can someone please do this math problem with process shown​

Answer:

-3(9y^2-12y^3+4y^4+x^2 - 4xy+3y^2)

Step-by-step explanation:

and there is no x-intercept. y= 10

Answer:

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Answer:

1. 175

2. 362.86

3. 1,960

Answer:

15 + 18

Step-by-step explanation:

Use the distributive property.

3(5 + 6) = 3 × 5 + 3 × 6 = 15 + 18

Answer:

116 miles (186 km)

Answer:

answer is D Add all the numbers that represent them x and do the same with the others then multiply by 4

___________

[tex] \: [/tex]

[tex]\boxed{ \rm{answer \: by \: { \boxed{ \rm{☆HayabusaBrainly}}}}}[/tex]

x² = (10,6)² + (6,1)²

x² = 112,36 + 37,21

x² = 149,57

x = 12,22mi✔

Answer:

45mph

Step-by-step explanation:

To find the average speed, we must add together all of the different speeds and divide by the quantity of them (assuming all of them are equal in time). In this case we have 2: 50 and 40.

[tex]50+40=90[/tex].

Then we divide by 2, since there were two segments of equal length

[tex]\frac{90}{2} =45[/tex]

45mph

Answer:

44.44

Step-by-step explanation:

Got the answer

-2/5 or -0.4

Hope this helps!

Answer:

4 to 20

Step-by-step explanation:

Answer:

20+4=24

There are 4 circles.

4:24

If you simplify that, it is 1:6.

1:6 is the answer simplified.

Answer:

280 student tickets

520 adult tickets

Explanation:

I'm guessing this is the question you meant to ask:

Eight hundred tickets were sold for a movie production and the receipts for the performance wear $8600. The tickets for adults and students sold for $12.50 and $7.50, respectively. How many of each ticket were sold?

Answer:

the answer to your question is 5+6+7+8

Answer:

ok

Step-by-step explanation:

The four consecutive numbers are 5, 6, 7, 8

The smallest number is 5.

Thus their sums equal to 26.

Answer:

w=[tex]\sqrt{\frac{x-y}{v}[/tex]

Step-by-step explanation:

The question is wrong because as the given angle is 90, the hypotenuse(11cm) should be greater than 16cm

Answer:

cant solve

Step-by-step explanation:

(sorry im not good at english) because there is no right triagle in which the length of the side of the right angle is greater than the length of the hypotenuse.

Answer:

angle 1 = 115°

Step-by-step explanation:

[tex]\sf{}[/tex]

hope it's helpful to you ☺️

Answer:

60 seconds make one minute. 2 minutes 30 seconds is 150 seconds

to find time per lap is 150 divided by 4 which will give you 37,5 second per lap

the answer is 37,5 seconds per lap.

Answer:

c

Step-by-step explanation:

did this test and got a 100

Step-by-step explanation:

a diameter is always twice the radius.

the only pairs in this list, where one number is twice the other, is :

2.5 and 5

7.6 and 15.2

so,

2.5 is the radius of A

5 is the diameter of A

7.6 is the radius of B

15.2 is the diameter of B

15.7 is then the circumference of A (as the smaller of the remaining 2 numbers).

47.7 is the circumference of B.

this is also proven by the formula for the circumference of a circle : c = 2×pi×r

Answer:

C I'm pretty sure yeah it's c

Answer:

Basically you just add the like terms together. Like terms are terms that have the same power, like 1, or 2 to the second power. x has a power of zero.

Step-by-step explanation:

Brainliest pls, ty

Answer:

I don’t know if it right but I got

L(6,-6)

M(8,-8)

N(3,-8)

Step-by-step explanation:

I did this because my teacher show me if it’s 90 counterclockwise is (-y,x) 180 counterclockwise (-x,-y) and if it 270 counterclockwise (x,y) and that what I got oh and the x=5 a reflect x in the 5

Answer:

40J

Step-by-step explanation:

YOU say 1/2 x 5 x4² ( 4 is velocity. 5 is mass )

it becomes 1/2 x5 x16

then it becomes 1/2 x 80

half of 80 is 40

the answer is then 40 JUOLES

Answer:

uhhhhhhhhhhhhhhhhh

Step-by-step explanation:

i wish i knew

Answer:

The quadratic x2 − 5x + 6 factors as (x − 2)(x − 3). Hence the equation x2 − 5x + 6 = 0

has solutions x = 2 and x = 3.

Similarly we can factor the cubic x3 − 6x2 + 11x − 6 as (x − 1)(x − 2)(x − 3), which enables us to show that the solutions of x3 − 6x2 + 11x − 6 = 0 are x = 1, x = 2 or x = 3. In this module we will see how to arrive at this factorisation.

Polynomials in many respects behave like whole numbers or the integers. We can add, subtract and multiply two or more polynomials together to obtain another polynomial. Just as we can divide one whole number by another, producing a quotient and remainder, we can divide one polynomial by another and obtain a quotient and remainder, which are also polynomials.

A quadratic equation of the form ax2 + bx + c has either 0, 1 or 2 solutions, depending on whether the discriminant is negative, zero or positive. The number of solutions of the this equation assisted us in drawing the graph of the quadratic function y = ax2 + bx + c. Similarly, information about the roots of a polynomial equation enables us to give a rough sketch of the corresponding polynomial function.

As well as being intrinsically interesting objects, polynomials have important applications in the real world. One such application to error-correcting codes is discussed in the Appendix to this module.