A 44 kg child steps onto a scale and reads 430 N so the magnitude of the normal force acting on the child will be 430 N.
What is Normal Force?The normal force is a common force that is experienced when an object is placed on a surface and pushed against it. For instance, the normal force prevents a book from falling through a table when it is placed on one. The book is being pulled downward by gravity, but because it isn't truly falling, something must be pushing it upward. The normal force is what we refer to as. Normal refers to something that is perpendicular to the surface.
According to the question,
Normal Force=Weight of the person
= 430 N
So, the Magnitude of the normal force acting on the child will be 430 N.
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A: Small rockets are used to make tiny corrections to the velocity of a satellite. If a rocket has a thrust of 35 N and is used to change the velocity of a 72000 kg satellite by 0.63 m/s, for how long (time) should it be fired?
B: A 2-kg pumpkin flies through the air at 42 m/s (93mph)! It strikes a 500kg Volkswagen Bug that has been abandoned in a corn field for quite some time. The pumpkin bounces off the car and has a final velocity of -2.68 m/s (-6.0 mph). What is the final velocity of the car?
The small rocket will be take time 1296 sec.
We are given that,
The thrust of the rocket = F = 35N
The velocity of the rocket = v = 0.63m/s
The mass of the satellite = m = 72000kg
Therefore , to get time t of the rocket when it would be fired and we use the equation such as , the product of the mass and velocity of an object i.e. known as momentum (p).
p = mv
Where p is the momentum of the rocket, m is the mass and v is the velocity of the rocket.
Since , here we can write Newtonian relations such as, Momentum is equivalence as a function of Force (F) and time (t) which is given as,
p = F t
So that from above two equation we can write as,
mv = Ft
t = mv/F
t = {(72000kg) ×(0.63m/s)}/35N
t = 1296 sec
Therefore, the rocket will be fired in 1296 seconds.
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Which of these does NOT represent the distance traveled by an object?
The bus ride was 30 minutes.
The bus traveled 300 meters.
The motorcycle went 4 miles.
The car drove 35 kilometers.
Answer:
1. The bus ride was 30 minutes
Explanation:
30 minutes = time
meters = distance
miles = distance
kilometers = distance
which detail from the text best supports the answer to part a
story: Alexander Hamilton
The detail from the text best supports the answer to part A is Hamilton’s passionate drive pushed him into many confrontations, both physical and political as he sought a lasting legacy.
The part A identifies the central idea of the text which is Hamilton’s strong opinions and tendency to fight relentlessly for his beliefs contributed to the large impact he had as a Founding Father, but also made him several enemies.
Alexander Hamilton was a founding father of United States. He fought in the American Revolutionary War. He drafted the constitution. He was the founder of American financial system.
Therefore, the detail from the text best supports the answer to part A is Hamilton’s passionate drive pushed him into many confrontations, both physical and political as he sought a lasting legacy.
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Steel has a density of 7.8 g/cm³ calculate the mass of a cubic block with a side length 5 cm
Answer:
9750g
Explanation:
Density=78g/cm³
volume= 5×5×5=125cm³
mass=Density×volume
mass=78g/cm³×125cm³
mass=9750g
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What is the magnitude of the magnetic force experience by a cable that is 3 cm long, going trough a magnetic field 44 x10-3 T strong, with a current of 2 A that is perpendicular to the field
The equation describes the force acting on a wire carrying current I and having length L in a magnetic field. Where is the angle formed by the wire and the magnetic field, and F=ILB sin x.
magnitude of the magnetic force experience
by a cable is 2.64 x 10 ^ -3 N
What is the formula of magnitude of magnetic force?The equation describes the force acting on a wire carrying current I and having length L in a magnetic field. Where is the angle formed by the wire and the magnetic field, and F=ILB sin x. The field and current are parallel to the force.The current's size has a direct correlation with the field's strength. The strength of the field is inversely proportional to the point's separation from the wire at any given time.When a current-carrying conductor is placed in a magnetic field, the force it experiences is at its strongest when the conductor is kept perpendicular to the magnetic field's direction.F = ILB sin x
= 2 x .03 x 44 x 10^ -3 x sin 90 = 2.64 x 10 ^ -3 N
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d?
