construct a simulated h1 nmr spectrum, including proton integrations, for ch3chcl2 . drag the appropriate splitting patterns to the approximate chemical shift positions; place the integration values in the small bins above the associated chemical shift. splitting patterns and integrations may be used more than once, or not at all, as needed. likewise, some bins might remain blank. note that peak heights are arbitrary and do not indicate proton integrations.

Answers

Answer 1

The 1H NMR spectrum for the given compound is shown below.

The chemical shift is equal to 10 to 1/6 the observed TMS shift in Hertz divided by the spectrometer frequency. It is observed in alkenes where the double bond is oriented perpendicular to the external field and the pi electrons are also orbiting perpendicularly.

The induced magnetic field lines are parallel to the external magnetic field at the sites of the alkene protons and thus shift in the range of 4.5 ppm to 7.5 ppm. Exact chemical shift values ​​depend on molecular structure and solvent temperature magnetic field in which the spectrum is recorded, and other neighboring functional groups.

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Construct A Simulated H1 Nmr Spectrum, Including Proton Integrations, For Ch3chcl2 . Drag The Appropriate

Related Questions

4. The pressure of a gas in a rigid container is halved when the Kelvin temperature changed.
Which of the following temperature change could be responsible for this?
A. 400 K to 800 K
B. 200 K to 300 K
C. 600 K to 300 K
D. 800 K to 200 K

Answers

Answer: D: 800 K to 200 K.

Explanation:

The pressure of a gas is directly proportional to its temperature on the Kelvin scale. This means that if the temperature of a gas increases, the pressure of the gas will also increase, and if the temperature decreases, the pressure will also decrease.

If the pressure of a gas in a rigid container is halved when the temperature changes, this means that the temperature must have decreased by a factor of 2.

Looking at the options provided, the only temperature change that could be responsible for halving the pressure is:

D. 800 K to 200 K

The temperature decreased by a factor of 4 (800 K / 200 K = 4), which is more than the factor of 2 needed to halve the pressure.

From what carboxylic acid derivative can urea most easily be prepared?carbonic acid, formyl chloride, phosgene, carbamic acid, or diurea

Answers

From Phosgene, the carboxylic acid derivative can urea most easily be prepared.

Phosgene is the organic chemical compound with the formula COCl2. It is the carboxylic acid derivative. It is a toxic, colorless gas. in low concentrations, its musty odor resembles that of freshly cut hay or grass. Phosgene is a valued and important industrial building block for the production of precursors of polyurethanes and polycarbonate plastics. Phosgene is extremely poisonous. It was a highly potent pulmonary irritant and quickly filled enemy trenches due to it being a heavy gas. It is a colorless gas with a suffocating odor like musty hay. Exposure to phosgene may cause irritation to the eyes, dry burning throat, vomiting, cough, foamy sputum, breathing difficulty, and chest pain.

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which of the following logic families has static power dissipation? static cmos logic dynamic logic pseudo nmos logic clocked cmos logic

Answers

The correct option is B. dynamic logic , The following factors are crucial for assessing and contrasting logic families: The supplied power necessary to run the specified logic function is referred to as power dissipation.

The power delivered from another gate is not included in this parameter. Some of these logic families employ static methods to reduce the complexity of the design. Clocked dynamic approaches are used by other logic families, such domino logic, to reduce size, power usage, and delay. Various solid-state and vacuum tube logic systems were employed for logic circuitry activities prior to the widespread introduction of integrated circuits.

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Choose the most appropriate reagent(s) for conversion of the cyclohexene intermediate (which comes from the Diels-Alder reaction) to the target molecule
A. CH3Br
B. CH3OH, H+ C.1.2 equiy CH,MgBr, ether 2. H2)
D NaOCH2
E. (CH3)2CuLi

Answers

Option (b). For the conversion of the Cyclohexene the intermediate used is treated with an acid. It undergo dehydration reaction.

According to Diels-Alder reaction, it forms a cyclohexene ring. The process by which the reaction occurs is by cycloaddition. This means that the electrons are transferred in a cyclic fashion between the diene and the alkene to for the cyclic structure.  the alkene that reacts with the diene is commonly referred to as the dienophile. This reaction tends to work best with dienes that are electron rich and dienophiles that are electron poor.

