celera
An
A force F = 89.2 N acts at an angle a = 38°
with respect to the horizontal on a block of
mass m = 26.8 kg, which is at rest on a
horizontal plane.
The acceleration of gravity is 9.81 m/s2.
If the static frictional coefficient is pls
0.74, what is the force of static friction?
=

CeleraAnA Force F = 89.2 N Acts At An Angle A = 38with Respect To The Horizontal On A Block Ofmass M

Answers

Answer 1

Hi there!

We know that the MAXIMUM static friction force to be overcome is:

Fs (Force of Static Friction) = μN (Normal Force)

The normal force is equal to the weight of the block AND the vertical component of the applied force, so:

N = Mg + Fasinθ

Plug in the given values:

N = 26.8(9.81) + (89.2)sin(38) = 317.825 N

Multiply by the force of static friction to derive the static force:

0.74 * 317.825 = 325.191 N <-- MAXIMUM STATIC FRICTION FORCE

The force applied, if not greater than this value, will result in an EQUAL and OPPOSITE static frictional force. Thus:

Fs = Horizontal component of the applied force

Fs = 89.2cos(38) = 70.291 N


Related Questions

Explain in terms of refraction and wavelength, why dispersion of white light happens.

Pls help

I will put brainliest​

Answers

Answer:

terms of refraction and wavelength, why dispersion of white light happens.

Explanation:

hope it helps

the colour of the shadow of coloured objects is not same as the colour of the objects​

Answers

The colour of the shadow of coloured objects is not same as the colour of the objects

When an opaque item absorbs all of the light falling from a light source, no light is reflected, and the thing appears black. The color of an object's shadow is independent of its hue; it can be red, yellow, green, or black.

The ruminant stomach has four compartments including the rumen, reticulum, omasum and large intestine,
O True
O False

Answers

Answer:

False

It has four compartments just not including all of those

Explanation:

Ruminant stomachs have four compartments: the rumen, the reticulum, the omasum and the abomasum.Anatomy of the ruminant digestive system includes the mouth, tongue, salivary glands (producing saliva for buffering rumen pH), esophagus, four-compartment stomach (rumen, reticulum, omasum, and abomasum), pancreas, gall bladder, small intestine (duodenum, jejunum, and ileum), and large intestine (cecum, colon, and rectum).

An empty 230 kg elevator accelerates upward
at 1.7 m/s^2
The acceleration of gravity is 9.8 m/s^2.
What is the tension in the cable that lifts
the elevator cab?
Answer in units of N.

Answers

Answer:

7.2 as used in the equation

One of your classmates, in a fit of unrestrained ego, jumps onto a lab table:
a) Draw a qualitative force diagram for the table. Use marks on the vectors to show the balance of forces.
b) Your classmate’s mass is 65 kg and the table weighs 0 N. Calculate the normal force on the table by the floor. Show your work!
c)Find the mass of the table

Answers

The equilibrium condition allows finding the results for the forces of the system are

      a) The free body diagram is in the attachment

      b) The normal force is N = 737 N

      c) The mass of the table is  10.2 kg

Newton's second law indicates that the net force is proportional to the product of the mass and the acceleration of the bodies, in the special case that the acceleration is zero, it is called the equilibrium condition

          ∑ F = 0

Where the bold letters indicate vectors, F is the external forces

a) A free body diagram is a scheme of the forces without the details of the bodies, in the attachmentt we see a free body diagram of the system.

b) The reaction force of the ground is applied in each of the legs of the table, in general this force has the same magnitude in each leg, therefore in Newton's second law we can place it as a single force

             N = N₁ + N₂ + N₃ + N₄₄

Let's apply the equilibrium condition

                N -  [tex]W_m -w_{table}[/tex] = 0

                N =  [tex]W_m +w_{table}[/tex]

                N = [tex]M_m g + w_{table}[/tex]  

They indicate the pose of the boy is 65 kg, for the weight of the table of a laboratory table is approximately 100 N

                N = 65 9.8 + 100

                N = 737 N

c) To calculate the mass of the table we use the relation

                W = [tex]m_{table}[/tex] g

                [tex]m_{table} = \frac{w_{table}}{g}[/tex]

                [tex]m_{tabble}= \frac{100}{9.8}[/tex]  

               [tex]m_{table}[/tex]e = 10.2 kg

In conclusion using the equilibrium condition we can find the results for the forces are

      a) The free body diagram is in the attachment

      b) The normal force is N = 737 N

      c) The mass of the table is  10.2 kg

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While closing a door of mass 10 kg, a student pushes on it with a force of 25 N. As the door is accelerating to close, what
force does the door exert on the student?

