Answer:4.99km
Explanation:
We'll use s for distance, and t for time in seconds.
s = (1/2)at²
t = 0.5 minute*(60sec/1min)=30 sec
s = (1/2)*(2.2m/s²)(30sec)²
s = 990m
Reference point is 4km at start. Distance from reference point is 9km + 0.990km = 4.99km
If a 2kg block of copper is heated and a temperature increase of 50C is measured, how much energy has been provided?
Explanation:
Given : S=400Jkg
−1
C
−1
and L
f
=3.5×10
5
Jkg
−1
Mass of copper block m=2kg
Heat released by the copper block is equal to the heat gained by the ice to melt.
Let the mass of the ice melted be M.
Change in temperature of copper block ΔT=500−0=500
o
C
∴ mS(ΔT)=ML
f
Or 2×400×500=M×3.5×10
5
⟹ M=1.14kg
hope it help u
We have that If a 2kg block of copper is heated and a temperature increase of 50C is measured,the energy has been provided is
E=418KJ
From the question we are told
If a 2kg block of copper is heated and a temperature increase of 50C is measured, how much energy has been provided?
Generally the equation for the Energy is mathematically given as
[tex]E=mC(T_1-T_2)\\\\E=2*4180(50)\\\\E=418000J\\\\E=418KJ[/tex]
Therefore
If a 2kg block of copper is heated and a temperature increase of 50C is measured,the energy has been provided is
E=418KJ
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Từ độ cao 100 m người ta thả một vật thẳng đứng xuống với v = 10 m/s, g = 10 m/s2 . a. Sau bao lâu vật chạm đất. b. Tính vận tốc của vật lúc vừa chạm đất.
Answer:
10 points dapat yawa aman daw gud
Câu 1. Một ôtô đang chạy với vận tốc 54km/h thì tài xế hãm phanh, sau 10 giây tốc độ của ôtô là 36km/h.
a) Tìm gia tốc của ôtô?
b) Tìm quãng đường ôtô đi được trong thời gian hãm phanh?
c) Tinh vận tốc của ôtô sau 16 giây kể từ lúc hãm phanh?
Câu 2. Từ độ cao 80m so với mặt đất, thả một vật rơi tự do. Lấy g = 10 m/s2
a) Tính thời gian vật rơi?
b) Tính vận tốc của vật khi chạm đất?
Câu 3. Một vật có khối lượng 500g đang nằm yên, chịu tác dụng một lục 1,2 N, vật chuyển động nhanh dần
đều.
a) Tìm gia tốc của vật?
b) Tìm quãng đường mà vật đi được sau 1 phút?
c) Tính vật tốc của vật sau 30s kể từ lúc bắt đầu chuyển động ?
d) Sau bao lâu kể từ lúc bắt đầu chuyển động, vật có vận tốc 72km/h?
anyone would like to help?
1. Yes. They are located and distributed around the earth (not randomly though)
2. No. They are usually located in distinct zones relating to tectonic plates
3. Yes. They are mostly in the region where plate boundaries are found.
4. Yes.
5. No. They are connected to plate tectonic theory of divergent, convergent, and transform plate boundaries.
6. Yes.
7. No. They are located in various regions around the world.
8. Yes. Divergent and convergent plate boundaries are likely to produce volcanoes.
9. Yes.
10. No. Mountain ranges are formed when continents collide. These collisions can produce earthquakes, and many of these mountain ranges include volcanoes.
what is the use if having a control condition in an investigation
Answer:
Thus, including a control condition allows researchers to compare the way things are in the presence of an independent variable with the way things would have been in the absence of an independent variable.
Explanation:
Thus, including a control condition allows researchers to compare the way things are in the presence of an independent variable with the way things would have been in the absence of an independent variable.
What happens to an object's atoms when the object becomes positively charged?
A 0.12 kg object makes an elastic head-on collision with a 0.18 kg stationary object. The final velocity of the 0.12 kg object after the collision is 0.048 m/s in the direction opposite its initial movement. The final velocity of the 0.18 kg object after the collision is 0.19 m/s in the same direction as the object which strikes it. What was the initial velocity of the 0.12 kg object?
Answer:
0.12kg / 0.19
Explanation:
Becase the volcity reuded
The final velocity of the 0.18 kg object after the collision is 0.19 m/s in the same direction as the object which strikes it, then the initial velocity of the 0.12 kg object would be 0.237 m / s .
