A jet plane's acceleration is a critical phase of flight that necessitates intense focus on the part of both pilots.
On the ground, things can get hectic and demand a lot of situational awareness, especially when there is little traffic separation, a runway is wet, visibility is poor, and there are heavy winds. Nevertheless, you start to relax a little and take in the beauty of flying as the engines begin to accelerate and you take off and break through the clouds. We have put up this essay with all you need to know so that you may master the takeoff phase in complete confidence.
You must commit to memory three call-outs for the acceleration and takeoff phases of your flight. You will first check your instruments at 80 knots. When you push the nose of your aircraft upward and rotate in V1, you are too quick to abort the takeoff.
This was merely a succinct justification. In order to help you mentally prepare, we will go over every important stage of a jet plane's acceleration.
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Blossom, the WonderDog, is ambling along at 1.1m/s when she sees a villainous squirrel
enter the yard. If Blossom continuously accelerates at 0.4m/s/s for 3.8 seconds before she
reaches her prey, how far did she travel?
Answer:
7.068m
Explanation:
We have the physics formula [tex]x=x_{0}+v_{0}t+\frac{1}{2}at^{2}[/tex]
[tex]v_{0}=[/tex] 1.1m/s
[tex]x_0=[/tex] 0m
[tex]a=[/tex] 0.4m/s²
[tex]t=[/tex] 3.8sec
Now we plug those values into the formula.
[tex]x=0+1.1(3.8)+\frac{1}{2}0.4 (3.8)^{2}[/tex]
[tex]x=4.18+0.2(14.44)[/tex]
[tex]x=4.18+2.888[/tex]
[tex]x=7.068[/tex]m
Blossom traveled 7.068m.
Hope this helps!
Which of the following objects requires the MOST power to lift?
A. A 2 kg box lifted 1 m in 1 s.
B. A 2 kg box lifted 2m in 1 s.
C. A 2 kg box lifted 1 m in 2 s.
D. A 2 kg box lifted 2 m in 2 s.
The object requires the MOST power to lift a 2 kg box 2 m in 1 s. Hence, option (B) is correct.
What is power?The quantity of energy moved or converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as activity in ancient writings. A scalar quantity is power.
Power required for lifting a 2 kg box 1 m in 1 s = (2×9.8×1)/1 watt = 19.6 watt.
Power required for lifting a 2 kg box 2 m in 1 s = (2×9.8×2)/1 watt = 39.2 watt.
Power required for lifting a 2 kg box 1 m in 2 s = (2×9.8×1)/2watt =9.8 watt.
Power required for lifting a 2 kg box 2 m in 2 s = (2×9.8×2)/2watt =19.6 watt.
So, The most power required in lifting a 2 kg box 2 m in 1 s.
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The specific heat capacities of F2(g), Cl2(g), Br2 (g), and I2 (g) are 0.824, 0.478, 0.225, and 0.145 JK^-1 g^-1, respectively. Compute the molar heat capacities of these elements and identify any periodic trend. If there is a trend, use it to predict the molar heat capacity of astatine, At2(g).
F2(g) = 31.2296, Cl2(g) = 16.9212, Br2 (g) = 35.955, I2 (g) = 18.4005. There is a trend the molar heat capacity of astatine, At2(g) is 167.8 J/molk
Molar heat capacity = At. wt. × specific heat.
Molar heat capacity
F2(g) = 0.824 × 37.9 = 31.2296
Cl2(g = 0.478 × 35.4 = 16.9212
Br2 (g) = 0.225 × 159.8 = 35.955
I2 (g) = 0.145 × 126.90 = 18.4005
There is a trend the molar heat capacity of astatine, At2(g) is 167.8 J/mol.k
A substance's molar heat capacity is the amount of heat needed to elevate a single mole of it by one degree Kelvin. [2] While measuring per mole rather than per gram of substance, molar heat capacity is quite comparable to specific heat capacity. Molar heat capacity (which doesn't change depending on how much substance is there) is an intense property. Joule per mole per Kelvin is the molar heat capacity SI unit. Heat capacity is the amount of energy needed to raise the temperature of a given quantity of material by one degree Celsius. One gram of a substance's heat capacity is referred to as its specific heat capacity (or specific heat), whereas one mole of a substance's heat capacity is referred to as its molar heat capacity.
