Does the US use the metric system? Please Only Real Answers Like Yes Or No Or yes because...... no because...... Thank You

Answers

Answer 1

Answer:

No

Explanation: It is the only country that does not. Hope this helped :)


Related Questions

Does the atomic number of an atom change?

Answers

Answer:

An elements atomic number will never change, that is because the atomic number is its "identity."

A car drives 10km with a speed of 72 km/hr and then runs out of gas. Then you walk 2km for the next 30 min until you find a gas station. (A) What is the displacement of the total trip? (B) How long does the entire trip take? (C) What is the average velocity of the entire trip?

Answers

Answer:

A- 12 km

B- 42 minutes

C- 17.14 km per hour

Explanation:

A- The displacement of the total trip is 12 kilometers, which emerges by adding the 10 kilometers traveled by car to the 2 kilometers traveled on foot.

B- The trip, in total, took 42 minutes, which arises from adding the 30 minutes of the journey on foot, plus 12 minutes of travel by car at 72 km / h (72/60 x 10 = 12).

C- While 12 km were covered in 42 minutes, the average speed of the trip was 17.14 km / h. This arises from the following calculation:

42 = 12

60 = X

(60 x 12) / 42 = X

17.14 = X

The position of a particle is r⃗ (t)=(3.0t2iˆ+5.0jˆ−6.0tkˆ)m. (a) Determine its velocity and acceleration as functions of time. (b) What are its velocity and acceleration at time t = 0?

Answers

Explanation:

It is given that,

The position of a particle is given by :

[tex]r(t)=(3t^2i+5j-6tk)\ m[/tex]

(a) Velocity of a particle is given by :

[tex]v=\dfrac{dr(t)}{dt}[/tex]

Putting values,

[tex]v=\dfrac{d}{dt}(3t^2+5-6t)\\\\v=(6ti-6k)\ m/s[/tex]

The acceleration of the particle is given by :

[tex]a=\dfrac{dv}{dt}\\\\a=\dfrac{d}{dt}(6t-6)\\\\a=6i\ m/s^2[/tex]

(b) At t = 0,

Velocity, v = 6k m/s

Acceleration, a = 6i m/s²

A car moves from rest with an acceleration of 0.2ms
Find its velocity when it has moved a
distance of 50m
From the problem we notice that the question
does not involver. Therefore, the required equation
is)​

Answers

Explanation:

Given:

Δx = 50 m

v₀ = 0 m/s

a = 0.2 m/s²

Find: v

The problem does not involve time.  Therefore, the required equation is:

v² = v₀² + 2aΔx

Plug in values and solve:

v² = (0 m/s)² + 2 (0.2 m/s²) (50 m)

v = 4.47 m/s

The velocity of the car when it has moved a distance of 50 meters is approximately 4.47 m/s.

To find the velocity of the car when it has moved a distance of 50 meters, we can use the following equation of motion:

v² = u² + 2as

Where:

v = final velocity

u = initial velocity (which is 0 in this case as the car starts from rest)

a = acceleration

s = distance traveled

Plugging in the values into the equation:

v² = 0² + 2(0.2)(50)

v² = 0 + 20

v² = 20

Taking the square root of both sides:

v = √20

v = 4.47 m/s

Therefore, the velocity of the car when it has moved a distance of 50 meters is approximately 4.47 m/s.

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Question
In order for work to be done, what three things are necessary

Answers

Perseverance, good mind set, and work ethic
you will need work ethic, self control, and a good mindset

Which kinds of objects emit visible light in the electromagnetic spectrum? A. all objects B. radioactive objects C. relatively cold objects D. relatively hot objects

Answers

Answer:

c

Explanation:

Answer:

the answer is c i just did it

Explanation:

A person drops two objects from the same height. One object weighs 15 N.
and the other weighs 10 N. How does the mass of the objects relate to the
force of gravity on them?
A. The 10 N object has the same mass as the 15 N object.
B. The 15 N object has twice the mass of the 10 N object.
C. The 15 N object has more mass than the 10 N object.
D. The 10 N object has more mass than the 15 N object.

Answers

Answer:

C

Explanation:

The 15N object has more mass than the 10N object.

A 15 N object has more mass than the 10 N object due to their weight differences.

What is Weight?

