An object with a mass of 5 kilograms starts from rest and achieves a maximum speed of 10 meters per second in 0.5 seconds. What average unbalanced force on this object?

a. 50 N

b. 100 N

c. 10 N

d. 1000 N

Answer:

16.2 m/s

Explanation:

2ad=Vf^2-Vi^2

2 (1.5) (40) = Vf^2 -(12)^2

Vf= 16.2 m/s

solid...............

Answer:

13 m/s vertical and 7.5 m/s horizontal

Explanation:

❤️

The vertical and horizontal components of a projectile is required.

The correct option is (2) 13 m/s vertical and 7.5 m/s horizontal

u = Initial velocity of projectile = 15 m/s

[tex]\theta[/tex] = Angle of projectile = [tex]60^{\circ}[/tex]

The horizontal component

[tex]u_x=u\cos \theta\\\Rightarrow u_x=15\cos60^{\circ}\\\Rightarrow u_x=7.5\ \text{m/s}[/tex]

The vertical component

[tex]u_y=u\sin \theta\\\Rightarrow u_x=15\sin60^{\circ}\\\Rightarrow u_x=13\ \text{m/s}[/tex]

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Answer:

The largest surface area window that can be used is [tex]A=0.01\ m^2[/tex]

Explanation:

Pressure

The pressure is defined as force per unit area. The SI unit for pressure is the Pascal (Pa), defined as Newton per square meter.

If a force F acts on a surface area A, the pressure is calculated as:

[tex]\displaystyle P=\frac{F}{A}[/tex]

The pressure at a depth of 90 m is P=1 Mpa= 1,000,000 Pa and the submarine's window can only take a force of F=10 kN=10,000 N.

We need to calculate the largest surface area of the window. We can solve the equation for A:

[tex]\displaystyle A=\frac{F}{P}[/tex]

Substituting:

[tex]\displaystyle A=\frac{10,000}{1,000,000}[/tex]

[tex]A=0.01\ m^2[/tex]

The largest surface area window that can be used is [tex]\mathbf{A=0.01\ m^2}[/tex]

Answer:

thank you

Explanation:

Split up the two given velocity vectors into horizontal and vertical components.

Plane:

p = (100 km/h) (cos(90°) i + sin(90°) j ) = (100 km/h) j

Its direction is given, 90° relative to east.

Traveling for 3 hours with this velocity results in a displacement of

p * (3 h) = (300 km/h) (3h) j = (900 km) j

meaning that this velocity contributes to a north-facing displacement of 900 km.

Wind:

w = (30 km/h) (cos(315°) i + sin(315°) j ) ≈ (21.2 km/h) i + (-21.2 km/h) j

Its direction is also given, 315° relative to east.

After 3 h, this velocity contributes to a displacement of

w * (3h) ≈ (63.6 km) i + (-63.6 km) j

meaning if the plane had no velocity of its own but somehow stayed in the air, the wind would have pushed it about 63.6 km south and 63.6 km east, which translates to a net displacement of

√((63.6 km)² + (-63.6 km)²) = 90 km

due southeast.

Putting everything together, your table displacement table should read:

.                       |   wind   |   plane

velocity           |   30      |   100       ...   km/h

direction         |   90°     |   315°      ...   relative to east

x                      |   63.6   |   0           ...   km

y                      |  -63.6   |   900      ...   km

The resultant vector is the sum of these, r = p + w :

r ≈ (21.2 km/h) i + (78.8 km/h) j

After 3 h, the resultant displacement is

r * (3h) ≈ (63.6 km) i + (236.4 km) j

with magnitude

√((63.6 km)² + (236.4 km)²) ≈ 244.8 km

and direction θ such that

tan(θ) ≈ (236.4 km) / (63.6 km)

θ ≈ arctan(3.714) ≈ 74.9°

So the resultant table should read

xnet             |   63.6 km

ynet             |   236.4 km

magnitude   |   244.8 km

theta            |   74.9° relative to east

Answer: c

Explanation:

The way to check which one is the correct one is to simply multiply and see if there are the same number of atoms in both sides for each element.

a. 2×2 atoms of Al ≠ 3×1 atoms of Al

2×3 atoms of O = 3×2 atoms of O

BOTH MUST BE EQUAL FOR IT TO BE ADJUSTED!!!!!

b. 3×2 atoms of Al ≠ 3×1 atoms of Al

3×3 atoms of O ≠ 2×2 atoms of O

c. 2×2 atoms of Al = 4×1 atoms of Al

2×3 atoms of O = 3×2 atoms of O

BOTH ARE EQUAL, CORRECT ANSWER!!!

d. 2×2 atoms of Al ≠ 1×1 atoms of Al

2×3 atoms of O = 3×2 atoms of O

Answer:

V = 6.56 m/s

Explanation:

in order to find the speed of the diver before she enters we need to find the vertical component of its final velocity by using 3rd equation of motion:

2gh = Vy² - V₀y²

where,

g = 9.8 m/s²

h = height = 2 m

Vy = Vertical Component of Final Velocity = ?

