Class 12 Question > In an L-R-C series circuit, the rms voltage a...Save
In an L-R-C series circuit, the rms voltage across the resistor is 30.0 V, across the capacitor it is 90.0 V, and across the inductor it is 50.0 V. Rms voltage of the source is
a) 60.0 V
b) 50.0 V
c) 65.0 V
d) 5.0 V

Colligative properties are those of solutions that are influenced by the volume of a nonvolatile solute dissolved in a solution but not by the nature of the solute. The correct option to this question is both b and c

When solute molecules are dissolved in a certain solvent, solutions are created as homogenous mixtures. These solutions have special characteristics that could be referred to as collaborative qualities. These include melting point depression, osmotic pressure, rising boiling point, and reducing vapor pressure.

These solute molecules have an impact on vapor pressure, freezing point, and boiling points.

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Complete question :colligative

property depends on _____.

a. the identity of the solute

b. the concentration of the solution

c. the number of solute particles dissolved in the solution

d. both a and b

e. both b and c

The current density  the magnitude of the magnetic field within the conductor is nevd.

The amount of current flowing per cross-sectional area is referred to as the current density and is expressed in amperes per square meter. As more current flows through a conductor, the current density rises. The term "current density" refers to the amount of current flowing through a material per unit cross-sectional area. Thus, the SI unit for current density must be ampere/m2. The current density is defined as the ratio of the current flowing through a conductor to its cross-sectional area perpendicular to the direction of current flow. The equation J=n e vd describes the interaction between drift velocity vd and current density J.

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A particle has a velocity of 3 m/s at one instant and a velocity of 23 m/s after 5 seconds when it is travelling straight forward with constant acceleration, then t=5sec at a displacement of 65m.

Acceleration, which refers to the rate at which velocity varies over time in terms of both speed and direction, has a value of t of 5 seconds. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. The equation a = v/t denotes acceleration (a), which is the change in velocity (v) over the change in time (t).

Total distance (S) = 23-3 = 20

Here v=23, u=3, time = 5sec

acceleration a= (v-u)/t

a=(23-3)/5

a=(20/5)

a=4

Now S=ut+ (1/2 *a *[tex]t^{2}[/tex])

S = 3(5) + (1/2 * 4 * 25)

S= 15+50

S= 65

t= 5 sec (time doesn't change here only displacement changes).

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Option C; The new magnitude of the centripetal acceleration 4ac

Initial condition time period = T

T = distance / speed = 2πR/v

T/2 = 2πR/V2

V2 = 4πR/T = 2V1

Centripetal acceleration,

Ac = 1/2mv² = 1/2 m4v1²

Ac = 4ac

As a characteristic of an object's motion when it is traveling along a circular path, centripetal acceleration is described. Centripetal acceleration is the motion of an item in a circle with its acceleration vector pointing in its direction of motion. Centripetal accelerations result from centripetal forces. The centripetal force driving the motion is a result of their gravitational pull in the unique instance of the Earth's round motion around the Sun, or any satellite's circular motion around any celestial body.

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According to the spaceship's passengers, the journey took 11.2 hours.

In reality, most of interstellar space is located within our solar system. Voyager 1 will need around 300 years to get to the inner edge of the Oort Cloud, and perhaps another 30,000 years to travel past it. The star that is currently closest to our solar system is Alpha Centauri.

The spacecraft will travel across in t = 15 hours.

Since this can be measured with a single clock at both locations, the time measured in S' frame is the correct time.

v = 10lh /15 h

v = 2/3 c

Because Δt° = Δς

Δς = Δt√1 - β²

Δς = (15h)√1 - (2/3)²

Δς = 11.2 h

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The total horizontal distance traveled by the tennis ball during the entire time it is in the air is approximately: 23 m

It is the line drawn horizontally from the viewer's eye. If an item is above the horizontal level, the angle of elevation is the angle created between the line of sight and horizontal level.

As we know,

H = [u(y)]²/2 g

or, H = (6.1)²/20

or, H = 1.86 m ≈ 1.9 m

Total max height = 1.9 m + 9.8 = 11 m

H = [u(y)]²/2g

or, 11 = [u(y)]²/20

or, u(y) = 14.832 m/s

u(x) = 7.6 m/sec

Now, R = u²sin 2θ/g

or, R = [2 u(x) u(y)] /g

or, R = [2×(7.6 )×( 14.832 )] / 10

or, R = 22.54 m
or, R = 23 m

Correct option: A

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Result = num1 ** num2, return result, mystery(10, 2) 10, 2. You can provide a function more information by using an argument.