Weight is defined as the force exerted by the earth on an object on the surface of earth. The direction of this force is directed towards the center of earth. Mathematically -

W = mg

Where -

m is the mass of body

g is the acceleration due to gravity

Weight can also be written as -

W = ρVg     [ρ is density and V is volume]

Given is a person who dropped two objects from the same height. One object weighs 15 N and the other weighs 10 N.

We can write -

Weight of Object 1 [W1] = 15 N

Weight of Object 2 [W2] = 10N

We know that -

W = m x g

We can write it as -

m = W/g

Therefore -

Mass of Object 1 [M1] = 15/9.8 = 1.53 Kg

Mass of Object 2 [M2] = 10/9.8 = 1.02 Kg

Clearly -

M1 > M2

So, the 15 N object has more mass than the 10 N object.

Therefore, a 15 N object has more mass than the 10 N object due to their weight differences.

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Suppose that a certain battery produces a voltage of 1.55V without a load connected (open circuit) and a current of 500mA when shorted. According to these specifications, if we were to model this as an ideal voltage source in series with a source resistance, what should the source voltage and internal resistance be? Justify your answer

Answers

Answer:

Explanation:

Let the internal resistance be r .

Since in open circuit the volt is 1.55 V , this will be the source voltage .

Source voltage = 1.55

If external resistance be R .

1.55 / (R + r ) = .500

R + r = 3.1 ohm

So sum of internal resistance and external resistance will be 3.1 ohm.

When students were surveyed about the kind of thinking they considered to be most important in their academic studies, the majority chose?

Answers

Answer:Critical Thinking

Explanation:

7.2 in college success text back

The mere exposure effect is

Answers

DescriptionThe mere-exposure effect is a psychological phenomenon by which people tend to develop a preference for things merely because they are familiar with them.

11. एक समान चुम्बकीय क्षेत्र में लम्बवत प्रवेश करने वाले किसी आवेशित कण द्वारा प्राप्त वृत्तीय पथ की
7 त्रिज्या का सूत्र ज्ञात कीजिए।
2
Find the formula of radius obtained by a charged particle entering perpendicularly
in a uniform magnetic field.​

Answers

Answer:

r=mv/Be

Explanation:

If a positive charge enters a magnetic field at 90 degrees the charge is deflected in a circular path by a force that acts perpendicular to it in line with Flemings right-hand rule

to derive the radius of the path of the charge we apply

F= mv^2/r=Bev

where

m= mass of the electronic charge

e=charge

B=magnetic field

v=average speed

r=radius

 

rearranging we have

r=mv^2/Bev

r=mv/Be

What exerts the thrust force acting on the cart?

Answers

Answer:

This question appears incomplete

Explanation:

The question appears incomplete. However, a thrust can be described as a force or a push. A cart can be described as a vehicle (usually with two wheels) that is used to transport load from one point/place to another.

Newton first law of motion (law of inertia) states that a body will continue to be in a state of rest or if in motion, remains in motion (at constant velocity) unless acted upon by an external force. Hence, a cart will continue to be in a state of rest unless acted on by an external force which can be exerted by animals or humans (depending on the type of cart).

Compare the de Broglie wavelength of a golf ball moving at 70.0 miles per hour (31.3 m/s) to that of an alpha particle moving at 3.40E+7 miles per hour (1.52E+7 m/s) and a bullet with a speed of 700 miles per hour (313 m/s). Which region of the electromagnetic spectrum are each of these wavelengths near

Answers

Answer:

1. Golf ball is in the range of only particulate detectable range

2, alpha partcle is in ultraviolet range of wavelength

3.bullet is in xray range of wavelength

All in the EMW spectrum

27.
In a graph showing how temperature of a material changes over time, temperature
change is the:
A. dependent variable
C. variable with the smallest range
B. independent variable
D. variable with the largest range

Answers

Answer:

A. Dependent variable

Explanation:

In a graph showing how temperature of a material changes over time, temperature is taken on y-axis and time is taken on x-axis. It shows how temerature altered as the time changes.

In temperature-time graph, temperature is directly dependent on time. With the increase in time, temperature rises, falls or remains constant. It implies that temperature is dependent variable that depend on time.

Hence, the correct option is (A).

In which direction does centripetal force act on an object? in the opposite direction of the tangential speed of the object in the same direction of the tangential speed of the object toward the outside of the circle in which the object is moving toward the center of the circle in which the object is moving

Answers

Answer:

towards the center of the circle

(which appears to be the last option in your list of possible answers)

Explanation:

The centripetal force points always towards the center of the circle described by the object moving.

