The centre of mass of the right rod has a final translational velocity of MWo2/12. The right rod's final angle of rotation about its centre is ML2/12.
Ordinary velocity, expressed in metres per second, is what translational velocity is. Tangential velocity is the part of ordinary (translational) velocity that is in the tangential direction. For instance, if a rigid body is rotating about a fixed axis at an angular velocity of radians per second, any point r metres away from the axis will have a purely tangential velocity of r metres per second. The speed at which the angular location or orientation of an item varies is represented by a pseudovector in physics as angular velocity or rotational velocity ( or ), also called an angular frequency vector.
Iz = Ix+Iy
Ix = iy
Iz = 2Ix
(ML^2/6)/2 = ML^2/12
the final angular velocity of the right rod around its center is ML^2/12.
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a) calculate i) the gain (vout/vin) of the op-amp (without c1), and ii) the gain (vout/vin) of the op-amp with c1 paralleled with r2. include your calculation in the report.
The negative sine is because current flows from input to output, but as in current flows from output to input is - 10 V/V.
Calculation:-
1. V in - 0 / 10 = - 10v/V
Therefore Vout / V in = - 10 V/V
2. V in - 0 / 10 = - 10v/V + 0 - V out / 20 sn
therefore V out / V in = - 1/ 0.1 + 200 ns.
Note that for practical signal scaling, an inverting amplifier can have a gain of less than 1, while a non-inverting amplifier must have a gain of at least 1. you'll need to power the op-amp with V+ and V- to have enough range to comfortably accommodate the expected signal output.
The formula for the output voltage Vout also shows that the circuit is linear for the fixed gain of the amplifier since Vout = Vin x gain. This property is very useful for converting small sensor signals into larger voltages.
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Describe the trends in the U.S. energy demands and the amount of this energy generated from nuclear power since 1970. Include in your answer any relationships that may exist between them. Consider data provided above and possibly extra research. As you make your claim ALWAYS use evidence to support your response.
The overall energy consumption in the United States has nearly tripled since 1970, and electricity consumption has grown even faster.
How is the energy consumption?The U.S. economy is heavily dependent on energy for everything from manufacturing and transportation to agriculture and housing. Power sources and uses are constantly changing.
A total of 98 quadrillion BTUs of energy were consumed in the United States in 2010, according to estimates. This is a little less than its peak in 2007, but nearly three times higher than its level in 1950 (34.6 quadrillion BTUs).
The average American uses 2.5 gallons of oil, 8.86 pounds of coal, and 246 cubic feet of natural gas per day. Each person in a household uses 12 kilowatt-hours (kWh) of electricity per day. The overall U.S. energy consumption dropped 3.1% from peak levels in 2019 in 2021.
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13. A child throws a 6.9 kg package horizontally from a boat with a speed of 10.0 m/s. Calculate the resulting recoil velocity of the boat if assuming it was initially at rest. The mass of the child is 25 kg and that of the boat is 55 kg. (.863m/s)
Answer:
0.863 m/s
Explanation:
This is a conservation of momentum problem.
Momentum = p = mv
(6.9 kg)(10 m/s) = (25 kg + 55 Kg)(v)
69 kg·m/s = (80 kg)v
v = (69 kg·m/s)/(80 kg) = 0.863 m/s
A very long insulating cylinder of charge of radius2.40 cm carries a uniform linear density of 13.0 nC/m.
If you put one probe of a voltmeter at the surface, how far fromthe surface must the other probe be placed so that the voltmeterreads 200 V?
The distance at which the probe should be placed so that the voltmeter reads 200 V is equal to 0.216 cm.
To find the distance at which the voltmeter reads 200 V, we need to use the equation for the electric potential at a point due to a continuous distribution of charge:
V = k * ∫λ(r')/r' dr'
where V is the electric potential at a distance r from the center of the cylinder, k is the Coulomb constant (8.99 x 10^9 N*m^2/C^2), λ is the linear charge density (13.0 nC/m in this case), and r' is a dummy variable of integration.
