Chri want to order DVD over the internet. Each DVD cot $15. 99 and hipping the entire order cot $9. 99. If he can pend no more than $100 , how many DVD could be buy?

Let's say Chloe spent X

Then Amy spent 60% more so Amy spent

X+60% of X =X + 0.6X =1.6X

Becky spent 15% of what Chloe spent so amount spent by Becky =15% of X = .15X

Now, in total, they spent 0.15X+ X + 1.6X =2.75X which is given as £55

So , X=55/2.75 = 20

Amount spent by Amy = 1.6X = 1.6 *20 =£32

Answer:

12

Step-by-step explanation:

1 -----> 3

?------>36

By make Cross

36*1/3 =12

Answer:

D. Corresponding angles

Step-by-step explanation:

Corresponding angles are angles located on the same side, the intersection of transversal and two or more straight lines. So, answer is D

The area of a rectangle is 42 quare millimeter. The length is 7 millimeter. 28 millimeters is the perimeter of the rectangle.

Perimeter = 2 × (Length + Width)

Perimeter = 2 × (7 + 6)

Perimeter = 28 millimeters

To calculate the perimeter of a rectangle, we need to multiply the length and the width of the rectangle, and then multiply that value by 2. In this case, the length is 7 millimeters, and the area is 42 square millimeters. To calculate the width, we can divide the area by the length, which is 42 divided by 7, which is equal to 6. So the width is 6 millimeters. Now we can calculate the perimeter using the formula: Perimeter = 2 × (Length + Width). Plugging in the values, we get: Perimeter = 2 × (7 + 6) = 28 millimeters.

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Answer:

68cm

Step-by-step explanation:

Because the scale factor is 2, which means the drawing is 2 times smaller than the actual airplane, multiply 34, the length of the wings tip to tip in the drawing by 2.

34 x 2 = 68

Answer: 68 meters

(Hope I'm correct, but read the explanation to make sure)

Step-by-step explanation:

Let's start with what we know. We know that the scale factor is 2, so in our model, from tip to tip, it is 34 cm. However, since the scale factor is 2:
34 * 2 = 68 meters

5. The constant of proportionality is $0.4 per pound

4. The constant of proportionality is  is 3 ounces of almond per ounces of dark chocolate

From the question, we are to determine the constant of proportionality from the given table

From the given information, we have that

There is a proportional relationship between x and y

That is,

y ∝ x

Then,

y = kx

Where k is the constant of proportionality

From the table,

When x = 5 pounds, y = $2

Then,

2 = k × 5

k = $2/5pounds  

k = $0.4/pound

k = $0.4 per pound

4.

x is proportional to y

Then,

y = cx

Where c is the constant of proportionality

From the table,

When x = 3 ounces of dark chocolate, y = 9 ounces of almond

Then,

9 = c × 3

c = 9/3

c = 3 ounces of almond / ounces of dark chocolate

c = 3 ounces of almond per ounces of dark chocolate

Hence, the proportionality constant is 3 ounces of almond per ounces of dark chocolate

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Answer:

-----------------------------------------

Simplify the expression:

Answer:

Step-by-step explanation:

[tex]log_{10}(2000xy)-(log_{10}x})(log_{10}y)=4\\\\log_{10}(2000(xy))-log_{10}(xy)=4\\\\log_{10}(2000)+log_{10}(xy)-log_{10}(xy)=4\\\\log_{10}(2(1000)=4\\\\log_{10}2+log_{10}(1000)=4\\\\log_{10}2+log_{10}(10^3)=4\\\\log_{10}2+3log_{10}(10)=4\\\\log_{10}2\approx0.3\\\\Hence,\\\\log_{10}2+3\neq 4[/tex]

[tex]log_{10}(2yz)-(log_{10}y)(log_{10}z)=1\\\\log_{10}(2(yz))-log_{10}(yz)=1\\\\log_{10}2+log_{10}(yz)-log_{10}(yz)=1\\\\log_{10}2\neq 1[/tex]

[tex]log_{10}(zx)-(log_{10}z)(log_{10}x)=0\\\\log_{10}(zx)-log_{10}(zx)=0\\\\0\equiv0[/tex]

The solution to the expression y² is 81 when y = -9

From the question, we have the following parameters that can be used in our computation:

y = -9

Also, from the question, we have

y2

Express the exponents in the above expression properly

So, we have the following representation

y²

Substitute the known values in the above equation, so, we have the following representation

y² = (-9)²

Remove the bracket in the expression

'This gives

y² = 9²

Evaluate the exponent

So, we have the following representation

y² = 81

Hence, the solution is 81

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The sum of two number is 92. Their difference i 20Let x and y represent the 2 number. Let x=the lager value and smaller valuex = 92 + 20 = 11,y = 92 - 20 = 72

Let x = the larger value and y = the smaller value.

