Answer:
22.1 ppm
Explanation:
The equation of the reaction is;
Pb2+ (aq) + 2NaI(s) ------>PbI2(s) + 2 Na^2+
Mass of precipitate = 55.1x10-3 g
Number of moles of precipitate = 55.1x10-3 g/461.01 g/mol = 1.2 * 10^-4 moles
1 mole of Pb2+ yields 1 mole of PbI2
Hence 1.2 * 10^-4 moles of Pb2+ also yields 1.2 * 10^-4 moles of PbI2.
Hence mass of Pb2+ present = 1.2 * 10^-4 moles * 207 g/mol = 0.025 g or 25 mg
Mass of solution = Density of solution * volume of solution
Mass of solution = 1.00 kg/L * 1.13 L
Mass of solution = 1.13 Kg
Concentration in mg/Kg(ppm) = mass of solute/mass of solution
= 25 mg/1.13 kg
= 22.1 ppm
(1.21 x 10^-3 + 1.3 x 10^-3) x 6.453 x 10^2 =
Answer:
1.61
Explanation:
How many moles of zinc are in 0.535 g ?*
Answer:
0.00818 moles
Explanation:
If the Bunsen burner gave a luminous flame and some soot was deposited on
the tube, what effect would this situation have on the calculated % of oxygen ?
Explanation:
If bunsen burner gave a luminous flame then there will deposition of soot at the bottom of the test tube which is actually pure carbon.
This deposition of soot actually depicts that there is incomplete combustion reaction that has taken place.
Also, the deposition of soot will provide a limited supply of oxygen to the reaction that has been calculated.
Therefore, in order to avoid any formation of soot it is advisable to adjust the burner flame till it produces a blue flame.
Which of these is an ion with a charge of 1+?
If only 0.225 g of Ca(OH)2 dissolves in enough water to give 0.100 L of aqueous solution at a given temperature, what is the Ksp value for calcium hydroxide at this temperature
Answer: The [tex]K_{sp}[/tex] value for calcium hydroxide at this temperature is [tex]1.08 \times 10^{-4}[/tex].
Explanation:
Given: Mass of [tex]Ca(OH)_{2}[/tex] = 0.225 g
Volume = 0.100 L
As moles is the mass of substance divided by its molar mass.
So, moles of [tex]Ca(OH)_{2}[/tex] (molar mass = 74 g/mol) is calculated as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{0.225 g}{74 g/mol}\\= 0.003 mol[/tex]
Molarity is the number of moles of substance present in a liter of solution.
Hence, molarity of given solution will be as follows.
[tex]Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.003 mol}{0.1 L}\\= 0.03 M[/tex]
The equation for dissociation of [tex]Ca(OH)_{2}[/tex] is as follows.
[tex]Ca(OH)_{2} \rightarrow Ca^{2+} + 2OH^{-}[/tex]
This means that [tex][Ca^{2+}] = 0.03[/tex] and [tex][OH^{-}] = 2 \times 0.03 = 0.06[/tex]. Hence, [tex]K_{sp}[/tex] value for this reaction is calculated as follows.
[tex]K_{sp} = [Ca^{2+}][OH^{-}]^{2}\\= (0.03) \times (0.06)^{2}\\= 1.08 \times 10^{-4}[/tex]
Thus, we can conclude that the [tex]K_{sp}[/tex] value for calcium hydroxide at this temperature is [tex]1.08 \times 10^{-4}[/tex].
If 23.6 mL of 0.200 M NaOH is required to neutralize 10.00 mL of a H3PO4 solution , what is the concentration of the phosphoric acid solution
Answer:
The correct answer is 0.157 M.
Explanation:
The chemical equation of the mentioned reaction is, 3NaOH + H₃PO₄ ⇄ Na₃PO₄ + 3H₂O The molarity of NaOH given is 0.2 M, the volume of NaOH given is 23.6 ml or 23.6 × 10⁻³ L. The moles of NaOH can be determined by using the formula, Moles of NaOH = Volume of NaOH × Molarity Moles of NaOH = 23.66 × 10⁻³ L × 0.2 M = 0.00472 moles Based on the reaction, 3 moles of NaOH needs 1 mole of H₃PO₄. So, 0.00472 moles of NaOH will require, 0.00472/3 = 0.0015733 moles.
The concentration or molarity of the H₃PO₄ will be, [H₃PO₄] = Moles of H3PO4/Volume of H₃PO₄ in liters (Volume of H₃PO₄ given is 10 ml of 10 × 10⁻³L) = 0.0015733 moles/ (10 × 10⁻³ L) = 0.157 M
If the specific heat capacity of copper is 387 J/kg/°C, then how much energy is needed to raise the temperature of 400 g of copper from 30°C to 55°C?
Answer:
Explanation:
mass = 400 grams * [1 kg/1000 grams] = 0.400 kg
c = 387 Joules / (oC * kg)
Δt = 55 - 30 = 25 oC
E = m*c * Δt
E = 0.4 * 387 * 25
E = 3870 Joules
What is the mass of 25.5 L of water assuming it is at 4 degrees Celsius?