To find the electric potential at a distance r from the surface of the cylinder, we can split the integral into two parts: one from the surface of the cylinder (r') to the point where the probe is placed (r), and one from r to the center of the cylinder (which will be a negative value since the charge density is negative):
V = k * [∫λ(r')/r' dr' from r'=r to r'=2.4 cm] + k * [∫λ(r')/r' dr' from r'=2.4 cm to r'=0]
The first term on the right hand side represents the potential at the point where the probe is placed, and the second term represents the potential at the surface of the cylinder. We are given that the potential at the surface is 200 V, so we can set the equation equal to 200 V and solve for r:
200 V = k * [∫λ(r')/r' dr' from r'=r to r'=2.4 cm] + k * [∫λ(r')/r' dr' from r'=2.4 cm to r'=0]
To solve this equation, we need to evaluate the integrals on the right hand side. The first integral is easy to evaluate:
∫λ(r')/r' dr' from r'=r to r'=2.4 cm = λ * ln(2.4 cm/r)
The second integral is a little more tricky, but we can use the fact that the charge density is uniform to simplify it:
∫λ(r')/r' dr' from r'=2.4 cm to r'=0 = λ * ∫1/r' dr' from r'=2.4 cm to r'=0
= λ * [ln(r')] from r'=2.4 cm to r'=0
= λ * [-ln(2.4 cm)]
Substituting these values back into the original equation and solving for r, we find that the distance at which the voltmeter reads 200 V is:
r = 2.4 cm * exp(-200 V / (k * λ))
r = 0.216 cm
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during a solar eclipse, the moon, earth, and sun all lie on the same line, with the moon between the earth and the sun.
The negative sign means the Moon is being pulled by the Sun more than it is being pulled by the Earth. Net force on Moon is -2.237×10^26 N
F = G * (M1 * M2) / R^2
G = 6.67×10^-11 m^3/(kg*s)
M = Mass of object
R = Distance between objects
F = force
Force between Moon and Earth
G * (7.35×10^22 kg * 5.97×10^24 kg) / (3.84×10^5 km)^2 = 1.98×10^26 N
Force between Moon and Sun
G * (7.35×10^22 kg * 1.99×10^30 kg) / (1.50×10^8 km - 3.84×10^5 km)^2 = 4.36×10^26 N
Net force on Moon
1.98×10^26 N - 4.36×10^26 N = -2.237×10^26 N
The negative sign means the Moon is being pulled by the Sun more than it is being pulled by the Earth.
Only the Moon orbits Earth naturally. With a diameter around one-fourth that of Earth, it is the largest and most massive satellite in relation to its home planet and the fifth largest satellite in the Solar System overall[f] (comparable to the width of Australia). [16] According to geophysical definitions of the term, the Moon qualifies as a satellite planet and is larger than other known dwarf planets of the Solar System because it is a planetary-mass object with a differentiated rocky body. [17] It has no major magnetic field, atmosphere, or hydrosphere. The only satellite in the Solar System known to have a higher surface gravity and density is Jupiter's moon Io, which has a gravity and density around one-sixth that of Earth (0.1654 g).
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Of the first exoplanets found, most were detected by:
A) noting the drop in the star's light as the planet transits its disk.
B) imaging them with the HST in the infrared, where they are easier to stop.
C) noting the Doppler shifts of the star as the planet orbits it from side to side.
D) receiving radio transmissions from them, much like Jupiter emits.
E) detecting the oxygen in their atmospheres spectroscopically.
Of the first exoplanets found, most were detected by: C) noting the Doppler shifts of the star as the planet orbits it from side to side.
The first exoplanets were found in what way?Instead, the first extraterrestrial planets were found by tracking the star's movement. It's a tiny white lie that kids are taught that planets rotate around the sun. In fact, the entire solar system's mass center revolves around the sun and the planets.
