g Incandescent bulbs generate visible light by heating up a thin metal filament to a very high temperature so that the thermal radiation from the filament becomes visible. One bulb filament has a surface area of 30 mm2 and emits 60 W when operating. If the bulb filament has an emissivity of 0.8, what is the operating temperature of the filament

Answers

Answer 1

Answer:

2577 K

Explanation:

Power radiated , P = σεAT⁴ where σ = Stefan-Boltzmann constant = 5.6704 × 10⁻⁸ W/m²K⁴, ε = emissivity of bulb filament = 0.8, A = surface area of bulb = 30 mm² = 30 × 10⁻⁶ m² and T = operating temperature of filament.

So, T = ⁴√(P/σεA)

Since P = 60 W, we substitute the vales of the variables into T. So,

T = ⁴√(P/σεA)

= ⁴√(60 W/(5.6704 × 10⁻⁸ W/m²K⁴ × 0.8 × 30 × 10⁻⁶ m²)

= ⁴√(60 W/(136.0896 × 10⁻¹⁴ W/K⁴)

= ⁴√(60 W/(13608.96 × 10⁻¹⁶ W/K⁴)

= ⁴√(0.00441 × 10¹⁶K⁴)

= 0.2577 × 10⁴ K

= 2577 K


Related Questions

Derive an expression for Root Mean Square (RMS) cur-rent through the capacitor as a function of the applied voltage amplitude. Recall that the RMS value of a sinewave with unity amplitude is 0.707.

Answers

Answer:

hello your question is incomplete attached below is the complete question

answer: Irms = 0.707*2[tex]\pi FcVo\\[/tex]

Explanation:

To derive the expression for the root mean square ( RMS ) current through the capacitor as a function of the applied voltage amplitude

RMS value of a sine wave with unity amplitude = 0.707

when the dc component is removed the i.e. the RMS signal = standard deviation ( signal )

attached below is the derivation

what are 2 bandwagon effect that can happen on students

Answers

Answer:

Below

Explanation: 1.Katie likes to read and would rather do that than play sports. Her friends make fun of her and tell her that reading is for nerds. Katie stops reading so much and starts to play sports more.

2. Marcus wants to go to a small community college close to home, but most of the kids in his class are applying to larger colleges out of state. Marcus decides that he should also apply to those colleges.

Three people pull simultaneously on a stubborn donkey. Jack pulls eastward with a force of 83.5 N, Jill pulls with 93.3 N in the northeast direction, and Jane pulls to the southeast with 121 N. (Since the donkey is involved with such uncoordinated people, who can blame it for being stubborn

Answers

Answer:

235.8 N

Explanation:

Given that

Jack

83.5 east

Jill

93.3√2/2 east

93.3√2/2 north

Jane

121√2/2 east

121√2/2 south

From the above listed, we can calculate the total force component on x axis to be

Fx = 83.5 + 93.3√2/2 + 121√2/2

Fx = 83.5 + 65.97 + 85.56

Fx = 235 N (east)

Again, we calculate the total force component on y axis to be

Fy = 93.3√2/2 - 121√2/2

Fy = 65.97 - 85.56

Fy = -19.59 N (south)

Finding the resultant, we have

F = √(Fx²+Fy²)

F = √(235² + (-19.59)²)

F = √55225 + 383.7681

F = √55608.7681

F = 235.8 N

When testing a home for radon, where is the most likely place for the highest detected level? A) the basement, due to ground seepage B) the first floor, due to doors to the outside allowing radon to enter C) the second floor, due to the chimney effect D) all areas will have equal levels of radon E) radon cannot be tested because it is odorless, colorless, and tasteless

Answers

Answer:

A

Explanation:

ive been buying loui i been shoppin

Answer: E) radon cannot be tested because it is odorless, colorless, and tasteless

Explanation:

edge2021

Sandy is riding a bicycle with tires that have a diameter of 650 mm. A small twig, caught in the spokes, causes the tire to click once each revolution. Of Sandy hears 8 such clicks every 3 seconds then how fast is she cycling (to the nearest km/hr)

Answers

Answer:

Explanation:

Sandy hears 8 such clicks every 3 seconds and a small twig, caught in the spokes, causes the tire to click once each revolution that means the wheel of the cycle is rotating at 8 rotations every 3 seconds or 8/3 rotation per second . In each rotation , it moves distance equal to its circumference .

circumference = 2π r = 2 x 3.14 x .65 / 2 m

= 2.041 m

In 8/3 rotation , distance covered = 8/3 x 2.041 = 5.44 m

So speed of cycle is 5.44 m per second

5.44 x 60 x 60 m per hour

19584 m per hour

= 19.584 km per hour .

