Mathematics College

Find the absolute extreme of the function on the closed interval. y=9e^xsinx , [0,pi]

Answers

Answer 1

For convenience sake, I will let [tex]y=f(x)=9e^{x}\sin x[/tex]

First, we evaluate the function at the endpoints of the interval.

[tex]f(0)=9e^{0}\sin(0)=0\\\\f(\pi)=9e^{\pi}\sin(\pi)=0[/tex]

Then, we need to find the critical points.

We can start by taking the derivative using the power rule.

[tex]f'(x)=9e^{x} \frac{d}{dx} \sin x+9\sin x \frac{d}{dx} e^{x}=9e^{x}(\cos x+\sin x)[/tex]

Setting this equal to 0,

[tex]9e^x (\cos x+\sin x)=0[/tex]

Since [tex]9e^x > 0[/tex], we can divide both sides by [tex]9e^x[/tex].

[tex]\cos x+\sin x=0\\\\\sin x=-\cos x\\\\\tan x=-1\\\\x=\frac{3\pi}{4}[/tex]

[tex]f\left(\frac{3\pi}{4} \right)=9e^{3\pi/4}\sin \left(\frac{3\pi}{4} \right)=\frac{9\sqrt{2}e^{3\pi/4}}{2}[/tex]

So, the absolute minimum is [tex]\boxed{\left(\frac{3\pi}{4}, \frac{9\sqrt{2}e^{3\pi/4}}{\sqrt{2}} \right)}[/tex] and the absolute minima are [tex]\boxed{(0,0), (\pi, 0)}[/tex]

Related Questions

cual es la ecuación de la recta que pasa por el punto (2;-1/2) y tiene de pendiente m=-2/3

Answers

Answer:

y = (-2/3)x + 5/6

Step-by-step explanation:

The general structure of a line in slope-intercept form is:

y = mx + b

In this form, "m" represents the slope and "b" represents the y-intercept. You have been given the value of "m". To find the value of "b", you can plug the slope and the values from the point (2, -1/2) into the general equation.

m = -2/3

Point (2, -1/2):

x = 2 and y = -1/2

y = mx + b <----- Slope-intercept form

y = (-2/3)x + b <----- Insert -2/3 in "m"

-1/2 = (-2/3)(2) + b <----- Insert "x" and "y" values from point

-1/2 = -4/3 + b <----- Multiply -2/3 and 2

-3/6 = -8/6 + b <----- Give the fractions common denominators

5/6 = b <----- Add 8/6 to both sides

Thus, the equation of the line is:

y = (-2/3)x + 5/6

In a random sample of 1214 eligible voters younger than 40 years old, 461 reported that they planned to vote in the upcoming election. In a random sample of 1098 voters 40 and older,560 reported that they planned to vote in the election. Construct a 90% confidence interval for the difference between the percent of all voters younger than 40 and 40 and older who plan to vote in the upcoming election. What critical z-score will be used

Answers

Using the z-distribution, with a critical z-score of z = 1.645, the 90% confidence interval is (-16.4%, -9.66%).

What are the mean and the standard error for the distribution of the difference of proportions?

For each sample, the mean and the standard error are given as follows:

[tex]p_y = \frac{461}{1214} = 0.3797, s_y = \sqrt{\frac{0.3797(0.6203)}{1214}} = 0.0139[/tex].[tex]p_o = \frac{560}{1098} = 0.51, s_o = \sqrt{\frac{0.51(0.49)}{1098}} = 0.0151[/tex].

Hence, for the distribution of differences, they are given as follows:

[tex]p = p_y - p_0 = 0.3797 - 0.51 = -0.1303[/tex].[tex]s = \sqrt{s_y^2 + s_o^2} = \sqrt{0.0139^2 + 0.0151^2} = 0.0205[/tex]

What is the confidence interval?

The interval is:

[tex]p \pm zs[/tex]

In this problem, we have a 90% confidence level, hence[tex]\alpha = 0.9[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.9}{2} = 0.95[/tex], so the critical value is z = 1.645.

Then the bounds of the interval are:

p - zs = -0.1303 - 1.645(0.0205) = -0.164.p + zs = -0.1303 + 1.645(0.0205) = -0.0966.

As a percentage, the 90% confidence interval is (-16.4%, -9.66%).

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Please help!!!! For the exponential function...

