Yes, for floating objects, the buoyant force equals the weight of the objects. since each object has the same weight, they must have the same buoyant force to counteract that weight and make them float.
What occurs to an item when its weight and buoyant force are the same?The object can stay suspended at its current depth if the buoyant force is equal to its weight. Regardless of whether an item floating, descends, or is immersed in a liquid, the buoyant force is constantly at work. Any item in any fluid will experience an upward push called the buoyant force.
What connection exists between an object's weight and the buoyant force acting on it?The total upward force acting on any item in any fluid is known as buoyant force. The object will ascend to the surface as well as float if the buoyant force is higher than its weight. The object will sink if the buoyant force is lower than its weight.
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a quantum oscillator in the wall of a black body cabity has frequency of 5.0*10(14) Hz. calculate the energy of the first two quantum states.
The energy of the first two quantum states, given that the black body cabity has frequency of 5.0×10¹⁴ Hz is 3.313×10⁻¹⁹ J
How do I determine the energy?Energy is defined as the capacity to do work. However, energy and frequency are related according to the formula given below:
E = hf
Where
E is the energyh is the Planck's constant f is the frequencyWe can obtain the energy of the two quantum states as shown below:
Frequency (f) = 5.0×10¹⁴ HzPlanck's constant (h) = 6.626×10⁻³⁴ JsEnergy (E) =? 6.23×10⁻¹⁹ JEnergy (E) = Planck's constant (h) × frequency (f)
E = hf
E = 6.626×10⁻³⁴ × 5.0×10¹⁴
E = 3.313×10⁻¹⁹ J
Thus, we can conclude from the above calculation that the energy is 3.313×10⁻¹⁹ J
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a hippo's body is 4.0 m long with front and rear feet located as in (figure 1). the hippo carries 60% of its weight on its front feet.
The distance at which the center of gravity of hippo is located from the tail of hippo is equal to 1.58 m.
Center of gravity is referred to the point in any object at which the weight of the object is distributed evenly in all the directions. We need to find the position of Center of Gravity of the Hippo from the tail. We are given that Hippo carries 60% weight on its front feet that is
M(front) = 0.60 W
M(rear) = 0.40 W
Let d be the distance of center of gravity from tail and we write the equation as
0.60(1.8 + 0.5 - d) - 0.4(d - 0.5) = 0
=> 1.08 + 0.3 - 0.60d - 0.4d + 0.2 = 0
=> d = 1.58 m
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Complete Question:
A hippo's body is 4.0 m long with front and rear feet located as in (Figure 1). The hippo carries 60% of its weight on its front feet. How far from its tail is the hippo's center of gravity?
A given net force propels an object along a straight-line path. If the mass were doubled, its acceleration would O quadruple be half double stay the same
A given net force propels an object along a straight-line path. If the mass were doubled, its acceleration would be half.
What is the relationship between force and acceleration mass?Force is mass times acceleration, or F = m * a. This means an object with a larger mass requires a stronger force to be moved along at the same acceleration as an object with a small mass. This is Newton's Second Law of Motion.
Newton's Second Law of Motion defines the relationship between force and acceleration. They are directly proportional. If you raise the force applied to an object, the acceleration of that object raises by the same factor. In short, force equals mass times acceleration.
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A heat engine takes in 330 J of energy from a hot reservoir and performs 22.0 J of work in each cycle. Find (a) the efficiency of the engine and (b) the energy expelled to the cold reservoir in each cycle.
a) The efficiency of the engine is 67% b) The energy expelled to the cold reservoir in each cycle is 307.89 J
Qh=330 J , W= 22.0 J
a) n= W/Qh = 22 J/330 J = 0.06675 = 0.067
b) n= W/Qh = (Qh-QL)/Qh = 1 - QL/Qh
Plugging values,
0.067 = 1 - QL/330 => QL = 307.89 J
As a ratio of useful work completed to heat produced, an engine efficiency is determined. completed the task. The power delivered at the clutch or the driveshaft is referred to as the "work done" in this context. As a result, the work produced by thermodynamic expansion is reduced by losses such as friction and other losses. Today's gasoline engines are only about 30 to 35 percent efficient, meaning that about 65 cents of every dollar you spend on gas is wasted even with routine auto maintenance like a tune-up or an oil change. According to the Second rule of thermodynamics, it is impossible for heat engines to achieve 100% thermal efficiency.
