-%deviation from expected value (show calculations) in relation between frequency and radius.

The magnitude of the force F exerted by the leg on the small pulley is, F = 38.53 N

We can calvulate the magnitude of the force by a mathematical calculation, which is as follows. As the small pulley and mass are not moving, they are stationary.

t2=t1 = mg = (2.27)(9.8)

= 22.246 N

Now resolve the force in the opposite direction.

F = 2Tcos30°

F = (2)(22.246)(cos30°)

F = 38.53 N

Therefore, the magnitude of the force is 38.53 N.

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When exercising in the heat, you should wear tight - fitting clothes to absorb your sweat, therefore the correct answer is option A.

Exercise is a physical activity that involves bodily movement that improves a person's health, fitness, and well-being while lowering their chance of contracting illnesses.

Dressing in layers is useful in extreme cold conditions and extremely cold weather.

Dark-colored clothing absorbs more heat as compared to light - colored clothing.

When exercising in the heat, you should wear tight-fitting clothes to absorb your sweat, therefore the correct answer is option A.

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ANSWER:

STEP-BY-STEP EXPLANATION:

We have the following:

Given

Three electrically charged spheres A,B and C. Sphere A is brought near Sphere B and both are attracted to each other electrically. Sphere B is brought near Sphere C and both repel each other electrically.

To find

What happens when Sphere A is brought near Sphere C?

Explanation

Sphere A and sphere B are attracted to each other.

Thus, both A and B are of opposite charge.

Let A be a positive charge and B be a negative charge.

When sphere B is brought near sphere C both repel.

Thus, sphere C is also of negative charge.

So A and C are then of opposite charges and would both attract each other.

Conclusion

When sphere A is brought near sphere then C)electrical attraction occurs.

The resultant of the two given vectors with magnitudes 16.3 m and 7.7 m at an angle of 137.8 degree is equal to 23.87 meters.

What is the parallelograms law of vector addition?

If two vectors are acting simultaneously at a point, then it can be represented both in magnitude and direction by the adjacent sides drawn from a point.

What is the trigonometric ratio?

Trigonometric Ratios are defined as the values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle. The ratios of sides of a right-angled triangle with respect to any of its acute angles are known as the trigonometric ratios of that particular angle.

Given:

Vector 1 of magnitude 7.7 m at an angle of 27.8 degree to x-axis.

vector 2 of magnitude 16.3 m at an angle of 20 degree to minus y axis.

Using the law of parallelogram vector addition

i.e.

resultant vector = √((v₁) ² + (v₂) ² + 2 × v₁ × v₂ × cos (angle between two vectors))

substituting given value in parallelogram vector addition we get,

resultant vector = √ (570)

resultant vector = 23.87 meters

therefore, the resultant of the two given vectors with magnitudes 16.3 m and 7.7 m at an angle of 137.8 degree is equal to 23.87 meters.

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Answer:

11.79

Explanation:

Answer: 85.4 km/h

Explanation:

We would apply the law of conservation of kinetic energy. The formula is expressed as

KE1 + PE1 = KE2 + PE2

where

KE1 and KE2 are the initial and final kinetic energies

PE1 and PE2 are the initial and final potential energies

The formula for calculating kinetic energy is

KE = 1/2mv^2

where

m is the mass of the object

v is the velocity

The formula for calculating potential energy is

PE = mgh

where

g is the acceleration due to gravity = 9.8m/s^2

h is the height of the object

From the information given,

m = 55

h = 8.3

Potential energy at the top = 55 x 9.8 x 8.3 = 4473.7

At the top, v = 72km/h

Recall, 1 km = 1000m

1 hour = 3600s

72km/h = 72 x 1000/3600 = 20m/s

kinetic energy at the top = 1/2 x 55 x 20^2 = 11000

KE1 + PE1 = 4473.7 + 11000 = 15473.7

At the point of landing,

PE2 =0

KE = 1/2 x 55 x v^2 = 27.5v^2

Thus,

27.5v^2 = 15473.7

v^2 = 15473.7/27.5

v = √(15473.7/27.5)

v = 23.72 m/s

his landing speed is 23.72 m/s

Converting to km/h, we would multiply 23.72 by 18/5

Landing speed = 85.4 km/h

The amount of energy stored in the spring, given it has a spring constant of 80 N/m is 1.6 Joules

