for this section of the lab, you will make a model of an expanding universe and record data about distances between galaxies as your universe expands. 1. take one of the white balloons and blow it up about the size of your clinched fist. do not tie the balloon but secure your universe with a plastic balloon clip so no air can escape. this is

A plastic stopper in a flask can help reduce heat loss in several ways. Some of the main mechanisms by which a plastic stopper can help to reduce heat loss include:

Overall, a plastic stopper in a flask can help to reduce heat loss by providing insulation, creating an airtight seal, and slowing the transfer of heat through its thermal conductivity. These mechanisms can help to keep the liquid hot for a longer period of time. ;)

If a resistance of 500 ohms makes the ohmmeter pointer deflect to its scale, then the resistance that would cause the pointer to deflect to the scale of the ohmmeter would be equal to the range of the ohmmeter.

Generally, The range of an ohmmeter refers to the range of resistances that it is designed to measure. If the ohmmeter has a range of 0 to 500 ohms, then a resistance of 500 ohms would cause the pointer to deflect to the scale of the ohmmeter.

If the ohmmeter has a range of 0 to 1,000 ohms, then a resistance of 500 ohms would not cause the pointer to deflect to the scale of the ohmmeter.

It is important to note that the range of an ohmmeter is typically marked on the front panel or in the user manual.

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The unit vector in the direction of the vector 6i+8j is [tex]\frac{\sqrt{10}}{10} 3i-j[/tex]

Unit vectors are vectors whose magnitude is exactly 1 unit. These unit vectors are commonly used to indicate a direction, with a scalar coefficient providing the magnitude. It is also known as the Direction Vector.

A unit vector x in the direction of x is given by

[tex]x=\frac{x}{|x|}[/tex]

In this case, we have

[tex]|v|=\sqrt{6^{2}+2^{2} }[/tex]

=√40

=2√10

So a unit vector in the direction of v will be equal to as follows

[tex]v=\frac{1}{2\sqrt{10} } 6i-2j[/tex]

Taking 2 as a common from 6i - 2j, we get

[tex]v=\frac{1}{\sqrt{10} } 3i-j[/tex]

To rationalize the denominator, we will multiply √10 in the numerator as well as the denominator. After this, we will get

[tex]\frac{\sqrt{10}}{10} 3i-j[/tex]

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The rings must look much the same today as they did shortly after Saturn formed.

The Rings of Saturn:

The Saturnian ring system is the largest ring system in the Solar System. They are made up of innumerable tiny particles that circle Saturn and range in size from micrometers to meters. With a very small amount of stony material, the ring particles are virtually exclusively formed of water ice. Regarding how they form, there is still no agreement. Newer evidence from Cassini indicates that the rings developed relatively late, despite theoretical models suggesting they were likely to have formed early in the Solar System's history.

It is believed that the fragments of comets, asteroids, or shattered moons that broke apart before they reached Saturn and were blasted apart by the planet's strong gravity make up Saturn's rings. They are composed of countless quantities of tiny pieces of rock and ice that have been dusted with other substances.

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A Doppler radar determines precipitation velocity by measuring changes in the frequency of the reflected radio wave.

Devices for Doppler microwave detection send a steady stream of low-energy microwave radiation toward a target location, then they examine the reflected signal. When the microwave source and the vehicle are moving relative to one another, the detector detects a change in the frequency of the waves that results.

The Doppler effect, also known as the Doppler shift, is a term used to explain changes in frequency caused by moving sources of sound or light with regard to an observer. As the source gets closer to the observer, the waves it is emitting become compressed and have a greater frequency.

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(a) The student feels heavy weighted.

(b) Magnitude of the force at lowest point = 799 N

(c) Highest magnitude = 1183 N

(d) Lowest magnitude = 159 N

The wheel rotates in the circular direction and while rotating the force tend to be at the center of the motion. This is called centrifugal force.

