Therefore, the velocity of block A when t=1s is 1.95 ft/s.
Let's first calculate the acceleration of block B. We know that the net force acting on block B is the force of gravity minus the force of friction.
[tex]F_net = mB * a_B\\F_gravity = mB * g\\F_friction = (mu)a * NA\\NA = mA * g\\F_net = F_gravity - F_friction\\F_net = mB * g - (mu)a * NA\\a_B = (F_net) / mB\\a_B = (mB * g - (mu)a * mA * g) / mB\\a_B = g - (mu)a * mA\\\\a_B = 32.2 ft/s^2 - 0.15 * 10 lb / 32.2 ft/s^2 = 31.89 ft/s^2[/tex]
The acceleration of block A is the same as that of block B, since they are connected by a string.
[tex]a_A = a_B = 31.89 ft/s^2\\Vf = Vi + a * t\\Vf_B = Vb1 + a_B * t\\Vf_B = 3 ft/s + 31.89 ft/s^2 * 1 s\\Vf_B = 34.89 ft/s[/tex]
Now, we can use the conservation of momentum to find the velocity of block A.
Initial momentum = Final momentum
[tex]mB * Vb1 + mA * Va1 = mB * Vf_B + mA * Vf_A\\3 lb * 3 ft/s + 10 lb * Va1 = 3 lb * 34.89 ft/s + 10 lb * Vf_A\\Va1 = (3 lb * 34.89 ft/s - 10 lb * Vf_A) / 10 lb[/tex]
At t=1s, we know that block B has moved a distance of
[tex]d_B = Vb1 * t + 1/2 * a_B * t^2\\d_B = 3 ft/s * 1 s + 1/2 * 31.89 ft/s^2 * (1 s)^2\\d_B = 34.89 ft[/tex]
The length of the string is constant, so block A has moved the same distance.
[tex]d_A = d_B = 34.89 ft[/tex]
We can use this distance to find the final velocity of block A:
[tex]d_A = Va1 * t + 1/2 * a_A * t^2[/tex]
34.89 ft = [tex]Va1 * 1 s + 1/2 * 31.89 ft/s^2 * (1 s)^2[/tex]
Va1 = [tex](34.89 ft - 1/2 * 31.89 ft/s^2) / 1 s[/tex]
Va1 = 1.95 ft/s
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a green 10 kg ball is moving 25 m/s hits a non-moving red 15 kg ball. After they hit,the red ball is moving to the right at a 55 degree angle from the green ball's original direction. The green ball is now moving at a 35 degree angle to the left of its original direction. What is the red ball's final speed? what is the green ball's final speed?
The red ball's final speed is 3 m/s.
The green ball's final speed is sqrt((20.50 m/s)^2 + (14.29 m/s)^2) = 25 m/s.
Find the speed of the red and green ball.We can start by using conservation of momentum, which states that the total momentum of the system before the collision is equal to the total momentum of the system after the collision.
Let's first find the initial momentum of the system. The momentum of an object is given by its mass times its velocity.
Initial momentum = (mass of green ball) x (velocity of green ball) + (mass of red ball) x (velocity of red ball)
Initial momentum = (10 kg) x (25 m/s) + (15 kg) x (0 m/s) (since the red ball is not moving initially)
Initial momentum = 250 kg m/s
After the collision, the green ball is moving at a 35-degree angle to the left of its original direction. We can use trigonometry to find the x and y components of its velocity.
x component of velocity = (magnitude of velocity) x cos(angle)
x component of velocity = (25 m/s) x cos(35 degrees)
x component of velocity = 20.50 m/s
y component of velocity = (magnitude of velocity) x sin(angle)
y component of velocity = (25 m/s) x sin(35 degrees)
y component of velocity = 14.29 m/s
So the final velocity of the green ball can be represented as a vector (20.50 m/s, 14.29 m/s) at a 35-degree angle to the left of its original direction.
Now, let's find the final velocity of the red ball. We know that it is moving to the right at a 55-degree angle from the green ball's original direction. Again, we can use trigonometry to find the x and y components of its velocity.
x component of velocity = (magnitude of velocity) x cos(angle)
x component of velocity = (magnitude of velocity) x cos(55 degrees)
y component of velocity = (magnitude of velocity) x sin(angle)
y component of velocity = (magnitude of velocity) x sin(55 degrees)
We don't know the magnitude of the velocity, but we can use the conservation of momentum to find it. The final momentum of the system is also equal to 250 kg m/s (since there are no external forces acting on the system).