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which moment corresponds to the minimum kinetic energy of the system? view available hint(s)for part b which moment corresponds to the minimum kinetic energy of the system? a b c d
Option A correlates to the system's least kinetic energy, according to the supplied statement.
Simply put, what is kinetic energy?Kinetic energy is the strength a thing possesses as a product of motion. To drive an object, a charge must be supplied to it. Energy is transmitted to the object once the work is accomplished, at which point it goes at a new, consistent rate.
What are some instances of kinetic energy?Kinetic energy, which may be seen in the motion of an object, particles, or group of particles, is the fuel of motion. Any moving object, such as a woman walking, a baseball being thrown, or a piece of food falling from a table, uses kinetic energy.
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2. the speed of sound in air can be found using the formula: , where t is the celsius temperature. calculate this value and use it as the theoretical value to calculate the % error for your value for the speed of sound.
The speed of sound in air can be found using the formula is v = √γRTM.
The equation for the rate of sound in air v = √γRTM may be simplified to present the equation for the speed of sound in air as a characteristic of absolute temperature.
Calculation:-
v=√γRTM
=√γRTM(273K273K)
=√(273K)γRM√T273K
⇒ 331m.
The relationship of the speed of sound, its frequency, and wavelength is the same as for all waves: vw=fλ, where vw is the rate of sound, f is its frequency, andλ is its wavelength.
The rate of that wind can be measured the use of a device known as an anemometer. An anemometer looks like a weather vane, but as opposed to measuring which route the wind is blowing with hints, it has 4 cups so that it may more accurately degree wind speed.
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a block of mass 3 kg slides down an inclined plane at an angle of p with a massless tether attached to a pulley with mass 1 kg and radius 0.5 m at the top of the incline (see the following figure). the pulley can be approximated as a disk. the coefficient of kinetic friction on the plane is 0.4. what is the acceleration of the block?
A block of mass 3 kg slides down an inclined plane at an angle of p with a massless tether attached to a pulley with mass 1 kg and radius 0.5 m at the top of the incline. The acceleration of the block is a = [m1g(sinΘ - μcosΘ)]/(m1 + 1/2m2).
Formula of acceleration = a bar = (v - v0)/t = delta v / delta t
a bar = average acceleration
v = final velocity
v0 = starting velocity
t = elapsed time
After solving by the formula we get, a = [m1g(sinΘ - μcosΘ)]/(m1 + 1/2m2).
Acceleration refers to the rate at which an object's velocity with respect to time varies. Acceleration is a vector quantity (in that they have magnitude and direction). The direction of an object's acceleration is determined by the direction of the net force acting on it. According to Newton's Second Law, the amount of an object's acceleration is the combined result of two causes: According to the materials used to make the object, the magnitude of the net balance of all external forces acting on it is inversely proportional to its mass, but the magnitude of the net resulting force is directly proportional to the net force.
We are aware that the angle = 45°, the block's mass m1 is 3 kg, and the pulley's mass m2 is 1 kg.
Pulley radius is 0.5 meters, and its coefficient of friction is 0.4.
Four forces are at work on the mass-m1 block:
Weight is represented by m1g, normal response force by N, tension by T, and frictional force by f.
After solving we get acceleration = a = [m1g(sinΘ - μcosΘ)]/(m1 + 1/2m2)
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An airplane flies due north at 176 km/h with respect to the air. There is a wind blowing at 79 km/h to the east relative to the ground. What is the plane's speed relative to the ground? - nearest hundreth
WILL GIVE BRAINLIEST PLEASE HELP
The speed of the plane relative to the ground is obtained as 192.9 m/s.
What is the relative speed?We know that the relative speed can be obtained as the resultant of the speed of the airplane and that of the wind. We have to recall that the relative speed is the single speed that has the same effect in magnitude and direction as two or more speeds acting together.
Now we can write;
R^2 = 176^2 + 79^2
We would now have to take the square root of the both sides so as to obtain the resultant velocity and we now have;
R = √ 176^2 + 79^2
R = 192.9 m/s
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which of the following is not a preventative approach to slowing down the progression of global warming? group of answer choices reducing fossil fuel use removing co2 from smokestack and vehicle emissions repairing leaky gas pipeline infrastructure improving energy efficiency switching from coal to natural gas
Global warming is raised by the emission of greenhouse gases. Therefore, removing CO₂ from smokestack is a preventive approach to slowing down the progression of global warming.
