An object weighing 2.7n while in air and 1.2n when completely immersed in water.find the relative density of the object

The magnitude of the force exerted by the second wire is 16.5 N.

Apply cosine rule to determine the force on the second wire;

W² = F₁² + F₂² - 2F₁F₂ cos(θ)

where;

(4.3 x 9.8)² = 31²  +  F₂²  - 2(31) F₂(cos 122)

1775.78 = 961  +  F₂²  + 32.85F₂

814.78 = F₂²  + 32.85F₂

F₂²  + 32.85F₂ - 814.78 = 0

Solve the quadratic equation using formula method;

F₂ = 16.5 N

Thus, the magnitude of the force exerted by the second wire is 16.5 N.

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(a) The initial horizontal velocity of the driver is 10 m/s.

(b) The time taken for him to reach the water is 1.75 s.

(c) The horizontal displacement is 17.5 m.

The initial horizontal velocity of the driver is given as 10 m/s.

h = vy(t) + ¹/₂gt²

where;

h = 0 +  ¹/₂gt²

2h = gt²

t = √(2h/g)

t = √(2 x 15 / 9.8)

t = 1.75 s

X = Vx(t)

X = 10 x 1.75

X = 17.5 m

Thus, the initial horizontal velocity of the driver is 10 m/s, the time of motion is 1.75 s and the horizontal displacement is 17.5 m.

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0.29 m/s is the speed of this wave.

How can we determine a wave's speed?

Given: The wave's traveling wavelength is () = 35 cm

The wave's period (t) is 1.2 seconds.

The wave's frequency is 0.833 Hz.

We must ascertain a wave's wave speed.

Formula for wave speed is 35 x 0.833 (wavelength x frequency).

= 29.167 cm/sec

= 0.29 m/sec

As a result, the wave's speed is 0.29 m/s.

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Answer: For a pull box housing shielded conductors carrying over 1000V and used in an angled pull, the distance between a conductor entry and exit must be 36 times the outside diameter.

Explanation: To find the correct explanation to the question, we have to find more about the pull box housing shielded conductors.

Thus, we can conclude that, for a pull box housing shielded conductors carrying over 1000V and used in an angled pull, the distance between a conductor entry and exit must be 36 times the outside diameter.

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New kinetic energy:

If the initial kinetic energy of a car is 0.3 MJ and the speed of the car decreased two times then the new kinetic energy will be 0.075 MJ.

The calculation for kinetic energy:

Step-1:

It is given that the car has a kinetic energy of 0.3 MJ. It is required to find the new kinetic energy when the car's speed decreases two times from its initial speed.

Let the mass of the car is m and the initial speed of the car is v.

It is known that the kinetic energy is calculated as,

[tex]\text{K.E}=\frac{1}{2}\times \text{mass}\times\text{speed}^2[/tex]

Therefore the initial kinetic energy is the car is,

[tex]\text{K.E}_1=\frac{1}{2}\times \text{m}\times\text{v}^2[/tex]

Step-2:

The speed of the car is decreased two times. Thus the speed becomes v/2. Therefore the final kinetic energy is the car is,

[tex]\text{K.E}_2&=\frac{1}{2}\times \text{m}\times(\frac{v}{2})^2\\&=\frac{1}{4}\times\frac{1}{2}\times \text{m}\times\text{v}^2\\&=\frac{1}{4}\times\text{K.E}_1\\&=\frac{1}{4}\times {0.3}\text{ MJ}\\&=0.075 \text{MJ}[/tex]

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-3.6× 10^5J is the Work done by friction force

Work done = force × distance

v^2 = u^ +2as

u= 22m/s

a =10m/s^2

When the car stops the final velocity (v) =0

0= 22^2 +2×10×s

s = -484/20

s =-24.2m

Work done = force × distance

Force = mass × acceleration

Work done = 1500×10× -24.2

= -3.6×10^5J

Hence the Work done is -3.6×10^5J

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Answer:

no sorry

Explanation:

Answer:

yes i play genshin

Explanation:

ignore how this is a year late...what server r u on ?im on america and europe!!!!!!!!!!!!(≧∇≦)

It means mass can be converted into energy.

I. E. In a nuclear fission, we start of with a greater mass of our rectant, which then decrease due to mass being converted into the (thermal) energy released, in our reaction. Later, being used to produce electricity, for example.

Hope this helps!

The initial speed of the object was 6.26 m/s.

Acceleration of the sled, a = -g*μk

= -9.8*0.2

= -1.96 m/s^2

Let u is the initial speed and v is the final speed.

Applying, v^2 - u^2 = 2*a*d

0^2 - u^2 = 2*(-1.96)*10

u = sqrt(2*1.96*10)

= 6.26 m/s

The kinetic friction coefficient μok is the ratio of the friction force to the normal pressure experienced by a body moving on a dry, non-easy floor. The determination of μok may be achieved quite appropriately through an alternative creative mechanism described with the aid of Timoshenko

The coefficient of friction (fr) is quite a number that is the ratio of the resistive force of friction (Fr) divided with the aid of the everyday or perpendicular force (N) pushing the items collectively. it is represented by the equation: fr = Fr/N.