A

Centrifugal force pushing student upwards at the top Fc = (671 - 543)N = 128N

B

At the bottom, an equal centrifugal force Fb acts downwards on the student giving a total of :

Fc + 671 = 128 + 671 = 799N

C

The total force at the top when the centrifugal force is quadrupled = 671+ (4×128)

= (671 + 512 )N = 1183 N

D

The centrifugal force is quadrupled when speed is doubled ,therefore, the total force at the top = 671 - (4× 128)

= (671 - 512)N = 159N

Therefore, the above magnitudes can be found out by the use of centrifugal force.

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(a) The student feels heavy weighted.

(b) Magnitude of the force at lowest point = 799 N

(c) Highest magnitude = 1183 N

(d) Lowest magnitude = 159 N

The wheel rotates in the circular direction and while rotating the force tend to be at the center of the motion. This is called centrifugal force.

Centrifugal force pushing student upwards at the top Fc = (671 - 543)N = 128N

At the bottom, an equal centrifugal force Fb acts downwards on the student giving a total of :

Fc + 671 = 128 + 671 = 799N

The total force at the top when the centrifugal force is quadrupled = 671+ (4×128)

= (671 + 512 )N = 1183 N

The centrifugal force is quadrupled when speed is doubled ,therefore, the total force at the top = 671 - (4× 128)

= (671 - 512)N = 159N

Therefore, the above magnitudes can be found out by the use of centrifugal force.

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The addition of 5th bulb connected in parallel with the first four bulbs will leave the illumination produced by bulbs in series unchanged (option d)

The relation between resistance, current, and voltage is given by:

I = V / R

Where:

I = current

V = voltage

R = resistance

In the given problem, all bulbs have the same resistance.

- 4 bulbs connected in series.

Let Is be the current when the 4 bulbs are connected in series. Then:

Is = V/4R

- Added the 5th bulb in parallel with the first four

The equivalent resistance will be 4/5 R and the current drawn from the battery:

Ip = V / (4/5 R) = 5 x (V/4R) = 5 x Is

So the current drawn from the battery is 5 times the initial current, Is.

However, this current is divided into 2 branches, let:

Ia = current flows to 4 bulbs

Ib = current flows to 1 bulb

Using the Kirchoff law:

Ia x 4R = Ib x R

and

Ia + Ib = Ip = 5 Is

We get:

Ia = 1/5 x Ip = 1/5 x 5Is = Is

Ib = 4/5 x Ip = 4/5 x 5Is = 4Is.

Hence,

               Ia = Is

Or in other word, the currents flow on the 4 bulbs, before and after the addition of the 5th bulb, are the same.

Therefore, the correct option is:

d) Leave the illumination produced by bulbs in series unchanged

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To increase the acceleration rider should crouch down which decrease the height of CG from Ground & hence increase acceleration since both are Inversely proportional.

At each whee By condition of equilibrium we can find Load

Rear load Wr= 224lb=224*4.45=996.8N

Front load Wf= 261lb=261*4.45=1161.1N

(2.30, 1.62) here the CG of  entire mass will be located

CG location Can be found by

x=sum(Wi*xi) /sum(Wi)

Load transfer due to acceleration is given by

DW=m*a*(h/L)

Where h= height of CG= 1.62ft=0.486m

            L= wheel base=5ft=1.5m

m= total mass in kg=(335+150) *0.45=212.25kg

For front wheel to be lifted,

dW=Wf

solving we get acceleration value as

a= 16.884m/s² of acceleration will be max for tipping of vehicle.

We known that,

Tractive force = ma

Gives us tractive force as T=212.25*16.88=3582.78N

This will be achieved when friction force at rear end at max tractive condition Tractive force = static friction force.

T= Friction force= (coefficient of friction) *N

Where N= Wf+Wr for tipping condition

Coefficient of friction= 3582.78/(Wf+Wr) =1.72

For tipping of vehicle we need a coefficient of friction greater than & equal to 1.72.