What is global warming?Global warming is a global phenomenon of rising the temperature of earth's atmosphere which in turn have the consequences such as melting of snow, rising sea level etc.
The major cause of global warming is the greenhouse gas effect. Greenhouse gases are carbon, dioxide and methane and oxides of sulfur and nitrogen which are intensely absorbing the heat energy radiating from the earth and maintain the heat in earth itself.
Emission of carbon dioxide and hydrocarbon gases through the burning of fossil fuels causes, the atmospheric temperature to raise up. Therefore ,the removal of CO₂ from the air.
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Based on current evidence, decide whether each of the following statements apply to the concept of dark matter, dark energy, both, or neither. Drag each statement into the appropriate bin. Reset Help the universe contains more of this than it contains matter made from atoms "dark" because it emits only infrared has mass blocks light from stars behind it inferred to exist from the measured acceleration of the universe's expansion the proposed source of a universal repulsive force likely to consist of tiny, weakly interacting particles most common form of mass in the halo of the Milky Way Galaxy detected through its gravitational attraction we do not know what it is made of Dark Matter (only) Both Dark Matter and Dark Energy Dark Energy (only) Neither Dark Matter nor Dark Energy
The statements which apply to the concept of dark matter, dark energy, both, or neither is A)Reset help the universe contains more of this than it contains matter made from atoms "dark" because it emits only infrared.
Dark matter is a speculative type of issue remembered to represent roughly 85% of the matter in the universe. Dark matter is classified "dim" on the grounds that it doesn't seem to communicate with the electromagnetic field, and that implies it doesn't retain, reflect, or transmit electromagnetic radiation and is, in this manner, hard to recognize.
Different astrophysical perceptions - including gravitational impacts which can't be made sense of by right now acknowledged hypotheses of gravity except if more matter is available than should be visible - infer dull matter's presence. Consequently, most specialists imagine that dull matter is plentiful in the universe and has affected its construction and evolution.
The essential proof for dark matter comes from computations showing that numerous cosmic systems would act contrastingly on the off chance that they didn't contain a lot of concealed matter.
Hence, correct option is A.
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(Complete question) is:
Based on current evidence, decide whether each of the following statements apply to the concept of dark matter, dark energy, both, or neither. Drag each statement into the appropriate bin.
A) Reset Help the universe contains more of this than it contains matter made from atoms "dark" because it emits only infrared has mass blocks light from stars behind it inferred
B)to exist from the measured acceleration of the universe's expansion the proposed source of a universal repulsive force likely to consist of tiny.
C)weakly interacting particles most common form of mass in the halo of the Milky Way Galaxy detected through its gravitational attraction we do not know what it is made of Dark Matter (only)
when discussing gravitational force, do we look at the distance between the edges of objects, or the distance between their centers
The distance between two masses is measured between their edges, from their centers, or from one mass's edge to its center.
What do mean by gravitational?This moon's gravitational pull causes water tides to fluctuate over time. strong movement or propensity towards something or someone, whether inherent or external: The reasons why they are drawn to destructive behavior have been the subject of extensive inquiry.
What is gravitational and example?This term force of gravity refers to the force that the earth exerts on a body. Such examples include the downward motion of water in a river, its downward motion of a ball thrown into the air, and also the downward motion of the fruits and leaves that fall from a tree towards the ground.
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a 200g oscillator in a vacuum chamber has a frequency of 1.9 hz . when air is admitted, the oscillation decreases to 60% of its initial amplitude in 50s. How many oscillations will have been completed when the amplitude is 30% of its initial value?
Oscillations will have been completed when the amplitude is 30% of its initial value 236
A = Ao e (bt / 2 m),
Putting each of the values into the equation as a replacement:
A/Ao = e (b t / 2 m)
When A / Ao = 0.60 and t = 50 s, we discover that b is equal to 0.60 when A / Ao = 0.60 and ln (0.60) = b t / 2 m.
B = (2m) ln (0.60) / t B = (.200) (.60) / 50 B =.00409
We discover the following for t when A/Ao = 0.30: 0.30 = e( b t / 2 m) ln (0.30) = (0.00409) t / 2. (0.200)
t = − (0.200) ln (0.30) / 0.00409 t = 118 s
The number of oscillations is thus:
oscillations = f * t=2s-1(118s) = 236
A quantity oscillates repeatedly or periodically when it moves between two or more states or around a central value, which is frequently an equilibrium point. Two typical illustrations of oscillation are an alternating current and a swinging pendulum. Oscillations can be used in physics to model complex interactions like those between atoms.
