If 2 balls of the same size and different masses roll down a ramp, which ball would be faster; the bigger mass or the smaller mass

Answers

Answer 1

Answer:

The bigger mass

Explanation:

This can be explained using F=ma

Let's say the acceleration is same on both balls 10m/s2 however we have different masses.

Pretend small mass ball is 0.5 kg and big mass is 1kg.

10 x 0.5 =5

10 X 1 =10

10 is bigger than 5


Related Questions

Hydrochloric acid and sodium hydroxide can be combined to form sodium chloride and water. Which best explains the reaction?

The mass of sodium hydroxide will result in the same mass of sodium chloride.
The total mass of hydrochloric acid and sodium hydroxide will result in a lower total mass of sodium chloride and water.
The mass of hydrochloric acid will result in the same mass of sodium chloride.
The total mass of hydrochloric acid and sodium hydroxide will result in the same total mass of sodium chloride and water.



THE ANSWER IS D

Answers

The statement that best describes the reaction is as follows: The total mass of hydrochloric acid and sodium hydroxide will result in the same total mass of sodium chloride and water (option D).

What is the law of conservation of matter?

The law of conservation of matter states that matter can neither be created nor destroyed. This law means that the mass that enters and leave a system is accounted for.

The law of conservation of mass explains the input and output of mass in a chemical reaction such that the mass of the reactants must be equal to the mass of the products.

According to this question, hydrochloric acid (HCl) and sodium hydroxide (NaOH) can be combined to form sodium chloride and water.

This means that the total amount of matter of the reactants (hydrochloric acid and sodium hydroxide) must equate the total amount of matter of the products (sodium chloride and water).

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X 24. A man drives a car and records the distance he travels on a distance- *0/2
time graph. At one point he gets stuck in traffic and does not move for
one hour. This point on the graph the slope will be horizontal. Why is this correct?

Answers

The distance-time graph will show the slope as horizontal for the time in which the man don't move.

How to find slope of a graph?

The slope formula rise/run is used to get the slope from a graph. The first thing we must do when given a line's graph and asked to determine its equation is to determine its slope. In order to determine the slope from a graph, we can take any two points on the line (x1, y1) and (x2, y2) and use the formula (y2 - y1) / (x2 - x1).

In the distance-time graph the distance is represented at y-axis and the time is represented at x-axis. So, In the time in which the man stops moving (stuck in the traffic) there is no change in distance but the times keeps changing or increasing that's why at the point he gets stuck in traffic and does not move for one hour. This point on the graph the slope will be horizontal.

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On the kickoff, the football was in the air for 4 seconds before hitting the ground 52 meters away. How fast did the ball leave the foot of the kicker?

Answers

The initial speed that the ball left the foot of the kicker if it was in the air for 4 seconds before hitting the ground 52 meters away is 23.64 m / s

T = 2 u sin θ / g

R = u cos θ * T

T = Total time of flight

u = Initial velocity

g = Acceleration due to gravity

R = Horizontal range

T = 4 s

R = 52 m

4 = 2 u sin θ / 9.8

u = 39.2 / 2 sin θ

u = 19.6 / sin θ → ( 1 )

52 = u cos θ * 4

u = 13 / cos θ → ( 2 )

Equating ( 1 ) and  ( 2 ),

19.6 / sin θ = 13 / cos θ

sin θ / cos θ = 19.6 / 13

tan θ = 1.5

θ = 56.3°

From ( 2 )

u = 13 / cos 56.3°

u = 13 / 0.55

u = 23.64 m / s

Therefore, the initial speed that the ball is 23.64 m / s

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Recognise cause and effect. Acceleration can occur when a car is moving at a constant speed what must cause this accelaration. please answer in full sentences​

Answers

Answer:

The car must be moving at a changing velocity but at a constant speed. This is caused when an object is changing direction but not its speed.

Explanation:

Since velocity is a vector, it is measured with both magnitude (the numerical value) and direction. Acceleration is the change in velocity over a time period, which makes acceleration also a vector.

Speed is a scalar, so it is only measured by its magnitude (the numerical value). Speed only changes if you:

1. slow down
2. speed up


There are 3 ways an object can accelerate:
1. by slowing down
2. by speeding up
3. by changing direction (turning)

Since the speed is the same, that means the car can't be speeding up or slowing down. Therefore, the car must be turning direction with a constant speed.

