Answer:
c
Step-by-step explanation:
Can someone help me out on this problem and show work
Answer: 4230.14
Step-by-step explanation:
The amount that the balance is multiplied by each month is
[tex]\frac{2448}{2040}=1.2[/tex].
So, after t months, the balance is [tex]1700(1.2)^{t-1}[/tex].
Substituting in t=6, we get the balance is
[tex]1700(1.2)^{6-1}=\boxed{4230.14}[/tex], to the nearest hundredth.
In the adjoining figure, ABCD is a trapezium.
If AB = 60cm , AD = 26cm and BC = 25 cm, find the area of given trapezium
The area of the given trapezium is 1781 cm².
What is the area of the trapezium?Area of the trapezium = ½(a + b) × h
Given;
AB = 60cm , AD = 26cm and DC = 77 cm
Area = ½(60 + 77) × 26
Area = ½(137)× 26
Area = 1781 cm²
Hence, the area of the given trapezium is 1781 cm².
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Combine the radicals 4√7+3√28.
O 10√7
O
4√7
0 -2√7
10√14
Answer:
10sqrt(7)
Step-by-step explanation:
[tex]4 \sqrt{7} + 3 \sqrt{28} \\ \\ 4 \sqrt{7} + 3(2 \sqrt{7} ) \\ \\ 4 \sqrt{7} + 6 \sqrt{7} = 10 \sqrt{7} [/tex]
Which represents the solution(s) of the graphed system of equations, y=x²+x-2 and y = 2x - 2?
Answer:
Option 2: (0,-2) and (1,0)
Step-by-step explanation:
Solutions to graphed systems of equations are the places where the graphs overlap/intersect.
For this system of equations, the red and blue graphs overlap at two points.
Since all of the answers are given as ordered pairs, it is important to know what an ordered pair means.
Ordered pairsAn ordered pair, (x,y), is a pair of numbers, written in parentheses, with a comma between them, that represent the coordinates of a point when graphed on a coordinate system. Each coordinate measures the distance in a certain direction from the origin. The origin is the special point at the intersection of the axes. The axes are the dark horizontal and vertical lines with numbers next to them, representing the value at that distance along the axis.
The first coordinate of an ordered pair is the x-coordinate, and measures the horizontal distance from the origin. Points to the right of the origin are defined to have a positive x-coordinate, and points to the left of the origin are defined to have a negative x-coordinate.
The second coordinate of an ordered pair is the y-coordinate, and measures the vertical distance from the origin. Points above the origin are defined to have a positive y-coordinate, and below the origin are defined to have a negative x-coordinate.
The intersectionsLooking directly below the origin, the blue curve and the red line intersect. Since they intersect directly below the origin, the ordered pair there must have an x-coordinate of zero because no left/right movement was required to get to this point. Only a vertical movement was necessary. The number on the vertical axis tells us that this point has a height of "-2", so the ordered pair for this point is (0,-2).
Looking directly to the right from the origin, the blue curve and the red line intersect again. Since they intersect directly to the right of the origin, the ordered pair there must have a y-coordinate of zero because no up/down movement was required to get to this point. Only a horizontal movement was necessary. The number on the horizontal axis tells us that this point has a horizontal value of "1", so the ordered pair for this point is (1,0).
Since the two points of intersection are (0,-2) and (1,0), the correct answer would be the second choice.
A tour company charges a given price per ticket based on the number, n, of people who take the tour. the maximum number of people who are allowed to take the tour is 35. the price per ticket is $20 unless more than 10 people take the tour. if more than 10 people take the tour, the price per ticket is given by the expression: 20- n-10/2 b. harper goes on a tour where the ticket price is $10.50. how many people went on this tour? solve algebraically.
Harper goes on a tour where the ticket price is $10.50 along with 29 people according to the given expression. Solving the given expression for 'n' results in the required number.
How to solve an algebraic expression?Solving an expression algebraically involves basic operations like addition, subtraction, multiplication, and division.