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2) Several possible forms for the spatial form of the wavefunction for a particle are sketched below. LIST the ones that are not physical, and give a reason for why each one is not. Dashed lines indicate that the wavefunction jumps from one value to the next at a single point. "МА, ДДД
The wavefunction jumps from one value to the next at a single point is mentioned below.
What is wavefunction ?
A particle's wave properties are mathematically described by its wave function, a variable quantity used in quantum physics. The magnitude of a particle's wave function at a certain place in space and time is proportional to the chance that the particle was there at that location at that precise moment.
What is single point ?
A common idealisation of particles in physics is the point particle, also known as an ideal particle, point-like particle, or point-like particle. Its absence of spatial extension, which distinguishes it from other objects since it lacks dimensions, makes it a non-physical object.
1) Second option the wave function cannot be discontinuous therefore this is also different from the actual wave function of the particle.
2) Not be the main function of the particle because this has double valued function at a single value of x and the main function is always single valued therefore this will not be a wave function for a particle to represent the special coordinates of the function.
3) This representation has a peak in it that means the Derivation for first derivative of the particle wave function will have a fixed value that will not be applied for the position of the particle so this will also not be the correct wave function.
Therefore, the wavefunction jumps from one value to the next at a single point is mentioned above.
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A reservoir manometer consists of a U-tube in which the two arms have different diameters, as shown in Fig. 13-1. The diameter on the narrow side is 10.0 mm and the diameter on the reservoir side is 25.0 mm. The liquid in the manometer is oil with a density of 830 kg/m3 and the fluids in contact with the oil are gases of negligible density. The dotted line indicates the level of the oil when the pressures p 1 andp 2 are equal. What is the value ofh whenP 1 -P 2 = 1000 Pa?
A U - tube manometer with two arms of two different diameters and their pressures are given. The value of height h is calculated to be 11 cm.
Given that,
D₁ = 10 mm = 10* 10⁻³ m
D₂ = 25 mm = 25* 10⁻³ m
Density of oil in the manometer ρ = 830 kg/m³
P₁ - P₂ = 1000 Pa
We know the relation between pressure, density of liquid in manometer, height of the liquid column, diameters of the manometer as
Placing in the values of the formula, we have,
P₁ - P₂ = ρ* g* h [ 1 + (10* 10⁻³/25* 10⁻³)²]
1000 = 830* 9.8* h [ 1 + 0.16]
h = 100/(83* 9.8* 1.16) = 100/ 943.5 = 0.11 m = 11 cm
Thus, the value of h is 11 cm.
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You start with some of the right kind of dead material, and heat this material in the right way, perhaps with a little squeezing. As the material changes, you end up with coal, and the name scientists give to the material changes. In order, from coolest (first) to warmest (last) the names given are:
A) Bituminous, peat, lignite, anthracite.
B) Bituminous, lignite, anthracite, peat.
C) Bituminous, anthracite, peat, lignite.
D) Peat, lignite, bituminous, anthracite.
E) Bituminous, anthracite, lignite, peat.D) Peat, lignite, bituminous, anthracite.
Feedback: This is mostly memorization. But the names hide a lot of history, the peat-bog cutters of Ireland, the brown lignites now being mined in Wyoming, the deep-mines and strip-mines of the bituminous coals of western Pennsylvania, West Virginia and elsewhere, and the hard-coal anthracite of the Scranton and Wilkes-Barre region. If you don't know any of this history, you might consider reading up on it a bit; it is fascinating.
Option D; As the material changes, you end up with coal, and the name scientists give to the material changes. In order, from coolest (first) to warmest (last) the names given are: Peat, lignite, bituminous, anthracite.
A form of coal known as bituminous coal, sometimes known as black coal, contains bitumen, also known as asphalt. It can be black or occasionally dark brown in hue, and the seams frequently contain distinct bands of shiny and dull material. Usually, it is rigid but hard. Its quality is graded lower than that of anthracite but higher than that of lignite and sub-bituminous coal. It is the most prevalent type of coal, with deposits found all across the world, frequently in Carboniferous-era strata. Sub-bituminous coal that has been sufficiently buried to reach temperatures of at least 85 °C (185 °F) is converted into bituminous coal.
