Assuming barber wants to setup a saloon in a measuring length of 3m by 3m. He has a simple wooden chairs,3 large mirror and one bulb. Using the knowledge of shadows and reflection, advice the barber on how to arrange a good saloon using the only item he has. Without adding more source of light, how can he enhance the lighting system in his saloon?​

Answers

Answer 1

The best way to arrange the salon to best use what he has is:

Place the bulb in the middle of the wallDirectly face the chair and mirror in front of the bulb for proper lighting and reflectionPlace the chairs side by side of each otherEach mirror should be facing each chai

What is Reflection?

This refers to the change in direction of a wavefront between two different media so that the wavefront returns to its originating medium.

Hence, we can see that from our knowledge of shadows and reflection, we can note that mirrors reflect and light helps to bring detail in a dark area and the chairs should be facing the mirrors directly so the customer can see his hair and how it is being cut by the barber.

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Assuming Barber Wants To Setup A Saloon In A Measuring Length Of 3m By 3m. He Has A Simple Wooden Chairs,3

Related Questions

A sphere of radius r has surface area
A = 4r2and volume V = (4/3r^3) The radius of sphere 2 is triple the radius of sphere 1.

(a)
What is the ratio of the areas, A2/A1?

(b)
What is the ratio of the volumes, V2/V1?

Answers

Answer:

A2/A1 = 9

V2/V1 = 27

Explanation:

Area of Sphere 1; A1 = 4πr²

Volume of Sphere 1; V1 = (4/3)πr³

Area of Sphere 2; A2 = 4π(3r)² = 9*4πr²

Volume of Sphere 2; V2 = (4/3)π(3r)³ = 27*(4/3)πr³

Thus;

A2/A1 = 9*4πr²/4πr² = 9

V2/V1 = [27*(4/3)πr³]/[(4/3)πr³] = 27

Problem 3: A block of mass m= 15.5 kg rests on an inclined plane with a coefficient of
static friction of us = 0.11 between the block and the plane. The inclined plane is L = 6.8 m long and
it has a height of h = 3.05 m at its tallest point.
A. What angle in degrees does the plane make with respect to the horizontal? B. What is the magnitude of the normal force in newtons that acts on the block? C. What is the component of the force of gravity along the plane, fgx in newtons? D. Write an expression in terms of degrees, the mass, the coefficient of the static friction, and the gravitational constant, for the magnitude of the force due to static friction, just before the block begins to slide.

Answers

(a) The angle the plane makes with respect to the horizontal is 27⁰.

(b) The magnitude of the normal force acting on the block is 135.3 N.

(c) The component of the force of gravity along the plane, fgx is 68.96 N.

(d) The expression for the net force on the block is mgsinθ - μmgcosθ = 0.

Angle of the plane with respect to the horizontal

sin θ = h/L

where;

θ is the angle of inclinationh is height of the inclineL is length of the plane

sin θ = 3.05/6.8

sin θ = 0.4485

θ = arc tan(0.4485)

θ = 26.7⁰

θ ≈ 27⁰

Normal force on the block

Fₙ = mgcosθ

Fₙ = (15.5)(9.8)cos(27)

Fₙ = 135.3 N

Parallel component of the force on the plane

Fx = mgsinθ

Fx = (15.5)(9.8) sin(27)

Fx = 68.96 N

Net force on the block

∑F = 0

Fx - Ff = 0

mgsinθ - μmgcosθ = 0

Thus, we can conclude the following;

the angle the plane makes with respect to the horizontal is 27⁰, the magnitude of the normal force acting on the block is 135.3 N,the component of the force of gravity along the plane, fgx is 68.96 N, and the expression for the net force on the block is mgsinθ - μmgcosθ = 0.

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Hello!
I have an equation where I can't really find To (Initial temperature). The equation is from the formula Newton's law of cooling. To is the initial temperature of the object and ln is the natural log. The -0.00124 is the constant k multiplied by the time.
I just need to find the initial temp.

