Based on your observations, which of the following factors affect the trajectory of an object or body in flight? Select all that apply. Projection angle Mass of the object Size (diameter) of the object Height of the object at take-off Initial velocity

The distance at which the charged sphere must be placed is 35.38 *10⁻⁹ m.

Fe is the electrostatic force experienced.

The weight mg of the particle can be resolved into two components as

mg sinθ along the inclined plane and mg cosθ perpendicular to the plane.

Applying Newton's second law along incline direction,

∑ F = m* a

Fe - mg sin 28° = 0

Fe = mg sin 28°

1/(4π∈₀) q₁* q₂/x² = mg/2

9* 10⁻⁹ * (4* 10⁻⁶ * 4*10⁻⁶)/x² = (2.3 * 10⁻³* 10)/2

x² * 2.3 * 10⁻² = 18* 16* 10⁻²¹

x² = (18* 16* 10⁻¹⁹)/2.3

x² = [18* 16/ 0.23]* 10⁻¹⁸

x = 35.38 *10⁻⁹ m

Thus, the distance from centre to centre is 35.38 *10⁻⁹ m.

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(a) The act of a chicken scratching the ground is doing positive work.

(b) A person studying does no work.

(c) A crane lifting a bucket of concrete does positive work.

(d) The gravitational force on the bucket in part (c) does negative work.

(e) When a person sits down, their leg muscles are said to be doing negative work.

We are aware of the work equation as being the result of force and displacement.

(a) The work done will be positive as the chicken is scratching the ground. Here, the displacement is along the direction of force.

(b) As there is no displacement, work done is zero, learning the language of physics is not work.

(c) The crane uses the bucket to perform positive work, and the displacement in this case is in the force's direction.

(d) The force of gravity pulls the bucket downward. In this case, the work completed will be negative because the forces acting on the bucket are in opposition to one another.

(e) Since the muscle's applied force are opposite to the displacement, negative work will be done.

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If the vehicle strikes ice at the circle's base, 150N will cause it to move.

The International Bureau of Weights and Measures defines it as the mass of a certain international prototype constructed of platinum-iridium and stored there. Initially, it was specified as being equal to the mass of one liter (10-3 cubic meters) of pure water. A mass of 1 kilogram weighs roughly 2.20 pounds at the surface of the Earth (lb).

The metric system's fundamental unit of mass is the kilogram (kg). The mass of 1,000 cubic centimeters of water is very nearly equal to one kilogram, although it was initially intended to be exactly equal. The precise definition of a pound is 0.45359237 kg.

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Let's imagine we have a 10 tonne barge with 100 tonnes of iron because when the barge is sitting in the lock loaded with iron the buoyancy (upthrust) of the water must balance the weight of the barge.

There will be 110 tonnes of upthrust, or 110,000 kg. Since water has a density of 1 kg/l, the amount of water that the loaded barge will move is also 110,000 kilograms, or 110,000 liters. Now toss the iron into the water. It is currently resting on the mud at the lock's base. The barge will continue to move 10 tons, or 10,000 lb, of water because it is still afloat.

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Observables of certain elliptical galaxies with shells of stars surrounding them that are likely developed from stars ripped out of smaller galaxies is the evidence supports the idea that a collision between two spiral galaxies might lead to the creation of a single elliptical galaxy.

That most of the galaxy populations at the centers of dense clusters of galaxies are made up of elliptical galaxies, studies of a few eccentric galaxies with central stars and gas clouds that orbit differently from the galaxy's other stars. Observations of massive, elliptical galaxies that may have developed by consuming other galaxies at the heart of dense clusters. A galaxy is a collection of stars, stellar remains, interstellar gas, dust, and dark matter that are gravitationally bonded together. The name comes from the Greek word galaxias, which means "milky" and refers to the Milky Way galaxy, which houses the Solar System. Galaxies, which contain an average of 100 million stars, range in size from dwarfs, which contain fewer than 100 million stars, to supergiants, which contain 100 trillion stars, all of which orbit the galaxy's center of mass. Only a small percentage of the mass in a normal galaxy is visible in the form of stars and nebulae; the majority of the galaxy's mass is dark matter. Supermassive black holes are a typical component of galaxy centers.

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The effect on the period of a pendulum if you double its length is the period increases by a factor of √2 and  if you decrease its length of a pendulum by 5.00% the period decreases by 2.5%.

