Given the inequality -6 (1 + 2x) ≥ 6 (2x - 1) + 2, which of the following are included in the solution? Select ALL that apply.



Ps. I chose just the answer 0 and only received a 1/3

Answer:

12499

Step-by-step explanation:

because if it would be 12500 it would round up to 13000.

Answer:

false

Step-by-step explanation:

Call the persons 1 through 7.

1,2

1,3

1,4

1,5

1,6

1,7

2,3

2,4

2,5

2,6

2,7

3,4

3,5

3,6

3,7

4,5

4,6

4,7

5,6

5,7

6,7

There are 21 handshakes.

1 handshaking 2 is the same as 2 handshaking 1.

6 × 7/2 = 21

Answer: false

Answer:

( 1 , –3)

Step-by-step explanation:

i hope this answer helped

A to E have an estimated running time of 15, 9, 3, 6, and 12 minutes, respectively. Average turnaround time for a quantum of one minute and four minutes is calculated to be 32.2 minutes and 97.4 minutes respectively.

Turnaround time (TAT) is the period of time between when a process is submitted and when it is finished. It can alternatively be viewed as the total of the times spent waiting to execute on the CPU, waiting in the ready queue or memory, and waiting to execute input or output. An essential parameter for assessing an operating system's scheduling algorithms is turnaround time.

a) For each process the turnaround time is

A= 45 minutes    b= 35 minutes

C= 13 minutes     D= 26 minutes

E= 42 minutes

The average time will be

[tex]\frac{45+35+13+26+42}{5} = 32.2 minutes[/tex]

b) For a quantum of 4 minutes

[tex]\frac{19+31+39+42}{5} = 97.4 minutes\\[/tex]

c) The average turnaround time can be calculated to be

[tex]\frac{9+21+36+39+45}{5} = 30 minutes[/tex]

d)The average turnaround time is

[tex]\frac{15+24+27+33+45}{5} = 28.8 minutes[/tex]

e) The average turnaround time is

[tex]\frac{3+9+18+30+45}{5} = 21 minutes[/tex]

Complete question:

Five batch jobs, A through E, arrive at a computer center at essentially the same time. They have an estimated running time of 15, 9, 3, 6, and 12 minutes, respectively. Their (externally defined) priorities are 6, 3, 7, 9, and 4, respectively, with a lower value corresponding to a higher priority. For each of the following scheduling algorithms, determine the turnaround time for each process and the average turnaround for all jobs. Ignore process switching overhead. Explain how you arrived at your answers. In the last three cases, assume that only one job at a time runs until it finishes and that all jobs are completely processor bound.

a) Round Robin with a quantum of one minute b) Round Robin with a quantum of 4 minutes c) Planning for Priority d) FCFS (running in order 15, 9, 3, 6 and 12) e) Shortest Process Next (SPN)

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Answer:

4m(m+7m) 8(2m+1)

________. x. ______

8(3m+2). 4m(5m-1)

(m+7m). (2m+1)

________. x. ______

(3m+2). (5m-1)

2m2 + 1m + 14m2 + 7m

__________________

15m2 -3m + 10m -2

16m2 + 8m

_________

15m2 + 7m - 2

8m (2m + 1)

__________

(5m - 1) (3m + 2)

Answer:

Step-by-step explanation:

11

Answer:

Step-by-step explanation:

Steps for Solving Linear Equation

−3(2x−4)=18

Divide both sides by −3.

2x−4=

−3

18

​

Divide 18 by −3 to get −6.

2x−4=−6

Add 4 to both sides.

2x=−6+4

Add −6 and 4 to get −2.

2x=−2

Divide both sides by 2.

x=

2

−2

​

Divide −2 by 2 to get −1.

x=−1

Answer:

x= -1

Step-by-step explanation:

-3x (2x-4) 18

Distribute

-6x + 12 = 18

Subtract

-6x + 12-12 = 18 - 12

Simplify

-6x = 6

Divide

-6x/-6 = 6/-6

Simplify

x= -1

Answer:

Below

Step-by-step explanation:

Square area = s^2

    ds/dt = 3

Area = s^2      Find the derivative with respect to t of both sides

area/dt = 2s ds/dt

                    = 2 (10)(3)  = 60 in^2   per sec

The amount of monthly increase will be 8$

What is Quadratic Equation?