In coefficient of Friction equation I have taken entire weight as normal since during tipping load will be shifted to rear wheel.

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The mass of Planet X estirated to be one-half that of Earth; and the radius of Planet X is estimated to be twice that of Earth. The acceleration due to gravity on the surface of Planet X is gx: The correct formula is gx = (1/8)ge.

Let,

The Earth's mass is m.

The Earth's radius is r.

Gravitational acceleration on Earth's surface is equal to ge.

Then,

The answer to the query is

Planet X's mass is equal to (1/2)m.

Planet X's radius is equal to 2r.

gx is the acceleration brought on by gravity on the surface of planet X.

We are aware that the calculation for the gravitational acceleration is

g = GM/R^2

Where,

g = Gravitational acceleration

The gravitational constant is G, which is 6.674*10(11) Nm2/kg2.

M is the planet's mass.

r = Planetary Radius

Currently, for Earth, we have

gₑ = Gm/r^2 ............ (1) (1)

And we have planet X.

gₓ = Gm/2(2r)^2

gₓ = Gm/8r^2 ......... (2) (2)

Equations (1) and (2) are contrasted to obtain

gₑr^2 = 8gₓr^2

gₓ = (1/8)gₑ

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Eudora spent 0.5 hours from home to library and 1.5 hrs from library to home.

Given,

Home to library, Average speed S₁ = 12 km/hr

Average speed S₂ = 76 km/hr

Total distance = 120 km

Total Time = 2 hrs

Let us take the time taken to go from home to library is x. So, from library to school will be 2-x.

S₁ = 12 km/hr

T₁ = x

S₂ = 76 km/hr

T₂ = 2-x

We know that, distance = speed * time

D₁ = 12x

D₂ = 76(2-x) = 152 - 76x

D₁ + D₂ = 120

12x + 152 - 76x = 120

152 - 64x = 120

64x = 32

x = 0.5 hrs

T₂ = 2-x = 2- 0.5 = 1.5 hrs

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The wave's speeds in parts (a) and (b) of the drawing are 13.7 m/s and 9.691 m/s, respectively.

(Tension / Mass per Unit Length) / sqrt = velocity

A) tension: m = 2.3 * 9.8 = 22.54 N; mass per unit length: 0.12 kg/m

velocity is equal to sqrt(22.54/0.12) = sqrt(187.83) = 13.7 m/s b. 2.3 * 9.8 / 2 = 11.27 N tension

velocity or speed is equal to sqrt(11.27/0.12) = sqrt(93.916) = 9.691 metres per second.

An oscillation of a wave that is perpendicular to the direction of the wave's progress is known as a transverse wave in physics. An oscillating wave moves in the opposite direction from a longitudinal wave, which moves in the same direction. Examples of transverse waves include water waves.

An easy illustration is provided by the waves that may be produced on a horizontal piece of string by anchoring one end and moving the other end up and down.

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The direction of fire spread is influenced by the direction of the wind. Strong winds developing high heat outputs in active fire heads can have a dramatic and far reaching effect on the rate and direction of fire spread.

High winds aloft can cause a rapid increase in heat output, as the fire is driven and pushed by the wind towards fuel sources. This can cause the fire to spread quickly, often at a rate faster than the firefighting teams are able to keep up with.

Additionally, with the potential for the wind to surface, the fire can be pushed in unexpected directions. This can cause the fire to spread in unintended directions, making it difficult for firefighters to contain. The wind direction can also influence the rate of spread, as the fire will take a more direct route when pushed in the same direction as the wind.

The wind speed and direction can also change suddenly, causing the fire to spread in yet another unexpected direction. This can cause the fire to spread in multiple directions, making it even more difficult for firefighters to contain.

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Answer:

Decantation

Explanation:

Immiscible liquids are liquids that are not able to be mixed together to form a homogenous solution. They can often be separated by using techniques such as decantation, in which the liquids are poured carefully so that they form separate layers, or by using a separating funnel, which allows the liquids to be separated by exploiting their differences in densities. Other methods for separating immiscible liquids include filtration, centrifugation, and distillation.