What and when was the first planet discovered?Uranus was the first planet to be found by the use of a telescope; it was identified as a planet in 1781 as a result of observations made using a telescope by Sir William Hershel (UK) and others. On March 13, 1781, Sir William Herschel performed the observations that proved Uranus was not a typical star.
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Monochromatic light from a distant source is incident on a slit 0.750 mm wide. On a screen 2.00m away, the distance from the central maximum of the diffraction pattern to the first minimum is measured to be 1.35mm
Calculate the wavelength of the light (answer in nm)
The wavelength of the light if a monochromatic light from a distant source is incident on a slit 0.750 mm wide. On a screen 2.00m away, the distance from the central maximum of the diffraction pattern to the first minimum is measured to be 1.35mm is 506.25 nm
When a wave is bent by an obstruction whose dimensions are close to the wavelength, diffraction is noticed. We can disregard the effects of extremes because the Fraunhofer diffraction is the simplest scenario and the impediment is a long, narrow slit.
This is a simple situation where the Fraunhofer single slit diffraction equation can be applied:
y = mλ D
α
where,
y = displacement from the centerline for minimum intensity = 1.35 mm
m = order number = 1
λ = light wave length
α = witdh of the slit = 0.750 mm
D = distance between the screen and the slit = 2m
so
λ = yα
mD
λ = (1.35 x 10⁻³)( 0.750 x 10⁻³) = 5.0625 x 10⁻⁷m = 506.25 nm
1x2
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in the overhead view of fig. 15-48, a long uniform rod of mass 0.600 kg is free to rotate in a horizontal plane about a vertical axis through its center. a spring with force constant k
The period of the small oscillations that result when the rod is rotated slightly and released is 0.0653s.
Harmonic motion, where the damping force is proportional to the velocity, which is a realistic damping force for a body moving through a fluid is called damped harmonic motion.
If τ=−Cθ, where τ is the torque, θ is the angle of rotation, and C is a constant of proportionality, then the angular frequency of oscillation is ω= sqrtC/I and the period is T=2π/ω=2π sqrtI/C.
where, I is the rotational inertia of the rod. The plan is to find the torque as a function of θ and identify the constant C in terms of identies given in question.
Now using T=2π sqrtI/C, we get
T= 2π sqrtm/3K
putting given quantities,
T= 0.0653s.
The question is incomplete, the complete question is
In the overhead view of above figure, a long uniform rod of mass 0.600kg is free to rotate in a horizontal plane about a vertical axis through its center. A spring with force constant k=1850N/m is connected horizontally between one end of the rod and a fixed wall. When the rod is in equilibrium, it is parallel to the wall. What is the period of the small oscillations that result when the rod is rotated slightly and released?
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turn on the supply of fig 13.4 and measure the voltage vab. then calculate the current il using the measured value of the 47 resistor
At the junction of two resistors, a voltage (V1) proportional to the measured voltage will be shown. The Arduino's analogue pin can then be attached to this junction.
This formula can be used to determine the voltage. Vm = (R2/(R1+R2)) * V1 The Arduino then measures the voltage V1. A voltage divider circuit that consists of two resistors linked in series as shown can be used to solve this problem. The voltage to be measured (Vm) is linked to one end of this series connection, and the ground is attached to the other end.
Vab can be determined visually to be 14 volts. First, use your eyes. Write down the following values for the voltages and currents specified by Ohm's law using just your eyes: Your biggest error, in my opinion, was failing to realise that the ground (shown in green) is connected to both the 6 volt supply and the 5 ohm resistor.
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Antoine burns some charcoal, and a very small diamond (!), and makes the ____________ that the only product of both reactions is a heavy gas (carbon dioxide).
Antoine burns some charcoal, and a very small diamond, and makes the observation that the only product of both reactions is a heavy gas (carbon dioxide).
The descriptions of scientists engaging in activities that are part of the scientific method.
When Antoine burns charcoal and a small amount of diamond, then in that case, each Carbon atom will form a tetrahedral bond with the other four carbon atoms which are present in a Diamond.
Due to the formation of the tetrahedral bond the structure becomes more and more compact and rigid.