What is momentum?It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.
As given in the problem, a 0.12 kg object makes an elastic head-on collision with a 0.18 kg stationary object. The final velocity of the 0.12 kg object after the collision is 0.048 m/s in the direction opposite its initial movement. The final velocity of the 0.18 kg object after the collision is 0.19 m/s in the same direction as the object which strikes it.
By using the conservation of the momentum,
v × 0.12 + 0 × 0.18 = ( - 0.048)× 0.12 + 0.19 × 0.18
v = 0.237 m / s
Thus, the initial velocity of the 0.12 kg object would be 0.237 m / s .
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How did the river cause the canyon to form?
Answer options with 4 options
A.
The motion of water compacted soil until it became sedimentary rock.
B.
The motion of water wore away and transported rock away from the area.
C.
The motion of water prevented rock layers from forming beneath the water.
D.
The motion of water prevented plants and animals from forming the land in the river bed.
Answer:
A
Explanation:
because the water carRies but also compacts
hai điện tích điểm bằng nhau có độ lớn 6.10^-8C đặt cách nhau một khoảng là r trong dầu hỏa có hằng số điện môi E=2,1. Lực tương tác tĩnh điện giữa chúng laf3,85.10^-4. tìm r
Answer:
hai điện tích điểm bằng nhau có độ lớn 6.10^-8C đặt cách nhau một khoảng là r trong dầu hỏa có hằng số điện môi E=2,1. Lực tương tác tĩnh điện giữa chúng laf3,85.10^-4. tìm r
im confused on number two can u help me through it
Hi there!
We can solve this in two ways, using the Work-Energy theorem or kinematics.
Work-Energy:
We know that:
Ei = Ef, as long as there are no external forces working on the system.
Thus:
Ei = PE = mgh
Ef = KE = 1/2mv²
Therefore:
mgh = 1/2mv²
We can cancel out the mass:
gh = 1/2v²
9.8(10) = 1/2v²
√196 = v = 14 m/s
We can also solve using kinematics, using the equation:
vf² = vi² + 2ad
From rest (vi = 0 m/s) and a = g, so:
vf² = 2gd
vf = √2gh
vf = √(2 × 9.8 × 10) = 14 m/s
what kind of role can you play in your family and locality in terms of population education awareness
Answer:
I can suggest them by making different program about it and I will tell them the importance of less and productive population . Also tell them bad consensus of over population. I also give the technique of stopping over population.
What does this poem mean:
A lake in the spring
Is a marvellous thing
Changes are on the way
The winter chills cease
with sunlight’s increase.
Cool waters cover the bay.
Water moves round
From surface to ground
Water is mixed this way
Spring storms bring rain
Lake water does gain
With nutrients caught in the fray
Tiny creatures abound
‘Cause algae’s around
The food chain is boosted this way.
the poem seems to be about the seasons transitioning from winter to spring. the poet explains the lake melting, the sunlight coming out, spring storms that add water to the lakes, and the creatures that come back to roam after winter comes to an end. im really sorry if that didnt help.
Answer this question fast please i will mark you brainliest
Answer:
respuesta d)
Explanation:
Answer:
b) 72 F°
Explanation:
In Fahrenheit, the difference between freezing and boiling is 180 F° (that’s 212 °F minus 32 °F). In Celsius, the difference is 100 C° (by definition of 0 °C and 100 °C for those two points). So 100 C° = 180 F°; dividing by 100 gives us 1 C° = 1.8 F°.
So a difference of 40 C° is equal to 40 times (1.8 F°) = 72 F°.
Notice I am using °F and °C for actual temperatures, and F° and C° for temperature DIFFERENCES.
whats the kinetic energy please help me ive been stuck for a while
Answer:
k=1/2mv²
Explanation:
k is the kinetic energy
m is mass
and v is velocity/speed
if the distance is 207m what is the time
Answer:
That depends on your average speed and the number of stops you make. However, assuming you could average 55 miles per hour for the entire distance, your total driving time would be about 3 hours and 45 minutes.
A truck pulls a trailer on a flat stretch of road. The forces acting on the trailer are
the force due to gravity (250 000 N downward), the force exerted by the road
(250 000 N upward), and the force exerted by the cable connecting the wailer to
the truck (20 000 N to the right). The forces acting on the truck are the force due to
gravity (80 000 N downward), the force exerted by the road (80 000 N upward), the
force exerted by the cable (20 000 N to the left), and the force causing the truck to
move forward (26 400 N to the right).
