Answer:
16 miles
Step-by-step explanation:
there are 8 units between the points each unit is 2 miles so 8*2= 16
A star patterned quilt has a star with the angels shown. What is the value of x? Explain your answer.
Answer:
81°
Step-by-step explanation:
x° and 24° are interior angles of a triangle that are opposite to an exterior angle of measure 105°. According to the exterior angle theorem of a triangle, thus:
[tex] x + 24 = 105 [/tex]
Subtract 24 from both sides
[tex] x + 24 - 24 = 105 - 24 [/tex]
[tex] x = 81 [/tex]
Value of x = 81°
system of equations
3x+5y=-7
6x-4y=0
Step-by-step explanation:
18x+30y=-7
18x+12y=0
42y=-7
y=-0.17
3x+5(-0.17)=-7
3x-0.85=-7
3x=-6.15
x=-2.05
Please help me I beg you I really need help.
Answer:
what's that ,we are all ears
HELPPPPP PLEASEEEEE!!!!!!!!!
The x intercept is (9/2,0) or (4.5,0). The y intercept is (0,-1):)
Find the lengths of the sides of the triangle PQR. P(3, â3, â3), Q(9, 0, 3), R(12, â6, â3) |PQ| = |QR| = |RP| = Is it a right triangle?
a. Yes
b. No
c. Is it an isosceles triangle?
Answer:
a. Yes
Step-by-step explanation:
Mr. Yen and Mrs. Barnes both have beautiful flower gardens. Mr. Yen has 7 rose bushes for every 3 lilac bushes. Mrs. Barnes has 9 rose bushes for every 4 lilac bushes. Whose garden has a higher lilac to rose ratio?
Answer:
Mrs Barnes has the highest
In City A, 4,099 of 5,289 residents, have reliable high-speed internet access. In City B, 15,798 of 20,868 residents have reliable high-speed internet access. In which town are residents more likely to have reliable high-speed internet access?
Answer:
4,099 and 5,011
Step-by-step explanation:
which of the following is not equivalent to the rational number 12/5
1) 2.4
2) 9/4
3) 2 2/5
4) 36/15
Answer:
2) 9/4
Step-by-step explanation:
12/5 in decimal form is 2.4. As a mixed number, 12/5 is 2 2/5. And, 12/5 is just a reduced form of 36/15. So, the only answer it can be is answer 2: 9/4
Lilly was shopping and saw the following prices on different packages of the same item
Answer:
What's the question?
Step-by-step explanation:
What are the solutions of 3(x – 4)(2x - 3) = 0? Check all that apply. -4 -3 win w bo 3 m/N 3 4
Answer:
Option (4) and Option (6)
Step-by-step explanation:
By the zero product property,
If (x - a)(x - b) = 0
Then, (x - a) = 0 ⇒ x = a
(x - b) = 0 ⇒ x = b
By following the zero product property,
From the given equation,
3(x - 4)(2x - 3) = 0
x - 4 = 0 ⇒ x = 4
2x - 3 = 0 ⇒ x = [tex]\frac{3}{2}[/tex]
Therefore, options (4) and (6) will be the correct options.
Answer:
4 and 6 :)
Step-by-step explanation:
edge
Identify the coefficient in 0.50(m)-0.20(g)+9.00
Answer:
-0.2 + 0.5m + 9
Step-by-step explanation: simplify
what is the perimeter of a rectangle
Answer:
p=2 (l+w)
Step-by-step explanation:
will give branlist
The sum of two numbers is 107, the difference is 51. Find the numbers.
Answer:
Answer is 79 and 28
Step-by-step explanation:
Let two numbers be x and y.
x + y = 107. --> 1
x - y = 51 -->2
solving above equations,
2x = 158
x =79
y = 28
What is the result when the number 63 is decreased by 1.3%?
Answer:
61.7
Step-by-step explanation:
Recall information from the previous task. A snack-size bag of carrots has a mean weight of 1.75 ounces and a
standard deviation of 0.1 ounce.
Kendra bought a snack-size bag of carrots to measure and found that her bag of snacks weighed 1.68 ounces. The Z-
score of Kendra's bag of carrots is -0.70.
