Ethanol (C2H5OH) melts at –114 °C and boils at 78 °C. The enthalpy of fusion of ethanol is 5.02 kJ/mol, and its enthalpy of vaporization is 38.56 kJ/mol. The specific heats of solid and liquid ethanol are 0.97 J/g-K and 2.3 J/g-K, respectively. The average specific heat of gaseous ethanol is about 1.80 J/g-K. a. How much heat is required to convert 35.0 g of ethanol at 27 °C to the vapor phase at 120 °C? b. How much heat is required to convert the same amount of ethanol at –120 °C to the vapor phase at 120 °C?

Answers

Answer 1

Answer:

First question

       [tex]Q = 36826 \ J[/tex]

Second  question  

       [tex]Q = 52299.7 \ J[/tex]

Explanation:

From the question we are told that

     The melting point of Ethanol is  [tex]T_m = -114 ^oC[/tex]

      The boiling point of Ethanol is  [tex]T_b = 78^ oC[/tex]

       The enthalpy of fusion of Ethanol is [tex]F = 5.02 \ kJ / mol = 5.02 *10^{3}\ kJ / mol[/tex]

        The enthalpy of vaporization  of Ethanol is [tex]L = 38.56 \ kJ / mol = 38.56 *10^{3} \ J / mol[/tex]

         The specific heat of solid Ethanol is  [tex]c_e = 0.97 \ J/ g \cdot K[/tex]

          The specific heat of liquid  Ethanol is [tex]c_l = 2.3 \ J / g \cdot K[/tex]

           The mass of the Ethanol given is  [tex]m = 35.0 \ g[/tex]

Considering the first question

           The initial  temperature is [tex]T_i = 27^oC[/tex]

             The final  temperature is  [tex]T_f = 120^oC[/tex]

Generally the heat required too raise the Ethanol to its boiling point is mathematically represented as

       [tex]Q_1 = m * c_l * (T_b - T_i)[/tex]

=>      [tex]Q_1 = 35.0 * 2.3 * ( 78 - 27)[/tex]

=>      [tex]Q_1 =4106 \ J[/tex]

Genially the number of moles of Ethanol given is mathematically represented as

         [tex]n = \frac{m}{Z}[/tex]

Here Z  is the molar mass of Ethanol  with value  [tex]Z = 46 g/mol[/tex]

So

         [tex]n = \frac{35}{46 }[/tex]

=>      [tex]n = 0.7609 \ mol[/tex]

Generally the heat of vaporization of the Ethanol is mathematically represented as

         [tex]Q_2 = n * L[/tex]

=>        [tex]Q_2 =0.7809 * 38.56 * 10^{3}[/tex]

=>        [tex]Q_2 =29339 \ J[/tex]

Generally the heat required too raise the Ethanol from  its boiling point to  [tex]T_f[/tex]  is  mathematically represented as

       [tex]Q_3 = m * c_l * (T_f - T_b)[/tex]

=>     [tex]Q_3 = 35 * 2.3 * (120 - 78 )[/tex]

=>     [tex]Q_3 = 3381 \ J[/tex]

Generally the total heat required is  

     [tex]Q = Q_1 + Q_2 + Q_3[/tex]

=>   [tex]Q = 4106 + 29339 + 3381[/tex]

=>   [tex]Q = 36826 \ J[/tex]

Considering the second question

           The initial  temperature is [tex]T_i = -120^oC[/tex]

             The final  temperature is  [tex]T_f = 120^oC[/tex]

Generally the heat required too raise the Ethanol to its melting  point is mathematically represented as

       [tex]Q_1 = m * c_e * (T_m - T_i)[/tex]

=>      [tex]Q_1 = 35.0 * 0.97 * ( -114 - (- 120) )[/tex]

=>      [tex]Q_1 = 203.7 \ J[/tex]

Generally the heat of fusion  of the Ethanol is mathematically represented as

                 [tex]Q_2 = n * F[/tex]

=>        [tex]Q_2 =0.7809 * 5.02 *10^{3}[/tex]

=>        [tex]Q_2 =3920 \ J[/tex]

Generally the heat required too raise the Ethanol to its boiling point is mathematically represented as

       [tex]Q_3 = m * c_l * (T_b - T_m)[/tex]

=>      [tex]Q_3 = 35.0 * 2.3 * ( 78 - (- 114) )[/tex]

=>      [tex]Q_3 =15456 \ J[/tex]

Generally the heat of vaporization of the Ethanol is mathematically represented as

         [tex]Q_4 = n * L[/tex]

=>        [tex]Q_4 =0.7809 * 38.56 * 10^{3}[/tex]

=>        [tex]Q_4 =29339 \ J[/tex]

Generally the heat required too raise the Ethanol from  its boiling point to  [tex]T_f[/tex]  is  mathematically represented as

       [tex]Q_5 = m * c_l * (T_f - T_b)[/tex]

=>     [tex]Q_5 = 35 * 2.3 * (120 - 78 )[/tex]

=>     [tex]Q_5 = 3381 \ J[/tex]

Generally the total heat required is  

     [tex]Q = Q_1 + Q_2 + Q_3+Q_4 + Q_5[/tex]

=>   [tex]Q = 203.7 + 3920 + 15456 +29339+3381[/tex]

=>   [tex]Q = 52299.7 \ J[/tex]


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If you have 2.0 moles of sodium chloride (NaCl), what is its mass in grams?

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117g

Explanation:

Given parameters:

Number of moles = 2moles

Unknown:

Mass of NaCl  = ?

Solution:

To solve the problem, we need to use the expression below;

    Mass of NaCl  = number of moles x molar mass

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So;

Insert the parameters and solve;

     Mass of NaCl  = 2 x 58.5  = 117g

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Answer:

1.957 × 10²⁴ molecules

Explanation:

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Answers

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Further explanation

In general, the gas equation can be written  

[tex]\large {\boxed {\bold {PV = nRT}}}[/tex]

where  

P = pressure, atm , N/m²

V = volume, liter  

n = number of moles  

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T = temperature, Kelvin  

P = 760 mmHg=1 atm

T = 300 K

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Number of moles :

[tex]\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{1\times 0.3}{0.082\times 300}\\\\n=0.0122[/tex]

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Answer:

They show you  how to do it sweetie

Explanation:

123456789 Common math

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Answers

Answer:

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Answers

Answer:

No mass loss

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Answers

Answer:

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Explanation:

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Group of answer choices

0.09g

630g

11.2

84g

Answers

Answer:

630gC₆H₁₂

Explanation:

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Answers

Answer:

See explanation

Explanation:

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Explanation:

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Answers

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For the first set:

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Answers

Answer:

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Answer:

M-A=N

Explanation:

M-A=N

Here is an example.

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Answers

Answer:

The official measurement unit for energy is the Joule (J). Among the most common units measuring energy mention should be made of the kilowatt/hour (kWh), used especially for electric energy (in fact it is used to calculate electricity bills).

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Answers

Answer:

C)  the relative number of moles taking part in the reaction

Explanation:

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a2

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a3

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a4

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Answers

1. solute is the substance that is being dissolve,while solvent is dissolving medium

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Mass
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Answers

Answer:

I believe its A. Mass

Explanation:

An intensive property is a property of matter that depends only on the type of matter in a sample and not on the amount. For example, the electrical conductivity of a pure substance is a property that depends only on the type of substance. Silver, gold, and copper are excellent conductors of electricity, while glass and plastic are poor conductors.. Other intensive properties include color, temperature, density, and solubility.

Answer:

B. Magnetism

Explanation:

Hope this helps! :))
Sorry for late answer

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Answers

Answer:

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Answer:

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