Common method of making cyclohexene is by taking cyclohexanol, cyclohexane with an −OH group attached to it and treating it with an acid of some sort. When cyclohexanol is reacted with an acid it undergoes a reaction called a dehydration reaction, which means it loses a water molecule.

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A reaction at 23.0 Degree C evolves 419. mmol of boron trifluoride gas. Calculate the volume of boron trifluoride gas that is collected. You can assume the pressure in the room is exactly 1 atm . Be sure your answer has the correct number of significant digits.

Answers

The volume of boron trifluoride gas that is collected during this experiment is  approximately 8.27 L.

To calculate the volume of boron trifluoride gas that is collected, you can use the ideal gas law: PV = nRT Where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the ideal gas constant, and T is the temperature of the gas in kelvins. You know the pressure of the gas (1 atm), the number of moles of the gas (419. mmol), and the temperature of the gas (23.0 degrees C). You can use the ideal gas constant R = 8.314 J/mol*K to convert the temperature to kelvins. Plugging in the values, you get: V = (419. mmol * 8.314 J/mol*K * (23.0 + 273.15 K)) / (1 atm) Solving for V, you get: V = 8.27 L.

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Gold occurs in a sample of sea water at a concentration of 1.1 × 10—2 ppb. How many litres of sea water must be processed to recover 31.1 g of gold? (Density of sea water = 1.025g/mL.)

Answers

The volume in liters of seawater that must be processed to recover 31.1 g of gold is 2.827 * 10⁶ Liters of seawater.

What is the concentration of gold found in the seawater sample?

The concentration of gold found in the seawater sample is given as 1.1 × 10⁻² ppb.

1 ppb is equivalent to 1 μg/mL

Based on the above conversion, 1.1 × 10⁻² ppb =  1.1 × 10⁻² μg/mL

This means that 1 mL of the seawater sample contains 1.1 × 10⁻² μg of gold.

1.1 × 10⁻² μg = 1.1 × 10⁻² μg * 10⁻⁶ g/μg

1.1 × 10⁻² μg = 1.1 × 10⁻⁸ g of gold

The volume of seawater in liters that will produce 31.1 g of gold is calculated below as follows:

The volume of seawater required = 31.1 g * 1 mL/1.1 × 10⁻⁸ g * 1 L/1000 mL

The volume of seawater required = 2.827 * 10⁶ Liters of seawater.

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given 1 in=2.54cm how many centimeters are in an average hand (9.50)?

Answers

If an average hand is 9.50 inches, the number of centimeters in an average hand would be 24.035 centimeters.

Unit conversion

The problem here is about converting from one unit to another.

We have been given that: 1 in = 2.54 cm

We were also given that an average hand measured 9.50 inches long. The average length of hand would be the sum of the length of all the hands in the population and the total number of hands whose lengths were measured.

Thus:

If 1 in = 2.53 cm

  9.50 in = 9.50 x 2.53

              = 24.035 cm

Thus, if 9.50 inches is 24.035 centimeters, it means an average hand will also be 24.035 centimeters long.

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module 16 exam 4 fos3042 carbonated beverages are infused with nitrogen gas carbon dioxide gas oxygen gas carbon monoxide gas

Answers

What is water gas?

Water gas may be a quite fuel gas, a mix of monoxide and hydrogen. it's created by "alternately hot processing a fuel layer [coke] with air and gasifying it with steam". The caloric yield of this can be concerning 10% of a contemporary syngas plant.

Water gas is a synthesis gas, containing carbon monoxide and hydrogen. it's a helpful product however needs careful handling thanks to its flammability and therefore the risk of carbon monoxide poisoning.

Producer gas: a gas composed of carbon monoxide, hydrogen, and nitrogen, obtained by passing air and steam through incandescent coke.

Syngas/synthesis gas, is a fuel gas mixture consisting primarily of hydrogen, carbon monoxide, and extremely usually some carbon dioxide.

Hence final answer is  Marsh gas  paraffin CH4

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True or False: the national fire protection association (nfpa) 704 diamond is a visual clue to the presence of hazardous materials.

Answers

True, the national fire protection association (nfpa) 704 diamond is a visual clue to the presence of hazardous materials.

