Given the following reaction:

2 CH4O + 3 O2 → 2 CO2 + 4 H2O

How many grams of CO2 will be produced if you start with 1.34 g CH4O?

Please use the periodic table and remember to include your units.

0.9541 grams of nickel (ii) hydroxide will be produced if 30.4 mL of 0.673 M KOH react completely and 1.3764 grams of nickel (ii) hydroxide will be produced if the 17.6 mL of 0.841 M NiCl₂ react completely.

According to the balanced chemical equation,

2KOH (aq) + NiCl₂ (aq) → 2 KCI (aq) + Ni(OH)₂ (S)

a. 2 Moles of KOH = one mole of Ni(OH).

As we know,

Molarity = moles/amount of solution(in liters)

For KOH,

0.675 = moles/0.0304

Moles of KOH = 0.02052.

Moles of Ni(OH) = 0.02052/2

Moles of Ni(OH) = 0.01026

We also know,

Moles = formed mass/molar mass

Molar mass of NiOH = 93 grams/mole

0.01026 = formed mass/93

Formed mass of NiOH = 0.9541 grams.

b. 1 Mole of NiCl₂ = one mole of Ni(OH).

As we know,

Molarity = moles/amount of solution(in liters)

For NiCl₂,

0.841 = moles/0.0176

Moles of NiCl₂ = 0.01480

Moles of Ni(OH) = 0.01480

We also know,

Moles = formed mass/molar mass

Molar mass of NiOH = 93 grams/mole

0.01480 = formed mass/93

Formed mass of NiOH = 1.3764 grams.

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I fell confident that I can identify the different rates of chemicals.

This is known to be be a powerful diagnostic tool and it is called a reaction's rate. It is one that is seen when we can create methods to increase production by understanding how quickly items are made and what slows down reactions.

Therefore, reaction rate, in regards to chemistry, is seen as the speed with which a said or given chemical reaction moves or functions.

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The maximum amount of sulfur dioxide (SO₂) that can be formed is 25.6 g.

The formula for the the limiting reagent is CO

The amount of excess reagent that remains after the reaction is 3.6 g.

The limiting reagent is the reactant that is completely used up in a reaction, and thus determines when the reaction stops.

The limiting reagent is determined by balancing the chemical equation as follows;

S + 2CO  --------> SO₂ +  2C

From the reaction above;

1 mole of sulfur = 2 mole of carbon monoxide = 1 mole of sulfur dioxide

56 g of carbon monoxide (CO)  = 64 g of sulfur dioxide (SO₂ )

22.4 g of CO = ? of SO₂

= (22.4 x 64)/56

= 25.6 g of SO₂

Thus, the maximum amount of sulfur dioxide (SO₂) that can be formed is 25.6 g.

The formula for the the limiting reagent is CO because it will be completely used up.

56 g of CO = 32

22.4  of CO  = ?

= (22.4 x 32)/56

= 12.8 g

Excess mass of the sulfur that remains = 16.4 g - 12.8 g = 3.6 g

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Answer:

6.15 moles

Explanation:

1 mole of C has 6.02 x 10^23 atoms

the number of mole in 3.7 x 10^24 is

(1 mole)(3.7 x 10^24)/(6.02 x 10^23)

= 6.15 moles

An object that weighs 10.045 g at room temperature may end up weighing 10.16g when it becomes very cold since the weight will increase slightly.

The relationship between density and temperature is inversely proportional. As the temperature of a substance decreases, the weight of the substance increases, vice versa.

During the process of decrease in temperature, the molecules of the object  come together and becomes very dense, hence increase in the weight of the object.

As the temperature increases, the molecules of the object moves further apart becoming less dense, hence the decrease in the weight of the object.

Thus, an object that is initially at room temperature will weight more when the temperature decreases.

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The balanced chemical equation of the chemical reaction of hydrogen and oxygen is:

2 H₂ (g)  + O₂ (g)  →  2H₂O (l)

A balanced chemical equation is an equation in which the number of atoms of each element on the left side of the arrow (reactant side) is equal to the number of atoms of each element on the right side (product side) of the arrow.

