Answer:
Let's define x as the number of text messages send.
y as the number of 1,000 minutes talk per month.
(so we can write y = N/1000) where N is exactly the number of minutes that you talked that month.
> The equation for Dash is:
C1(x, y) = $80
>The equation for AB&C
C2(x,y) = $0,20*x + $55*y
> Horizon
C3(x,y) = $0.10*x + $75*y.
Now, which company you should go for?
Well, it depends on the values of x and y that you have.
if in your case you have x > y, you may want to go with Horizon, because the price per text is smaller.
if you usually talk, you may want to go with AB&C because the slope for y is smaller.
If you send a lot of texts and talk a lot, then Dash is the best option, because there is no dependence with the variables x, y
1.4.27
Use the number line below, where RS = 5y +3, ST = 4y + 7, and RT = 64.
a. What is the value of y?
b. Find RS and ST.
R
a. What is the value of y?
y=(Type an integer or a decimal.)
Answer:
(a). The value of y is 6.
(b). The value of RS and ST are 33 and 31.
Step-by-step explanation:
Given that,
RS = 5y+3
ST=4y+7
RT=64
(a). We need to calculate the value of y
Using given data
[tex]RS+ST=RT[/tex]
Put the value into the formula
[tex]5y+3+4y+7=64[/tex]
[tex]9y=64-10[/tex]
[tex]y=\dfrac{54}{9}[/tex]
[tex]y=6[/tex]
(b). We need to calculate the value of RS
Using equation of RS
[tex]RS=5y+3[/tex]
Put the value of y
[tex]RS=5\times6+3[/tex]
[tex]RS=33[/tex]
We need to calculate the value of ST
Using equation of ST
[tex]ST=4y+7[/tex]
Put the value of y
[tex]ST=4\times6+7[/tex]
[tex]RS=31[/tex]
Hence, (a). The value of y is 6.
(b). The value of RS and ST are 33 and 31.
Es para hoy hasta las 8:30 Cuantos vasos, con capacidad de 200 mililitros, se necesitan para trasvasar 20 litros de leche que están en un tonel de 200 litros a un porrón de 25 litros de capacidad
Answer:
100 vasos
Step-by-step explanation:
Sabemos que usando la conversión de unidades SI
1 litro = 1000 mililitros
En la pregunta se nos dice que:
Necesitamos trasvasar 20 litros de leche utilizando vasos de 200 mililitros de capacidad.
Por lo tanto,
1 litro = 1000 mililitros
20 litros =
20 litros × 1000 mililitros / 1 litros
= 20.000 mililitros de leche que hay que transferir.
Dado que estamos usando vasos con capacidad de 200 mililitros, la cantidad de vasos necesarios
= 20.000 mililitros de leche / 200 mililitros
= 100 vasos
Por tanto, se necesitan 100 vasos de 200 mililitros de capacidad para trasvasar 20 litros de leche que se encuentran en un barril de 200 litros a una jarra de 25 litros de capacidad.
y/3=2-2y in a verbal sentence
Answer:
Y=6/7
Step-by-step explanation:
Y=0.857142
Answer:
a number divided by 3 equals the value of two times the same number subtracted from 2Step-by-step explanation:
Simplify:
4 (1/2 + 5/4) +-5=
A.2
B.3
C.4
D.5
Answer:
2
Step-by-step explanation:
First do whats in the parenthesess
it will look like this
2+5-5=2 the 5's cancel eachother out so your left with 2
Convert 45 miles per hour to miles per minute
Answer:
0.75 miles is miles per minute
67 hundreds into standard form
There's a difference between "hundredths" and "hundreds". I'm going to assume you mean 6,700.
Answer:
6.7*10^3
Step-by-step explanation:
Write out the number.
6700
Bring the decimal to the left. However many times you move over to the left until you get between 6 & 7 should be your exponent for 10.
6.7*10^3
Writing a two-column proof
Answer: I know this is late, but hope this helps. ^-^
Step-by-step explanation: Edge 2021.