First, we shall list out the given parameters from the question. This is shown below:

The energy stored in the spring, given the above data can be obtained as follow:

E = ½Ke²

E = ½ × 80 × 0.2²

E = 40 × 0.04

E = 1.6 Joules

Thus, from the above calculation, we can conclude that the energy stored is 1.6 Joules

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The unknown mass of water is 545.21

What is mass?

mass is a quantitative measure of inertia , a fundamental property of all matter .

mass depends on the number and kind of atoms.

It is a dimensionaless quantity.

Sol-

As per the given question

220 g of water added to 90°c

Mass of water=10°C

Tempreture of the mixture =33°C

Unknown mass

m1 (n-t)= m2(t-b)

220(90-33)=m2(33-10)

:- (we can also do multiple of cp but as both side of the cp fluid unit  are same so it's not needed)

220×57=m2 (23)

m2= 220×57/23

m2 =545.21

Thus the unknown mass of water is 545.21 .

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Given:

The charge on the capacitor is Q = 0.617 nC

The distance between plates is d =1.784 mm

The area is

To find the electric field strength.

Explanation:

The electric field strength can be calculated by the formula

The constant is

On substituting the values, the electric field strength will be

To determine if a frame is an inertial frame we just need to remember that they can only be at rest or moving with constant speed. Therefore, the inertial frames in this case are:

A train traveling with a constant velocity of 54 m/s

A train at rest

Given

The half life is T=5715 years

The initial amount is N=50 g

To find

1) How much of it remains after 1600 years?

(2) How much of it remains after 16000 years?

Explanation

The amount of carbon remains after t yaers is

1. Thus putting t=1600 years

2.Putting t=16000

Conclusion

1.Amount remains after 1600 year is 41.208 g

2.Amount remains after 16000 year is 7.184 g

The magnitude of your horizontal acceleration as you begin to slow is 7.35m/s².

Applying work-energy theorem,

Total work done on the body by all the forces = change in kinetic energy.

So, here,

Work done by friction = ∆KE

-uMgd = 1/2M(v²-u²)

u is the coefficient of friction,

M is the mass of the car,

g is the acceleration due to gravity,

v is the final velocity of car,

u is the final velocity of car,

d is the horizontal distance moved by car.

(-0.75)(1800)(9.8)d = -1/2(1800)(21)²

d= 30 meters.

Applying Equation of motion,

V²-U²=2ad

Where a is the horizontal acceleration,

-(21×21) = 2(30)a

a = 7.35m/s².

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Given:

Velocity = 40 m/s

Angle = 37°

Let's find the distance from the cnnon where you should place a matress to catch the human if the muzzle is 0.75 meters from the ground.

Let's first draw the projectile motion diagram:

To find the distance, first apply the formula to solve for the time taken for the human to reach the matress.

Where:

Height from the ground to the muzzle = yo = 0.75

y = 0

Velocity = vo = 40 m/s

initial vertical velocity = voy = vo sinθ = 40 sin37

We have:

g is the acceleration due to gravity = 9.8 m/s²

Now, let's solve for the time t:

To sove for the horizontal distance, x, apply the formula:

Hence, we have:

Therefore, the matress should be placed at 157.8 meters from the cannon in order to catch the human.

ANSWER:

157.8 meters

If the earth has a radius R of about  6.37 × 10⁶ m, then the power received by the earth would be 2.722 × 10¹⁰ watts.

The rate of doing work is known as power. The Si unit of power is the watt.

Power =work/time

As given in the problem Earth has a radius R of about 6.37 × 10⁶ m.