In the principle of moments (select the correct statement):
20 points
the moment of the biggest Force will be always bigger than the moment of the other force
moments of both forces are equal
the moment of the smallest Force will be always bigger than the momentof the other Force

Answers

According to the research, the correct option is moments of both forces are equal. In the principle of moments, both moments of forces are equal.

What is the principle of moments?

It states that the moment of a force about a point is equal to the sum of the moments of the components of the force about the point where two forces are equivalent when their effects on a rigid body are the same, that is, produce the same moment.

In this sense, two forces acting on an object are known as a couple whose torques about a point cause the object they act on to tend to rotate.

Therefore, we can conclude that following the equilibrium condition in the principle of moments, a structure of an object has to respond to the action of a moment with another of the same value and in the opposite direction.

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A block of mass 290 kg slides on a frictionless plane inclined at 39◦ with the horizontal under the influence of a restraining force of 1643 N acting parallel to the incline and up the incline. The acceleration of gravity is 9.8 m/s^2

What is the magnitude of the acceleration of the block? Answer in units of m/s^2

The resulting motion is
1. down the plane, since the acceleration is positive.
2. up the plane, since the acceleration is negative.
3. undetermined.

Answers

The magnitude of the acceleration is  −0.50 m/s² of the block of mass 290kg that slides on a frictionless plane inclined at 39◦ with the horizontal under the influence of a restraining force of 1643 .

The resulting motion is

2. up the plane, since the acceleration is negative.

What is acceleration?

Acceleration describes the speed and direction changes in velocity over time. Acceleration refers to the change in speed or direction of an object or point moving straight ahead.

Due to the constant change in direction, motion on a circle accelerates even when the speed is constant. Both effects help to accelerate all other types of motion.

We have given that,

m = 290 kg

θ = 39◦

F = 1643 N

g = 9.8 m/s²

The force due to gravity

F₁ = m × g × sinθ

F₁ = 290 × 9.8 × sin 39°

F₁ = 1790.46 N

Lets take acceleration is a m/s²

Form Newtons second law

F - F₁ = m × a

1643 - 1790.46 = 290 x a

a = −0.50 m/s²

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A cougar with a mass of 80 kg is standing at the edge of a cliff. Find the cougar's potential energy if the cliff is 70 m high. show your work !!!

Answers

The potential energy of the 80kg cougar at a height of 70m is 54880 Joules.

What is the potential energy of the cougar?

Potential energy is simply the energy a body possesses due to its position.

It is expressed mathematically as;

P.E = mgh

Where m is mass, h is height and g is acceleration due to gravity ( g = 9.8m/s² )

Given the data in the question;

Mass of the cougar m = 80kgHeight h = 70mPotential energy P.E = ?

Plug the given values into the potential energy formula above and solve.

P.E = mgh

P.E = 80kg × 9.8m/s² × 70m

P.E = 54880kgm²/s²

P.E = 54880 Joules.

Therefore, the potential energy of the cougar is 54880 Joules.

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A girl is outside walking on level ground. First she walks 829 m to the east, then 223 m north, and finally 387 m west. What is the magnitude of her displacement? Give your answer in meters correct to at least 1 decimal place. Do not include units in your answer.​

Answers

Answer:

not enough information need more information to answer the question

what factors affect skill-related fitness and how does each affect it?

Answers

Several factors affect your skill-related fitness and your skills, including heredity, practice etc .

Skill-related fitness is have six different components; agility, speed, power, balance, coordination, reaction time.

Several factors affect your skill-related fitness and your skills, including heredity, practice etc

for example some people are able to run faster than others or react quick because they inherited these traits from their parents. A person who did not inherited a tendency in these areas from their ancestors ,may have more difficulty performing skills that require those abilities.