Use the vocabulary words from "Read It" to complete the
following sentences.
We all exert a lot of force every day accomplishing basic
tasks. To make work easier, humans have invented
machines. A (4).
makes work easier with a single
motion. It changes the direction of a force and/or the
amount of work that is applied. One example of this type
of machine is a (5)
which is a beam or bar that
There are three
pivots on a point called a (6)
different classes of this type of machine, but all
three have an (7)
force that is used to
lift the (8)
OUTPUT
STATION
A (4) machine makes work easier with a single motion.
One example of this type of machine is a (5) beam balance which is a beam or bar that.
There are three pivots on a point called a (6) work different classes of this type of machine, but all three have an (7) input force that is used to
lift the (8) object.
What facilitates and expedites our work?Our task is made simpler and quicker by machines.
Contrary to common assumption, using machines does not result in more work being done. They only alter the method of operation. By increasing the amount of force delivered, extending the distance over which the force is applied, or altering the force's direction, machines facilitate work.
By increasing the amount of force delivered, extending the distance over which the force is applied, or altering the force's direction, machines facilitate work.
We are able to gather water thanks to the well-use pulley. We can staple pages together with the aid of a stapler, a machine.
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In 6–8 sentences, write a summary of what you learned from this activity. Include an explanation of what causes the spectral shifts you observed. Also, explain how scientists might use spectra analysis to support the big bang theory.
Answer :First part is what you learned so write what you learned then the other parts is The evidence that the universe is expanding comes with something called the red shift of light. Light travels to Earth from other galaxies. As the light from that galaxy gets closer to Earth, the distance between Earth and the galaxy increases, which causes the wavelength of that light to get longer.
Explanation:
I need help with homework
Given
Mass of the shot, M=50 kg
Its speeed, u=35 m/s
Mass of the smaller shots, m=m'=25 kg
let its velocity be v
To find
The velocity of the smaller shots
Explanation
By conservation of momentum,
[tex]\begin{gathered} Mu=(m+m^{\prime})v \\ \Rightarrow50\times35=(25+25)v \\ \Rightarrow v=\frac{50\times35}{(25+25)} \\ \Rightarrow v=\frac{50\times35}{50} \\ \Rightarrow v=35\text{ m/s} \end{gathered}[/tex]Conclusion
The velocity is 35 m/s.
Mass can be defined as the amount of matter in an object. If you were to go to another planet or the moon, would the mass of the object increase, decrease, or stay the same? Explain.
Mass does not change thus the object would have the same mass in ay planet or the moon.
What is the mass?
We need to look at the mass of the body as the quantity of matter that we can find in the body. This implies that the more of matter that we can find in a particular object, the more the mass of the object. It is also possible to define the mass as the quantity of the inertia in an object. These are the basic ways that the mass of the object could be considered or understood in this case.
We know that the mass of the object does not change. This is because the quantity of the matter that an object has is not going to change no matter where the object is found whether on the earth or in the moon.
Having said this, we can now agree that the mass of the object would stay the same both on earth and in the moon.
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What does the CARES Act allow regarding charitable contributions?
(1 point)
The CARES Act regarding charitable contributions, allows you to deduct $ 300 in charitable contributions.
CARES act stands for Coronavirus Aid, Relief, and Economic Security act. It is a bill passed by the then U.S. president Donald Trump. It was released as a response to economic fallout due to COVID 19.
According to CARES act, a single tax filer can reduce up to 300 dollars for contributing to charity without the itemization of deductions. If it is a joint tax filing by married individuals the deduction is increased to 600 dollars.
Therefore, the CARES Act allows you to deduct $ 300 in charitable contributions.
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Personal Finance: Role of Financial Institutions Quick Check
1) the sum of your deductible contributions exceeds $300.
2) It allows you to deduct $300 in charitable contributions.
3) Internal Revenue Service
4) a retail or commercial bank
5) It guarantees that you won't lose all of your money.
