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Consult a peer or a family member about ways your design could be improved. Describe the feedback and provide the name of the reviewer. These are only suggestions that you can use to plan for Design Two. Use complete sentences and detailed examples.
l need this answer first one to get it gets brainlist

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Answer 1

Explanation:

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Related Questions

Consider the following chemical reaction:
2 Cr(OH)3(aq) ------------> Cr2O3(s) + 3H2O(l)

12.00 moles of chromium (III) hydroxide is decomposed. Calculate moles of the water produced.

Answers

From the calculation, the moles of water produced is 18 moles of water.

What is a decomposition reaction?

A decomposition reaction is one in which a substance is split up into smaller parts.

We have the reaction; 2 Cr(OH)3(aq) ------------> Cr2O3(s) + 3H2O(l)

From this reaction;

2 moles of  Cr(OH)3 produced 3 moles of water

12 moles of  Cr(OH)3 will produce;

12 moles  *  3 moles / 2moles

= 18 moles of water

Hence, 12 moles of chromium (III) hydroxide produces 18 moles of water.

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What is hypotheses
?

Answers

Answer:

is an assumption , in an idea that is proposed for the sake of argument so that it can be tested to see if it might be true.

아 이거 끝이 없어

it’s an assumption or prediction for the experiment before you do it

A sample of helium gas inside a closed but flexible container occupies a volume of 355mL at 23°C. If the pressure is held constant, to what temperature must the He be raised to cause the container to expand to a final volume of 1.50 L?

Answers

Answer:

978.19° C

Explanation:

P1V1/T1 =P2V2/T2     Since the pressure is constant, this can be written as

V1/T1 = V2/T2      RE-ARRANGE TO

V2 *  T1/V1   = T2       Note:  T must be in Kelvin!!

1.5 L  *  (273.15 + 23)  / (.355 L ) = T2 = 1251.338 K  =978.19 C


How much does 2.3 moles of Mg(NO2)2 weigh?

Answers

Answer:

mass = 266.8 g

Explanation:

mass = no. of moles  x   molar mass ([tex]M_r[/tex])

[tex]M_r \space\ \space\ of[/tex] [tex]Mg(NO_2)_2[/tex]   = 24 + 2[14 + 2(16)]

                                 = 116

∴ mass = 2.3  x  116

            = 266.8 g

Perform the calculation to the correct number of significant figures. (8.81 - 7.50)/0.0020

Answers

Answer:

655

Explanation:

using bodmas, (bracket first), 8.81-7.50=1.31

1.31÷0.0020=655

A space shuttle gaining speed as it travels through earth's atmosphere? A) 1st Law B) 2nd Law C) 3rd Law​

Answers

Answer is B) Newton’s second law
Reason - Acceleration. Newton's Second Law Equation.

what substances dissociate into ions when dissolved in water

Answers

Polar or ionic substances dissociate into ions when dissolved in water.

What substances dissociate into ions when dissolved in water?

Ionic substances dissociate into ions when dissolved in water because water is also a polar by nature. We know that like dissolve like so polar substances dissolve in water and dissociate into ions i.e. positive an negative ions.

So we can conclude that polar or ionic substances dissociate into ions when dissolved in water.

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The compound HgO can be decomposed to form Hg and O2. This can be represented at the atomic level by a chemical equation:
2HgO 2Hg + O2

According to the law of conservation of mass, if 23.5 grams of HgO decomposes and 21.8 grams of Hg is formed, how many grams of O2 must simultaneously be formed?

Answers

According to the law of conservation of mass 1.7 grams of [tex]O_2[/tex] will be formed.

What are moles?

A mole is defined as 6.02214076 × 1[tex]0^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

[tex]2HgO[/tex]→ [tex]2Hg + O_2[/tex]

According to the laws of conservation mass of reactants should be equal to the mass of products.

23.5 grams - 21.8 grams

1.7 grams of [tex]O_2[/tex] will be formed.