Hence, the missing word is given below.
Antoine burns some charcoal, and a very small diamond (l) and makes the observation that the only product of both reactions is a heavy gas.
Missing word:- Observation
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(a) Stone A leaves the player's hand with a velocity of 2.90 m/s.
The mass of stone A is 17 kg.
(i) State the formula linking momentum, mass and velocity.
(ii) Show that the momentum of stone A is approximately 50 kg m/s.
(1)
(2)
Answer:
(a)(i) momentum(kg m/s) = mass x velocity
p=mv
(a)(ii) 17 x 2.90 = 49.3
49.3 is approximately 50 kg m/s
Explanation: mass of stone A is 17 kg and the velocity of stone A is 2.90 m/s. To find momentum is to times mass and velocity.
A bowling ball of mass 7.22 kg and radius 10.2 cm rolls without slipping down a lane at 3.20 m/s . Calculate its total kinetic energy.
The total kinetic energy of the bowling ball is 51.75 Joules.
The mass of the bowling ball is 7.22 Kg and the radius of the ball is 10.2cm.
The radius in meter is 0.102 m.
The ball is rolling without slipping with a speed of 3.20m/s.
The total kinetic energy of the bowling ball is given by,
KE = 1/2Mv²(1+k²/r²)
where,
M is the mass of the ball,
v is the speed of the ball on the lane,
k is the radius of gyration,
r is the radius of the ball.
Putting values,
KE = 0.5 x 7.22 x 3.2 x3.2 x 1.4
KE = 51.75 Joules.
The total kinetic energy of the ball is 51.75 Joules.
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g a uniform electric field has magnitude e and is directed in the negative x direction. the potential difference between point a (at x= 0.60 m) and point b (at x= 0.90 m) is 310 v. Part A Which point, a or b, is at the higher potential? Part B Calculate the value of E. Express your answer using two significant figures. Part C A negative point charge q = -0.200 mu C is moved from b to a. Calculate the work done on the point charge by the electric field. Express your answer using two significant figures.
A) Point A is the one with the highest potential.
B) The uniform electric field's magnitude E is equal to 1033.33 V/m.
Given that,
Potential difference at point A ( at x ) = 0.6 m
Potential difference at point B ( at x ) = 0.9 m
Potential difference = 310 volts
Point charge is -0.200 μC = - 0.2 * 10⁻⁶ C
A) The point with a larger potential is point A because the uniform electric field of magnitude (E) is not close to the positive charge and is farther away from point B by 0.9 m. This is because the uniform electric field is directed in the negative x direction. Additionally, the square of the distance from a point charge has an inverse relationship with the potential difference of an electric field.
B) In order to determine the size (E) of the uniform electric field:
The equation Vab = E* d determines the magnitude (E) of this electric field at a constant potential difference.
Where Vab is the potential difference between points A and B, and E is the uniform electric field's magnitude
E is the electric field's strength, and d is the separation between points A and B.
Let us determine the distance (d),
d = db - da
⇒ 0.9 - 0.6 = 0.3 m
By changing the values in the formula above, we arrive at
310 = 0.3 E
E = 1033.33 V/m
Therefore, the uniform electric field has a magnitude of 1033.33 V/m.
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WILL MAKE BRAINLIEST:
A 100 kg object takes one MINUTE to travel 300 m east. It began travelling at 240 m/s and came to a stop (0 m/s) at the end. What was its acceleration?
240
0.8
-4
-2.4
Answer:
To find the acceleration of the object, we can use the formula: acceleration = (final velocity - initial velocity)/time.
Plugging in the given values, we get: acceleration = (0 m/s - 240 m/s)/1 minute.
Since 1 minute is equal to 60 seconds, we can convert the time to seconds to get: acceleration = (0 m/s - 240 m/s)/60 seconds.
Simplifying this equation gives us: acceleration = -4 m/s^2.