Quadratics are polynomial equations of the second degree, which means that they contain at least one squared term. Quadratic equations are another name for it. The quadratic equation has the following general form: ax² + bx + c = 0. x is an unknown variable, whereas a, b, and c are numerical coefficients.

Solution:

Given Equation is x² - 16x + 64 = 0

Using the formula method we will first find the discriminant

D = b² - 4ac

D = 256 - 256 = 0

x = -b +- √D / 2a

x = 16/2 = 8

x = 8

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Answer:9.9

Step-by-step explanation:

We know that pythagorean Theorem is a^2+b^2=c^2

Using this, and A & B we can plug them in

We get 49+49=c^2

98=c^2

we can square root both sides to get

sqrt98=c^2

or 9.9(rounded to the nearest 10th)

Answer:

c = 9.9 to the nearest tenth

Step-by-step explanation:

Pythagoras theorem = c² = a² + b²

a= 7, b = 7, c =?

c² = 7² + 7²

c² = 49 + 49

c² = 98

c =√98

c = 9.8995

Answer to the nearest tenth

c = 9.9

Answer: y = 35x + 75

Step-by-step explanation:

Let x be the number of hours and y is the total cost

We will have the equation

y = 35x + 75

Answer:

Step-by-step explanation:

Input: 1, 2, 3, 4, 5

Output: -7, -9, -11, -13

To get the output you'd add -2 each time. -7+(-2) is -9. -9+(-2)=-11. -11+(-2)=-13. And because it keeps on increasing like this the n should be 5. Because the output keeps increasing by the same value the input should too. It's increasing by 1.

( not sure if this is what you wanted us to answer)

Answer:

---------------------------

Using table, put the output values as a sequence:

We see the first term is -7 and the common difference is - 2.

The nth term would be:

Answer:

[tex] \frac{x {}^{13} }{y} [/tex]

Step-by-step explanation:

[tex]1. \: \frac{xx {}^{12} }{y} \\ 2. \: \frac{x {}^{13} }{y} [/tex]

Answer:

Step-by-step explanation:

In order to answer this question, we need to know what PEMDAS stands for.

Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction.

Now using this order, we can solve.

There isn't any parenthesis.

There is an exponent, [tex]5^{3}[/tex].

Let's solve this.

5 × 5 × 5 = 125

Our equation now looks like this:

125 + 28 ÷ 7 - 1

There isn't any multiplication for us to solve.

There is division.

28 ÷ 7 = 4

Now our equation looks like this:

125 + 4 - 1

Now it's time for addition.

125 + 4 = 129

Now our equation looks like this:

129 - 1

Now all we need to do is subtraction.

129 - 1 = 128

The final answer is 128.

Answer:

2hrs(3x faster) :

6hrs = 15 miles

2hrs = 15 miles

Step-by-step explanation:

The average rate of change of a function is said to be a measure of how much the function changed per unit The average rate of change is -100/11

The average rate of change of a function is said to be a measure of how much the function changed per unit, on average, over that interval. It is also said to be derived from the slope of the straight line connecting the interval's endpoints on the function's graph

f(x) over an interval [x1,x2] is given by:

average rate of change = change in y/change in x

= f(x2) − f(x1) / x2−x1

With f(x) = 1/x over [1, 11]

average rate of change = f(11) − f(1) / 11−1

average rate of change = (1/11 − 1) / 10

average rate of change = (−10/11 / 10

average rate of change = −100/11

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Answer:

  0.2 m

Step-by-step explanation:

You want to know the height of a cylinder with 1 m radius and a volume of 628 liters.

The formula for the volume of a cylinder is ...

  V = πr²h

Using the given values, we have ...

  0.628 m³ = 3.14(1 m)²h

  0.2 m = h . . . . . . . . . divide by 3.14 m²

The depth of the water in the cylinder is 0.2 m.