2nd question please, no explanation. Trying to see if I was right
The gravitational potential energy depends on the altitude, more altitude means more potential energy. But, equal altitude means equal potential energy.
Therefore, A and D have the same potential energy.Match each phase change description with the correct term.A change from solid to gasA change from liquid to gasA change from gas to liquidA change from solid to liquid?Melting?Sublimation?Condensation
By definition we have that:
Melting: A change from solid to liquid
Sublimation: A change from solid to gas
Condensation: A change from gas to liquid.
Vaporization: A change from liquid to gas
If a batter can apply the same out of maximum force from their hands to each bat to swing it why would the speed of the bat swing decrease as the mass of the bat increases
The speed of the bat swing decrease as the mass of the bat increases because mass is inversely proportional to velocity squared if the centripetal force is constant.
[tex]F_{c}[/tex] = m v² / r
[tex]F_{c}[/tex] = Centripetal force
m = Mass
v = Velocity
r = Radius
Rearranging for v,
v² = [tex]F_{c}[/tex] * r / m
Since [tex]F_{c}[/tex] and r is constant,
v² ∝ 1 / m
Since v² is inversely proportional to m and vice-versa, as the mass of the bat increases, speed of the bat swing decreases.
A centripetal force is responsible for making a body follow a curved path. The direction of centripetal force is perpendicular to the motion and towards the center of curvature.
Therefore, the speed of the bat swing decrease as the mass of the bat increases because mass is inversely proportional to velocity squared if the centripetal force is constant.
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9. If you increase the velocity of an object moving in a circle, does it require more centripetal
force or less?
Yes, more centripetal force is required to to sustain an object in circular motion that is moving at a greater velocity.
Answer:
Explanation:
Force:
Fₙ = m*V² / R
m - const
R - const
V ↑
Fₙ ↑
A new airbus 5200 weighs 150,000 lbs and has a maximum take off acceleration of 2.7 m/s. How long of a runway is required to reach a velocity of 82 m/s for a safe take off.
The resistance of a round copper conductor is 0.2 02. What is the resistance of a copper conductor of equal
length, but four times the diameter?
Resistance of copper wire with four times the diameter is 3.23 Ω.
Formula of resistance is, R= ρl/A.
where, ρ = Resistivity of material
l = Length of material
A= area of material
In first case, resistance of Copper conductor = 0.202 Ω
0.202 = ρ × l /πr²
0.202 = ρ × l/ π (d/2)² …equation 1
In second case, let resistance of copper conductor where diameter is four times be R'
R' = ρ × l /π (d/8)² …equation 2
upon substituting value of equation 1 in 2,
R' = 0.202 × 16
R' = 3.23 Ω
Hence, Resistance of copper conductor with four times diameter is 3.23 Ω
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module 2 question 8
A seagull flies at a velocity of 11.00 m/s straight into the wind.
(a) If it takes the bird 21.0 min to travel 6.00 km relative to the earth, what is the velocity of the wind?
m/s
(b) If the bird turns around and flies with the wind, how long will he take to return 6.00 km?
s
(c) Discuss how the wind affects the total round-trip time compared to what it would be with no wind.
v = d / t
d = 6 km = 6000 m
t = 21 min = 1260 s
v = Velocity
d = Distance
t = Time
Let B represent the seagull, E represent Earth and W represent the wind.