V₀y = Vertical Component of Initial Velocity = 0 m/s

Therefore,

2(9.8 m/s²)(2 m) = Vy² - (0 m/s)²

Vy = √39.2 m²/s²

Vy = 6.26 m/s

Assuming negligible air friction, the x-component of the final velocity will be the same as the initial velocity:

Vₓ = V₀ₓ = 1.95 m/s

Hence, the final velocity will be:

V = √(Vₓ² + Vy²)

V = √[(1.95 m/s)² + (6.26 m/s)²]

V = 6.56 m/s

Answer:

don't know sorry for the irreverent answer..

Answer:

The index of refraction varies with frequency, it doesn't change as light travels from one medium to another, As violet colour has the shortest wavelength and so the refractive index is maximum for it.

Answer:

Acceleration due to Gravity:

Explanation:

Here g is acceleration due to gravity. So C. 3.8 m/s2

Answer:Newton

Explanation:

Answer:

18.5 m/s

Explanation:

Just did it on EdPuzzle

The y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis would be 18.5 m / s .

The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.

Examples of vector quantities are displacement, velocity acceleration, force, etc.

As given in the problem we have to find out the y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis.

The y-component of a velocity vector = 37 × sin 30

                                                                   = 18.5 m / s

Thus , y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis would be 18.5 m / s.

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Answer:

coal: nonrenewable

geothermal energy: renewable

wind: renewable

natural gas: nonrenewable

Explanation:

Have a good day

Thanks

Answer:

coal is non-renewable, the wind is renewable, I belive natural gas is not but I'm not to sure with that one. geothermal energy is renewable.

Explanation:

Answer:

96.04Pa

Explanation:

height=3.5m

gravity=9.8%

density=9.8/3.5

=2.8

Preassure=h×g×d

=3.5×9.8×2.8

=96.04Pa

Answer:

A.

Explanation:

A man using a microwave to boil water

Answer:

d

Explanation:

Answer:

B i think

Explanation:

B because it travels in the same wavelentgh.............

[tex]gjkrejktg[/tex]

Type A is constructive interference and Type B wave gives destructive interference. The constructive interference would be louder.

Interference can be described as a natural phenomenon that occurs at every place and at every moment. Interference can be defined as the phenomenon in which two waves superpose to produce the resultant wave of the lower, higher, or same amplitude. Light waves are produced randomly by most of the sources.

The interference of light from the soap bubble which reflects colors when illuminated by a light source. The starting point of the wave produced may be a maximum or a minimum,  and there is no way to predict which phase the wave will start.

Interference can either be constructive interference or destructive interference. Constructive interference occurs when the crest of one wave falls on the crest of another wave and the amplitude is maximum.

In destructive interference, when the crest of one wave falls on the trough of another wave and the amplitude is minimum. The phase and displacement of these waves are not the same.

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Answer:

The answer is 120lbs

Explanation:

because the scale exerts enough force to equal out to 0 and since the person is putting 120lbs onto the scale it then pushes back enough force to keep them up

The upward force acting on the body is 534 N which is equal to 240 lbs in the upward direction, hence, option d is correct.

Force is an external agent acting on a body to change it from the state of motion or rest. There are various kind of forces namely, gravitational force, magnetic force, nuclear force etc.

Gravitational force is the force by which an object  attracts other objects to its center of mass. Gravitational force depends on the  mass of the object and the distance from the surface of earth.

The weight of the person is 120 lbs.

1 Kg = 2.2 lbs

120 lbs = 54.5 Kg.

The force acting on the body by their weight =  mg = 54.5 Kg × 9. 8 m/s².

= 534 N.

Hence, 534 N is  240 lbs  (534 /2.2 ) of force upward.

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Answer:

b I think. sorry if it's wrong

Answer:

7m/s²

Explanation:

Given parameters:

Velocity at the top = 1m/s

Velocity at the bottom  = 36m/s

Time  = 5s

Unknown:

Average acceleration = ?