Answers

Answer: b.) 40

Given that:

f(x) = 5 × 2ˣ

To find f(3), simplify insert [x = 3] in the given equation:

f(3) = 5 × 2³

f(3) = 5 × 2 × 2 × 2

f(3) = 40

what’s the answer to 3\4(8x + 12) = 3

Answers

Answer:

x = - 1

Step-by-step explanation:

[tex]\frac{3}{4}[/tex] (8x + 12) = 3 ( multiply both sides by 4 to clear the fraction )

3(8x + 12) = 12 ( divide both sides by 3 )

8x + 12 = 4 ( subtract 12 from both sides )

8x = - 8 ( divide both sides by 8 )

x = - 1

if you are looking for the x value this is the answerx = -1

Determine whether the events A and B are mutually exclusive. Explain your choice. A sample of 75 books is selected from a library. A: At least 10 of the authors are female: B: At least 10 of the books are fiction.

Answers

The events are not mutually exclusive.

What are Mutually exclusive events ?

Two events that cannot occur at the same time are called Mutually exclusive event.

It is given that

A sample of 75 books is selected from a library.

Event A: At least 10 of the authors are female

Event B : At least 10 of the books are fiction.

Both can happen simultaneously

Therefore the events are not mutually exclusive.

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And a certain watery an urn contains balls number 1 to 34 from this are in five balls are chosen randomly without replacement for a one dollar bed a player chooses one set of phone numbers to Wayne all five numbers match match those shows it from the urn the order in which the balls or select it doesn’t matter what is the probability of winning the lottery with one ticket

Answers

The probability of winning the lottery with one ticket is mathematically given as

P(W)=2.99484408*10^{−8}

What is the probability of winning the lottery with one ticket?

Generally, the equation for the probability is mathematically given as

P(1st ball)=1/34

one ball drawn remain

34-1=33

P(2nd ball)=1/33

In conclusion, the probability of winning the lottery with one ticket is

P(W)=1/34*1/33*1/32*1/31*1/30

P(W)=2.99484408*10^{−8}

Answers

Answer:

(x-2)/(x-1)

Step-by-step explanation:

(x-2)/(x-1)

Which amount of time is greater for the average person? The total time spent on his/her cell phone in a year’s time, or the total time spent waiting in line when shopping in a lifetime?

Consider it to be 2 separate problems and arrive at your conclusion.

You need to make assumptions, conversions, and math calculations to arrive at your answer. If you choose to research data for this project, that is fine but there is no need to site your references.

Answers

The total time spent on his/her cell phone in a year’s time is less than the total time spent waiting in line when shopping in a lifetime.

x= 1825 hrs

z=4929.4 hrs.

This is further explained below.

Which amount of time is greater for the average person?

let's say on average a person spends 5 hours on a mobile phone.

Individual annual mobile phone use time.

x= 5x365

x= 1825 hrs

let's consider an average every day a person, spent 5 minutes in the queue when shopping.

Take the average person. 70-year life for a person.

Hence in a year, he spent

y=365x5 mints

y=1825 min

y=30.42 hrs

Hence lifetime time spent on line

z = 70 x 30.42

z=4929.4 hrs.

In conclusion, we estimate that the typical individual will spend z=4929.4 hours waiting in line for merchandise throughout the course of their lifetime.

z=4929.4 hrs.

Answers

Answer:

81m + 27t

Step-by-step explanation:

Using distributive property, this expression can be solved.

So 9(9m + 3t) has operations in it.

9 would be multiplied by whatever is in the parenthesis followed by the variable.

So 9 * 9 = 81.

9 * 3 = 27.

So putting it together with the variables.

It would be:

⇒ 81m + 27t

A shape is picked at random from this group. Which theoretical probabilities are exactly 3/4?

Check all that apply.

not picking a triangle

picking a square

picking a shape with only straight edges

not picking a circle

not picking a square

Answers

Probability helps us to know the chances of an event occurring. The correct option is D, not picking a circle.

What is Probability?

Probability helps us to know the chances of an event occurring.

[tex]\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}[/tex]

For the theoretical probability to be 3/4, the number of desired outcomes must be 6. Therefore, let's check the number of desired outcomes,

Not picking a triangle = 4

Picking a square = 3

Picking a shape with only straight edges = 0

Not picking a circle = 6

Not picking a square = 5

Hence, the correct option is D, not picking a circle.

The group of the shape is given in the below image.

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You are volunteering to help with the soccer team fundraiser for Valentine's Day. Your team promised to deliver one 16 ounce bag of nuts to students with at least 60% chocolate-covered nuts inside.

