Assuming barber wants to setup a saloon in a measuring length of 3m by 3m. He has a simple wooden chairs,3 large mirror and one bulb. Using the knowledge of shadows and reflection, advice the barber on how to arrange a good saloon using the only item he has. Without adding more source of light, how can he enhance the lighting system in his saloon?​

+ X axis.

The equation for torque is:
[tex]\tau = r \times F[/tex]

Torque is the CROSS-PRODUCT of 'r' and 'F'.

We can use the right-hand rule to determine the direction of torque.

Looking at the diagram, with an open hand, point your fingers towards the top of the picture (Along the +Z axis in the direction of the 'r' vector.)

Then, curl your fingers in the direction of the force vector, (along the -Y axis).

Your thumb will stick out in the direction of the torque, or the +X axis.

You can also just eliminate any options that involve axes that have already been used for 'r' and 'F'. In this case, there are components in the Z and Y axis, so this leaves the 'X' axis to be considered.

The mechanical energy of the baseball when it is at a height of 9.0m is 39.7 N.

The mechanical energy of the bat is in the form of potential energy.

At a height of 9.0m, the potential energy of the ball = 0.45 * 9.81 *

Potential energy = 39.7 N

In conclusion, the mechanical energy of the baseball bat is the potential energy at that height.

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Answer:

See below

Explanation:

x axis components

  5 cos 37   +   10 cos  53  = 5(.8) + 10(.6)  = 1.0 units     x-axis

y axis components

 5 sin 37     + 10 sin 53 =  5(.6) + 10 (.8) = 1.1  units      y- axis

The correct answer for the magnitude of the sum of vector is (i) along x-axis is [tex](\sqrt{10})^2[/tex]  and (ii) along y-axis is  [tex](\sqrt{11})^2[/tex] .

Given:

Vector A magnitude: 5 units,

angle of inclination with x-axis = 37°.

Vector B magnitude:  10 units.

angle of inclination with x-axis = 53°.

Sum of vectors along x-axis:

AB = [tex]\sqrt{5cos37^o +10cos53^o }[/tex]

= [tex]\sqrt{(5*(0.8))^2+(10*(0.6))^2}[/tex]

[tex]= (\sqrt{10})^2[/tex]

Along y-axis:

AB =[tex]\sqrt{5sin37^o +10cos53^o }[/tex]

[tex]\sqrt{5(0.6) +10(0.8) }\\\\= (\sqrt{11})^2[/tex]

Magnitude along x-axis and  along y-axis is [tex]10[/tex] and [tex]11[/tex] respectively.

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Centripetal force causes the water on the lettuce to come off the lettuce and go to the walls of the bowl.

Centripetal force is the force that is necessary to keep an object moving in a curved path and that is directed inward toward the center of rotation. This force can move the body in the circular direction.

So we can conclude that Centripetal force causes the water on the lettuce to come off the lettuce and go to the walls of the bowl.

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The force that causes the water on the lettuce to come off the lettuce and go to the walls of the bowl is the centrifugal force.

The centrifugal force is the force that force that tends to throw an object out of the circular path. It is the opposite of the centripetal force which tends to keep the object in the circular path.

Hence. the force that causes the water on the lettuce to come off the lettuce and go to the walls of the bowl is the centrifugal force.

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Answer:

1/6 m/s^2      ( about 1/6th gravity of Earth ( 9.81 m/s^2)

Explanation:

Displacement =  yo  +  vo t  - 1/2 a t^2

      -  3.2          = 0     +  0     - 1/2 a(2.0)^2

      -     3.2       =                -2a

             a = 3.2 / 2 = 1.6 m/s^2

An astronaut is on the moon. He drops a hammer from a height of 3.2metres and it takes 2.0 seconds to reach the lunar landscape. Then the acceleration due to gravity of the moon is 1.6 m/s².

Gravity, which derives from the Latin word gravitas, which means "weight", is a basic interaction in physics that causes all objects with mass or energy to attract one another. The electromagnetic force, the weak interaction, and the strong interaction are all significantly stronger than gravity, which is by far the weakest of the four fundamental interactions. As a result, it has no appreciable impact on subatomic particle level phenomena. However, at the macroscopic level, gravity is the most important interaction between objects and governs the motion of planets, stars, galaxies, and even light.