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Some students are trying to determine whether the radius of a metal sphere affects the amount of charge that it can hold. The students have metal spheres of different radii and known masses that can be attached to a stand by a string, as shown above. The stand is midway between a set of large plates that are connected to a battery to create a nearly uniform electric field in the region between them and near their centers. The students rub a rod with cloth and touch it to each sphere to charge the sphere, and they observe the deflection of the sphere as it is attracted to one plate. They keep adding charge to each sphere until they cannot observe any change in deflection. Which of the following data will give them information that is useful for quantitatively comparing the amount of charge on each sphere?
The number of times they rub the cloth back and forth on the rod
The number of times they touch the rod to the sphere
The string's angle of deflection
The string's angle of deflection is useful for quantitatively comparing the amount of charge on each sphere.
The angles of trajectory that all of your strings take across and behind the nut and saddles of your instrument are, in a nutshell, what is meant by this term. The string's angle, which are located above the headstock, are the downward angles your strings make when they travel through the nut slot, emerge over the fingerboard, and exit the rear edge of the nut to the string wraps on the machine head posts. It is the angle that the string makes at the bridge between your saddle and the spot where the ball end of your string is located.
The string's ability to transfer downward stresses into the guitar is governed by break angles.
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in fig. 30-45, two straight conducting rails form a right angle. a conducting bar in contact with the rails starts at the vertex at time t 0 and moves with a constant velocity of 5.20 m/s along them. a magnetic field with b 0.350 t is directed out of the page. calculate (a) the flux through the triangle formed by the rails and bar at t 3.00 s and (b) the emf around the triangle at that time. (c) if the emf is at n, where a and n are constants, what is the value of n?
(a) The flux through the triangle formed by the rails and bar at t 3.00 s is calculated to be 85.2 Wb.
(b) The EMF around the triangle at that time is 56.8 V.
(c) If the EMF is at n, where a and n are constants, the value of n is 1.
(a) The height of the triangular area enclosed by the rails and bar is the same as the distance traveled in time t. So, we have d = v * t
where, v = 5.2 m/s
We also note that the base of the triangle is the distance between the intersection points of the bar with the rails which is 2 d. The area of the triangle is
A = 1/2 * b * h = 1/2 * 2 v t * v t = v² t²
As the field is said to be uniform B = 0.35 T
The magnitude of flux is given by,
Ф = B * A = 0.35 * v² t² = 0.35 * 5.2² * t² = 9.46 v² t²
At t = 3 s, we get Ф = 85.2 Wb
(b) The magnitude of EMF is
ε = dФ/dt = 9.46 dt²/dt = 18.9 t
At t = 3 s, ε = 18.9 t = 56.8 V
(c) Our solution part of (b) shows, n = 1
The question is incomplete. The attachment shows the figure.
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If we were to characterize how good a material is as an insulator by its resistance to dissipating charge, which of the following two materials is the better insulator? Dry Soil: epsilon_r = 2.5, sigma = 10^-4 (S/m) Fresh Water: epsilon_r = 80, sigma = 10^-3 (S/m)
Fresh water is better material for insulation than dry soil.
The electrons in water are bound by chemical bonds and are therefore unable to take part in conduction. Materials that effectively conduct heat are known as excellent conductors, whereas those that do not are known as bad conductors or insulators. This makes water an insulator.
Given data,
Dry soil ε[tex]_r[/tex] = 2.5, σ =[tex]10^-^4[/tex] s/m
Fresh water ε[tex]_r[/tex] = 80, σ =[tex]10^-^3[/tex] s/m
To test which is a good insulator first we need to calculate the value of Relaxation time constant. Relaxation time constant is given by,
τ[tex]_r[/tex]=ε/σ
Relaxation time constant of Dry soil is:
τ[tex]_r[/tex]=ε/σ
=2.5/[tex]10^-^4[/tex]
=2.5x[tex]10^4[/tex]s
Relaxation time constant of Fresh water is:
τ[tex]_r[/tex]=ε/σ
=80/[tex]10^-^3[/tex]
=8x[tex]10^4[/tex]s
The relaxation time constant is high for Fresh water. Hence, it takes more time to dissipate the charge.
Fresh water is better material for insulation than dry soil.
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a particle is accelerated uniformly from rest to a speed of 50m/s in 5 seconds. the average speed of the particle during the 5 second time interval is question 6 options: 5m/s 10m/s 25m/s 50 m/s
The average speed of the particle during the 5 second time interval isis 25m/s. Option C.