The variables used to define a function are known as parameters. They are variables that will be used in the function body and are present in the function signature. When we call a function, arguments are the real values that are supplied to it.

A function is defined in Python by using the def keyword, which is followed by the function's name, parentheses, and a colon. Make sure to indent with a tab or 4 spaces the following step, and then specify.

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The ball must be fired at point p with a speed of 6.635 m/s in order for it to settle at a distance of 6 cm.

Due to it,

Height h1 equals 5 cm

h2 = 1.6 cm tall

Distance d = 6 cm

We are aware that t = (h2/g2) = (1.6*)/9.8 = 0.57 s.

We are aware that distance is simply speed times time.

The expression may be written as d = V1* t V1 = d/t = 6/0.57 = 10.52 m/s based on the aforementioned assertion.

According to the work energy theory, mg(h1-h2) = 1/2* m* V12 - 1/2* m* V22.

When "m" is removed from both sides, 1/2* V12 - 1/2* V22 = g(h1 - h2) 9.8 (5 - 1.6) = 1/2* 10.522 - 1/2* V22 33.32 = 1/2(10.522 - V22) (10.522 - V22) = 66.64 V22 = 44.03 V2 = 6.635 m/s

In light of this, the recommended ball speed is 6.635 m/s.

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mu sub s times N is the frictional force

which equals 196 N

so 196 newton force is required for the shoe to slide

Answer: 196 N

Explanation: The coefficient of static friction (μs) between two surfaces represents the maximum horizontal force that can be applied to an object before it begins to slide. The formula for calculating the required horizontal force to cause an object to slide is:

F = μs * N

where F is the required horizontal force, μs is the coefficient of static friction, and N is the normal reaction force acting on the object.

In this case, the required horizontal force to cause the basketball shoe to slide is:

F = 0.56 * 350 N

F = 196 N

So, a horizontal force of 196 N is required to cause the basketball shoe to slide on the court.

Option D; Upward pressure against the bottom is greater than downward pressure against the top of the submerged object.

The buoyant force is an upward force applied to objects submerged in fluids. As you swim downward, the water will try to force you back up to the surface, which can be annoying. The buoyant force is the name given to this upward force acting on things submerged in fluids.

The differential in Upward pressure between the top and bottom of the submerged object is the cause. Imagine a bean can being dumped into a watery basin. Since pressure (P gauge=rho gh)(P gauge = gh)left parenthesis, P, start subscript, g, a, u, g, e, end subscript, equals, rho, g, h, right parenthesis grows as you move deeper in a fluid, the force from pressure exerted increases.

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The work done by an 85.0-kg man who pushes a crate 4.00 m up along a ramp that makes an angle of with the horizontal  3.14 x 103 J.

We know that

F = w x d

given

d =4 m

mass of man = 85 kg

force exerted by man on block = 500 N

resolving mg will give mgsin\large \theta   and mgcos\large \theta

Ftotal = Fm  + 500

Ftotal =  mgsin\large \theta + 500  = 85x 9.8 x sin20  + 500 =  284.902 + 500  =  784.902 N

W = Ftotal x d =  784.902 x 4  =  3139.61 = 3.14 x 103 J

In physics, work is energy transferred to or from an object by applying a force along a displacement. In its simplest form, if the constant force is aligned with the direction of travel, it equals the product of the force and the distance traveled.

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Torque rods only really suitable for use in low Earth orbit due to the magnetic field is stronger option -1 is correct.

By preventing the motor from rolling during the transfer of load, torque rods or torque roll restrictors reduce the effect of torque. The difficulties brought on by recovery functions are also addressed. They also stop vibration and noise from traveling from the motor block to the chassis, which limits motor roll.

Electromagnets used for attitude control on spacecraft are called torque rods. The spacecraft experiences a torque and changes in orientation when a current flows through the torque rod, creating a magnetic field that interacts with the geomagnetic field of the planet.

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The magnitude of B in the interior of the solenoid is 5 * 10⁻⁷ A/m.