To prove : m∠ABC = m∠GHI
Given,
∠ABC ≅ ∠DEF
∠GHI ≅ ∠DEF
Here,
∠ABC ≅ ∠DEF
∠GHI ≅ ∠DEF
∠DEF ≅ ∠ABC (Symmetric property)
∠GHI ≅ ∠ABC (transitive property)
m∠GHI = m∠ABC (definition of ≅ angles)
m∠ABC = m∠GHI ( symmetric property)
Hence
m∠ABC = m∠GHI
Know more about angles,
https://brainly.com/question/11293539
#SPJ2
como se daca el area de un triangulo
The area is the measure of a space delimited by a contour that is called perimeter. In some cases, the term surface or area is often used interchangeably, but the former refers to space, while the latter refers to its measurement. That is, area is the measurement of a surface.
To calculate the area of a triangle:Obtaining the measurements of its sides,
The sides are:
BaseHeightEach of these sides measures a certain amount, for that, which is multiplied.
To calculate the area: multiply the given value of the base by the value of the height, and divide by 2.
For this, the following formula is applied:Area = B * h / 2See more at:https://brainly.com/question/24514946HELP ME PLZ !!! The first one who answers gets brainliest
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Please evaluate the Derivative using the Limit Process. Show all workings.
Answer:
[tex]\displaystyle f'(x)=-\frac{2}{x^{{}^{3}\!/\!{}_{2}}}[/tex]
Step-by-step explanation:
We have the function:
[tex]\displaystyle f(x)=\frac{4}{\sqrt x}[/tex]
And we want to find the derivative using the limit process.
Recall that the definition of a derivative is:
[tex]\displaystyle \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}[/tex]
Therefore, by substitution:
[tex]\displaystyle \lim_{h \to 0}\frac{\dfrac{4}{\sqrt{x+h}}-\dfrac{4}{\sqrt x}}{h}[/tex]
First and foremost, we can move the constant factor outside of the limit:
[tex]\displaystyle =\lim_{h \to 0}\frac{4\left(\dfrac{1}{\sqrt{x+h}}-\dfrac{1}{\sqrt x}\right)}{h}\\ \\=4\lim_{h \to 0}\frac{\dfrac{1}{\sqrt{x+h}}-\dfrac{1}{\sqrt x}}{h}[/tex]
Next, we can multiply everything by (√(x + h)(√x) to eliminate the fractions in the denominator. Therefore:
[tex]\displaystyle =4\lim_{h \to 0}\frac{\dfrac{1}{\sqrt{x+h}}-\dfrac{1}{\sqrt x}}{h}\left(\frac{\sqrt{x+h}\sqrt x}{\sqrt{x+h}\sqrt x}\right)[/tex]
Distribute:
[tex]\displaystyle =4\lim_{h \to 0}\frac{\left({\sqrt{x+h}\sqrt x}\right)\dfrac{1}{\sqrt{x+h}}-(\sqrt{x+h}\sqrt x)\dfrac{1}{\sqrt x}}{h({\sqrt{x+h}\sqrt x})}[/tex]
Distribute and simplify:
[tex]\displaystyle =4 \lim_{h\to 0}\frac{\sqrt x-\sqrt{x+h}}{h(\sqrt{x+h}\sqrt{x}) }[/tex]
Next, we can multiply both sides by the conjugate of the numerator. In other words, multiply by (√x + √(x + h)). Thus:
[tex]\displaystyle = 4\lim_{h\to 0}\frac{\sqrt x-\sqrt{x+h}}{h(\sqrt{x+h}\sqrt{x}) }\left(\frac{\sqrt x +\sqrt{x+h}}{\sqrt x +\sqrt{x+h}\right)}[/tex]
Simplify:
[tex]\displaystyle =4 \lim_{h \to 0} \frac{x-(x+h)}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}\\ \\ \\ =4 \lim_{h \to 0} \frac{x-x-h}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})} \\ \\ \\=4 \lim_{h \to 0} \frac{-h}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}[/tex]
Cancel like terms:
[tex]\displaystyle =4 \lim_{h \to 0} -\frac{1}{(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}[/tex]
Now, we can use direct substitution. Hence:
[tex]\displaystyle \Rightarrow4 \left( -\frac{1}{(\sqrt{x+0}\sqrt x)(\sqrt x+\sqrt{x+0})}\right)[/tex]
Simplify:
[tex]\displaystyle =4\left( -\frac{1}{(\sqrt{x}\sqrt x)(\sqrt x+\sqrt{x})}\right) \\ \\ \\ =4\left( -\frac{1}{(x)(2\sqrt{x})}\right)[/tex]
Multiply:
[tex]\displaystyle =- \frac{4}{2x\sqrt{x}}[/tex]
Reduce and rewrite:
[tex]\displaystyle =-\frac{2}{x(x^{{}^{1}\! / \! {}_{2} \!})}[/tex]
Simplify:
[tex]\displaystyle =-\frac{2}{x^{{}^{3}\!/\!{}_{2}}}[/tex]
Therefore:
[tex]\displaystyle f'(x)=-\frac{2}{x^{{}^{3}\!/\!{}_{2}}}[/tex]
3. ¿Cuál es el valor de x
x3=100
Answer:
do you know the answers???