The NFPA 704 Diamond, also known as the NFPA Hazard Diamond, is a system for identifying the specific hazards of a material as well as the intensity of the potential danger that'd occur when in an emergency service. The National Fire Protection Association (NFPA) is a worldwide self-funded organization that was established in 1896 that is devoted to preventing accidents, harm, damage to property, and financial damage resulting from fire, electronics, and other obstacles. Fire protection involves the formulation and construction of structural and functional systems to lessen the effects of fire on persons and property. Fire-protection systems are classified into two types: passive and active fire protection and active fire protection.

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Equal volumes of a 0.020 M Zn^2+ solution and a 2.0 M NH3 solution are mixed. Kf for [Zn(NH3)4]^2+ is 4.1 × 10^8. If enough sodium oxalate is added to make the solution 0.10 M in oxalate, will ZnC2O4 precipitate? What is Q? Ksp ZnC2O4 = 2.7 × 10^-8 Answer: no, Q = 2.9 × 10^-12

Answers

Q = 2.5*1012 if sufficient sodium oxalate is modified to make the fluid 0.10 M in oxalate.

What is the purpose of sodium oxalate?

In the majority of naturally occurring metabolic processes within plants and vegetables, sodium oxalate is often used as a reducing agent. It is also frequently used as a principal standard for the standard of ammonium hydroxide solutions.

How safe is sodium oxalate?

When in touch with skin, harmful. Effects/symptoms upon skin contact: Repeated contact to this substance can cause serious health risks from skin absorption. When in touch with skin, harmful. Symptoms/results following eye contact: seriously irritates the eyes.

Briefing:

M₁V₁ = M₂V₂

M₁ * V = M₂*2V

M₂ = M₁*V/2V

M₂ = M₁/2

Zn²⁺ = 0.020M/2

= 0.010M

Molarity of NH₃= 2.0M/2

NH₃ = 1.0M

Q = 2.5*10⁻¹¹M * 0.10M

Q = 2.5*10⁻¹²

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In all of your lab work this semester, you routinely used glassware to measure volumes of liquids. It was important to record volumes with proper number of significant digits and this depended on the type of glass container used. Looking at the picture below, what is the volume of water in the graduate cylinder? 64.0 mL 63 mL 56 mL O 56.0 mL 64 mL

Answers

The colorless solution lower meniscus is 56 ml option (c) is correct.

What is volume ?

A solid shape's capacity is measured using volume, a three-dimensional quantity. It implies that a closed figure's volume determines how much three-dimensional space it may fill.

What is liquids ?

A liquid is a form of substance that has unique characteristics that make it more rigid than a gas but less stiff than a solid. Like a solid, a liquid may flow and lacks a fixed form. A liquid, on the other hand, takes the shape of the container it is kept in.

Therefore, the colorless solution lower meniscus is 56 ml option (c) is correct.

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highly efficient two-step synthesis of 2,5-furandicarboxylic acid from fructose without 5-hydroxymethylfurfural (hmf) separation: in situ oxidation of hmf in alkaline aqueous h2o/dmso mixed solvent under mild conditions 30 october 2018

Answers

Time evolution of HMF conversion and yields of FDCA, FFCA, and HMFCA; comparison of conversion and yields; typical HPLC spectra of reaction mixture; 1H NMR spectrum of FDCA product;

The effective synthesis of 2,5-furandicarboxylic acid (FDCA), a promising biobased aromatic monomer that can be exploited to create innovative biobased polymeric materials, is still a significant problem. The direct synthesis of FDCA from fructose without the need for 5-hydroxymethylfurfural (HMF) separation is proposed in this work as a two-step process employing catalysts that are readily accessible in the market. By dehydrating fructose in DMSO for one hour at 120 °C under the catalysis of Amberlyst-15, HMF was produced in the first stage with a 97.1% HPLC yield. The second stage involved oxidizing the in-situ created HMF in a 3/1 (w/w) alkaline (K2CO3) H2O/DMSO medium for 10 hours at 100 °C with Pt/C as the catalyst to produce FDCA in a 91% HPLC yield. A total of 88.4% of fructose was converted into FDCA overall.