In the expression, add/subtract the constant terms on both sidesMultiply/divide the coefficient of the variable on both sidesSolve for the variable.Calculation:Given that,
A tour company charges a given price per ticket based on the number 'n' of people who take the tour.
The maximum number of people who are allowed to take the tour is 35. I.e., n ≤ 35.
The price per ticket is $20 for n < 10 people and the price per ticket is given by the expression 20-(n-10)/2 for n > 10 people.
Harper goes on a tour where the ticket price is $10.50.
Since the price is less than $20, so the number of people who went on this tour is known by the expression 20-(n-10)/2 for n > 10 people.
So, solving the given expression:
20-(n-10)/2 = $10.50
-(n-10)/2 = 10.50 - 20
-(n-10)/2 = -9.5
(n-10) = 9.5 × 2
n -10 = 19
∴ n = 19 + 10 = 29
Therefore, 29 people went on this tour for a ticket price of $10.50.
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A motorbike is priced at $945.50 Johnson has $ 5000.
How many motorbikes could he buy?
The number of motorbikes is 5
How to determine the number of motorbikes?The given parameters are:
Motorbike = $945.50
Johnson = $5000.
The number of motorbikes is calculated as:
n = Johnson/Motorbike
So, we have:
n = 5000/945.5
Evaluate
n = 5.29
Remove the decimal
n = 5
Hence, the number of motorbikes is 5
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please assist me on this question
Answer:
135 units = x
Step-by-step explanation:
81 is to x as x is to (81 + 144)
81/x = x / 225 cross multiply to get
18225 = x^2
x = 135
1. A motorist takes 30 mins to complete a journey when he travels at 60km/h. How long will it'
take to cover the same distance at 50 km/h?
Answer:
36 minutes
Step-by-step explanation:
Distance , speed and time:Speed = 60 km/hr
time = 30 mins = 30/60 = 1/2 hour
[tex]\sf \boxed{\bf Distance =speed * time}[/tex]
[tex]\sf = 60 * \dfrac{1}{2}\\\\ = 30 \ Km[/tex]
Distance = 30 km and speed = 50 km/hr
[tex]\sf \boxed{\bf Time =\dfrac{Distance}{speed}}[/tex]
[tex]\sf = \dfrac{30}{50}\\\\=\dfrac{3}{5} \ hour\\\\=\dfrac{3}{5}*60\\\\= 3*12\\\\= 36 \ minutes[/tex]
Answer:
0.6 hours
Step-by-step explanation:
• First calculate the distance travelled at 60km/h:
distance = speed x time
= 60 x 0.5
= 30 km
• Now calculate the time taken at 50 km/h:
time = distance/ speed
= 30 / 50
= 0.6 hours
= 0.6 x 60 min
= 36 minutes
List the first four terms of the sequence.
The first four terms of the sequence are -1, 6, -22, 90
What is a sequence?A sequence is an order in which numbers occur in a given group of numbers.
It is also numbers arranged based on a certain rule.
Analysis:
a1 = -1
for n ≥ 2
a2 = -4a1 +2
a2 = -4(-1) + 2 = 4+2 = 6
a3 = -4a2 + 2
a3 = -4(6) + 2 = -24 + 2 = -22
a4 = -4a3 +2
a4 = -4(-22) + 2 = 88 + 2 = 90
In conclusion, the first four terms of the sequence are -1, 6, -22, 90
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Rename 1/10 and 1/4
using the least common denominator.
The renaming of the fractions 1/10 and 1/4 using the least common denominator gives us; 2/20 and 5/20
How to find the Least Common Denominator?To find the least common denominator here, we will just the least term that can divide both denominators. In this case, the least term will be 20. Thus;
1/10 = (1 * 2)/(2 * 10) = 2/20
1/4 = (1 * 5)/(4 * 5) = 5/20
Therefore renaming the fractions 1/10 and 1/4 using the least common denominator gives us; 2/20 and 5/20
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hope this helps, Plato
What type of function is shown in the data in the table below?
Answer:
the function is quadratic because it have (2) turning points which is a sign of the ax² in rhe quadratic equation (ax²+bx+c)
Use the quadratic formula to find both solutions to the quadratic equation
given below.