Final momentum = (mass of green ball) x (velocity of green ball) + (mass of red ball) x (velocity of red ball)
Final momentum = (10 kg) x (20.50 m/s) + (15 kg) x (magnitude of velocity)
Final momentum = 205 kg m/s + 15(magnitude of velocity)
250 kg m/s = 205 kg m/s + 15(magnitude of velocity)
45 kg m/s = 15(magnitude of velocity)
magnitude of velocity = 3 m/s
So the final velocity of the red ball can be represented as a vector (3 m/s, 2.69 m/s) at a 55-degree angle to the right of the green ball's original direction.
To summarize:
The red ball's final speed is 3 m/s.
The green ball's final speed is sqrt((20.50 m/s)^2 + (14.29 m/s)^2) = 25 m/s.
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Air enters a nozzle steadily at 2.21 kg/m^3 and 40 m/s and leaves at 0.762 kg/m^3 and 180 m/s. If the inlet area of the nozzle is 90 cm,^2 , determine(a) the mass flow rate through the nozzle, and(b) the exit area of the nozzle
Air enters a nozzle steadily at 2.21 kg/m³ and 40 m/s and leaves at 0.762 kg/m³and 180 m/s. If the inlet area of the nozzle is 90 cm²,
(a) the mass flow rate through the nozzle is 0.7986 kg/s
(b) the exit area of the nozzle is 0.00582 m².
(a) To determine the mass flow rate through the nozzle,
we need to multiply the density of the air at the inlet (2.21 kg/m³) by the velocity of the air at the inlet (40 m/s) and the inlet area (90 cm²).
First, let's convert the inlet area from cm² to m²:
90 cm² = 90 * 0.0001 m²
= 0.009 m²
Now we can calculate the mass flow rate:
[tex]Mass flow rate = density * velocity * area[/tex]
Mass flow rate = 2.21 kg/m^3 × 40 m/s × 0.009 m^2
Mass flow rate = 0.7986 kg/s
So, the mass flow rate through the nozzle is 0.7986 kg/s.
(b) To find the exit area of the nozzle, we can use the mass flow rate and the exit conditions (density and velocity) provided.
First, we can rearrange the mass flow rate equation to solve for the exit area:
[tex]Exit area = mass flow rate / (exit density * exit velocity)[/tex]
Now, plug in the given values:
Exit area = 0.7986 kg/s / (0.762 kg/m^3 × 180 m/s)
Exit area = 0.7986 kg/s / 137.16 kg/(m^2 s)
Exit area ≈ 0.00582 m^2
The exit area of the nozzle is approximately 0.00582 m^2.
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Consider a pipe of length 60 m in which saturated steam at 300°C is flowing. The pipe is made of copper with thermal conductivity k = 400 W/(m.K). The inner and outer diameters of the pipe are D; = 26 cm and D. = 32 cm, respectively. Outside of the pipe 1 we have air at a temperature To= 20°C and natural convective heat transfer coefficient h= 5 W/(m²K). The cooling of the pipe by air causes some of the steam inside the pipe to condense into saturated liquid, but as you know from Thermodynamics, the temperature inside the pipe does not change upon this condensation. a. Find the steady state temperature profile (temperature as a function of radius) within the pipe wall b. What is the rate at which heat is being removed from the pipe by air? c. What is the temperature at the outer surface of the pipe? d. Bonus point (1 point): What is the rate (in kg/s) at which steam is getting condensed within the pipe?
A is the surface area of the pipe, Ts is the temperature at the outer surface of the pipe, and To is the temperature of the air.
What is Temperature?
Temperature is a measure of the average kinetic energy of the particles in a substance, which determines the direction of heat flow. It is a scalar quantity that quantifies the hotness or coldness of an object or a system.
a. To find the steady state temperature profile within the pipe wall, we can apply the steady-state heat conduction equation. Since the pipe is made of copper, which is a good conductor of heat, we can assume one-dimensional radial conduction along the radial direction.
The heat conduction equation in cylindrical coordinates is given by:
∂/∂r (r * k * ∂T/∂r) = 0
where:
r is the radial distance from the center of the pipe
k is the thermal conductivity of copper (given as 400 W/(m.K))
T is the temperature
Considering the inner and outer surfaces of the pipe, we can set up the boundary conditions:
At r = r₁ (inner surface of the pipe): T = 300°C (temperature of saturated steam)
At r = r₂ (outer surface of the pipe): T = Tₒ (temperature of air, given as 20°C)
Solving the heat conduction equation with the given boundary conditions, we can obtain the steady state temperature profile within the pipe wall.
b. The rate at which heat is being removed from the pipe by air can be calculated using the convective heat transfer equation, which is given by:
Q = h * A * (T - Tₒ)
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What things about the resistors in this circuit are the same for all three? A. Current I B. Potential difference Δ V C. Resistance R D. A and B E. B and C
The potential difference across all three resistors in a series circuit is the same, as the voltage from the battery is divided across the resistors in proportion to their resistance values. Therefore, option B (potential difference ΔV) is the same for all three resistors.