Given that,

Rate of change of current = 3000 A/s

EMF induced ε = 0.6 V

Number of turns N = 1200 turns

Cross-sectional area A = 35 mm² = 35 * 10⁻⁶ m²

Current i = 3 A

We know the relation, ε = L* dI/dt

Making L as subject, L = ε / ( dI/dt )

Substituting the values, we have

L = 0.6 / 3000 = 0.0002 H

We know the relation between N, i, B and L as

N* B = L *i

Making B as subject, we have

B = L *i/N = (0.0002 * 3)/1200 = 0.0000005 A/m = 5 * 10⁻⁷ A/m

Thus, magnetic field in the interior of the solenoid is 5 * 10⁻⁷ A/m.

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The minimum length required is 17.91 m when a laser beam starts 10 cm from side a of the container and enters the water at position x.

The output laser consists of a number of very closely spaced, discrete frequency components (very narrow spectral lines) covering a moderately broad spectral range. The discrete components are called laser modes and the spectral range they occupy is approximately the fluorescent line width of atomic transition giving rise to the laser output.

Laser oscillations occur, when the wave within the cavity replicate itself after two reflections so that the electric fields add in phase. In other words, the mirrors form a resonant cavity and standing wave patterns are setup.

In most high power applications for material processing or medical surgery, the laser is used as a mean for transferring the energy to the target. Thus there is no importance for the longitudinal laser modes.

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The magnitude of the electric field due to the rod at a location 8 cm from the midpoint of the rod is 2 N/C

E=F/Q

E=120/60

E=2 N/C

Any charge results in an electric field being connected to a specific location in space. The value of E, also known as the electric field strength, electric field intensity, or just the electric field, expresses the magnitude and direction of the electric field. Without any specific knowledge of what caused the field, knowing the value of the electric field at a particular location is sufficient to predict what will happen to nearby electric charges. The electric force F, or Coulomb force, exerted per unit positive electric charge q at that location may be used to calculate the strength of an electric field, or E = F/q, if the second charge, or test, is positive.

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The running of a clock at the top of a tower at the equator would be predicted by special relativity to be slow, and by general relativity to be fast.

The equator, which separates Earth's Northern and Southern hemispheres, is a circle of latitude with a radius of around 40,075 kilometers (24,901 mi). Halfway between the North and South poles, at 0 degrees latitude, is a fictitious line. Any other roughly spherical celestial body can likewise be referred to by this name.

The equator of a spinning spheroid, such as a planet, is the parallel (circle of latitude) where latitude is defined to be 0° in astronomical (3D) spatial geometry. It is a fictitious line that divides the spheroid into its northern and southern hemispheres and runs parallel to its poles. It is, in other words, the point at which the spheroid intersects the plane that is perpendicular to its axis of rotation.

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Given [tex]s(t) = t^{4} + 21t^{3} + 17t^{2} + 4t +33[/tex]

The velocity of the object at time t is [tex]v(t) = 4t^{3} + 63t^{2} + 34t + 4[/tex]

We know that, velocity is change in position with respect to time.

Therefore, [tex]v(t) = \frac{d[s(t)]}{dt}[/tex]

And it is given that [tex]s(t) = t^{4} + 21t^{3} + 17t^{2} + 4t +33[/tex]

So, differentiating above equation with respect to time t, we get

[tex]\\v(t) = \frac{d[s(t)]}{dt}\\\\ v(t) = \frac{d[t^{4} + 21t^{3} + 17t^{2} + 4t +33]}{dt} \\\\v(t) = 4t^{3} + 63t^{2} + 34t + 4[/tex]

For the second part of the equation, we need to find out if acceleration ever becomes zero. If acceleration is zero, it means the will stop changing it's position.
Now, we know that acceleration is change in velocity with respect to time.

Therefore, [tex]a(t) = \frac{d[v(t)]}{dt}[/tex]

[tex]a(t) = \frac{d[4t^{3} + 63t^{2} + 34t + 4]}{dt} \\\\a(t) = 12t^{2} + 126t +34[/tex]

Since acceleration becomes zero at two values of time t, therefore we can say that it will stop changing position.
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The sum stop signs of the car that accelerates at 4.3 m/s² for 6.4 s, coasts for 2.2 s, and then slows down at a rate of 3.5 m/s² = 216.118 m.

Velocity is a vector quantity that shows how fast an object moves from one place to another. A vector quantity is a term that is intended for a quantity that has both value and direction, meaning that the determination of the value of that quantity is based on direction.