The solution of the equation are [tex]x = \frac{7 + \sqrt{61}}{6}[/tex] and [tex]x = \frac{7 - \sqrt{61}}{6}[/tex]
How to determine the solution?The equation is given as:
3x^2 - 7x- 1 = 0
The quadratic equation is represented as:
[tex]x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]
So, we have:
[tex]x = \frac{7 \pm \sqrt{(-7)^2 - 4 *3 *-1}}{2*3}[/tex]
Evaluate the expression
[tex]x = \frac{7 \pm \sqrt{61}}{6}[/tex]
Expand
[tex]x = \frac{7 + \sqrt{61}}{6}[/tex] and [tex]x = \frac{7 - \sqrt{61}}{6}[/tex]
Hence, the solution of the equation are [tex]x = \frac{7 + \sqrt{61}}{6}[/tex] and [tex]x = \frac{7 - \sqrt{61}}{6}[/tex]
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What is the value of log 13? Use a calculator. Round your answer to the nearest tenth.
0.1
0.3
1.1
2.6
Answer:
the answer is 1.1
Step-by-step explanation:
log13 =1.113
which is approximately 1.1
The value of given logarithmic expression is 1.1. Therefore, option C is the correct answer.
What are logarithms?In mathematics, the logarithm is the inverse function to exponentiation. That means the logarithm of a number x to the base b is the exponent to which b must be raised, to produce x.
The given logarithmic expression is log13.
The result can be shown in multiple forms.
Exact Form:
log(13)
Decimal Form:
1.11394335....
≈ 1.1
Therefore, option C is the correct answer.
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What is the length of the longest side of a triangle that has the vertices (-2, 1), (5, 1), and (5, 4)?
OA. 65 units
OB. √58 units
OC. 6√65 units
OD. 5√65 units
Answer:
B
Step-by-step explanation:
To find the length of the longest side of the triangle, first sketch the triangle. A graph paper is not needed here.
In this case we have a right-angled triangle, since the ends of the adjacent side has the same y-coordinate of 1 and the opposite side has the same y-coordinate of 5.
In a right-angled triangle, the hypotenuse side is the longest. The length of the hypotenuse side can be found using 2 methods.
1) Pythagoras' Theorem
a² +b²= c²
(adjacent)² +(opposite)²= (hypotenuse)²
Length of adjacent
= 5 -(-2)
= 7 units
Length of opposite side
= 4 -1
= 3 units
(hypotenuse)²
= 7² +3²
= 58
hypotenuse= [tex] \sqrt{58} [/tex]
2) Distance formula
Since we know that the hypotenuse side is the longest, we can simply find the length of the hypotenuse side instead of calculating the length of each side.
[tex]\boxed{{\text{Distance between 2 points}= \sqrt{(y_1 - y_2)^{2} + (x_1 - x_2)^{2} } }}[/tex]
Length of longest side
= distance between (5, 4) and (-2, 1)
[tex] = \sqrt{(4 - 1) {}^{2} + (5 - ( - 2)) {}^{2} } [/tex]
[tex] = \sqrt{3 {}^{2} + {7}^{2} } [/tex]
[tex] = \sqrt{58} [/tex]
Thus, the length of the longest side is [tex] \sqrt{58} [/tex] units.
Can someone please help me on this question
Answer: ? = 72
Step-by-step explanation:
We will set up a proportion to solve.
[tex]\displaystyle \frac{?}{56} =\frac{45}{35}[/tex]
Now, we will cross-multiply.
? * 35 = 56 * 45
35? = 2,520
? = 72
Which is the best approximation for the solution of the system of equations? y = a system of equations. y equals negative startfraction 2 over 5 endfraction x plus 1. y equals 3 x minus 2.x 1 y = 3x – 2
The best approximation for the solution of the system of equations is (0.88,0.65).
Given a system of equations is y=-(2/5)x+1 and y=3x-2.
A system of linear equations consists of two or more equations, and one attempts to solve the equations together.
To find the best approximation solution solve the system of equations.