Complete the statement interpreting the Z-score.
Kendra's bag of carrots is 0.70 —standard deviations—below—the mean weight.
Put the right answers up ^
Answer:
Standard Deviation and Below are, in fact, the right answer.
Step-by-step explanation:
Edge. :)
Answer:
The person above is right, they deserve brainliest.
-standard deviations
-below
ED2021
what have the same value as 15 percent of 20
Answer:
3
Step-by-step explanation:
cause its a pretty simple question
HELP PLEASE ASAP
Which of the following is not equivalent to the following expression 2x^2 -16
Answer:
Option C. 2(x + 8)
Step-by-step explanation:
To know which option is the correct answer, let us simplify each expression given in the options to know which will not result to 2x² – 16. This is illustrated below:
For Option A:
2x² + 4x – 4x – 16
= 2x² – 16
For Option B:
2(x² – 8)
Clear bracket
2x² – 16
For Option C:
2(x + 8)
Clear bracket
2x + 8
For Option D:
(4x² – 32) /2
4x²/2 – 32/2
2x² – 16
From the above illustration, option C did not result to 2x² – 16.
Therefore, option C is the answer to the question.
Write the hypothesis: If the pen is not blue then today is Friday.
a. The pen is not blue
b. If the pen is not blue
c. If today is Friday
d. today is not Friday
Determine weather the following is real or complex
i^6-122-7i^2
Answer:
Real
Step-by-step explanation:
i^6-122-7i^2
(i^2)^3-122-7i^2
(-1)^3-122-7×(-1)
-1-122+7
-123+7
-116
So the final answer is -116
What is an equation of the line that passes through the points (6, 4) and (4,1)?
Answer:
3/2 x-5
Step-by-step explanation:
Answer:
y=3/2x-5
Step-by-step explanation:
m=y²-y¹/x²-x¹
m=1-4/4-6
m=-3/-2
m3/2
y-y=m(x-x1)
y-1=3/2(x-4)
y-1=3/2x-6
+1 +1
y=3/2x-5
A ball has a diameter
8 inches what is the surface area
Answer:
diameter ÷ 2 = 8 ÷ 2 = 4
Step-by-step explanation:
A card is drawn from a deck of 52 cards.
Find the probability of drawing a black 8:
Answer:
1/26
Step-by-step explanation:
There are two sets colors; red and black.
13 ranks, each rank has 2 black cards and 2 red
but there are only 2 black eights
2/52
How did the National Woman Suffrage Association (NWSA) differ from the American Woman Suffrage Association (AWSA)?
Answer:
The National Woman Suffrage Association advocated for a range of reforms to make women equal members of society, such as the right to own property, etc. The American Woman Suffrage Association lobbied state governments to enact laws granting or expanding women's right to vote in the United States.
Answer:
C: The NWSA wanted to address the voting rights of both women and formerly enslaved people.
Step-by-step explanation:
The NWSA wanted to address and justify the rights of both former slaves and women, while the AWSA only wanted to either help women or former slaves, not simultaneously.
Please answer the 2 questions if you can? (This is my math from 8th grade)
Answer:
8.no answer A. x=8
Step-by-step explanation:
10.no answer B. x= -3
Answer:
8. (A) x = 8 , 10. (C.) x = 3
Step-by-step explanation:
Number 8 you could do 75 - 35 = 40
so what can you multiply 5 by (x) to get 40? you would multiply 5 by 8 or (x) and get 40
then add 35 + 40 to get 75 degrees which is the parallel angle to the other 75 degrees.
Number 10 you just want to get them to the same number.
so you would do ( 97 - 3 ) to get the ANSWER 87.
so x = 3
2) What is 75% of $20.00? *
A. 1,500
B. $15.00
C. $0.15
D. $150.00
Answer:
It is $15.00
Step-by-step explanation:
It is B because A is not even money, C is fifteen cents which is not correct because the question is asking for 75% of $20.00, and finally D is incorrect because it is more than the amount of money asked in the question.
Which would be the best concluding sentence?
Tom wrote this paragraph:
Eating at Joe's Pizza Place is a delightful experience.