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. describe the physical appearance (color)of each complex (formula of complex) substance produced of cu
A complex will appear to be the colours that is right opposite it on the colour wheel if it absorbs a specific colour. Colors are produced by the partially filled d orbitals of the stable ions Cr3+(aq), Fe3+(aq), and Co2+ (located to the left, centre, and right, respectively).
Because the [Cu(NH3)4]2+ ion absorbs the orange and red light, leaving the complementary colours of blue and green, it has a blue colour. Some of the light's wavelengths are absorbed by [Cu(NH3)4]SO4 solution when white light, such as common sunshine, travels through it. Red light in the spectrum is absorbed by the [Cu(NH3)4]2+ ions in solution. All the colours, with the exception of red, will be present in the light that exits the solution. This combination of wavelengths appears light blue to us (cyan). The diagram illustrates what happens when white light is sent through a [Cu(NH3)4]SO4 solution.
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as an automobile approaches an observer at rest, the driver sounds her 450 hz horn. if the car moves at 45 mi/hr, find the frequency heard by the stationary observer.
The frequency heard by the stationary observer is 468.44 Hz. Frequency is a measure of the number of cycles of a periodic phenomenon that occurs in a unit of time.
Frequency is an important concept in many areas of physics and engineering, including acoustics, electronics, and telecommunications. It is also used in other fields, such as biology and medicine, to describe the periodic phenomena that occur in those fields. It is typically measured in Hertz (Hz), which is the number of cycles per second.
The frequency of the horn as heard by the stationary observer is given by the Doppler shift formula:
frequency_heard = frequency_emitted * (speed of sound + speed of observer) / (speed of sound - speed of car)
Plugging in the values given in the problem, we get:
frequency_heard = 450 hz * (331.5 m/s + 0 m/s) / (331.5 m/s - (45 mi/hr * 1609 m/hr / 3600 s))
Converting the speed of the car to meters per second, we get:
frequency_heard = 450 hz * (331.5 m/s + 0 m/s) / (331.5 m/s - 12.5375 m/s)
Simplifying the expression and converting the result to hertz, we get:
frequency_heard = 450 hz * (331.5 m/s) / (319 m/s)
frequency_heard = (450 hz * 331.5 m/s) / 319 m/s
frequency_heard = 450 hz * 1.0398936170212766
frequency_heard = 468.4414893617021 hz
So the frequency heard by the stationary observer is approximately 468.44 Hz.
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a golf ball stays on the tee until the golf club hits it. which of the following principles best describes why this occurs?
Newton's law of inertia best describes why a golf ball stays on the tee until the golf club hits it.
Newton's law of inertia states that an object at rest will remain at rest unless acted upon by an external force. In the case of a golf ball on a tee, the golf ball is not moving because there is no external force acting upon it. Therefore, the golf ball will remain on the tee until the golf club is used to hit it, applying an external force and causing the golf ball to move.
Newton's laws of motion are three physical laws that, together, laid the foundation for classical mechanics. They describe the relationship between a body and the forces acting upon it, and its motion in response to those forces.
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virtual particles are the hypothesized particles that combine to form quarks and other fermions. the graviton, and other particles predicted but not yet observed. particles that temporarily materialize out of the vacuum of space. a mathematical tool used to solve the equations describing the motion of real particles in quantum mechanics.
In quantum mechanics, virtual particles are the hypothesized particles that combine to form quarks, graviton etc is a correct statement.
Quantum mechanics is the branch of science that examines the atomic and subatomic behavior of matter and light. It tries to explain and characterize the properties of molecules, atoms, and their constituent protons, neutrons, electrons, and other less well-known particles like quarks and gluons. These characteristics include electromagnetic radiation and how the particles interact with one another (i.e., light, X-rays, and gamma rays). It can be difficult to understand and accept the implications of the quantum theory because the behavior of matter and radiation at the atomic level frequently appears peculiar. Its theories frequently contradict intuitions derived from observations of the real world.
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A ball dropped on a surface from a 2-m height bounces to a height of 0.98 m.