Therefore, the acceleration of the object is -4 m/s^2. The correct answer is therefore (-4).
discovery of mineral perchlorate on mars by the phoenix lander was significant because group of answer choices
The lander discovered falling snow and soil chemistry that has important implications for life. The largest finding of perchlorate, a substance on Earth that may be poisonous to certain organisms while providing nourishment for others.
What is the real name of Earth?Contrary to popular belief, Earth is not known by a recognized international name. "A common misinterpretation of the civilization's scientific name is "Terra." Earth is the planet's commonly used name in English, especially in science.
What are the specifics of Earth?Soil, air, liquid, and life are the components of Earth. There are flat areas, valleys, and mountains on the earth. The air is made up of many gases, mostly nitrogen and oxygen. Rain, snow, ice, rivers, lakes, seas, and streams are all forms of water.
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___ is experimental coefficient of kinetic friction the slope of the line of best fit between kinetic frction and normal force
Answer is Force, The kinetic fiction force, also known as sliding friction, only affects moving objects (thus the term "kinetic"). Pushing a box across floorboards is an example of this force opposing sliding motion.
This sort of friction has a particular coefficient of friction (such as rolling friction). The materials used to create the contacting surfaces are particular to this coefficient. The coefficient will be higher on a rougher surface. This is the equation that will assist you in determining the coefficient of kinetic friction: The force holding the items together, or the force perpendicular to the surfaces in contact, is known as the normal force.
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Suppose that a woman weighing 130 lb and wearing high heeled shoes momentarily places all her weight on the heel of one foot. If the area of the heel is 0.50 in.2, calculate the pressure exerted on the underlying surface in (a) pounds per square inch, (b) kilopascals, and (c) atmospheres.
The pressure exerted on a 130 lb woman wearing high heels to momentarily place her entire body weight on the heel with an area of 0.50 in 2 on either foot is:
a. 260 lb/in².
b. 1,794 KPa
c. 17.69 atm
PressurePressure is a strong pushing force. Physics explains that the unit of pressure is symbolized by the letter P.
In addition to N/M², the pressure formula has another unit of measurement, namely Pascal (Pa).
The pressure formula used is:
P = F/A.
Where,
P = pressure (N/m²or Pa)
F = compressive force (N).
A = surface area (m²)
If you have the mass of the object:
P = (m.g)/A
m = object mass (kg)
g = acceleration due to gravity (m/s²)
A = surface area (m²)
We have,
Mass of the woman = 130 lb ⇒ 58.97 kg
The area of the heel = 0.50 in² ⇒ 3.21 m²
So, the pressure exerted on the underlying surface:
a. P = F/A
= 130 lb/0.50 in²
= 260 lb/in²
b. P = (58.97) (9.8) / 3.22
= 179.4 x 10⁴ Pa = 1,794 KPa
c. 1 KPa = 0.0098692329 atm
So, 1,794 KPa = 17.69 atm
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what average net force is required to accelerate an 8kg bicycle to a speed of 6.2m/s in 5s?
The average net force required to accelerate an 8kg bicycle to a speed of 6.2m/s in 5s is 9.92 Newton.
What is force?The definition of force in physics is: The push or pull on a massed object changes its velocity.
An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
Given that: mass of the bicycle: m = 8 kg.
Final speed : v = 6.2 m/s.
Time interval: t = 5 s.
Hence, average net force applied on it = change in momentum/time interval
= 8 kg × 6.2 m/s/5 s
= 9.92 Newton.
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a 4.0 kg object moving at 6.0 m/s encounters a 20 n resistive force over a duration of 0.20s. the momentum change (magnitude only) experienced by this object is approximately ns.
The momentum change experienced by the given object is approximately is 4 N/s .
What is Momentum Change ?
The term momentum change is defined the change in the product of an object's mass and velocity.
A force is required for changing momentum of an object. This force applied can increase or decrease momentum and can even change the object's direction .
given that ;
mass of moving object is ⇒ 4 Kg ,
velocity of the moving object is ⇒ 6 m/s ,
the force = 20N .
time for which the force is applied is = 0.20 s .
