Ethanol (C2H5OH) melts at –114 °C and boils at 78 °C. The enthalpy of fusion of ethanol is 5.02 kJ/mol, and its enthalpy of vaporization is 38.56 kJ/mol. The specific heats of solid and liquid ethanol are 0.97 J/g-K and 2.3 J/g-K, respectively. The average specific heat of gaseous ethanol is about 1.80 J/g-K. a. How much heat is required to convert 35.0 g of ethanol at 27 °C to the vapor phase at 120 °C? b. How much heat is required to convert the same amount of ethanol at –120 °C to the vapor phase at 120 °C?

Answers

Answer 1

Answer:

First question

       [tex]Q = 36826 \ J[/tex]

Second  question  

       [tex]Q = 52299.7 \ J[/tex]

Explanation:

From the question we are told that

     The melting point of Ethanol is  [tex]T_m = -114 ^oC[/tex]

      The boiling point of Ethanol is  [tex]T_b = 78^ oC[/tex]

       The enthalpy of fusion of Ethanol is [tex]F = 5.02 \ kJ / mol = 5.02 *10^{3}\ kJ / mol[/tex]

        The enthalpy of vaporization  of Ethanol is [tex]L = 38.56 \ kJ / mol = 38.56 *10^{3} \ J / mol[/tex]

         The specific heat of solid Ethanol is  [tex]c_e = 0.97 \ J/ g \cdot K[/tex]

          The specific heat of liquid  Ethanol is [tex]c_l = 2.3 \ J / g \cdot K[/tex]

           The mass of the Ethanol given is  [tex]m = 35.0 \ g[/tex]

Considering the first question

           The initial  temperature is [tex]T_i = 27^oC[/tex]

             The final  temperature is  [tex]T_f = 120^oC[/tex]

Generally the heat required too raise the Ethanol to its boiling point is mathematically represented as

       [tex]Q_1 = m * c_l * (T_b - T_i)[/tex]

=>      [tex]Q_1 = 35.0 * 2.3 * ( 78 - 27)[/tex]

=>      [tex]Q_1 =4106 \ J[/tex]

Genially the number of moles of Ethanol given is mathematically represented as

         [tex]n = \frac{m}{Z}[/tex]

Here Z  is the molar mass of Ethanol  with value  [tex]Z = 46 g/mol[/tex]

So

         [tex]n = \frac{35}{46 }[/tex]

=>      [tex]n = 0.7609 \ mol[/tex]

Generally the heat of vaporization of the Ethanol is mathematically represented as

         [tex]Q_2 = n * L[/tex]

=>        [tex]Q_2 =0.7809 * 38.56 * 10^{3}[/tex]

=>        [tex]Q_2 =29339 \ J[/tex]

Generally the heat required too raise the Ethanol from  its boiling point to  [tex]T_f[/tex]  is  mathematically represented as

       [tex]Q_3 = m * c_l * (T_f - T_b)[/tex]

=>     [tex]Q_3 = 35 * 2.3 * (120 - 78 )[/tex]

=>     [tex]Q_3 = 3381 \ J[/tex]

Generally the total heat required is  

     [tex]Q = Q_1 + Q_2 + Q_3[/tex]

=>   [tex]Q = 4106 + 29339 + 3381[/tex]

=>   [tex]Q = 36826 \ J[/tex]

Considering the second question

           The initial  temperature is [tex]T_i = -120^oC[/tex]

             The final  temperature is  [tex]T_f = 120^oC[/tex]

Generally the heat required too raise the Ethanol to its melting  point is mathematically represented as

       [tex]Q_1 = m * c_e * (T_m - T_i)[/tex]

=>      [tex]Q_1 = 35.0 * 0.97 * ( -114 - (- 120) )[/tex]

=>      [tex]Q_1 = 203.7 \ J[/tex]

Generally the heat of fusion  of the Ethanol is mathematically represented as

                 [tex]Q_2 = n * F[/tex]

=>        [tex]Q_2 =0.7809 * 5.02 *10^{3}[/tex]

=>        [tex]Q_2 =3920 \ J[/tex]

Generally the heat required too raise the Ethanol to its boiling point is mathematically represented as

       [tex]Q_3 = m * c_l * (T_b - T_m)[/tex]

=>      [tex]Q_3 = 35.0 * 2.3 * ( 78 - (- 114) )[/tex]

=>      [tex]Q_3 =15456 \ J[/tex]

Generally the heat of vaporization of the Ethanol is mathematically represented as

         [tex]Q_4 = n * L[/tex]

=>        [tex]Q_4 =0.7809 * 38.56 * 10^{3}[/tex]

=>        [tex]Q_4 =29339 \ J[/tex]

Generally the heat required too raise the Ethanol from  its boiling point to  [tex]T_f[/tex]  is  mathematically represented as

       [tex]Q_5 = m * c_l * (T_f - T_b)[/tex]

=>     [tex]Q_5 = 35 * 2.3 * (120 - 78 )[/tex]

=>     [tex]Q_5 = 3381 \ J[/tex]

Generally the total heat required is  

     [tex]Q = Q_1 + Q_2 + Q_3+Q_4 + Q_5[/tex]

=>   [tex]Q = 203.7 + 3920 + 15456 +29339+3381[/tex]

=>   [tex]Q = 52299.7 \ J[/tex]


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Answer:

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Answers

Answer:

1.957 × 10²⁴ molecules

Explanation:

The number of carbon dioxide molecules can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 3.25 × 6.02 × 10²³

We have the final answer as

1.957 × 10²⁴ molecules

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While imaging tests such as X-rays can show what the structures inside your body look like, a SPECT scan produces images that show how your organs work. For instance, a SPECT scan can show how blood flows to your heart or what areas of your brain are more active or less active.

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a compound

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Answers

Explanation:

I think its a solution just me tell me in comments if right

Answer:

A solution

Explanation:

Sugar is soluble in water and would dissolve into the water to form a solution.

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Answers

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Further explanation

In general, the gas equation can be written  

[tex]\large {\boxed {\bold {PV = nRT}}}[/tex]

where  

P = pressure, atm , N/m²

V = volume, liter  

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Answers

Answer:

No mass loss

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Answers

Answer:

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Explanation:

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Explanation:

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Answers

Answer:

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Unknown:

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Solution:

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Answer:

See explanation

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Answers

Answer:

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Answer:

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M-A=N

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M-A=N

Here is an example.

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35-17=18.

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Answers

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Group of answer choices

0.09g

630g

11.2

84g

Answers

Answer:

630gC₆H₁₂

Explanation:

How many grams are in 7.5 moles of C₆H₁₂?

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H₁₂:1.008×12=12.096

72.066+12.096=84.162

84.162g/mol C₆H₁₂

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B)
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C)
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D)
the conditions necessary for the reaction to take place

Answers

Answer:

C)  the relative number of moles taking part in the reaction

Explanation:

From a balanced chemical equation, it is always possible to determine the relative number of moles taking part in a chemical reaction.

The number of moles is the amount of the reacting specie that makes up a chemical reaction.

In balanced chemical equation, the number of moles of reactants and products must be the same. From this understanding, we can determine the amount of reactants and products needed for a chemical reaction to take place.

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Answer:

Here you go

Explanation:

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