Answers

Answer:

[tex]T_0=80695.17162...[/tex]

Explanation:

Given equation:

[tex]\ln \left(\dfrac{T_0-100}{T_0}\right)=-0.00124[/tex]

To solve the given equation:

[tex]\textsf{Apply log rules}: \quad e^{\ln (x)}=x[/tex]

[tex]\implies \dfrac{T_0-100}{T_0}=e^{-0.00124}[/tex]

Multiply both sides by T₀:

[tex]\implies T_0-100=T_0e^{-0.00124}[/tex]

Add 100 to both sides:

[tex]\implies T_0=T_0e^{-0.00124}+100[/tex]

Subtract [tex]T_0e^{-0.00124}[/tex] from both sides:

[tex]\implies T_0-T_0e^{-0.00124}=100[/tex]

Factor out the common term T₀:

[tex]\implies T_0(1-e^{-0.00124})=100[/tex]

Divide both sides by [tex](1-e^{-0.00124})[/tex]

[tex]\implies T_0=\dfrac{100}{1-e^{-0.00124}}[/tex]

Carry out the calculation:

[tex]\implies T_0=\dfrac{100}{1-0.99876...}[/tex]

[tex]\implies T_0=\dfrac{100}{0.001239231...}[/tex]

[tex]\implies T_0=80695.17162...[/tex]

Why was the APA not implemented early on for research on humans and these ethics of research in place?

Answers

APA not implemented early on for research on humans and these ethics of research in place because there was no stable and widely accepted system of research.

What is APA?

This is referred to a writing style used by American Psychological Association in reasearches etc.

There was no stable method of writing which was the reason why it wasn't used early for researches.

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A cube, whose mass is 0.660 kg, is attached to a spring with a force constant of 106 N/m. The cube rests upon a frictionless, horizontal surface (shown in the figure below).

The cube is pulled to the right a distance A = 0.140 m from its equilibrium position (the vertical dashed line) and held motionless. The cube is then released from rest.

(a) At the instant of release, what is the magnitude of the spring force (in N) acting upon the cube?
________N



(b) At that very instant, what is the magnitude of the cube's acceleration (in m/s2)?

_____ m/s2

(c)
In what direction does the acceleration vector point at the instant of release?
- The direction is not defined (i.e., the acceleration is zero).
-Away from the equilibrium position (i.e., to the right in the figure).
- Toward the equilibrium position (i.e., to the left in the figure).
- You cannot tell without more information.


***Please refer to attached photo

Answers

Answer:

F = - F x       force acting on cube

F = -106 N/n * .14 m = -14.8 N         direction opposite to force

a = F / m = -14.8 N / .66 kg = -22.5 m/s^2        acceleration of cube

direction is towards equilibrium point (opposite F)

A truck is carrying a refrigerator as shown in the figure. The height of the refrigerator is 158.0 cm, the width is 60.0 cm. The center of gravity of the refrigerator is 67.0 cm above the midpoint of the base.
What is the maximum acceleration the truck can have so that the refrigerator doesn't tip over? (The static friction between the truck and the refrigerator is very large.)

Answers

The maximum acceleration the truck can have so that the refrigerator does not tip over is 4.15 m/s².

What will be the maximum acceleration of the truck to avoid tipping over?

The maximum acceleration is obtained by taking clockwise moments about the tipping point of rotation.

Clockwise moment = Anticlockwise moment

Ft * 1.58 m = F * 0.67 m

where

Ft is tipping force = mass * acceleration, aF is weight = mass * acceleration due to gravity, g

m * a * 1.58 = m * 9.81 * 0.67

a = 4.15 m/s²

The maximum acceleration the truck can have so that the refrigerator does not tip over is 4.15 m/s².

In conclusion, the acceleration of the truck is found by taking moments about the tipping point.

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Pls help !!

What must be the same for two resistors that are connected in parallel?
OA. The resistance of each
OB. The voltage drop across each
OC. The power used by each
OD. The current in each

Answers

Answer

its c

Explanation:

When resistors are connected in parallel combination the voltage drop across each resistor is same. However , the total current gets branched into different amount .

Question :

— What must be the same for two resistors that are connected in parallel ?