Area of the earth assuming it is a circle = 3.14 × 6.37 × 10⁶

                                                                 = 2 × 10⁷ meter²

The power received by the earth = 2 × 10⁷ × 1361

                                                       = 2.722 × 10¹⁰ watts

Thus, the power received by the earth would be 2.722 × 10¹⁰ watts.

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The exact point of an object measured from all its edge center of mas.

What is center of mass?

the center of mass of a distribute of mass in space is the unique point where the weighted relatively position of the devided mass sums to 0. This is a point to which a force of  may be applied to cause of a  linear acceleration it without an angular acceleration.

Most of the time (not everytime)the centre of mass of an object lies within the object itself.

Eg-the center of mass of a ball in middle of a ball and the centre of mass of a copy is middle of a copy.

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Answer:

a) She get detention for being late again

Explanation:

First, we need to identify how much time does she take on each hallway.

With the distance and the speed, we can calculate the time as:

t = distance/speed

So, for each hallway, we get:

First hallway:

distance = 35 m

speed = 3.5 m/s

time = 35/3.5 = 10s

Second Hallway

distance = 48 m

speed = 1.2 m/s

time = 40s

Third Hallway

distance = 60 m

speed = 5 m/s

time = 60/5 = 12 s

Therefore, the total time that she takes was

10s + 40s + 12s = 62s

Since she takes more than 60 seconds, she will be late again.

Finally, we know that she takes 10s to run a distance of 35m, then another 40s to run a distance of 48 m, and another 12s to run a distance of 60 m. Therefore, the distance vs. time graph for this situation is

D. increased speed; acceleration is the correct description of that graph.

Shown far an item has come in a certain amount of time is displayed on a distance-time graph. The graph that shows the results of the distance vs time analysis is a straightforward line graph. The Y-axis represents the distance.

A sloping line on a distance-time graph shows that an item is moving. In a distance-time graph, the object's speed is equal to the slope or gradient of the line. The line becomes steeper as the thing goes more quickly (and the greater the gradient).

The horizontal line on a graph of a distance vs time indicates that the item is at rest because the distance does not change over time.

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The correct answer to the statement " Do two bodies have to be in physical contact to exert a force upon one another " is:

No, the gravitational force is a field force and does not require physical contact to exert

a force.

The correct option is a.

It has been practically proven that two bodies can exert a force upon each other even if there is no physical contact between them. This can as a result of gravity.

That being said, a magnetic attraction can also exert a force between two different bodies upon one another.

So therefore, it can be deduced from above that two different bodies do not have to be in physical contact before they exert a force upon one another.

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Answer:F - mB g

Explanation: If two objects are connected by a rope, the tension is the same at both ends. Thus, the same magnitude T2 pulls both the block and the weight.

According to the zeroth law of thermodynamics, no heat is transferred between the two objects if both the objects are at the same temperature.

Thus, no heat transfer between the water, pot, and air occurs according to the zeroth law of thermodynamics.

Hence, the zeroth law of thermodynamics is the correct answer.

The impulse is mathematically given as

v_f=3.61m/s

This is further explained below.

Generally, In classical mechanics, the integral of a force F over the time period t during which it operates is referred to as the impulse of the system.

It should come as no surprise that impulse is likewise a vector quantity given that force is one.

When an impulse is applied to an item, a corresponding vector change in the object's linear momentum occurs, also in the direction that the impulse causes.

In conclusion, Impulse = Area Under Curve

             =2*4+1*4

  [tex]m\left(v_f-v_i\right)=12 \\\\v_f=\frac{12}{2.35}=5.11 \mathrm{~m} / \mathrm{s}\\\\m\left(v_f-(-1.5)\right)=12 \\v_f=5.11-1.5 \\\\ =3.61 \mathrm{~m} / \mathrm{s} \\v_f=3.61 \mathrm{~m} / \mathrm{s}\end{gathered}$$[/tex]

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CQ

A force of magnitude Fx acting in the x-direction on a 2.35-kg particle varies in time as shown in the figure below.

(a) Find the impulse of the force.

____________kg

ANSWER

EXPLANATION

First, let us make a sketch of the problem:

where r = angle of refraction

d = depth of the pool

First, we have to find the angle of refraction, r, by applying Snell's law:

where n1 = incident refractive index = 1

n2 = refracted index = 1.33

i = angle of incidence = 70°

Therefore, solving for r, we have that:

Now, we can solve for the depth of the pool by applying trigonometric ratios for right triangles for tangent:

That is the depth of the pool.

If the angular velocity id doubled, then the linear speed of the boy will be doubled.

As we know,

If a body is rotating in a circular path, it will have an angular as well as linear velocity.

The angular velocity is responsible for rotation and the linear velocity is responsible for changing the direction in a circular manner.

The angular velocity W is related to the linear velocity V as,

W = V/R

Let us say this is equation 1,

Where R is the radius of the merry go round,

Now if the angular velocity is doubled,

W' = V'/R

Let us say this is equation 2.

On dividing equation 1 and 2,

W/W' = V/V'

As we know, W' = 2W.

1/2 = V/V'

V' = 2V.

The linear velocity will increase by a factor of 2.

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22920 years old is an artifact if four half-lives have occurred and the half-live of carbon-14 is 5730 years.

Due to radioactive decay to nitrogen-14, carbon-14 has a very short half-life of 5,730 years, which means that over this time, the proportion of carbon-14 in a sample will have decreased by 50%.

A half-life is the amount of time it takes for something to go from 100% to 50%. The phrase is most frequently used in reference to radioactive decay, which happens when energetic atomic particles that are unstable lose momentum.

The half-life of carbon-14 is 5730 years. Accordingly, a sample of 100 carbon-14 atoms has a half-life of 5730 years, or 50 carbon-14 and 50 carbon-12 (i.e., 100 carbon-14, one half-life = 50 carbon-14, 50 carbon-12).

4 half lives

=5730×4

=22,920 years old.

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The magnitude of the force is found to be 140N.

Force (F1)acting on θ1(90°) is 100N

Force (F2)acting on θ2(150°) is 60N

Therefore the angle between F1 and F2 is

θ2-θ1 = 150°-90° =60°

Now we calculate magnitude of force ,

Magnitude of force ,F= F1+F2

F. F = [tex]\sqrt{ ( F1+F2). (F1+F2) }[/tex]

|F|² = [tex]\sqrt{F1 ²+F2 ²+F1 F2 COS θ}[/tex]

F= [tex]\sqrt{ 100²+60²+2×100×60× cos60°}[/tex]

F= [tex]\sqrt{10000+3600+6000}[/tex]

F= [tex]\sqrt{19600}[/tex]

F= 140N.

Thus, the magnitude of force is found to be 140N.

The total amount of forces exerted on an object is referred to as the magnitude of the force. The strength of the force increases when all the forces are pulling in the same direction. When forces are exerted on an item from different angles, the force’s strength reduces.

There is magnitude and direction to force. When two forces of equal size are working in opposite directions one in the east and the other in the west the results of the two forces are not the same.

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ANSWER:

-3.73 m/s^2

STEP-BY-STEP EXPLANATION:

Acceleration is the rate of change of velocity and we can calculate it as follows:

Replacing:

The baseball's player's deceleration is 3.73 m/s^2

To send information through verbal speech, transmitter cords send information encoded in radio waves through the air.

The basic principle is simple. At one end a transmitter encodes or modulates the message by varying the amplitude or frequency of the waves. This is a bit like Morse code. Meanwhile, a receiver tuned to the same wavelength receives the signal and decodes it into the desired format sound image data, etc.

Communications and satellite transmissions. Radio waves travel easily through the air. Radio waves are used for the wireless transmission of sound messages and information for communications, and for maritime and air navigation. Information is applied to an electromagnetic carrier wave as amplitude modulation AM frequency modulation FM or digital form pulse modulation.

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Answer:

the analysis from are there 331