The resistance of each resistor is different, so option C is not the same for all three resistors.
The current through each resistor is the same, as there is only one path for the current to flow in a series circuit. Therefore, option A (current I) is the same for all three resistors.
So the correct answer is D, "A and B".
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if you will be a science what would you be and how it will benefit the human race?
Answer:
In other words, science is one of the most important channels of knowledge. It has a specific role, as well as a variety of functions for the benefit of our society: creating new knowledge, improving education, and increasing the quality of our lives. Science must respond to societal needs and global challenges.
to what potential should you charge a 0.600 μf capacitor to store 1.60 j of energy
To store 1.60 j of energy, the capacitor of 0.600 μf must be charged to a potential of 2.31 kV.
To find the potential needed to charge a 0.600 μF capacitor to store 1.60 J of energy, we can use the formula for the energy stored in a capacitor:
Energy (E) = (1/2) × Capacitance (C) × Voltage^2 (V²)
We are given the energy (E = 1.60 J) and the capacitance (C = 0.600 μF), and we need to find the voltage (V).
1. Rearrange the formula to solve for V:
V² = (2 × E) / C
2. Plug in the given values:
V² = (2 × 1.60 J) / (0.600 μF)
3. Calculate the result:
V² = 5.333... (rounded to the nearest thousandth)
4. Take the square root of both sides to find V:
V = √5.333...
5. Calculate the final value for V:
V = 2.31 kV (rounded to the nearest hundredth)
So, you should charge the 0.600 μF capacitor to a potential of 2.31 kV to store 1.60 J of energy.
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An AC voltage of the form Δv = (85.0 V)sin(260t) is applied to aseries RLC circuit. If R = 52.0 Ω, C = 28.0 μF, and L = 0.250 H,find the following.(a) impedance of the circuit Incorrect: ____ Ω(b) rms current in the circuit: _______A(c) average power delivered to the circuit: _____ W
a). Impedance of the circuit Incorrect: Z = 85.9 ohms
(b) Rms current in the circuit: 0.69 A
c) Average power delivered to the circuit: 35.88 W
What does an AC current frequency not include?Due to the fact that DC current is a sort of continuous current, its frequency is 0 hertz. Therefore, AC current is not limited to zero Hz as its rest frequency.
Given : 85 sin(260t)
C = 28mF = 28x 10⁻³ F
Inductance = L = 0.250 H
a) Inductive reactance = X(L) = ω L = (350)(0.2) = 70 ohms
Capacitive reactance = X(C) = 1 / ωC = 0.114 ohms
Reactance = Z = [tex]\sqrt{R^{2} + (X_{L} - X_{C} ) }[/tex]
= [tex]\sqrt{52^{2} +(70 -0.114)^{2} }[/tex]
=85.9
B ) current = I = 85 / 85.9 = 0.98 A
Irms = 0.98 / [tex]\sqrt{2}[/tex] = 0.69 A
c) P = R = (0.69)(52) = 35.88 W
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two speakers, s1 and s2, operating in phase in the same medium produce the circular wave patterns shown in the diagram below. at which two points is constructive interference occurring?
The constructive interference occurs at points A and D.
Constructive interference occurs when two waves superpose (combine) in such a way that their amplitudes add up, resulting in a wave with a higher amplitude. In the case of two speakers operating in phase, where their wave patterns are aligned, constructive interference will occur at specific points where the crests of the waves align.
These points of constructive interference can be determined by examining the distance between the two speakers and the wavelength of the waves they produce. Constructive interference occurs when the path length difference between the two waves is an integer multiple of the wavelength.
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Your question is incomplete, most probably the full question is this:
two speakers, s1 and s2, operating in phase in the same medium produce the circular wave patterns shown in the diagram below. at which two points is constructive interference occurring?
A 0.75-kg mass oscillates according to the equation x(t)=0.21 cos(145t), where the position x(t) is mcasured in meters 25% What is the period, in seconds, of this mass?
The period of a mass oscillating according to the equation x(t)=0.21 cos(145t) is equal to the inverse of the frequency, which is equal to 145. This means that the mass completes one cycle of oscillation every 0.0069 seconds.
Therefore, the period of a mass with a mass of 0.75 kg oscillating according to this equation is equal to 1/145 seconds, or about 0.0069 seconds. This means that the mass oscillates at a frequency of 145 Hz, or cycles per second.