What is the coefficient of restitution between ball and surface?
The coefficient of restitution between the ball and the surface is equal 0.70.
What is the coefficient of restitution?The coefficient of restitution can be defined as the ratio of the final to the initial speed between two objects after they collide. It generally ranges from 0 to 1 where 1 will be a perfectly elastic collision.
The velocity of the ball when drooped from height 'h' is given by:
[tex]v = \sqrt{2gh}[/tex]
Before impact, the velocity is given by: [tex]u_1 = \sqrt{2gh}[/tex]
[tex]\displaystyle e =\sqrt{\frac{2gh_1}{2gh}}[/tex]
[tex]\displaystyle e =\sqrt{\frac{h_1}{h}}[/tex]
Given, h = 2 m , h₁ = 0.98 m
[tex]\displaystyle e =\sqrt{\frac{0.98}{2} }[/tex]
e = 0.70
Therefore, the coefficient of restitution between the ball and the ground is 0.70.
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You are at a furniture store and notice that a Grandfather clock has its time regulated by a physical pendulum that consists of a rod with a movable weight on it. When the weight is moved downward, the pendulum slows down; when it is moved upward, the pendulum swings faster. If the rod has a mass of 1.23 kg and a length of 1.25 m and the weight has a mass of 1.99 kg, where should the mass be placed to give the pendulum a period of 2.00 seconds? Measure the distance in meters from the top of the pendulum.
I think the equation for this problem is T= 2pi * sqrt ( I / mgd), where I = md^2
The reason why I think that is because it is no a simple pendulum, it is a physical pendulum which means that a hanging object hangs about a fixed axis that does not pass through its center of mass.
The distance from the top of the pendulum is 2.98 m.
Given,
Mass of the pendulum rod, M = 1.23 kg
Length of the pendulum rod, L = 1.25 m
Mass of the weight, m = 1.99 kg
Time period, T = 2 s
Let,
The distance is d.
We know that the formula of the time period is given by
[tex]T =[/tex] [tex]2\pi \sqrt{\frac{1}{(M+m)g} \frac{1}{3}ML^{2}+\frac{1}{(M+m)g}md^{2}}[/tex]
4 = 4π² {1/3(1.23)(1.25)(1.25) + (1.99)d²}/{(1.23 + 1.99)9.8}
94.668 = 6.034 + 10d²
d = 2.98 m
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Mary weighs 525 N and she walks down a flight of stairs to a level 6.5 m below her starting point. What is the change in Mary’s potential energy? Answer in units of J.
The change in Mary’s potential energy is - 3412.5 Joule.
What is gravitational potential energy?
The energy that an item has or acquires when its location changes as a result of being in a gravitational field is known as gravitational potential energy. Gravitational potential energy can be defined as an energy that has a connection to gravitational force or gravity.
Given that:
Weight of Marry: W = 525 N.
She walks down a flight of stairs to a level 6.5 m.
Hence, decrease in potential energy of her = Wh
= 525 N × 6.5 m
= 3412.5 Joule.
Hence, the decrease in potential energy of her is 3412.5 Joule.
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#2. The magnetic field B at all points within a circular region of radius R is uniform and directed out of the page_ That region could be a cross section inside of the long solenoid. If the magnetic field decreasing at a rate of dB/dt; what are the magnitude and direction of force on a stationary negative point charge q located at points (1) a inside of that solenoid) (2) and at point b outside of that solenoid)
The magnetic field is upward diection.
What is magnitude ?
The definition of magnitude is "distance or amount." It displays an object's size or motion in either an absolute or a relative sense. It is a means of describing the magnitude or range of something. In physics, a magnitude frequently describes a length or a size.
What is magnetic field ?
The magnetic field is the region where the force of magnetism works around a magnetic substance or a moving electric charge. a magnetic field illustration that shows how the magnetic force is distributed throughout and around a magnetic substance.
Inside the circulation region at distance r,
El = d∅/dt = s (dB / dt )
Therefore E (2π r ) = (π r2). dB/dt
Therefore E = r dB/2 dt
F = qE = qr dB/ 2 dt
At points a and b, distance from Centre is r
Therefore F = qE = qr dB/2 dt
At point c, distance r = 0
Therefore F = 0
Magnetic field is increasing. Hence, induced current in an imaginary loop passing through a and b should be anti-clockwise. Force on positive charge is in the direction of induced current. Hence force at a is towards left and force at b is upward.
