Denzel identified (3,2) as a point on the line y-2 = 2/3 (x+ 3). What is the error Denzel made?

Answers

Answer 1

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

He identified the incorrect x-value.

See explanation below.

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\text{General Point-Slope Form is:}\\\\y - y_1 = m(x-x_1)\\\rule{150}{0.5}\\\\(x_1,y_1) -\text{A point that is given.}\\\\m -\text{Slope}[/tex]

⸻⸻⸻⸻

Denzel incorrectly identified the x-value of the given point.  The value '-3' is actually indicated in the equation. If you plug in '-3' into the equation, you would get '-(-3)', which simplifies to '+3'.

⸻⸻⸻⸻

[tex]y-2 = \frac{2}{3} (x-x_1)\rightarrow y-2 = \frac{2}{3} (x-(-3))\rightarrow y-2=\frac{2}{3} (x+3)[/tex]

⸻⸻⸻⸻

The point in the equation should be: (-3, 2).

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer 2

The correct points of the line will be (-3,2).

What is an equation of the line?

An equation of the line is defined as a linear equation having a degree of one. The equation of the line contains two variables x and y. And the third parameter is the slope of the line which represents the elevation of the line.

The general form of the equation of the line:-

y = mx + c

m = slope

c = y-intercept

Slope = ( y₂ - y₁ ) / ( x₂ - x₁ )

Given that the point (3,2) is on the line y-2 = 2/3(x+ 3). Satisfy the equation with the given point and check.

y-2 = 2/3(x+ 3)

2-2 = (2/3)(3 + 3)

0 = 4

To make left hand side and right hand side equal the value of x coordinate should be -3.

y-2 = 2/3(x+ 3)

2-2 = (2/3)(3 + 3)

0 = 0

Therefore, the correct points of the line will be (-3,2).

To know more about an equation of the line follow

brainly.com/question/18831322

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*What you should know*

Point slope form,

y-y1=m(x-x1)

Parallel lines have the same slope.

1. Points (4,2)

y=2

x=4

m=-3/4

substitute this information into the point-slope form formula,

y-2=-3/4(x-4)

2.

y=-3

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y-(-3)=7/3(x-(-3))

3.(-4,0)

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m=3/4

》y-0=3/4(x-4)

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x=-1

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