This means that the mass completes a full cycle of oscillation every 0.0069 seconds. Therefore, it takes the mass 0.0069 seconds to move from its maximum position to its minimum position and back again. This is the period of oscillation for the mass.
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what is the commonly expressed equation to describe newton’s second law of motion
The commonly expressed equation to describe Newton's second law of motion is F = m×a.
Newton's second law of motion states that the acceleration of an object is directly proportional to the force applied to it, and inversely proportional to its mass.
Mathematically, this can be expressed as F = ma, where F is the net force applied to an object, m is the object's mass, and a is the resulting acceleration of the object.
In other words, the greater the force applied to an object, the greater its acceleration will be, and the more massive the object is, the less its acceleration will be for a given force.
This law is one of the fundamental principles of classical mechanics and is essential for understanding the behavior of objects in motion.
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An emitter follower, when driven from a 10-k ohm source, was found to have an output resistance Rout of 200 ohm. The output resistance increased to 300 ohm when the source resistance was increased to 20 k ohm. Find the overall voltage gain when the follower is driven by a 30-k ohm source and loaded by a 1-k ohm resistor.
The overall voltage gain of the emitter follower when driven by a 30-k ohm source and loaded by a 1-k ohm resistor is approximately 0.00645 or 0.645%.
To find the overall voltage gain of the emitter follower, we need to first calculate its voltage gain under the given conditions.
The voltage gain of an emitter follower is approximately unity (i.e. 1) as the output voltage follows the input voltage with a small voltage drop across the transistor. Therefore, the voltage gain of the emitter follower is independent of the input signal frequency and is close to unity for all input frequencies.
Now, to calculate the output voltage of the emitter follower when driven by a 30-k ohm source and loaded by a 1-k ohm resistor, we need to use the voltage divider rule.
The output voltage can be calculated as:
Vout = Vin * (Rout / (Rout + Rin + Rload))
Where Vin is the input voltage, Rin is the input resistance (which is equal to the source resistance), and Rload is the load resistance.
Using the given values, we get:
Vout = Vin * (200 / (200 + 30,000 + 1,000))
Vout = Vin * 0.00645
Therefore, the overall voltage gain is 0.00645 or 0.645%.
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to 56.4°c contains pure carbon resistors. what is the percent difference in resistance over this range? the temperature coefficient of resistivity for carbon is −0.500 ✕ 10-3/°c.
tThe percent difference in resistance over this temperature range is 2.82% when coefficient of resistivity for carbon is -0.500 × 10⁻³/°C.
To determine the percent difference in resistance over this range, we need to use the given temperature coefficient of resistivity for carbon, which is -0.500 × 10⁻³/°C. First, we need to find the change in resistance:
ΔR = R × α × ΔT
Where ΔR is the change in resistance, R is the initial resistance, α is the temperature coefficient of resistivity, and ΔT is the change in temperature.
In this case, ΔT = 56.4°C, and α = -0.500 × 10⁻³/°C. We can't find the exact change in resistance without the initial resistance value, but we can still find the percent difference in resistance:
Percent difference = (ΔR / R) × 100
Plugging in the given values:
Percent difference = (R × (-0.500 × 10⁻³/°C) × 56.4°C) / R × 100
The R values cancel out, leaving:
Percent difference = (-0.500 × 10⁻³/°C × 56.4°C) × 100 = -2.82%
The negative sign indicates a decrease in resistance, so the percent difference in resistance over this temperature range is 2.82%.
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a beam of light of wavelength 630 nm is incident on a slit that is 0.400 mm wide. if the distance between the slit and the screen is 1.80 m, what is the width on the screen of the central bright fringe?
The width of the central bright fringe on the screen is approximately 5.67 mm.
To calculate the width on the screen of the central bright fringe, we need to use the equation:
w = (λL)/d
Substituting the given values, we get:
w = (630 nm x 1.80 m)/0.400 mm
w = 2.835 x 10^-3 m or 2.84 mm (rounded to two significant figures)
Width = 2 * (λL / a)
- Width is the width of the central bright fringe on the screen
- λ is the wavelength of light (630 nm or 630 x 10^-9 m)
- L is the distance between the slit and the screen (1.80 m)
- a is the width of the slit (0.400 mm or 0.400 x 10^-3 m)
Width = 2 * (630 x 10^-9 m * 1.80 m) / (0.400 x 10^-3 m)
Width ≈ 0.00567 m or 5.67 mm
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what is the potential energy of 3 charges, each with charge 3 millicoulombs, arranged in a line? the charges are separated from each other by a distance of 1 meters.