When you arrive, instead of a bag of plain nuts and chocolate nuts, you find there are two bags of mixed nuts. The first says it is 50/50 plain and chocolate covered. The second bag contains 80% chocolate covered nuts.

The team is dismayed, but you come up with a solution. You suggest combining

ounces* of the 50/50 bag of nuts with

ounces* of the 80% bag of nuts, to make it an approximately 60% mixture.

*estimate

Then another student on the team says, "Wait, we promised at least 60%. So if we just do half and half won't we be giving them at least 60%?" This student

correct.

Answers

The student, who suggests that if we do half and half of each bag, we will be giving them at least 60%, is correct.

What is the implication of the phrase "at least"?

The phrase "at least" means the minimum that is true or possible.

Mathematically, by "at least," we mean 'equal to or greater than.'

Data and Calculations:

Since each bag of nuts contain 16 ounces,

The 1st bag contains x/2 ounces (50%) of plain nuts and x/2 ounces (50%) of chocolate-covered nuts.

The 2nd bag contains x/5 ounces (20%)of plain nuts and 4x/5 ounces (80%) of chocolate-covered nuts.

If half of the 1st bag is mixed with half of the 2nd bag, each bag will contain only 65% (that is, 25% (50%/2) from the 1st bag and 40% (80%/2) from the 2nd bag).

Thus, the student, who suggests that if we do half and half of each bag, we will be giving them at least 60%, is correct since they will not be given less than 60% of chocolate-covered nuts inside.

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What is the quotient of startstartfraction 90 (cosine (startfraction pi over 4 endfraction) i sine (startfraction pi over 4 endfraction) ) overover 2 (cosine (startfraction pi over 12 endfraction) i sine (startfraction pi over 12 endfraction) ) endendfraction ?

Answers

The value of the quotient is [tex]\frac{45\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})} = 45(\cos(\frac{\pi}{6}) + i\sin(\frac{\pi}{6}))[/tex]

How to determine the quotient?

The expression is given as:

[tex]\frac{90\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{2\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})}[/tex]

Divide 90 by 2

[tex]\frac{45\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})}[/tex]

As a general rule, we have:

[tex]\frac{\cos(\frac{\pi}{A}) i\sin(\frac{\pi}{A})}{\cos(\frac{\pi}{B}) i\sin(\frac{\pi}{B})} = \cos(\frac{\pi}{2B/A}) + i\sin(\frac{\pi}{2B/A})[/tex]

The above means that:

A = 4 and B = 12

So, we have:

2B/A = 2 * 12/4

Evaluate

2B/A = 6

So, the equation becomes

[tex]\frac{\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})} = \cos(\frac{\pi}{6}) + i\sin(\frac{\pi}{6})[/tex]

Substitute [tex]\frac{\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})} = \cos(\frac{\pi}{6}) + i\sin(\frac{\pi}{6})[/tex] in [tex]\frac{45\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})}[/tex]

[tex]\frac{45\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})} = 45(\cos(\frac{\pi}{6}) + i\sin(\frac{\pi}{6}))[/tex]

Hence, the value of the quotient is [tex]\frac{45\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})} = 45(\cos(\frac{\pi}{6}) + i\sin(\frac{\pi}{6}))[/tex]

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Complete question

What is the quotient of [tex]\frac{90\cos(\frac{\pi}{4}) i\sin(\frac{\pi}{4})}{2\cos(\frac{\pi}{12}) i\sin(\frac{\pi}{12})}[/tex]

The following present value factors are provided for use in this problem.

Periods Present Value
of $1 at 8% Present Value of an
Annuity of $1 at 8%
1 0.9259 0.9259
2 0.8573 1.7833
3 0.7938 2.5771
4 0.7350 3.3121
Xavier Co. wants to purchase a machine for $37,500 with a four year life and a $1200 salvage value. Xavier requires an 8% return on investment. The expected year-end net cash flows are $12,500 in each of the four years. What is the machine's net present value?
$(3901).
$3901.
$4783.
$(4783).
$42,283.

Answers

The net present value of machine is $5982

What is investment?

An investment is an asset or item acquired with the goal of generating income or appreciation.