Calculation:-
Let acceleration = a
vi = 0
v1 = 50m /s
f = 5sec
v_{1} = v_{i} + at
a = 10 m/s^2
d = 1/2 a t ^ 2 +vi f
d = 1/2 * 10 *s ^ 2
d = 125m
Vavg = d/t = 125/5 .
Vavg = 25 m/s.
Acceleration is the rate of change of velocity over time, both in terms of velocity and direction. A point or object moving in a straight line accelerates as it accelerates or decelerates. Circumferential motion is accelerated because it always changes direction even at constant velocity.
Acceleration is the change in velocity over time. Whenever a change in velocity or acceleration in the direction of movement occurs. At constant velocity, acceleration is zero. Deceleration is called negative acceleration or deceleration.
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PLS HELP URGENT A moon orbits a planet as shown above.
The moon has a mass 0.66 x 1022 kg and the gravitational field strength at distance R is 0.0012 N/kg. What is the magnitude of the gravitational force exerted by the planet onto the moon while it is in orbit of radius R?
Type your answer in scientific notation with two decimal places. Example: 1.23*10^4
The "magnitude of the gravitational force exerted by the planet onto the moon" (whew!) is just the moon's weight.
Weight = m•g ...... We know both of these
(0.66 x 10^22 kg) • (0.0012 N/kg) =
7.92 x 10^18 Newtons
Steven sets up an experiment as shown below. He found that the bulb did not glow. Which of the following is MOST LIKELY to make the bulb glow?
A. Dropping some metal coins into the water
B. Mixing a few teaspoons of salt into the water
C. Replacing the carbon rods with copper plates
D. Touching the carbon rods to the bottom of the beaker
Answer:
Below
Explanation:
Adding salt to the water will make it CONDUCTIVE and the bulb will then have a complete circuit and possibly glow
Steven sets up an experiment as per the diagram and the bulb is not glowing, so he should mix a few teaspoons of salt into the water. Hence, option B is correct.
What is Electrical energy?Charged material experiences a force when exposed to an electromagnetic field because of the fundamental characteristic of electric charge. It's conceivable for electrical ions to be positive or negative. Two charges that are opposed to one another repel one another.
An object with no net charge is said to be "neutral." Classical electrodynamics refers to the older theory of how charged particles interact, and it is still valid for problems that do not necessitate accounting for quantum phenomena.
The net charge of an isolated system, which is the total of the negative and positive charges, cannot change since electrical current is a conserved property. Electric charge is carried by subatomic particles.
The bulb is not glowing because the conduction of electricity does not take place through pure water, so he needs to put some teaspoons of salt into the water due to which the conduction of electric will take place and the bulb be glowed.
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A particle a traveling along the positive x axis of frame S with speed 0.5c decays into two identical particles, a b b, both of which continue to travel on the x axis. (a) Given that ma = 2.5mb, find the speed of either b particle in the rest frame of particle a. (b) By making the necessary transformation on the result of part (a), find the velocities of the two b particles in the original frame S.
The speed of either b particle in the rest frame of particle by making the nevessory transformation is √1 - 4m²/M² C.
Average velocity is a measure of total displacement divided by total time. The total displacement is the distance between the start and endpoints. Since the car moves from point A at both the start and end points the total displacement is zero and the average velocity is also zero.
Calculation:-
Ub1 = √1 - 4m²/M² C
Ub2 = - √1 - 4m²/M² C
Velocity is the distance traveled per unit of time, the speed of movement. The speed of a car traveling on a smooth, flat section of a highway without traffic congestion is constant and not zero. Acceleration is the rate of change of velocity. The reason is simple. Velocity is the percentage of time an object moves along a path and Velocity is the speed and direction of an object's movement.
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A 500-N parachutist opens his chute and experiences an air resistance force of 800 N. The net force on the parachutist is
300 N upward
When a parachutist opens her parachute after accomplishing terminal speed, in what path does she accelerate.
When a parachutist opens her chute, she slows down. That method she hurries up upward.Once the parachute is opened, the air resistance overwhelms the downward pressure of gravity. The internet pressure and the acceleration at the falling skydiver is upward.