Solution;

Acceleration is the rate of change of velocity with time. It is expressed as;

  A = [tex]\frac{v -u}{t}[/tex]

v is the velocity at the top

u is the velocity at the bottom

t is the time taken

 Now, insert the parameters and solve;

  A = [tex]\frac{36 - 1}{5}[/tex]   = 7m/s²

Given values:

Top velocity,

Bottom velocity,

Time,

The acceleration is:

→ [tex]A = \frac{v -u}{t}[/tex]

By putting the values,

       [tex]= \frac{36-1}{5}[/tex]

       [tex]= \frac{35}{5}[/tex]

       [tex]= 7 \ m/s^2[/tex]

Thus the answer above i.e., "option d" is correct.

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Answer:

7.53 km

Explanation:

We at given;

Speed of runner; v_r = 8.5 km/hr

Speed of bird; v_y = 17 km/hr

L = 6.4 km

We know that; time = distance/speed.

We are told that the bird starts from 6.4 km from the start and that it flies back to meet the runner after it reaches the finish line. If the total distance back to the runner is x, it means bird distance is 6.4 + (6.4 - x) = 12.8 - x

Thus;

Time of bird(t_y) = (12.8 - x)/17

Thus,

Time of runner(t_r) = x/8.5 hr

To find x, we have to equate the times of the runner and the bird.

Thus;

x/8.5 = (12.8 - x)/17

Multiply both sides by 17 to get;

2x = 12.8 - x

2x + x = 12.8

3x = 12.8

x = 12.8/3

x = 4.27 km

Thus, cumulative distance traveled by bird is; 12.8 - 4.27 = 7.53 km

Answer:

Explanation:

The distance covered by an object given it's velocity and time taken can be found by using the formula

distance = velocity × time

From the question we have

distance = 2 × 6

We have the final answer as

Hope this helps you

Answer:

B

Explanation:

V=IR    I= curren V=volt R=resistor

8=2.R   8/2=R R=4

Answer:

80/1

Explanation:

to figure out the answer of how many miles/meters per second divide the meters/miles by the second

so 400÷5 would be 80

80 meters per second

hope this helps :))

Answer:

If an object has a fast velocity, the dots on a ticker tape diagram will be far apart.

Answer:

Electricity is the flow of electrical power or charge. It is a secondary energy source which means that we get it from the conversion of other sources of energy, like coal, natural gas, oil, nuclear power and other natural sources, which are called primary sources.

[tex]\mathrm {Hey, there!}[/tex]

Let's solve your problem:

We will convert your number, 212°F, to Kelvin and Celsius.

212°F is equal to 100° Celsius.

Now, let's do the Kelvin convert.

To convert Celsius to Kelvin, we have to add 273.5 to the amount of Celsius.

100° + 273.5 = 373.5

We have all our conversions. Finally, let's set them out.

Fahrenheit: 212°F

Celsius: 100°C

Kelvin: 373.5°K

Answer:

There are [tex]9.537\times 10^{-23}[/tex] kilograms of radioactive material after 300 seconds.

Explanation:

From Physics we know that radioactive materials decay at exponential rate, whose differential equation is:

[tex]\frac{dm}{dt} = -\lambda\cdot m[/tex] (1)

Where:

[tex]\frac{dm}{dt}[/tex] - Rate of change of the mass of the radioactive material, measured in kilograms per second.

[tex]m[/tex] - Current mass of the radioactive material, measured in kilograms.

[tex]\lambda[/tex] - Decay constant, measured in [tex]\frac{1}{s}[/tex].

The solution of the differential equation is:

[tex]m(t) = m_{o}\cdot e^{-\lambda\cdot t}[/tex] (2)

Where:

[tex]m_{o}[/tex] - Initial mass of the radioactive material, measured in kilograms.

[tex]t[/tex] - Time, measured in seconds.

If we know that [tex]m_{o} = 20\,kg[/tex], [tex]\lambda = 0.179\,\frac{1}{s}[/tex] and [tex]t = 300\,s[/tex], then the initial mass of the radioactive material is:

[tex]m(t) = (20\,kg)\cdot e^{-\left(0.179\,\frac{1}{s} \right)\cdot (300\,s)}[/tex]

[tex]m(t) \approx 9.537\times 10^{-23}\,kg[/tex]

There are [tex]9.537\times 10^{-23}[/tex] kilograms of radioactive material after 300 seconds.

Answer:

C. 212,000 years

Explanation:

believe me it's correct.....and you're welcome :)