As, 4th Year Cash Flow

= Salvage Value + Expected End Year Net Cash Flow

= $1,200 + $12,500

= $13,700

Year Cash flow ($) PVF at 8% Present value ($)

0 37,500 1.000 -36,300

1 12,500 0.9259 11573.75

2 12,500 0.8573 10716.25

3 12,500 0.7938 9922.5

4 13,700 0.7350 10069.5

Net value 5982

Hence, net present value of machine is $5982

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Which of the following best describes the ordered pairs listed below? (-3, 4), (2, -6), (7, -16), (9, -20) A. function only B. both a relation and a function C. neither a relation nor a function D. relation only

Answers

c neither a relation or a function

If your piece of graph paper goes only 20 blocks above the x-axis, then where will the
function below first go off the page?
y = 2²

Answers

The function will go somewhere between x = 4 and x = 5

How to determine the location of the function?

The function is given as:

y = 2^x

The question implies that:

If the maximum y value on a graph is x = 20; What is the maximum x value on the graph of y = 2^x

To do this, we start by setting y to 20.

So, we have:

2^x = 20

Take the logarithm of both sides

x log(2) = log(20)

Divide by log(2)

x = 4.32

4.32 is between 4 and 5

Hence, the function will go somewhere between x = 4 and x = 5

Answers

Answer:

y = 3x - 13

Step-by-step explanation:

We are given the points (7,8) and (3,-4)

We want to write an equation of the line that passes through those 2 points.

There are 3 ways to write the equation of the line:

Slope-intercept form, which is y=mx+b, where m is the slope and b is the value of y at the y intercept.Standard form, which is ax+by=c, where a, b, and c are free integer coefficients, but a and b cannot be 0 and a cannot be negative. Point-slope form, which is [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1 ,y_1)[/tex] is a point.

Although while any one of these options work, the most common way is to use slope-intercept form, so let's do it that way.

First, we need to find the slope of the line.

The slope (m) can be found using this formula: [tex]\frac{y_2-y_1}{x_2-x_1}[/tex], where [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] are points.

Even though we already have 2 points, let's label their values to avoid any confusion.

[tex]x_1=7\\y_1=8\\x_2=3\\y_2=-4[/tex]

Now substitute these values into the formula.

m=[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

m=[tex]\frac{-4-8}{3-7}[/tex]

Subtract.

m=[tex]\frac{-12}{-4}[/tex]

Divide.

m = 3

The slope of the line is 3.

Here is the equation of the line so far:

y = 3x + b

We now need to find b.

As the equation passes through (7,8) and (3,-4), we can use either one of the points to help us solve for b.

Taking (7,8) for instance:

Substitute 7 as x and 8 as y in the equation.

8 = 3(7) + b

Multiply

8 = 21 + b

Subtract 21 from both sides

-13 = b

Substitute -13 as b in the equation.

y = 3x - 13

Topic: finding the equation of the line

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A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of the line that passes through the points (7,8) and (3,-4) is y=3x-13.

What is the equation of a line?

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of line is given by,

y =mx + c

where,

x is the coordinate of the x-axis,

y is the coordinate of the y-axis,

m is the slope of the line, and

c is the y-intercept.

The slope of the equation will be,

Slope, m = (-4-8)/(3-7) = -12/-4 = 3

Substitute one of the points in the equation of the line,

-4 = 3(3) + C

C = -13

Hence, the equation of the line that passes through the points (7,8) and (3,-4) is y=3x-13.

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A correlation coefficient between number of miles driven and number of gallons of gas remaining is most likely to be __________.

Answers

A correlation coefficient between number of miles driven and number of gallons of gas remaining is most likely to be 0 to -1. Then the correct option is A.

What is a correlation coefficient?

A mathematical indicator of the degree of the association seen between fluctuation of 2 factors is the correlation coefficient.

A correlation coefficient between number of miles driven and number of gallons of gas remaining is most likely to be 0 to -1.

Then the correct option is A.

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Compare A and B in three ways, where A = 1.8 million is the 2012 population of city X and B = 2.6 million is the 2012 population of city Y.

a. Find the ratio of A to B.
b. Find the ratio of B to A.
c. Complete the sentence: A is ____ percent of B.

Answers

The function g(x) = p sin x +q, where p>0, has a maximum value of 10 and a minimum value of -4. Find the value of p and of q.

Answers

Answer: [tex]p=7, q=3[/tex]

Step-by-step explanation:

The midline of the function is

[tex]\frac{10-4}{2}=3 \implies q=3[/tex]

This means that to obtain a maximum of 10, when [tex]\sin x[/tex] reaches it's maximum, 1, [tex]g(x)=p+q=10 \implies p=7[/tex]

HELP ASAP!!!!GIVING BRAINLIEST!!!!!!
If f(x)=2x^2+2 and g(x)=x^2-1, find (f-g)(x).

