Determine if the two triangles are congruent if they are state how do you know SSS,SAS,HL,ASA, OR AAS. Be sure to include any extra vocabulary reflexive vertical angles alternative interior angles

Determine If The Two Triangles Are Congruent If They Are State How Do You Know SSS,SAS,HL,ASA, OR AAS.

Answers

Answer 1
1: yes AAS
2: yes SSS reflective
3: yes ASA
4: yes HL reflective
5: no SSA vertical
6: yes SAS vertical

Not sure on vocabulary for 1 and 3 sorry:(

Related Questions

sec^2 (pi/2 - x) * [sin^2 (x) - sin^4 (x)]

Answers

Answer:

Explanation:

Identity:  sec2θ=1+tan2θ

sec2(π2−x)−1=1+tan2(π2−x)−1

=tan2(π2−x)

Identity: tan(π2−θ)=cotθ

=cot2x

My sis is having a hard time simplifying a problem. I'm not good at simplifying myself So I cant help her ):P

simplify 48 divided by 2 x 4

Answers

3 x 2 x 2 x 2 x 2 / 2 x 2 x 2

48 / 2 x 4

[48 can be simplified to 24 x 2 and 4 can be simplified to 2 x 2]

24 x 2 / 2 x 2 x 2

[24 can be simplified to 12 x 2]

12 x 2 x 2 / 2 x 2 x 2

[12 can be simplified to 6 x 2]

6 x 2 x 2 x 2 / 2 x 2 x 2

[6 can be simplified to 3 x 2]

3 x 2 x 2 x 2 x 2 / 2 x 2 x 2

Please someone help me with this

Answers

Answer:

ANSWER:C

Step-by-step explanation:

sana maka tulong

over 2 days, students completed a math test. in the first test. there were 50 questions, and one student got 39 questions correct. which percent equation correctly represents this situation?​

Answers

Answer:

78%

Step-by-step explanation:

39/50 x2 → 78/100 so 78%

The formula for the area of a trapezoid is A=1/2(b1+b2)h. Solve the equation for b1

Answers

2A=b1 +b2
So
b1= 2A-b2

A balloon is being inflated mechanically in such a way that the volume is increasing at a constant rate of 15 cm3 /s. If the volume of the balloon was originally 30 cm3, determine the average rate of change of the volume of the balloon with respect to the radius of the balloon, to the nearest centimetre cubed per centimetre, between 0 s and 10s, and between 10 s and 20 s.Discuss the following question:Is the rate of change of volume with respect to radius constant?

Answers

The magnitude of the volume of the balloon increases at a faster rate than

the radius of the balloon.

The rate of change of the volume of the balloon with respect to radius is not  constant.

Reasons:

The rate at which the volume of the balloon is increasing, [tex]\dfrac{dV}{dt} = 15 \ cm^3/s[/tex]

The initial volume of the balloon, V = 30 cm³

The rate of change of the volume of the balloon with radius is given as follows;

[tex]\dfrac{\Delta V}{\Delta r}= \dfrac{V_2 - V_1}{r_2 - r_1}[/tex]

[tex]Volume \ of \ the \ balloon, \ V = \dfrac{4}{3} \cdot \pi \cdot r^3[/tex]

[tex]V = 30 + \dfrac{dV}{dt} \times t[/tex]

∴ V = 30 + 15·t

At t = 0, V = 30 cm³

Where;

[tex]r =\sqrt[3]{ \dfrac{3 \cdot V}{4 \cdot \pi} }[/tex]

When V = 30

[tex]r =\sqrt[3]{ \dfrac{3 \times 30}{4 \cdot \pi} } \approx 1.93[/tex]

The radius, r ≈ 1.93 cm.

At t = 10 s., we have;

V = 30 + 15 × 10 = 180

[tex]r =\sqrt[3]{ \dfrac{3 \times 180}{4 \cdot \pi} } \approx 3.5[/tex]

At t = 20 s., we have;

V = 30 + 15 × 20 = 330

[tex]r =\sqrt[3]{ \dfrac{3 \times 330}{4 \cdot \pi} } \approx 4.29[/tex]

Therefore;

Between 0 s. and 10 s., we have;

[tex]\dfrac{\Delta V}{\Delta r}=\dfrac{180 - 30}{3.5-1.93} \approx 96[/tex]

Rate of change of the volume of the balloon with respect to the radius of the balloon to the nearest centimeter, between 0 s and 10 s is 96 cm³/cm.