= 20 km per hour approx.

2. Which of the following items would be the WORST conductor of electricity?
A. A steel rod
B. A copper wire
C. An aluminum bat
D. A rubber band

Answers

Answer: a rubber band

Explanation: A rubber band has no conductivity and no electricity would be able to flow whereas steel and copper and aluminum would be able to allow electricity to flow due to how they are built

Tim has a weight of 500N, which his half of his father's
weight. He, his father and his uncle sit on a see saw. If
both Tim and his father sit on the right ended of the
see saw, 5m from the pivot, his uncle's weight is the
same his fathers. Where should Tim's uncle sit in order
to achieve a state of balance?​

Answers

Answer:

3.75m on the left end

Explanation:

Given data

Tim's  weight = 500N= 0.5kN

Tim's fathers weight= 500*2= 1000N= 1kN

Tim and the fathers weight = 500+1000= 1500N= 1.5kN

Tim's uncle weight= 1.5kN

Length of seesaw= 5m

let the distance  Tim's uncle sits be x

We know that summation of clockwise moment equals the summation of anticlockwise moment

Taking moment about the center of the seesaw

1.5*2.5= 1*x

3.75= 1x

Divide boths sides by 1

x= 3.75/1

x= 3.75m

Hence Tim's uncle will sit 3.75m on the left end

Complete the following statement: Momentum will be conserved in a two-body collision only if a both bodies come to rest. b the internal forces of the two body system cancel in action-reaction pairs. c the kinetic energy of the system is conserved. d the net external force acting on the two-body system is zero. e the collision is perfectly elastic.

Answers

Answer:

d the net external force acting on the two-body system is zero

Explanation:

The net external force acting on the two-body system is zero .

During a collision , two internal forces appear on two bodies in opposite directions separately . As they act on each object separately , they do not cancel each other . But the net force on two body system is zero . Total momentum is always conserved during collision because no external force is involved . Collision is not always elastic .

a block of mas \( m \) = 4.8 kg slides head on into a spring of spring constant \( k \) = 430 N/m. When the block stops, it has compressed the spring by 5.8 cm. The coefficient of kinetic friction between block and floor is 0.28. \( (g =9.8m/s^2) \)

Answers

Answer:

See explanation below

Explanation:

The question is incomplete. The missing part of this question is the following:

"While the block is in contact with the spring and being brought to rest, what are (a)the work done by the spring force and (b) the increase in thermal energy of the blockfloor system? (c) What is the blocks speed just as it reaches the spring?"

According to this we need to calculate three values: Work, Thermal Energy and Speed of the block when it reaches the spring.

Let's do this by parts.

a) Work done by the spring:

In this case, we need to apply the following expression:

W = -1/2 kx²  (1)

We know that k = 430 N/m, and x is the distance of compressed spring which is 5.8 cm (or 0.058 m). Replacing that into the expression:

W = -1/2 * 430 * (0.058)²

W = -0.7233 J

b) Increase in thermal energy

In this case we need to use the following expression:

ΔEt = Fk * x   (2)

And Fk is the force of the kinetic energy which is:

Fk = μk * N   (3)

Where μk is the coeffient of kinetic friction

N is the normal force which is the same as the weight, so:

N = mg (4)

Let's calculate first the Normal force (4), then Fk (3) and finally the chance in the thermal energy (2):

N = 4.8 * 9.8 = 47.04 N

Fk = 0.28 * 47.04 = 13.1712 N

Finally the Thermal energy:

ΔEt = 13.1712 * 0.058

ΔEt = 0.7639 J

c) Block's speed reaching the spring

As the block is just reaching the speed, the initial Work is 0. And the following expression will help us to get the speed:

V = √2Ki/m   (5)

And Ki, which is the initial kinetic energy can be calculated with:

Ki = ΔU + ΔEt   (6)

And ΔU is the same value of work calculated in part (a) but instead of being negative, it will be positive here. So replacing the data first in (6) and then in (5), we can calculate the speed:

Ki = 0.7233 + 0.7639 = 1.4872 J

Finally the speed:

V = √(2 * 1.4872) / 4.8

V = 0.7872 m/s

Hope this helps

What three factors affect the viscosity of magma

Answers

1. The temperature
2. The dissolved gases it contains
3. It’s chemical composition

The factors that affect the viscosity of magma include temperature, crystal and rock fragments (composition), and the different dissolved gases.