A 500-N parachutist opens his chute and reports an air resistance pressure of 800 N. The internet pressure at the parachutist is. three hundred N upward (Air resistance exerts a pressure withinside the path contrary the path of the movement of the person. So, the internet pressure is 500 N down plus 800 N up, that is three hundred N up
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The upper part of a thunderstorm cloud is normally ____ charged, and the middle and lower parts are ____.​
​positively; positive
​negatively; neutral
​positively; negative
​negatively; positive
​positively; neutral
​positively; negative
The upper part of a thunderstorm cloud is normally positively charged, and the middle and lower parts are negatively charged.
A thunderstorm cloud is a type of dense, vertically towering cloud. They usually produce torrential rain and may cause flash flooding and straight-line winds, but they also may produce bolts of lightning.
Generally, positive charges are accumulating at higher altitudes. The ground (lower parts) normally has a slight negative charge, but when the cloud is directly overhead, the negative charge in the middle of the storm cloud repels the ground underneath, causing the ground to become positively charged.
Lightning happens when the accumulated electric charge in a thunderstorm becomes sufficiently large.
Attached below is an image of a thunderstorm cloud by the NOAA/AOML/Hurricane Research Division.
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part h find the capacitor charge when the current has half the value that you found in part e. express your answer with the appropriate units.
The capacitor charge when the current has half the value is 3.175 uc.
Describe the capacitor.
An electrical component known as a capacitor uses a battery to draw power and stores it. The terminals inside are connected to two metal plates that are spaced apart by a non-conducting material. A capacitor swiftly releases electricity after activation in a very little period of time.
At this point, the capacitor charge will be:
E= 1.739 x [tex]10^{-8}[/tex] J
Qc= [tex]\sqrt{2. 1.739. 10^{-8}. 290. 10^{-6} }[/tex]
Qc= 3.175 x [tex]10^{-6}[/tex]
=3.175 uC
Therefore, the capacitor charge when the current has half the value is 3.175 uc.
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Complete question:
An L-C circuit consists of_ 60.0 mH inductor and 250 pF capacitor The initial charge on the capacitor is 6.00 pC and the initial current in the inductor is 0.600 mA.
Part H Find the capacitor charge when the current has half the value that you found in part E_ Express your answer with the appropriate units.
If a player kicks a football from ground level with a velocity of
27.0 m/s at an angle of 30° above the horizontal, then how
long is the ball in the air?
Use g-9.81 m/s2 for the acceleration due to gravity.
The time for which the football will stay in the air is equal to 2.75 s.
What are velocity components?The projectile travels a parabolic path due to the effect of gravity. No horizontal forces act on it so there is no horizontal acceleration.
The velocity of a projectile has a horizontal component and a vertical component.
The vertical component of the velocity is, [tex]\displaystyle V_y = Vsin\theta[/tex]
The horizontal component of the velocity is, [tex]\displaystyle V_x = Vcos\theta[/tex]
Given the angle θ of the football with the X- axis = 30°
The velocity of the football V = 27 m/s
The Y component of the velocity, Vy = 27× sin30°
Vy = 13.5 m/s
The time for which football is in the air,
T = 2Vy/g = 2×13.5/9.8 = 2.75 s
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Giraffe bending to drink. In a giraffe with its head 2.0m above its heart, and its heart 2.0m above its feet, the (hydrostatic) gauge pressure in the blood at its heart is 250torr.Assume that the giraffe stands upright and the blood density is . In torr (or mm Hg), find the (gauge) blood pressure (a) at the brain (the pressure is enough to perfuse the brain with blood, to keep the giraffe from fainting) and (b) at the feet (the pressure must be countered by tight-fitting skin acting like a pressure stocking). (c) If the giraffe were to lower its head to drink from a pond without splaying its legs and moving slowly, what would be the increase in the blood pressure in the brain? (Such action would probably be lethal.)
The brain (the pressure is enough to perfuse the brain with blood is 33330.5 Pascal and Blood pressure at the brain is 311.666 torr.
Given quantities are
Blood pressure at the heart Ph=250 torr = 250∗133.322 = 33330.5 Pascal as [ 1torr= 133.322 Pa]
Height to the head from its heart hh =2 m
Height to the heart from feet hf =2 m
Density of blood ρ=1.06×103 kg/m3
Blood pressure at the brain
Pb = Ph − hhρg
= 33330.5 + 2*1.06*103*9.8 = 54106.5Pa
Increase in blood pressure
P = Pf − P
b = 405.833 − 94.167 = 311.666 torr
a pressure measurement in the meter-kilogram-second system that is equal to one newton per square meter. The computer programming language Pascal, often known as PASCAL, was created from Algol and is built to handle both textual and numerical data. In the International System of Units, the pascal (Pa) is the unit of pressure or stress (SI). The mathematician and physicist Blaise Pascal is honored by the name of this object. Over a surface area of one square meter, one pascal is equal to one newton (N) of force (m2). French mathematician, philosopher, and physicist Blaise Pascal lived in the 17th century. The syringe, the hydraulic press, the roulette wheel, and an early digital calculator were all inventions credited to him. He made significant advances in atmospheric pressure and established the vacuum above the atmosphere.