A.5n
b.25n
c.250n
d.35n

Answers

Answer:

its 30 n

trust me

The pressure of liquid varies as per it's depth.

Answers

Answer: The pressure in a liquid is different at different depths. Pressure increases as the depth increases. The pressure in a liquid is due to the weight of the column of water above. The greater pressure at the bottom would give a greater 'force per unit area' on the wall.

Explanation:

Calculate the kinetic energy of a 70 kg person moving at a speed of 5m/s

Answers

Answer:

875 J

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

m is the mass

v is the velocity

From the question we have

[tex]k = \frac{1}{2} \times 70 \times {5}^{2} \\ = 35 \times 25 \\ = 875[/tex]

We have the final answer as

875 J

Hope this helps you

Answer:

[tex]\boxed {\boxed {\sf 875 \ Joules}}[/tex]

Explanation:

Kinetic energy is the energy an object possesses due to motion. It is calculated using the following formula:

[tex]KE= \frac{1}{2}mv^2[/tex]

The mass of the person is 70 kilograms and they are moving at a speed of 5 meters per second.

m= 70 kg v= 5 m/s

Substitute these values into the formula.

[tex]KE= \frac{1}{2} (70 \ kg )(5 \ m/s)^2[/tex]

Solve the exponent.

(5 m/s)² = 5 m/s * 5 m/s = 25 m²/s²

[tex]KE= \frac{1}{2}(70 \ kg)(25 \ m^2/s^2)[/tex]

Multiply the numbers in parentheses.

[tex]KE= \frac{1}{2} (1750 \ kg*m^2/s^2)[/tex]

Multiply by 1/2 or divide by 2.

[tex]KE= 875 \ kg*m^2/s^2[/tex]

Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule. So, our answer of 875 kg*m²/s² is equal to 875 Joules.

[tex]KE= 875 \ J[/tex]

The person has 875 Joules of kinetic energy.

✏️Topic: Comparing Arguments

My reflective journal.

Direction: Supply the sentence below to complete the information askes.

I learned that comparing arguments________________________One example of this is____________. We can use​

Answers

Answer:

WOW ANG HIRAP NG TANONG MO

Explanation:

Di ko yan masasagutan

stay safe

[tex]lol[/tex]

Linearize equation T=KL^n​

Answers


Ano po question talaga dyan

Explanation:

một vật dao động trong 10 phút thực hiện 500 dao động tính chu kì và tần số dao động

Answers

Answer:

Explanation:

T = 10(60)/500 = 1.2 s

f = 1/T = 0.83 Hz

I don’t get anything that this question is asking me and I need to turn this in quick

Answers

Answer:

Hey there

when they meat they will constructivly interfere, wich means they will become one big wave. After that they will pas right through each other and continue.

10. Based on the current position of the continents, South America is moving away from
Africa in what direction?
A. West
C. North
B. East
D. South

Answers

Answer:

D

Explanation:

bexause south jnshdbsjsvhhhgvvvbbhhhhbbbvgj ghbvkbBBCfjnbbcgn. gxb NBCxbncc gcbnbyd vvvv b jb jbhhhhhvvhbvvhjjnnjj,jzjsjdndjjshshdjsbddvdusvusgavahmmsbyurdvsbsjsiwjSCjDHLseekscoopDJxxvisoscoopxxviwellAbbistopDHLshopgogogogotoFL

If a 2 kg block of aluminium (SHC: 921 J/kg°C) is heated from 20°C to 40°C, how much energy was transferred to it?

Answers

H = mc∆T

where, H=heat energy

c = SHC

H = 2*921*(40-20)

H = 36840J

H = 36.84KJ

The energy transferred to it is 36.84KJ

The energy transferred to aluminum from 20°C to 40 °C is equal to 36840 J.

What is the specific heat capacity?

The specific heat capacity can be described as the quantity of heat required to increase the temperature of 1 unit of substance by one degree Celsius. The specific heat capacity of the substance depends upon the nature of the substance.

The mathematical equation is used to calculate the specific heat is equal to:

[tex]Q = m\times C\times \triangle T[/tex]

Given, the mass of the aluminum block, m = 2 Kg

The initial temperature of aluminum, T₁ = 20 °C

The final temperature of the aluminum, T₂ = 40 °C

The specific heat capacity of aluminum, C = 921 J/kg°C

The energy transferred to the aluminum block:

Q = 2 × 921 × (40-20)

Q = 36840 J

Therefore, the energy transferred to aluminum from 20°C to 40°C is  36840 J.