We know that the sum of x and y is 92, so

x + y = 92

We also know that the difference between x and y is 20, so

x - y = 20

Add the two equations to get

2x = 112

Divide by 2 to get

x = 112

Substitute x = 112 into the first equation to get

112 + y = 92

Subtract 112 from both sides to get

y = 72

Therefore, the two numbers are x = 112 and y = 72.

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The real and imaginary parts of the three complex numbers are:

In this question we find three case of complex numbers, that is, numbers of the form z = a + i b, where a, b are real coefficients and i = √(- 1). The coefficient a corresponds to the real part of the complex number and the coefficient b is its imaginary part. Now we proceed to analyze each of the three cases:

Case 1: - 7

The number - 7 is equivalent to - 7 + i 0, where - 7 is the real part and 0 is the imaginary part.

Case 2: 5 - √(- 24)

First, we rewrite the entire expression in standard form:

5 - √(- 24)

5 - √[(- 1) · 24]

5 - √(- 1) · √24

5 - i √24

5 - i 2√6

The real part is 5 and the imaginary part is 2√6.

Case 3: (6 - i) · (6 + i)

We expand and simplify the resulting expression:

(6 - i) · (6 + i)

6 · (6 - i) + i · (6 - i)

36 - i 6 + i 6 - i²

(36 - i²)

36 + 1

37

37 + i 0

The real part is 37 and the imaginary part is 0.

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Answer:

The real and imaginary parts of the three complex numbers are:Real part: - 7, Imaginary part: 0Real part: 5, Imaginary part: 2√6Real part: 37, Imaginary part: 0How to determine the real and imaginary component of a complex number.In this question we find three case of complex numbers, that is, numbers of the form z = a + i b, where a, b are real coefficients and i = √(- 1). The coefficient a corresponds to the real part of the complex number and the coefficient b is its imaginary part. Now we proceed to analyze each of the three cases:Case 1: - 7The number - 7 is equivalent to - 7 + i 0, where - 7 is the real part and 0 is the imaginary part.Case 2: 5 - √(- 24)First, we rewrite the entire expression in standard form:5 - √(- 24)5 - √[(- 1) · 24]5 - √(- 1) · √245 - i √245 - i 2√6The real part is 5 and the imaginary part is 2√6.Case 3: (6 - i) · (6 + i)We expand and simplify the resulting expression:(6 - i) · (6 + i)6 · (6 - i) + i · (6 - i)36 - i 6 + i 6 - i²(36 - i²) 36 + 137 37 + i 0The real part is 37 and the imaginary part is 0.

Step-by-step explanation: hope this helps0^0

Answer:

x intercept= (1.5,0)

y intercept= (0,-2)d

Step-by-step explanation:

Rearrange the equation to be in the form y=mx+c:

4x-1=3y+5

y=(4x-6)/3

y=4/3(x)-2

y intercept= c from equation above =-2

y intercept=-2

x intercept => when y=0

sub 0=y

0=4/3(x)-2

2=4/3(x)

x=1.5

Answer:  The correct answer is 0.0165041148268188

Step-by-step explanation:

Complete division (no rounding precision):

0.442 ÷ 26.7812 = 0.0165041148268188

Answer:

b) arithmetic

Step-by-step explanation:

Knowledge Needed

c and d are not valid sequence types.

Geometric Sequences are when the values of terms are found by multiplying the previous term's value by the same number.

Example:

1, 2, 4, 8, 16

x2

2, 6, 18, 54, 162

x3

20, 10, 5, 2.5, 1.25

x0.5

Arithmetic Sequences are when the values of terms are found by adding the previous term's value by the same number.

Example:

5, 6, 7, 8

+1

7, 19, 31, 43

+12

9, 6, 3, 0

-3

Question

Examine the sequence. From viewing the first 2 terms, we know that it can either be a geometric sequence that multiplies by 11/3 every time the term increases or an arithmetic sequence that adds 8 every time the term increases.

Looking at the 2nd and 3rd term, we know it is an arithmetic sequence because 19 is not equal to 11 times 11/3.

