Answer:
acceleration, a = 11m/s² ; time, t = 0.84sec
Explanation:
Fw = mass(m) × acceleration due to gravity(g)
Fw = 71.9kg × 10m/s²
Fw = 719N
F = Fw(sintheta+coefficient of friction(costheta))
F = 719(sin38° + 0.61(cos38°)
F = 719(0.615661475+0.480686559)
F = 719(1.096348034)
F = 788.27N
Force(F) = mass(m) × acceleration(a)
Make acceleration the subject
acceleration = Force÷ mass
a = 788.27÷719
a = 11m/s²
using this formula v² = u² +2gh
v² = 0² + 2×10m/s²×4.3m
√v² = √86
v = 9.27m/s
acceleration = velocity/time
make time the subject
time = velocity/acceleration
t = 9.27m/s/11m/s²
t = 0.84sec
What type of system would allow light and air to enter and exit? A. Connected
B. Closed C. Isolated D. Open
Answer:
An open system.
Explanation:
An isolated system allows the exchange of neither energy nor matter with the surroundings. A closed system allows the exchange of energy, but not matter. An open system allows the exchange of both energy and matter.
Notice that in this question, light (electromagnetic wave) is a form of energy. The entry and exit of light allows this system to exchange energy with its surroundings- just as how the earth receives energy from the sun. Additionally, this system could exchange energy with its surroundings through the exchange of matter (in particular, air) with its surroundings.
Thus, the system in this question is an open system.
Zero, a hypothetical planet, has a mass of 4.5 x 1023 kg, a radius of 3.2 x 106 m, and no atmosphere. A 10 kg space probe is to be launched vertically from its surface. (a) If the probe is launched with an initial kinetic energy of 5.0 x 107 J, what will be its kinetic energy when it is 4.0 x 106 m from the center of Zero
a.) K 2=K 1 +GmM( r 21− r 11)=2.2×10 7J
b.) K 2 +GmM( r 11− r 21)=6.9×10 7 J
Applying Law of Energy conservation :
K 1+U 1
=K 2+U 2
⇒K 1− r 1GmM
=K 2− r 2 GmM
where M=5.0×10 23kg,r1
=> R=3.0×10 6m and m=10kg
(a) If K 1
=5.0×10 7J and r 2
=4.0×10 6 m, then the above equation leads to
K 2=K 1 +GmM (r 21− r 11)=2.2×10 7J
(b) In this case, we require K 2
=0 and r2
=8.0×10 6m, and solve for K 1:K 1
=K 2 +GmM (r 11− r 21)=6.9×10 7 J
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Two children are riding on a merry-go-round. Child A is at a greater distance from the axis of rotation than child B. Which child has the larger tangential speed
Answer: Two children are riding on a marry-go-round. Child A is at a greater distance from the axis of rotation than child B. Thus, the child A, located at a greater distance from the axis of rotation have a larger tangential speed.
Explanation: To find the correct answer we have to know more about the Angular velocity of a rotating body.
What is the angular velocity?In rotational motion, the angular velocity ω can be defined as, the change in angular displacement(Ф) per unit time (t).It's the revolution per second.The angular velocity can be expressed in terms of the tangential velocity as well as the radius of the circular path as,[tex]w=V/r[/tex]
How to solve the question?We know that the expression for the tangential velocity as,[tex]V=wr[/tex]
In the question, for both the child, the value of w will be same. Thus, the only quantity that depends on the tangential velocity will be the distance from the axis of rotation.The maximum will the value of V, if the r maximizes.Thus, child A with greater distance will have larger tangential speed.Thus, we can conclude that, child A with greater distance will have larger tangential speed.
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The engine of a 1560-kg automobile has a power rating of 75 kW. Determine the time required to accelerate this car from rest to a speed of 100 km/h at full power on a level road. Is your answer realistic
The time required to accelerate this car from rest to a speed of 100 km/h at full power on a level road is 7.73 seconds.
Mass of the engine = 1500 kg
Power rating = 75 kW = 75,000 W
Final speed = 100 km/hr = = 27.78 m/s
v₁ = 0
Power = Work done ÷ Time
Work done = Final energy - Initial energy
=1/2 x 1560 x 27.78^2 = 1/2 x 1560 x 0^2\
= 578703.72 J
Thus,
75,000 = 578703.70 ÷ time=7.72 seconds.
Work is done every time a force moves something over a distance. By multiplying the force by the distance traveled in the direction of the force, you can calculate the energy transferred or the work done. Energy transmitted = work completed = force x distance traveled in the direction of the force.
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If a car moving at 15 m/s skids to a stop after 20 m, how far will it skid if it is moving at 45 m/s? Assume that the braking force is constant. Group of answer choices 50 m 20 m 180 m 90 m 120 m
The car will skid at 80m
As we know that In mechanics, acceleration is the rate of change of the velocity of an object with respect to time.
It is a vector quantity
The velocity is the distance covered by an object per unit time
Given
Initial velocity (u) = 15m/s
Final Velocity (v) = 0m/s
Distance (s) = 20 m
Deceleration (a) =?