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Solve this whole experiment,
I'll be so glad . thanks
●do the above experiment
●give detailed answers
THANKS ​

Answers

Are you saying yes or no to this Bec it’s your prediction

How many moles of H2SO4 are needed in 0.500m³ of a 0.150M tetraoxosulphate solution?​

Answers

Answer:

0.015 moles

Explanation:

0.500 m³ of a 0.150 M tetraoxosulphate solution contains 0.075 moles of tetraoxosulphate ions. Since 1 mole of H2SO4 is needed for every 2 moles of tetraoxosulphate ions, then 0.015 moles of H2SO4 are needed.

Determine the molar mass of a gas that moves 1.25 times as fast as CO2.

Answers

The molar mass of a gas that moves 1.25 times as fast as CO2 is 28.16 g.

Molar mass of the gas

The molar mass of the gas is determined by applying Graham's law of diffusion.

R₁√M₁ = R₂√M₂

R₁/R₂ = √M₂/√M₁

R₁/R₂ = √(M₂/M₁)

where;

R₁ is rate of the CO2 gasM₁ is  molar mass of CO2 gasR₂ is rate of the second gasM₂ is the molar mass of the second gas

R₁/1.25R₁ = √(M₂/44)

1/1.25 =  √(M₂/44)

0.8 = √(M₂/44)

0.8² = M₂/44

M₂ = 0.8² x 44

M₂ = 28.16 g

Thus, the molar mass of a gas that moves 1.25 times as fast as CO2 is 28.16 g.

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when 1 mol of glucose is burned, 2802.5kj of energy is released. calculate rhe quantity of energy released to a person by eating 5.00g of glucose in a candy

Answers

77.78 kJ of energy is released when 1 mol of glucose is burned, 2802.5 kJ of energy is released.

What are moles?

A mole is defined as 6.02214076 ×[tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Calculate the moles of 5.00g of glucose.

Given mass = 5.00g

The molar mass of glucose = 180.156 g/mol

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]Moles = \frac{5.00g}{180.156 g/mol}[/tex]

Moles =0.02775372455

The quantity of energy released to a person by eating 5.00g of glucose in a candy.

0.02775372455 x 2802.5 kJ

77.77981305 kJ =77.78 kJ

Hence, 777.78 kJ of energy is released.

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How much would a 55 kg person weigh on venus

Answers

Answer:

109.988623 Pounds or 49.89kg

Explanation:

49.73 kg!

Weight on Venus= (Weight on Earth/9.81m/s2) * 8.87m/s2

what is the frequency of a photon with an energy of 4.56 x 10-19J?

Answers

Answer:

The wavelength of a photon with an energy of 4.56×10⁻¹⁹ J is 463nm (nanometer)

Define the wavelength of a photon.

Each photon has a wavelength and a frequency. The wavelength is defined as the distance between two peaks of the electric field with the same vector.

A photon is the smallest element of electromagnetic radiation. You can think of a photon as a packet of energy travelling at the speed of light. There is no constant wavelength of a photon, it is dependent on how much energy the photon carries.

The mathematical relationship can be written as

E=hc/ λ

In terms of wavelength,

λ=hc/E

- h is planks constant

- c is the speed of light

- E is the energy of the photon

Where h = 6.626×10⁻³⁴ J⋅s is Planck’s constant and c = 3×10⁸ m/s is the speed of light.

If E = 4.56×10⁻¹⁹ J then λ = 463nm (nano meter)

Hence, the wavelength of a photon with an energy of 4.56×10⁻¹⁹ J is 463nm(nanometer)

Hope its helpful!

Answer:

The wavelength of a photon with an energy of 4.56×10⁻¹⁹ J is 463nm (nanometer)

Define the wavelength of a photon.

Each photon has a wavelength and a frequency. The wavelength is defined as the distance between two peaks of the electric field with the same vector.