The equation is:

V = s/t

Acceleration is the rate of increase in speed in a certain time expressed in units of meters per second squared (m/s²).

The function of speed is to determine how fast an object goes at a certain distance and is measured based on a vector quantity. Conversely, acceleration serves to change the speed of an object that is moving.

The equation is:

α = v/t

The question is not complete, it should be:

How far apart are the stop signs?

We have,

Acceleration = 4.3 m/s²

t = 6.4 s

First, determine the distance (1)

It's start from rest, so v₀ = 0

s₁ = (v₀t)₁ + ½ (at)₁²

= 0 + ½ (4.3) (6.4)²

= 88.064 m

Next, the distance (2)

a₂ = 0 m/s²

s₂ = (v₀t)₂ + ½ (at)₂²

= 0 + 20.812

= 20.812 m

The last, the distance (3)

s₃ = (v₀t)₃ + ½ (at)₃²

= (27.52) (8.6) + ½ (-3.5) (8.6)²

= 107.242 m

So, the sum stop sign = 88.064 m + 20.812 m + 107.242 m

= 216.118 m

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The magnitude of the field at point is  1/4π∈od³ √q² d² + p²

E resulting from the dipole generated by charges at the very end.

Ex = Kp/d³ in x direction.

E due to the charge at center

Ey = Kq/d²

Net electric field is E = 1/4π∈od³ √q² d² + p²

"Distance. or quantity." is how magnitude. is simply. defined. It shows how an object moves when it is in motion, whether that movement is absolute, relative, or of a certain size. It serves as a way to describe something's size or scope. Magnitude is a term used in physics to describe either an amount or a distance. A force's strength is quantified by a number called its magnitude. Take a force of 10 N, for instance, in the direction of the east. The phrase "towards east" denotes a direction, and "10" represents the force's magnitude. The 'value' or 'amount' of any physical quantity is what is essentially meant by the term "magnitude." A automobile is travelling quicker than a bike, for instance, in terms of speed.

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Color subtraction produces the colours displayed on the cover of our physics book.

What is colour subtraction?

If the incident light and pigment colours are known, the colour subtraction approach can be a useful tool for predicting the ultimate colour appearance of an object. The complementary colour scheme can be used to identify the light colours that will be absorbed by a certain material. To identify the colours of reflected light (or transmitted light), subtract the incident light colours (if any are present). Thus, the colour appearance of the item may be predicted.

Color subtraction produces the colours displayed on the cover of our physics book.

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The concentration of K+ is higher inside than outside the cell.

The resting membrane potential is maintained by Na+-K+ pumps that actively transport K+ into and Na+  out of the cell.

The concentration of Na+ is higher outside than inside the cell.

The concentration of potassium ions inside the cell is greater than the concentration of sodium ions outside the cell. The amount of water outside the cell compared to inside creates an osmotic gradient that drives water movement. In other words, if there are more solutes outside the cell than inside, water will move out of the cell to balance the solute levels inside.

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A model as a tube of diameter 8.0 cm and length 1.2 m. assume that urine has the same density as water, the pressure is -9088 pa.

Calculation :

v = flowrate/area = 0.0060/π(0.04)² = 1.2 m/s

2). from Bernoulli's eqn ,

  [tex]P_{bla}[/tex] -    [tex]P_{atm}[/tex] = [tex]\frac{1}{2}Pv _{2} ^{2}[/tex]  + [tex]\frac{1}{2}Pv _{1} ^{2}[/tex]  -  ρgh1

 [tex]P_{bla}[/tex] -    [tex]P_{atm}[/tex] = [tex]\frac{1}{2}Pv _{2} ^{2}[/tex]  + 0 -  ρgh1

ΔP  = 1/2(1000)(1.19)² - (1000)(9.8)(1)

       = 712.4 - 9800

       = -9088 pa

Pressure (symbol: p or P) is the force normal to the surface of an object per unit area over which that force is distributed.

Various units are used to express pressure. Some of these are units of force divided by units of area. For example, the SI unit of pressure, Pascal (Pa), is 1 Newton per square meter (N/m2).

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False.  A pan of enchiladas is served at a dinner party and it does not start to cool according to Newton's law of cooling.

Newton's Law of Cooling states that the rate of heat loss of a body is proportional to the difference in temperatures between the body and its surroundings. This means that the hotter an object is compared to its surroundings, the faster it will cool.