What is magma?

It is a mixture of solid, volatile and liquid materials.

Characteristics of the viscosity of magma

It is a mixture of chemical components that form high-temperature silicates.

It includes substance in solid, liquid and gaseous state due to the temperature of the magma which is above the melting points of certain components.

Volcanic eruptions often occur when the vapor pressure of the gases becomes greater than the pressure exerted by the solid rocks that keep the magma confined.

Therefore, we can conclude that the fluidity or viscosity of magma depends on its chemical composition and, in particular, the liquids and solids that the magma contains and the various gases dissolved in it.

Learn more about viscosity of magma here: https://brainly.com/question/20621986

Consider a Carnot cycle executed in a closed system with 0.6 kg of air. The temperature limits of the cycle are 300 and 1100 K, and the minimum and maximum pressures that occur during the cycle are 20 and 3000 kPa. Assuming constant specific heats, determine the net work output per cycle.

Answers

Answer:

63.8 kJ

Explanation:

The net work output per cycle is the difference in heat input and heat output. The heat input and heat output are expressed as a function of volume ratios, while volume is expressed as a function of pressure and pressure as a function of temperature.

R = 287 J/kg.K, k = 1.4

Hence the net work input (W) is given as:

[tex]W=Q_{in}-Q_{out}\\\\W=mR[T_Hln\frac{V_2}{V_1} -T_Lln\frac{V_3}{V_4}]\\\\=mR[T_Hln\frac{P_1}{P_2} -T_Lln\frac{P_4}{P_3}]\\\\=mR[T_Hln(\frac{P_1}{P_3}(\frac{T_L}{T_H} )^\frac{k}{k-1}) -T_Lln(\frac{P_1}{P_3}(\frac{T_L}{T_H} )^\frac{k}{k-1})]\\\\=mR(T_H-T_L)ln(\frac{P_1}{P_3}(\frac{T_L}{T_H} )^\frac{k}{k-1})\\\\Substituting\ values:\\\\W=mR(T_H-T_L)ln(\frac{P_1}{P_3}(\frac{T_L}{T_H} )^\frac{k}{k-1})=0.6*287(1100-300)ln(\frac{3000*10^3}{2-*10^3}(\frac{300}{1100} )^\frac{1.4}{1.4-1})\\\\[/tex]

[tex]W=63.8\ kJ[/tex]

An unstrained horizontal spring has a length of 0.29 m and a spring constant of 180 N/m. Two small charged objects are attached to this spring, one at each end. The charges on the objects have equal magnitudes. Because of these charges, the spring stretches by 0.021 m relative to its unstrained length. Determine (a) the possible algebraic signs and (b) the magnitude of the charges.

Answers

Answer:

A) they both have the same algebraic sign

B)6.377×10^-6 C

Explanation:

From columb's law, the force acting on both charges can be expressed as

F=( kq1*q2)/r^2

Where F= electrostatic force

r= distance between the charges

q1 and q2= charges

The force acting on a spring can be expressed as

F= kx..................eqn(2)

Where

K= spring constant = 180 N/m.

x= stretch of the string= 0.021m

Substitute the values into eqn (2)

F= (180×0.021)

F= 3.78N

If we compare with spring force,

Hence, F( electrostatic) = 3.78N

From

F=( kq1*q2)/r^2 ..............eqn(1)

Where

r= (0.29 m + 0.021m)= 0.311m

K= the electrostatic constant= 8.99×10^9 kg⋅m3⋅s−2⋅C−2.

If we substitute the values we have

Since the charges are the same, then

kq1 and q2 equals "q"

3.78= (8.99×10^9 ×q^2)/(0.311)^2

Making q^2 subject of the formula

3.78× (0.311)^2 = 8.99×10^9 × q^2

q^2= [(0.311)^2 × 3.78]/8.99×10^9

q^2= 40.668×10^-12

q=√40.668×10^-12

q= 6.377×10^-6 C

(a) the possible algebraic signs

They have the same algebraic sign

(b) the magnitude of the charges.