The net vertical force on the trailer is 0, while the net horizontal force on the trailer is 20,000 N to the right.
The net vertical force on the truck is 0, while the net horizontal force on the truck is 6,400 N to the right.
The given parameters;
the trailer:
force on the trailer due to gravity, Fg = 250,000normal force on the trailer due to the road, N = 250,000 Nhorizontal force on the trailer, Fx = 20,000 N to the rightthe truck:
force on the truck due to gravity, Fg = 80,000 Nnormal force on the truck due to the road, N = 80,000 Nleft horizontal force on the truck, Fx = 20,000 Nright horizontal force on the truck, Fx = 26,400 NThe net force on each vehicle is calculated as follows;
for the trailer:
Net vertical force is calculated as;
[tex]\Sigma F_y = 250, 000 \ N - 250,000 \ N = 0[/tex]
Net horizontal force is calculated as;
[tex]\Sigma F_x = 20,000 \ N[/tex]
for the truck;
Net vertical force is calculated as;
[tex]\Sigma F_y =80,000 \ N - \ 80,000 \ N = 0[/tex]
Net horizontal force is calculated as;
[tex]\Sigma F_x = 26,400 \ N - \ 20,000 \ N = 6,400 \ N \ to \ the \ right[/tex]
"Your question is not complete, it seems to be missing the following information;"
find the net force on each vehicle.
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A car accelerates uniformly in a straight
line from rest at the rate of 3.3 m/s^2
What is the speed of the car after it has
traveled 60 m?
h
Answer in units of m/s.
how Long does it take the car to travel 60m?
answer in units of s
Answer: see below
Explanation:
The intial speed is u=0[tex]\frac{m}{s}[/tex]
The acceleration is a= 3.3[tex]\frac{m}{s}^2[/tex]
The distance is s=60m
Apply the equation of motion
[tex]v^{2}[/tex]=[tex]u^{2}[/tex]+2as
So,
[tex]v^{2}[/tex]=0+2*3.3*60=396
v=[tex]\sqrt{396}[/tex] = 19.89 m/s ≈20 m/s
Applying the equation of motion
v=u+at
t= [tex]\frac{v-u}{a}[/tex] =[tex]\frac{19.89-0}{3.3}[/tex] = 6.02seconds
PLZZZZZZ Help Due tmr
how the x ray use the behavior and characteristics of the electromagnetic wave to function.
Answer:
How do X rays use electromagnetic waves to function?
X-rays are very high-frequency waves and carry a lot of energy. They will pass through most substances, making them useful in medicine and industry to see inside things. An X-ray machine works by firing a beam of electrons at a "target." If we fire the electrons with enough energy, X-rays will be produced.
Explanation:
True or False: Parasites use the host's fluids/tissues for nutrients.
Answer:
true
Explanation:
its true becuse i did this at school today.
A toy car is pushed off a 1.2 meter tall table and lands 3 meters from the base of the table.
A. What was the initial horizontal velocity of the toy car?
B. How long did it take the toy car to hit the ground?
HOPE IT HELPS YOU
CAN YOU BRAINLEST ME
Answer:
w
Explanation:
w
State whether these questions are true or false.
Q1) Distance formula is displacement/time T/F?
Q2)velocity formula is = displacement/time T/F?
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
The given statements are :
Q1) Distance formula is displacement/time T/F?
- False
Q2)velocity formula is = displacement/time T/F?
- True
Rubric for Grading O Activity3. Answer me! Directions: Compare and contrast the scientific method in philosophy and in science. Complete the Venn Diagram below.(10 pts) Scientific Method in Philosophy Scientific Method in Science
Time
This graph shows the results of an experiment where a rubber ball was dropped and the kinetic energy and the potential energy
were tracked. We know that energy can neither be created nor destroyed, only changed in its form. If the blue line shows kinetic
energy and the red line shows potential energy, what can you infer about the relationship between potential and kinetic energy in.
a bouncing ball? Select ALL that apply.
A)
The total amount of energy is always constant.
B)
When potential energy is its highest, kinetic energy is its lowest.
There is a direct relationship between potential and kinetic energy.
D)
When potential energy is its highest, kinetic energy is its highest.