HMF is quickly converted to 5-hydroxymethyl-2-furancarboxylic acid (HMFCA) and 5-formyl-2-furancarboxylic acid (HMFCA) respectively, however the rate-limiting step in the oxidation of HMF is the conversion of FFCA to FDCA. Important variables influencing the reaction rate and selectivity include the H2O/DMSO ratio, alkali type, alkali/HMF ratio, and reaction temperature. High FDCA yield is achieved by DMSO and alkaline aqueous solution working in harmony.

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How might data for this experiment be organized to help look for
patterns?

Answers

Answer:

5g5

Explanation:

reder

if an antacid tablet weighed 1.6 grams, how many moles of gastric acid (hci) would it neutralize? use the results obtained in data tables 1 and 2 to explain and quantify your answer.

Answers

The 0.015 moles of gastric acid will be neutralized by a 1.6 gram antacid pill.

By inhibiting the enzyme that produces acid in the stomach to break down food for digestion, antacids neutralize the gastric acid there. An enzyme called pepsin, which breaks down proteins, is inhibited by the antacids, which work by neutralizing the stomach's pH.

0.342 grams of HCL are neutralized every gram of antacid.

Based on the titration's equivalence point expression, this is calculated.

1.6 gram HCL neutralized antacid is,

(0.342 grams HCL to 1 grams antacid) A 1.6 gram antacid

= 0.5472 gram

HCL has a 36.5 gram molar mass.

Moles of HCL = 0.5472 g/36.51 g = 0.01499

As a result, HCL has a mole of 0.015 moles of gastric acid (hci) would it neutralize

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Aqueous solutions of the following reactants are mixed. Calculate the concentration in mol/L) of calcium ions in solution after the reaction has gone to completion. 75.0 mL of 1.50 M AgNO, are mixed with 75.0 mL of 2.1 M Cacly DO NOT include units in your answer. If you round during your calculation, be sure to keep at least four (4) decimal places. Report your answer to two (2) decimal places. Answer: Calculate the mass of precipitate formed (in grams) when aqueous solutions of the following reactants are mixed. Assume that the reaction goes to completion. 79 mL of 1.50 M AgNO3 are mixed with 75.0 mL of 1.00 M CaCl, Do NOT include units in your answer. If you round during your calculation, be sure to keep at least four (4) decimal places. Report your answer to two (2) decimal places. Answer:

Answers

The concentration (in mol/L) of calcium ions in solution after the reaction has gone to completion. 75.0 mL of 1.50 M AgNO, are mixed with 75.0 mL of 2.1 M is 0.75 mol / L.

The reaction is given as :

2AgNO₃(aq)    +   CaCl₂(aq)   ----->   Ca(NO₃)₂(aq)    +   2AgCl(s)

moles of AgNO₃ = molarity × volume

                            = 1.50 × 0.075

                            = 0.1125 mol

moles of  CaCl₂ = 2.1  × 0.075

                           = 0.1575 mol

AgNO₃ is a limiting reactant ,2mole of AgNO₃ produces 1 mole of Ca(NO₃)₂

moles of Ca(NO₃)₂ = 0.1125 / 2 = 0.05625 mol

concentration of Calcium ion is = 0.05625  / 0.075

                                                    = 0.75 mol/ L

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the carotenoid with the most vitamin a activity is . beta-carotene alpha-carotene beta-cryptoxanthin lycopene

Answers

Carotenoids are a group of plant-made pigments that include yellow, orange, and red hues. [tex]\alpha[/tex]-carotene, [tex]\beta[/tex]-carotene, [tex]\beta[/tex]-cryptoxanthin, lutein, zeaxanthin, and lycopene are the most common carotenoids in the diets of North Americans.

Beta-carotene, zeaxanthin, and lycopene are all provitamin A carotenoids that can be converted to retinol in the body (vitamin A). Contrarily, lutein, zeaxanthin, and lycopene do not contribute to vitamin A activity.

The eyes selectively absorb the carotenoid antioxidants lutein and zeaxanthin from the diet, where they absorb up to 90% of blue light and aid in the preservation of healthy eye function in the macula. For the time being, it is unknown if the biological benefits of carotenoids in humans are connected to their antioxidant activity or any other activity than antioxidant activity.

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5. The volcanic eruption of Mt. St. Helens in the state of Washington in 1980
produced a considerable quantity of a radioactive element in a gaseous
state. Atoms in the radioactive substance had 86 protons. Which was it?

Rubidium
Bromine
Polonium
Radon

Answers

Answer:Polonium

Explanation:

which one of the following molecules would have the largest bond dissociation energy if all bonds in the molecule are broken?

Answers

N2 has a largest bond dissociation energy. because as nitrogen has triple bond.

The bond energy can be visualized as the average amount of energy required or produced when a bond in a chemical compound is broken or formed.

when the bond in a chemical compound is broken, then there is a need for energy hence the bond energy will have a positive value. and when the bond in a chemical compound is formed, then the energy will be released  hence the bond energy will have a negative value. bond energy gives an idea of strength of a chemical bond and therefore the stability of the compound. hence the more stable the compound, the more energy will be needed to break the bond.

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Which statement best explains an atomic emission spectrum?
4
As electrons transition between different energy levels within a wavelength, they make their own
unique spectrum of visible light.
As electrons transition between different energy levels within an atom, they release or absorb energy.
The released energy forms a spectrum of electromagnetic energy specific to each element.
As wavelengths transition between different transmittance levels within an atom, the visible colors
show on a scale.
As electrons transition between different energy levels within a frequency, they make their own unique
spectrum of visible color.

Answers

An atomic emission spectrum is best described as an electronic transition between different energy levels within an atom, thereby releasing or absorbing energy.

What is an emission spectrum?

Emission spectrum is defined as a spectrum of a chemical compound or substance composed of frequencies of electromagnetic radiation. Radiations which are emitted while electron make transition from higher to lower energy level.

Energy of photon is equal to the difference between the two energy states . There are many possible electronic transitions in an atom and every transition has a specific wavelength.

Collection of different transitions with respect to different wavelengths makes up an emission spectrum.Emission spectrum of each element is unique and therefore spectroscopy is used to identify elements which are present in different substances.

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Which statements best describe the first stage of cellular respiration? Select three options.

Answers

The statement which best describes the first stage of cellular respiration is the break down of glucose. That is the glycolysis thus, d is correct.

What is cellular respiration?

Individual cells use cellular respiration to break down food molecules like glucose and release energy. The process is similar to burning, but it does not produce as much light or heat as a campfire.

This is due to the fact that cellular respiration slowly releases the energy in glucose in many small steps. It converts the released energy into molecules of ATP, the energy-carrying molecules that cells use to power biochemical processes.

The first stage in cellular respiration is the break down of glucose called glycolysis. Hence, option d is correct.

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Your complete question is as follows:

Which statements best describe the first stage of cellular respiration? Select three options.

the stage happens in cytoplasm [ ]

The stage happens in mitochondria

Oxygen combines with small molecules[ ]

Glucose is broken down

Energy is released

Amino acids can be either polar or= non-polar based on their Choose_. In general, amino acids are non-polar if Choose peptide bonds referred to as Fent: Such amino aci Choose. R groups amide groups Other amino acids are polar and are generally referred to as Choose _. checK

Answers

The answers of the blanks are :

In the first- R group

In the second - only carbon and hydrogen

In the third - Hydrophobic

In the fourth - Hydrophilic

non polar is hydrophobic

polar is hydrophilic

Non-polar depends on the hydrocarbon

Amino acids are the molecules which combine together to form proteins.

the classification of Amino acids based on R group is

of two types

Polar and Non-polar

Non-polar  amino acids are mostly hydrocarbons

Polar amino acids are of 3 types

Acidic basic neither acidic nor basic

Acidic amino acids are Carboxyl groups and amino groups (-COOH)

(-NH2)

Basic amino acids some examples are Arginine(Arg) , Lysine (lys)

Neither acidic nor basic are

Amide , alcohol cysteine

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Question
03/20
When cleaning a food preparation area, how can you protect the food
from the cleaning products?

Answers

Answer:

lots of answers

Explanation:

so basically cook in an different area

or use the cleaning products carefully, don't spray onto food, be mindful

wash your hands personal hygiene is key

don't cough on food wear gloves for hands if possible

Answer:

Explanation:

dont cook near the cleaning products, wash the stuff you use really good before you start to cook

dont clean with products only with water until your dont with cooking

Problems:
Show all three steps of using a formula - show the formula, fill in the formula, 8 solve for the answer.
22) Calculate the energy of a photon of radiation with a frequency of 9.50 x 10¹³ Hz.