A chemical equation is a way to express the chemical reaction in terms of symbols of the substances. It is very important that a balanced chemical equation must obey the law of conservation of mass.

By following the law, the total mass of the elements left side or reactant side should be equal to the total mass of elements on the right side (product side) in a balanced chemical equation.

Given, the chemical reaction of the water formation is as follows:

H₂ (g)  + O₂ (g)  →  2H₂O (l)

The number of oxygen on both sides is equal but the number of hydrogens is unequal. So multiply the hydrogen gas on the left side by 2.

So the balanced chemical equation of water formation becomes:

2 H₂ (g)  + O₂ (g)  →  2H₂O (l)

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In an aqueous solution of ethanol, C₂H₅OH, the molecules that would be present in the solution are ethanol molecules and water molecules.

Aqueous solutions are solutions containing water as the solvent of the solution.

An aqueous solution simply means dissolved in water.

When dissolved in water, ionic compounds dissociate to form ions in aqueous solutions.

Other polar solutes which are non-ionic will simply dissolve in water as a result of the interaction of the polar ends of the molecules. However, no ions will be formed by these polar non-ionic solutes.

For example, a solution of ethanol in water is a non-ionic aqueous solution.

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The theoretical yield of All3 obtain from the reaction is 121g.

2Al + 3I₂ —> 2AlI₃

Molar mass of I₂ = 2 × 127 = 254 g/mol

Molar mass of I₂ from the equilibrium equation = 3 × 254 = 762 g

Molar mass of AlI₃ = 27 + (3 × 127) = 408 g/mol

Mass of AlI3 from the equilibrium equation = 2 × 408 = 816 g

762 g I₂

From the balanced formula above,

762 g I 2 is The reaction produced by 816 g of All3.

From the balanced equation above,

gives 762 g of I2, which reacts to form 816 g of AlI3 121g.

Convert grams to moles using molar ratios to crosslink products and reactants and convert moles back to grams. Calculated on a stoichiometric basis. Actual yield is determined experimentally. The yield rate is determined by calculating the ratio of actual yield/theoretical yield.

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a) The percentage of presence in nature of 1st 2nd and 3rd isotopes is 92.2% 4.7 %  and 3.1 %.

b) The chemical symbol for isotopes is ²⁸Si , ²⁹Si , ³⁰Si.

Element with atomic number 14 silicon . chemical symbol is Si.. Four isotopes of silicon's occur in natural environment-  ²⁸Si , ²⁹Si , ³⁰Si ³²Si. The ²⁸Si , ²⁹Si , ³⁰Si is stable isotopes. And the fourth one ³²Si is radiogenic. Silicon atom have mass of 28 amu. ²⁸Si is the most abundant isotope of silicon has percentage of 92.2% . ²⁹Si is 4.7 % and the third is ³⁰Si is 3.1 %.

Thus, An unknown element Y with atomic number 14 is found in nature as a mixture of three isotopes. isotopes 28 has percentage of 92.2 % and isotopes 29 which has percentage of 4.7 %.the third isotopes is 30.

a) The percentage of presence in nature of 1st 2nd and 3rd isotopes is 92.2% 4.7 %  and 3.1 %.

b) The chemical symbol for isotopes is ²⁸Si , ²⁹Si , ³⁰Si.

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Answer: what?

Explanation:

Answer: Huh?

Explanation:

Answer:

Explanation:

Here's a quick review of the types of reactions.
Synthesis:
Two or more chemicals combine to make a new one.
Ie: A+B => AB or A+B => C

Decomposition:
The opposite of synthesis.
Ie: AB => A+B, C => A+B

Combustion:
Usually something reacting with oxygen. That something usually being a carbohydrate.
Ie: CH4 + 2O2 => CO2 + 2H2O

Single replacement:
One atom or molecule of a compound is knocked out of place and replaced by another chemical
Ie: A+BC => AB + C (note how the bond between B and C break while a bond between A and B form)

Double replacement:
A little like a single replacement, but two bonds break and two new bonds form between two reactants.
Ie: AB+CD => AC+BD

The actual answer

The first equation (2C3H7OH + 9O2....)
Is a combustion reaction because it contains oxygen and the oxygen is oxidizing something.