6.377×10^-6 C

The moon has a gravitational field strength (acceleration due to gravity) that is about 1/6 that of

Earth's. What is the gravitational field strength (acceleration due to gravity) on the moon?

Answers

Answer:

The gravitational field strength (acceleration due to gravity) on the moon is 1.63 m/s²

Explanation:

From the question, the moon has a gravitational field strength (acceleration due to gravity) that is about 1/6 that of  Earth's.

To determine the gravitational field strength (acceleration due to gravity) on the moon, we will multiply the Earth's gravitational field strength (acceleration due to gravity) by 1/6.

Earth's gravitational field strength = 9.8 m/s²

∴ Moon's gravitational field strength = 1/6 × 9.8 m/s²

Moon's gravitational field strength  = 1.63 m/s²

Hence, the gravitational field strength (acceleration due to gravity) on the moon is 1.63 m/s².

The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 4.0 rev/s in 9.0 s. At this point, the person doing the laundry opens the lid, and a safety switch turns off the washer. The tub slows to rest in 15.0 s. Through how many revolutions does the tub turn during this 24 s interval

Answers

Answer:

48 rev

Explanation:

a) we can calculate the distance covered by the tube using the formula:

θ = (ω + ωo)t/2

where ω is the final angular speed, θ is the distance covered, t is the time taken, ωo is the initial angular speed.

Firstly, we calculate the distance covered from 0 to 9 s then from 9s to 24 s.

within 9s, the tub runs from rest (0) to 4 rev/s, hence:

t = 9s, wo = 0, w = 4 rev/s = (4 * 2π) rad/s = 8π rad/s. Hence:

θ = (ω + ωo)t/2 = (0 + 8π)9 / 2 = 36π rad

θ = 36π rad = (36π)/2π rev = 18 rev

Also, within 15 s, the tub runs from 4 rev/s to rest, hence:

t = 15 s, wo = 4 rev/s = 8π rad/s, w = 0 rad/s. Hence:

θ = (ω + ωo)t/2 = (8π + 0)15 / 2 = 60π rad

θ = 60π rad = (60π)/2π rev = 30 rev

Therefore the total revolutions by the tube during 24 s interval = 30 rev + 18 rev = 48 rev

please help asap!!

Explain the movement of a roller coaster in terms of potential and kinetic energy? When are these energies thegreatest? Smallest? Are they ever the same?​

Answers

Answer:

Potential energy: Greatest at the top of the hill

Kinetic energy: Greatest at the bottom of the hill

The two meet at some point on the way down!

Explanation:

Potential energy is energy that represents an object's potential for motion. Kinetic energy is that object's energy during motion. They're two sides of the same coin, and in fact, their sum gets a special name: mechanical energy. Potential energy builds up in reaction to working against certain forces - in the case of the roller coaster, that primary force is gravity. Gravity exerts a downward force on the roller coaster, and it takes work to pull it up the hill.

When it reaches the peak, the coasters potential energy is at its highest, and the moment it crests over the hill and begins its descent, that gravitational potential energy starts converting into kinetic energy: the coaster starts accelarating down the track, and the potential energy decreases at the same rate that the kinetic energy increases.

At the bottom of the hill, all of that potential energy has become kinetic energy, and the coaster zooms along the track, hopefully not giving too many riders nausea

A disk is rotating with an angular velocity function given by ω=Kt+L. What is the angular acceleration of the disk at t=T ?

Answers

Answer:

Angular acceleration of the disk ∝ = K

Explanation:

Given that;

Angular velocity function given by ω = Kt + L

Angular acceleration of the disk at t=T is = ?

Now,

Angular velocity;

ω = Kt + L

Angular acceleration is;

∝ = dω / dt

= [tex]\frac{d}{dt}[/tex] ( Kt + L )

At t = T

∝ = K

Because  ∝  is not dependent on t

Therefore

Angular acceleration of the disk ∝ = K

what is the direction of the third force that would cause the box to remain stationary on the ramp ?

Answers

An arrow pointing from the bottom of the ramp to the top, I assume it would be friction.

The arrow on the bottom pointing down due to friction the bow would not be able to go down the ramp

* Psychology

Match the types of psychoactive drugs to their functions,

depressants

stimulants

amphetamines

hallucinogens

to excite neural activity and temporarily

elevate awareness

to increase dopamine activity and produce

schizophrenic-like paranoid symptoms

>

to inhibit the function of the central nervous

system and neural activity

to distort perceptions and effects on thinking

Answers

Answer:

See explanation below

Explanation:

Psychoactive drugs are drugs that affect the central nervous system. They alter cognitive function by changing mood and consciousness.