Answer: Median is 12, mode is 5, mean is 13.71

Step-by-step explanation:

Answer:

The median is 18

The mode is 5

The mean is 13

Step-by-step explanation:

a) The equation is  y = 4/x².

b) The value of x is 2/9 when y = 25.

What is relationship?

The relation in mathematics is the connection between two or more sets of values. Assume that there are two sets of ordered pairs, x and y. If set x and set y are related, then the values of set x are referred to as the domain while the values of set y are referred to as the range.

Given table is

x      1       2        3          4

y      4       1       4/9       1/4.

Given that y is inversely proportional to the square of x.

y∝ 1/x²

y = k/x² where k is proportional constant.

Putting x = 1 and y = 4 in equation y = k/x²:

4 = k/1²

k = 4

Putting x = 2 and y = 1 in equation y = k/x²:

1 = k/2²

k = 4

Putting k = 4 in  y = k/x²:

y = 4/x²

Putting y = 25 in  y = 4/x²

25 = 4/x²

25x² = 4

Divide both sides by 25:

x² = 4/25

Take square root on both sides:

x = 2/5

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Answer

x=5 y=2

Step-by-step explanation:

Answer: 18

Step-by-step explanation:

there you go <3

Answer:

f(x)=3x+4 and g(x)=2x3

find.

a:fg(x)

b:gf(x)

The ratio of purple flower to white flowers is 1:1 for each friend.

A system of arrangement where objects are set at the center position.

In another words the piece that kept in the center position.

As example, for the purpose of decorating a table with flowers, we need to keep the flowers in such a way that all the flowers occupy the center position.

If we want to display a table as centerpieces with white and purple flowers, we must keep the two flowers in the same ratio to look the display more attractive.

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The f< [tex]f_{max}[/tex] the semicircular disk does not slip at the given instant.

The semicircular disk having a mass of 10 kg.

ω = 4 rad/s,  θ = 60 °

First we have to draw the free body diagram,

Calculate the distance AG.

[tex]$$\begin{aligned}A G & =\sqrt{O G^2+O A^2-2 \times O G \times O A \times \cos \theta} \\& =\sqrt{\left(\frac{4 \times 0.4}{3 \pi}\right)^2+0.4^2-2 \times \frac{4 \times 0.4}{3 \pi} \times 0.4 \times \cos 60^{\circ}} \\\end{aligned}$$[/tex]

=0.3477 m.

Calculate the angle ∝.

[tex]$$\begin{aligned}& \frac{\sin \alpha}{O G}=\frac{\sin 60^{\circ}}{0.3477} \\& \alpha=25.01^{\circ}\end{aligned}$$[/tex]

Calculate the normal acceleration at A.

[tex]$$\begin{aligned}a_{A, y} & =\omega^2\left(r_{A O}\right) \\& =4^2 \times 0.4 \\& =6.4 \mathrm{~m} / \mathrm{s}^2\end{aligned}$$[/tex]

Calculate the acceleration at G.

[tex]& \mathbf{a}_G=\mathbf{a}_A+\boldsymbol{\alpha} \times r_{G / A}-\omega^2\left(\mathbf{r}_{G / A}\right) \\[/tex]

[tex]& -a_{G, x} \mathbf{i}-a_{G, y} \mathbf{j}=\left\{\begin{array}{l}a_{A, x} \mathbf{i}+a_{A,} \mathbf{j}+\alpha \mathbf{k} \times A G(-\sin \alpha \mathbf{i}+\cos \alpha \mathbf{j}) \\-\omega^2[A G(-\sin \alpha \mathbf{i}+\cos \alpha \mathbf{j})]\end{array}\right\} \\[/tex]

[tex]& -a_{G, x} \mathbf{i}-a_{G, y} \mathbf{j}=\left\{\begin{array}{l}0+6.4 \mathbf{j}+\alpha \mathbf{k} \times 0.3477(-\sin 25.01 \mathbf{i}+\cos 25.01 \mathbf{j}) \\-4^2[0.3477(-\sin 25.01 \mathbf{i}+\cos 25.01 \mathbf{j})]\end{array}\right\} \\[/tex]

[tex]& -a_{G, x} \mathbf{i}-a_{G, y} \mathbf{j}=(0.3151 \alpha-2.352) \mathbf{i}+(0.147 \alpha-1.3584) \mathbf{j}\end{aligned}$$[/tex]

Equate i coefficient:

[tex]-a_{G, x}=0.3151 \alpha-2.352[/tex][tex]-a_{G, x}=0.3151 \alpha-2.352[/tex]

Equate j coefficient:

[tex]$$-a_{G, y}=0.147 \alpha-1.3584$$[/tex]

The free body diagram and the kinematic diagram of the semicircular disk is as follows:

Calculate the mass moment of inertia of the semicircular disk about point O.