AnswEr :

When the two resistors are connected in parallel therefore , the Voltage drop across each resistors will be same .

Option B seems to be correct answer .

An extended body (not shown in the figure) has its center of mass at the origin of the reference frame. In the case below give the direction for the torque τ with respect to the center of mass of the body due to force F acting on the body at a location indicated by the vector r.

Options are:
-Y
x
Z
-Z

Answers

+ X axis.

The equation for torque is:
[tex]\tau = r \times F[/tex]

Torque is the CROSS-PRODUCT of 'r' and 'F'.

We can use the right-hand rule to determine the direction of torque.

Looking at the diagram, with an open hand, point your fingers towards the top of the picture (Along the +Z axis in the direction of the 'r' vector.)

Then, curl your fingers in the direction of the force vector, (along the -Y axis).

Your thumb will stick out in the direction of the torque, or the +X axis.

You can also just eliminate any options that involve axes that have already been used for 'r' and 'F'. In this case, there are components in the Z and Y axis, so this leaves the 'X' axis to be considered.

An ideal gas in an isentropic process has an initial pressure of 200 kPa and relative pressure is 3.482; the final pressure is now 320 kPa, find the relative pressure at this state. round to the nearest 3 decimal places

Answers

The relative pressure at this state is determined as 0.455.

Initial pressure of the ideal gas

The pressure of the ideal gas given rise to the relative pressure is calculated as follows;

R.P = P2/P1

P2 = P1(R.P)

P2 = 200 kPa x (3.482)

P2 = 696.4 kPa

New relative pressure

R.P = (P3)/(P2)

R.P = (320)/(696.4)

R.P = 0.455

Thus, the relative pressure at this state is determined as 0.455.

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how mesuremerment of gravity using simple pendulum

Answers

Answer:

See below

Explanation:

Set up your pendulum

  measure its length  and time the period ( you could time 100 of them and divide the time result by 100 to get the period, T)

    then use  

             T = 2 pi  sqrt (L/g)        T = period    L = length   g = gravity

A motor hoists a mass m = 60 kg crate at a constant velocity to a height of h = 5 m in 2 s. If the indicated power of the motor is 3.2 kW, determine the motor's efficiency.

Answers

60% efficiency maybe

Select the correct answer. Which segment of this graph shows a decreasing velocity? Graph representing Time in seconds on the x-axis and position in miles on the y-axis. The line starts at point A (0, 20), and passes points B (20, 20), C (40, 40), D (60, 60), E (80, 60), and F (100, 80) A. A to B B. B to C C. C to D D. D to E E. E to F

Answers

The portion that shows a decreasing velocity is  D to E.

What is a position - time graph?

The position time graph is used to describe the motion of a body. We know that the slope of a velocity time graph is the velocity of the graph.

If we look at the graph as shown in the image attached to the answer, we can see that the portion that shows a decreasing velocity is  D to E.

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Answer:

D - E

Explanation:

hope this help

The farther a star is away from Earth, the more it is

Answers

Answer:

black hole     -   one of the most dense objects in the universe

red giant       -    a very large star

white dwarf   -   an old, very dense hot star that is cooling

nebula           -   a mass of gas and dust

A soccer ball is kicked from the top of one building with a height of H1 = 30.2 m to another building with a height of H2 = 12.0 m.
The ball is kicked with a speed of v0 = 15.10 m/s at an angle of θ = 74.1° with respect to the horizontal. The mass of a size 5 soccer ball is m = 450 g. When the ball lands on the other building, its speed is 19.89 m/s.
1. How much energy was lost to air friction? The ball is kicked without a spin.

Answers

Hi there!

Initially, we have gravitational potential energy and kinetic energy. If we set the zero-line at H2 (12.0m), then the ball at the second building only has kinetic energy.

We also know there was work done on the ball by air resistance that decreased the ball's total energy.

Let's do a summation using the equations:
[tex]KE = \frac{1}{2}mv^2 \\\\PE = mgh[/tex]

Our initial energy consists of both kinetic and potential energy (relative to the final height of the ball)

[tex]E_i = \frac{1}{2}mv_i^2 + mg(H_1 - H_2)[/tex]

Our final energy, since we set the zero-line to be at H2, is just kinetic energy.