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A block of mass 200g is oscillating on the end of a horizontal spring of spring constant 100 N/m and natural length 12 cm. When the spring is stretched to a length of 14 cm, what is the acceleration of the block? [F=ma=kx]

Answers

In order to determine the acceleration of the block, use the following formula:

[tex]F=ma[/tex]

Moreover, remind that for an object attached to a spring the magnitude of the force acting over a mass is given by:

[tex]F=kx[/tex]

Then, you have:

[tex]ma=kx[/tex]

by solving for a, you obtain:

[tex]a=\frac{kx}{m}[/tex]

In this case, you have:

k: spring constant = 100N/m

m: mass of the block = 200g = 0.2kg

x: distance related to the equilibrium position = 14cm - 12cm = 2cm = 0.02m

Replace the previous values of the parameters into the expression for a:

[tex]a=\frac{(\frac{100N}{m})(0.02m)}{0.2\operatorname{kg}}=10\frac{m}{s^2}[/tex]

Hence, the acceleration of the block is 10 m/s^2

consider a resistor-inductor circuit where a 10v force is applied for a period of 2 seconds. the equation for the current in the circuit is given: \f$\displaystyle \small \frac{di}{dt} 5i

Answers

A step function is defined U(t)=0,1 [tex]\left \{ {{t < 0} \atop {t > 0}} \right.[/tex]  i(t)=e^-5t + 2 if t=2&3 & i(t)=3e^-5t if  2>t>3.

A step function, sometimes known as a staircase function, is a piecewise constant function with a limited number of parts, according to the definition given in mathematics. In other words, one can think of a function on the real numbers as a finite linear combination of indicator functions of given intervals. In addition, it goes by the names floor function and biggest integer function. There is no continuity in the step function. In mathematics, a step function is a function whose graph resembles a series of steps because it is made up of numerous horizontal line segments interspersed with jumps. The biggest integer function is a frequent illustration of step functions in mathematics.

When provided intervals are used, a step function has a constant value, but the constant varies for each interval. A function that returns the biggest integer that is less than or equal to x is known as the greatest integer function.

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An arrow is launched straight up from the ground with an initial velocity of 23.4m/s how long until it reaches its highest point

Answers

Answer:

t = 2.388 seconds

Explanation:

Initial velocity is 23.4 m/s

At the highest point, the velocity will be 0 m/s

We can use the equation

[tex]v = u+at[/tex]

V is the final velocity at the highest point

U is the initial velocity

A is the gravity pulling down on the ball

T is the time in seconds  

We plug in the numbers

[tex]0 = 23.4 - 9.8t[/tex]

[tex]t = 2.387755102[/tex]

an airplane traveling 1001 m above the ocean at 125 km/h is going to drop a box of supplies to shipwrecked victims below. a. how many seconds before the plane is directly overhead should the box be dropped?

Answers

14.3 seconds before the plane is directly overhead should the box be dropped in projectile motion.

The motion of thebox is a projectile motion, therefore it consists of two independent motions:  

A uniform motion (at constant velocity) along the horizontal direction  

A uniformly accelerated motion, with constant acceleration (=acceleration of gravity, ) in the downward direction  

s = 1000 m is the vertical distance that the box must cover

u = 0 (the box's initial vertical velocity (zero, since it is travelling horizontally)

g is the acceleration of gravity

t is the time

The time the box needs to arrive at the ground is determined by solving for t:

[tex]t=\sqrt((2s/g=\sqrt((2(1000))/(9.8))=14.3s[/tex]

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You are instructed by your supervisor to move 20 boxes—each of which has a weight of 11.34 N—onto an awaiting truck. The back of the truck is 1.65 m above the loading dock. How much work must you perform to do your assignment?

Answers

The amount of work done to move 20 boxes each of weight 11.34 N onto an awaiting truck with back 1.65 m above the loading dock is 374.22 Joule.

Work done is calculated by the product of total force and displacement.

According to the question, total force done to lift the boxes is twenty times the weight of each box. So, the force required to lift all the blocks is,

Force = 20 × 11.34 = 226.8 N

As the back of the truck is 1.65 m above the loading dock, displacement done to move the boxes is 1.65 m.

So, the work done is,

Work = 226.8 × 1.65 = 374.22 Joule

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a cylinder of mass m slides down from rest in a vertical tube whose inner surface is covered by a viscous oil of film thickness h. if the diameter and height of the cylinder are d and l, respectively, derive an expression for the velocity of the cylinder as a function of time, t. discuss what will happen as t → [infinity]. can this device serve as a viscometer?

Answers

When there is relative motion between the fluid layers or between the fluid and solid surface, the fluid's internal property known as viscosity is created. This relative motion is being resisted by viscosity.

Derivations of the equations of motion—the connections for the conservation of mass and momentum—in rectangular,

coordinates that are spherical and cylindrical. The entire body of experimental data suggests that the fundamental equations of fluid mechanics are in fact those listed below, and that they apply to any circumstance where a Newtonian fluid is flowing, in theory.