A photon is the smallest element of electromagnetic radiation. You can think of a photon as a packet of energy travelling at the speed of light. There is no constant wavelength of a photon, it is dependent on how much energy the photon carries.

The mathematical relationship can be written as

E=hc/ λ

In terms of wavelength,

λ=hc/E

- h is planks constant

- c is the speed of light

- E is the energy of the photon

Where h = 6.626×10⁻³⁴ J⋅s is Planck’s constant and c = 3×10⁸ m/s is the speed of light.

If E = 4.56×10⁻¹⁹ J then λ = 463nm (nano meter)

Hence, the wavelength of a photon with an energy of 4.56×10⁻¹⁹ J is 463nm(nanometer)

electronic configuration of organic compounds

Answers

The electronic configuration of organic compounds depends on the orbitals of their atoms and molecules.

What is electronic configuration?

The expression 'electronic configuration' makes reference to the spacial arrangement of electrons in distinct energy orbitals of an atom/molecule.

The orbitals are designed with numbers and letters, whereas the amount of electrons in each orbital is expressed as superscripts (e.g., 1s² 2s² 2p² in the C atom that form glucose).

In conclusion, electronic configuration of organic compounds depends on the orbitals of their atoms and molecules.

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If 5.00 L of argon gas is at 0.460 atm and -123°C, what is the volume at STP?

Answers

Answer:

4.27 L

Explanation:

STP = 0 C   and   1 atm  

P1V1/T1   = P2V2/T2       where T is in Kelvin

P1 V1 / T1   *T2/P2   = V2

.469 * 5 / ( 273.15-123)  *  273.15/1   = V2 = 4.27 L

What is the molality, m, of a solution made by adding 8.21 g of solid naphthalene, C10H8, to 27.92 g of liquid benzene, C6H6? The molar mass of naphthalene = 128.2 g/mol and benzene = 78.1 g/mol.

Answers

4.21×[tex]10^{-4}[/tex] Molal is the molality, m, of a solution made by adding 8.21 g of solid naphthalene, [tex]C_{10}H_8[/tex], to 27.92 g of liquid benzene,[tex]C_6H_6[/tex].

What are moles?

A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

[tex]Molality = \frac{Moles \;solute}{Solvent \;in \;kg}[/tex]

Moles of naphthalene=[tex]\frac{mass}{molar \;mass}[/tex]

Moles of naphthalene[tex]=\frac{8.21 g}{128.2 g/mol}[/tex]

=0.064

Moles of benzene[tex]=\frac{mass}{molar \;mass}[/tex]

Moles of benzene[tex]=\frac{27.92 g}{78.1 g/mol}[/tex]

=0.357

Total mole of solute= 0.064+0.357=0.421

[tex]Molality = \frac{Moles \;solute}{Solvent \;in \;kg}[/tex]

[tex]Molality = \frac{0.421 }{1000}[/tex]

Molality = 4.21×[tex]10^{-4}[/tex] Molal

Hence, 4.21×[tex]10^{-4}[/tex] Molal is the molality, m, of a solution made by adding 8.21 g of solid naphthalene, [tex]C_{10}H_8[/tex], to 27.92 g of liquid benzene, [tex]C_6H_6[/tex].

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Discuss why the solubility of CaCO33(s) would be greater in distilled water than in tap water that contains 50 mg/L of calcium ions (Ksp CaCO3 = 8.7x10-9).

Answers

Answer:

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Explanation:

uodigdoydoydohhxoydoydodkgdyodisirs85ssto toutuset8itgxotteotsmvtieksititsgie8e85t8upfgtjwdujhftisnfvoyxuvfgkrtj57lhmdkhflfheogkhptufsjfxocljhflhfoydllbxoydoggsigxitieoyurreifosuuluprohgsjtgjzffgfhcpzfjchzjfcg gsjiggdoydogxlhd6oxhx9yfljf

The greater, the ionic property, the greater will be solubility. water is a covalent compound where calcium carbonate is ionic that's why the solubility of [tex]CaCO_{3}[/tex](s) would be greater.