Sublunar tides in the oceans are created by the Moon's gravity, much as gravity on Earth imparts weight to physical things (the analogous antipodal tide is generated by inertia).

according to kinematics,

S = ut + 1/2 at²

initial velocity is zero

S = 1/2 at²

putting all the values,

3.2 = 1/2a2²

6.4/4 = a

a = 1.6 m/s²

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The magnitude of the vector C is 96.32m

Ax = AcosθA

= 40 cOS 20

= 37.59

Ay = AsinθA

-40sin20

= -13.68

Bx = B cos θ B

= 75Cos50

= 48.21

By = BsinθB

= 75sin50

= 57.45

Cx = AX + Bx

= 37.59 + 48.21

= 85.8

Cy = Ay + By

= -13.65 + 57.45

= 43.77

The magnitude is solved by

|c| = [tex]\sqrt{Cx^{2}+Cy^{2} }[/tex]

= √85.8² + 43.77²

= 96.32m

The magnitude of the vector c is 96.32m

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The portion that shows a decreasing velocity is  D to E.

The position time graph is used to describe the motion of a body. We know that the slope of a velocity time graph is the velocity of the graph.

If we look at the graph as shown in the image attached to the answer, we can see that the portion that shows a decreasing velocity is  D to E.

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Answer:

D - E

Explanation:

hope this help

Answer

its c

Explanation:

When resistors are connected in parallel combination the voltage drop across each resistor is same. However , the total current gets branched into different amount .

Question :

— What must be the same for two resistors that are connected in parallel ?

AnswEr :

Option B seems to be correct answer .

The tension in rope C is determined as 122.23 N.

The tension in rope C is calculated as follows;

B² = A² + C²

C² = B² - A²

C² = (752²) - (742²)

C² = 14,940

C = √14,940

C = 122.23 N

Thus, the tension in rope C is determined as 122.23 N.

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Light behaves as it relates to its nature (waves or particles). light travels as and interacts with matter as wave particles.

Electromagnetic radiation that is within the region of the electromagnetic spectrum that the human eye can see is referred to as light or visible light.

The main characteristics of light include intensity, polarization, frequency or wavelength spectrum, and propagation direction. One of the fundamental constants of nature is its speed in a vacuum, which is 299 792 458 meters per second (m/s).

Light can be categorized according to two theories: the first categorizes light as particles, and the second categorizes light as waves.

The main difference between the wave and particle natures of light is that the former asserts that light can act as an electromagnetic wave while the latter asserts that light is made up of tiny particles known as photons.

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Answer: 1.waves 2.particles

Explanation: just did it!<3

The speed and pressure at another end will be 9 m/sec and -31500 pascals.

The difference between absolute pressure and atmospheric pressure is known as gauge pressure. Relative pressure is another name for gauge pressure.

Given data in problem is;

For horizontal pipe, Z₁=Z₂

Pressure at end 1, P₁ = 4500Pa

Speed at end 1, V₁ = 3 m/sec

Speed at end 2, V₂ = ? m/sec

Area of cross-section at end 1,A₁ =A

Area of cross-section at end 1,A₂ = A/3

From the continuity equation;

A₁V₁=A₂V₂

A× 3  = (A/3)×V₂

V₂ = 9 m/sec

From Bernoulli's equation;

[tex]\rm \frac{P_1}{\rho g} + \frac{v_1^2}{2g} +Z_1 = \frac{P_2}{\rho g} + \frac{v_2^2}{2g} +Z_2 \\\\ \frac{P_1-P_2}{\rho g } = \frac{v_2^2-v_1^2}{2g} \\\\ \frac{P_1-P_2}{\rho} = \frac{v_2^2-v_1^2}{2} \\\\ \frac{4500-P_2}{1000} = \frac{9^2-3^2}{2} \\\\ 4500 -P_2 = 36000 \\\\ P_2 = - \ 31,500 \ pa[/tex]

Hence the speed and pressure at another end will be 9 m/sec and -31500 pascals.

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Answer:

• black hole     -   one of the most dense objects in the universe

• red giant       -    a very large star

• white dwarf   -   an old, very dense hot star that is cooling

• nebula           -   a mass of gas and dust

Answer:

See below

Explanation:

Set up your pendulum

  measure its length  and time the period ( you could time 100 of them and divide the time result by 100 to get the period, T)

    then use  

             T = 2 pi  sqrt (L/g)        T = period    L = length   g = gravity

Answer:

F = - F x       force acting on cube

F = -106 N/n * .14 m = -14.8 N         direction opposite to force

a = F / m = -14.8 N / .66 kg = -22.5 m/s^2        acceleration of cube

direction is towards equilibrium point (opposite F)

The molar mass of ammonium sulphate [(NH4)2SO4] is 132.17 g (option E). Details about molar mass can be found below.