[tex]$$\begin{aligned}I_0 & =\frac{1}{2}\left(\frac{1}{2} m r^2\right) \\& =\frac{1}{2}\left(\frac{1}{2} \times 10 \times 0.4^2\right) \\& =0.4 \mathrm{~kg} \cdot \mathrm{m}^2\end{aligned}$$[/tex]

Calculate the mass moment of inertia of the semicircular disk about point G.

[tex]$$\begin{aligned}I_G & =I_0-m(O G)^2 \\& =0.4-10\left(\frac{4 \times 0.4}{3 \pi}\right)^2 \\& =0.1118 \mathrm{~kg} \cdot \mathrm{m}^2\end{aligned}$$\\[/tex]

Consider moment equilibrium condition about point A.

[tex]$$\begin{aligned}& \sum M_A=I_G \alpha+\sum m a_G d \\& m g(A G \sin \beta)=I_G \alpha+m a_{G, x}(A G \cos \beta)+m a_{G, y}(A G \sin \beta) \\& 10 \times 9.81\left(0.3477 \times \sin 25.01^{\circ}\right)=\left\{\begin{array}{l}0.1118 \alpha+10 a_{G, x}\left(0.3477 \cos 25.01^{\circ}\right) \\+10 a_{G, y}\left(0.3477 \sin 25.01^{\circ}\right)\end{array}\right\} \\& 0.118 \alpha+3.151 a_{G, x}+1.47 a_{G, y}=14.42\end{aligned}$$[/tex]

Solve the equations (1), (2), and (3), the values obtained are as follows:

[tex]$$\begin{aligned}& \alpha=18.04 \mathrm{rad} / \mathrm{s}^2 \\& a_{G, x}=3.333 \mathrm{~m} / \mathrm{s}^2 \\& a_{G, y}=1.294 \mathrm{~m} / \mathrm{s}^2\end{aligned}$$[/tex]

Consider the force equilibrium along the horizontal direction:

[tex]$$\begin{aligned}& \sum F_x=m a_{G, x} \\& f=m a_{G, x} \\& f=10 \times 3.33\end{aligned}$$[/tex]

f=33.33 N.

Consider the force equilibrium along the vertical direction:

[tex]$$\begin{aligned}& \sum F_y=m a_{G, y} \\& m g-N=m a_{G, y} \\& (10 \times 9.81)-N=10 \times 1.294 \\& N=85.16 \mathrm{~N}\end{aligned}$$[/tex]

Calculate the maximum frictional force at point A.

[tex]$$\begin{aligned}f_{\max } & =\mu_s N \\& =0.5 \times 85.16 \\f_{\max } & =42.58 \mathrm{~N}\end{aligned}$$[/tex]

Since, f< [tex]f_{max}[/tex]the semicircular disk does not slip at the given instant.

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Except table 2, all tables have greater unit rate than the graph.

The required arrangements of tables is  Table 2 < Table 1 < Table 3 < Table 5 < Table 4 < table 7 < Table 6

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

From the given graph it is clear that the line passes through the points (0,0) and (11,20). So, unit rate of graph is

m=20-0/11=20/11=1.818

Similarly, we need to calculate the unit rate for each table.

m1=26-13/14-7=1.81

m2=18-9/10-5=9/5=1.81

m3=34-7/18-9=1.88

m4=42-21/22-11=21/11=1.90

m5=38-19/20-10=1.9

m6=50-25/26-13=25/13=1.923

m7=46-23/24-12=23/12=1.9166

Hence, Except table 2, all tables have greater unit rate than the graph.

The required arrangement of tables is  Table 2 < Table 1 < Table 3 < Table 5 < Table 4 < Table 7 < Table 6

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The transformation from the parent function is a translation by 2 units right and 1 unit up

From the question, we have the following function that can be used in our computation:

f(x) = x³

g(x) = (x − 2)³ - 1

First, we have the transformation to be:

From f(x) = x³ to f'(x) = (x − 2)³

This means the function is translated right by 2 units

Next, we have:

From f'(x) = (x − 2)³ to g(x) = (x − 2)³- 1

This means the function is translated up by 1 unit

Hence, the transformation is 2 units right and 1 unit up

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The function has no vertical asymptotes and the horizontal asymptotes of the function is y=0.