HINT:
You can make the formula parts larger by dragging them to the size that you prefer. DELETE THIS BOX AFTER READING!
HINT:
To make a superscript, cntrl / cmmd. (period)

Answers

The energy of a photon of radiation with a frequency of 9.50 × 10¹³ Hz is 6.3 × 10⁻²⁰ J.

The Energy that comes from electromagnetic radiation is quantized, It exists in the form of small energy packets known as photons. The energy of a photon is dependent on the frequency at which it is propagating from the source of radiation.

The energy of a photon is given by the equation:

E = hν

here, E is the energy of photon

h is Plancks's constant whose value is 6.626 × 10⁻³⁴ Js

ν is the frequency

According to the question,

given, frequency ν = 9.50 × 10¹³ Hz

therefore,

E = 6.626 × 10⁻³⁴ Js ×  9.50 × 10¹³ Hz      (1 Hz = 1s⁻¹)

E = 6.2947 × 10⁻²⁰ J

E≈ 6.3 × 10⁻²⁰ J

Thus, energy of the photon is 6.3 × 10⁻²⁰ J

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1) Write the balanced equation and draw the particulate representation of the following chemical reaction: Sodium metal reacts with chlorine gas to produce sodium chloride 2) Draw the complete decomposition of 4 molecules of hydrogen peroxide (H20.) into water and oxygen gas.

Answers

The balanced chemical equations for the given chemical reactions are given serially i) 2 Na+Cl₂ 2 NaCl  ii) 4 H₂O₂ 4 H₂O + 2 O₂  iii)CH₄ +2 O₂CO₂ +2 H₂O

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

The first chemical equation was put forth by Jean Beguine in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.

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Myristic acid (CH3(CH2)2COOH) can be converted to several different derivatives using standard organic chemistry reactions. Select the best reagents to transform Myristic acid to the derivatives below.

Answers

These are the Myristic acid converted reactions are mentioned below.

What is Myristic acid ?

Myristic acid is a saturated long-chain fatty acid with a 14-carbon carbon backbone. Myristic acid is a substance that naturally exists in butter fat, coconut oil, and palm oil. Gladiolus italicus, Staphisagria macrosperma, and other species for which there is information contain myristic acid, which is a naturally occurring chemical.

What is reactions ?

In a chemical reaction, one or more chemicals, also known as reactants, are transformed into one or more additional substances, also known as products. Substances are composed of chemical components or chemical ingredients.

1) O= OH ⇒ Ammonia ⇒ So₂, O= NH₂

O= Cl₂

2)O= OH ⇒ Br₂ cat. P Br₃/ H₃o⁺²/ H₂o ⇒ LiaH₄ o= Br

O= OH

Therefore, these are the Myristic acid converted reactions .

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the reaction between an amine and carboxylic acid produces a peptide bond. identify the functional group produced in the formation of this bond.

Answers

The functional group produced in the formation of peptide bond is amide group [tex]CO-NH[/tex].

What is a peptide bond?

Two amino acids form a chemical bond known as a peptide bond. It is created when an amino acid's carboxyl group reacts with another amino acid's amino group, losing one molecule of water in the process [tex](H_{2}O)[/tex]. Peptide bond synthesis or formation is the term used to describe this process.

According to the problem:

The reaction between an amine group [tex](NH_{2} )[/tex] and a carboxyl group [tex](COOH)[/tex] to form a peptide bond involves the loss of a molecule of water [tex](H_{2}O)[/tex]. This following equation can represent the process:

[tex]NH_{2} + COOH + H_{2}O \rightarrow C-O-O-C[/tex]

A covalent bond between the two amino acids is created in this reaction when the carboxyl group of one amino acid accepts the hydrogen atom that belongs to its amine group. Peptide bonds are the resultant bonds.