E)
There is an inverse relationship between potential and kinetic energy.
Answer:
A) B) and E)
Explanation:
How am i supposed to know if i should use sin/cos/tan when i have 2 unknowns?
Answer:
a=6.71cm and b= 9.948cm
Explanation:
[tex]\frac{a}{h} = sin(\alpha )\\a=hsin(\alpha )\\\\\\\frac{b}{h} =cos(\alpha )\\b=hcos(\alpha )\\[/tex]
which alpha is 34°
what is the point value for scoring in handball
Answer:
one point
Explanation: trust me :)
If Ms. Ramirez drops a watermelon from the top of the second-floor fire escape outside her room, and it takes 1.5 seconds to hit the ground, calculate the velocity of the watermelon as it hits the ground.
The velocity of the watermelon as it hits the ground is 14.715 m/s.
Given the data in the question;
Since the Watermelon was dropped from rest,
Initial velocity of the Watermelon;[tex]u = 0m/s[/tex]Time taken for the Watermelon to hit the ground; [tex]t = 1.5s[/tex]We know that, Acceleration due to gravity; [tex]g = 9.81 m/s^2[/tex]Now, we determine the velocity of the watermelon as it hits the ground which is the final velocity.
From the First Equation of Motion:
[tex]v = u + at[/tex]
Now, under gravity, acceleration ''a" will Acceleration due to gravity;[tex]g = 9.81m/s^2[/tex], "v" is the final velocity, "u" is the initial velocity and "t" is the time taken.
So, we substitute our values into the equation
[tex]v = 0m/s\ +\ ( 9.81m/s^2\ * 1.5s )\\\\v = ( 9.81m/s^2\ * 1.5s )\\\\v = 14.715 m/s[/tex]
Therefore, the velocity of the watermelon as it hits the ground is 14.715 m/s
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NEED HELP!!!! 11 POINTS!!!
Mia plays soccer for her high school team. Generally, they start practice by stretching. What kind of stretching should they do before they are warmed up?
A.
ballistic stretching
B.
dynamic stretching
C.
flexibility stretching
D.
static-active stretching
PLEASE NO LINKS
The kind of stretching they should do before they are warmed up is dynamic stretching.
What does dynamic stretching mean?
A dynamic stretch is a movement-based type of stretch. It uses the muscle itself to induce stretching. It differs from traditional "static" stretches because the stretch position is not preserved.
Extend your left foot backward, bend your right foot forward and bend it, and rotate left and right to raise your arms to the sky. Or why not stand and add another kind of gentle twist.
Dynamic stretches are based on movement, while static stretches move the joints as much as possible and hold them for a period of time (usually 30-90 seconds).
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An inductor is connected to a 24volts , 50 Hz main supply . If the current through the inductor is 1.5A , calculate the inductance of the inductor. ( Take π = 22/7 )
Explanation:
Correct Answer: Option D
Explanation
X L=V/I=24/1.5=16Ω
L = XL/2πf=16/2π50
= 0.05H
hope this helps you.
Answer:
Hello There!!
Explanation:
I believe the answer is=>5.1 x 10-2H
Here's the explanation:↬
•XL= V/I= 24/1.5= 16Ω
•L= XL/2πf= 16/2π50
So the answer is 0.05H.
hope this helps,have a great day!!
~Pinky~
Please help I'll mark brainliest
Answer:
B. 5Ω
Explanation:
Equivalent resistance between point P and Q
= 3Ω + Tp
Total Parallel resistance, Tp
[tex] \frac{1}{Tp} = \frac{1}{12Ω} + \frac{1}{6Ω} + \frac{1}{4Ω} [/tex]
[tex]\frac{1}{Tp} = \frac{1}{12Ω} + \frac{2}{12Ω} + \frac{3}{12Ω} [/tex]
[tex]\frac{1}{Tp} = \frac{6}{12Ω}[/tex]
[tex]6(Tp) = 12Ω[/tex]
[tex]Tp = \frac{12Ω}{6} [/tex]
[tex]Tp = 2Ω[/tex]
Equivalent resistance between point P and Q
= 3Ω + 2Ω
= 5Ω
inattention hyperactivity and impulsivity are characteristics of
Answer:
ADHD, also called attention-deficit disorder, is a behavior disorder, usually first diagnosed in childhood, that is characterized by inattention, impulsivity, and, in some cases, hyperactivity.
Explanation: