(answer only if you know the answer or I'll report) Help me please solve it w steps​

Answer:

The weight of the bird is equal to 7.28 N.

Explanation:

The upward force acting on the bird = 7.28 N

The bird is climbing at a constant rate of 1 m/s.

We need to find the weight of the bird.

We know that the weight of an object is the force of gravity acting on it. It can be calculated as follows :

W = mg

In this case, 7.28 N of force is acting on the object. Hence, the weight of the bird is equal to 7.28 N.

Answer:

28.6 m/s

Explanation:

Using the equation for the range of a projectile,

R = U²sin2θ/g where U = initial speed of flaming pitch balls, θ = launch angle = 53° and g = acceleration due to gravity = 9.8 m/s²

Making U subject of the formula, we have

U = √(gR/sin2θ)

substituting the values of the variables into the equation given that R = 81.1 m, we have

U = √(9.8 m/s² × 81.1 m/sin2(53°))

U = √(794.78 m²/s²/sin106°)

U = √(794.78 m²/s²/0.9613)

U = √(826.78 m²/s²)

U = 28.75 m/s

U ≅ 28.6 m/s

Explanation:

given Time Period = 5 Sec

Amplitude = 1m, Wave length = 15 m

using time period = 1/ frequency , Frequency = 1/5 cycles per sec = 0.2 sec = 12 per min

wave speed= Frequency * Wave length

speed = 0.2*15 = 3m/s

Answer:

P = 113.4 N

Explanation:

We know that if it is on the Moon it has another gravity. Therefore, it is known through the International System that the gravity of the Moon is 1.62 m/s², so..

Data:

Use formula:

Replace and solve:

The man's weight is 113.4 Newtons.

Greetings.

Answer:

[tex] \large{ \tt{☄ EXPLANATION}} : [/tex]

[tex] \large{ \tt{♡ \: LET'S \: GET \: STARTED}} : [/tex]

[tex] \large{ \boxed{ \tt{❃ \: WORK ( \: W \: ) = FORCE\: ( \: F) \times DISPLACEMENT \: ( \: D \: )}}}[/tex]

- Plug the values and then simplify !

[tex] \large{ \bf{↦ \: 150 = F \times 10}}[/tex]

[tex] \large{ \bf{↦F\times 10 = 150}}[/tex]

[tex] \large{ \bf{↦ \: F = \frac{150}{10}}} [/tex]

[tex] \large {\bf{↦F = \boxed{ \bf{15} \: N}}}[/tex]

[tex] \boxed{ \boxed{ \large{ \tt{✤ \: OUR \: FINAL \: ANSWER : \boxed{ \bf{15 \: n}}}}}}[/tex]

ツ Hope I helped ! ۵

☪ Have a wonderful day / evening ! ☼

# StayInAndExplore ! ☂

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

Answer:

  t = 0.714 s and  x = 5.0 m

Explanation:

This is a projectile throwing exercise, in this case when the skater leaves the bridge he goes with horizontal speed

         vₓ = 7.0 m / s

Let's find the time it takes to get to the river

         y = y₀ + v_{oy} t - ½ g t²

the initial vertical speed is zero and when it reaches the river its height is zero

        0 = y₀ + 0 - ½ g t²

        t = [tex]\sqrt{\frac{2y_o}{g} }[/tex]

        t = ra 2 2.5 / 9.8

        t = 0.714 s

the distance traveled is

       x = vₓ t

       x = 7.0 0.714

       x = 5.0 m

Answer:

Buzz Aldrin was American astronaut, engineer and fighter pilot. he did three spacewalks as pilot of the 1966 Gemini 12 mission, and as the lunar modulbe pilot on the 1969 Apollo 11 mission, he and mission commander Neil Armstrong were the first two people to land on the Moon.

I hope it helps

have have a great day

Answer:

0.011

Explanation:

Answer:

Aerobic Fitness. Aerobic fitness improves overall health and well-being. ...

Muscular Fitness. Strength training improves your muscle and bone health and helps with weight loss. ...

Flexibility. Flexibility allows you to move your body freely. ...