1.62x10⁻⁴ J is the potential energy of 3 charges, each with charge 3 millicoulombs by a distance of 1 meters.
To calculate the potential energy of 3 charges arranged in a line, we need to use the formula for electric potential energy by Coulombs law
PE = k×q1×q2/d
where k is Coulomb's constant, q1 and q2 are the charges, and d is the distance between them.
In this case, we have 3 charges of 3 millicoulombs each arranged in a line, separated by a distance of 1 meter. Let's label them as q1, q2, and q3.
The potential energy of q1 and q2 is:
PE1-2 = k×q1×q2/d = (9x10⁹ N×m²/C²)×(3x10⁻³ C)×(3x10⁻³ C)/(1 m) = 8.1x10⁻⁵ J
The potential energy of q2 and q3 is:
PE2-3 = k×q2×q3/d = (9x10⁹ N×m²/C²)×(3x10⁻³ C)*(3x10⁻³ C)/(1 m) = 8.1x10⁻⁵ J
To find the total potential energy of the system, we just need to add the two values:
PE total = PE1-2 + PE2-3 = 2*(8.1x10⁻⁵ J) = 1.62x10⁻⁴ J
Therefore, the potential energy of 3 charges, each with charge 3 millicoulombs, arranged in a line and separated from each other by a distance of 1 meter, is 1.62x10⁻⁴ J.
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Example
We can use the idea of work to help us calculate the braking distance of a car.
A car of mass 1500 kg is travelling at a speed of 20 m/s. The brakes apply a force
of 5000 N to slow down and stop the car.
Calculate the braking distance of the car.
The braking distance of the car from the question is 60 m
What is the braking distance?The braking distance is the distance traveled by a vehicle after the brakes have been applied, until it comes to a complete stop. It is the sum of the thinking distance (the distance traveled by the vehicle while the driver reacts to a hazard and decides to apply the brakes) and the braking distance (the distance traveled by the vehicle while the brakes are being applied to slow it down).
Given that;
F = ma
a = F/m
a = 5000 N/1500 Kg
a = 3.33 m/s^2
Given that;
v^2 = u^2 - 2as
Since v = 0
u^2 = 2as
s = u^2/2a
s = (20)^2/2 * 3.33
s = 60 m
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An object moves with simple harmonic motion on a smooth table. If the amplitude and the period are both doubled, the object's maximum speed is A. Quartered B. Quadrupled C. Doubled D. Unchanged
The maximum speed of the object will double as well.
Simple harmonic motion is a type of motion where the object oscillates back and forth with a constant period and amplitude. The maximum speed of the object occurs when it passes through the equilibrium point, where its velocity is at its maximum.When the amplitude and period are both doubled, the motion of the object becomes more exaggerated, meaning that it will oscillate over a greater distance and take longer to complete one cycle. However, the maximum speed of the object will still occur at the equilibrium point, where the acceleration is at its maximum.
Since the period is doubled, the time it takes for the object to complete one cycle is also doubled. This means that the object will spend twice as much time at the equilibrium point, where its maximum speed occurs. Therefore, the maximum speed of the object will double as well.
So, the correct answer is C. Doubled.
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2a. to find the electric field at point p, first find the magnitude of electric field at point p due to each charge. (express your answer in terms of 10-6 k.)
The given units of 10^-6 k, the electric field would be expressed as N/C x 10^-6 k, where N/C is the standard unit for electric field.
To find the electric field at point P, you need to first find the magnitude of the electric field at point P due to each charge. This can be done using Coulomb's Law, which states that the magnitude of the electric field at a point is directly proportional to the magnitude of the charge and inversely proportional to the distance squared between the charge and the point.
So, if you have multiple charges, you would calculate the electric field due to each one individually, and then add up the vectors to get the net electric field at point P.
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A particle moves 5m in the positive x direction while being acted upon by a constant force vec F = (4 N) cap i + (2 N) cap j ? (4N) cap k. The work done on the particle by this force is: A. 20 J B. 10 J C. -20 J D. 30 J E. Is impossible to calculate without knowing other forces
The work done on the particle by the force F is 20 J. Answer A is correct.