[tex]V_{BE}[/tex] = 6000 / 1260
[tex]V_{BE}[/tex] = 4.76 m / s
[tex]V_{BW}[/tex] = 11 m / s
[tex]V_{WE}[/tex] = [tex]V_{WB}[/tex] + [tex]V_{BE}[/tex]
[tex]V_{WE}[/tex] = - 11 + 4.67
[tex]V_{WE}[/tex] = - 6.33 m / s
b ) [tex]V_{BE}[/tex] = [tex]V_{BW}[/tex] + [tex]V_{WE}[/tex]
[tex]V_{BE}[/tex] = - 11 - 6.33
[tex]V_{BE}[/tex] = - 17.33
[tex]V_{BE}[/tex] = d / t
- 17.33 = - 6000 / t
t = 346.22 s = 5.77 min
c ) The total time taken in the presence of wind = 21 + 5.77
The total time taken in the presence of wind = 26.77 s
Speed of the seagull in the absence of wind, v = 11 m / s
Total distance travelled = 6 + 6 = 12 km = 12000 m
t = d / v
t = 12000 / 11
t = 1090.9 s
t = 18.18 min
Difference in time = 26.77 - 18.18
Difference in time = 8.59 min
Therefore,
The velocity of the wind with respect to Earth is 4 m / sThe time taken by the seagull to return 6 km is 5.77 minThe time taken without the wind is 8.59 min lesser than in the presence of wind.To know more about relative velocity
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three glasses of thickness 2cm , 4cm and 7cm are arranged adjacent .if their refractive indices arec 1.5 , 1.6 and 1.8 respectively. find the bottom of the prism to be raised above.
*Solution*
d = (2/1.5)+(4/1.6)+(7/1.8)
d =
A prism is a translucent, triangular object composed of glass or plastic (or any transparent material). Refraction is a phenomenon that causes white light to curve when it passes through a prism. Light is bent when it travels from one medium (like air) to another medium through the process of refraction (like water or glass).
The refractive index of an optical medium is a dimensionless quantity that describes how efficiently the medium bends light. The amount of light that enters a substance is refracted or bent depends on the substance's refractive index.
Apparent depth is the distance between the real depth of an item and its image when it is submerged in a transparent medium, which is lowered by a factor equal to the relative index of refraction of the medium with regard to air.
apparent depth is equal to actual depth / refractive index.
d = (2/1.5) + (4/1.6) + (7/1.8)
= 5.741 cm
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A car slams into a brick wall, with an impulse of 10Ns, the duration of the impulse was 0.2 sec. What was the average force the car hit the wall?
Answer:
50 N
Explanation:
The change in momentum in this case can be calculated in this way
Impulse (Ns) = force (N) X time (s)
We have Impulse and time here:
10Ns= force X 0.2s
We rearrange the formula to get force
10 ÷ 0.2 = 50
Therefore average force is 50N
The body of a snorkeler swimming in salt water has a resistance of about 605 Ω . If the snorkeler is unfortunate enough to be struck by the eel, what current will flow through her body?
Resistance of snorkeler, R = 605 Ω.
Current, I = V/R 500/605 = 0.83 A
⇒ I = 0.83 A.
The flow of charge across the cell membrane creates an electric current. Cells control the flow of specific charged elements across membranes using proteins that reside on the cell surface and create openings for specific ions to pass through. These proteins are called ion channels.
For example, if there is a voltage difference between one arm and the other a current will flow through the body. The human body has a higher impedance to DC current than to its AC current. That is, a person can withstand the effects of an electric shock caused by a DC voltage more than he can by an AC voltage. It interferes with the normal functioning of the nervous and muscular systems, causing severe muscle contractions.
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What is it called when you place the ball in your palm (facing up or sideways) during a dribble?
When you place the ball in your palm (facing up or sideways) during a dribble it is called carrying.
What is carrying in basketball?Carrying occurs when the dribbling player continues to dribble after allowing the ball to come to rest in one or both hands and/or places their hand underneath the basketball. Carrying is a violation of the basketball rules.
There is a type of carrying, known as palming which involves holding the ball in one hand in a grip without allowing it to fall naturally.
Dribbling in basketball is referred to as a repetitive action in which a player uses one hand to bounce the basketball continuously on the court.
There are types of dribbling in basketball which includes:
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A student drops a water balloon out of a dorm window 17 m above the ground. What is its speed when it hits the ground?
PLEASE HELP!!!
The speed of the water balloon dropped out of a dorm window 17 m above the ground when it hits the ground is 18.25 m / s
v² = u² + 2 a s
v = Final velocity
u = Initial velocity
a = Acceleration due to gravity
s = Displacement
d = 17 m
a = 9.8 m / s²
u = 0
v² = 0 + ( 2 * 9.8 * 17 )
v² = 333.2
v = 18.25 m / s
The equation used to solve the problem is an equation of motion. An equation of motion is used to describe the position of an object in motion with constant acceleration.