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e sure to answer all parts. classify the solid state of the following substances as ionic crystals, covalent crystals, molecular crystals, or metallic crystals. ionic: covalent: molecular: metallic: co2 i2 s8 kbr mg sio2 licl cr co2 i2 s8 kbr mg sio2 licl cr co2 i2 s8 kbr mg sio2 licl cr co2 i2 s8 kbr mg sio2 licl cr

Answers

In the solid state, there are four types of crystals that can exist: 1. Ionic crystals - In this type of crystal, an ionic crystals is used to bond two atoms, which connects two oppositely charged atoms, i.e., cation and anion. KBr (d) and LiCl (g). 2. ionic crystals.

Weak intermolecular forces, similar to dispersion forces, hold atoms together, resulting in a molecular crystal. 4th. Ionic crystal, the metal cation with delocalized electrons is the type of bond that makes up a metallic crystal. Crystalline solids have long-range order and a definite geometric shape. These solids are isotropic and lack a distinct heat of fusion. Quartz and sodium chloride are examples of crystalline solids. True solids are another name for crystalline solids.

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alculate ph of: a pure buffer; a buffer to which a small amount of a strong acid or a strong base is added an aqueous solution of a strong acid or base an aqueous solution of a weak acid or base

Answers

This causes a very slight reduction in the pH of the buffer solution . After one weak acid has been applied, a "ICE" chart can be used to determine the system's pH level.

Example, what is buffer solution?

Strong acids or bases applied in modest amounts don't cause buffer solutions to shift pH. An illustration of a buffer made up of an acidic solution and its salt is a chemical compound with the formula and oxalic acid CH3COOH + CH3COONa.

purpose of using a buffer solution?

In acid-base chemistry, a buffer is a very helpful solution. The pH can occasionally vary rapidly and significantly when solutions combine with only a strong base or an acid. The pH can alter more gradually by neutralizing part of the additional acid or base with a buffer solution.

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An unknown metal nitrate with the formula M(NO3), was dissolved in water and treated with excess aqueous sodium sulfate. The total amount of sulfate salt produced in this reaction had a mass of 8.159 g. The initial mass of the metal nitrate sample was 9.835 g. Assuming that the reaction goes to completion, determine the number of moles of the sulfate salt produced. DO NOT include units in your answer. If you round during your calculation, be sure to keep at least three (3) decimal places Do NOT use scientific notation in your answer. Report your answer to three (3) decimal places

Answers

The moles of metal sulphate formed in the given reaction is 0.0598.

The reaction of metal nitrate M(NO3)2 with sodium sulphate Na2SO4 can be written as

M(NO3)2 + Na2SO4 → 2 NaNO3 + MSO4

1 mole of metal nitrate produces 1 mole of metal sulphate.

let molar mass of metal M be 'a' g/mol.

molar mass of M(NO3)2 = a+ 14 × 2 + 16×6 = 124+a

moles of M(NO3)2 reacted = 9.835 / (124+a)

molar mass of MSO4 = a+ 32 + 16×4 = 96+a

moles of MSO4 formed = 8.159 / (96+a)  

Since 1 mole of metal nitrate produces 1 mole of metal sulphate thus moles of M(NO3)2 reacted and moles of MSO4 formed should be equal.

⇒ 9.835 / (124+a) = 8.159 / (96+a)

⇒ 9.835 × (96+a)  = 8.159× (124+a)

⇒ 944.16 + 9.835a = 1011.716 + 8.159a

⇒ 9.835a - 8.159a = 1011.716 - 944.16

⇒ 1.676a = 67.556

⇒ a = 40.3g/mol

Molar mass of unknown metal M is 40.3g/mol.

moles of MSO4 formed = 8.159 / (96+a)  

putting the value of 'a' we get

moles of MSO4 formed = 8.159 / (96+40.3) = 0.0598

Thus moles of metal sulphate formed in the given reaction is 0.0598.

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For 16-23, identify the atomic model that matches the description below. Some letters may be used more than once
A. Dalton's atomic model
B. Thomson's atomic model
C. Rutherford's atomic model
D. Bohr atomic model
E. Quantum mechanical model
16. In this model, you can only describe the most probable location of an electron.
17. This model describes the atom as indivisible and indestructible.
18. This model was the first to propose that an atom is mostly empty space.
19. This model describes an atom as a positive sphere on which electrons are embedded.
pls help

Answers

Answer:

16. Quantum Mechanical Model

17. Dalton's Atomic Model

18. Rutherford's Atomic Model

19. Thomson's Atomic Model

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