In the given question,

Consider the following function.

f(x) = e^{−x^2}

We have to find the vertical asymptote(s), x = Find the horizontal asymptote(s) or y = .

As we know that, a vertical asymptote is a line that runs vertically and guides the graph of the function but does not actually exist on it. Due to its position at an x-value that is outside of function's domain, it is difficult for the curve to ever pass it.

The function f(x) = e^{−x^2} has no undefined points. So the function has no vertical asymptotes.

The limit of the function at x→±∞ is calculated as follows:

[tex]\lim_{x\rightarrow \pm\infty }[/tex]f(x) = [tex]\lim_{x\rightarrow \pm\infty }[/tex]e^{−x^2}

[tex]\lim_{x\rightarrow \pm\infty }[/tex]f(x) = 0

So the horizontal asymptotes of the function is y=0.

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The right question is:

Consider the following function. (If an answer does not exist, enter DNE.) f(x) = e^{−x^2}. Find the vertical asymptote(s). (Enter your answers as a comma-separated list.) x = Find the horizontal asymptote(s). (Enter your answers as a comma-separated list.)

y =

The interest amount that will be capitalized is $4.04 million.

The entire cost to purchase a good or service is referred to as an expense. A $30 million piece of equipment with a six-year useful life, for instance, is considered a capital expenditure. An expense is something that calls for the transfer of funds, or fortune in general, from one person or group to another as payment for a good, service, or other type of cost. Rent is a cost to a tenant. Tuition is a cost to parents or students.

The following can be deduced from the information:

Average Expenditure for 2023

= 78 million* 6/6 month + 46 million ** 3/6 month

= 101 million

Amount of interest that should capitalized in 2023 using a specific interest method

= Average expenditure for 2023 * interest rate *6/12 month

= $101 million * 8% * 6/12

= $4.04 million

The interest amount is $4.04 million.

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The value of x in the solution set of the inequality is -4.

Inequalities are of two types, > and <. The > sign means that left hand side is greater than the right hand side, while the < sign means that the left hand side is less than than the right hand side.

We can solve the inequality by assuming the inequality sign as the = sign, except that when we divide or multiply one side by (-1), the inequality sign will reverse (for eg it will change from > to <).

9(2x+1) < 9x - 18

2x+1 < x - 2

2x < x - 3

x < -3

This means that x can be any value less than -3 (but not equal to -3 since the sign is < and not ≤) . Hence, the answer is -4.

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Answer:

-4

Step-by-step explanation:
taking  test

Answer:

This answer assumes that the function is A(x) = 100x − 2x^2.  The function as written is A(x) = 100x - (4 or 4x)

The domain is 0 - 50 feet.

Step-by-step explanation:

The area function is a polynomial with a vertex (hghest area possible) at (25,1250).  This is telling us that for a side length of 25 feet, the area is at a maximum of 1250 ft^2.  This is actually not totally correct.  We only need 3 sides of fencing since the school wall will make up the fourth.  The given equation does not seem to allow for this caveat, since it uses 100 feet for all four sides.

Given the equation, the domain for the function A(x) is positive for all values between 0 and 50 feet.  The domain is 0 - 50 feet.

The measures of dilated triangle A'B'C' are A'B'= 4.1 units, A'C'= 2.2 units and B'C'= 4.2 units.

A scale factor is defined as the ratio between the scale of a given original object and a new object, which is its representation but of a different size (bigger or smaller).

The basic formula to find the scale factor of a figure is expressed as,

Scale factor = Dimensions of the new shape ÷ Dimensions of the original shape.

Given that, center of dilation is P and scale factor is 1/3.

In the given triangle ABC, AB=12.4 units, AC=6.7 units and BC=12.7 units

Now, A'B'=12.4/3

A'B'= 4.1 units

A'C'=6.7/3

A'C'= 2.2 units

B'C'=12.7/3

B'C'= 4.2 units

Therefore, the measures of dilated triangle A'B'C' are A'B'= 4.1 units, A'C'= 2.2 units and B'C'= 4.2 units.

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If you assume that there is a 0.990.99 percent chance that you will find a prize in the cereal box, the odds are 99:1.

A probability is a measure of how likely or likely it is that a certain event will occur. Probabilities can be represented as percentages between 0% and 100% as well as proportions between 0 and 1.

How likely an event is to occur is determined by the concept of probability. For instance, meteorologists can predict the possibility of rain by looking at weather patterns. In epidemiology, probability theory is used to understand the relationship between exposures as well as the risk of health effects.

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