Stability and Balance

Explanation:

UP

Answer:

67.5

Explanation:

The plane accelerates at 2.7m/s,^2

Time is 25 seconds

The velocity can be calculated as follows

= 25×2.7

= 67.5

Hence the speed f the plane is 67.5

Answer:

Initial y-component of speed

Vy = 28 * sin 30 = 14 m/sec vertically

1/2 m Vy^2 = 2 m g h    conservation of energy of y-component

h = Vy^2 / (2 * g) = 14^2 / (2 * 9.8) = 10 m

Answer: [tex]3920\ J[/tex]

Explanation:

Given

mass of ball m=10 kg

It is placed at a height of 150 m

It is dropped from the height and allowed to free fall for 40 m

Velocity acquired by the ball during this fall is given by [tex]v^2-u^2=2as[/tex]

Insert u=0, a=g

[tex]\Rightarrow v^2-0=2\times 9.8\times 40\\\Rightarrow v=\sqrt{784}\\\Rightarrow v=28\ m/s[/tex]

Kinetic energy at this instant

[tex]K.E.=\dfrac{1}{2}\times 10\times 28^2\\\\\Rightarrow K.E.=3920\ J[/tex]

Translate to English please

The answer for this question is negative externality

Force is a push or pull that changes or attempts to change the shape or size of an object's position.

F = m × a

Here

F= Force

m= mass of object

a= Acceleration

When light passes through one transparent medium to another transperent medium it bends and that beding of light is know as refraction of light !

Answer:

Sound is transmitted by longitudinal waves thru air - the observer cannot hear the explosion because no air is present between the moon and the ship

Light is transmitted by electromagnetic waves so the light from the explosion can travel between the  moon and the observer.

Answer:

Explanation:

Angular momentum is L = mvr:

L = (5.2)(1.8)(.86) so

L = 8.05 kg*m/s

[tex]\huge{ \mathrm{  \underline{ Answer }\:  \:  ✓ }}[/tex]

Total force acting on right side = 800 N

Total force acting on left side :

Now, equivalent force acting on the plane is :

And the direction of equivalent force will be the direction of greater force, that is right direction.

Hence, Correct option is :

_____________________________

[tex]\mathrm{ \:TeeNForeveR\:}[/tex]

Answer:

a)  [tex]\frac{dE}{dt}=\frac{q^2a^2}{4\pi E_0C^3}[/tex]

b)  [tex]x=\frac{6.0}{4.3*10^{-32}}[/tex]

c) [tex]x'=\frac{6.0}{2.22*10^{-3}}[/tex]

Explanation:

From the question we are told that:

Kinetic energy of Proton[tex]K.E_p= 6.0 MeV[/tex]

Radius [tex]r=0.750[/tex]

Energy [tex]\frac{dE}{dt}=\frac{q^2a^2}{4\pi E_0C^3}[/tex]

a)

[tex]\frac{dE}{dt}=\frac{q^2a^2}{4\pi E_0C^3}[/tex]

b)

Generally the equation for acceleration of proton is mathematically given by

[tex]a_p=\frac{v^2}{r}[/tex]

Where

Speed of Proton particle is

[tex]V_p=2.12 *10^3 m/s[/tex]

[tex]a_p=\frac{(2.12 *10^3)^2}{0.750}\\a_p=1.27*10^{10}m/s^2[/tex]

Therefore

[tex]\frac{dE}{dt}=\frac{q^2a^2}{4\pi E_0C^3}[/tex]

[tex]\frac{dE}{dt}=\frac{9*10^9*(1.6*10^{-19}^2*(1.27*10^{10})^2)}{(3*10^8)^3}[/tex]

[tex]\frac{dE}{dt}=6.881810^{-51}J/s[/tex]

Energy radiated per sec

[tex]mev=\frac{6.881810^{-51}}{1.6*10^{-19}}\\mev=4.3*10^{-32}ev[/tex]

Therefore the Fraction of its energy  it radiates per second is given as

[tex]x=\frac{ K.E_p}{mev}\\[/tex]

[tex]x=\frac{6.0}{4.3*10^{-32}}[/tex]

c)

Generally the equation for acceleration of proton is mathematically given by

[tex]a_p=\frac{v^2}{r}[/tex]

Where

Speed of Proton particle is

[tex]V_p=2.5 *10^7 m/s[/tex]