Examples;

Depressants: Inhibit the function of the central nervous system and neural activity.

Stimulants: Excite neural activity and temporarily elevate awareness.

Amphetamines: Increase dopamine activity and produce schizophrenic-like symptoms.

Hallucinogens: Distort perceptions and effects on thinking.

A drug is any substance that alters how the body functions.

What is a drug?

A drug is any substance that alters how the body functions. There are different types of drugs that affect different parts of the body.

We shall now explain the following classifications of drugs;

depressants - to inhibit the function of the central nervousstimulants - elevate awarenesshallucinogens - to distort perceptions and effects on thinkingamphetamines - schizophrenic-like paranoid symptoms

Learn more about drugs: https://brainly.com/question/6022349

Charlotte is driving at 66.5 mi/h and receives a text message. She looks down at her phone and takes her eyes off the road for 3.47 s. How far has Charlotte traveled in feet during this time

Answers

Answer:

the distance traveled by Charlotte in feet is 338.44 ft

Explanation:

Given;

speed of Charlotte, u = 66.5 mi/h

time of motion, t = 3.47 s

The distance traveled by Charlotte in feet is calculated as;

[tex]Distance = Speed \ \times \ time \\\\D = ut\\\\D = (\frac{66.5 \ mi}{h} \times \frac{5280 \ ft}{1 \ mi} \times \frac{1 \ h}{3600 \ s} )(3.47 \ s)\\\\D = 338.44 \ ft[/tex]

Therefore, the distance traveled by Charlotte in feet is 338.44 ft

Janice has just measured the density of an object. Which value is possible? (Density: D = )

Answers

Explanation:

Density is an intensive property of matter.

It is the mass per unit volume of a substance and it is expressed mathematically below:

          Density  = [tex]\frac{mass}{volume}[/tex]  

Mass is the amount of matter present within a substance

Volume is the space a substance occupies

So, density is directly proportional to the mass of a body and inversely related to the volume it occupies.

The packing of a substance is very important for determining the density values .

Followed by the previous question: presume that the electron performs a uniform circular motion around the hydrogen nucleus. What is the magnitude of the centripetal acceleration in m/sec2? (radius of the circle LaTeX: 5\times 10^{-11}5 × 10 − 11m; period of the motion LaTeX: 1.5 \times 10^{-16}1.5 × 10 − 16sec) Group of answer choices

Answers

Answer:

[tex]A_c=87.73*10^{21}m/s[/tex]

Explanation:

From the question we are told that

[tex]r=5\times 10^{-11}[/tex]

[tex]T=1.5 \times 10^{-16}[/tex]

Generally the equation for velocity is mathematically given as

[tex]Velocity (v)=\frac{2 \pi r}{t}[/tex]

[tex]V=\frac{2 \pi (5*10^{-11})}{1.5*10^{-16}}[/tex]

[tex]V=\frac{2 \pi (5*10^{-11})}{1.5*10^{-16}}[/tex]

Generally the equation for Centripetal acceleration is mathematically given as

[tex]A_c=\frac{V^2}{r}[/tex]

[tex]A_c=(\frac{20.944*10^5)}{r5*10^{-11}}[/tex]

[tex]A_c=87.73*10^{21}m/s[/tex]

Using equations, determine the temperature, pressure and density of the air for a aircraft flying at 19.5 km. Is this aircraft subsonic or supersonic

Answers

Answer:

a) - 72.5°c

b) pressure = 3625.13 Pa

c) density =  0.063 kg/m^3

d) it is a subsonic aircraft

Explanation:

a) Determine Temperature

Temperature at 19.5 km ( 19500 m )

T = -131 + ( 0.003 * altitude in meters )

  =  -131 + ( 0.003 * 19500 ) = - 72.5°c

b) Determine pressure and density at 19.5 km altitude

Given :

Po (atmospheric pressure at sea level )  = 101kpa

R ( gas constant of air ) = 0.287 KJ/Kgk

T = -72.5°c ≈ 200.5 k

pressure = 3625.13 Pa

hence density = 0.063 kg/m^3

attached below is the remaining part of the solution

C) determine if the aircraft is subsonic or super sonic

Velocity ( v ) = [tex]\sqrt{CRT}[/tex]  =  [tex]\sqrt{1.4*287*200.5 }[/tex] = 283.8 m/s

hence it is a subsonic aircraft

the visible light spectrum ranges between what rays

Answers

The visible spectrum of light ranges between 380 and 700 nanometers :)

A car traveling west at 15 m/s and speeds up to 20 m/s west in 5 seconds. Why is the acceleration of the car?