Therefore, the magnetic field is upward direction.
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Particle a is pursuing particle b along the x-axis of a frame S. The two masses are ma and mo (with va > vb). When a catches up with b, they collide and coalesce to form a single particle of mass m and speed v. (a) (10 points) Find m and v. (b) (5 points) How much kinetic energy is lost in this collision? Your answers should be in terms of ma, mb, va and vb.
A particle of mass m is travelling with an initial velocity of u I along the x-axis.
It moves with half of its initial kinetic energy after elasto-magnetically colliding with a particle of mass 10 m at rest (see figure). If sin 1 = n sin 2, then n has value. A particle of mass m collides with a particle of mass 2m that is initially at rest while travelling along the x-axis at a speed of v. Following the collisions, as shown in the picture, the second particle has split into two equal-mass pieces that travel at equal angles theta? 0 with the x-axis. The first particle has come to rest. The x-axis is being traveled by a particle. Its speed (v) along with.
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Where does the maximum acceleration occur in SHM?
A. At equilibrium
B. At the amplitude
C. Not enough info
D. Somewhere in the middle
Answer:
A: at equilibrium
Explanation:
In simple harmonic motion (SHM), the maximum acceleration occurs at the points where the displacement of the object is zero, which is also known as the equilibrium position. Therefore, the correct answer is option A: at equilibrium.
Maximum acceleration is max at the amplitudes in simple harmonic motion. Velocity is maximum at equilibrium. Refer to the photo.
Which of the following color combinations will produce white light?
a. blue light + red light
b. blue light + magenta light
c. blue light + cyan light
d. blue light + yellow light
Answer:
d) blue light + yellow light
Explanation:
The color combination that will produce white light is blue light + yellow light. White light is the combination of all colors of the visible spectrum. When blue and yellow light are mixed together, they create a white light because blue and yellow are complementary colors. Complementary colors are pairs of colors that are opposite each other on the color wheel, and when they are mixed together, they create a neutral color (in this case, white). Therefore, the correct answer is d) blue light + yellow light.
At the surface of Mars, Gravity is [tex]3.8m/s^2[/tex]. A robot weights 150N on the surface of Mars.
(a) Find it's mass on Mars.
(b) State it's mass on Earth.
(c) Calculate it's weight on Earth.
The mass of the robot on mars will be 39.4 Kg. The mass of an object is constant hence, the mass of the robot in earth also be 39.4 Kg. But it weight in earth changes to 386 N.
What is gravitational force?Gravitational force is the force by which an object attracts other objects into its centre of mass. Earth exerts a gravitational force to every objects on its surface and that's why everything stay on the ground and experience a weight.
The weight of a body in a gravitational field is the product of its mass and acceleration due to gravity g. The g value in mars is 3.8 m/s². The weight of the robot in mars is 150 N
mass of robot = 150 N/3.8 m/s² = 39.4 Kg.
Mass of an object is constant everywhere and the mass of robot in earth be 39.4 Kg.
The g value of earth is 9.8 m/s². Thus, weight of the robot in earth = 34.9 × 9.8 m/s² = 386 N.
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What is a Physics teachers favourite number?
Answer:
243?
I hope this helps?
we will model the spine and upper body as a horizontal rigid rod of uniform density with a length of 50.0 cm and a mass of 40.0 kg. assume that the person attempts to lift an object with their arms, which we will model as attached at the far end of the rod. support of the back in this position is provided primarily by the erector spinalis muscle which we will model as being attached at one end to the spine at a point 33.0 cm from the hip at an angle of 10
Tension in the back muscle for this scenario is 3095.4 N and the compressive reaction force is 3048 N, and the ratio is 5.53.
Two forces are acting on the compartment, Gravity acting downward, Tension T in cable acting upward.