[tex]a_p=\frac{(2.5 *10^7)^2}{0.750}\\a_p=0.33*10^{14}m/s^2[/tex]

Therefore

[tex]\frac{dE}{dt}=\frac{q^2a^2}{4\pi E_0C^3}[/tex]

[tex]\frac{dE}{dt}=\frac{9*10^9*(1.6*10^{-19}^2*(0.33*10^{14})^2)}{(3*10^8)^3}[/tex]

[tex]\frac{dE}{dt}=59.26^{-25}J/s[/tex]

Energy radiated per sec

[tex]mev=\frac{59.26^{-25}}{1.6*10^{-19}}\\mev=2.22*10^{-3}ev[/tex]

Therefore the Fraction of its energy  it radiates per second is given as

[tex]x'=\frac{ K.E_p}{mev}\\[/tex]

[tex]x'=\frac{6.0}{2.22*10^{-3}}[/tex]

Answer:

C.

A factor of something is an ingredient, or it makes up that thing. For example, in math, we always try to find the factors of a number. We are basically trying to find the "ingredients" of a number.

Answer:

Waves. Refraction is an effect that occurs when a light wave, incident at an angle away from the normal, passes a boundary from one medium into another in which there is a change in velocity of the light. ... The wavelength decreases as the light enters the medium and the light wave changes direction.

Explanation:

As a wavelength increases in size, its frequency and energy (E) decrease. From these equations you may realize that as the frequency increases, the wavelength gets shorter. ... Mechanical and electromagnetic waves with long wavelengths contain less energy than waves with short wavelengths.

Answer:

 v_f = 20 m / s

Explanation:

For this exercise let's use the relationship between momentum and moment

        I = Δp

        F t = m v_f - m v₀

as the body starts from rest v₀ = 0

        F t = m v_f

        v_f = [tex]\frac{F t}{m}[/tex]

let's calculate

        v_f = 4 2 / 0.4

         v_f = 20 m / s

a = ( v(2) - v(1) ) ÷ ( t(2) - t(1) )

2 = ( v(2) - 10 ) ÷ ( 6 - 0 )

2 × 6 = v(2) - 10

v(2) = 12 + 10

v(2) = 22 m/s

Answer:

[tex]D_T=18.567m[/tex]

Explanation:

From the question we are told that:

Acceleration [tex]a=8.0 m/s^2[/tex]

Displacement [tex]d=1.05 m[/tex]

Initial time [tex]t_1=6.0s[/tex]

Final Time [tex]t_2=2.5s[/tex]

Generally the equation for Velocity of 1.05 travel is mathematically given by

Using Newton's Law of Motion

 [tex]V^2=2as[/tex]

 [tex]V=\sqrt{2*6*1.05}[/tex]

 [tex]V=4.1m/s[/tex]

Generally the equation for Distance traveled before stop is mathematically given by

 [tex]d_2=v*t_1[/tex]

 [tex]d_2=3.098*4[/tex]

 [tex]d_2=12.392[/tex]

Generally the equation for Distance to stop is mathematically given by

Since For this Final section

Final velocity [tex]v_3=0 m/s[/tex]

Initial velocity [tex]u_3=4.1 m/s[/tex]

Therefore

Using Newton's Law of Motion

 [tex]-a_3=(4.1)/(2.5)[/tex]

 [tex]-a_3=1.64m/s^2[/tex]

Giving

 [tex]v_3^2=u^2-2ad_3[/tex]

Therefore

 [tex]d_3=\frac{u_3^2}{2ad_3}[/tex]

 [tex]d_3=\frac{4.1^2}{2*1.64}[/tex]

 [tex]d_3=5.125m[/tex]

Generally the Total Distance Traveled is mathematically given by

 [tex]D_T=d_1+d_2+d_3[/tex]

 [tex]D_T=5.125m+12.392+1.05 m[/tex]

 [tex]D_T=18.567m[/tex]

Answer:

Each parent has a set of genes, and a combination of the genes from the mom and the dad could come together to make the child look totally different.

A child looks different to both parents because children usually look like a "combination" of both their parents. Each parent gives their child their genes.  So a child wouldn't look exactly like one parent.