A pendulum has an initial period of 2π√L/ g and then it has some new period T2 which is 2π√L2/g

(a) Give that L2 = 2L1

So we'll substitute in 2L1 in place of L2

T2 = 2π√2L1/g = √2T1

So when doubling the length, the period increases by a factor of √2

(b) Given that length of a pendulum decreases by 5.00%

Then length of remaining pendulum = L2 = 95% L1= 0.95L1

T2=  2π√L2/g =  2π√0.95L1/g = √0.95T1 = 0.975T1

Hence it decreases by  2.5%.

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At -272.997°C the nitrogen molecules will have an rms speed of 1.5 m/s

The speed of gas molecules is the speed experienced by gas particles based on their average speed. Molecular velocity is a representation of the overall value of the speed of gas molecules moving in a vessel.

Given that

The molecular mass of nitrogen is m = 28(1.66x 10⁻²⁷ kg) = 4.6 x 10⁻²⁶ kg

The speed ​​rms formula is

vrms = √[(3kT)/m]

So, the temperature

T = (v)²(m)/(3k)

T = (1.50 m/s)²(4.6 x 10⁻²⁶ kg)/(3(1.38 x 10⁻²³K)

T = (2.25 m/s) (4.6 x 10⁻²⁶ kg)/(4.14 x 10⁻²³K)

T = 10,35 x 10⁻²⁶/4.14 x 10⁻²³K

T = 2,5 x 10⁻³

T = 00025 K.

T = 2.5 mK

in °C

T = -272.997°C

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Answer: 0.0541

Explanation:

If the car took a time of 74.4 seconds to complete one lap around a circular track, the circumference of the track is 50.0 m/s * 74.4 s = <<50.0*74.4=3720>>3720 m.

The radius of the circular track is half the circumference, so it is 3720/2 = <<3720/2=1860>>1860 m.

The acceleration of a body moving in a circle with constant speed is given by the formula a = v^2/r, where a is the acceleration, v is the speed, and r is the radius of the circle.

Therefore, the magnitude of the acceleration of the car is 50.0^2/1860 = <<50.0^2/1860=0.0541>>0.0541 m/s^2

Answer:

Approximately 2.4 x 10^-8 N.

Explanation:

The force acting on the smaller object can be calculated using the formula for gravitational force:

F = G * (m1 * m2) / d^2

Where F is the force, G is the gravitational constant (6.674 x 10^-11 N * m^2 / kg^2), m1 is the mass of the smaller object (1.5 kg), m2 is the mass of the larger object (6.0 x 10^24 kg), and d is the distance between the two objects (6.4 x 10^6 m).

Substituting these values into the formula, we get:

F = 6.674 x 10^-11 * (1.5 * 6.0 x 10^24) / (6.4 x 10^6)^2

We can simplify this expression by dividing both sides by 6.0 x 10^24 to get:

F / 6.0 x 10^24 = 6.674 x 10^-11 * (1.5 / (6.4 x 10^6)^2)

Then we can simplify the right-hand side by performing the calculations in parentheses:

F / 6.0 x 10^24 = 6.674 x 10^-11 * (1.5 / (6.4 x 10^6)^2)

               = 6.674 x 10^-11 * (1.5 / 41.6 x 10^12)

               = 6.674 x 10^-11 * 3.6 x 10^-13

Finally, we can multiply both sides by 6.0 x 10^24 to get the value of the force acting on the smaller object:

F = 6.0 x 10^24 * (6.674 x 10^-11 * 3.6 x 10^-13)

 = 2.4 x 10^-8 N

Therefore, the size of the force acting on the smaller object is approximately 2.4 x 10^-8 N.

Answer:

4.5125m

Explanation:

Initial Velocity(U)=9.5m/s

Maximum Horizontal Distance (i.e maximum height) = ?

V^2=U^2-2gH (negative because the motion is against gravity i.e g is negative)

0^2=9.5^2-(2×10×H)

0=90.25-20H

20H=90.25

H=90.25/20=4.5125m

Answer: 2 m/s. v = Δx/Δt = (12 m)/(6 s)

At an angle of 33 degrees, the ray leaves the second mirror.

As per the below-attached figure:

The light beam is reflected at A, incident on the first plane at XA, and then incident on the second plane at XB, where it is again reflected as BY.

The law of reflection is the idea that when light rays strike a smooth surface, the angle of incidence and the angle of reflection are both identical. Additionally, the incident ray, the reflected ray, and the surface normal all reside in the same plane.

From the law of reflection of angle:

angle : BAO = θ = 34 degree

It is also given that,

Angle ABO = φ

Angle AOB = 113 degree

As in a triangle,

The sum of all three angles must be 180 degrees.

So, we can write it as:

∴θ+φ+113=180

φ=180-113-34= 33 degree.