Force is an influence which could change the movement of an object. A pressure can reason an object with mass to change its pace (e.g. moving from a kingdom of relaxation), i.e., to boost up. pressure can also be described intuitively as a push or a pull. A pressure has both importance and course, making it a vector quantity. it's far measured within the SI unit of newton (N). it's far a wellknown mechanical quantity. pressure is represented with the aid of the symbol F (previously P).
A) In equilibrium net torque about the hip = 0
T*sintheta*x - Fgup*L/2 - Fgob*L = 0
T*sin10*0.33 - 40*9.8*0.5/2 - 16.2*9.8*0.5 = 0
Tension(T) = 3095.4 N
B) Fv = FRx = T*costheta
Fv = 3095.4*cos10
= 3048 N
C) Fv/(wub + wobj) = 3048/((40+16.2)*9.8) = 5.53
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Unpolarized red light is incident on two identical, narrow vertical slits. The photograph at right shows the interference pattern that appears on a distant screen. a. Specify the quantity or quantities that are adding to zero at the interference minima. light waves from the two slits are adding to zero is not a sufficient answer.)b. A polarizer is placed directly in front of both slits, so that the light is vertically polarized before passing through the slits. It is observed that the intensity at each point on the screen decreases by a factor of two. How can your account for the decrease in intensity at the interference maxima?c. The polarizer is slowly rotated through 360 degree . As the polarizer is rotated, it is observed that the interference pattern does not change. What is the flaw in the reasoning? Explaind. Now imagine that one polarizer is placed in front of each slit: one polarizer with its direction of polarization vertical; the other, horizontal.Would there still be locations on the screen at which the intensity is zero? Explain why or why not.
Electromagnetic waves make up light. Electric fields can be in any direction perpendicular to the propagation of unpolarized light rays. At each point, the intensity is halved.
a). Light is an electromagnetic wave. It consists of minimally intense, pulsing electric and magnetic fields that are directed in all directions perpendicular to the propagation diffraction pattern. Electric fields of light from two slits add up to zero, therefore they likewise sum to zero in terms of light intensity.
b). In light waves (unpolarized), the electric field can be in any direction perpendicular to its propagation. Polarization entails facing the electric field in all directions except one toward zero. While polarisation, for example, in the vertical direction, additional electric field components from other directions are added to the necessary (remaining) direction.
c). Electric fields at angle θ to vertical adds Ecosθ to vertical field
before polarisation: same E in all directions
I∝E²
∝[tex]\int\limits^\pi _0[/tex]E² dθ =E² π
After polarisation;
I∝ [tex]\int\limits^\pi _0[/tex] (E cosθ )²dθ =E² π/2
Hence, Intensity is halved at every point
d). Electric field cannot be stopped by slits since it is not a mechanical thing that can be.
e). The horizontal and vertical electric field vector addition cannot be zero. Therefore, there won't be any places with 0 intensity.
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(Come) back to the future. Suppose that a father is 21.00 y older than his daughter. He wantsto travel outward from Earth for 2.000 y and then back to Earth for another 2.000 y(both intervals as he measures them) such that he is then 21.00 y younger than hisdaughter. In terms of c, what constant speed (relative toEarth) is required for the trip?
1_________ c
The constant speed (relative to earth) required for the trip is 0.9959.
Solution:
Then these three equations combine to give a single condition from which γ can be determined (and consequently v ):
44 = 4y = y=11 = β = 2√3/11 = 0.9959
A car moving at a constant speed is an example of constant speed because it travels the same distance in the same amount of time. Aircraft systems use constant-speed drives to transfer power to an onboard generator at a constant output speed regardless of engine input speed.
Even if the speed is constant the speed will change if you are moving in a circular motion. This is because when an object moves in a circle, the direction of movement is always changing. Therefore the speed is not constant. DC motors have a large installed base and provide maximum torque at zero speed.
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a string and allowed to revolve in a circle
of radius 1.7 m on a frictionless horizontal
surface. The other end of the string passes
through a hole in the center of the surface,
and a mass of 1.5 kg is tied to it, as shown.
The suspended mass remains in equilibrium
while the puck revolves on the surface.
0.029 kg
1.7 m
1.5 kg
What is the magnitude of the force that
maintains circular motion acting on the puck?
The acceleration due to gravity is 9.81 m/s?.
Answer in units of N.
part 2 of 2
What is the linear speed of the puck?