Viscosity, a characteristic of fluids, is produced when there is relative motion between the fluid layers or between the fluid and solid surface. Viscosity prevents this relative motion from happening.

Unfortunately, due to their all-encompassing nature, their analytical solution is challenging or impossible unless the circumstances are quite straightforward.

However,

These "Navier-Stokes equations" must be understood for the following reasons.

reasons:

1. They result in the analytical and precise resolution of some basic yet significant problems.

issues.

2. They serve as the foundation for additional chemical engineering research in various fields.

3. A few reasonable simplification assumptions can frequently result in

for many engineering problems, approximation solutions are eminently acceptable purposes. Typical examples can be found in the study of boundary layers, the use of films to cover substrates, waves, lubrication, and inviscid (irrotational) flow.

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electromagnetic radiation with a maximum wavelength of 540 nm(5.4×10−7 m) is needed for the study of the photoelectric effect in potassium atoms. what is the approximate frequency that corresponds to this wavelength?

Answers

At a speed of two times ten to the eighth and violent. 5, 40 times 10 to the power -9 meters is written as. This leads to the conclusion that frequency F is equivalent to 5.6 times. Turn 14 times every second. Therefore, the given electromagnetic radiation requires this frequency.

In this problem, we have a given violent electromagnetic radiation, and we need to determine the frequency that corresponds to that violent electromagnetic radiation.

The chosen wavelength is lambda. I called at five minutes and forty nanometers—540 times 10 to the power—or nine meters. Considering that one nanometer equals 10 to the power -9 meters. Now, sea upon lambda finds frequency.

The value of C is three in 2, ten to the power eight meters per second, violent, and the speed of light in a vacuum. 5, 40 times 10 to the power -9 meters is written as. This leads to the conclusion that frequency F is equivalent to 5.6 times. Turn 14 times every second. Therefore, the given electromagnetic radiation requires this frequency.

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two carts mounted on an air track are moving toward one another. cart 1 has a speed of 0.9 m/s and a mass of 0.45 kg. cart 2 has a mass of 0.62 kg. (a) if the total momentum of the system is to be zero, what is the initial speed of cart 2 in meters per second?

Answers

Because the total momentum of the system is zero, Cart 2's initial speed is 0.62 m/s. No, the system's kinetic energy is not equal to zero because energy, according to the law of conservation of energy, cannot be destroyed.

The kinetic energy of the system is 0.268 Joules. Linear momentum is a vector quantity defined as the product of an object's mass, m, and velocity, v. The letter 'p' is used to express it, and momentum is used for short. Please keep in mind that the body's momentum always points in the same direction as its velocity vector. A body's momentum is defined as the product of its mass and velocity.

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What type of wave is an electromagnetic wave?
transverse
longitudinal
both
neither

Answers

Both.
Electromagnetic waves could be transverse or longitude or a combination of both.

Your community is considering building a dam on a nearby river to reduce flooding. Would you support this proposal? Explain.
I need to get it done right now

Answers

Your community is considering building a dam on a nearby river to reduce flooding. yes, this proposal need support. because through dam we can store flood water.

What is a dam?

A physical barrier known as a dam slows or limits the flow of surface or subsurface water. Reservoirs built by dams provide water for navigation, aquaculture, irrigation, human consumption, industrial use, and other purposes.

What is the use of dam?

Let's examine some of a dam's uses now that we have a basic understanding of what a dam is. It is valued as a resource for water. They provide water for a variety of uses, including home, agricultural, and industrial ones. Dams are also utilised to produce energy and improve river transportation. Dams are used more and more frequently in daily life. Dams also promote local tourism, which contributes to the growth of the nation. Dams can be used for many different things.

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replace the force system acting on the post by a resultant force, and specify where its line of action intersects the post ab measured from point b. (10 points)

Answers

The resultant force is the force that can replace all the acting forces and have a comparable effect on the section or beam when several forces are acting on it.

If the forces acting on a body in a specific direction result in a net sum of zero in that direction, the forces acting on the body are said to be in equilibrium.

The resultant force is the force that can replace all other forces operating on a beam or section while still having the same impact on the section or beam. This force is used when many forces are acting on a beam or section.

