Answer this question fast please i will mark you brainliest​

The wavelength and the frequency of the light are inversely proportional to each other, the multiplication of the wavelength and the frequency of the light is equal to the speed of the light.

It can be understood in terms of the distance between any two similar successive points across any wave for example wavelength can be calculated by measuring the distance between any two successive crests.

C = λν

As given in the problem we have to find out how are wavelength, frequency, and energy-related to photons of light,

The relationship between the wavelength and the frequency of light is inverse, and the product of the wavelength and the frequency equals the speed of light.

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Answer:

Explanation:

Flares occur in active regions around sunspots, where intense magnetic fields penetrate the photosphere to link the corona to the solar interior. ... X-rays and UV radiation emitted by solar flares can affect Earth's ionosphere and disrupt long-range radio communications.

Answer:

напряженность поля в некоторой точке 0,8 кН/кл определите величину силы,с которой поле будет в этой точке действовать на заряд 2,5мкКл 00

The impulse is the product of mass and velocity. Hence, the impulse delivered by the second shopping cart is 3mv/2

Given the Parameters :

Impulse delivered by the second cart on the first :

Impulse = Mass × velocity

Impulse = Mass of cart 2 × final velocity of cart 1

Impulse = 3m × v/2 = 3mv/2 Ns (towards the left)

Therefore ; the impulse delivered by the second shopping cart is 3mv/2 to the left.

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Answer:   see below.

Explanation:

Your question is lacking the necessary parameters, so I will assume the values to enable me to solve it:

Mass of football = 20 grams

Volume of football = 100[tex]cm^{3}[/tex]

To find the density of the football;

Density is simply mass per unit volume of an object such as a football.

Mathematically, the density of an object is given by the formula;

Density=[tex]\frac{Mass}{Volume}[/tex]

Substituting the assumed values into the above formula;

Density=[tex]\frac{20}{100}[/tex]

Density= 0.2g/[tex]cm^{3}[/tex]

Therefore, the density of the football is     0.2g/[tex]cm^{3}[/tex] .

For you: You can substitute the appropriate parameters into the formula to get the exact density of the ball.

Answer:

18.71 joules

Explanation:

The formula to solve for potential energy is PE = mgh

where m = mass, g = force of gravity, and h = height.

m = 1.11 kg

g = 9.8 m/s^2

h = 1.72 meters

PE = (1.11)(9.8)(1.72)

PE = 18.71016

Therefore, the potential energy of the ball is 18.71 joules.

Answer:

The formula to solve for potential energy is PE = mgh

where m = mass, g = force of gravity, and h = height.

m = 1.11 kg

g = 9.8 m/s^2

h = 1.72 meters

PE = (1.11)(9.8)(1.72)

PE = 18.71016

Therefore, the potential energy of the ball is 18.71 joules.

Answer:

Explanation:  HIII

from,

v² = u² + 2as

where s = distance

a = (v² - u²) /2s

a = (85² - 6²) /2*550

a = 6.53m/s²

Answer:

A. It moved from 3 cm to 10 cm at a constant speed of 2 cm/s.

Explanation:

Just took the quiz.

It moved from 3 cm to 6 cm at a constant speed of 3 cm/s.​ This  statement accurately describes the motion of the object in the graph above

An object is said to be in motion , if its position changes with respect to its surroundings and time.

A. Object's motion is from 3 cm to 10 cm at a constant speed of 2 cm/s

let us check

time = 7 sec

distance = 10 - 3 = 7 sec

speed = distance / time = 7/7 = 1 m/s

wrong option

B. Object's motion is from 0 cm to 6 cm at an average speed of 1 cm/s.

distance = 6 cm

time = 7.5 sec

speed = 6/7.5 = 0.8 m/s

wrong option

C. Object's motion is from 0 cm to 10 cm at an average speed of 2 cm/s.

distance = 10 cm

time = 9 sec

speed = 10 / 9 = 1.11 m/s

wrong option

D.  Object's motion  is from 3 cm to 6 cm at a constant speed of 3 cm/s.​

distance = 6-3 = 3 cm

time = 7.5 - 6.5 = 1 sec

speed = 3 /1 = 3 m/s

correct option  D. It moved from 3 cm to 6 cm at a constant speed of 3 cm/s.​

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The density of the solution from the given compositions of water and ethanol is 799.55 kg/m³.

The given parameters;

The density of the solution from the given compositions of water and ethanol is obtained by finding the respective amount of water and ethanol composition is the solution.

The density of the solution is calculated as follows;

[tex]\rho = \frac{5(1000 \ kg/m^3) + 95(789 \ kg/m^3)}{100} \\\\\rho = 799.55 \ kg/m^3[/tex]

Thus, the density of the solution from the given compositions of water and ethanol is 799.55 kg/m³.

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The answer is 799.55 kg/m3.

Answer:

Expiratory Reserve Volume

Explanation:

Answer:

Explanation:

See attachment.

a  NO - it depends on distance between the masses, also.