The area of the sector of a circle  is 28π square miles

The area of a sector of a circle is equal to the area of the circle multiplied by the ratio of the central angle to the full circumference. Therefore, the area of the sector of a circle with a radius of 6 miles formed by a central angle of 2.8 radians is equal to the area of the circle multiplied by the ratio of 2.8 radians to 2π radians (or the circumference of the circle). This means that the area of the sector is equal to 6^2π * 2.8/2π = 28π square miles. In other words, the area of the sector of a circle with a radius of 6 miles formed by a central angle of 2.8 radians is equal to 28π square miles. To visualize this, imagine a pizza slice with a radius of 6 miles. The area of the pizza slice is equal to 28π square miles. The area of the sector is the same as the area of the pizza slice. Therefore, the area of the sector of a circle with radius of 6 miles formed by a central angle of 2.8 radians is equal to 28π square miles.

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The bicycle is moving at a speed of 14,356 meters per hour.

Here, we are given that the wheel of a bicycle is spinning at the rate of 150 revolutions per minute.

The diameter of the wheel is 20 inches

⇒ radius = 10 inches

⇒ circumference of the wheel = 2 × π × 10

= 20π

Thus, the wheel will cover a distance of (20π × 150) inches in a minute

= 300π

now, we know that 1 inch = 0.254 meters

⇒ 300π inches = 300π × 0.254

= 76.2π

Thus, the bicycle covers 76.2π meters in a minute

⇒ it'll cover 76.2π × 60 meters in an hour

= 4572π

= 4572 × 3.14

= 14,356.08

Thus, the bicycle is moving at a speed of 14,356 meters per hour.

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Answer:

D. Corresponding Angles

Step-by-step explanation:

This is becasue they're both the same angle on the same side

If the 11th graders prefer hotdogs at a rate of 70%, the bar for 11th graders would show 70% percentage.

A segmented bar chart is a graphical representation of data that is divided into different segments. It is typically used to compare different categories of data. In this case, the bar chart is used to compare the lunch preference of different grades. The bar for 11th graders would show the percentage of 11th graders who prefer hotdogs. If 70% percentage of 11th graders prefer hotdogs, then the bar for 11th graders would show 70%. The bar chart can also show the percentage of 11th graders who prefer other lunch options, such as sandwiches, salads, etc. This information can help school administrators to better understand the lunch preferences of their students and make informed decisions about what types of food to serve for school lunch.

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15 inches is the width of each present.

Two or more expressions with an Equal sign is called as Equation.

Given that Lana elf measured the width of 9 Christmas presents.

The total width of all the presents was 135 inches.

If the presents were all the same width then we need to find the width of each present.

w=width.

As given, 9w=135

Divide both sides by 9

w=135/9

w=15

Hence, 15 inches is the width of each present.

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The extent to which the researcher can refer that findings with a sample from which it was drawn is referred to as generalizability.

Generalizability refers to the ability to extrapolate study findings from a sample to the entire population. It also refers to the capacity to apply findings from one study to a similar environment in a different investigation.

Generalizability and transferability are two research traits that are related. When considering generalizability in research, there are two features or dimensions to consider: generalizability as it relates to the specific population on which the research is conducted, and generalizability on a global scale.

Such studies will be easier to generalize if the researcher uses adequate sampling approaches, sample sizes, and exact processes.

In general, a study has strong generalizability when the findings apply to a wide range of persons or situations. The study has weak generalizability if the results can only be applied to a subset of the population or in a very specific circumstance.

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The length vector is 1. So the sketch vector field f is given below. So the option a is correct.

In the given question, the vector field F by drawing a diagram like this figure.

The given vector field F is:

F(x, y) = (yi + xj)/√(x^2 + y^2)

We can write the vector field as:

F(x, y) = yi/√(x^2 + y^2) + xj/√(x^2 + y^2)

Here

F(x, y) = [y/√(x^2 + y^2)]^2 + [x/√(x^2 + y^2)]^2

F(x, y) = y^2/(x^2 + y^2) + x^2/(x^2 + y^2)

F(x, y) = (y^2+ x^2)/(x^2 + y^2)

F(x, y) = 1

F(0, y) = y/|y| = ±1

F(x, 0) = x/|x| = ±1

So the length vector is 1.

So the sketch vector field f is given below:

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The complete question is:

Sketch the vector field F by drawing a diagram like this figure.