Between 10 s. and 20 s., we have;

[tex]\dfrac{\Delta V}{\Delta r}=\dfrac{330 - 180}{4.29 - 3.5} \approx 190[/tex]

Between 10 s. and 20 s. the rate of change is approximately 190 cm³/cm.

Therefore;

The rate of change of the volume of the balloon with respect to radius is not constant, but increases as the volume of the balloon increases.

Learn more here:

https://brainly.com/question/13489213

Hannah made four withdrawals of $20 from her checking account. She also
wrote a check for $215. By how much did the amount in her checking account
change?
(Show answer )

Answers

20 *4 = 80, 215 +80 = 295.
Answer She took out 295 dollars or -295

You would do 20x4+215

Calculate the average speed (in miles per hour) of Cassandra who runs a 18 mile marathon in 6 hours.

0 24 mi/hr
O 3 mi/hr
O 0.333 mi/hr
O 12 mi/hr

help plssss

Answers

Cassandra runs 3 miles.

Hope this helps! :D

Hi upandover can you help me.

Answers

Answer:

-a^5x^3

Step-by-step explanation:

hope this helps! :)

Let's separate this out and multiply the coefficients first, then the variables.

2 1/3 = 7/3

7/3 * -3/7 = -1

(a^2)(x)(a^3)(x^2)

When we multiply terms with exponents, we ADD the exponents.

(a^5)(x^3)

Answer: (-1)(a^5)(x^3)

Coefficient: -1

Hope this helps!

help pleaseeeeeeee!!!!!!!!

Answers

Answer:

4,3

Step-by-step explanation:

Answer:

rectangle

Step-by-step explanation:

square corners and unequal sides

3/4 + 3/16 and 3/4 - 3/16

Answers

Answer:

for the first it is 15/16 and the second is 9/16

to help you use desmos sictific coulator

what is -1/2 cubed? ?

Answers

Answer:

-1/8

Step-by-step explanation:

(-1/2)^3 = (-1/2) * (-1/2) * (-1/2) = -1/8

Answer:

-0.125

:) Hope this helped, let me know if you need more help! :)

A cheetah traveling at 31 m/s chased its prey for 11 seconds. What distance did the cheetah travel during the chase?

Answers

Answer:

341 meters

Step-by-step explanation:

you just multiply 31 by 11.

Answer:

341 meters

Step-by-step explanation:

Jusr do 31 times 11

Evaluate p+23 for p=8

Answers

Answer:

31

Step-by-step explanation:

p = 8

p + 23

= 8 + 23

= 31

31 is the answer.

Round 19.432 to the nearest whole.

Answers

19:))))))))))))))))))))))))))))))))))

I need help with these

Answers

Answer:

The graph is linear and shaded below the line.

Step-by-step explanation:

It looks like the graph is linear, since the line is straight and continues on forever in both directions. It's not quadratic or absolute value, since quadratic graphs are curved and absolute value graphs branch off in two directions.

If you look at the Desmos graph attached, the shade is below the line, not above the line.

Finally, (0, 0) is not a solution since this point is not part of the shaded section of the graph.

Hopefully this helps! If you need further clarification, let me know!

How do I simplify (9 square 3-4 square+2)-(x square 3+3 square 2 +1

Answers

Answer:

8x³ - 3x² - 4x + 3

Step-by-step explanation:

first, eliminate the parenthesis. you can just drop the first set, but you have to distribute the negative through the second set.

9x³ - 4x + 2 - x³ - 3x² +1

then combine like terms (terms with the same exponent)

8x³ - 4x + 3 - 3x²

then put it in the correct order

8x³ - 3x² - 4x + 3

this is what my techer told me to do "Show a different way to solve 99x76"

Answers

Answer:

I think it's 76×99

Step-by-step explanation:

hope it helps

what is 75 divided by 5

Answers

75 divided by 5 = 15

Answer: 75 / 5 = 15

Ways to write it:

75 ÷ 5 = 15

75 over 5 = 15

75⁄5 = 15

(with work shown) what is 6396 / 15 then that answer -6000

Answers

Answer:

-5573.6

Step-by-step explanation:

Answer correctly for brainliest

Answers

where is your question?