[tex]E_f = \frac{1}{2}mv_f^2[/tex]

And:
[tex]W_A = E_i - E_f[/tex]

The work done by air resistance is equal to the difference between the initial energy and the final energy of the soccer ball.

Therefore:
[tex]W_A = \frac{1}{2}mv_i^2 + mg(H_1 - H_2) - \frac{1}{2}mv_f^2[/tex]

Solving for the work done by air resistance:
[tex]W_A = \frac{1}{2}(.450)(15.1^2)+ (.450)(9.8)(30.2 - 12) - \frac{1}{2}(.450)(19.89^2)[/tex]

[tex]W_A = \boxed{42.552 J}[/tex]

A treasure chest full of silver and gold coins is being lifted from a pirate ship to the shore using two ropes as shown in the figure. The mass of the treasure chest is 75.6 kg.
If the tension in rope A is 7.42x10^2 N and the tension rope B carries is 7.52x10^2 N, what is the tension in rope C?

Answers

The tension in rope C is determined as 122.23 N.

Tension in rope C

The tension in rope C is calculated as follows;

B² = A² + C²

C² = B² - A²

C² = (752²) - (742²)

C² = 14,940

C = √14,940

C = 122.23 N

Thus, the tension in rope C is determined as 122.23 N.

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Complete the sentence to describe how light behaves as it relates to its nature (waves or particles). light travels as and interacts with matter as .

Answers

Light behaves as it relates to its nature (waves or particles). light travels as and interacts with matter as wave particles.

What is light?

Electromagnetic radiation that is within the region of the electromagnetic spectrum that the human eye can see is referred to as light or visible light.

The main characteristics of light include intensity, polarization, frequency or wavelength spectrum, and propagation direction. One of the fundamental constants of nature is its speed in a vacuum, which is 299 792 458 meters per second (m/s).

Light can be categorized according to two theories: the first categorizes light as particles, and the second categorizes light as waves.

The main difference between the wave and particle natures of light is that the former asserts that light can act as an electromagnetic wave while the latter asserts that light is made up of tiny particles known as photons.

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Answer: 1.waves 2.particles

Explanation: just did it!<3

anyone solve this for mw urgently please.

Answers

Decrease.

What is the weight on the equator than at the Poles?

Yes, You weigh less on the equator than at the North or South Pole, but the difference is small.

Note that your body itself does not change.

Rather it is the force of gravity and other forces that change as you approach the poles. These forces change right back when you return to your original latitude.

In short, a trip to the equator is not a viable long-term weight-loss program.

Your weight is the combination of all the large-scale, long-term forces on your body. While the earth's gravity is by far the strongest large-scale force, it is not the only one.

We experience as "something pulling you down" is actually the total of all the forces and not just gravity.

The four dominant large-scale, long-term forces are:

The earth's gravity

The sun's gravity

The moon's gravity

The earth's centrifugal force

Hence, the weight of a body at the equator will be less than at the Poles.

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PLEASEEE HELP HELP PLEASE


A 0.450 kg baseball comes off a bat and goes straight up. At a height of 10.0 m, the baseball has a speed of 24.5m/s. Determine its mechanical energy at this height. Show your work

What is the baseball's mechanical energy when it is at a height of 9.0m? Explain your answer.

Answers

The mechanical energy of the baseball when it is at a height of 9.0m is 39.7 N.

What is the mechanical energy of the baseball bat?

The mechanical energy of the bat is in the form of potential energy.

Potential energy = mass * acceleration due to gravity * height

At a height of 9.0m, the potential energy of the ball = 0.45 * 9.81 *

Potential energy = 39.7 N

In conclusion, the mechanical energy of the baseball bat is the potential energy at that height.

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Karen Horney, a prominent neo-Freudian, believed that Freud's theory Select one: A. discounted the importance of dreams. B. disputed that women never experience a phallic stage of development. C. discounted strong unconscious, aggressive desires. D. showed a masculine bias.