The molar mass of a substance can be calculated by adding the atomic masses of the elements in the compound.

According to this question, the atomic mass of nitrogen is given as 14.01, hydrogen is 1.01, sulfur is 32.07, and oxygen is 16.00.

The molar mass of ammonium sulphate is as follows:

[(NH4)2SO4] = [14.01 + 1(4)]2 + 32.07 + 16.00(4)

= 36.02 + 32.07 + 64

= 132.09

Therefore, the molar mass of ammonium sulphate [(NH4)2SO4] is 132.17 g.

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APA not implemented early on for research on humans and these ethics of research in place because there was no stable and widely accepted system of research.

This is referred to a writing style used by American Psychological Association in reasearches etc.

There was no stable method of writing which was the reason why it wasn't used early for researches.

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(a) The voltage that is produced in the secondary circuit is 1,800 V.

(b) The current that flows in the secondary circuit is 1 A.

Np/Ns = Vp/Vs

where;

100/1500 = 120/Vs

Vs = (120 x 1500)/100

Vs = 1,800 V

Is/Ip = Vp/Vs

where;

Is = (IpVp)/Vs

Is = (15 x 120)/1800

Is = 1 A

Thus, the voltage that is produced in the secondary circuit is 1,800 V.

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Answer:

[tex]T_0=80695.17162...[/tex]

Explanation:

Given equation:

[tex]\ln \left(\dfrac{T_0-100}{T_0}\right)=-0.00124[/tex]

To solve the given equation:

[tex]\textsf{Apply log rules}: \quad e^{\ln (x)}=x[/tex]

[tex]\implies \dfrac{T_0-100}{T_0}=e^{-0.00124}[/tex]

Multiply both sides by T₀:

[tex]\implies T_0-100=T_0e^{-0.00124}[/tex]

Add 100 to both sides:

[tex]\implies T_0=T_0e^{-0.00124}+100[/tex]

Subtract [tex]T_0e^{-0.00124}[/tex] from both sides:

[tex]\implies T_0-T_0e^{-0.00124}=100[/tex]

Factor out the common term T₀:

[tex]\implies T_0(1-e^{-0.00124})=100[/tex]

Divide both sides by [tex](1-e^{-0.00124})[/tex]

[tex]\implies T_0=\dfrac{100}{1-e^{-0.00124}}[/tex]

Carry out the calculation:

[tex]\implies T_0=\dfrac{100}{1-0.99876...}[/tex]

[tex]\implies T_0=\dfrac{100}{0.001239231...}[/tex]

[tex]\implies T_0=80695.17162...[/tex]

For a ball that slows down as it rolls up a hill the value of the change in its kinetic energy, ΔEk is: Negative

Kinetic energy can be defined as the ability assumed by an object in motion.

Kinetic energy is also said to be a form of mechanical energy that is possessed by an object to be in motion.

Normally kinetic energy is believed to be positive by when it begins to slow down a negative effect is experienced

In conclusion, For a ball that starts rolling down a ramp the value of the change in its kinetic energy, ΔEk is: Positive

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Answer:

A2/A1 = 9

V2/V1 = 27

Explanation:

Area of Sphere 1; A1 = 4πr²

Volume of Sphere 1; V1 = (4/3)πr³

Area of Sphere 2; A2 = 4π(3r)² = 9*4πr²

Volume of Sphere 2; V2 = (4/3)π(3r)³ = 27*(4/3)πr³

Thus;

A2/A1 = 9*4πr²/4πr² = 9

V2/V1 = [27*(4/3)πr³]/[(4/3)πr³] = 27

Hi there!

Initially, we have gravitational potential energy and kinetic energy. If we set the zero-line at H2 (12.0m), then the ball at the second building only has kinetic energy.

We also know there was work done on the ball by air resistance that decreased the ball's total energy.

Let's do a summation using the equations:
[tex]KE = \frac{1}{2}mv^2 \\\\PE = mgh[/tex]

Our initial energy consists of both kinetic and potential energy (relative to the final height of the ball)

[tex]E_i = \frac{1}{2}mv_i^2 + mg(H_1 - H_2)[/tex]

Our final energy, since we set the zero-line to be at H2, is just kinetic energy.

[tex]E_f = \frac{1}{2}mv_f^2[/tex]

And:
[tex]W_A = E_i - E_f[/tex]

The work done by air resistance is equal to the difference between the initial energy and the final energy of the soccer ball.