The second equation (2Al + 3 ZnCl2...)
Is a single replacement reaction because only one type of bond is being broken (the Zn---Cl bond) and only another one type of bond is formed (The Al---Cl bond)

The third equation (NaCl + AgNO3...)
Is a double replacement reaction because two types of bonds are being broken (Na---Cl and Ag---NO3) and two new bonds are forming (Ag---Cl and Na---NO3)

The fourth equation (N2H8CO3...)
Is a decomposition reaction because there is only one reactant and it is splitting into multiple pieces

The fifth equation (2Al + 3Br2...)
Is a synthesis reaction because two elements/ compounds are being combined to make a singular new compound

The number of copper atoms are in 5.33mol CuCl2 =5.33 ​ × 6.023 × 1023 = 3.21 × 1024

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Plastic items are not biodegradable and contaminate the environment, petroleum is a non-renewable resource, and processing and consuming petroleum emits toxins into the environment.

We refer to a substance as being biodegradable if it can be naturally broken down by living things in an environment. Simply explained, the term "biodegradable" refers to a substance that gradually deteriorates into smaller parts like gases and sugar. Microorganisms, such as fungi and bacteria or microbes to be reabsorbed by the surrounding environment, ideally without generating any pollutants, are responsible again for biodegradation.

Examples of biodegradable materials that microbes can break down include food and paper waste.

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The substances would look as follows;

Let us recall that just like solids, the density of the solids is important in the determination of how the mixture of the substances would appear. The substances that are denser would tend to appear below while the substances that are less dense would tend to appear above.

Let us remind ourselves the densities of each of the substances as a hep to where we are going;

Water - 1 g/cm³

Mercury - 5.43 g/cm³

Kerosene - 0.82 g/cm³

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Since Tricia is investigating a crime, the best form of remedy that Tricia can use to solve this  issue is option A. She should talk to witnesses who observed the crime.

A witness is said to be a term that is defined as a person who has observed an occurrence or who testifies to what they have observed.

Note that a person who witnesses a robbery as well as testifies in court about what they observed is an example of a witness and they are the best people to get accurate information regarding the crime from.

Hence, option A is correct.

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Answer:  A

Explanation:

The question requires us to balance a given reaction and then determine the excess reagent for this same reaction, given that 3.4 moles of Ca(NO3)2 and 2.4 moles of LiPO4 are used.

First, let's balance the equation so we can make the required calculations from it. A simple way to balance this reaction is to start with metals (Li and Ca) and consider the anions NO3 and PO4 instead of the isolated N, O and P atoms:

1) We write the given equation:

___Ca(NO3)2 + ____Li3PO4 --> ___LiNO3 + ____Ca3(PO4)2

2) We check the amount of Ca and Li on both sides of the reaction:

On the left side -> 1 Ca and 3 Li

On the right side -> 3 Ca and 1 Li

3) Then, we change the coefficients in order to have the same amount of Ca and Li on both sides:

3

4) Next, we check the amount of NO3 and PO4 anions:

Left side -> 3*2 NO3 = 6 NO3 and 1 PO4

Right side -> 3*1 NO3 = 3 and 2 PO4

4) We need to adjust some numbers in order to have the same amount of all considered species:

5) At last, we check again:

Left side -> 3 Ca, 6 NO3, 6 Li, 2 PO4

Right side -> 3 Ca, 6 NO3, 6 Li and 2 PO4

a) Then, the balanced reaction is:

1

b) Now that we know the stoichiometric coefficients, we can determine the excess reagent.

From the balanced reaction, we know that we need 3 moles of Ca(NO3)2 to react with 2 moles of Li3PO4. Then, we can write:

3 mol Ca(NO3)2 --------------- 2 mol Li3PO4

3.4 mol Ca(NO3)2 ------------ x

exexcesslimiting (more than 2.27 moles)

We can also determine the excess reactant from the following relation:

y ------------- 2.4 mol Li3PO4

In this case, solving for y, we have that we would need 3.6 moles of Ca(NO3)2 to react with 2.4 moles of Li3PO4, meaning that there is less than required of Ca(NO3)2, thus this is the limiting reactant while Li3PO4 is the excess reactant.