The total velocity required (Av) to transfer from one circular orbit to another is 7.086 km/s

The total velocity required (Av) to transfer from one circular orbit to another is given by Av = √(μ/p)(2/r1 - 1/r2), where μ is the standard gravitational parameter of the central body and p is the semi-latus rectum of the transfer ellipse.

Given the parameters for the two circular orbits, r1 = 12,750 km and r2 = 31,890 km, and for the transfer ellipse, p = 13,475 km and e = 0.76, we can calculate the total velocity required to transfer between the two orbits as follows:

Av = √(μ/p)(2/r1 - 1/r2)

Av = √(3.986E+13/13,475)(2/12,750 - 1/31,890)

Av = √(2.946E+10)(0.0690 - 0.0314)

Av = √(2.946E+10)(0.0375)

Av = 7.086 km/s

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Select a capacitor that can resist the impossibly high peak currents produced by snubbers. Dipped mica capacitors should be your first port of call for capacitance levels up to 0.01 F. Look for the Type DPP radial-leaded polypropylene, film/foil capacitors for larger capacitance values.

C + I Δt ΔV . Plug the peak current, risetime, and maximum ripple voltage parameters into equation (1), then solve for C to determine the decoupling capacitance. It is safe to presume that the OMAP5910's typical maximum ripple voltage and risetime are 10 mV and 1 ns, respectively.

A mechanical snubber is a tool used to shield components from excessive stress or sway brought on by seismic activity or other momentary forces. The snubber permits tension and compression movement under normal working circumstances.

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If there is no friction and the mass's displacement out of its equilibrium position at x = 0 is "small," the motion of a mass linked to a spring is simple harmonic motion.

Mode of antisymmetry Four. .Both this and the modes mentioned above might have variants.

Free motion is described by its normal modes at specific frequencies.The term "natural" or "resonant frequencies" refers to these fixed frequencies of the a system's normal modes.Natural oscillations of a mass on a spring occur at the a single frequency.

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Athletes training for the 100-meter dash will mostly rely on phosphocreatine for this event's rapid energy.

Numerous creatine kinases catalyze the reversible phosphorylation of creatine, which includes both the forward and backward reactions. It is used to detect tissue injury when creatine kinase (CK-MB, creatine kinase myocardial band) is present in blood plasma.

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There are many potential ways in which human beings could be affected by rising global temperatures and sea levels. Some potential impacts include:

Overall, the impacts of rising global temperatures and sea levels are likely to be complex and far-reaching, potentially affecting many aspects of human life.

Net electric field and Net gravitational field both can never be zero at any region. So, option d)No, there is no point on the z-axis where both the fields are zero, is the correct answer.

Since both particles have same charge then electric field and magnitude will be same for both particles because in electric field mass is not responsible. It means that electric field is independent from mass. Electric field is given by

E=  [(μ[tex]_o[/tex] /4π)q²] /r²

where q is the charge of both particles and r is the distance between them.

Now, talking about about gravitational field, we get

=>Force between two masses is given by =(G[tex]M_A[/tex][tex]M_B[/tex])/r² where M is the mass of the particle and r is the distance between the particle. Since, mass is different, therefore it can be zero at some point.

Hence, option d is correct.

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FT​=8278.857 N In the arteries of a man, the pulse wave moves at a rate of 4 to 10 meters per second.Its velocity is somewhat influenced by the blood flow through the artery under consideration

Your pulse is how you can feel your heart rate. Every time your heart beats, it squeezes and propels blood through the network of arteries in your body. Your pulse is the pressure in your arteries going up briefly as your heart pushes out more blood to keep circulation going.

The amplitude, length, & pulse width of a pulse have no effect on its speed.The breadth or length of a pulse changing has no effect on the pulse speed.