The given system of equations are
y=-(2/5)x+1 .......(1)
y=3x-2 .......(2)
Firstly, substitute the value of y into equation (1) to find the value of x, we get
3x-2=-(2/5)x+1
Now, we will add (2/5)x in both sides, we get
3x-2+(2/5)x=-(2/5)x+1+(2/5)x
3x-2+(2/5)x=1
Further, we will add 2 on both sides, we get
3x-2+(2/5)x+2=1+2
3x+(2/5)x=3
17x/5=3
Furthermore, we will multiply both sides with 5, we get
5×(17x/5)=3×5
17x=15
Now, divide both sides with 17, we get
17x/17=15/17
x=0.88
Further, we will find the value of y by substituting the value of x in equation (2), we get
y=3(0.88)-2
y=2.65-2
y=0.65
Hence, the best approximation for the solution of the system of equations y=-(2/5)x+1 and y=3x-2 is (0.88,0.65).
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Problem 2
Given: HJ = 5x - 3, JK = 82-9, and KH = 131
Find: x, HJ, and JK
x =
HJ =
JK =
What is the answer.
Answer:
i got 12.2
Step-by-step explanation: (5x-3) +73 =131 is the equation and from that x = 12.2
A sphere has a surface area of 16pi cm³. Find the volume giving your answer in form. Anyone know how to do this question?
Answer:
Your answer should be around 10.7π cm³
Step-by-step explanation:
The surface area formula for a sphere is SA = 4πr^2. The volume formula for a sphere is V=4/3πr^3. Use the given SA to find the value of V.16π=4πr^2 Divide by 4π on both sides. 4 = r^2. r=2 Plug in 2 for r in the equation V=4/3πr^3. Your answer should be around 10.7π cm³
select the correct answer. If f(x)=2x^2-x-6 and g(x)=x^2-4, find f(x) ÷ g(x)
A, 2x + 3/x - 2
B. 2x - 3/x+ 2
C. 2x +3/x+2
D. 2x- 3/x-2
Answer:
[tex]f(x) = {2x}^{2} - 4x - 6 \\ {2x}^{2} - 4x + 3x - 6 \\ = 2x(x - 2) + 3(x - 2) \\ g(x) = {x}^{2} - 4 \\ (x + 2)(x - 2) \\ \frac{f(x)}{g(x)} = \frac{(2x + 3)(x - 2)}{(x + 2)(x - 2)} = \frac{2x + 3}{x + 2} [/tex]
[tex]\underline{\underline{\boxed{ \pink\star \: C.) \: \sf{\frac{2x +3}{x + 2}}}}}[/tex]
━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
Here,
[tex]\sf{f(x) = 2x^2 - x - 6}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: [/tex]
[tex]\longrightarrow\sf{2x^2 - 4x + 3x - 6}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: [/tex]
[tex]\longrightarrow\sf{2x(x-2)+3(x-2)}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: [/tex]
[tex]\longrightarrow\sf{(2x+3)(x-2)}[/tex]
---------------------------------------------------
[tex]\sf{g(x) = x^2 - 4}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: [/tex]
[tex]\longrightarrow\sf{x^2 - 2^2}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: [/tex]
[tex]\longrightarrow\sf{(x+2)(x-2)}[/tex]
Therefore,
[tex]\huge\sf{ \frac{f(x)}{g(x)} = \frac{(2x+3)(x-2)}{(x+2)(x-2)}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: [/tex]
[tex]\longrightarrow \huge\sf{ \frac{2x + 3}{x + 2}}[/tex]
[tex]\boxed{\underline{\color{hotpink}{ \red \star \: ᖇEᒪᗩ᙭GᖇOᗯ \: \: }}}[/tex]
What is the slope of these two equations?
Answer:
8. 0
9. undefined
Step-by-step explanation:
8. 0
> because the y variable is the same for all x-values, this is a horizontal line. Horizontal lines have a slope of 0.
> Thinking of slope as rise over run: we will always rise 0, and run __ from any two points--0 divided by any number is always 0
9. undefined
> because the x variable is always the same, no matter what y variable we graph, we will have the same outcome. So, this would look like a straight line, which have an undefined slope.