The food is freshly prepared right there in the
kitchen. Joe uses only the
freshest ingredients and
makes his own tomato sauce. He even makes
homemade sausage.
O Joe's wife, Emma, has decorated the restaurant
with great care.
O A mural on the wall shows Joe making his tomato
sauce at the Pizza Place.
O Joe also keeps a close eye on the servers and
makes sure customers are happy.
O Anyone who enjoys great food should plan a visit to
Joe's Pizza Place.
lol
the last one seems to be the best
Answer:
D
Step-by-step explanation:
Complete the equation that represents the total value of the nickels and p pennies
Answer:
Answers below
Step-by-step explanation:
Equation
Let's call:
p = number of pennies Janesa has in her pocket
n = number of nickels Janesa has in her pocket
She has 24 coins in total, thus:
[tex]p + n=24\qquad\qquad [1][/tex]
Since each penny is worth $0.01 and each nickel is worth $0.05, and Janesa has $1 in total:
[tex]0.01p+0.05n=1[/tex]
Multiplying by 100:
[tex]p+5n=100\qquad\qquad [2][/tex]
A. Completing the equation:
[tex]5n+p=100[/tex]
B.
From [1]:
[tex]p=24-n[/tex]
Substituting into [2]:
[tex]24-n+5n=100[/tex]
Simplifying:
[tex]24+4n=100[/tex]
Rearranging:
[tex]4n=100-24=76[/tex]
[tex]n=76 / 4= 19[/tex]
[tex]p=24-19=5[/tex]
B. There are 5 pennies in Janesa's pocket
C. Since each penny is worth $0.01, the total value of pennies is 5*$0.01=$0.05
The total value of the pennies is $0.05
D. The total value of the nickels is 19*$0.05 = $0.95
E. Jackson should say she has 19 nickels and 5 pennies
janesa has 24 coins in her pocket worth exactly $1.00. she tells her younger brother jackson that he can have the coins if he correctly guesses how many of each coin she has. she gives him the hint that there are only nickels and pennies. complete the equation that represents the total value of the nickels and p pennies 5( blank ) + p = 100 The type of coins that Janessa has = nickels and pennies.
Janessa has a total number of 24 coins
The sum of the nickels and pennies = $1.00
Let us represent the number of nickels as x
The number of pennies as y
i just got done cutting and taking out the seeds of chilies and i went to go use the restroom and now my bottom part is BURNING HELP ME
Answer:
Lol I can't help im sorry
Find the first six terms of the sequence defined by each of these recurrence relations and initial conditions.
a) an=6an-1, a0=2
b) an=a2n-1, a1=2
c) an=an-1+3an-2, a0=1 , a1=2
d) an=nan-1+n2 an-2 a0=1 ,a1=1
e) an= an-1+an-3 , a0=1, a1=2 , a2=0
Answer:
See explanation
Step-by-step explanation:
Solving (a):
[tex]a_n = 6a_{n-1}[/tex] where [tex]a_0 = 2[/tex]