The resultant force in the X direction equals 250 and must act for more than five, minus 500 cosign 30 minus 300, which equals 533.41 Newton and the magnitude of the forces in the left direction. The magnitude of the resultant force in the y direction should likewise be the same. S

ome forces that are equal to 500 sign 30 - 150 in the y direction. multiply it by 3/5 so that it equals 100. Newton's are inefficient, thus the force Rf's magnitude should be square root off 533.1 square lost 100 square, equaling 542 Newtons, and the angle Sita if 10 members 100 over 533.41, equal to 10.6 degrees for the location off.

We have 533.1 when we multiply the equal 500 committed by the result on force So instant off the resultant around the. 30 supply point to minus 250 and multiplied by minus 500. city above five, apply.

Subtract 200 50 from 0.5. Divide by 4/5. Loss of three supplies A 300 must submit one. Therefore, using this equation, we can determine T's value, which is 827 millimeters.

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17. A ball rolls off a lab table at 5 m/s horizontally. The table is 1.2 meters tall.

a. How long is it in the air?

b. How far from the table does it hit the ground?

c. What are the x and y speeds just before it hits the ground?

Answers

The ball is in the air for 0.24 seconds, the ball hits the ground 2.46 meters far from the table and the x speed is 0m/s and y speed is 5m/s.

Velocity of the ball is 5m/s and the height of the table is 1.2 meters.

a. We know,

Velocity = distance/time

5 = 1.2/time

Time = 1.2/5

Time = 0.24 seconds.

The time taken by the ball to reach the ground is 0.24 seconds.

b. The ball after rolling of the table will behave like Horizontal projectile.

Horizontal range R formula,

R = V.√(2h/g)

Putting all the values,

R = 5.√(2×1.2/9.8)

R = 5×0.49

R = 2.46 meters.

c. When the ball reaches the ground,

X speed is 0m/s and Y speed is 5m/s.

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what is temperature?
how temperature can be measured​

Answers

Answer:

Temperature is the kinetic energy of the particles of a substance.

Explanation:

The more kinetic energy a particle has the higher it's temperature. In the case of the atmosphere, which is what we are primarily concerned with in Meteorology, we measure this using a mercury thermometer (in certain situations we use an alcohol thermometer and of course modern times have given us things like dewcells and digital thermometers but we always go back to the mercury thermometer for accuracy).

Find the x -component of vector a⃗ = (7.0 m/s2 , −y -direction).

Answers

The y-component of vector (a ) is  -7.0j m/s²

In science, anything that has both a direction and a magnitude is referred to as a vector. They are typically represented by pointing arrows, the length of which denotes the size of the vector. The direction is then crucial in accordance with the vector.

We are given that,

the x -component of vector (a)x = 7.0m/s²

The acceleration in vector sum form x - direction and y - direction is given as,

[tex]a = a_{x} +a_{y}[/tex]

So that , the (-y-direction) acceleration then x- component must be zero then,

[tex]a =(7.0i) + (-7.0j)\\a= - 7.0j[/tex]

Thus, the acceleration on -y- direction will be -7.0jm/s²

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Your friend states in a report that the time needed for ten laps has been measured and that the average time required to circle the 2.5-mile track was 65.421 seconds. You know that the clock used has a precision of .2 seconds. How much confidence do you have in the results of the report? Explain

Answers

Results are never more exact than the least precise measurement. The average lap time surpasses clock precision.  I will have a fair amount of confidence in the results of the report

This is further explained below.

What is a circle?

Generally, A result can never be more accurate than the measurement that was the least accurate.

The calculated average lap time is more accurate than the clock can measure.

A conclusion can never be more accurate than the measurements that were used to get at it. The accuracy that may be achieved with the clock is exceeded by the average lap time that was determined.

Hence, for a clock that bears a precision of 0.2 seconds, I will be confident in its results bearing precision in mind, Because knowing the precision you can easily manipulate the results to get the desired outcome

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A scientific model can be used to

Answers

Scientific models area unit accustomed make a case for and predict the behaviour of real objects or systems.

A system of ideas, events, or processes is described physically, mathematically, conceptually, or conceptually in an exceedingly scientific model. By victimisation their scientific experience to produce explanations that create it doable to forecast the patterns, scientists work to recognise and comprehend the patterns that exist in the environment.