Answers

Karen Horney, a prominent neo-Freudian, believed that Freud's theory showed a masculine bias (Option D).

What is Freud's theory?

Freud's theory, also called the psychoanalytic theory,  is a model used in physiology to understand human behavior.

Freud's theory is based on the assumption that human behaviors are mainly controlled by the libido (unconscious) of people.

In conclusion, Karen Horney believed that Freud's theory showed a masculine bias (Option D).

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A ball slows down as it rolls up a hill. What is the value of the change in its kinetic energy, ΔEk?


Positive


Zero


Negative

Answers

For a ball that slows down as it rolls up a hill the value of the change in its kinetic energy, ΔEk is: Negative

Meaning of Kinetic energy

Kinetic energy can be defined as the ability assumed by an object in motion.

Kinetic energy is also said to be a form of mechanical energy that is possessed by an object to be in motion.

Normally kinetic energy is believed to be positive by when it begins to slow down a negative effect is experienced

In conclusion, For a ball that starts rolling down a ramp the value of the change in its kinetic energy, ΔEk is: Positive

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Using appropriate technology, you determine that Earth's magnetic field at your location has a magnitude of 5.88 10-5 T and is directed north at an angle of 56° below the horizontal. You charge a metallic projectile and fire it north with a speed of 663 m/s and at an angle of 14° above the horizontal. Determine the sign (+ or −) and charge of the projectile, if the magnetic force on the projectile is 3.22 10-10 N, directed due west.
C

Answers

The sign (+ or −) and charge of the projectile, if the magnetic force on the projectile is 3.22 10-10 N, directed due west is mathematically given as

q=+1.11524613*10^{−4}C

What is the sign (+ or −) and charge?

Generally, the equation for Force is  mathematically given as

[tex]F=Bqvsin\theta[/tex]

Therefore

[tex]3.22 10^{-10}= 5.88 10^{-5 } *633*sin 56*q\\\\q=\frac{3.22 10^{-10}}{5.88 10^{-5 } *633*sin 56}[/tex]

q=+1.11524613*10^{−4}C

In conclusion, the sign (+ or −) and charge

q=+1.11524613*10^{−4}C

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After washing lettuce, you can dry the water from it using a salad spinner. You put the lettuce in the bowl, and then crank the handle, spinning and drying the lettuce.



From the frame of reference of the lettuce in the spinning strainer, what causes the water on the lettuce to come off the lettuce and go to the walls of the bowl?


The centripetal force


The force of gravity


Newton's first law of motion


The centrifugal force

Answers

Centripetal force causes the water on the lettuce to come off the lettuce and go to the walls of the bowl.

What is centripetal force?

Centripetal force is the force that is necessary to keep an object moving in a curved path and that is directed inward toward the center of rotation. This force can move the body in the circular direction.

So we can conclude that Centripetal force causes the water on the lettuce to come off the lettuce and go to the walls of the bowl.

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The force that causes the water on the lettuce to come off the lettuce and go to the walls of the bowl is the centrifugal force.

What is the centrifugal force?

The centrifugal force is the force that force that tends to throw an object out of the circular path. It is the opposite of the centripetal force which tends to keep the object in the circular path.

Hence. the force that causes the water on the lettuce to come off the lettuce and go to the walls of the bowl is the centrifugal force.

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The atomic mass of nitrogen is 14.01, hydrogen is 1.01, sulfur is 32.07, and oxygen is 16.00. What is the molar mass of ammonium sulphate [(NH4)2SO4]?
A.
63.09 g
B.
84.17 g
C.
114.12 g
D.
118.16 g
E.
132.17 g
Reset Next

Answers

The molar mass of ammonium sulphate [(NH4)2SO4] is 132.17 g (option E). Details about molar mass can be found below.

How to calculate molar mass?

The molar mass of a substance can be calculated by adding the atomic masses of the elements in the compound.

According to this question, the atomic mass of nitrogen is given as 14.01, hydrogen is 1.01, sulfur is 32.07, and oxygen is 16.00.