Now , By Newton's Second Law ,
"the time rate of momentum change is directly proportional to the force applied on the object ".
So , momentum change is = 20 × 0.20
= 4 Ns .
Therefore , the momentum change is 4Ns .
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the speed of light is the fastest anything in the universe can go if it is traveling through space.________ can break that speed limit.
The speed of light is the fastest anything in the universe can go if it is traveling through space. Much faster than light can break that speed limit.
How quickly must you go in order to surpass the speed of light?We can never go faster than light. Or, to be more precise, in a vacuum, we can never travel at the speed of light. In other words, the 299,792,458 m/s upper limit of the universe's speed is the speed at which all other particles must move in order to exist.
What is the light's 3x10 8 speed?In a vacuum, light travels at a speed of 3 108 m/s. About 8 minutes pass before sunlight reaches Earth.
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jupiter has retained almost all of its original atmosphere because of its dramatic, prominent ring system. it is rotating so quickly, with the highest rotation speed of any of the planets. it is so massive and thus has a strong gravitational pull. io's volcanic activity adds material and replenishes the atmosphere.
This means that solid surfaces that must have a constant rotational speed are not visible.
More fundamental is the rotation of the mantle and core. These can be determined by periodic fluctuations in the radio waves emitted by Jupiter and controlled by its magnetic field. The magnetic field (discussed below) originates deep inside the planet and thus shares the internal rotation.
Jupiter was so massive that it was not as hot as the terrestrial planets when it formed, so it retained most of its original atmosphere. Since Jupiter is a ball of gas, it actually experiences differential rotation. Depending on where you are on Earth, the rotation will take a different amount of time.
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a bottle has a mass of 36.00 gg when empty and 95.94 gg when filled with water. when filled with another fluid, the mass is 89.22 g. Determine the specific gravity of the other fluid.
The specific gravity of the other fluid in the bottle with a mass of 53.22 g is determined to be 0.8879.
The ratio of a material's density to a predetermined reference substance is the substance's specific gravity. If anything has a specific gravity, it will either float or sink. When tested against water, the specific gravity of a solid or liquid is compared; if it is less than one, it will float, and if it is greater than one, it will sink. Then, the specific gravity of a material is given by, [tex]RD = \frac{\rho_{\text{substance}}}{\rho_{\text{reference}}}[/tex].
The mass of water in the bottle is 95.94 g - 36.00 g = 59.94 g. And the mass of another fluid in the bottle is 89.22 g - 36.00 g = 53.22 g. Then,
[tex]\begin{aligned}\text{specific gravity of other fluid}&=\frac{\rho_{\text{fluid}}}{\rho_{\text{water}}}\\&=\frac{\frac{m_f}{V}}{\frac{m_w}{V}}\\&=\frac{m_f}{m_w}\\&=\frac{53.22}{59.94}\\&=0.8879\end{aligned}[/tex]
The answer is 0.8879.
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While visiting the Albert Michelson exhibit at Clark University, you notice that a chandelier (which looks remarkably like a simple pendulum) swings back and forth in the breeze once every T = 6.1 seconds.
a) Calculate the frequency of oscillation (in Hertz) of the chandelier.
b) Calculate the angular frequency ω of the chandelier in radians/second.
c) Determine the length L in meters of the chandelier.
d) That evening, while hanging out in J.J. Thompson's House O' Blues, you notice that (coincidentally) there is a chandelier identical in every way to the one at the Michelson exhibit except this one swings back and forth 0.11 seconds slower, so the period is T + 0.11 seconds. Determine the acceleration due to gravity in m/s2 at the club.
The acceleration an object experiences as a result of gravitational force is known as acceleration due to gravity. M/s2 is its SI unit. Its vector nature—which includes both magnitude and direction—makes it a quantity. The unit g stands for gravitational acceleration. At sea level, the standard value of g on earth's surface is 9.8 m/s2.
How do we calculate the gravitational acceleration?
