sqrt{2} )\\\\= 5\sqrt{2} + (\sqrt{2})^2+5+\sqrt{2} \\\\= 5\sqrt{2} + 2 + 5 + \sqrt{2} \\\\= 2+5+\sqrt{2} + 5\sqrt{2} \\\\= 7 + \sqrt{2} (1+5)\\\\= 7 + 6\sqrt{2} \\\\\rule[225]{225}{2}[/tex]

Hope this helped!

Answer:

Given that (x-3) (Ax²+bx+c) = x³-7x-6, find the value of A, B and C

Given that (x-3) (Ax²+bx+c) = x³-7x-6, find the value of A, B and C

Answer:

Many mathematical operations are reversible, meaning you can go not just from A to B, but by the same reason go from B back to A.

Example x + 4 = 7. Subtract 4 from each side to get x = 7 - 4 = 3. But you could, if you wished, go from x = 3 to x + 4 = 7 by simply doing the opposite, adding 4.

Now consider an operation that is NOT reversible.

Example: Given sqrt(x) = x - 2. Square each side to get x = (x - 2)^2 =x^2 - 4x + 4, or

x^2 - 5x + 4 = 0. Factoring gives (x - 1) (x - 4) = 0. So, IF the original equation holds for a real number x, then the only possibilities are x = 1, x = 4.

If you plug x = 4 back into original equation, you get sqrt(4) = 4 - 2, which is true. But, if you plug in x = 1, you get sqrt(1) = 1 - 2, which is NOT true, as sqrt(1) = 1, not -1. The logic of the derivation was that, IF original equation were true, then x could possibly be only 1 and/or 4. In effect, it was really telling you what x is NOT, namely any number besides 1 and 4. Once you test the two “candidates” you see that one works and the other doesn’t.

Why does this happen? It has to do with the fact that square root is only a principal branch. Just as sqrt(16) is only 4 and not -4, so we are dealing with a limited possibility with which to start. Squaring glosses over this, and when you solve a quadratic equation, it generally gives two solutions (not nec. real). Because sqrt(x) started out to be nonnegative, that created the problem at end.

Answer:

22/3

Step-by-step explanation:

because it is

Answer:

-1

Step-by-step explanation:

-15-2(-7)

-15+2·7

-15+14

-1

Answer:

I think It would be B lest goooooooo

Answer: a. -3a^3 - 6a^2 + 7a - 13

Step-by-step explanation:

(-8a^2 + 7a - 9) - (3a^3 - 2a^2 + 4)

-3a^3 -6a^2 + 7a - 13

Answer:

1. D

2. E

3. C

Step-by-step explanation:

f(x)=(5x³-x²-3x+9)+(3x²-x-7)-(3x³+x²-4)

f(x)=(5x³-x²-3x+9)+(3x²-x-7)+(-3x³-x²+4)

f(x)=(2x³-x²-3x+9)+(2x²-x-3)

f(x)=2x³+x²-4x+6

1. D (the degree is the largest value of an exponent)

2. E (the constant term is the number without a variable)

3. C (the leading coefficient is the coefficient of the largest variable exponent in the value)

Answer:

b

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

Explanation:

You are probably familiar with the formula [tex]a^2+b^2 = c^2[/tex] which is the pythagorean theorem.

The [tex]a^2[/tex] is the square of the first leg 'a', while [tex]b^2[/tex] is the square of the second leg b. Adding those two squares leads to the square of the hypotenuse c, aka [tex]c^2[/tex]. This only works with right triangles, which are triangles that have a 90 degree angle.

The solution in form of fraction is,

⇒ 8 / 15

We have to given that,

An expression to solve,

⇒ 2/9 divided by 5/12

Now, We can divide the numbers into form of fraction as,

⇒ 2/9 ÷ 5/12

⇒ 2/9 × 12/5

⇒ 24 / 45

⇒ 8 / 15

Therefore, The solution in form of fraction is,

⇒ 8 / 15

Learn more about the fraction visit:

https://brainly.com/question/5454147

#SPJ6

Answer:

answer is

frghhfgyyuu67.5

Answer:

highest 7/8, 0.5, -1/4, -1  1/5 lowest

Answer: i'm not certain but i think its -1 1/5 first then -1/4 next is 0.5 then 7/8

once again not certain but i think that's the answer

Answer:

2z-4

Step-by-step explanation:

Hope that helped! Can I also get brainliest? I need a few more to advance, if not thank you anyways and have a nice day!!!