The molar mass of ammonium sulphate is as follows:

[(NH4)2SO4] = [14.01 + 1(4)]2 + 32.07 + 16.00(4)

= 36.02 + 32.07 + 64

= 132.09

Therefore, the molar mass of ammonium sulphate [(NH4)2SO4] is 132.17 g.

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A step-up transformer has a primary coil with 100 loops and a secondary coil with 1,500 loops. If the primary coil is supplied with a household current of 120 V and 15 A, (a) what voltage is produced in the secondary circuit? (b) What current flows in the secondary circuit?

Answers

(a) The voltage that is produced in the secondary circuit is 1,800 V.

(b) The current that flows in the secondary circuit is 1 A.

Voltage in the secondary coil

Np/Ns = Vp/Vs

where;

Np is number of turns in primary coilNs is number of turns in secondary coilVp is voltage in primary coilVs is voltage in secondary coil

100/1500 = 120/Vs

Vs = (120 x 1500)/100

Vs = 1,800 V

Current in the secondary coil

Is/Ip = Vp/Vs

where;

Is is secondary currentIp is primary current

Is = (IpVp)/Vs

Is = (15 x 120)/1800

Is = 1 A

Thus, the voltage that is produced in the secondary circuit is 1,800 V.

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The stool is 120 cm tall. How tall is it in inches? Note: there are 2.54 cm in 1 inch

Answers

47.24
Work: 120 / 2.54

Answer:

47.24 in

Explanation:

120 / 2.54 = 47.24

The water is flowing through the horizontal constricted pipe. The pressure at one end is 4500Pa, speed is 3m/s and area of cross-section is A, Calculate the speed and pressure at another end where the area of cross-section is A/3.​

Answers

The speed and pressure at another end will be 9 m/sec and -31500 pascals.

What is gauge pressure?

The difference between absolute pressure and atmospheric pressure is known as gauge pressure. Relative pressure is another name for gauge pressure.

Given data in problem is;

For horizontal pipe, Z₁=Z₂

Pressure at end 1, P₁ = 4500Pa

Speed at end 1, V₁ = 3 m/sec

Speed at end 2, V₂ = ? m/sec

Area of cross-section at end 1,A₁ =A

Area of cross-section at end 1,A₂ = A/3

From the continuity equation;

A₁V₁=A₂V₂

A× 3  = (A/3)×V₂

V₂ = 9 m/sec

From Bernoulli's equation;

[tex]\rm \frac{P_1}{\rho g} + \frac{v_1^2}{2g} +Z_1 = \frac{P_2}{\rho g} + \frac{v_2^2}{2g} +Z_2 \\\\ \frac{P_1-P_2}{\rho g } = \frac{v_2^2-v_1^2}{2g} \\\\ \frac{P_1-P_2}{\rho} = \frac{v_2^2-v_1^2}{2} \\\\ \frac{4500-P_2}{1000} = \frac{9^2-3^2}{2} \\\\ 4500 -P_2 = 36000 \\\\ P_2 = - \ 31,500 \ pa[/tex]

Hence the speed and pressure at another end will be 9 m/sec and -31500 pascals.

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A javelin is thrown at 28.5 m/s from flat
ground at a 43.2° angle. How much time
is it in the air?
(Unit = s)
HELP FAST

Answers

Answer:

did you ever the answer?

Explanation:

The time for the javelin in the air will be 3.977 second

What is the period?

The value of time needed to complete the upward and the downward motion is the total period. Its unit is the second and is denoted by t. T is the time at which the ball first hits the ground.

Given data;

Θ is the angle of throw = 43.2°

u is the thrown velocity =  28.5 m/s

t is the  time for the javelin in the air

The time period is found as;

[tex]\rm t = \frac{2u sin \theta }{g} \\\\ t = \frac{ 2 \times 28.5 \ sin 430.2^0}{9.81 } \\\\ t = 3.977 \ sec.[/tex]

Hence the time for the javelin in the air will be 3.977 second

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An astronaut is on the moon. He drops a hammer from a height of 3.2metres and it takes 2.0 seconds to reach the lunar landscape. What is the acceleration due to gravity of the moon?