The work done on the particle by the force F can be calculated using the formula:
[tex]W = F \int ds[/tex]
where F is the force vector and ds is the displacement vector. Since the force is constant, we can simplify this to:
[tex]W = F . \int ds[/tex]
where [tex]\int ds[/tex] is the displacement vector. In this case, the particle moves 5m in the positive x direction, so we have:
[tex]\int ds = 5 \hat{i}[/tex]
Substituting this into the equation for work, we get:
W = F · 5 [tex]\hat{i}[/tex]
where F is the force vector given as:
F = (4 N) [tex]\hat{i}[/tex] + (2 N) [tex]\hat{j}[/tex] − (4 N) [tex]\hat{k}[/tex]
Taking the dot product of F and 5[tex]\hat{i}[/tex], we get:
[tex]F . 5 \hat{i} = (4 N) (5) + (2 N) (0) - (4 N) (0)\\\\ = 20 J[/tex]
Choice A is correct.
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Please I need help finding this answer in this textbook!!!
ASAP
In Racial Formations, race is defined as a socio historical concept, what does that mean
to the authors? Do you agree with this definition why or why not? Explain how race is
socially constructed or strictly biological. Support your response with two paragraphs.
Yes I agree and the socio historical concept implies that race is created and maintained through systems of power and inequality.
What is race?According to Michael Omi and Howard Winant, in Racial Formations, race is a socio-historical concept that is constructed through the intersection of cultural, political, and economic forces.
In this book, they argue that race is not an immutable, biologically determined characteristic of individuals or groups but rather a social construct that is created and maintained through systems of power and inequality. The authors illustrate how race is constructed through examples from different historical periods and social contexts.
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calculate the linear acceleration of a car, the 0.310-m radius tires of which have an angular acceleration of 15.5 rad/s2. assume no slippage and give your answer in m/s2.
the linear acceleration of a car, the 0.310-m radius tires of which have an angular acceleration of 15.5 rad/s2 is 4.805 m/s².
To calculate the linear acceleration of a car with 0.310-meter radius tires and an angular acceleration of 15.5 rad/s², you can use the following formula:
Linear acceleration (a) = Radius of tires (r) × Angular acceleration (α)
Step 1: Identify the given values
- Radius of tires (r) = 0.310 meters
- Angular acceleration (α) = 15.5 rad/s²
Step 2: Use the formula to calculate the linear acceleration
a = 0.310 m × 15.5 rad/s²
Step 3: Calculate the result
a = 4.805 m/s²
The linear acceleration of the car is 4.805 m/s².
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the transfer of 100 kj of heat to a large mass of water at 0°c (273 °k) results in change in entropy, δs, of how much in j/°k?
In this case, q = 100 kJ and T = 273 K, so: δs = (100 kJ) / (273 K) = 0.366 kJ/K. The change in entropy (δs) of the transfer of 100 kJ of heat to a large mass of water at 0°C (273 K) can be calculated using the formula δs = q/T, where q is the heat transfer and T is the temperature in Kelvin.
Therefore, the change in entropy (δs) for the transfer of 100 kJ of heat to a large mass of water at 0°C is 0.366 kJ/K. This means that there is an increase in the randomness or disorder of the system due to the transfer of heat.
It is important to note that entropy is a state function, meaning that the change in entropy is independent of the path taken to achieve that change.
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a 7.000 turn coil carries has a radius of 9.800 cm and a magnetic moment of 6.500 x 10-2 am2. what is the current through the coil?
The current through the coil is 13.91mA.
What is the carrying capacity of the 18 cm diameter, 250 turn circular coil?
Current of 12a is carried through a circular coil with 250 turns and an 18 cm diameter. How Strong a Magnetic Moment Is There When the Coil Is Connected? -- Physics. Current carrying capacity is 12A in a circle with 250 turns and an 18 cm diameter.
What does a current-carrying coil of radius 10's magnetic field at its centre look like?The magnetic field at a location on the axis of a circular current-carrying coil with a 10 cm radius is 55 times greater than the magnetic field at the coil's centre.
M=I[tex]\pi r^{2}[/tex]
0.065=I3.14*9.8*9.8*7
I=13.91mA
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a 1.000 turn coil carries a 66.000 a current and has a magnetic moment of 5.100 x 10-2 am2. what is the radius of the coil?
The radius of a 1.000-turn coil that carries a 66.000 A current and has a magnetic moment of 5.100 x 10⁻² Am² is approximately 1.568 x 10⁻² meters.
To find the radius of the coil, we will use the formula for the magnetic moment, which is given by:
Magnetic moment (μ) = N * I * A
where N is the number of turns (1.000 turn), I is the current (66.000 A), and A is the area of the coil.
We know the magnetic moment (μ) = 5.100 x 10⁻² Am², so we can solve for the area (A):
A = μ / (N * I) = (5.100 x 10⁻²) / (1.000 * 66.000) = 7.727 x 10⁻⁴ m²
Since the coil is circular, we can use the formula for the area of a circle:
A = π * r²
where r is the radius of the coil.