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Answer:

The mass of the second student is 60 kg.

Explanation:

Note: It is assumed that radius of piston is 0.23 m and density ρ is 850 kg/m^3 and mass of first student is 55 kg.

There occurs a change in pressure on a piston when some mass is added on the other piston.

This change of mass on the piston is given by the formula,

Δm=ρhA/g

where A is the area of piston.

Given h=35 cm or 0.35 m, change in mass is,

Δm=850*(0.35)*π*(0.23)^2 / 9.8

Δm=5.0 kg

Therefore, the mass of the second student is 55+5=60 Kg

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Answer:

D. 20 N

Explanation:

Force = mass(m) × acceleration due to gravity (g)

Force = 2kg × 10m/s²

Force = 20N

Answer:

kinetic energy and potential and electrical energy

Explanation:

it will be need to maintain the motion of the vehicle and produce electrical energy

the action-reaction forces that the blocks exert on each other will 13 N and 22N

Force is the product of mass and acceleration. There will be constant acceleration on both object X and Y.

Given that the Mass of block X is 10 kg and that of block Y is 5 kg. The magnitude of force of friction on blocks X and Y is 8.0 N and 4.0 N respectively. if an applied force of 40 N [right] acts on block,

We are given that:

With the use of the formula below,

F - [tex]F_{r}[/tex] = ma

Where

The acceleration will be;

40 - (8 + 4) = (10 + 5)a

40 - 12 = 15 a

28 = 15a

a = 28/15

a = 1.8667 m/[tex]s^{2}[/tex]

The tension between the two blocks will be

Force applied-frictional force on X-tension = mass of X × acceleration

That is,

F - [tex]F_{r}[/tex] = ma

40-8-T = 10 × 1.8667

32 - T = 18.667

T = 32 - 18.667

T = 13.33 N

The opposite reaction will be

F - 8 = 10 x 1.8667

F - 4 = 18.67

F = 18.67 + 4

F = 22.67 N

Therefore, the action-reaction forces that the blocks exert on each other will 13 N and 22N

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Forward and downward speed are referred to as acceleration and deceleration respectively.

This is the rate at which an object gains speed with respect to time with its unit being meter per second square(m/s²).

Objects in constant speed are said to have a uniform motion. The downward speed is known as deceleration which involves the object losing speed to return to a state of rest.

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Answer:

0.010 m

Explanation:

So the equation for a pendulum period is: [tex]y=2\pi\sqrt{\frac{L}{g}}[/tex] where L is the length of the pendulum. In this case I'll use the approximation of pi as 3.14, and g=9.8 m\s. So given that it oscillates once every 1.99 seconds. you have the equation:

[tex]1.99 s = 2(3.14)\sqrt{\frac{L}{9.8 m\backslash s^2}}\\[/tex]

Evaluate the multiplication in front

[tex]1.99 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}[/tex]

Divide both sides by 6.28

[tex]0.317 s= \sqrt{\frac{L}{9.8 m\backslash s^2}}[/tex]

Square both sides

[tex]0.100 s^2= \frac{L}{9.8 m\backslash s^2}[/tex]

Multiply both sides by m/s^2  (the s^2 will cancel out)

[tex]0.984 m = L[/tex]

Now now let's find the length when it's two seconds

[tex]2.00 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}}[/tex]

Divide both sides by 6.28

[tex]0.318 s = \sqrt{\frac{L}{9.8 m\backslash s^2}[/tex]

Square both sides

[tex]0.101 s^2 = \frac{L}{9.8 m\backslash s^2}[/tex]

Multiply both sides by 9.8 m/s^2 (s^2 will cancel out)

[tex]0.994 m = L[/tex]

So to find the difference you simply subtract

0.984 - 0.994 = 0.010 m

the answer should be 0.00988 m

Answer:

A

Explanation:

At point 'A' the ball is highest to the ground.As the formula of  gravitational potential energy is Eg=MGH, in which 'M' is mass,'H' is height and 'G' is the gravitational pull of earth

The magnitude of the force exerted by the rope on the bucket is 8N.

To find the answer, we need to know about the force.

Thus, we can conclude that there's no force on the bucket by the person as he is lowering it by constant velocity. But force on the bucket by the rope is 8N.

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The approximate magnitude of the force of air resistance is 882 N

The magnitude of the force of air resistance can be obtained as illustrated below:

F = mg

F = 90 × 9.8

F = 882 N

Thus, approximate magnitude of the force of air resistance is 882 N

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The height is 0.70 meters

The formula for gravitational potential energy is

= mgh

m= mass, g= acceleration due to gravity, h= height

54.9= 8 × 9.8 × h

54.9= 78.4h

h= 54.9/78.4

= 0.70 meters

Hence the height at which the bacpack was lifted is 0.70 meters


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Answer:

its 0.7m

Explanation:

Answer:

इअग्सिव्ह्ह्व्य्वुव्व्ह्विहेधेइएह

Explanation:

ह्य्स्स्येउ?स्य्ग्स्झ्स

Interference and diffraction are the phenomena that support only the wave theory of light. Options 2 and 3 are correct.