What is solubility?

The capability of a substance, the solvent, to combine with another substance, the solvent, has been known as solubility. Insolubility, or just the solute's inability to create that kind of a solution, would be the opposite attribute.

How does solubility depend on the ionic compound?

Ionic chemicals dissolve readily in just about any liquid that has the ability to rupture the ionic link present in them. Since water itself has a stronger ionic bond and is still polar in nature, water disrupts the ionic link by hydrogen bonding. Several other solvents, like kerosene and gasoline, are unable to dissolve the ionic bond.

The greater, the ionic property, the greater will be solubility. water is a covalent compound where calcium carbonate is ionic that's why the solubility of [tex]CaCO_{3}[/tex](s) would be greater in distilled water than in tap water that contains 50 mg/L of calcium ions

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a compound with a molar mass of 92g/mol contains 0.3955g of nitrogen and 0.904g of oxygen. Determine the empirical and molecular formula

Answers

Answer:

Empirical: NO2. Molecular: N2O4

Explanation:

In order to determine the empirical formula, we divide each element's mass by their respective molar mass:

N: 0.3955g/14.01 g/mol = 0.02823 mol

O: 0.904g/16.00 g/mol = 0.0565 mol

Next, we take the smallest value and multiply it till it is close enough to an integer:

0.02823 x 40 = 1.12 Close enough to 1.

0.0565 x 40 = 2.26. Close enough to 2.

Therefore, the Empirical Formula is: NO2

Next, we determine how much the Empirical formula weighs and see if it matches 92g/mol:

14.01 g/mol + 2(16.00 g/mol) = 46.01 g/mol

We can assume this is roughly half of 92 g/mol so we can multiply each subscript by 2 to match the weight.

Therefore, the Molecular formula is N2O4

Hope this helped!

How much pure alcohol is in a 316 mL bottle of a "wine cooler" that is 4.8 percent alcohol by volume?

Answers

Answer:

15.17 ml

Explanation:

4.8 % is .048 in decimal

316 ml  * .048 = 15.17 ml    ( about 1/2 ounce)

Which of the following chemical reactions is a decomposition reaction?


2 HgO → 2 Hg + O2


Al + 3 CuCl → AlCl3 + 3 Cu


2 H2 + O2 → 2 H2O


HCl + NaOH → NaCl + H2O

Answers

Answer:

2 HgO → 2 Hg + O2

Explanation:
Decomposition is when one reactant breaks down into two or more products due to heat, light or electricity
Here mercury (II) oxide goes through thermal decomposition to make mercury and oxygen

Answer:

2HgO—»2Hg+O_2

Explanation:

The decomposition reaction

It's reaction in which a single reactant gives two or more than two products

Here Mercury oxide gives mercury and oxygen

so option A is decomposition

1. Balance the equation below: Fe(s) + Cl₂(g) → FeCl3(aq) 2. Calculate the moles of FeCl3 that will form if 2.0 moles of Fe react with sufficient Cl₂. 3. Calculate the moles of FeCl3 that will form if 1.0 moles of each reactant mix together. 4. How many grams of FeCl3 that will form if 1.0 g of each reactant mix?​

Answers

Answer:

1.) 2 Fe (s) + 3 Cl₂ (g) ---> 2 FeCl₃ (aq)

2.) 2.0 moles FeCl₃

3.) 0.67 moles FeCl₃

4.) 1.5 g FeCl₃

Explanation:

1.)

The unbalanced reaction:

Fe (s) + Cl₂ (g) ---> FeCl₃ (aq)

Reactants: 1 iron, 2 chlorine

Products: 1 iron, 3 chlorine

The balanced reaction:

2 Fe (s) + 3 Cl₂ (g) ---> 2 FeCl₃ (aq)

Reactants: 2 iron, 6 chlorine

Products: 2 iron, 6 chlorine

2.)