Therefore:
[tex]W_A = \frac{1}{2}mv_i^2 + mg(H_1 - H_2) - \frac{1}{2}mv_f^2[/tex]

Solving for the work done by air resistance:
[tex]W_A = \frac{1}{2}(.450)(15.1^2)+ (.450)(9.8)(30.2 - 12) - \frac{1}{2}(.450)(19.89^2)[/tex]

[tex]W_A = \boxed{42.552 J}[/tex]

(a) The angle the plane makes with respect to the horizontal is 27⁰.

(b) The magnitude of the normal force acting on the block is 135.3 N.

(c) The component of the force of gravity along the plane, fgx is 68.96 N.

(d) The expression for the net force on the block is mgsinθ - μmgcosθ = 0.

sin θ = h/L

where;

sin θ = 3.05/6.8

sin θ = 0.4485

θ = arc tan(0.4485)

θ = 26.7⁰

θ ≈ 27⁰

Fₙ = mgcosθ

Fₙ = (15.5)(9.8)cos(27)

Fₙ = 135.3 N

Fx = mgsinθ

Fx = (15.5)(9.8) sin(27)

Fx = 68.96 N

∑F = 0

Fx - Ff = 0

mgsinθ - μmgcosθ = 0

Thus, we can conclude the following;

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Answer:

did you ever the answer?

Explanation:

The time for the javelin in the air will be 3.977 second

The value of time needed to complete the upward and the downward motion is the total period. Its unit is the second and is denoted by t. T is the time at which the ball first hits the ground.

Given data;

Θ is the angle of throw = 43.2°

u is the thrown velocity =  28.5 m/s

t is the  time for the javelin in the air

The time period is found as;

[tex]\rm t = \frac{2u sin \theta }{g} \\\\ t = \frac{ 2 \times 28.5 \ sin 430.2^0}{9.81 } \\\\ t = 3.977 \ sec.[/tex]

Hence the time for the javelin in the air will be 3.977 second

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Answer:

47.24 in

Explanation:

120 / 2.54 = 47.24

The relative pressure at this state is determined as 0.455.

The pressure of the ideal gas given rise to the relative pressure is calculated as follows;

R.P = P2/P1

P2 = P1(R.P)

P2 = 200 kPa x (3.482)

P2 = 696.4 kPa

R.P = (P3)/(P2)

R.P = (320)/(696.4)

R.P = 0.455

Thus, the relative pressure at this state is determined as 0.455.

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The sign (+ or −) and charge of the projectile, if the magnetic force on the projectile is 3.22 10-10 N, directed due west is mathematically given as

q=+1.11524613*10^{−4}C

Generally, the equation for Force is  mathematically given as

[tex]F=Bqvsin\theta[/tex]

Therefore

[tex]3.22 10^{-10}= 5.88 10^{-5 } *633*sin 56*q\\\\q=\frac{3.22 10^{-10}}{5.88 10^{-5 } *633*sin 56}[/tex]

q=+1.11524613*10^{−4}C

In conclusion, the sign (+ or −) and charge

q=+1.11524613*10^{−4}C

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Decrease.

Yes, You weigh less on the equator than at the North or South Pole, but the difference is small.

Note that your body itself does not change.

Rather it is the force of gravity and other forces that change as you approach the poles. These forces change right back when you return to your original latitude.

In short, a trip to the equator is not a viable long-term weight-loss program.

Your weight is the combination of all the large-scale, long-term forces on your body. While the earth's gravity is by far the strongest large-scale force, it is not the only one.

We experience as "something pulling you down" is actually the total of all the forces and not just gravity.

The four dominant large-scale, long-term forces are:

The earth's gravity

The sun's gravity

The moon's gravity

The earth's centrifugal force

Hence, the weight of a body at the equator will be less than at the Poles.

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Karen Horney, a prominent neo-Freudian, believed that Freud's theory showed a masculine bias (Option D).

Freud's theory, also called the psychoanalytic theory,  is a model used in physiology to understand human behavior.

Freud's theory is based on the assumption that human behaviors are mainly controlled by the libido (unconscious) of people.

In conclusion, Karen Horney believed that Freud's theory showed a masculine bias (Option D).

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The maximum acceleration the truck can have so that the refrigerator does not tip over is 4.15 m/s².

The maximum acceleration is obtained by taking clockwise moments about the tipping point of rotation.

Clockwise moment = Anticlockwise moment

Ft * 1.58 m = F * 0.67 m

where

m * a * 1.58 = m * 9.81 * 0.67

a = 4.15 m/s²

The maximum acceleration the truck can have so that the refrigerator does not tip over is 4.15 m/s².

In conclusion, the acceleration of the truck is found by taking moments about the tipping point.

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