n = 1
[tex]a_n = 6a_{n-1}[/tex]
[tex]a_1 = 6a_{1-1}[/tex]
[tex]a_1 = 6a_{0}[/tex]
Substitute 2 for [tex]a_0[/tex]
[tex]a_1= 6 * 2[/tex]
[tex]a_1= 12[/tex]
n = 2
[tex]a_n = 6a_{n-1}[/tex]
[tex]a_2 = 6a_{2-1}[/tex]
[tex]a_2 = 6a_{1}[/tex]
Substitute 12 for [tex]a_1[/tex]
[tex]a_2= 6 * 12[/tex]
[tex]a_2= 72[/tex]
n = 3
[tex]a_n = 6a_{n-1}[/tex]
[tex]a_3 = 6a_{3-1}[/tex]
[tex]a_3 = 6a_2[/tex]
Substitute 72 for [tex]a_2[/tex]
[tex]a_3= 6 * 72[/tex]
[tex]a_3= 432[/tex]
n = 4
[tex]a_n = 6a_{n-1}[/tex]
[tex]a_4 = 6a_{4-1}[/tex]
[tex]a_4 = 6a_{3}[/tex]
Substitute 432 for [tex]a_3[/tex]
[tex]a_4 = 6 * 432[/tex]
[tex]a_4 = 2592[/tex]
n = 5
[tex]a_n = 6a_{n-1}[/tex]
[tex]a_5 = 6a_{5-1}[/tex]
[tex]a_5 = 6a_4[/tex]
Substitute 2592 for [tex]a_4[/tex]
[tex]a_5 = 6 * 2592[/tex]
[tex]a_5 = 15552[/tex]
n = 6
[tex]a_n = 6a_{n-1}[/tex]
[tex]a_6 = 6a_{6-1}[/tex]
[tex]a_6 = 6a_{5}[/tex]
Substitute 15552 for [tex]a_5[/tex]
[tex]a_6 = 6 * 15552[/tex]
[tex]a_6 = 93312[/tex]
[tex]a_1= 12[/tex] [tex]a_2= 72[/tex] [tex]a_3= 432[/tex] [tex]a_4 = 2592[/tex] [tex]a_5 = 15552[/tex] [tex]a_6 = 93312[/tex]
Solving (b):
[tex]a_n = a^2_{n - 1[/tex] where [tex]a_1 = 2[/tex]
We have
[tex]a_1 = 2[/tex] which serves as the first term
n =2
[tex]a_n = a^2_{n - 1[/tex]
[tex]a_2 = a^2_{2-1}[/tex]
[tex]a_2 = a^2_{1}[/tex]
Substitute 2 for [tex]a_1[/tex]
[tex]a_2 = 2^2[/tex]
[tex]a_2 = 4[/tex]
n = 3
[tex]a_3 = a^2_{3-1}[/tex]
[tex]a_3 = a^2_{2}[/tex]
[tex]a_3 = 4^2[/tex]
[tex]a_3 = 16[/tex]
n = 4
[tex]a_4 = a^2_{4-1}[/tex]
[tex]a_4 = a^2_3[/tex]
[tex]a_4 = 16^2[/tex]
[tex]a_4 = 256[/tex]
n =5
[tex]a_5 = a^2_{5-1[/tex]
[tex]a_5 = a^2_4[/tex]
[tex]a_5 = 256^2[/tex]
[tex]a_5 = 65536[/tex]
n = 6
[tex]a_6 = a^2_{6-1[/tex]
[tex]a_6 = a^2_{5[/tex]
[tex]a_6 = 65536^2[/tex]
[tex]a_6 = 4294967296[/tex]
[tex]a_1 = 2[/tex] [tex]a_2 = 4[/tex] [tex]a_3 = 16[/tex] [tex]a_4 = 256[/tex] [tex]a_5 = 65536[/tex] [tex]a_6 = 4294967296[/tex]
Solving (c):
[tex]a_n=a_{n-1}+3a_{n-2};[/tex] [tex]a_0=1[/tex] ; ; [tex]a_1=2[/tex]
[tex]a_1=2[/tex] ---- First term
n = 2
[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes
[tex]a_2=a_{2-1}+3a_{2-2}[/tex]
[tex]a_2=a_1+3a_0[/tex]
Substitute values for a1 and a0
[tex]a_2=2+3 * 1[/tex]
[tex]a_2=2+3[/tex]
[tex]a_2=5[/tex]
n = 3
[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes
[tex]a_3=a_{3-1}+3a_{3-2}[/tex]
[tex]a_3=a_{2}+3a_{1}[/tex]
[tex]a_3=5+3 * 2[/tex]
[tex]a_3=5+6[/tex]
[tex]a_3=11[/tex]
n = 4
[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes
[tex]a_4=a_{4-1}+3a_{4-2}[/tex]
[tex]a_4=a_{3}+3a_{2}[/tex]
[tex]a_4=11+3 * 5[/tex]
[tex]a_4=11+15[/tex]
[tex]a_4=26[/tex]
n = 5