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the pointing vector for the given wave is  [tex]219.26*10^{-9}j[/tex]

Electromagnetic waves, or EM waves, are waves produced by oscillations between electric and magnetic fields. In other words, EM waves consist of oscillating magnetic and electric fields.

The electric and magnetic fields of electromagnetic waves are perpendicular (right angles) to each other. They are also perpendicular to the EM wave direction.

S = (1/μ[tex]_{o}[/tex] )E*B ,

where

μ[tex]_{o}[/tex] is the vacuum permeability;

E is the electric field;

B is the magnetic flux density.

And,

1/μ[tex]_{o}[/tex] [tex]= 7.9*10^{5} units[/tex]

so,

[tex]S = 7.9*10^{5} (-9.13*10^{-3} ) *(-3.04*10^{-11} )[/tex]                               ∵ [tex](kxi = j)[/tex]   [tex]S = 219.26*10^{-9} j[/tex]

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The heat released in the whole process in which a sample of water is cooled and frozen is 4.64 * 10⁸ J.

The problem is to be divided into two steps. This process releases a certain quantity of heat,

Step 1) Solidification of the water at 0°C into ice.

Q = m* Lf

where,

m is the mass of the water

Lf stands for the latent heat of ice fusion

Substituting numbers, we find

Q₁ = (1271 kg)* (334 kJ/kg) = 424514 kJ = 4.2* 10⁸ J

step 2) The water became ice, now we need to cool it down to -36°C . This process releases a certain quantity of heat, which is

Q₂ = m* Cs* ΔT

where,

m is the mass of ice

Cs is the specific heat of ice

ΔT is the variation of temperature

By placing the numbers in the formula, we have,

Q₂ = (1271 kg)* (2050 J/kg K) (-17-0) = 44294350 J = - 0.44 * 10⁸ J

The negative sign means the heat is released by the system.

Thus, the overall process produces heat that is

Q = Q₁ + Q₂ = 4.2* 10⁸ J + 0.44 * 10⁸ J = 4.64 * 10⁸ J

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The speed of the air flowing into the room (in ft/s) is equal to 0.944 when air flows through a heating duct with a square cross-section with 6-inch sides at a speed of 5.9 ft/s.

By the equation of continuity

(Rate of volumetric flow rate is constant)

A1v1 = A2v2

(6×6)×5.9(inch2ft/sec) = (15×15)×v2

V2 = 4.5(81/169) ft/sec

V2 = 0.944 ft/sec

In contrast to velocity, which describes the speed and direction of an object's movement, speed is the rate of movement along a path. Alternatively, velocity is a vector while speed is a scalar quantity. For instance, the speed of a car on a road is shown by 50 km/h (31 mph), but the velocity is indicated by 50 km/h west.

Physicists employ the fundamental units of speed and velocity to express how things move through space, time, and in a particular direction.

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A. μ0/2π. Il㏒e. a+I/a. the average power dissipated in the loop is when the current in the wire is I = I0sin(ωt).

As the field of current wire passing the loop is same in direction but not uniform in magnitude.

we use integration method for finding the flux.

The same flux ,a thin rectangular strip of length l and with dx, is given by

dϕB=Bx.dS=B(x)dScos180∘.

Magnetic field due to a long straight wire carrying current I is given by B=μ0I/2πx, and area, dS=l×dx.

∴ ϕB=∫dϕB=−∫μ0/2πIlx.dx=−μ0/2πIl[logex]x=a+l/x=a

=−μ0/2π.Illoge.a+I/a

Any equation linking power to current, voltage, and resistance may be used to calculate the power wasted by each resistor because all three variables are known. Since each resistor receives its full voltage, let's use P=V2R P = V 2 R.

Power consumption refers to the device's overall power usage. The portion of power used by objects unrelated to the targeted tasks is known as power dissipation.

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The distance is 1.026 m, the mass be placed to give the pendulum a period of 2.00 seconds.