how you expect me to do this
(3x-2)(2x+4) using the box method of multiplication
Answer:
6x²-8x-8
Step-by-step explanation:
[tex](3x - 2)(2x + 4)[/tex]
[tex]3x \times 2x = 6 {x}^{2} \\ 3x \times 4 = 12x \\ - 2 \times 2x = - 4x \\ - 2 \times 4 = - 8[/tex]
[tex]6 {x}^{2} + 12x - 4x - 8 \\ 6 {x}^{2} + 8x - 8[/tex]
Answer:
(3x-2)(2x+4)
= 6x^2+8x-8
Step-by-step explanation:
I am a two digit prime number I am one less than multiple of 10. If you add 30 to meet you get another prime number. What number am I?
Answer: 29
Step-by-step explanation:
Evaluate the expression the quantity 3 plus 5, multiplied by, the quantity h minus k, divided by 4, when h = 4 and k = 12. A –16 B 8 C 20 D 29
Answer:
A is the correct option.
Step-by-step explanation:
We need to evaluate the expression 3 plus 5, multiplied by, the quantity h minus k, divided by 4, when h = 4 and k = 12. It can be written as :
[tex](3+5)\times \dfrac{h-k}{4}[/tex]
Put h = 4 and k = 12 in above expression.
So,
[tex](3+5)\times \dfrac{h-k}{4}=(3+5)\times \dfrac{4-12}{4}\\\\=8\times \dfrac{-8}{4}\\\\=2\times -8\\\\=-16[/tex]
After solving we get that the value of the given expression is -16.
Please help!! I've been getting them all wrong
Answer:
your welcome it has to be c
Answer:
I honestly dont know
Step-by-step explanation:
Use a calculator for algebra srry if this answer is useless
What is the x-coordinate of the image of point (−2, 6) after a reflection in the -axis?
(2,6) after a reflection in the x axis
(-2,-6) after a reflection in the y axis
Given f(x),=19x+10find f(4).
Mary likes to collect coins. Mary got 24 coins from her brother, 16 coins from her mother as well as
37 coins from Joan. However, Mary lost 23 coins before putting those coins into her piggy bank. How
many coins does Mary have in her piggy bank?
Answer:
53
Step-by-step explanation:
24+16=40 40+37=77 77-24 = 53
**URGENT** what is 2 and 1/3 minus 4/5 written as an improper fraction?
Answer:
23/15
Step-by-step explanation:
Step 1:
2 5/15 - 12/15
Step 2:
35/15 - 12/15
Answer:
23/15
Hope This Helps :)
how to do recurring decimal and fraction
Answer:
What do you mean.....???
ex.....0.444444.......