The direction of centripetal force acting on an object is always towards the center of the circle in which the object is moving.

The given problem is based on the concept and fundamentals of centripetal force. When an object is known to move around a circular path, then there is a force comes to play acting towards the centre of circular path, known as centripetal force.

In other words, the centripetal force is also known termed as the force that tends to act on a body moving in a circular path and is directed towards the centre around which the body is moving.For example - Motion of merry go round and the motion of roller skates on the rink floor are the examples of centripetal force, where the force always acts in the direction, center of the circular track.

Thus, we can conclude that the direction of centripetal force acting on an object is always toward the center of the circle in which the object is moving.

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Help please Subject (general psychology)

Answers

Answer:

plz give the question... floor the proper answer

Explanation:

plz mark me add the brainliest

thank

me and follow ma

it is required that an object weighing 8N be moved up ward at an acceleration of 2m/s what is the upward force needed ​

Answers

Answer:

F = 1.6 N

Explanation:

Newton's Second Law of Motion states that whenever an unbalanced force is applied on a body. It produces an acceleration in the body, in its own direction. The magnitude of the force is given by the following formula:

F = ma

where,

F = Force Required to Move the Object Upward = ?

m = mass of object

a = upward acceleration = 2 m/s²

but, we know that weight of object is given as:

Weight = mg

8 N = m(9.8 m/s²)

m = 0.8 kg

using values in the equation:

F = (0.8 kg)(2 m/s²)

F = 1.6 N

Determine the distance S to which the 90kg painter can climb without causing the 4m ladder to slip at it's lower end A. The top of the 15kg ladder has a small roller, and at the ground the coefficient of static friction is 0.25. The mass center of the painter is directly above her feet.​

Answers

Explanation:

...................,..........

Newton's first law states that at rest the sum of the forces acting on a body is zero

The distance S to which the painter can climb is approximately 2.55 meters

The reason the above value for the distance is correct is as follows:

The given parameter are;

The mass of the painter, m₁ = 90 kg

Length of the ladder, l = 4 m

The mass of the ladder, m₂ = 15 kg

The coefficient pf static friction, μ = 0.25

Friction force, [tex]\mathbf{F_f}[/tex] = Normal reaction, N × μ

Normal reaction (flat surface), N = Weight of painter + Weight of ladder

N = m₁·g + m₂·g

Where;

g = The acceleration due to gravity, g = 9.81 m/s²

N = 90 kg × 9.81 m/s² + 15 kg × 9.81 m/s² = 1,030.05 N

∴ [tex]\mathbf{F_f}[/tex] = 1,030.05 N × 0.25 = 257.5125 N

Friction force, [tex]\mathbf{F_f}[/tex] = 257.5125 N (Horizontal force)

At equilibrium, the sum of the  horizontal forces = 0

Fₓ + [tex]\mathbf{F_f}[/tex] = 0

Fₓ = [tex]-F_f[/tex] = -257.5125 N (Acting opposite to the direction of the friction force)

The height of the top of the ladder from the ground, h = √(4²-1.5²) = √(13.75)

Taking moment about point A gives;

Clockwise moment = Anticlockwise moment

Fₓ × h = m₁·g·s·cos(θ) + m₂·g·(l/2)·cos(θ)

Therefore;

Fₓ × √(13.75) m = 90 kg × 9.81 m/s² × s × (1.5/4) + 15 kg × 9.81 m  × 2 m × (1.5/4)

Fₓ × √(13.75) m = 331.0875 N × s + 110.3625 J

257.5125 N × √(13.75) m = 331.0875 N × s + 110.3625 J

s = (257.5125 N × √(13.75) m - 110.3625 J)/(331.0875 N) ≈ 2.55 m

The distance to which the 90 kg painter can climb without causing the 4 m ladder to slip at its lower end, A, distance S2.55 meters

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An object is released from rest from a top of a building 90 meters high. Neglect air friction.
What is the volume of its acceleration?
Calculate the time it takes to reach the floor?
With what velocity does it reach the floor?
How fast is it moving when it is 50 meter above the floor?

Answers

Answer:

1. a = 9.8 m/s²

2. t = 4.28 s

3. Vf = 42 m/s

4. Vf = 28 m/s  

Explanation:

1.