Therefore, the rate of cooling of the enchiladas would depend on the temperature of the environment in which it is served. If the environment is a warm room, for example, the pan of enchiladas would cool at a slower rate than if it were served in a cold room.

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When only switch s2 is closed the hat straightener will not turn on because the switches are connected In series. for current to flow all the switches must be closed

A closed circuit is a circuit without interruption, providing a continuous path through which a current can flow.. This can be likened to two path ways connected by a bridge to make transportation flow. In a circuit the bridge is the switch or key.

An open circuit is a circuit where the path has been interrupted or "opened" at some point so that current will not flow. An open circuit is also called an incomplete circuit.

When the switch is closed then we will have a closed circuit.

When multiple switches are connected in series with each other, they all must be in the closed position for current to travel through the circuit, thereby energizing the load. The load is the hat straightener here.

Therefore the the hat straightener will not turn on because if only s2 is closed because s1, s2 and s3 are connected in series.

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The equation for the induced current as a function of time when the crank is turned at frequency f is I = 2*pi*r2*B*Force(sin (2*pi*force*t))/R. You will need to turn the crank at a frequency of 540.54 Hz.

To completely illuminate the bulb requires the maximum current. Furthermore, this frequency is not practical. The current that results from electromagnetic induction is known as the induced current. The production of electric power relies heavily on electromagnetic induction. Several methods exist for producing this change, including altering the magnetic field's strength,

B, r, R, f, and t are words that describe induced current.

I = E/R = r2*B*2pi*force*sin(2*pi*force*t)/R

Max current Imax = 3.70*10-3 = Imax/3.70*10-3 P = I2/R

Imax = ((4)1/2)/2 AMP F = (2.3.70*10-3) = 540.54Hz

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The minimum weld size is 3/16 inch (based on the gusset plate thickness). Maximum size = 0.400- 1/16 0.338 in., or 5/16 in to the nearest 1/16 in.

LRFD solution,

P = 1.2D+1.6L 1.2(48)+ 1.6(120) = 249. 6 kips

Try w = 3/16 in.,

OR, 1.392 x 3 sixteenths = 4.176 kips/in.

The base metal shear yield strength (gusset plate controls) is 0.6F, t=0.6(36)

Shear rupture strength is 0.45F₁ = 0.45(58)() = 9.788 kips/in..

The weld strength of 4.176 kips/in. governs. Both longitudinal and transverse welds will be used. To determine the required length of the longitudinal welds, investigate the two options specified in AISC J2.4(c). First, assuming the same strength for both the longitudinal and transverse welds,

Total required length of weld= 249.6 4.176 59. 77 in.

length of longitudinal welds = 59.77-9.00 = 25.39 in.

For the second option, the strength of the longitudinal welds is 0.85(4.176) 3.550 kips/in.

and the strength of the transverse weld is 1.5(4.176) 6.264 kips/in.

The load to be carried by the longitudinal welds is

249.6-9(6.264) = 193.2 kips so the required length of the longitudinal welds is 193.2 2(3.550) 27.21 in.

To minimize the length of the connection, use the maximum weld size permitted. Use W 5/16 in.

PR. 1.392 x 5 sixteenths 6.96 kips/in

First, assuming the same strength for both the longitudinal and transverse welds,

249.6

total required length of weld= = 35.86 in.

6.96

length of longitudinal welds = 35.86-9.00 13. 43 in. 2

For the second option, the strength of the longitudinal welds is

0.85(6.96) 5.916 kips/in.

and the strength of the transverse weld is

1.5(6.96) 10.44 kips/in.

The load to be carried by the longitudinal welds is

249.6-9(10.44) = 155. 6 kips

so the required length of the longitudinal welds is

155.6/ 2(5.916) =13. 15 in.

The second option requires slightly shorter longitudinal welds. Try a 9-inch transverse weld and two 13½-inch longitudinal welds. Check the block shear strength of the gusset plate.

Agy Any 2x (13.5) 10. 13 in.2

Ant= (9) = 3.375 in.2

R = 0.6FA+Ubs FuAnt 0.6(58) (10.13)+ 1.0(58) (3.375) 548. 3 kips with an upper limit of 0.6FyAg+UbsFuAnt 0.6(36) (10.13)+1.0(58) (3.375) 414. 6 kips (controls) The design strength is OR, 0.75(414.6) 311 kips > 249.6 kips.