> If you think of a slope as rise / run; if you go from any two points, there will be a 0 in the denominator--which is undefined
hope this helps!! have a lovely day :)
Is xxx greater than, less than, or equal to 50^\circ50
∘
50, degrees?
The value of the angle c will be 50°. Option C is correct.
What is angle measurement?An angle measure is the measurement of the angle created by two rays or arms at a shared vertex in geometry. A protractor is used to measure angles in degrees (°).
If the two line segment intersects at each other the angle formed by the intersecting lines will be the same.
From the given digrame,∠x =50°
Hence option C is correct.
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does anyone know how to do these??
Answer:
b)
c=140°
a= 40°
b=40°
c)
p= 60°
q= 60°
r= 120°
d)
a= 65 °
b= 65°
c= 65°
d= 115°
e=65°
Step-by-step explanation:
Hope it helps
-8y=7y-5 direct variation or not
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\textbf{Equation: }[/tex]
[tex]\mathbf{-8y = 7y - 5}[/tex]
[tex]\huge\textbf{Solving for the equation:}[/tex]
[tex]\mathbf{-8y = 7y - 5}[/tex]
[tex]\mathbf{7y - 5 = -8y}[/tex]
[tex]\huge\textbf{SUBTRACT 7y to BOTH SIDES}[/tex]
[tex]\mathbf{-8y - 7y = 7y - 5 - 7y}[/tex]
[tex]\huge\textbf{SIMPLIFY IT!}[/tex]
[tex]\mathbf{-15y = -5}[/tex]
[tex]\huge\textbf{DIVIDE -15 to BOTH SIDES}[/tex]
[tex]\mathbf{\dfrac{-15y}{-15} = \dfrac{-5}{-15}}[/tex]
[tex]\huge\textbf{SIMPLIFY IT!}[/tex]
[tex]\mathbf{y = \dfrac{-5}{-15}}[/tex]
[tex]\mathbf{y = \dfrac{-5\div-5}{-15\div-5}}[/tex]
[tex]\mathbf{y = \dfrac{1}{3}}[/tex]
[tex]\huge\textbf{Met your answer:}[/tex]
[tex]\huge\text{Therefore, your answer should be: \boxed{\mathsf{y = \dfrac{1}{3}}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]how do you solve 32 - 6x = 53?
Answer:
x = - 3.5
Step-by-step explanation:
32 - 6x = 53 ( subtract 32 from both sides )
- 6x = 21 ( divide both sides by - 6 )
x = [tex]\frac{21}{-6}[/tex] = - [tex]\frac{7}{2}[/tex] = - 3.5
[tex]\large\boxed{x=-\frac{7}{2}}[/tex]
To solve for [tex]x[/tex], we need to isolate it on one side of the equation.
The most important part of this is knowing that whatever we do to one side of the equation, we must also do to the other.
Subtract 32 from both sides of the equation.
[tex]\begin{aligned}32-32-6x&=53-32\\-6x&=21\end{aligned}[/tex]
Divide both sides of the equation by [tex]-6[/tex].
[tex]\begin{aligned}\frac{-6x}{-6}&=\frac{21}{-6}\\x&=\boxed{-\frac{7}{2}}\end{aligned}[/tex]
Which of the following terminating decimals is equivalent to StartFraction 3 over 8 EndFraction
The 0.375 terminating decimals are equivalent to 3/8 option second is correct.
What is a fraction?Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.
The fraction is:
= 3/8
After dividing with 8
= 0.375
Thus, the 0.375 terminating decimals are equivalent to 3/8 option second is correct.
The complete question is:
Which of the following terminating decimals is equivalent to 3/8?
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Can someone please explain what an outlier is? it keeps popping up in all of my math questions and it is really confusing me...
Answer:
An outlier is something that is out of place compared to the rest of the group. For example, If you had the numbers 3,4,5,4,3,4, and 19, 19 would be the outlier.
Step-by-step explanation:
An outlier is a number that's far away from the rest of your data.