To find moles FeCl₃, you need to multiply the given value by the mole-to-mole ratio of Fe to FeCl₃. This ratio is constructed via the coefficients from the balanced equation.

2.0 moles Fe          2 moles FeCl₃
---------------------  x  ------------------------  = 2.0 moles FeCl
                                 2 moles Fe

3.)

To determine how much FeCl₃ is produced, you need to identify the limiting reagent. To find it, you need to convert both reactants to the product then identify which reactant gives you the smallest amount of product. This reactant is the limiting reagent and will give you your actual answer.

1.0 mole Fe         2 moles FeCl₃
-------------------  x  -----------------------  = 1.0 moles FeCl
                               2 moles Fe

1.0 mole Cl₂         2 moles FeCl₃
-------------------  x  ------------------------  = 0.67 moles FeCl
                              3 moles Cl₂

4.)

Because Cl₂ is the limiting reagent, we need to convert grams Cl₂ to grams FeCl₃. This can be done using the molar masses of both compounds and the mole-to-mole ratio.

Molar Mass (Cl₂): 2(35.453 g/mol)

Molar Mass (Cl₂): 70.906 g/mol

Molar Mass (FeCl₃): 55.845 g/mol + 3(35.453 g/mol)

Molar Mass (FeCl₃): 162.204 g/mol

1.0 g Cl₂          1 mole             2 moles FeCl₃         162.204 g
-------------  x  -----------------  x  -----------------------  x  ------------------  =  1.5 g FeCl
                      70.906 g            3 moles Cl₂              1 mole

In the preparation of the soap above, a student dissolved 5 g of NaOH in 25 mL water and added 10 mL palm kernel oil (density: 0.997 g/cm3). The mixture was heated and boiled with 20 mL of water, followed by addition of NaCl to the soap solution. At the end of the experiment, the student obtained 6.2 g of soap What is the percentage yield of the soap?

Answers

The  Percent yield of  soap is 17.8%

What is the percent yield of soap?

Percent yield is given as follows:

Percent yield = actual yield/expected yield * 100%

The actual yield of soap = 6.2 g

The expected yield is determined from the equation of the reaction.

The equation of the reaction is given as follows:

NaOH + CH₃(CH₂)₁₄COOH ----> CH₃(CH₂)₁₄COONa + H₂O

Molar mass of (palm kernel oil) CH₃(CH₂)₁₄COOH = 256 g/mol

Molar mass of NaOH = 40 g/mol

Molar mass of (soap) CH₃(CH₂)₁₄COONa = 278 g/mol

Mass of palm kernel oil = 9.9 g

Expected mass of soap = 5/40 * 278 = 34.75 g

Percent yield = 6.2/34.75 * 100 = 17.8%

Therefore, the Percent yield of  soap is 17.8%

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Consider the following balanced chemical reaction: 2 H2(g) + CO (g) -> CH4O (1). If
6.12 g of H₂ reacts with excess CO, how many grams of CH4O can be produced?
Select one:
a. 16.5g
b. 27.29
c. 64.5g
d. 48.6 g
e. 75.8 g

Answers

Answer:

d

Explanation:

2H₂(g) +CO(g) → CH₄O (l)

Since H₂ was reacted with excess CO, H₂ is the limiting reagent. This means that the amount of product formed is dependent on the amount, i.e. the number of moles, of H₂.

The number of moles of H₂ can be calculated by taking the mass divided by its Mr (relative molecular mass).

Mr of H₂= 2(1)= 2

Moles of H₂ (g)

= 6.12 ÷2

= 3.06 mol

From the balanced equation, 2 moles of H₂(g) produces 1 mole of CH₄O(g).

Since we have 3.06 moles of H₂(g),

Moles of CH₄O (l) produced

= 3.06 ÷2

= 1.53 mol

Mr of CH₄O

= 12 +4 +16

= 32

Mass= mole ×Mr

Mass of CH₄O (l) produced

= 1.53(32)

= 48.96 g

Thus, d would be the best option.