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The required diagram is attached below:

A 55-kg lady stands on a bathroom scale inside an elevator. the scale reads 45 kg. Lift is going downward is the motion of the elevator.

An object changing its position with regard to time is referred to as motion. Motion is mathematically characterized in terms of displacement, distance, velocity, acceleration, and speed as well as the observer's frame of reference and the measurement of the change in the body's position with respect to that frame over time. Kinematics is the area of physics that studies how motion is affected by forces, whereas dynamics is the area that studies how motion is affected by forces. An object is said to be at rest, motionless, immobile, stationary, or to have a constant or time-invariant location with respect to its surroundings if it is not changing with respect to a certain frame of reference. Objects, bodies, matter particles, matter fields, radiation, radiation fields, radiation particles, curvature, and space-time are only a few examples of physical systems where motion is applicable. One may also discuss the movement of borders, shapes, and images. The word "motion" often refers to a continual change in the positions or arrangement of a physical system in space. One can discuss the motion of a wave or a quantum particle, for instance, where the configuration is the likelihood that the wave or particle would occupy a particular place.

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A cartridge is removed from the chamber by the extractor mechanism, and is then ejected by the ejector.

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The proton's speed as it passes through point P is 1.66×10⁶ m/s.

The proton's speed at point P can be determined by the equation:

KE = PE + ( mv²/2 )

where,

KE= kinetic energy

PE = potential energy

m = mass of the proton

v = speed of the proton.

Given

Proton's initial speed is v₀ = 2.8×10⁶ m/s

By putting the values in the question the solution is as follows so as the Proton's speed at point P can be calculated as:

v = √(2KE/m)

= √(2 ×2.8 × 10⁶ m/s² / 1.67 × 10⁻²⁷ kg)

= 1.66 × 10⁶ m/s

Therefore, the proton's speed as it passes through point P is 1.66×10⁶ m/s.

Your question is incomplete most probably your full question was

A proton follows the path shown in (Figure 1) . Its initial speed is v0 = 2.8×106 m/s.What is the proton's speed as it passes through point P?Express your answer to two significant figures and include the appropriate units.

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The correct statement is 'x₂ will shift the estimated value of y either by 0 units or by β₂ units.'

Given that,

y = β₀ + β₁ x₁ + β₂ x₂

where,

x₂ is the binary predictor

A binary predictor is a categorical random variable in the regression analysis which can take only two values. These variables typically fall into one of two groups, 0 or 1, depending on the variable.

If such binary variables are employed in the study, the regression line's intercept can take two values from two different categories.

Consider, x₂ = 0,1, we get two equations with same slope but different intercepts.

y₀ = β₀ + β₁ x₁ + β₂ (0) = β₀ + β₁ x₁

y₁ = β₀ + β₁ x₁ + β₂ (1) = (β₀ + β₂) + β₁ x₁

The two equations reflect the shift in the regression line by β₂ units relative to basic equation.

The question is incomplete as it does not contain options. They are ' A. x₂ would be a significant predictor if β₂ = 423.72.

B. x₂ will shift the estimated value of Y either by 0 units or by β₂ units.

C. x₂ = 0, x₂ = 1, x₂ = 2 would be appropriate if three categories exist .

D. x₂ = 1 should represent the most desirable condition.'

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A boy who is 1 meter tall requires a mirror that is at least 0.50 m tall in order to see his entire height.

The mirror must be at least half as long as the individual is tall in order for them to see their entire reflection. In order to make it simpler for the person to see themselves in the mirror.

Given that the boy's height (h) = 1 m,

the mirror's height should be h/2 = 1/2 = 0.50 m.

Behind the glass of a mirror, people can see an image of themselves. This image is created when light rays hit the shining surface and reflect or bounce back, creating a "mirror image." Glass can be made into a mirror that reflects light by having a bright metal coating on one side. Mirrors can reflect 95% of the light that hits them, whereas window glass can only reflect 8% of the light that hits it.

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We would change the acetylation of histones and increase the phosphorylation of histones in cancer cells that are over-expressing oncogenes.

A gene which has the potential to cause cancer is called as an oncogene. These genes are frequently altered or highly expressed in tumor cells. Once key functions are disrupted and gone haywire, the majority of conventional cells can survive a predetermined type of quick death. The transcription apparatus is given dynamic access to a genome that would otherwise be firmly packaged thanks to chromatin remodeling, which is a key factor in the regulation of gene expression. According to broad consensus, chromatin remodeling factors control how cellular components interact with target DNA; as a result, any disruption or dysregulation of these special machinery is anticipated to alter the transcriptome status in a malignant state.