Answer in units of m/s.
The magnitude of the force that maintains circular motion while acting on the puck is 14.7 N
F=ma
F=1.5 kg×9.8 m/s^2
F=14.7 N
When an object interacts with another object, it feels a push or a pull. Each object that two objects make contact with experiences a force. Once the encounter is over, the force between the two objects is gone. Forces are merely interactions; they do not exist independently. When two objects interact and appear to be in physical contact with one another, contact forces are generated. Several types of contact forces include frictional forces, tensional forces, normal forces, air resistance forces, and applied forces. Even when two interacting objects are far apart from one another, action-at-a-distance forces are still present.
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an 18 kg shopping cart moving at a velocity of 0.7 m/s collides with a store wall and stops. the momentum of the shopping cart
The momentum of the cart of mass 18 kg is 12.6 kgm/s.
What is momentum?Momentum is the product of mass and velocity.
To calculate the momentum of the shopping cart, we use the formula below.
Formula:
M = mv........................ Equation 1Where:
M = Momentumm = Mass of the shopping cartv = Velocity of the shopping cartFrom the question,
Given:
m = 18 kgv = 0.7 m/sSubstitute these values into equation 1
M = 18×0.7M = 12.6 kgm/sHence, the momentum of the cart is 12.6 kgm/s.
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The momentum of the shopping cart will be 12.6Kgm/s.
What is Momentum?Momentum is defined as the product of mass of an object and velocity of that object. It is vector quantity and it has both direction and magnitude.
The formula for momentum is written as;
p = m × v
p = momentum
m = mass of the object
v = velocity
Types of MomentumLinear MomentumAngular Momentump = m × v
where m = 18kg
v = 0.7m/s
p = 18 x 0.7
p = 12.6 Kgm/s
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A thin circular wooden hoop of mass m and radius Rrests on a horizontal frictionless plane. A bullet, also of mass m, moving with horizontal velocity v, strikes the hoop and becomes embedded in it as shown in the figure. (a) (2) Calculate the center of mass velocity (b) (2) Calculate the angular momentum of the system about the CM. (c) (32) Calculate the angular velocity w of the hoop. (d) (4) Calculate the kinetic energy of the system, before and after collision (e) (48) Find a point of the hoop which remains at rest after collision
The velocity of the center of mass of the system is the same as the velocity of the bullet, which is v. The total angular momentum of the system about the center of mass is Lhoop + Lbullet. he kinetic energy of the system, before and after collision Khoop + Kbullet and Khoop_after + Kbullet_after respectively. The axis of rotation, which is the center of the hoop, will remain at rest after the collision.
The center of mass of the system is at point Q, which is a distance d from point O, where:d = (mP + mO)/(2*m).The velocity of the center of mass is the derivative of the position with respect to time. Since the bullet is moving with constant velocity, the position of its center of mass is also moving with constant velocity. The position of the center of mass of the hoop is not changing, so its velocity is zero. Therefore, the velocity of the center of mass of the system is the same as the velocity of the bullet, which is v.
The angular momentum of the bullet about the center of mass is:Lbullet = Ibulletw + md*v where Ibullet is the moment of inertia of the bullet about its center of mass, and d is the distance from the center of mass to the point of contact between the bullet and the hoop. The total angular momentum of the system about the center of mass is the sum of the angular momenta of the hoop and the bullet: Ltotal = Lhoop + Lbullet
Since angular momentum is conserved, this change in angular momentum must be due to the change in the angular momentum of the hoop. Therefore, we can set the change in angular momentum of the hoop equal to Ltotal and solve for the angular velocity w:
Ltotal = Lhoop + Lbullet
Ltotal = Ihoopw + mRv + Ibulletw + mdv
Ltotal = (Ihoop + Ibullet)w + (mR + md)v
w = Ltotal/(Ihoop + Ibullet) - (mR + md)*v/(Ihoop + Ibullet).