You are at a furniture store and notice that a Grandfather clock has its time regulated by a physical pendulum that consists of a rod with a movable weight on it. When the weight is moved downward, the pendulum slows down; when it is moved upward, the pendulum swings faster. If the rod has a mass of 1.23 kg and a length of 1.25 m and the weight has a mass of [10] kg, where should the mass be placed to give the pendulum a period of 2.00 seconds?

mass of rod, M = 1.23 kg

Length, L = 1.25 m

mass, m = 10 kg

Time period, T = 2 s

Let the distance is d.

The formula of the time period is given by,

T=2π√1/3ML²+md²/(M+m)g

2x2=4π2x1/3×1.23×1.25×1.25+10d²/(1.23+10)×9.8

11.16=0.64+10d²

d=1.026m

You can use the equation L = (T/ 2)2*g to determine the length of a basic pendulum. where g is the acceleration caused by gravity and T is the simple pendulum's period of time.

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Answer:

A piece of paper will not produce the same kind of reflection as a mirror. A mirror is a highly polished, smooth surface that is able to reflect light in a way that produces a clear and detailed image. A piece of paper, on the other hand, is a rough and porous surface that is not able to reflect light in the same way. When light hits a piece of paper, it is absorbed by the fibers and absorbed, scattered, and absorbed again in multiple directions, which produces a diffuse and distorted reflection. Therefore, a piece of paper will not produce the same kind of reflection as a mirror.

Answer:

15/20 = 3/4. 3/4 hours = 45 minutes.

Explanation:

Compared to the fullback, the less massive running back will experience a greater momentum change, a greater impulse and a greater collision time.

The momentum change of an object can be calculated from knowledge of the object's mass and velocity change, represented by

P = m* Δv

When a force is exerted upon an object in a collision, the object is said to have experienced an impulse.

Impulse = momentum change

F * t = m* Δv

The essential difference between the fullback and the running back is their mass. Each player has same velocity change and encounters same force during the collision. The fact that two players have different mass means the more massive player encounters the greatest momentum change. Since, momentum change is equal to impulse, then the fullback must also encounter the greater impulse. This greater impulse is due to the fact that the same collision force must endure for a longer period of time.

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There are several types of mirrors that can produce distorted images, including concave and convex mirrors. Concave mirrors are curved inward and produce a smaller, magnified image that is often distorted around the edges. Convex mirrors are curved outward and produce a larger, distorted image that appears farther away than it actually is. Both types of mirrors are used for a variety of purposes, including in telescopes, cameras, and other optical instruments.

In order to increase the temperature of an ideal gas in a cylinder that is initially at room temperature, the statement that correctly indicates the appropriate action is to push the piston in rapidly. The temperature of the gas will increase because no energy will be transferred to the surrounding by cooling. (Option C)

An ideal gas refers to a theoretical gas which is composed of many randomly moving point particles that are not subject to interparticle interactions. The concept is useful as it obeys the ideal gas law, which is a simplified equation of state, and is amenable to analysis under statistical mechanics. For an ideal gas, as the temperature increases, the average kinetic energy increases as does the velocity of the gas particles hitting the walls of the container. The force exerted by the particles per unit of area on the container is the pressure, so as the temperature increases the pressure must also increase. Hence, when the piston is compressed so quickly that there is no time to exchange heat to the surrounding, the temperature of the gas increases rapidly.

Note: The question is incomplete. The complete question probably is: A student wants to increase the temperature of an ideal gas in a cylinder that is initially at room temperature. The cylinder has a movable piston with negligible friction. Which of the following correctly indicates an action the student could take to increase the temperature of the gas and why does the temperature increases? A) Pull the piston out rapidly. The gas will expand violently and increase in temperature B) Pull the piston out slowly. The gas will have time to absorb energy from the surroundings by heating as it expands. C) Push the piston in rapidly. The temperature of the gas will increase because no energy will be transferred to the surrounding by cooling. D) Push the piston in slowly. The gas will have time to absorb energy from the surroundings by heating as it is compressed

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