Since, the body is under free fall motion. Therefore, the value of its acceleration shall be equal to the acceleration due to gravity.

a = 9.8 m/s²

2.

The time taken by the ball to reach the ground can be calculated by using second equation of motion:

h = Vi t + (1/2)gt²

where,

h = height = 90 m

Vi = initial velocity = 0 m/s

t = time taken = ?

Therefore,

90 m = (0 m/s)t + (1/2)(9.8 m/s²)t²

t = √(18.36 s²)

t = 4.28 s

3.

In order to find final velocity we use first equation of motion:

Vf = Vi + gt

Vf = 0 m/s + (9.8 m/s²)(4.28 s)

Vf = 42 m/s

4.

when the ball is at height of 50 m, it means it has covered:

h = 90 m - 50 m = 40 m

we use third equation of motion at this point:

2gh = Vf² - Vi²

(2)(9.8 m/s²)(40 m) = Vf² - (0 m/s)²

Vf = √(784 m²/s²)

Vf = 28 m/s

Suppose a radio signal (light) travels from Earth and through space at a speed of 3 × 108/ (this is the speed of light in vacuum). How far (in meters) into space did the signal travel during the first 10 minutes?

Answers

Answer:

18*10^10 meters

Explanation:

V= d/t         10 mins = 600 seconds

3*10^8 = d/600s

(3*10^8)*(6*10^2) = d

d = 18*10^10 m

Suppose a fast-pitch softball player does a windmill pitch, moving her hand through a circular arc with her arm straight. She releases the ball at a speed of 21.3 m/s21.3 m/s (about 47.6 mph47.6 mph ). Just before the ball leaves her hand, the ball's radial acceleration is 871 m/s2871 m/s2 . What is the length of her arm from the pivot point at her shoulder?

Answers

Answer:

R = 52.08 cm

Explanation:

given data

tangential velocity v = 21.3 m/s

radial acceleration aR = 871 m/s²

solution

we will get here length of her arm from the pivot point at her shoulder so

here we know aR = [tex]\frac{v^2}{R}[/tex]     ........................1      

so put here value and we get

871 = [tex]\frac{21.3^2}{R}[/tex]  

R = 0.5208840 m

R = 52.08 cm

Answer:

Explanation:

linear speed of ball v = 21.3 m /s

radial acceleration = 871 m /s²

radial acceleration = v² / R

where R is length of arm which acts as radius of circular path of the ball .

Putting the values

21.3² / R = 871

R = .52 m.

4. What is the momentum of a 78.0 N bowling ball with a velocity of 8.00 m/s?

Answers

Momentum = (mass) x (speed)

We don't know the mass of the bowling ball, but we know how much it weighs.  So if we knew the acceleration of gravity in the place where the ball is, we could calculate its mass.  The question doesn't tell us what planet the bowling ball is on.  So if we only use the information given in the question, there's no way to find the answer, and we're stuck here.

But I urgently need the points, so I'm going to go out on a limb here and make a big assumption:  I'll assume that the alley where this ball is rolling and bowling is located on planet Earth, where the acceleration  of gravity is around  9.8 m/s²  everywhere on the planet's surface.  NOW I can go ahead and answer the question that I just invented.

weight = m  g

Mass = (weight) / (g)

Mass = (78.0 N) / (9.8 m/s²)

Mass = 7.96 kilograms

Momentum = (mass) x (speed)

Momentum = (7.96 kg) x (8.00 m/s)

Momentum = 63.7 kg-m/s

3. A block of mass m is suspended by strings as shown in the figure. The tension in the horizontal string
is 36 N. The angle 0 is 60°. Find the mass of the block and the tension forces in string A and string
B

I am having trouble trying to answer this problem. Any help?

Answers

Answer:

mass of the block is 7.2Kg

Tension on string A = 72N

Tension on the string with an angle is =  108N

Explanation:

The Horizontal string will have the cos component of the force...

Hence, mg cos60 = 36

by keeping acceleration due to gravity = 10 m/s^2, we get,

m = 7.2Kg

The tension in String A = mg = 7.2*10 = 72N

since the whole string holding the block is pulled by another string with 36 N

the resultant force will be the tension of the string with an angle.

Hence, 72 +36 = 108 N

Please let me know whether I got this right or not...

Calculate the length of segment RS with midpoint, M , if RM = 5x and MS = x + 12.

