Exams are approaching and Helen is allocating time to studying for exams. She feels that with the appropriate amount of studying, she has an 80% chance of getting an A in Marketing. She also feels that she has a 60% chance of getting an A in Spanish with the appropriate amount of studying. Given the demands on her time, she feels that she has only a 45% chance of getting an A in both classes. What is the probability that Helen does not get an A in either class?

Answers

Answer 1

Answer: 0.05

Step-by-step explanation:

Let M = Event of getting an A in Marketing class.

S = Event of getting an A in Spanish class,

i.e. P(M) = 0.80 , P(S) = 0.60 and P(M∩S)=0.45

Required probability = P(neither M nor S)

= P(M'∩S')

= P(M∪S)'                                 [∵P(A'∩B')=P(A∪B)']

=1- P(M∪S)                               [∵P(A')=1-P(A)]

= 1- (P(M)+P(S)- P(M∩S))   [∵P(A∪B)=P(A)+P(B)-P(A∩B)]

= 1- (0.80+0.60-0.45)

= 1- 0.95

= 0.05

hence, the probability that Helen does not get an A in either class= 0.05


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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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Answers

Steps to solve:

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~Substitute

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~Simplify

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Step-by-step explanation:

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Answers

Answer:

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Answer:

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Step-by-step explanation:

One way to make a decimal non-repeating is to extend a pattern by one digit each time you write the pattern. That is the structure of the number Sophia and Nora are looking at. It is also the structure of the number in your question ...

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__

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Answer:

Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer and Step-by-step explanation:

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Answers

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Answers

Answer:

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Answers

Answer:

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Step-by-step explanation:

Given:

A tank of,

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