Answers

Answer: B. x^2 + 3

Step-by-step explanation:

2x^2 + 2 -(x^2 - 1)

2x^2 + 2 - x^2 + 1

x^2 + 3

If f (x) = 2x ^ 2 + 2
Answer is B
x2 + 3

PLEASE HELP ME! I WILL AWARD BRAINLIEST TO WHOEVER ANSWERS THE QUESTION BEST!

Which of the following could be solution to the equation below?
[tex]cos(3x+4)=sin(2x+6)[/tex]

A. x = 2, sin 10° = cos 10°
B. x = 16, sin 52° = cos 38°
C. x = 34, sin 74° = cos 106°
D. x = 16, sin 38° = cos 52°

Answers

Using complementary angles, it is found that a solution to the given equation is:

D. x = 16, sin 38° = cos 52°.

What are complementary angles?

Two angles are called complementary if the sum of their measures is of 90º. If two angles A and B are complementary, we have that:

cos(A) = sin(B) and sin(A) = cos(B).

In this problem, the expression is:

cos(3x + 4) = sin(2x + 6).

Hence:

3x + 4 + 2x + 6 = 90

5x = 80

x = 16.

Then:

cos(3x + 4) = cos(52).sin(2x + 6) = sin(38).

Which means that option D is correct.

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Lily read 3 books in 4 months. What was her rate of reading in books per month? Express your answer in simplest form.

Answers

Answer:

1.33 repeating

Step-by-step explanation:

you just do 4 divided by 3.

Please mark as brianliest if i got it right

Answer is 3/4 or 75% or .75 rate
Reason
She read 3 books out of 4 months
So 3/4

z varies directly as x⎯⎯√ and inversely as y2. If z=182 when x=25 and y=8, find z if x=64 and y=3.

Answers

When x = 64 and y = 3, we will have:

z = 3,313.21

How to find the value of z?

First, we know that z varies directly with x and inversely with y², then we can write:

z = k*x/y^2

Where k is a constant.

We know that z = 182 when x = 25 and y = 8, replacing that we can find the value of k.

182 = k*25/(8²)

k = 182*8²/25 = 465.92

Now, we just need to evaluate the function in x = 64 and y = 3.

z = (465.92)*64/3² = 3,313.21

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Geometry
Help pls list steps so I can learn :)

Answers

Answer: [tex]\frac{25\pi}{4}[/tex]

Step-by-step explanation:

The area of the entire circle is [tex]\pi(5^2)=25\pi[/tex].

The area of a quarter of the circle is thus [tex]\frac{25\pi}{4}[/tex]

Given: Triangle ABC, mmBC=24 cm, line segment AL- < bisector
Find: AL

AL= __cm
Please answer in detail ASAP thank you so much it would help a lot <3

Answers

The value of line AL is 21. 51cm

How to determine the length

To find line AL,

Using

Sin α = opposite/ hypotenuse to find line AB

Sin 90 = x/ 24

1 = x/24

Cross multiply

x = 24cm

Now, let's find line AC

Sin angle B = line AC/24

Note that to find angle B

angle A + angle B + angle C = 180

But angle B = 2 Angle A

x + 2x + 90 = 180

3x + 90 = 180

3x = 180-90

x = 30°

Angle B = 2 × 30 = 60°

Sin 60 = x/ 24

0. 8660 = x/24

Cross multiply

x = 24 × 0. 8660

x = 20. 78cm

We have the angle of A in the given triangle to be divide into two by the bisector, angle A = 15°

To find line AL, we use

Cos = adjacent/ line AL

Cos 15 = 20. 78/ line AL

Line AL = 20. 78/ cos 15

Line AL = 20. 78 / 0. 9659

Line AL = 21. 51 cm

Thus, the value of line AL is 21. 51cm

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A distributor has received an invoice of $13,190 dated April 12, terms 6/20, n/30 EOM, for a

shipment of coffee makers that arrived on May 25.

a) What is the last day for taking the cash discount?

b) How much is to be paid if the discount is taken? $

Answers

The last day for taking the cash discount is May 5 and discount is taken is: $12,398.6.

Cash discount

Since the invoice was dated April 12, the last day for taking the cash discount is May 5.