Scientific model illustrations include:

a simulation of the sun, moon, and earth's motions (which you participated in last year) a way for statement eclipses. The weather will be foretold victimisation models that describe weather events.

Models will assist you in mentally imagining one thing that's difficult to ascertain or comprehend. Models will aid in scientific prediction, understanding of processes, and communication of ideas.

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an initially stationary box of sand is to be pulled across a floor by means of a cable in which the tension should not exceed 1100 n. the coefficient of static friction between the box and the floor is 0.35. (a) what should be the angle between the cable and the horizontal in order to pull the greatest possible amount of sand, and (b) what is the weight of the sand and box in that situation?

Answers

a) The angle between the cable and the horizontal in order to pull the greatest possible amount of sand is 19°. b) The weight of the sand and box in that situation is 3.3x10³ N.

A similar scenario is depicted with a free-body diagram and in the textbook's illustration, where the unknown angle is represented by the symbol. We employ the same system of coordinates as in that figure.

a) Newton's second law thus results in

x : T cosФ - f = ma

y : T sinФ + Fn-mg = 0

With a = 0 and f = f s, max = s F N, we may solve for the mass of the box-and-sand (as a function of angle) as follows:

m = T/g (sinФm + cosФm/us )

Hence, in order to determine the angle m that corresponds to the greatest mass that may be drawn, we will solve using calculus techniques.

dm/dt = T/g  (sinФm + cosФm/us ) = 0

As a result, tan m = s is obtained, and for s = 0.35, m = 19 is obtained.

(b) The result of entering our value for m into the formula we discovered for the mass of the box and sand is m=340 kg. This is equivalent to a weight of mg=3.3x10³ N.

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Which requires more work to do, using a force to lift a 50 kg. rock, 2 meters or lifting a 25 kg. rock, 4 meters? (1 kilogram=10 newtons)

Answers

Given data:

Mass of rock 1;

[tex]m_1=50\text{ kg}[/tex]

Height rock 1 lifted;

[tex]h_1=2\text{ m}[/tex]

Mass of rock 2;

[tex]m_2=25\text{ kg}[/tex]

Height rock 2 lifted;

[tex]h_2=4\text{ m}[/tex]

The work done in lifting the rock is given as,

[tex]W=mgh[/tex]

Here, m is the mass of the rock, g is the acceleration due to gravity (g=10 m/s²) and h is the height the rock lifted.

The work done in lifting rock 1 is given as,

[tex]W_1=m_1gh_1[/tex]

Substituting all known values,

[tex]\begin{gathered} W_1=(50\text{ kg})\times(10\text{ m/s}^2)\times(2\text{ m}) \\ =1000\text{ J} \end{gathered}[/tex]

The work done in lifting rock 2 is given as,

[tex]W_2=m_2gh_2[/tex]

Substituting all known values,

[tex]\begin{gathered} W_2=(25\text{ kg})\times(10\text{ m/s}^2)\times(4\text{ m}) \\ =1000\text{ J} \end{gathered}[/tex]

On comparing the work done in lifting rock 1 and 2 we conclude that,

[tex]W_1=W_2=1000\text{ J}[/tex]

Therefore, the same amount of work is done in lifting a 50 kg rock by 2 meters and lifting a 25 kg rock by 4 meters.

[2-d collision on a frozen pond] while doing physics experiments on a frozen pond's frictionless horizontal surface, sam, of mass 80.0 kg, is given a push and slides eastward. abigail, of mass 50.0 kg, is sent sliding northwards. they collide (whump!), and afterwards sam is moving at 37.0° north of east at 6.00 m/s, while abigail is moving 23.0° south of east at 9.00 m/s.

Answers

We could  calculate the initial and final kinetic energy after computing the velocities prior to the impact. So, the total kinetic energy of the two people decrease during the collision by -638.73 J.

Since the velocity before to the collision is unknown, it is impossible to calculate the kinetic energy. So, we'll start by computing the velocities before to the impact.

If all external forces have a zero vector total, momentum is said to be conserved. In other terms, it may be said that the system's momentum prior to the collision and its after momentum should be identical.

This indicates that even if we know little or nothing about the internal forces of the system, we can still calculate the system's momentum.

The kinetic energy prior to and following the collision must be calculated in order to calculate the change in kinetic energy.