Answer:

2 − 4 Is the correct answer

Step-by-step explanation:

In pic

(Credits: Symbolab)

(Hope this helps can I pls have brainlist (crown)☺️)

Answer:

20g onions at 50 carrotsat 2tablespoon oil at 30 tomatos 1l vegtable stock

Answer:

Data set: 47, 45, 44, 41, 48

1. Find the mean.

Mean = 47 + 45 + 44 + 41 + 48

5

= 225

5

= 45

2. Find each absolute deviation.

Absolute deviations: 2, 0, 1, 4, 3

What is the mean absolute deviation (MAD) for the data set?

MAD =

Step-by-step explanation:because thats it because yea

Answer:

C.

Step-by-step explanation:

hope this helps♡^.^^_^

Answer:

C

Step-by-step explanation:

-6 is more to the left of the number line than -3

Step-by-step explanation:

(a+b)×h

_______

2

= (12 + 12 ) × 26

= (24) × 26

= 624 ÷2

= 312

Answer:

h(-4) = 32.8

h(0) = 12

h(3.5) = -6.2

Step-by-step explanation:

Answer:

i think 27777777777777/100000000000000

Step-by-step explanation:

Answer:

Convert it to a whole number

Step-by-step explanation:

by multiplying it with 1000000000000

=2.78 x 10 ^ -15

Hello There!

y-y1=m(x-x1)

y-3=5(x+8)

y-3=5x+40

[tex]y=5x+43[/tex]

Hope this helps!

[tex]GraceRosalia[/tex]

Answer:

x=30

Step-by-step explanation:

isolate the numbers that don't contain the variable, then divide the factors that don't contain the variable.

Answer:

x=20

Step-by-step explanation:

Given: x+3+x-8+x=55

Combine like terms: 3x-5=55

Add 5 to the other side: 3x=60

Divide both sides by 3: X=20

Answer:

Terms Are

8 , 16 , 32

5 , 10 ,  15 , 20

3 , 6 , 12

All of them are less than 50.

Step-by-step explanation:

Answer:

The given relation is not a function.

Step-by-step explanation:

A relation is any set of ordered pairs, which can be thought of as (input, output).

A function is a relation in which no two ordered pairs have the same first component (x-values or input) and different second components (y-values or output).

Given the following relation: {(7, 4), (5, - 1), (3, - 8), (1, - 5), (3, 6)}

There is an input value (x = 3) that has two corresponding outputs (y-values): y = -8 and y = 6.  

Remember that a function can only take on one output for each input.

It also helps to do the Vertical Line Test, which allows us to know whether or not a graph is actually a function.  If a vertical line intersects the graph in all places at exactly one point, then the relation is a function.  To use the vertical-line test, imagine dragging a ruler held vertically across the  graph from left to right. If the graph is that of a function, the edge of the ruler would hit the graph only once for every x -value.

Attached is a screenshot of the plotted points on a graph, where I performed the Vertical Line Test. The green line is the vertical line that contains two points that made the relation invalid as a function.

Please mark my answers as the Brainliest if you find my explanation helpful :)

Answer:

x=-1

Step-by-step explanation:

-10+11+x=0

-11         -11

-10+x=-11

+10         +10

x=-1

Answer:

[tex]\frac{2}{5}[/tex] and [tex]\frac{2}{7}[/tex]

Step-by-step explanation:

We want to work backwards. Currently we have [tex]\frac{ }{ }[/tex][tex]\frac{?}{?}[/tex] ÷ 5 = [tex]\frac{2}{25}[/tex].

If we multiply both sides by 5, we get [tex]\frac{?}{?}[/tex] = [tex]\frac{2}{25}[/tex] × [tex]\frac{5}{1}[/tex].

We can use multiplication of fractions to solve this. To multiply fractions we multiply the two numerators together and multiply the two denominators together, giving an answer of [tex]\frac{?}{?}[/tex] = [tex]\frac{10}{25}[/tex].

This can be simplified to [tex]\frac{2}{5}[/tex].

We can use the same method on the other equation to get an answer of [tex]\frac{2}{7}[/tex].

**This content involves multiplying fractions and questions with the blanks not isolated, which you may wish to practice.