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Answer:

0.003 mi/s²  

Explanation:

a = (Vf - Vi) / t

Vi = 0 (started from rest)

First you have to convert MPH into miles/sec (the problem did not state that you have to convert to meters/sec)

(80 miles/hr)/(3600 sec/hr) = 0.022 mi/sec

a = (0.022 mi/sec - 0)/8 sec = 0.003 mi/s²  

Answer:

Question 1.  50 m

Question 2.  80 kg

Question 3.  750 N

Question 4.  80 m

Explanation:

Here are some equations that we might have to use.

[tex]F_{Cnet} =m*a_c\\F_{Cnet} =\frac{m*v^2}{r}\\a_c=\frac{v^2}{r}\\a_c=\frac{F_{Cnet} }{m}\\m=\frac{F_{Cnet} }{a_c}\\m=\frac{F_{Cnet} *r}{v^2} \\r=\frac{m*v^2}{F_{Cnet} }\\r=\frac{v^2}{a_c}[/tex]

Question 1

We are given

[tex]m=700\\v=20\\F_{Cnet}=5600[/tex]

We will use [tex]r=\frac{m*v^2}{F_{Cnet} }[/tex]

[tex]r=\frac{700*20^2}{5600}[/tex]

[tex]r=50[/tex]

Question 2

We are given

[tex]r=25\\v=15\\F_{Cnet} =720[/tex]

We will use [tex]m=\frac{F_{Cnet} *r}{v^2}[/tex]

[tex]m=\frac{720*25}{15^2}[/tex]

[tex]m=80[/tex]

Question 3

We are given

[tex]m=900\\v=5\\r=30[/tex]

We will use [tex]F_{Cnet} =\frac{m*v^2}{r}[/tex]

[tex]F_{Cnet} =\frac{900*5^2}{30}[/tex]

[tex]F_{Cnet} =750[/tex]

Question 4

We are given

[tex]m=800\\v=40\\F_{Cnet}=16000[/tex]

We will use [tex]r=\frac{m*v^2}{F_{Cnet} }[/tex]

[tex]r=\frac{800*40^2}{16000}[/tex]

[tex]r=80[/tex]

Hopefully this helps! A rating/review would be much appreciated! :)

The δs∘rxn  for the reaction  2NO(g)+O₂(g) → 2NO₂(g) is -146 J/K.

Entropy is a scientific concept and observable physical feature that is typically associated with a state of chaos, unpredictability, or uncertainty.

The unpredictability or chaos of the system would be gauged by entropy. As unpredictability rises, so does entropy. It has a state function as well as a wide range of attributes. The unit is present J⁻¹ K mol⁻¹ .

ΔS°rxn = 2 mol × S°(2NO(g) - S°O₂(g) - 1mol S°O₂

ΔS°rxn = 2 mol × 240 J/mol.K - 2 mol × 210 J/mol.K-1 mol  ×205.2 J/mol.K

ΔS°rxn = -146.8 J/K

Therefore, the δs∘rxn  for the reaction 2NO(g)+O₂(g)→2NO₂(g)  would be -146 J/K.

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Jupiter is a gas giant with no solid surface so it needs airships floating houses or spacecraft to live on.

Jupiter is the fifth planet from the Sun and the largest planet in the solar system. It is a gas giant with a mass more than two and a half times that of all the other planets in the Solar System combined, but slightly less than one-thousandth the mass of the Sun.

Jupiter's magnetic field traps charged particles from the Sun and Mars's volcanic moon Io. These particles create intense radiation belts. The radiation belt around Io's orbit is powerful enough to kill an unprotected human within minutes. It's easy to see with your eyes if you know when and where to look.

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There is no such thing as an ideal machine because no machine is 100 % efficient.

Hence option D is the correct option.

For a machine to be ideal, machine should follow many criteria the machine should be frictionless and the work input must always be equal to the work output.

In reality, no machine is an ideal machine as every machine involves friction. There is no machine without friction. Friction is a necessity in our life. Without friction, we can not survive. Friction helps us to walk and even stop. Friction is like oxygen, it has vital importance in our life. Hence no machine is friction-free and friction causes wear and tear in machines. Similarly, no machine is 100 % efficient. There is always some energy loss in the process, so work input is never equal to the work output.

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The belt of constellations through which all the planets move is called the Zodiac. The zodiac belt runs along the plane of the ecliptic.