The gravitational force between two objects depends only on their masses.

b  YES - see attachment

The gravitational force between two objects increases if the mass of one object increases.

c. No - it decrease

The gravitational force between two objects increases if the distance between the objects decreases.

d. It appears the answer is incomplete (stops at . . ., no . . ).  Otherwise I say YES.

Any two objects that have mass also have a force of gravity acting between them, no

Given : A car starts from rest and retains the acceleration of 4m/s² in 20 second. Calculate its final velocity.

Solution : As we know that a car starts from rest so it's initial velocity should be 0 m/s. Acceleration is 4 m/s² and time taken is 20 sec. So, we need to calculate it's final velocity which we can get it usi g the first equation of motion.

First Equation of Motion : v = u + at

Putting all the required values in the formula we will get v

Henceforth, final velocity is 80 m/sec.

La actividad física posee muchos beneficios para la salud. Algunos de estos beneficios son la reducción en el riesgo de padecer enfermedades, control del peso, fortalecimiento de huesos y músculos, etc.

La actividad física regular previene la aparición de enfermedades cardiovasculares al evitar la acumulación de colesterol en las arterias que transportan sangre a diferentes áreas del organismo.

La actividad física consume calorías, especialmente aquellas provenientes de los lípidos (grasas), con lo cual permite controlar el peso y reducir el riesgo de obesidad.

La actividad física también ayuda al fortalecimiento de los tejido oseo, con lo cual previniendo enfermedades relacionadas tales como la osteoporosis.

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Answer:

hi uv f hmm k in vyvj

Explanation:

hujjkiv ghujihtnkbggvhbbbnnjnj

Answer:

1 / 3 or 0.33

that is if you meant that the object accelerates at 3 m / s² not 3 m / s

for the unit of acceleration is m / s²

Explanation:

m = ?

a = 3

f = 1N

where;

m = mass ( kg )

a = acceleration ( m / s² )

f = force ( N )

from all the parameters we are given, we can use Newton's second law of motion to solve it

that is;

a = f / m

to make m the subject of the formula, we have to cross multiply to give us;

m( a ) = f

divide through by a to give us;

m ( a ) / a = f / a

therefore,

m = f / a

so, we substitute our values to give us;

m = 1 / 3

therefore. m = 1 / 3 or 0. 33

hope this helps

thank you!!!!

No,

Doctor not only advice for physical activity but also for social and mental activities

Answer:

No

Explanation:

Answer:

Magnetism

Explanation:

Answer:

V = 10

I = 2

R = ?

from,

R = V/I

R = 10/2 = 5 ohms.

P.S; don't die. :))

B is the correct answer

[tex]1.39[/tex] × [tex]10^{6} N[/tex] acting  [tex]30^{o}[/tex] to the left of the vertical.

The weight of the airliner is [tex]1.20[/tex] × [tex]10^{6} N[/tex] and there is an aerodynamic lift force of [tex]1.39[/tex] × [tex]10^{6} N[/tex] acting  [tex]30^{o}[/tex] to the left of the vertical.

Therefore, the airliner follows this circular path while maintaining a steady speed.

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c] Electrons

Electron gets transferred

Answer:

6.06 seconds i believe (rounded)

i just divided.

The motorized toy boat experiences a net force of 0 N between 4 s and 8 s.

The motorized toy boat moves at 8 m/s (u) at 4 s and at 8 m/s (v) at 8 s. We can calculate the acceleration (a) in that period using the following kinematic expression.

[tex]a = \frac{v-u}{\Delta t} = \frac{8m/s-8m/s}{8s-4s} = 0 m/s^{2}[/tex]

The object with a mass (m) of 2.0 kg experiences an acceleration of 0 m/s². We can calculate the net force (F) in that period using Newton's second law of motion.

[tex]F = m \times a = 2.0 kg \times 0 m/s^{2} = 0 N[/tex]

The motorized toy boat experiences a net force of 0 N between 4 s and 8 s.

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Answer:

The conventional wisdom of the digital era is that journalists can now know their audiences in far more intimate detail than at any other time in the history of the profession. Previously, journalists based their audience knowledge primarily on their closest social circles. Now, new tools can help them solicit readers’ feedback, analyze and understand readers’ behavior, and open new channels for conversation. These new capabilities promise to shine a light on the abstract audience — making one’s readers present, quantified and real

Answer:

There is absolutely No relationship between the weight of an object (which is constant) and the frictional force. If a block is sliding on a surface, that surface will be exerting a force on the block. That force can be resolved into a component parallel to the surface (which we call the frictional component), and a component perpendicular to the surface (called the normal component). For many situations, we find experimentally that the frictional component is approximately proportional to the normal component. The frictional component divided by the normal component is defined to be a quantity called the coefficient of kinetic or sliding friction. The coefficient of kinetic friction obviously depends on the nature of the surfaces involved. The normal component on an object can be decreased if you pull in the direction of the normal component (the weight does not change). However pulling this way on the object not only decreases the normal component, but it also decreases the frictional component since they are proportional. This is why it is easier to slide something if you pull up on it while you push it. If you push down, the normal and frictional components increase so it is harder to slide the object. The weight of an object is the downward force exerted by Earth’s gravity on that object, and it does not change no matter how you push or pull on the object.