Answer:
25.5kg or about 56.2lbs
Explanation:
At 4°C pure water has a mass of about 1 kg/liter.
So, if there was 25.5 L of water it would be 25.5kg or about 56.2lbs.
HELP PLS HELP i rlly need help omg
an organic compound that contains only carbon and hydrogen and a triple bond (all the other bonds are single bonds) is classified as:
a. alkane
b. alkene
c. alkyne
d. arene
Answer:
c. alkyne.
Explanation:
Hello there!
In this case, according to the attached file, it turns out possible for us to say that alkanes have only single-bonded carbon atoms, alkenes have two double-bonded carbon atoms and alkynes have two triple-bonded carbon atoms.
In such a way, according to the aforementioned definition, we infer that that an organic compound that contains only carbon and hydrogen and a triple bond (all the other bonds are single bonds) is classified as c. alkyne.
Regards!
10. What is the molarity of a solution containing 20 moles of NaCl dissolved in 10 liters of water?
0.5 mol/L
2 mol/L
5 mol/L
10 mol/L
Answer:
2 mol/L
Explanation:
M=Mol of solute/L. of solution
M=20mol/10L of H2O= 2mol/L
Answer:
2mol/L
Explanation:
got it correct on my quiz
Please help, any and all is very much appreciated!
What caused carbon dioxide to decrease in the air (abiotic matter) of the biodome?
Answer:
As organisms release energy during cellular respiration, carbon dioxide is produced from the carbon in energy storage molecules. ... Carbon dioxide in the biodome decreased because decomposers decreased which means there was a decrease in cellular respiration overall.
Explanation:
Carbon dioxide is "a colorless, odorless gas that is present in the atmosphere and is formed when any fuel containing carbon is burned".
What is atmosphere?Atmosphere is "a mixture of gases that includes about 78% nitrogen and 21% oxygen at Earth's surface".
What is fuel?Fuel is "a substance which upon combustion produces a usable amount of energy".
When the population of decomposer decreased, the amount of carbon dioxide in the biodome decreased drastically. The carbon dioxide that used to be in the air (abiotic matter) is now in another part of the ecosystem and the carbon remained constant.
Hence, Carbon dioxide decreased in the air (abiotic matter) of the biodome.
To learn more about Carbon dioxide here
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in some applications nickel-cadmium batteries have been replaced by nickel-zinc batteries a single nickel-cadmium cell has a voltage of 1.30 V. Based on the idfference in the standard reduction potentials of CD2 and ZN2_, what votlage would you estimate a nickel-zinc a battery would produce
) Dinitrogen Tetroxide partially decomposes according to the following equilibrium: N2O4 (g) 2NO2 (g) A 1.00-L flask is charged with 0.400 mol of N2O4. At equilibrium at 373 K, 0.0055 mol of N2O4 remains. Keq for this reaction is __________.
Answer: The value of [tex]K_{eq}[/tex] for this reaction is 1.578.
Explanation:
Given: Initial moles of [tex]N_{2}O_{4}[/tex] = 0.4 mol
Volume = 1.00 L
Therefore, initial concentration of [tex]N_{2}O_{4}[/tex] is calculated as follows.
[tex]Concentration = \frac{moles}{volume}\\= \frac{0.4}{1.0 L} mol\\= 0.4 M[/tex]
Now, ICE table for the given reaction equation is as follows.
[tex]N_{2}O_{4}(g) \rightleftharpoons 2NO_{2}[/tex]
Initial: 0.4 0
Change: -x +2x
Equib: 0.4 - x = 0.0055 2x
Hence, the value of x is calculated as follows.
0.4 - x = 0.0055
x = 0.4 - 0.0055
= 0.3945
Now, the [tex][NO_{2}][/tex] is calculated as follows.
2x = [tex][NO_{2}][/tex] = [tex]2 \times 0.3945 = 0.789[/tex]
Therefore, [tex]K_{eq}[/tex] for the given reaction is calculated as follows.
[tex]K_{eq} = \frac{[NO_{2}]^{2}}{[N_{2}O_{4}]}\\= \frac{(0.789)^{2}}{(0.3945)}\\= 1.578[/tex]
Thus, we can conclude that [tex]K_{eq}[/tex] for this reaction is 1.578.
The law of partial pressures was developed by ___________.
Answer:
John Dalton
Explanation:
what does litmus do when it is put into sodium hydroxide?
PLEASE ANSWER ME FAST PLEASE
Answer:
The red litmus turns to blue
Explanation:
Hope it helps
If an atomic number of an element is 24, the number of protons the Atom has is
A. 24
B. 12
C. 189
D.51.996
Explanation:
i think the answer is A ........ hope this helps
Each of the following models represents particles present before and after a
chemical reaction which correctly shows conservation of mass during a
reaction?
Answer:
D
Explanation:
According to the law of conservation of mass, matter can neither be created nor destroyed. The implication of this is that the total mass of reactants should be equal to the total mass of products.
There should be equal masses of reactants and products on both sides of the reaction equation. This most important condition is only satisfied by option D.