Answers

Answer:

1 m/s

Explanation:

5m/s change in velocity, divided by 5 seconds= 1 meter/second/second

change in velocity/change in time

Acceleration = (change in velocity) / (time for the change)

that's = (change in speed and its direction) / (time for the change)

Change in velocity = (ending velocity) - (starting velocity)

Change in velocity = (20 m/s west) - (15 m/s west)

Change in velocity = 5 m/s west

Acceleration = (5 m/s west) / (5 seconds)

Acceleration = 1 m/s west


Surface currents are on the
of the Earth's oceans

Answers

Surface currents, which make up only 8% of all water in the ocean, are generally restricted to the upper 400 m (1,300 ft) of ocean water, and are separated from lower regions by varying temperatures and salinity which affect the density of the water, which in turn, defines each oceanic region.

A fish finder uses a sonar device that sends 20,000-Hz sound pulses downward from the bottom of the boat, and then detects echoes. If the maximum depth for which it is designed to work is 85 m, what is the minimum time between pulses (in fresh water)?

Answers

Answer:

0.3106 seconds

Explanation:

Frequency= 20,000-Hz

The speed of echoes sounds can be calculated using the expression below;

Y= ( 2x/t) ...........................eqn(1)

t= overall time taken

x = maximum depth = 230m

Y= speed of echoes sounds

Speed of sound in water= 1,481 m/s which is a constant with little variation.

If we substitute the given values into eqn(1) we have

1481 = (2× 230)/ t

1481 × t= 460

t=460/1481

t=0.3106 seconds

Hence, the minimum time between pulses (in fresh water) is 0.3106 seconds

A ratio is another name for a decimal true or false

Answers

True....................

Need help can anyone help me with this collision problem

Answers

Answer:

4 m/s

Explanation:

From the question given above, the following data were obtained:

Mass of 1st cart (m₁) = 20 kg

Initial velocity of 1st cart (u₁) = +6 m/s

Mass of 2nd cart (m₂) = 30 kg

Finally velocity of both cart (v) = 0 m/s

Initial velocity of 2nd cart (u₂) =?

The initial velocity of the 2nd cart can be obtained as follow:

m₁u₁ – m₂u₂ = v(m₁ + m₂)

(20 × 6) – (30 × u₂) = 0 (20 + 30)

120 – 30u₂ = 0(50)

120 – 30u₂ = 0

Collect like terms

– 30u₂ = 0 – 120

– 30u₂ = – 120

Divide both side by –30

u₂ = –120 / –30

u₂ = 4 m/s

Thus, the 2nd (i.e the 30 kg) cart was initially moving with a velocity of 4 m/s.

Which of the following is NOT a step used to perform a scientific inquiry

Answers

Answer:

b. Designing an uncontrolled experiment.

Explanation:

They always have it controlled.

Answer:

B. Designing an uncontrolled experiment.

Explanation:

Correct Answer!!!!!!

Unpolarized light of intensity 30 W/cm2 is incident on a linear polarizer set at the polarizing angle θ1 = 22 ∘. The emerging light then passes through a second polarizer that is set at the polarizing angle θ2 = 162 ∘. Note that both polarizing angles are measured from the vertical. What is the intensity of the light that emerges from the second polarizer?

Answers

Answer:

I₂ = 8.80 W/cm²

Explanation:

To solve this exercise we need to apply the Malus's law.

First, when the light gors through the first polarizer which is linear, intensity is always cut in half, therefore:

I₁ = I / 2   (1).