2FeCl + 3Na2CO2= Fe2 (CO3)3 + 6NaCl
If you begin a reaction with 127.490 g of Na2CO3, how many moles of NaCl can you theoretically produce, assuming an excess of FeCl3 is present?
I need help

Answers

Taking into account the reaction stoichiometry, 2.405 moles of NaCl are formed when  127.49 grams of Na₂CO₂ reacts with excess of FeCl₃.

Reaction stoichiometry

In first place, the balanced reaction is:

2 FeCl+ 3 Na₂CO₂ → Fe₂(CO₃)₃ + 6 NaCl

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

FeCl: 2 moles Na₂CO₂: 3 molesFe₂(CO₃)₃: 1 moleNaCl: 6 moles

The molar mass of the compounds is:

FeCl: 91.3 g/moleNa₂CO₂: 106 g/moleFe₂(CO₃)₃: 291.7 g/moleNaCl: 58.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

FeCl: 2 moles ×91.3 g/mole= 182.6 gramsNa₂CO₂: 3 moles ×106 g/mole= 318 gramsFe₂(CO₃)₃: 1 mole ×291.7 g/mole= 291.7 gramsNaCl: 6 moles ×58.45 g/mole= 350.7 grams

Mass of NaCl produced

The following rule of three can be applied: if by reaction stoichiometry 318 grams of Na₂CO₂ form 6 moles of NaCl, 127.49 grams of Na₂CO₂ form how many moles of NaCl?

[tex]moles of NaCl=\frac{127.49 grams of Na_{2} CO_{2} x6 moles of NaCl }{318grams of Na_{2} CO_{2} }[/tex]

moles of NaCl= 2.405 moles

Then, 2.405 moles of NaCl are formed when  127.49 grams of Na₂CO₂ reacts with excess of FeCl₃.

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Which of the following equations is correct for coffee-cup calorimeter?
q reaction = q calorimeter
q reaction = -q calorimeter

Answers

The equation that is correct for coffee-cup calorimeter is q reaction = -q calorimeter. Details about coffee-cup calorimeter.

What is a calorimeter?

A calorimeter is an apparatus for measuring the heat generated or absorbed by either a chemical reaction, change of phase or some other physical change.

A coffee-cup calorimeter is a specific type of calorimeter that involves the absorption of heat of a reaction by water when a reaction occurs.

The enthalpy change of the reaction is equal in magnitude but opposite in sign to the heat flow for the water:

qreaction = -(qwater)

Therefore, the equation that is correct for coffee-cup calorimeter is q reaction = -q calorimeter.

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In a constant‑pressure calorimeter, 55.0 mL of 0.310 M Ba(OH)2 was added to 55.0 mL of 0.620 M HCl.
The reaction caused the temperature of the solution to rise from 24.25 ∘C to 28.47 ∘C. If the solution has the same density and specific heat as water ( 1.00 g/mL and 4.184J/g⋅°C,) respectively), what is Δ for this reaction (per mole H2O produced)? Assume that the total volume is the sum of the individual volumes.

Answers

The enthalpy change (ΔH) for the reaction (per mole H₂O produced) is 56.96 KJ/mol

How to determine the mass of the solutionVolume = 55 + 55 = 110 mLDensity = 1 g/mLMass = ?

Mass = density × volume

Mass = 1 × 110

Mass = 110 g

How to determine the heat Mass (M) = 110 gInitial temperature (T₁) = 24.25 °C Final temperature (T₂) = 28.47 °CChange in temperature (ΔT) = 28.47 – 24.25 = 4.22 °C Specific heat capacity (C) = 4.184 J/gºC Heat (Q) =?

Q = MCΔT

Q = 110 × 4.184 × 4.22

Q = 1942.2128 J

How to determine the mole of H₂O produced

Ba(OH)₂ + 2HCl --> BaCl₂ + 2H₂O

Since the reaction occurs in a constant‑pressure calorimeter, it means both reactants are sufficient enough for the reaction.