A. 3

B. 25

C. 30

D. 36

E. 15

Answers

Answer:

the full segment is:  30 units long

which coincides with answer C in your list

Explanation:

If M is the midpoint, then it divides the segment in two equal parts. Then, we can say that:

RM = MS (equality among the two parts of the divided segment)

replacing RM with "5 x" and MS with "x + 12", we get:

5 x = x + 12

solving for x:

5 x - x = 12

4 x = 12

then x = 3

With this info, we can calculate the length of each half of the segment and consequently its full length:

RM = 5 x = 5 (3) = 15

then the full segment is:  30 units long


Elmer Fudd is walking at 2.0 m/s. If he walks for 2.0 minutes, how far does he walk?
(Can someone help with the answer due in 5min)

Answers

Answer:

240 meters

Explanation:

He is walking 2 meters per second, and there are 60 seconds per minute. There are 120 seconds in two minutes. So, 120 x 2 = 240. That's your answer!

c) A sample of substance of volume 10 cm3 was brought back to Earth from the Moon.
The weight of the sample on the Moon was 0.13 N. The gravitational field strength
on the Moon is 1.6 N kg-1.
(1)
Calculate the density of the sample.

Answers

Answer:

8125

Explanation:

[tex]P=0,13 N\\a=1,6 N/kg\\m=P/a=0,13/1,6=0,08125\\V=10(cm)^{3} =10^{-5} meters^{3} \\p=m/V=0,08125/10^{-5} =0,08125*100000=8125kg/meters^{3}[/tex]

Which law applies to the picture?
Newtons 1st Law of Motion
Newtons 2nd Law of Motion
Newtons 3rd Law of Motion​

Answers

Answer:

Newton's first law

Explanation:

Newton's first law of motion says, that an object will stay in its current motion, unless if a force acts upon it.

So an object already at rest, will stay at rest. And the ball rolling will keep rolling, if no other force such as friction slows it down.

A girl delivering newspapers covers her route by traveling 6.00 blocks west, 3.00 blocks north, and then 7.00 blocks east. HINT (a) What is her final position relative to her starting location? (Enter the magnitude in blocks and the direction in degrees north of east.) magnitude blocks direction ° north of east (b) What is the length (in blocks) of the path she walked?

Answers

Answer:

a) we can form a triangle in order to use the Pythagorean theorem = 3² + 1² = h²

h² = 9 + 1 = 10

h = √10

h = 3.1623 blocks

we must also find the angle at the initial point of the triangle (A):

tan⁻¹ (1/3) = 18.43°    

the position relative to her starting position is 90° - 18.43° = 71.57° north of east

b) total distance traveled = 6 + 3 + 7 = 16 blocks

If you walk 5 km north and then 12 km east. Your resultant displacement is____.a. magnitude: 1.1km; direction: 53.1 degrees east of north.b. magnitude: 2.00; direction: 53.1 degrees east of north.c. magnitude: 2.00; direction: 36.9 degrees east of north.d. magnitude: 1.1km; direction: 36.9 degrees east of north.

Answers

Answer:

Resultant = 13km

Direction = 67.38° East of North

Explanation:

Given the following :

5km North ; 12km East

Resultant Displacement (r) :

r² = 5² + 12²

r² = 25 + 144

r² = 169

r = √169

r = 13

Direction:

Tangent = opposite / Adjacent

Tanθ = opposite / Adjacent

Opposite = 12 ; adjacent = 5

Tanθ = (12/5)

Tanθ = 2.4

θ = tan^-1(2.4)

θ = 67.38° east of north

Question: A) A car is driving too fast on a flat non-banked curve. The car cannot stay on the road. What path will the car take as it leaves the road? See Image. (a) (b) B) The driver wants to go faster around the same curve mentioned above and not run off the road. He adds sandbags to his car to make it weigh more so that the friction force between the tires and the road will be increased. Will this work? Explain your answer.​

Answers

Explanation:

(a) The car will leave tangentially to the road, so it will take path d.

(b) Sum of forces on the car in the vertical direction:

∑F = ma

N − mg = 0

N = mg

Sum of forces on the car in the centripetal direction:

∑F = ma

Nμ = m v²/r

mgμ = m v²/r

gμ = v²/r

v = √(grμ)

The maximum velocity is independent of mass, so adding sandbags will not work.

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