We can use the law of ideal gases to solve this question.

The law of ideal gases is represented by the following formula:

Where P is the pressure, v is the volume, n is the number of moles, R is the ideal gas constant and T is the temperature.

The first step is to convert kPa to atm, °C to K and mL to L.

Now, we can use these values to find n, which is the amount of moles of the gas:

The answer is 0.00264 moles of chlorine are released.

The Net force is 20.12 N  and acts in a direction 26.56° South of East.

A net force is a force that is the vector sum of all the forces acting on an object.

The net force is also known as the resultant force.

The net force produces the same effect as all the forces acting together on an object.

The net force of the given forces in the diagram is calculated as follows:

The forces acting on the object are an 18 N force acting in a direction to the east and a 9 N force acting vertically downward in a direction south of the object.

The two forces form two sides of a right angle triangle.

Net force is calculated using Pythagoras' rule:

Net force = √ (18² + 9²)

Net force = √ (324 + 81)

Net force = √ 405

Net force = 20.12 N

The direction of the Net force = tan⁻¹ (9 / 18)

The direction of the Net force = tan⁻¹ 0.5

The direction of the Net force = 26.56° South of East

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To determine the level of radionuclides present is the best reason for consulting with a nuclear chemist before building the processing plant.

The level of radionuclides refers to the concentration in the atmosphere of radioactive compounds, which may be harmful to humans and therefore theirs levels should be monitored in order to maintain well being, especially in nuclear plants where they can be dangerous to the environment.

Therefore, we can conclude that it is required to know the level of radionuclides that are present in a processing plant.

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Answer:a

Explanation:

From the data provided and the equation of reaction:

The maximum amount of the product that can be formed is calculated from the equation of reaction as follows:

From the equation of reaction, the mole ratio of hydrogen to nitrogen is 3 : 1

From the given data:

mass of hydrogen reacting = 4.65 grams

mass of nitrogen reacting = 4.67 grams

The moles of the reactants is determined as follows:

molar mass of hydrogen gas = 2.0 g

molar mass of nitrogen gas = 28.0 g

Moles of hydrogen = 4.65/2 = 2.325 moles

Moles of nitrogen = 4.67/28 = 0.1667 moles

mole ratio of hydrogen to nitrogen is 2.325 : 0.1667 = 14 : 1

The limiting reagent is nitrogen while the excess reagent is hydrogen.

The formula of nitrogen is N₂.

Hence, the maximum moles of ammonia (NH₃ ) that can be formed is 0.1667 moles.

mass of ammonia formed = 0.1667 * 17 grams

mass of ammonia formed = 2.83 g

The moles of the excess reagent remaining after the reaction is complete = 2.335 - (0.1667 * 3) = 1.835

moles of the excess reagent remaining = 1.825 moles

mass of the excess reagent remaining = 1.825 * 2

mass of the excess reagent remaining = 3.65 grams

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Answer:

1368.9 [gr].

Explanation:

1. the formula of the required mass is:

m=Mν, where M=[gr/mol] and ν=[moles];

2. M=M(NaCl)=M(Na)+M(Cl)=23+35.5=58.5 [gr/mol];

ν=23.4 [moles] according to the condition, then

3. the required mass:

m=23.4*58.5=1368.9 [gr].

Answer:

107 g

Explanation:

Based on the half-lives of the given materials:

The half-life of a substance is the time taken for half the amount present in the original sample of a substance to decay.

The half-life of a substance is constant.

Considering the given questions:

1. the half life of radium-226 is 1,600 years, how long will it take for 93.75% of a sample of radium-226 to decay?

The amount of remaining after 93.75% have decayed = 100 - 93.75 = 6.25%

The number of half-lives that will result in 6.25 % remaining will be:

After first half life = 50% remains

After second half life = 25% remains

After third half life = 12.5% remains

After fourth half life = 6.25% remains

Number of years taken = 4 * 1600

Number of years taken = 6400 years

2. Sodium-24 has a half life of 15 days. What fraction of the original amount of sodium-24 will remain in a sample after 105 days?