Mole of Ba(OH)₂ = molarity × volume

Mole of Ba(OH)₂ = 0.310 × (55 / 1000)

Mole of Ba(OH)₂ = 0.01705 mole

From the balanced equation above,

1 mole of Ba(OH)₂ reacted to produce 2 moles of H₂O.

Therefore,

0.01705 mole of Ba(OH)₂ will react to produce = 0.01705 × 2 = 0.0341 mole of H₂O.

How to determine the enthalpy change ΔH per mole of H₂O producedHeat (Q) = 1942.2128 JMole of H₂O (n) = 0.0341 moleEnthalpy change (ΔH) =?

ΔH = Q / n

ΔH = 1942.2128 / 0.0341

ΔH = 56956.29 J/mol

Divide by 1000 to express in KJ/mol

ΔH = 56956.29 / 1000

ΔH = 56.96 KJ/mol

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In Part A, we saw that the theoretical yield of aluminum oxide is 1.60 mol . Calculate the percent yield if the actual yield of aluminum oxide is 1.22 mol .

Answers

Taking into account definition of percent yield, the percent yield for the reaction is 76.25%.

Percent yield

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

[tex]percent yield=\frac{actual yield}{theorical yield}x100[/tex]

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

Percent yield in this case

In this case, you know:

actual yield= 1.22 moltheorical yield= 1.60 mol

Replacing in the definition of percent yields:

[tex]percent yield=\frac{1.22 mol}{1.60 mol}x100[/tex]

Solving:

percent yield= 76.25%

Finally, the percent yield for the reaction is 76.25%.

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A student performs the following lead extraction to test the stoichiometric method and to determine the efficiency of the reaction. In the reaction 49.5 g of lead(II) nitrate is reacted with excess zinc in a single displacement reaction.

a. Calculate the theoretical yield of lead in the experiment.
b. After separating the lead by filtration and allowing it to dry, the student obtains 19.8g of lead. What is the percent yield of the experiment?

Answers

Theoretical yield produced is 31.8 gram and the percentage yield is 62.27%.

The zinc (Zn) is more reactive than lead (Pb). So that zinc loses electrons more easily than lead .

And the electrons of Zn are transfer to lead in this reaction .

This question is a limiting reactant question .

And For limiting reactant questions so that we need to determine that how much product can be produced by all reactant .

Zinc and Lead (II) nitrate react to form Zinc Nitrate and Lead.

Zn + Pb(NO₃)₂ → Zn(NO₃)₂ + Pb

Now we have- Weight of Pb(NO₃)₂ = 49.5 g

molar mass of Pb(NO₃)₂ = 331.2 g

now moles of Pb(NO₃)₂ = 49.5 ÷ 331.2 = 0.15 moles

Moles of Pb consumed = 1 × 0.15 = 0.15

moles mass of Pb consumed = 0.15 × 207.2 = 31.8 gm

Here Zn is in excess so that lead(II) nitrate is a limiting reactant.

(a) Theoretical yield of lead -  

moles of Pb produced = 0.15 × 1  = 0.15 moles

molar mass of Pb = 207.2g

mass of Pb produced in reaction = 0.15 × 207.2   = 31.08 g

theoretical yield = 31.8 gram

(b) After separating the lead by filtration -

obtained lead = 19.8gm

Percentage yield = 19.8 ÷ 31.8 ×100 = 62.27%

so that after separating the lead the percentage yield is 62.27%.

So, After applying the concepts of stoichiometric method the theoretical yield produced came out to be 31.8 gram and the percentage yield came out to be 62.27%.

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Identify the nitrogen compound represented by the formula NO2.
Nitrous oxide
Nitrite
ammonia
nitrate

Answers

Answer:

Nitrite

Explanation:

Nitrous Oxide = N₂O

Nitrite = NO₂

Ammonia = NH₃

Nitrate = NO₃⁻

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