For example, if we look at the numbers 3, 2, 4, 5, 27, and 1, you can likely consider 27 to be an outlier because it's so far away from the rest of the data.
The specific definition of how far something has to be from the rest of the data to be an outlier depends entirely on the situation, but in general: if a number obviously sticks out from the rest, it's probably an outlier.
Fill in the gaps below:
Answer:
anticlockwise; reflection about x = 0; reflection about y = x - 1
Step-by-step explanation:
To get from A to A', we have to rotate anticlockwise. This rotation would take us around the coordinate plane from the first quadrant to the fourth quadrant to the third quadrant to the second quadrant. Clockwise about (0, -1) would not bring us to A'. To get from A' to A'', we to reflect across the line x = 0. As you can see in the image, the two triangles mirror each other across a vertical line in the center of them, and this vertical line would be x = 0 because both triangles are at least 1 unit away from it (they are equidistant from this line)
A single transformation that could map A onto A'' would be a reflection about y = x - 1. Both triangles happen to meet at this point so you might be able to visualize it. However, we can also test some points to see if this works. First, we can test the right-most point of A (which is the top-most point of A''). This point on A is (6, 0). If this point was reflected across y = x - 1, y would become 6 - 1 or 5, and since y = x - 1 is the same as x = y + 1, x would become 0 + 1 or 1. Indeed, the equivalent point on A'' is (1, 5).
The following graph describes function 1, and the equation below it describes function 2. Determine which function has a greater maximum value, and provide the ordered pair. (1 point)
Function 1
graph of function f of x equals negative x squared plus 8 multiplied by x minus 15
Function 2
f(x) = −x2 + 2x − 3
Function 1 has the larger maximum at (1, 4).
Function 1 has the larger maximum at (4, 1).
Function 2 has the larger maximum at (1, −2).
Function 2 has the larger maximum at (−2, 1).
Finding the vertex of the quadratic functions, the correct statement is:
Function 1 has the larger maximum at (4, 1).
What is the vertex of a quadratic equation?A quadratic equation is modeled by:
[tex]y = ax^2 + bx + c[/tex]
The vertex is given by:
[tex](x_v, y_v)[/tex]
In which:
[tex]x_v = -\frac{b}{2a}[/tex][tex]y_v = -\frac{b^2 - 4ac}{4a}[/tex]Considering the coefficient a, we have that:
If a < 0, the vertex is a maximum point.If a > 0, the vertex is a minimum point.For function 1, we have that:
f(x) = -x² + 8x - 15.
Hence the coefficients are a = -1, b = 8, c = -15, and the vertex is:
[tex]x_v = -\frac{8}{2(-1)} = 4[/tex][tex]y_v = -\frac{8^2 - 4(-1)(-15)}{4(-1)} = 1[/tex]For function 2, we have that:
f(x) = -x² + 2x - 3.
Hence the coefficients are a = -1, b = 2, c = -3, and the vertex is:
[tex]x_v = -\frac{2}{2(-1)} = 1[/tex][tex]y_v = -\frac{2^2 - 4(-1)(-3)}{4(-1)} = -2[/tex]1 > -2, hence the correct statement is:
Function 1 has the larger maximum at (4, 1).
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Quadrilateral ABCD is similiar to quadrilateral EFGH. The lengths of the three longest sides in quadrilateral ABCD are 24 feet, 16 feet, and 12 feet long. If the two shortest sides of quadrilateral EFGH are 9 feet long and 18 feet long, how long is the 4th side on quadrilateral ABCD?
A. 6 feet
B. 12 feet
C. 10 feet
D. 8 feet
The length of the 4th side on quadrilateral ABCD will be D. 8cm.
How to calculate the length?From the information given, we are told that the lengths of the three longest sides in quadrilateral ABCD are 24 feet, 16 feet, and 12 feet long.
In this case, the side will be:
24/16 = 12/x
x = (16 × 12)/24
x = 8
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Which graph represents the function f(x) = |-x - 2|-1?
-6-
Answer:
it is the third one
Step-by-step explanation:
third one