The formula for calculating acceleration due to gravity is given below in its most practical form by these two laws: Where g is the acceleration brought on by gravity, G is the gravitational constant of the universe, M represents mass, and R is distance, g = G*M/R2.
Describe 9.8 m s2?
Lowercase g indicates the gravity acceleration's magnitude, which is 9.8 m/s2. g = 9.8 m/s2. This means that gravity will increase an object's velocity by 9.8 m/s for every second it is in free fall. Following one second, the item is moving at a speed of 9.8 m/s.
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When a bar magnet is thrust into a coil of copper wire, the coil tends toA) repel the magnet as it enters. B) attract the magnet as it enters. C) both of these D) neither of these
A) repel the magnet as it enters.
When a bar magnet is thrust into a coil of copper wire the coil tends to repel the magnet as it enters. Option A.
For example, passing the poles of a permanent bar magnet through a coil of wire induces a current in the coil. The current creates a magnetic field around the coil, turning it into a magnet. Lenz's law indicates the direction of the induced current.
When a magnet moves in a coil of wire the magnetic field and flux through the coil change, creating a voltage in the coil according to Faraday's law. In the example shown below, as the magnet moves into the coil, the galvanometer deflects to the left in response to the increasing magnetic field.
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a unit load of not less than _volt-amperes per square foot be included for storage spaces in other than dwelling units
A unit load of not less than 1/4 volt-amperes per square foot is included for storage spaces other than dwelling units.
What is unit load?The unit load can be described as the size of an assemblage into which a number of items are combined for ease of storage and handling, for example, a pallet load expresses a unit load that can be moved easily with a pallet jack, or a container load expresses a unit for shipping purposes.
A unit load can pack tightly into a warehouse rack, truck, or intermodal container, yet can be broken apart at a distribution point, generally a distribution center, or wholesaler, for sale to consumers or for use.
A unit load can be defined as the basic storage and transport unit arranged on modular support or in packaging to ensure efficient handling.
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which of the following experiments best supports the idea that a transcriptional regulatory sequence can be located in an intron of a gene?
The experiment which best supports the idea that a transcriptional regulatory sequence can be located in an intron of a gene is: The intron of a gene is deleted, the gene is introduced into mouse cells, and the mRNA levels are measured. These mRNA levels are compared to a normal gene which is also introduced into mouse cells. The mutated gene shows no mRNA transcription, whereas the normal one does.
What is an intron of a gene?An intron is a region which resides within a gene but does not remain in the final mature mRNA molecule following transcription of the gene and does not code for amino acids which make up the protein encoded by the gene. Most protein-coding genes in the human genome consist of exons and introns.
Introns are crucial because the protein repertoire or variety is greatly enhanced by alternative splicing in which introns take partly important roles. Alternative splicing is a controlled molecular mechanism producing multiple variant proteins from a single gene in a eukaryotic cell.
Although part of your question is missing, you might be referring to this full question: Which of the following experiments best supports the idea that a transcriptional regulatory sequence can be located in an intron of a gene?
The intron of a gene is deleted, the gene is introduced into mouse cells, and the mRNA levels are measured. These mRNA levels are compared to a normal gene which is also introduced into mouse cells. The mutated gene shows no mRNA transcription, whereas the normal one does.The deleted intron that acts as a transcriptional regulatory element would result in a lack of mRNA, whereas the mouse cells with the normal gene would show mRNA transcription, thus serving as a positive control.Learn more about introns at: https://brainly.com/question/14317818
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Question is attached below
(a) the shell's horizontal range = 285839 m.
(b) the amount of time the shell is in motion is: 273.11 sec.
What is horizontal range?The length of the horizontal axis is a projectile's horizontal range. In addition, it would move before returning to the original vertical position.
Horizontal range is equal to Initial Speed in the horizontal direction, multiplied by the time the shell is in motion. Therefore, both questions can be solved at the same time.