Applying this, we have:

I₁ = 30 / 2 = 15 W/cm²

Now, we can calculate the intensity of the light, after it passes through the second polarizer. The Law of Malus states that light intensity will be:

I₂ = I cos²Ф   (2)

Where Ф, is the difference between the angle of the first polarizer and the second. In this way we have:

Ф = α - β

Ф = 162 - 22 = 140°

Now, applying Malus's law we have:

I₂ = 15 cos²140°

I₂ = 8.80 W/cm²

Hope this helps

Other Questions
Read these lines from "lf" by Rudyard Kipling. The first three lines are an example of If you can dream - and not make dreams your master; If you can think - and not make thoughts your aim; If you can meet with Triumph and Disaster And treat those two impostors just the same; O dialogue O repetition O stanzas. O onomatopeia Deborah bought a computer for 25% off the list price. If the list price is $2,428, how much did Deborah spend? Refer to your Expeditions in Reading book for a complete version of this text.Based on Solar Power for Public Buildings, which answer best states the authors position on the use of solar power in California?A The use of solar energy will double the pollution produced in California.B The states tap water will be purer if processed in solar-powered plants.C Increasing the use of solar power will positively impact the environment.D Solar panels remove most of the toxic chemicals found in the atmosphere. how is the following written with only one exponent?a^3 . a^5 solve the equation PLZ I need a good grade American MadafokerHELP ,!!!No speak englishNo hablo ingles xd Students running a food drive have collected their goal amount of canned goods. Over the weekend, volunteers collect an additional 18% of the goal. Write an expression to represent the total percentage of their goal collected in two different ways. Calculate the perimeter of this shape.12 cm18 cm Question 7(Multiple Choice Worth 1 points)(05.02 MC)A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of standard Eskimo dogs are normally distributed, what range of weights would 99.7% of the dogs have? Approximately 2634 pounds Approximately 2436 pounds Approximately 2832 pounds Approximately 2931 pounds What is the standard algorithm PLEASE HELP ME ON THIS THE ANSWERS ARE 1/3 cm/s, 1/2 cm/s, 2/3 cm/s, and 3/2 cm/s HELP PLS PLSSSSSASAP Each day that a library book is kept past its due date, a $0.30 fee is charged at midnight. Which ordered pair is aviable solution if x represents the number of days that a library book is late and y represents the total fee?O (-3,-0.90)O(-2.5, -0.75)O(4.5, 1.35)O (8, 2.40)I need the answer mate Frankenberger Company, which uses a weighted-average process-costing system, had 7,000 units in production at the end of the current period that were 60% complete. Material A is introduced at the beginning of the process; material B is introduced at the end of the process; and conversion cost is introduced evenly throughout manufacturing. Equivalent-unit production costs follow. Material A: $12.50 Material B: $2.00 Conversion cost: $6.60 The cost of the company's ending work-in-process inventory is: This is to all the people who are self cautious and think your not good enough...STOP PUTTING ALL THIS STUFF ON YOURSELF.... you are beautiful and nobody can ever change that about you. You are loved. Don't ever change yourself bc of someone else. If they love u than they should love the REAL you not the you that you wanna be or the you that they think you should be. Remember God loves you and so do i unconditionally. We are all human and make mistakes and have regrets in life that we cant take back or wish we can change but we cant. You are yourself and nobody else dont wanna be the popular girl or guy in class wanna be YOURSELF. Their life may seem perfect but its not its really not. We all have made mistakes just some ppl don't show it. Love yourself no matter what other ppl tell you. Have a wonderful day and just know that you are loved. I hope u have a wonderful life and year and may your family and yourself and friends be safe The image shows a bar graph.A bar graph shows a series of 4 vertical bars along an x and y axis.In which scenarios would using this graph be best for a presentation? Check all that apply.showing change in a communitys average median age over a centurycomparing the percentages of the types of pets owned in a community showing how the worlds shark population has changed over 50 yearscomparing the number of men and women who earned engineering degrees in a decadeshowing the percentages of the various religions practiced in Indonesia Below are certain events that took place at Hazzard, Inc., last year: Collected cash from customers. Paid cash to repurchase its own stock. Borrowed money from a creditor. Paid suppliers for inventory purchases. Repaid the principal amount of a debt. Paid interest to lenders. Paid a cash dividend to stockholders. Sold common stock. Loaned money to another entity. Paid taxes to the government. Paid wages and salaries to employees. Purchased equipment with cash. Paid bills to insurers and utility providers. Required: Indicate how each of the transaction would be classified on a statement of cash flows. Place an X in the Operating, Investing, or Financing column as appropriate. Question 27 (1 point)The relationship between the amount of inputs and outputs is known as How do you get from 4 to 4/3 Kelly has 7 days to read 60 pages of a book for school. She plans to read 8 pages a night for 6 nights.What percent of the assigned pages will she have left to read on the last night?