Now we can solve for the radius (r):
r² = A / π = (7.727 x 10⁻⁴) / π
r² ≈ 2.460 x 10⁻⁴
Taking the square root of both sides:
r ≈ √(2.460 x 10⁻⁴) ≈ 1.568 x 10⁻² m
So, the radius of the coil is approximately 1.568 x 10⁻² meters.
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Use the following steps to prove Kepler's Second Law. The notation is the same as in the proof of the First Law in Section 13.4. In particular, use polar coordinates so that r = (r cos theta)i + (r sin theta)j. (a) Show that h = r^2 d theta/dt k. (b) Deduce that r^2 = d theta/dt = h. (c) If A = A(t) is the area swept out by the radius vector r = r(t) in the time interval [t_0, t] as in the figure, show that dA/dt = 1/2 r^2 d theta/dt (d) Deduce that dA/dt = 1/2 h = constant This says that the rate at which A is swept out is constant and proves Kepler's Second Law. Let T be the period of a planet about the sun: that is, T is the time required for it to travel once around its elliptical orbit. Suppose that the lengths of the major and minor axes of the ellipse are 2a and 2b. (a) Use part (d) of Problem 1 to show that T = 2 pi ab/h. (b) Show that h^2/GM = ed = b^2/a. (c) Use parts (a) and (b) to show that T^2 = 4 pi^2/GM a^3. This proves Kepler's Third Law. [Notice that the proportionality constant 4 pi^2/(GM) is independent of the planet.]
We also know from Kepler's Second Law that the rate at which area is swept out by the radius vector is constant, which means dA/dt is constant. Therefore, we can deduce that 1/2 h is constant.
What is Velocity?
Velocity is a vector quantity that describes the rate of change of displacement of an object with respect to time. It is defined as the change in displacement per unit of time and includes both magnitude (speed) and direction. Velocity is typically denoted by the symbol "v" and is measured in units of distance per time, such as meters per second (m/s) or kilometers per hour (km/h).
d(theta)/dt = h/[tex]r^{2}[/tex]
Now, recall that the area A swept out by the radius vector r in a time interval dt is given by:
dA = (1/2)[tex]r^{2}[/tex] d(theta)
Taking the derivative of both sides with respect to time t, we get:
dA/dt = (1/2)[tex]r^{2}[/tex]d(theta)/dt
Substituting the expression for d(theta)/dt from above, we get:
dA/dt = (1/2)[tex]r^{2}[/tex] (h/[tex]r^{2}[/tex])
Simplifying, we get:
dA/dt = 1/2 h
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a 1700 kgkg car drives around a flat 200-mm-diameter circular track at 35 m/sm/s .What is the magnitude of the net force on the car?
We can calculate the net force: F_net = 1700 kg * 12.25 m/s^2 = 20,825 N So, the magnitude of the net force on the car is 20,825 N.
The magnitude of the net force on the car can be calculated using the formula F = ma, where F is the net force, m is the mass of the car, and a is the acceleration of the car. To find the acceleration, we can use the formula a = v^2/r, where v is the speed of the car and r is the radius of the circular track (which is half the diameter).
So, first we need to convert the diameter to radius by dividing it by 2:
r = 200 mm / 2 = 100 mm = 0.1 m
Then, we can calculate the acceleration:
a = v^2/r = (35 m/s)^2 / 0.1 m = 12,250 m/s^2
Finally, we can calculate the net force:
F = ma = (1700 kg)(12,250 m/s^2) = 20,825,000 N
Therefore, the magnitude of the net force on the car is approximately 20,825,000 N.
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calculate the final velocity right after a 115 kg rugby player who is initially running at 7.95 m/s collides head‑on with a padded goalpost and experiences a backward force of 17900 n for 5.50×10−2 s.
The final velocity right after a 115 kg rugby player collides head‑on with a padded goalpost is approximately 0.61 m/s backwards.
To calculate the final velocity of the rugby player after the collision, we need to use the impulse-momentum theorem. The equation for this is:
Impulse = Change in momentum
Impulse = Force × Time
Change in momentum = Mass × Change in velocity
Given values:
Initial velocity (v₁) = 7.95 m/s
Mass (m) = 115 kg
Force (F) = -17900 N (backward force)
Time (t) = 5.50 × 10⁻² s
First, we'll find the impulse:
Impulse = Force × Time
Impulse = -17900 N × 5.50 × 10⁻² s
Impulse ≈ -984.5 kg·m/s
Now, we'll find the change in momentum:
Change in momentum = Impulse
Change in momentum = -984.5 kg·m/s
Next, we'll calculate the change in velocity:
Change in velocity = Change in momentum / Mass
Change in velocity ≈ -984.5 kg·m/s / 115 kg
Change in velocity ≈ -8.56 m/s
Finally, we'll find the final velocity (v₂):
v₂ = Initial velocity + Change in velocity
v₂ = 7.95 m/s - 8.56 m/s
v₂ ≈ -0.61 m/s
So, the final velocity of the rugby player right after the collision is approximately -0.61 m/s (negative sign indicates the backward direction).