Step 1. Find Velocity in the Horizontal direction by:
Vx = (1.70 x 10³) × cos(52°)
Vx = 1046.6 m/sec
Step 2. Find Velocity in the Vertical direction by:
Vy = (1.70 x 10³) × sin (52°)
Vy = 1339.6 m/sec
Step 3. Find the amount of time the shell is in motion by:
t= (2 × Vy)/gravity
t = (2 × 1339.6) / 9.81 [ Gravity = 9.81m/s²]
t = 273.11 sec
Step 4. Find the shell's horizontal range:
Distance = Vx × t
or, distance = (1046.6 × 273.11)
or, distance = 285839 m
Thus, (a) the shell's horizontal range = 285839 m.
(b) the amount of time the shell is in motion is: 273.11 sec.
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Place the events involved in generation of an action potential in the correct order of occurrence from left to right : Hyperpolarization K+ channels close; Na+ channels close K+ channels open; Threshold stimulus Na channels open; Na influx Depolarization; K+ efflux Repolarization
4, 2, 1, 5, 3 ;Threshold stimulus, Na+ channels open, Na+ influx, depolarization, Na+ channels close, K+ channels open, K+ efflux, repolarization,. Hyperpolarization, K+ channels close.
The gated sodium ion channels on the neuron's membrane quickly open during the depolarization phase, letting sodium ions (Na+) from the outside flood inside the cell. The nerve's intrinsic charge shifts from -70 mV to -55 mV as the sodium ions enter the cell fast. Depolarization is when an internal change in a cell results in a shift in the distribution of electric charges, leaving the cell with a less negative charge than the surrounding area. Depolarization is essential for several cell processes, cell-cell communication, and general organism physiology. A rise in membrane potential is referred to as depolarization. In other words, as sodium ions enter the intracellular fluid due to the opening of voltage-gated sodium cations, the membrane potential increases.
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At an intersection of hospital hallways, a convex spherical mirror is mounted high on a wall to help people avoid collisions. The magnitude of the mirror's radius of curvature is0.560m.
(a) Locate the image of a patient10.6m from the mirror. (Use the correct sign conventions.)
cm (from the mirror)
(b) Indicate whether the image is upright or inverted.
upright
inverted
(c) Determine the magnification of the image.
At an intersection of hospital hallways, a convex spherical mirror is mounted high on a wall to help people avoid collisions. The magnitude of the mirror's radius of curvature is0.560m. The image of a patient Located at -0.2877m. The image is an upright and a virtual image. The magnification of the image is 0.0271.
The image location can be calculate as follows:
The values of the image distance and focal length for a convex mirror are negative. using the mirror formula
1 = 1/u + 1/v
f u v
where,
f is the focal length = Radius of curvature/2 = 0.560/2 = 0.28m
u is the object distance = 10.6m
v is the position of the image
1 = 1 + 1
f u v
1 = 1 + 1
0.28 10.6m v
3.57 = 0.094 - 1/v
3.57 - 0.094 = -1/v
3.476 = -1/v
v = -1/3.476
v = -0.2877m
B) The fact that the image distance is negative indicates that the image is virtual and upright. Every upright image has a negative image distance.
C) Magnification: image/object distance
Magnification = 0.2877/10.6
Magnification= 0.0271.
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hans decides to test an idea that the atom is made of a soft positive substance with hard specks of negative substance (the electrons) embedded in it. he sets up an in which heavy positive particles will be fired into some gold atoms. hans will monitor how much these positive particles are deflected passing through the gold atoms.
He sets up experiment an in which heavy positive particles will be fired into some gold atoms.
The electron is a subatomic particle with a bad one standard electric charge. Electrons belong to the primary technology of the lepton particle own family, and are typically thought to be fundamental particles because they have no recognized additives or substructure.
For most realistic purposes, an electron is a structureless particle with an intrinsic angular momentum, or spin. simply two numbers — the electron's mass and its electric price — gasoline the equations that describe its behaviour.
By using the best values for the wave-length and the scattering by matter of tough X-rays and ?-rays, the radius of the electron is anticipated as approximately 2 × 10-10 cm.
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