Learn more about specific heat capacity, here:

brainly.com/question/28302909

#SPJ2

A can of soda weighs 4.7 newtons (N) on Earth's surface. What will it weigh on Planet X where the acceleration due to gravity is 1.82 meters per second^2?

Answers

Explanation:

The mass of the soda can is

[tex]m = \dfrac{W}{g} = \dfrac{4.7\:\text{N}}{9.8\:\text{m/s}^2} = 0.48\:\text{kg}[/tex]

The weight of this same soda can on Planet X is

[tex]W = mg_p = (0.48\:\text{kg})(1.82\:\text{m/s}^2) = 0.87\:\text{N}[/tex]

how much kinetic energy is stored in a 1.5 kg object that is moved at 15 m per second​

Answers

Answer:

Explanation:

KE=0.5xM(Vpower2)

=0.5x1.5(15power2)

=168.75

A ball is thrown from the top of a 15.0 m tall building. The ball is initially released with a speed of 25.0 m/s in the direction 30.0 degrees above the horizontal. 2.00 seconds after it was released, the ball is traveling with a speed of 22.8 m/s in the direction 18.2 degrees below the horizontal. Using a coordinate system where x points in the direction the ball was released and y points up, what is the y component of the ball's motion after 2.00 seconds

Answers

Answer: the final velocity and final velocity velocity can also be written as we It went to one route A. V. Of X. Care plus movie. Why is here? This is a vision number two. And this is a revision number one food equation and one into to get we want to and wrote. We now takes scared plus we not scared away helpless to And by and the horizontal and the vertical component which are we know scare X is equal to we not cost it and we're not scared by going to we not scientific putting these value. Immigration number three. We get we will too. Are we not scared? I got scared to to less. We not scare Science square theater plus two. Why? So this we equal to he went to work and rude. We're not scared people to got scared he to less science security theater Last two. A. Y. Sure we get we s we're not scared into I. Plus to A Y. So we is able to. And road we now scared. Plus two. Am I. So this is a vision number four. And we are given me an artist 14 m purse again. And why he has given us. Uh huh. three m. So we can we find out by putting this value innovation number for the disk 14 scared. Uh huh. Plus To into -9.8 into three. We get to be It will do 11.7. Me did last

Explanation:

Maganda ka Tapos Liit mopa

Answers

Answer:

naol may pinoy dito nag jakoI

Answer:

jupiter mars and sun

Explanation:

. The artificial sweetener NutraSweet is a chemical called aspartame (C14H18N2O5). What is (a) its molecular mass (in atomic mass units)? (3) (b) the mass (in kg) of an aspartame molecule?​

Answers

The molecular mass, in atomic mass unit, of aspartame would be 294 amu while the mass, in kg, of an aspartame molecule would be 0.294 kg

Aspartame has the chemical formula C14H18N2O5

C = 12, H = 1, N = 14, O = 16

(a) Molecular weight = (12x14) + (1x18) + (14x2) + (16x5)

                                  = 168 + 18 + 28 + 80

                                    = 294 amu

(b) Mass of 1 molecule of aspartame = mole x molar mass

                                    = 1 x 294

                                        = 294 g

Converting 294 g to kg = 294/1000

                                         = 0.294 kg

More on mole and molar mass can be found here: https://brainly.com/question/6613610

Does a paddle boat’s wheel rotate clockwise or counterclockwise? PLS HELP

Answers

Propeller walk (also known as propeller effect, wheeling effect, paddle wheel effect, asymmetric thrust, asymmetric blade effect, transverse thrust, prop walk) is the term for a propeller's tendency to rotate about a vertical axis (also known as yaw motion). The rotation is in addition to the forward or backward acceleration.

Knowing of and understanding propeller walk is important when maneuvering in small spaces. It can be used to one's advantage while mooring off, or it can complicate a maneuver if the effect works against the pilot.

Which of the following is not an aspect of instincts?

Answers

There’s nothing there dude? What

21) A charged polyester ball is placed over a charged PVC pipe. The ball, which
has a mass of 1.2 grams, rests 42 cm above the pipe. If the ball and pipe have
the same negative charge, what is the charge on the ball?

Answers

The negative charge on the polyester ball is -1.53 x 10⁻⁶ C.

The given parameters;

mass of the ball, m = 1.2 gdistance between the ball and the pipe = 42 cm = 0.42 m

The gravitational force on the ball is calculated as follows;

F = mg

F = 0.012 x 9.8

F = 0.12 N

The electrostatic force on the ball is calculated as follows;

[tex]F= \frac{kq^2}{r^2} \\\\q^2 = \frac{Fr^2}{k} \\\\q = \sqrt{\frac{0.12 \times (0.42)^2}{9\times 10^9}} \\\\q =+/ -\ \ 1.53 \times 10^{-6} \ C\\\\q =-\ \ 1.53 \times 10^{-6} \ C[/tex]

Thus, the negative charge on the polyester ball is -1.53 x 10⁻⁶ C.