Therefore, the speed of the water balloon when it hits the ground is 18.25 m / s
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The longest delivery flight ever made by a twin-engine commercial jet took place in 1990. The plane covered a total distance of 14 890 km from Seattle, Washington to Nairobi, Kenya in 18.5 h. Assuming that the plane flew in a straight line between the two cities, find the magnitude of the average velocity of the plane. Also, find the eastward and southward components of the average velocity if the direction of the plane’s flight was at an angle of 25.0° south of east.
The average velocity of the plane is 804.86 km/h. The eastward and southward components of the average velocity is 729.45 km/h and 340.14 km/h respectively.
The total distance covered by the plane (d) = 14890 km
The time taken for the flight to cover distance (t) = 18.5 hr
The average velocity is calculated by total distance divided by time taken.
[tex]V_{avg} = \frac{d}{t}[/tex]
[tex]V_{avg}=\frac{14890}{18.5}=804.86 km/h[/tex]
The eastward component of average velocity = [tex]V_{x}[/tex]
The southward component of average velocity = [tex]V_{y}[/tex]
[tex]V_{x}= V_{avg}cos\theta[/tex]
[tex]V_{y}= V_{avg}sin\theta[/tex]
Substitute the values and find the components of average velocity.
[tex]V_{x}[/tex] = 804.86*0.90 = 729.45 km/h
[tex]V_{y}[/tex] = 804.86*0.44 = 340.14 km/h
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module 1 question 5
If a marathon runner averages 6.6 mi/h, how long does it take him or her to run a 26.22-mi marathon?
h
The time taken to cover the distance during the marathon as shown in the question is 4.0 hours.
What is speed?The term speed has to do with the ratio of the distance that have been covered to the time that have been taken to cover that distance. We know that the distance is a scalar quantity and that the direction of the quantity is not involved. We now need to obtain the speed
Now we have the following;
Speed of the runner = 6.6 mi/h
Distance covered by the runner = 26.22-mi
Speed = distance/time
time = distance/speed
time = 26.22-mi / 6.6 mi/h
= 4.0 hours
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Rank these automobiles based on the magnitude of their momentum before the brakes are applied, from largest to smallest.Rank from largest to smallest. To rank items as equivalent, overlap them. If the ranking cannot be determined, check the box below.
Explanation
The magnitude of the momentum of an object is given by:
[tex]p=mv[/tex]where p is the momentum
m is the mass of the object
v is the mass of the object
so
Step 1
ind the momentum of aeach vehicle
a)
let
mass=1000 Kg
v=20 m/s
replace and calculate
[tex]\begin{gathered} p=mv \\ P=1000\text{ Kg}\cdot20\text{ }\frac{m}{s} \\ P_1=20000Kg\frac{m}{s} \end{gathered}[/tex]b
let
mass=2000 Kg
v=5 m/s
replace and calculate
[tex]\begin{gathered} p=mv \\ P=2000\text{ Kg}\cdot5\text{ }\frac{m}{s} \\ P_2=10000Kg\frac{m}{s} \end{gathered}[/tex]c
let
mass=1000 Kg
v=10 m/s
replace and calculate
[tex]\begin{gathered} p=mv \\ P=1000\text{ Kg}\cdot10\text{ }\frac{m}{s} \\ P_3=10000Kg\frac{m}{s} \end{gathered}[/tex]d)let
mass=500 Kg
v=20 m/s
replace and calculate
[tex]\begin{gathered} p=mv \\ P=500\text{ Kg}\cdot20\frac{m}{s} \\ P_4=10000Kg\frac{m}{s} \end{gathered}[/tex]e)xlet
mass=4000 Kg
v=5 m/s
replace and calculate
[tex]\begin{gathered} p=mv \\ P=4000\text{ Kg}\cdot5\frac{m}{s} \\ P_5=20000Kg\frac{m}{s} \end{gathered}[/tex]f)let
mass=500 Kg
v=10m/s
replace and calculate
[tex]\begin{gathered} p=mv \\ P=500\text{Kg}\cdot10\frac{m}{s} \\ P_6=5000Kg\frac{m}{s} \end{gathered}[/tex]Step 2
ow, raknk the automobiles based on the magnitude of the momentum( from the largest to smallest)
so
(automoblile 1 is the one on the left)
I hope this helps you
What is the force of gravity between two 1039 kg cars separated by a distance of 25.15 m on an interstate highway?