kinetic energy is conserved, this means that the change in kinetic energy of the hoop must be equal to the change in kinetic energy of the bullet. Therefore, we can set the change in kinetic energy of the hoop equal to the change in kinetic energy of the bullet and solve for the kinetic energy of the hoop after the collision:
Khoop_after - Khoop = Kbullet - Kbullet_after
Khoop_after = Khoop + Kbullet - Kbullet_after
The kinetic energy of the system after the collision is the sum of the kinetic energies of the hoop and the bullet after the collision:
Ktotal_after = Khoop_after + Kbullet_after
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Plaskett's binary system consists of two stars that revolve In a circular orbit about a center of mass midway between them. This statement implies that the masses of the two stars are equal (see figure below). Assume the orbital speed of each star is |v | = 240 km/s and the orbital period of each is 12.5 days. Find the mass M of each star. (For comparison, the mass of our Sun is 1.99 times 1030 kg Your answer cannot be understood or graded. More Information solar masses
Each star has a mass M of 1.43 × 10³²kg.
The simplest types of orbits in celestial mechanics are circular orbits, in which an orbiting body moves around a gravitational mass while maintaining a constant radius.
Calculation:We learn from the question that the stars'masses are m1 = m2 = M.
Each star orbits at a speed of Vs = 240 km/s or 240000 m/s.
T = 12.5 days, often known as 12.5246060, or 1080000sec, is the orbital period.
The mathematical formula for the centripetal force exerted on these stars isFc = Mv²/r
The mathematical formula for the gravitational force exerted on these stars is
Fg = GM²/d²
so Fc = Fg
Mv²/r = Gm₁ₓm₂/d²
v²/r = GM/(2r)²
v²/r = GM/4r²
M = v² × 4r /G
Each sun travels a certain distance during one cycle, which is mathematically expressed asD = V × T
D = 240000 × 1080000
D = 2.592×10¹¹ m
Now this can also be represented asD = 2πr
Therefore
2πr = 2.592×10¹¹ m
r = 2.592×10¹¹ / 2π
r = 4.124 × 10¹⁰ m
So,
M = v² × 4r/ G
M = (240000)² × 4 × 4.124 × 10¹⁰/ 6.67 × 10 ⁻¹¹
M = 1.43 × 10³²kg.
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the a string on a cello vibrates in its first normal mode with a frequency of 220 hz. the vibrating segment is 66.0 cm long and has a mass of 1.80 g.(a) Find the tension in the string.N(b) Determine the frequency of vibration when the string vibrates in three segments.Hz
The string vibrates in three segments at a frequency of 660 Hz while exerting a force of 166.27 N. The first normal mode of a cello string vibrates at a frequency of 220 Hz.
The frequency of an event is its repetitions per unit of time. As a contrast to spatial frequency, it is also sometimes referred to as temporal frequency, and as a contrast to angular frequency, it is sometimes referred to as ordinary frequency. The hertz unit is used to measure frequency (Hz). f = 220Hz
L = 66cm = 0.6m for the wire's length
Wire mass = 1.8*10-3 kg, m/L = 1.8*10-3/0.66, and kg/m = 2.7*10-3
F = 4*2.7 *10^-3 *(0.6^2)*(220)^2 = 166.2N
The frequency at which n segments appear in a string is known:
fn = nf1
For, n = 3
f3 = 3f1
f3 = 3*220
f3 = 660Hz
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an object with height 0.85 cm is placed a distance 19.75 cm in front of a convex mirror with focal length -6.25 cm,removedde6d0d485ec413711a4e98afe87284678ac0bba70217810ba692cdd66aafdf8cremoved 2m68-57-20-4f-a59d-29897 20% part (a) calculate and enter a value for the magnitude of the distance between the image and the mirror given the values in problem statement. |di||di|
The distance between the image and the mirror is -4.63 cm.
The mirror equation is given by,
1/u + 1/v = 1/f
where, u is the distance to the object = 17.95 cm
v is the distance to the image
f is the focal length = -6.25 cm
Placing the values in the equation, we have
1/17.95 + 1/v = -1/6.25
1/v = -1/6.25 - 1/17.95
1/v = - 0.16 - 0.056
1/v = - 0.216
v = -4.63 cm ( minus sign indicates that the image is behind the mirror and it is virtual)
Thus, the image distance is -4.63 cm.