Learn more here:https://brainly.com/question/18108470

Find the center of the galaxy with Shapley method

Answers

Answer:

Calculating Center

Shapley correctly determined the galactic center of the Milky Way to be located in the constellation of Sagittarius. He did this by mapping out a three-dimensional distribution of the globular clusters.

Explanation:

Mark me the Brainliest..PLS

A 10-cm-long archerfish begins such a leap with its body vertical in the water, using its fins and undulating its body to propel itself sharply upward. Its acceleration steadily decreases as it leaves the water because less of its body and fewer of its fins are in contact with the water.

With what speed does the fish leave the water?
What height above the water does it reach?

Answers

Answer:

Explanation:

Velocity will be equal to the area under the curve of the acceleration-time plot.

v = ½(45)(0.075) = 1.6875

v = 1.7 m/s

h = (0² - 1.6875²) / (2(-9.8)) =  0.145288...

h = 15 cm

what does that mean?

Answers

Answer:

Acceleration is the rate at which the velocity changes .

Hope it's help you !!

2. What are the units of mass?

kg
N
m/s
m/s^2
(kg)(m/s)
m
S

Answers

Answer:

Kg

Explanation:

The units of mass are gram (g) , kilograms (Kg)

But SI of mass accepted is Kilograms (Kg)

Answer:

kg

Explanation:

the s.i unit is kilogram

An object travelling at 12 m/s has 64.8j of stored kinetic energy. What is the mass of the object, in grams?​

Answers

Answer:

So u divided 12 divided by 64.8 okay

Explanation:

and when I getc the answer that's urs answer

Tốc độ v của một vật được cho bởi phương trình v = At
3
– Bt, trong
đó t là thời gian.
(a) Xác định thứ nguyên của A và B.
(b) Đơn vị SI của các hằng số A và B là gì?

Answers

If v(t) is speed measured in meters per second (m/s), and t is time measured in seconds (s), then the constants A and B in

v(t) = At ³ - Bt

must have units of m/s⁴ and m/s², respectively; otherwise, the equation is dimensionally inconsistent.

[m/s] = A [s]³ - B [s]

[m/s] = [m/s⁴] [s]³ - [m/s²] [s]

[m/s] = [m/s] - [m/s]

[m/s] = [m/s]

If the mass is 2.0 kg and the acceleration is 5 m/s/s, then what is the force?

Answers

Answer:

Explanation:

F = ma = 2.0(5) = 10 N

One train (22,680 kg) moving east at 170 km/h collides with a car (1,200 kg) that was moving north at 5 km/h. They get attached to each other, moving in the direction of the train. What is the final velocity of the objects and the type of collision? If the collision happened in 1.2X10-3 seconds, what was the force? How much kinetic energy was lost?

Answers

The final velocity of the objects is 229.82km/hrSince energy was lost after the collision, the type of collision that occurs is an elastic collision.The required force is 1,090,918,000NThe amount of Kinetic energy lost is 12,401,976.656Joules

According to the law of collision'

m1u1 + m2u2 = (m1+m2)v

Given the following:

m1 = 22,680kg

u1 =170km/h

m2 = 1200kg

u2 = 5km/hr

Get the final velocity "v"

22680(170) + 1200(5) = (22680 + 1200)v

3855600 + 6000 = 12880v

3,861,600 = 12880v

v = 3,861,600/12,880

v = 229.82km/hr

Hence the final velocity of the objects is 229.82km/hr

Since energy was lost after the collision, the type of collision that occurs is an elastic collision.

According to Newton's second law, the formula for calculating the force is expressed as;

F = ma

F = m(v-u)/t

F = 22680+1200(229.82-175)/t

Ft = 23880(54.82)

F = 1,309,101.6/0.0012

F = 1,090,918,000N

Hence the required force is 1,090,918,000N

KE lost = Kinetic energy after collision - Kinetic energy before collision

Kinetic energy after collision = 1/2 * 12880 * 229.82²

Kinetic energy after collision = 340,142,976.656 Jolues

Kinetic energy before collision = 1/2 * 22680(170)²+ 1/2*1200(5)²

Kinetic energy before collision = 327,726,000 + 15000

Kinetic energy before collision = 327,741,000

Kinetic energy lost = 340,142,976.656 - 327,741,000 =  12,401,976.656Joules

Learn more here: https://brainly.com/question/9537044

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