Convert 2.0 micrometer to centimeters and to inches
Answer:
2x10⁻⁴cm and 7.9x10⁻⁵ inches
Explanation:
Micrometer, μm, is an unit of length. Could be related with another units of lenght as, for example:
1.0μm = 1x10⁻⁴cm
1.0μm = 3.93701x10⁻⁵ inches
That means, 2.0μm are:
2.0μm * (1x10⁻⁴cm / 1μm) = 2x10⁻⁴cm
And:
2.0μm * (3.93701x10⁻⁵ inches / 1μm) = 7.9x10⁻⁵ inches
As the diagram model the processo se reproduction lomon) formand change formation Sexual reproduction results in a child that is different from its parents because
A. the child receives all of is genetic information from its mother
B. the child produces its own genetic information once it is formed
C. the child receives half of is genetic information from each parent
D. the child receives all of it's genetic information from it's father there
Answer:
The answer is C. the child receives half of is genetic information from each parent
Explanation:
hope this helps enjoy
4. Are there any solutions that have the measure of -3
? Briefly explain why.
Limitations of Pearson rule
Which atom has the smallest atomic radius between cesium, potassium, rubidium, and francium?
Pea plants have green seeds only if a plant receives an allele for green seeds from each of its parents. What kind of allele produces green seeds in pea plants?
Your answer:
Hybrid
Dominant
Recessive
Mutated
Answer:If two heterozygous parents with a genotype of Yy are crossed, the possible combination of genotypes in their offspring would be YY, Yy, Yy, and yy. Therefore, the genotypic ratio of the offspring produced is 1:2:1.
Explanation:If two heterozygous parents with a genotype of Yy are crossed, the possible combination of genotypes in their offspring would be YY, Yy, Yy, and yy. Therefore, the genotypic ratio of the offspring produced is 1:2:1.
Choose the group that corresponds to each element.
Alkali Metal
Alkali earth metal
Halogen
Noble gas
The group corresponding to alkali metal, alkali earth metal, halogen, and noble gas is IA,IIA, 17, 18 group respectively.
Alkali metals have one outermost electron in their valence shell. They are kept under oil and are in the group IA of the periodic table.Alkaline earth metals have two outermost electrons in their valence shell. Examples are beryllium, magnesium, etc.Halogens have seven electrons in their outermost shells. They are in the periodic table in group 17 naming fluorine to iodine.Noble gas is the one that has fulfilled electronic configuration and doesn't react with any other compound.This is present in group 18 of periodic table.Learn more about alkali metals at:
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i. Complete the chemical reaction to show this. Make sure your equation is balanced. (2 points)
C6H12O6 + 02 →
This is the reaction of respiration. Hence, the complete reaction is:
C₆H₁₂O₆ + O₂ → 6CO₂ + 6H₂O
What is respiration?Respiration is defined as a metabolic process wherein the living cells of an organism obtain energy (in the form of ATP) by taking in oxygen and releasing carbon dioxide from the oxidation of complex organic compounds. There are two forms of respiration: aerobic and anaerobic.
Aerobic respiration occurs in the presence of oxygen, while anaerobic respiration occurs in the absence of oxygen.
Because it generates the energy required for body function, respiration is significant. It gives the cells oxygen and releases harmful carbon dioxide. Hence, the reaction of cellular respiration is:
C₆H₁₂O₆ + O₂ → 6CO₂ + 6H₂O
Learn more about respiration, here:
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Draw the major organic product(s) for the reaction. The starting material is a benzene ring with one substituent. The substituent is a nitrogen bonded to a hydrogen and a carbonyl that is bonded to a methyl group. THis reacts with tert butyl bromide and A l b r 3 to give the product.
Answer:
See Explanation
Explanation:
In electrophilic aromatic substitution, the benzene ring undergoes substitution when it is reacted with suitable electrophiles.
The products of electrophilic aromatic substitution depends on the substituents already present on the benzene ring. Some substituents activate the ring towards electrophilic substitution and direct the incoming electrophile to the ortho and para positions on the ring while some substituents deactivate the benzene ring towards electrophilic substitution and direct the incoming electrophlle to the meta position on the ring.
The amide substituent is moderately activating and is an ortho, para director hence the products shown in the mage attached to this answer.
In Atom, what is a heavier sub-atomic particle than the others and explain why
The nucleons are havier in sub atomic particle like neutrons and protons.
fun fact i read in a book even 1cm³ of nucleons are around 2 million Kg which you can't pick up by hand even by machines like buldozer.
2) A 0.77 mg sample of nitrogen gas reacts with chlorine gas to form 6.61 mg of a nitrogen
chloride compound. What is the empirical formula of the nitrogen chloride compound?
Answer:
NCl₃
Explanation:
From the question given above, the following data were obtained:
Mass of nitrogen (N) = 0.77 mg
Mass of chlorine (Cl) = 6.61 mg
Empirical formula =?
The empirical formula of the compound can be obtained as follow:
N = 0.77 mg
Cl = 6.61 mg
Divide by their molar mass
N = 0.77 / 14 = 0.055
Cl = 6.61 / 35.5 = 0.186
Divide by the smallest
N = 0.055 / 0.055 = 1
Cl = 0.186 /0.055 = 3
Therefore, the empirical formula of the compound is NCl₃