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A ball is thrown upwards at time t = 0. The graph shows the variation with
time of the height of the ball. The ball returns to the initial height at time
T.
What is the height h at time t ?
The height at which the half time is provide as the equation in a. Here, the time t is not half of the total time of flight. Thus, the correct equation is option D.
What is horizontal flight?When an object flies to a height t, with a speed and its height depends on the time of travel. There is linear relation with the time of fly and height upto a point in the horizontal flight and after that, the height reduces with time.
Here, height at the exact middle of the plot that is at the half of the time the equation corresponding to the height is
h = 1/2 gt²
But the time given here is not the half of total time and the time can be taken as T-t. Therefore, the equation corresponding to the height of the ball is
1/2 g t (T- t).
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the in situ moisture content of a soil is 15% with saturation level equal to 70% and void ratio of 0.9. the specific gravity of soil solids is 2.75. this soil is to be excavated and transported to a construction site for use in a compacted fill. if the specifications call for the soil to be compacted
Excavated and brought to a construction site, this soil will be used in a compact The volume fill is 8680.73 m³.
Given,
The specific gravity of soil solids = 2.75
The situ moisture content of the soil =15%
Saturation level = 70%
void ratio = 0.9.
Dry weight = 103.5
We know that,
Yd = [tex]\frac{16.5}{1+\frac{18}{100} }[/tex]
Yd = 14.34KN/m³
The volume of soil to be excavated to produce 7651m³ is
[tex]V=\frac{Yd (compacted)}{Yd(insite)} Compacted Fill Volume[/tex]
[tex]V=\frac{16.27}{14.34}7651[/tex]
[tex]V=8680.73m^{3}[/tex]
No of trucks = [tex]\frac{V*Y(insity)}{1.78}[/tex] = 826 trucks
The most conventional approach involves using the human body, such as pinching or measuring the volume of an object using the size of your hand. On the other hand, because of its variations, the human body is very unpredictable. Utilizing reasonably consistent and durable natural things, such as gourds, sheep or pig stomachs, and bladders allows for a more accurate method of measuring volume. Since metallurgy and glass manufacture have evolved throughout time, small amounts are routinely measured using standardized man-made containers today. For granular goods, the container is shaken or leveled off to produce a virtually smooth surface. This method is not the most accurate way to measure.
Hence,
Excavated and brought to a construction site, this soil will be used in a compact The volume fill is 8680.73 m³.
And
No of trucks = [tex]\frac{V*Y(insity)}{1.78}[/tex] = 826 trucks.
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which of these observable aspects is most useful to astronomers when measuring the dark matter content of galaxies?
The observable aspect which most useful to astronomers when measuring the dark matter content of galaxies is stellar velocities.
What is dark matter?Dark matter is composed of particles which do not absorb, reflect, or emit light, so they cannot be detected by observing electromagnetic radiation. Dark matter is material which cannot be seen directly. We know that dark matter exists because of the effect it has on objects that we can observe directly.
Dark matter's existence was first inferred by Fritz Zwicky in 1933, a Swiss American astronomer, who discovered that the mass of all the stars in the Coma cluster of galaxies provided only about 1 percent of the mass required to keep the galaxies from escaping the cluster's gravitational pull.
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the system is an open system because the total mechanical energy of the system is not constant, which means that an external force removed 140 j140 j of mechanical energy from the system.
This is true that the system is an open system because the total mechanical energy of the system is not constant, which means that an external force removed 140 j of mechanical energy. this can also be a closed system if there is only exchange of energy.
An open system can exchange energy and matter both with its surrounding. One example is the stovetop which releases heat water vapor to the surrounding.
A closed system can exchange only energy with surroundings, not matter. A tightly-fit container is an example of a closed system.
An isolated system can't exchange energy or matter with its surroundings. An insulated drink cooler can be thought of as an isolated system. A truly isolated system can't be obtained.
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