Answers

Answer:

1/6 m/s^2      ( about 1/6th gravity of Earth ( 9.81 m/s^2)

Explanation:

Displacement =  yo  +  vo t  - 1/2 a t^2

      -  3.2          = 0     +  0     - 1/2 a(2.0)^2

      -     3.2       =                -2a

             a = 3.2 / 2 = 1.6 m/s^2

An astronaut is on the moon. He drops a hammer from a height of 3.2metres and it takes 2.0 seconds to reach the lunar landscape. Then the acceleration due to gravity of the moon is 1.6 m/s².

What is gravity ?

Gravity, which derives from the Latin word gravitas, which means "weight", is a basic interaction in physics that causes all objects with mass or energy to attract one another. The electromagnetic force, the weak interaction, and the strong interaction are all significantly stronger than gravity, which is by far the weakest of the four fundamental interactions. As a result, it has no appreciable impact on subatomic particle level phenomena. However, at the macroscopic level, gravity is the most important interaction between objects and governs the motion of planets, stars, galaxies, and even light.

Sublunar tides in the oceans are created by the Moon's gravity, much as gravity on Earth imparts weight to physical things (the analogous antipodal tide is generated by inertia).

according to kinematics,

S = ut + 1/2 at²

initial velocity is zero

S = 1/2 at²

putting all the values,

3.2 = 1/2a2²

6.4/4 = a

a = 1.6 m/s²

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A vector of magnitube 5 units is inclined at an angle 37° to the x-axis and another vector of magnitube 10 units is inclined at 53° to the x-axis. What is the magnitude of the sumbof the vector components ( i ) along the x-axis ( ii ) along the y-axis? ( sin 37° = cos 53° = 0.6 / sin 53 = cos 37° = 0.8 )

Answers

Answer:

See below

Explanation:

x axis components

  5 cos 37   +   10 cos  53  = 5(.8) + 10(.6)  = 1.0 units     x-axis

y axis components

 5 sin 37     + 10 sin 53 =  5(.6) + 10 (.8) = 1.1  units      y- axis

The correct answer for the magnitude of the sum of vector is (i) along x-axis is [tex](\sqrt{10})^2[/tex]  and (ii) along y-axis is  [tex](\sqrt{11})^2[/tex] .

Given:

Vector A magnitude: 5 units,

angle of inclination with x-axis = 37°.

Vector B magnitude:  10 units.

angle of inclination with x-axis = 53°.

Sum of vectors along x-axis:

AB = [tex]\sqrt{5cos37^o +10cos53^o }[/tex]

= [tex]\sqrt{(5*(0.8))^2+(10*(0.6))^2}[/tex]

[tex]= (\sqrt{10})^2[/tex]

Along y-axis:

AB =[tex]\sqrt{5sin37^o +10cos53^o }[/tex]

[tex]\sqrt{5(0.6) +10(0.8) }\\\\= (\sqrt{11})^2[/tex]

Magnitude along x-axis and  along y-axis is [tex]10[/tex] and [tex]11[/tex] respectively.

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A vector A⃗ has a magnitude of 40.0 m and points in a direction 20.0∘ below the positive x axis. A second vector, B⃗, has a magnitude of 75.0 m and points in a direction 50.0 above the positive x axis. Sketch the vectors A⃗ , B⃗ , and C⃗ =A⃗ +B⃗, and using the component method of vector addition, find the magnitude of the vector C⃗ .

Answers

The magnitude of the vector C is 96.32m

How to solve for the magnitude of vector c

Ax = AcosθA

= 40 cOS 20

= 37.59

Ay = AsinθA

-40sin20

= -13.68

Bx = B cos θ B

= 75Cos50

= 48.21

By = BsinθB

= 75sin50

= 57.45

Cx = AX + Bx

= 37.59 + 48.21

= 85.8

Cy = Ay + By

= -13.65 + 57.45

= 43.77

The magnitude is solved by

|c| = [tex]\sqrt{Cx^{2}+Cy^{2} }[/tex]

= √85.8² + 43.77²

= 96.32m

The magnitude of the vector c is 96.32m

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