The result of two or more wave trains flowing in opposite directions on a crossing or coinciding pathways. This phenomenon is known as the interference of waves.

The phenomenon of interference occurs when two wave pulses are traveling along a string toward each other.

The light wave hypothesis states that light behaves like a wave. Since light is an electromagnetic wave, it may be transmitted without a physical medium.

Light has magnetic and electric fields, much like electromagnetic waves do.

Transverse waves, such as those seen in light waves, oscillate in the same direction as the wave's path. A wave of light may experience interference as well as diffraction as a result of these properties.

All of the remaining options are the light phenomenon.

Hence, options 2 and 3 are correct.

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Answer:

Since velocity is a vector quantity there is no net displacement and the average velocity is zero

(A) is correct

1. The part that shows the body is accelerating is the first 2 hours (ABE). The acceleration is 20 Km/h²

2. The part that shows the body is coming to rest the last 2 hours (CDF)

3. The distance travelled in the first 2 hours is 40 Km

Acceleration is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

From the diagram (ABE), we can see that the body starts from rest and attain a final velocity (40 Km/h) within the first 2 hours. This clearly indicates that the body is accelerating.

The acceleration can be obtained as followed:

a = (v – u) / t

a = (40 – 0) / 2

a = 20 Km/h²

From the diagram (CDF), we can see that the object velocity changes from 40 to 0 within the last 2 hours. This clearly indicates that the object caming to rest.

v² = u² + 2as

v² = 2as

s = v² / 2a

s = 40² / (2 × 20)

s = 40 Km

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Answer:

The acceleration of the rifle equals the force that the bullet exerts on the rifle divided by the mass of the rifle. The two forces are equal, but since the mass of the rifle is much greater than the mass of the bullet, the acceleration of the rifle is much less than the bullet's acceleration.

The time period of the pendulum is 2 sec, and the frequency will be 0.5 and will on depend on weight of the object.

The time period of a basic pendulum is defined as the time it takes to complete one full oscillation and is indicated by the letter "T".

This concept of frequency leads to the simplest frequency formula

Frequency = 1 / T.

T signifies the time it takes to complete one wave cycle in seconds, while f denotes frequency.

The formula for time period of simple pendulum is

Time Period = 2π√(l/g)

As we can see there is no mass term in the formula, Hence we can say that the time period of simple pendulum will not depend on mass or weight of the object tied to the string.

We have given length as 1 m

Time Period = 2π√(1/9.8)

Time Period = 2π×0.319

Time Period = 2 seconds

Time of the Simple Pendulum is 2 seconds.

Frequency = 1 / Time period

Frequency = 1 / 2

Frequency = 0.5 1/second

Frequency of the Simple Pendulum is 0.5

So we can conclude that the Time period of Simple pendulum is 2π√(l/g) and as we can see there is no term of mass, means the simple pendulum will not be depend on mass or weight. The time period came out to be 2 seconds and the frequency came out to be 0.5.

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Answer:

mass

Explanation:

Mass (M) is the measure of the amount of matter in an object. Mass is measured in grams (g). Mass is measured on a balance by comparing the object against other objects with known masses.

Answer:

Mass is the amount of matter in a substance

A movement which keeps the distal end of the body segment fixed in one location describes what type of kinetic chain movement is known as a closed kinetic chain movement.

A closed kinetic chain movement is defined as that position where the most distal aspects of a particular extremity are fixed to the earth or another solid object.

In conclusion; a movement which keeps the distal end of the body segment fixed in one location describes what type of kinetic chain movement is known as a closed kinetic chain movement.

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(a) The unknown charge kept at distance 0.250m directly below  -0.450 charge is  2.315 x 10⁻¹² C.

(b) The magnitude of the force is 29.16 x 10¹² N.

The electrostatic force F between two charged objects placed distance apart is directly proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between them.

F = kq₁q₂/r²

where k = 9 x 10⁹ N.m²/C²

Given is a negative charge -0.450 exerts an upward 0.150N force on an unknown charge 0.250m directly below it .

In equation of the magnitude of force, only the magnitude of charges are taken.

Substituting the values into the expression ,we get the charge

0.150 = (9 x 10⁹ x 0.450x q)/ (0.25)²

q = 2.315 x 10⁻¹² C

Thus, the magnitude of the unknown charge is 2.315 x 10⁻¹² C.

b)Let the unknown charge be  0.450C to exert on -450C.

Substituting the values into the expression ,we get the electrostatic force

F = kq₁q₂/r²

F = (9 x 10⁹ x 0.450x 0.450)/ (0.25)²

q = 2.315 x 10⁻¹² C

Thus, the magnitude of the force is 29.16 x 10¹² N.

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