Remove point.... and Write 9 as denominator
that is 4/9
A manager of a grocery store collects data on each shopper who uses the self-checkout lanes on a Saturday morning. Which of the following is an example of a discrete quantitative variable that might be recorded in this setting?
the gender of each shopper
the shopper’s use of coupons
the number of items for each shopper
the time each shopper spends completing the transaction
Answer:
The correct option is;
The number of items for each shopper
Step-by-step explanation:
Quantitative data are data that are the result of a measurement and are therefore the numerical value assigned as an attribute of an item based on measurement. Examples of quantitative data are, the weights or heights of items, the count of an item and other similar measurable data
Discrete data are data to which are assigned specific unique numerical values
Data that is obtained by counting of a number of items are quantitative discrete data
Therefore, of the options, the one that is a discrete quantitative variable is the number of items for each shopper as it is countable which makes it quantitative and it carries a unique number, which makes it countable.
Answer:
The number of items for each shopper
Step-by-step explanation:
give the other guy brainliest
Solve for t 4/3 = t/7
Answer:
t=28/3
Step-by-step explanation:
Id this helped feel free to send thanks and give brainliest so I can continue to help people around the brainly community.
Amy invested $250 in the bank and a year later has $285.72. By what percent has the amount changed?
Answer:
14.28 %
Step-by-step explanation:
It is given that,
Initial amount is $250 and after 1 year the amount is $285.72. We need to find the percent by which the amount changed. It can be calculated as follows :
[tex]\%=\dfrac{\text{change in amount}}{\text{initial amount}}\times 100\\\\\%=\dfrac{285.72-250}{250}\times 100\\\\\%=14.28\%[/tex]
Hence, there is an increase of 14.28 % in this case.
What percent of 101 is 16.16?
Answer:
16.16 is 16% of 101
Step-by-step explanation:
Hope this helps!
Dori bought a sandwich for $6.75, a bag of dried fruit for $1.45 and a bottle of water for $1.75. She paid the cashier with a $20 bill. How much change did she receive?
Answer:
She would receive $10.05 cents back
Step-by-step explanation:
Add 6.75, 1.45, and 1.75. You would get 9.95. Then, you would subtract $20.00 by $9.95, getting 10.05 as change.
Hope this helps!
Mr. Sloan is purchasing 2.3 pounds of trail mix that costs $6.25 per pound. How much change will Mrs. Sloan receive if she gives the cashier $20. do it on rational numbers
Answer:
5.55
Step-by-step explanation:
The cost of the 3.4 pounds of trail mix is:
STEP 1:
multiply number of pounds purchased by price per pound
= 3.4 pounds * $4.25 per pound
= $14.45 total cost
STEP 2:
subtract total cost of purchase (step 1) from amount she gave cashier ($20.00)
= $20.00 - $14.45
= $5.55 amount received back from cashier
In a cyclic quadrilateral ABCD, if (∠B – ∠D) = 60o , show that the smaller of the two is 60o
ANSWER
It is given that ABCD is a cyclic quadrilateral
(∠B−∠D)=60
o
......(1)
(∠B+∠D)=180
o
.....(2)
By adding both the equations
∠B−∠D+∠B−∠D=60
o
+180
o
So we get
2∠B=240
o
By division
∠B=120
o
By substituting equation it in equation (1)
(∠B−∠D)=60
o
120
o
−∠D=60
o
On further calculation
∠D=120
o
−60
o
by subtraction
∠D=60
o
Therefore, the smaller of the two angles ∠D=60
o
.
Step-by-step explanation:
A large rectangle has length a + b and width c + d. Therefore, its area is (a + b)(c + d).
Find the area of each of the four small rectangles in the figure. Then find the sum of these areas.
The area of each of the small rectangles is __?
Answer:
The area of four small rectangles are ac, bc, ad and bd.
To rule How to find f(7) ?
11. Mis the midpoint of QR. Q is at (-8, 2) and M is at (4, -3). Find the coordinates of the endpoint R.
Answer:
R(16,-8)
Step-by-step explanation:
if (x1,y1) and (x2,y2) are coordinates of two points and (x,y) the coordinate of midpoint.
then x=(x1+x2)/2
and y=(y1+y2)/2
let coordinates of R are (x,y)
4=(-8+x)/2
8=-8+x
x=8+8=16
-3=(2+y)/2
-6=2+y
y=-6-2=-8
so R is (16,-8)