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Consider the photoelectric effect when one decreases only the frequency of the incoming light onto the emitter, one measures an increased current. either a. or c. You cannot determine which from the information given. no change in either current or stopping voltage. a decrease in the necessary stopping voltage. an increase in the necessary stopping voltage.
An increase in the required stopping voltage if the photoelectric effect simply affects the frequency of a incident sunlight onto to the emitter.
What is the way Einstein described the photoelectric effect?Since photons are the units of light, according to Einstein's theory, an electron receives the entire photon's energy when it collides with a metal surface. The ejected electron receives the remaining energy as kinetic energy after using some of this energy to free it from the metal atom's hold.
What are the main points of the photoelectric effect?Three key properties of the photoelectric effect that are not consistent with classical physics include: (1) the lack of a lag, (2) the independence of photoelectrons' kinetic energy from the strength the incident radiation, and (3) the existence of a cut-off frequency.
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Complete the given reaction which is part of the electron transport chain. The abbreviation abbreviation for the product. represents coenzyme Q. Use this FADH,+Q- The reactant that is reduced is In complex III, electrons are transferred from coenzyme Q to cytochrome C, which contains iron. QH; +2 cyt (Fe) —Q+2 cyt (Ft) +2H+ Determine the oxidation number for iron on the right side of the reaction arrow
Make use of this FADH,+Q- The reduced reactant is In complex III, iron-containing cytochrome C receives electrons from coenzyme Q. QH; +2 cyt (Fe); Q+2 cyt (Ft); +2H+. Iron's oxidation number is +2, which is shown on the right side of the reaction arrow.
FADH₂ + Q [tex]\rightarrow[/tex] QH2+ FAD+
Coenzyme Q is reduced in this situation, and FADH2 is oxidized, hence the correct response is Q.
reduced Complex III oxidizes coenzyme Q, cut chromosome c is reduced, resulting in the reduction of Fe3+ to Fe2+, and the iron on the right side is now in the +2 oxidation state.
so the answer is x=+2
Subatomic particles known as electrons have a -1 magnitude elementary charge. The magnitude of an electron's charge is equivalent to that of a proton (but has an opposite sign).
Because of this, electrically neutral atoms and molecules need to contain an equal number of protons and electrons. The size and mass of an electron are significantly smaller than those of a proton, despite the fact that the magnitude of the charges borne by protons and electrons is the same (the mass of an electron is around 1/1837 that of a proton).
Protons, electrons, and neutrons are the fundamental subatomic particles that were later identified by scientists. At the core of each atom is a large mass known as the nucleus. Both neutrons and protons are found in the nucleus. Take into account the solar system.
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Mark pushes his broken car 190 m down the block to his friend's house. He has to exert a 160 N horizontal force to push the car at a constant speed. How much thermal energy is created in the tires and road during this short trip? Express your answer to two significant figures and include the appropriate units. Delta E_Ts =
The thermal energy is created in the tires and road during this short trip is 30400 J.
Thermal energy is a type of energy that occurs when the temperature rises. Thermal energy is directly proportional to the temperature change of an object. Heat is a form of thermal energy. The hotter the substance, the greater its thermal energy. The increase in thermal energy caused by raising the temperature is due to the faster movement of atoms and molecules in matter.
Calculation :
Here,
distance ,d = 190 m
force exerting , F = 160 N
for the thermal energy created
thermal energy created in tires = work done by the pushing force
thermal energy created in tires = 190 * 160
thermal energy created in tires = 30400 J
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one of the features that is helpful in identifying many metamorphic rocks is the presence of foliation. foliation is the apparent layering within a rock due to the alignment of minerals from compression or shear stress. below are three dough balls experiencing stress. select the one that is experiencing shear stress.
Based on the provided figures, the dough balls which is experiencing shear stress is option C.
Shear stress refers to force tending to cause deformation of a material by slippage along a plane or planes parallel to the imposed stress. The resultant shear is significant in nature, being intimately related to the downslope movement of earth materials and to earthquakes. Shear stress may also happen in solids or liquids. Shear stress causes foliation. When a rock is acted upon by pressure that is not the same in all directions, or by shear stress, minerals can become elongated in the direction perpendicular to the main stress and the pattern of aligned crystals that results is known as foliation. Foliation is among the features that are helpful in identifying many metamorphic rocks.
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