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Two different fluorescent probes are attached to separate sites on a protein: A ( λ ex =388 mm;λ em =475 mm) and B(λ er =483 nm;λ em =538 mm). The value of R0 is 64AThe following data are obtained. Fluorescence intensity of A in the absence of B: 160 units Fluorescence intensity of A in the presence of B:156 units At this efficiency, what is the distance between the probes? 117.86 A
64 A
0 A
34.75 A
˚
The distance between the probes is given as 117.86 A
How to solve for the distanceWe are given that the fluorescence intensity of probe A decreases from 160 units in the absence of probe B to 156 units in the presence of probe B. This decrease in intensity is due to the energy transfer from probe A to probe B. The efficiency of energy transfer can be calculated using the following equation:
E = 1 - (I_AB / I_A)
where I_AB is the fluorescence intensity of probe A in the presence of probe B and I_A is the fluorescence intensity of probe A in the absence of probe B.
Substituting the given values, we get:
E = 1 - (156 / 160) = 0.025
Now we can calculate the distance between the probes:
R = 64 A * [(1/0.025) - 1]^(1/6) = 117.86 A
Therefore, the distance between the probes is approximately 117.86 A.
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carbon 14 has a half-life of 5715 years. how much carbon 14 is left after 6,451 years, given that the initial mass is q0 = 492 grams? (write the answer with 2 exact decimals).
After 6,451 years, there would be approximately 124.05 grams of carbon 14 left, the time elapsed since the start of the half-life (in this case, 736 years), T is the half-life (5,715 years), and q0 is the initial mass (492 grams.
calculated as follows:
First, we need to determine how many half-lives have passed during the 6,451 years. To do this, we divide the time elapsed by the half-life:
6,451 years / 5,715 years per half-life = 1.13 half-lives
This means that 1 half-life has fully elapsed, and we're partway through the second half-life.
To calculate how much carbon 14 is left after 1 half-life, we use the formula:
q = q0 / 2
where q is the amount of carbon 14 remaining and q0 is the initial mass. In this case, q0 = 492 grams, so after 1 half-life (5,715 years), we have:
q = 492 / 2 = 246 grams
Now we need to calculate how much further decay occurs during the remaining 1/13th of a half-life. To do this, we use the formula:
q = q0 * (1/2)^(t/T)
where t is the time elapsed since the start of the half-life (in this case, 736 years), T is the half-life (5,715 years), and q0 is the initial mass (492 grams). Plugging in these values, we get:
q = 492 * (1/2)^(736/5,715) = 124.05 grams
Therefore, after 6,451 years, approximately 124.05 grams of carbon 14 would remain, assuming an initial mass of 492 grams.
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find the total work done
The total work done by the gas from D to E to F is 450J
How to solveTo calculate the total work done by the gas as it undergoes a change in state from point D to point E to point F, we need to consider the changes in pressure and volume.
The change in pressure (DF) is determined by subtracting the initial pressure of 300 N/m^2 from the final pressure of 600 N/m^2, resulting in a pressure difference of 300 N/m^2.
Similarly, the change in volume (FE) is calculated by subtracting the initial volume of 2.0 m^3 from the final volume of 5.0 m^3, resulting in a volume difference of 3.0 m^3.
Using the formula for the area of a triangle, we can determine the work done by the gas during the process.
The area of triangle DEF is half of the product of the pressure difference and the volume difference, which results in a value of 450 J.
Therefore, the total work done by the gas from D to E to F is calculated as 450 J
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is it possible for an application to run slower when assigned 10 processors when assigned 8?
Yes, it is possible for an application to run slower when assigned 10 processors compared to when it is assigned 8 processors.
This is because the application may not be optimized to effectively use all 10 processors, leading to increased overhead and decreased performance. Additionally, if the system is not able to effectively manage the workload distribution across all 10 processors, it can lead to congestion and decreased performance. Therefore, it is important to consider the specific requirements of the application and the capabilities of the system before assigning a specific number of processors.
This can happen due to factors such as poor parallelization, overhead, and diminishing returns. To optimize the application's performance, it is crucial to ensure efficient use of the available processors and manage parallel tasks effectively.
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