The force of gravity between the two cars is 1.14 x 10⁻⁷ N.
What is force of gravity?
The force of attraction on a body by earth or force of gravity is defined the gravitational pull of the earth on every object on earth.
Mathematically, the gravitational force between two object is given by;
F = Gm₁m₂/r²
where;
G is universal gravitation constantm is mass of the objectsr is the distance of separation of the objects.F = (6.67 x 10⁻¹¹ x 1039 x 1039)/(25.15)²
F = 1.14 x 10⁻⁷ N
Thus, we can conclude that the force of attraction between two objects in the universe increases with decrease in the distance of separation.
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Without adding more sources of light,how can he enhance the light in his salon
Placing lights at either side of the mirror to directly brighten the complexion is the simplest way to help reduce shadows on the face. The temperature of this bulb should be comfortable as well (2,700 to 3,500 Kelvin).
How can I update the lighting in my salon?Lighting in salons should be positioned to eliminate shadows. Placing lights at either side of the mirror to directly brighten the complexion is the simplest way to help reduce shadows on the face. The temperature of this bulb should be comfortable as well (2,700 to 3,500 Kelvin).
Why does lighting in a spa matter?Compared to other spaces or buildings, a beauty salon has a lot more practical uses for lighting. It facilitates work, helps staff members see consumers clearly, and ensures that everything is carried out correctly.
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module 1 question 11
A cheetah can accelerate from rest to a speed of 26.5 m/s in 6.50 s. What is its acceleration?
m/s2
The acceleration of the cheetah is 4.07 m/s^2.
Acceleration is the rate of change of the velocity of an object with respect to time. The unit of acceleration is meter per seconds squared (m/s^2). The equation of acceleration is given below.
a = (v_f - v_i)/t
Where a = acceleration, v_f = final velocity, v_i = initial velocity and t = time.
Here, the final velocity = 26.5 m/s, initial velocity = 0 m/s (cheetah is at rest) and time = 6.5 s. The acceleration of the cheetah will be,
a = (26.5 - 0)/6.5
a = 4.07 m/s^2
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Describe how you can tell if an object is accelerating by observing its motion. Be sure to cover all cases.
If an object is changing its direction or the speed of the object is changing then the object is said to be accelerating.
What is meant by acceleration?Acceleration is the rate at which speed and direction of velocity change over time. A point or object moving straight ahead is accelerated when it accelerates or decelerates. Even though the speed is constant, motion on a circle accelerates because the direction is constantly shifting.
An object is said to be accelerating if its velocity is changing, whether the change in velocity is constant or varies by a fixed amount.
Since acceleration is a vector quantity—which means it has both a magnitude and a direction—it follows that an object is said to be accelerating if its direction is changing.
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A large truck travelling at +17 m/s takes 2.5 seconds to come to a complete stop at a red light. What is the acceleration of the truck?Select one:a.- 6.8 m/s^2b.+ 6.8 m/s^2c.+ 42.5 m/s^2d.- 42.5 m/s^2
The acceleration of the truck is -6.8 m/s².
Given data:
The inital speed is u=17 m/s.
The time taken is t=2.5 s.
The truck come to a compelet stop that means the final speed of truck is zero, i.e., v=0 m/s.
The formula for the acceleration is given by,
[tex]\begin{gathered} a=\frac{v-u}{t} \\ a=\frac{0\text{ m/s-17 m/s}}{2.5\text{ s}} \\ a=-6.8\text{ m/s}^2 \end{gathered}[/tex]Thus, the acceleration of the truck is -6.8 m/s².