Due to the unknown velocity before to the contact, it is impossible to calculate the kinetic energy. As a result, we'll start by computing the velocities that existed before the impact.

The first step is to calculate the x and y components of the velocity following the collision. Sam might be represented by variable S, and Abigail by variable A.

v S = v S x + v S y = 6.00 m / s cos 37 + 6.00 m / s sin 37 v S = ( 4.79 I + 3.61 j ) m / s v A = v A x + v A y = 9.00 m/s cos 23 + 9.00 m/s sin 23 v A = ( 8.28 I + 3.52 j ) m / s

Then, keep in mind the equation for momentum conservation: p 1 = p 2

where p 1 represents the momentum prior to the collision and p 2 represents the momentum following the collision. Since Sam is sliding eastward before to the collision in the aforementioned scenario, we will only utilize the x component of the velocity after the collision of Sam and Abigail to compute the velocity of Sam before the collision, and we will also set Abigail's momentum to zero.

We could now calculate the initial and final kinetic energy after computing the velocities prior to the impact.

KE1=12mS(vS1)

2+12mA(vA1)

2=12(80 kg)(9.97 m/s)

2+12(50 kg)(2.26 m/s)

2KE1=4103.73 J

KE2=12mS(vS1)

2+12mA(vA1)

2=12(80 kg)(6.00 m/s)

2+12(50 kg)(9.00 m/s)

2\sKE2=3465 J

The difference between the end and starting kinetic energy could be used to calculate the change in kinetic energies.

KE= -638.73J

Complete question is:

You and your friends are doing physics experiments on a frozen pond that serves as a frictionless, horizontal surface. Sam, with mass 80.0 kg, is given a push and slides eastward. Abigail, with mass 50.0 kg, is sent sliding northward. They collide and after the collision, Sam is moving at 37.0 degrees north of east with a speed of 6.00m/s and Abigail is moving at an angle 23.0 degrees south of east with a speed of 9.00 m/s. By how much did the total kinetic energy of the two people decrease during the collision?

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A rectangular loop of wire with a cross-sectional area of 2.936 m2 carries a current of 6.488 A. The loop is free to rotate about an axis that is perpendicular to a uniform magnetic field strength of 1.108 T. The plane of the loop is initially at an angle of 59.914o to the direction of the magnetic field. What is the magnitude of the torque on the loop ?

Answers

ANSWER:

10.58 Nm

STEP-BY-STEP EXPLANATION:

Given:

Area (A) = 2.936 m²

Current (i) = 6.488 A

Magnetic field (B) = 1.108 T

Angle (θ)= 59.914°

To calculate the torque we must resort to the following formula:

[tex]\begin{gathered} \tau=MB\sin\alpha \\ \\ \alpha=90\degree-\theta=90-59.914\degree \\ \\ \alpha=30.086\degree \end{gathered}[/tex]

We need to know the magnetic moment, as follows:

[tex]\begin{gathered} M=NIA \\ \\ M=1\cdot6.488\cdot2.936 \\ \\ M=19.05\text{ A}\cdot m^2 \end{gathered}[/tex]

In this way we can calculate the torque:

[tex]\begin{gathered} \tau=19.05\cdot1.108\cdot\sin(30.086\degree) \\ \\ \tau=10.58\text{ Nm} \end{gathered}[/tex]

Therefore, the magnitude of the torque on the loop is 10.58 Nm

If an airplane is flying 100 mph South but there is a crosswind pushing the airplane 30 mph to the West, then what would the resulting velocity be?
O 104.4 mph, NE
O 104.4 mph, SW
O 10900 mph, NE
O 11.4 mph, SW

Answers

The resultant velocity of the plane has a magnitude  104.4  mph and direction    south of west .

What do you mean by velocity?The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate.The speed at which something moves in a specific direction is known as its velocity. as the speed of a car driving north on a highway or the pace at which a rocket takes off. Because the velocity vector is scalar, its absolute value magnitude will always equal the motion's speed.

The plane is flying south at a speed of  100  mph and is blown by a  30mps strong wind due west.

⇒  The angle between the direction of flight of plane and the direction of the wind is  90° .

⇒  By Pythagoras theorem, the resultant speed is

[tex]\sqrt{100^{2} +30^{2} } =\sqrt{10900}[/tex] =104.4 mph

⇒  The resultant velocity of the plane has a magnitude  104.4  mph and direction    south of west

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