[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes
[tex]a_5=a_{5-1}+3a_{5-2};[/tex]
[tex]a_5=a_{4}+3a_3[/tex]
[tex]a_5=26+3 * 11[/tex]
[tex]a_5=26+33[/tex]
[tex]a_5=59[/tex]
n = 6
[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes
[tex]a_6=a_{6-1}+3a_{6-2}[/tex]
[tex]a_6=a_{5}+3a_4[/tex]
[tex]a_6=59+3*26[/tex]
[tex]a_6=59+78[/tex]
[tex]a_6=137[/tex]
[tex]a_1=2[/tex] [tex]a_2=5[/tex] [tex]a_3=11[/tex] [tex]a_4=26[/tex] [tex]a_5=59[/tex] [tex]a_6=137[/tex]
Solving (d):
[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex]; [tex]a_0=1[/tex]; [tex]a_1=1[/tex]
[tex]a_1=1[/tex] --- First term
n = 2
[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes
[tex]a_2=2 * a_{2-1}+2^2a_{2-2}[/tex]
[tex]a_2=2 * a_1+4*a_0[/tex]
[tex]a_2=2 * 1+4*1[/tex]
[tex]a_2=2 +4[/tex]
[tex]a_2=6[/tex]
n = 3
[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes
[tex]a_3=3 * a_{3-1}+3^2 * a_{3-2}[/tex]
[tex]a_3=3 * a_{2}+9 * a_{1}[/tex]
[tex]a_3=3 * 6+9 * 1[/tex]
[tex]a_3=18+9[/tex]
[tex]a_3=27[/tex]
n = 4
[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes
[tex]a_4=4*a_{4-1}+4^2*a_{4-2}[/tex]
[tex]a_4=4*a_{3}+16*a_{2}[/tex]
[tex]a_4=4*27+16*6[/tex]
[tex]a_4=204[/tex]
n = 5
[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes
[tex]a_5=5 * a_{5-1}+5^2 * a_{5-2}[/tex]
[tex]a_5=5 * a_{4}+25 * a_{3}[/tex]
[tex]a_5=5 * 204+25 *27[/tex]
[tex]a_5=1695[/tex]
n = 6
[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes
[tex]a_6=6 * a_{6-1}+6^2*a_{6-2}[/tex]
[tex]a_6=6 * a_{5}+36*a_{4}[/tex]
[tex]a_6=6 * 1695+36*204[/tex]
[tex]a_6=17514[/tex]
[tex]a_1=1[/tex] [tex]a_2=6[/tex] [tex]a_3=27[/tex] [tex]a_4=204[/tex] [tex]a_5=1695[/tex] [tex]a_6=17514[/tex]
Solving (e):
[tex]a_n= a_{n-1}+a_{n-3};\ a_0=1; a_1=2; a_2=0[/tex]
First term: [tex]a_1=2[/tex]
Second Term: [tex]a_2=0[/tex]
n = 3
[tex]a_n= a_{n-1}+a_{n-3}[/tex] becomes
[tex]a_3= a_{3-1}+a_{3-3}[/tex]
[tex]a_3= a_{2}+a_0[/tex]
[tex]a_3= 0+1[/tex]
[tex]a_3= 1[/tex]
n = 4
[tex]a_n= a_{n-1}+a_{n-3}[/tex] becomes
[tex]a_4= a_{4-1}+a_{4-3}[/tex]
[tex]a_4= a_{3}+a_{1}[/tex]
[tex]a_4= 1+2[/tex]
[tex]a_4=3[/tex]
n = 5
[tex]a_n= a_{n-1}+a_{n-3}[/tex] becomes
[tex]a_5= a_{5-1}+a_{5-3}[/tex]
[tex]a_5= a_{4}+a_{2}[/tex]
[tex]a_5= 3 + 0[/tex]
[tex]a_5= 3[/tex]
n = 6
[tex]a_n= a_{n-1}+a_{n-3}[/tex] becomes
[tex]a_6= a_{6-1}+a_{6-3}[/tex]
[tex]a_6= a_{5}+a_{3}[/tex]
[tex]a_6= 3 + 1[/tex]
[tex]a_6= 4[/tex]
[tex]a_1=2[/tex] [tex]a_2=0[/tex] [tex]a_3= 1[/tex] [tex]a_4=3[/tex] [tex]a_5= 3[/tex] [tex]a_6= 4[/tex]
find the missing side lengths. leave ur answers as radicals
Because of the 45 45 90 theorem since the hypotenuse is 9√2 x and y are both 9