Number of half lives after 105 days = 105/15

Number of half lives after 105 days = 7 half lives

Fraction remaining = (¹/₂)⁷

Fraction remaining = 0.78 %

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Taking into account the reaction stoichiometry, if 42.9 g of iron is reacted with 27.5 g of oxygen, 61.335 grams of iron(III) oxide are produced.

In first place, the balanced reaction is:

4 Fe + 3 O₂ → 2 Fe₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 96 grams of O₂ reacts with 223.4 grams of Fe, 27.5 grams of O₂ reacts with how much mass of Fe?

mass of Fe= (27.5 grams of O₂× 223.4 grams of Fe)÷ 96 grams of O₂

mass of Fe= 63.995 grams

But 63.995 grams of Fe are not available, 42.9 grams are available. Since you have less mass than you need to react with 27.5 grams of O₂, Fe will be the limiting reagent.

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 223.4 grams of Fe form 319.4 grams of Fe₂O₃, 42.9 grams of Fe form how much mass of Fe₂O₃?

mass of Fe₂O₃= (42.9 grams of Fe×319.4 grams of Fe₂O₃)÷ 223.4 grams of Fe

mass of Fe₂O₃= 61.335 grams

Then, 61.335 grams of Fe₂O₃ are produced.

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The volume of the cube that has an edge length of 0.017m is 4.9 × 10-⁶m³.

Volume is a three-dimensional measure of space that comprises a length, a width and a height. It is measured in units of cubic centimeters in metric, cubic inches or cubic feet.

The volume can be calculated by multiplying the length, breadth and height of a three-dimensional shape such as cube.

According to this question, a cube has an edge length of 0.017m. The volume can be calculated as follows:

Volume = 0.017 × 0.017 × 0.017

Volume = 0.000004914

Volume = 4.9 × 10-⁶m³

Therefore, 4.9 × 10-⁶m³ is the volume of the cube

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Answer:

Explanation:

i dont kow

The complete ionic equation and the net ionic equation for the reaction of aqueous ammonia and aluminum nitrate is written as follows:

[tex]Al^{3+} (aq)+3(NO_{3})^{-}(aq)+3NH_{4}^{+} (aq) + OH^{-}(aq)\rightarrow Al(OH)_{3}(s)+3NH_{4}^{+}(aq)+NO_{3}^{-}(aq)[/tex]

[tex]Al^{3+}(aq)+ OH^{-}(aq)\rightarrow Al(OH)_{3}(s)[/tex]

In an ionic equation all the ions are charges are balanced to the proper stoichiometric ratio. The states of each species have to be written in the brackets.

The reaction of aluminum nitrate and aqueous ammonia is written as follows:

[tex]Al(NO_{3})_{3}(aq) + 3NH_{4}OH(aq)\rightarrow Al(OH)_{3}(s) +3NH_{4}NO_{3}(aq)[/tex]

The complete ionic equation is written below:

[tex]Al^{3+} (aq)+3(NO_{3})^{-}(aq)+3NH_{4}^{+} (aq) + OH^{-}(aq)\rightarrow Al(OH)_{3}(s)+3NH_{4}^{+}(aq)+NO_{3}^{-}(aq)[/tex]

From this complete ionic equation the net ionic equation can be written by cancelling same species from both side as below:

[tex]Al^{3+}(aq)+ OH^{-}(aq)\rightarrow Al(OH)_{3}(s)[/tex]

Therefore, the net product aluminum hydroxide is precipitated and the net ionic equation is written as above.

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Answer:

Explanation:

6.78 kg

Explanation:

Molality is the ratio of the amount of substance of a solute (in moles – n) to the mass in kilograms of the solvent (m).

The symbol for molality is usually W and it can be calculated by the following formula:

W = n/m

here, we need to calculate n of NaCl using the formula:

n = m/MM

where MM of NaCl is 58.5 g/mol

n = 120/58.5

n = 2.05 moles

W = 2.05/30

W = 0.068 mol/Kg

Answer: A) 0.068

A mass of 0.141 g Ca(OH) is present in a sample if it is  titrated to its equivalence point with 44.02 mL of HNO3.

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