F(x, y) = (yi + xj)/√(x^2 + y^2)

If Dave bought 5 packs of snacks, then the amount on Dave's account for snack last month should be $3.75.

Dave purchased 5 packs of snacks last month and the cost of each pack was $0.75. The total cost of the snacks was charged to Dave's account, so his account balance should reflect the total cost of the snacks. In this case, Dave purchased 5 packs of snacks, so the total cost would be $3.75 ($0.75 x 5). Therefore, Dave's account balance should show $3.75 for the snack purchases last month. This amount is the sum of the individual cost of each snack pack, multiplied by the number of packs Dave purchased. In this case, the amount on Dave's account for snack last month should be $3.75.

5 packs of snacks x $0.75 = $3.75

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The value of the sequence a2 is (c) 75

From the question, we have the following sequence that can be used in our computation:

a₁ = 6 and an = 3 + 2(an-1)²

Substitute 2 for n in the equation an = 3 + 2(an-1)²

So, we have the following representation

a2 = 3 + 2(a2-1)²

This gives

a2 = 3 + 2(a1)²

Substitute a₁ = 6 in a2 = 3 + 2(a1)²

a2 = 3 + 2(6)²

Evaluate

a2 = 75

Hence, the value of a2 is 75

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The combined cost per game ticket is $1.71

In this question we have been given Clayton and Iris purchase admission to a carnival plus a number of game tickets. Clayton purchased 10 game tickets and spend $19. 50.

Iris purchase 15 game tickets and spend $23. 25

We need to determine cost per game ticket.

The total cost of Clayton's game tickets is $19.50 for 10 tickets,

So, by unitary method the cost per ticket is:

= 19.5/10

= $1.95 per ticket.

The total cost of Iri's game tickets is $23.25 for 15 tickets

So, by unitary method the cost per ticket is:

= 23.25/15

= $1.55 per ticket.

The combined cost of all the game tickets is $19.50 + $23.25 = $42.75.

The total number of game tickets purchased is 10 tickets + 15 tickets = 25 tickets.

The combined cost per game ticket would be,

= 42.75 / 25

= $1.71 per ticket.

Therefore, the cost per game ticket = $1.71

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The number of more workers required that the work will finish in 24 days will be equal to 3 workers.

The four basic operations of arithmetic can be used to add, subtract, multiply, or divide two or even more quantities.

They cover topics like the study of integers and the order of operations, which are relevant to all other areas of mathematics including algebra, data processing, and geometry.

As per the given information in the question,

12 workers can finish the work in 30 days.

Let the number of more men be x that the work will be finished in 24 days.

Use the man-days concept.

M₁ D₁ = M₂D₂

Here, M₁ and M₂ are the numbers of men, and D₁ and D₂ are the numbers of days.

12 × 30 = x × 24

x = (12 × 30)/24

x = 15

So, the number of extra men is,

15 - 12 = 3 workers.

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The domain and range is calculated to be

domain { x | 0 ≤ x ≤ 12 }

range (3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25 }

The situation described has the following information deduced form the problem

a parking garage that operates from 7:00 a.m. to 7:00 p.m.

from  7:00 a.m. to 7:00 p.m = 12 hours

hence form 0 to 12 is the domain

and charges $3 for the first hour and. $2 for each additional hour or part of an hour of parking

this means that the y intercept is 3 and the slope is 2, hence the equation of the line is

y = 2x + 3

The range is calculated as follows, since 11.59 is counted as 12 we take 11

at x = 0, y = 2 * 0 + 3 = 3

at x = 11, y = 2 * 11 + 3 = 25

the range is calculated to be 3 to 25

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Using the formula for the combination and with the And rule of probability, The answer is 20.

Simply put, probability is the likelihood that something will occur. When we don't know how an event will turn out, we can discuss the likelihood or likelihood of several outcomes. Statistics is the study of events that follow a probability distribution.

Combinations are mathematical operations that count the number of potential configurations for a set of elements when the order of the selection is irrelevant. You can choose the components of combos in any order.

It's formula is:

[tex]C(n,r) = \frac{n!}{r!*(n-r)!}[/tex]

orange balls = 5

yellow balls = 4

green balls = 1

probability = C(5,1)*C(4,1)*C(1,1)

=5*4*1

=20.

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