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A sample of an ideal gas goes through the process, the difference in internal energy [tex]E_{int},B - E_{int}.A[/tex] is 4.29 × 10⁴ J.

To calculate the difference in internal energy (ΔE_int) between points B and A, we need to consider the energy changes in each segment of the process and apply the First Law of Thermodynamics, which states:

Δ[tex]E_{int[/tex] = Q - W

where Δ[tex]E_{int[/tex] is the change in internal energy, Q is the heat added to the system, and W is the work done by the system.

Let's calculate the changes in internal energy for each segment:

1. From A to B (adiabatic process):

In an adiabatic process, no heat exchange (Q) occurs. Therefore, Q = 0.

The work done (W) in an adiabatic process is given by:

W = n * Cv * ( [tex]T_B[/tex] - [tex]T_A[/tex])

Since it is an ideal gas, the molar specific heat at constant volume (Cv) can be expressed as Cv = (f/2) * R.

The change in temperature ( [tex]T_B[/tex] -  [tex]T_A[/tex]) can be found using the adiabatic equation:

( [tex]T_B[/tex] /  [tex]T_A[/tex]) = [tex](V_A / V_B)^{(\gamma - 1)[/tex]

where γ is the adiabatic index or ratio of specific heats (γ = Cp/Cv).

2. From B to C (isobaric process):

In an isobaric process, the change in internal energy is given by:

Δ[tex]E_{int[/tex] = Q - W

W = P * ΔV

where P is the constant pressure and ΔV is the change in volume.

3. From C to D (isothermal process):

In an isothermal process, the temperature remains constant. Therefore, Δ[tex]E_{int[/tex] = 0.

4. From D to A (isobaric process):

Similar to the B to C segment, the change in internal energy is given by:

Δ[tex]E_{int[/tex] = Q - W

Given that the heat added from B to C is 345 kJ, and the heat released from D to A is 371 kJ, we can now calculate the difference in internal energy (Δ[tex]E_{int[/tex]) between points B and A.

Thus, if we sum up all the changes in internal energy for each segment, we get the desired value of Δ[tex]E_{int[/tex] which is approximately 4.29 × 10^4 J.

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Classical Physics is normally concerned with matter and energy on the normal scale of observation, while modern physics is caring with the behavior of matter and energy under extreme conditions or on a very large or very small scale.

For example, atomic and nuclear physics studies matter on the tiny scale at which chemical elements can be identified. The physics of elementary particles is on an even smaller scale since it is concerned with the most basic units of matter.

Classical Physics is also known as high-energy physics because of the extremely high energies required to produce many types of particles in particle accelerators.

On this scale, regular, commonsense notions of space, time, matter, and energy are no longer valid.

Computational modeling is essential for quantum and relativistic physics.

Classic physics is considered the limit of quantum mechanics for a large number of particles.

On the other side, classic mechanics is derived from relativistic mechanics. Like, in most of the formulations from special relativity, a correction factor (v/c)**2 appears, where v is the velocity of the object and c is the speed of light.

For velocities much minute than that of light, one can neglect the terms with c2 and higher that appear.

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Answer:

C. the soccer ball because it has the most mass

Explanation:

soccer ball - 410 g
beach ball - 110 g
baseball - 143 g
golf ball - 46 g

(i just took the test)

The amplitude motions are W =≈ 12 rad/s  , Vmax= 0.36 m/s   , T= ≈ 0.54 s.

What is amplitude ?

Distance between a wave's resting position and its highest movement is known as amplitude. Frequency is the quantity of waves that pass past a certain place each second. Period is the amount of time it takes for a wave cycle to finish.

What is force?

Everyday activities like walking, setting something down on a surface, tossing something into the air, and even the tides' regular variations all include the application of force. The result of the interaction between two or more things, a force is a push or a pull.

a)w = √k/m = √(67/0.49) = 11.69336 ≈ 12 rad/s

b)v_max = A w = 0.031 * 11.69336 = 0.36 m/s

c)T = 2π/w = 2*3.14/11.69336 = 0.53706 ≈ 0.54 s

Therefore, the amplitude motions are W =≈ 12 rad/s  , Vmax= 0.36 m/s   , T= ≈ 0.54 s.

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