The Zodiac is the belt of constellations that all the planets pass through. The sun and moon are also always within this belt. The ecliptic occurs when they appear to move ordinarily along on the particular path through the sky. On the path of the ecliptic, those are 13 astronomical constellations:

In the fifth century B.C., astronomers identified the 12 astronomical constellations as zodiac signs without Ophiuchus. Ophiuchus did not fit into the ancient calendar of 12 lunar months. As a result, the astronomers omitted Ophiuchus for practical reasons.

Astronomy studies the constellations of the zodiac. So, the constellations of the zodiac are not astrology, which is concerned with personal characteristics (zodiac signs differ with zodiac constellations). In the past, they assisted in the creation of calendars and served to track the time period and the seasons for ancient people. They are still applied today for scientific observations and maritime navigation. For example, they serve as excellent reference points for amateur astronomers when trying to find planets.

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The availability of the a galactic nucleus inside a galaxy experiencing starbursts can slow or stop the starburst process.

Due to "increasing financial concerns," Mars Wrigley quietly pulls Starburst candies from grocery shelves throughout Australia. An popular Australian lollipop brand got dropped by a US confectionery business after one social media user noticed her favorite delicacy was inexplicably gone while looking for it.

22 years after being renamed, Starburst will become Opal Fruit, according to a statement from the candy's manufacturer, Mars. Stores including Poundland, B&M, Home Bargains, Iceland, Savers, and others will sell the goods for fans to purchase.

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Bright fringes occurs to the distances between bright spots (intensity maxima) on the screen if the spacing between the slits is doubled.

Diffraction is the interference or bending of waves via an aperture into the area that is geometrically in the shadow of the obstruction or aperture. Effectively, the wave's secondary source is the diffracting element or aperture. The term "diffraction" was created by Italian scientist Francesco Maria Grimaldi, who also made the first precise observations of the phenomena in 1660. The wavefront's phase contributions are projected at an infinite number of spots (three are depicted) along length d, leading to a continually changing intensity on the registration plate. The Huygens-Fresnel principle, which views each point in a propagating wavefront as a collection of unique spherical wavelets, describes the diffraction phenomenon in classical physics. As seen in the enclosed figure, the distinctive bending pattern is most obvious when a wave from a coherent source (like a laser) comes into contact with a slit or aperture that is roughly the same size as its wavelength. This results from the addition or intensity maxima of various wavefront points (or, alternatively, each wavelet) that follow pathways to the registering surface of varying lengths.

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The mass of the planet from this information. 3.56×10²⁶ Kg. A planet's gravitational pull on other bodies determines its weight (or mass).

Every piece of matter in the cosmos is drawn to one another by a gravitational force that is proportionate to its mass, according to Newton's Law of Gravitation. A balance is what you would use to measure mass. A triple beam balance or an electronic balance may be used in the lab to measure mass, but the traditional balance shown below could help you understand what mass is. This is significant because a planet's atmosphere has a direct impact on its climate. The mass of the planet in issue will consequently affect where the "habitable zone" surrounding a star is located.

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frequency is inversely proportional to the length. So, the magnitude of the final frequency is 341 Hz

Frequency can be defined as the number of complete revolution per second made by a vibrating body.

Given that a guitar string has its length shortened to 3/4 of its initial length. if the original frequency was 256 Hz, what will the final frequency be ?

Experiment shows that frequency is inversely proportional to the length of the string. That is, F [tex]\alpha[/tex] 1/L

F = V/L

V = FL

Since the speed of the sound is the same, we can say

F1L1 = F2L2

Where

Substitute all the parameters

256L = 3L/4 × F2

The L cancels out

256 = 3/4 × F2

F2 = 4/3 × 256

F2 = 1024/3

F2 = 341.3 Hz

Therefore, the final frequency will be 341.3 Hz

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The characterized the sound of the second wave of hip-hop, as characterized in the work of run-dmc and the beastie boys is that it is second wave.

S-waves (secondary waves or shear waves) are a swaying, rolling motion that rocks the ground back and forth perpendicular to the direction of the wave and lasts more slowly.

Wave – A secondary body wave that vibrates the ground perpendicular to the direction of wave propagation. They travel about 1.7 times faster than P waves. S-waves cannot travel through liquids such as water, lava, and the outer core of the Earth because liquids cannot withstand shear stress.59.903

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As a result, it can be concluded that block C must have a mass of at least 39 kg in order for blocks A and B to continue sliding past one another when the system is freed from rest.

Relative motion between two things or materials is resisted by friction, a force. Surface roughness, deformations, and molecule adhesion are the causes of this resistive force.

Rolling friction, beginning friction, and sliding friction are the three types of friction that exist between the car's tires and the road, and they are all what allow us to operate cars at all.

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