Cash discount

Using this formula

Amount paid =Invoice amount × (1-rate)

Let plug in the formula

Amount paid=$13,190 ×(1-6%)

Amount paid=$13,190×0.94

Amount paid=$12,398.6

Therefore the last day for taking the cash discount is May 5 and the amount to be paid is: $12,398.6.

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Determine if
16
x
2
−
25
y
2
=
1
16
x
2
-
25
y
2
=
1
is a hyperbola and if it is, which type it is. The transverse axis is
what is A and B

Answers

The values of a and b are 1/4 and 1/5 respectively

How to determine the true statement?

The function is given as:

16x^2 - 25y^2 = 1

The above function is a horizontal hyperbola.

A horizontal hyperbola that passes through the origin is represented as:

[tex]\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1[/tex]

Rewrite 16x^2 - 25y^2 = 1 as

[tex]\frac{x^2}{1/16} - \frac{y^2}{1/25} = 1[/tex]

By comparison, we have:

[tex]a^2 = \frac{1}{16}[/tex]

[tex]b^2 = \frac{1}{25}[/tex]

Solve for a and b

[tex]a = \frac{1}{4}[/tex]

[tex]b = \frac{1}{5}[/tex]

Hence, the values of a and b are 1/4 and 1/5 respectively

Answers

Hello !

3y + 12 =2(y + 30)

⇔ 3y + 12 = 2y + 60

⇔ y + 12 = 60

⇔ y = 60 - 12

⇔ y = 48

Answer:

y = 48

Step-by-step explanation:

the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

3y + 12 is an exterior angle of the triangle , so

3y + 12 = y + 30 + y + 30 ( base angles of an isosceles Δ are congruent )

3y + 12 = 2y + 60 ( subtract 2y from both sides )

y + 12 = 60 ( subtract 12 from both sides )

y = 48

explain the error and solve the equation correctly. Be sure to use the equation editor to show your work

(x-3)(x+1)=5

Answers

The solution to the given linear equation are -4 and 2

Solving quadratic equation

Quadratic equations are equations that has a leading degree of 2. Given the expression below

(x-3)(x+1)=5

Expand

x^2+x - 3x - 3 = 5

x^2 - 2x - 8 =0

Factorize

x^2 + 4x - 2x - 8= 0

x(x+4)-2(x+4) = 0

x = -4 and 2

Hence the solution to the given linear equation are -4 and 2

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These 3 points are on a parabola defining the edge of a ski:

(-4,1)
(-2,0.94)
(0,1)
The general form for the equation of a parabola is .

1.
Use the x- and y-values of 1 to build a linear equation with 3 variables: A, B, and C.
Repeat this process with the other 2 points to build a 2nd linear equation.
Record all three equations in the box below.

2.
Build a matrix equation that represents this system of equations. Record your matrix equation here.

3.
Use a graphing calculator or other graphing utility to find the inverse of the coefficient matrix. Record your result here.

4.
Use the inverse matrix to solve the system of equations. Record the equation of the parabola here.

Answers

The equation of the parabola is y = 0.015x^2 + 0.06x + 1

The linear equations

A parabola is represented as:

y = ax^2 + bx + c

The points are given as:

(-4,1), (-2,0.94) and (0,1)

When these points are substituted in y = ax^2 + bx + c, we have the following linear equations

16a - 4b + c = 1

4a - 2b + c = 0.94

c = 1

The matrix that represent the system of equations

In (a), we have:

16a - 4b + c = 1

4a - 2b + c = 0.94

c = 1

Remove the variables (leaving the coefficients)

a b c

16 -4 1 1

4 -2 1 0.94

0 0 1 1

So, the matrix representation of the system of equations is:

[tex]\left[\begin{array}{ccc}16&-4&1\\4&-2&1\\0&0&1\end{array}\right] \left[\begin{array}{c}1&0.94&1\end{array}\right][/tex]

The inverse of the coefficient matrix

Using a graphing calculator, we have the inverse of the coefficient matrix to be

[tex]\left[\begin{array}{ccc}0.125&-0.25&0.125\\0.25&-1&0.75\\0&0&1\end{array}\right][/tex]

The solution to the system of equations

Using a graphing calculator, we have the solution to the system of equations to be

a = 0.015

b = 0.06

c = 1

Recall that:

y = ax^2 + bx + c

So, we have:

y = 0.015x^2 + 0.06x + 1

Hence, the equation of the parabola is y = 0.015x^2 + 0.06x + 1