Answer:

what is your question?

4^3 • 5^3 and 20^3, Are the expressions equivalent? Yes or no?

Answers

Answer:

Yes

Step-by-step explanation:

4³ × 5³

(4 × 5)³

=20³

Both are equivalent

Hey there!

4^3 * 5^3 = ?

4^3

= 4 * 4 * 4

= 16 * 4

= [64]

5^3

= 5 * 5 * 5

= 25 * 5

= [125]

125 * 64

= [8,000]

20^3

= 20 * 20 * 20

= 400 * 20

= 8,000

8,000 = [8,000]

Therefore, this statement is TRUE so your answer is: [YES]

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)


Write an equation of the line that passes through point (6, 1) and has the slope m = -3.
y
4

Answers

Answer:

[tex]y = mx + c[/tex]

[tex]1 = - 3 \times 6 + c[/tex]

[tex]1 = - 18 + c[/tex]

[tex]1 + 18 = - 18 + 18 + c[/tex]

[tex]19 = c[/tex]

[tex]y = 6x + 19[/tex]

Please find the value of X

Answers

Answer:

x = 116°

Step-by-step explanation:

since l and m are parallel lines

by property

116° = x

f(x)= ve + 9. Find f'(x) and its domain.

Answers

Answer:

Find the domain by finding where the expression is defined.

Interval Notation: [tex](-[/tex]∞[tex],[/tex] ∞[tex])[/tex]

Set-Builder Notation: {[tex]x|x[/tex] ∈  R}

The function declaration [tex]f(x)[/tex] varies according to [tex]x[/tex], but the input function [tex]ve + 9[/tex] only contains the variable [tex]v[/tex]. Assume

[tex]f(v)=ve+9[/tex]

[tex]f(v)=ve+9[/tex]

what is the answer to the equation 5x+10=25

Answers

Answer:

x=7

Step-by-step explanation:

Answer:

x = 3

Step-by-step explanation:

5x+10=25

you want x to be by itself

5x=15

so subtract 10 from both sides

then dived 5 from 15

x=3

Rates & proportional relationships: Quiz 1
Which equation has a constant of proportionality
equal to 10?
Choose 1 answer:
2
y = х
20
30
y = -
3
©
12
y = -
2
5
Y= T

Answers

Answer:

The answer is B. when you do 30 / 3 you get 10

I need help figuring out the answers to these kinda poorly worded questions

Answers

Answers:What is that positive integer?  400What is the value of the positive root?  20What is the value of the negative root?  -20

=======================================================

Explanation:

Let x be the unknown positive integer.

The square roots of x are [tex]\sqrt{x}[/tex] and [tex]-\sqrt{x}[/tex], representing the positive and negative square roots respectively.

Taking the difference of those means we subtract:

[tex]\text{PositiveRoot}-\text{NegativeRoot} = \sqrt{x} - (-\sqrt{x}) = \sqrt{x}+\sqrt{x} = 2\sqrt{x}[/tex]

Set that equal to 40 and solve for x

[tex]2\sqrt{x} = 40\\\\\sqrt{x} = 40/2\\\\\sqrt{x} = 20\\\\x = 20^2\\\\x = 400[/tex]

Therefore, the integer we're after is 400.

The positive square root of such is [tex]\sqrt{x} = \sqrt{400} = \sqrt{20^2} = 20[/tex]

And the negative square root is [tex]-\sqrt{x} = -\sqrt{400} = -\sqrt{20^2} = -20[/tex]

The difference of which is:

(Positive Root) - (Negative Root) = 20-(-20) = 20+20 = 40

This helps confirm the answers.

Hey anyone help please n thank you :)

Answers

Answer:

(9, 9) this is where they intersect at

Step-by-step explanation:

rearrange to make x the subject

[tex]y=\frac{3x-2}{x+1}[/tex]

please i need for hwk for exam

Answers

Step-by-step explanation:

Given equation :

y = 3x - 2 / x+1

for subject x

» x = - 2 + y -3+ y
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