Now we know that ,
v² = u² + 2as
Substituting the value
0² = 15² + (2)*(a)*(20)
0 = 225 + 40a
Collecting the like terms
0 – 235 = 40a
–225 = 40a
To find the value of a divide both side 40
a = –225 / 50
a = –5.625 m/s²
Determination of the distance
Deceleration (a) = –5.625 m/s²
Initial velocity (u) = 30 m/s
Final velocity (v) = 0 m/s
Distance (s) =?
v² = u² + 2as
0² = 30² +(2 × –5.625 × s)
0 = 900 – 11.25s
Collecting like terms
0 – 900 = –11.25s
–900 = –11.25s
To find the value of s divide both side by –11.25
s = –900 / –11.25
s = 80 m
Hence the car will skid 80 m
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The constant G in Newton's equation _______. View Available Hint(s)for Part A The constant G in Newton's equation _______. was measured by Newton shows gravity to be a relatively huge force produces equilibrium makes the units of measurement consistent
The constant G in Newton's equation makes the units of measurement consistent was measured by Newton shows gravity to be a relatively huge force produces equilibrium makes the units of measurement consistent.
Newton's law:The three fundamental laws of classical mechanics known as Newton's laws of motion describe how an object's motion and the forces acting on it interact.
Newton's First lawNewton's Second lawNewton's Third lawNewton's first law, an object will not change its motion unless a force acts on it.
Newton's second law, the force on an object is equal to its mass times its acceleration.
Newton's third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
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Inez uses hairspray on her hair each morning before going to school. The spray spreads out before reaching her hair partly because of the electrostatic charge on the hairspray droplets. If two drops of hairspray repel each other with a force of 9 x 10^-9 N at a distance of 0.07 cm ( 7 x 10^ -4 m), what is the charge on each of the equally charged drops of hairspray?
Please show the steps as well. Written out, if possible.
The charge on each of the equally charged drops of hairspray willl be 7 × 10 ⁻¹³ C
What is Columb's law?The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
Similar charges repel each other, whereas charges that are opposed attract each other.
Given data;
Electric force,F = 9 × 10 ⁻⁹ N
Distance between charges,d = 7 × 10⁻⁴ m
Chrge,q₁ = q₂ =q C
From Columb's law;
[tex]\rm F = K \frac{q_1q_2}{d^2} \\\\ 9 \times 10^{-9} = 9 \times 10^9 \frac{q^2}{(7 \times 10^{-4})^2} \\\\ q^2 = 4.9 \times 10^{-25} \\\\ q = 7 \times 10^{-13} \ C[/tex]
Hence the charge on each of the equally charged drops of hairspray willl be 7 × 10 ⁻¹³ C
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The Viking spacecraft observed several features on Mars that, at first, appeared to be artificially crafted. After further study the features were primarily naturally occurring phenomena resulting from _____ on the Martian surface.
Answer:
Erosion of the surface of Mars.
Explanation:
The surface of Mars have features which were formed as a result of the erosion of the surface of the Mars.
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Calculate the time needed for a 0.600 kg hammer to reach the surface of the Earth
if dropped from 10.0 m on Earth and on the Moon. The gravitational strength on
the Moon is 1.6 N/kg.
The time needed for the hammer to reach the surface of the Earth is 3.54 s.
Time of motion of the hammer
The time of motion is calculated as follows;
t = √(2h/g)
where;
h is height of fallg is acceleration due to gravityt = √(2 x 10 / 1.6)
t = 3.54 s
Thus, the time needed for the hammer to reach the surface of the Earth is 3.54 s.
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Select odd one out and also give the reason:
a) Gravitational force , magnetic force , electrostatic force
Gravitational force is not related to other force because it is related to gravity.
How magnetic force and electrostatic force are related?Electrostatic force and magnetic force are link to each other because both have charges. Electrostatic force is type of force that is present between two electrically charged particles. They can either be a repulsive or attractive force.
So we can conclude that Gravitational force is not related to other force because it is related to gravity.
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A force of 15 n is applied to a spring, causing it to stretch 0.3 m. what is the spring constant for this particular spring? n/m
Answer:
-50N/m
Explanation:
Force , F = 15N
Displacement , x = 0.3m
Spring constant , K = ?
K = -F/x
K = -15N/0.3m
K = -50N/m
Answer: 50 N/m
Explanation:
Edge 2022
Vector A has a magnitude of 623. What are its west and north components?
A
The problem cannot be solved because vectors at 90 degree angles to the reference system do not have components.
B
0 south, 0 east
C
623 west, 0 north
D
623 north, 0 west
Answer:
D) 623 N
Explanation:
The vectors' direction is in the North And when we try to take Y and X components Cos(90°) is Zero ... So the X (West) component will be zero
A dentist holds a small mirror 1.9
cm from a patient’s tooth. The image
formed is upright and 5
times as largeas the object. (a) Is
the image real or virtual? (b) What
is the focal length of the mirror? Is it
concave or convex? (c) If the mirror
is moved closer to the tooth, does the
image get larger or smaller? (d) For
what range of object distances does
the mirror produce an upright image?
Answer:
follow me for legitimate answer… oh? U don’t like the feeling of people stealing ur points huh?! Well theirs a taste of your own medicine
Explanation:
You travel in a circle, whose circumstances is 8 kilometers, at an average speed 8 kilometers/hour. If you stop at the same point you started from what is your average velocity
Answer:
The Average Velocity is 2.22m/s.
Explanation:
Average Velocity = displacement(m) ÷ time(s)
8km = 8000m
8km/hr = 2.22m/s
Finding Time
Time = distance÷speed
Time = 8000m ÷ 2.22m/s = 3603.6s = 3604s
Finding Average Velocity
Average Velocity = displacement ÷ time
Average Velocity = 8000m ÷ 3604s
Average Velocity = 2.22m/s
Therefore the Average Velocity is 2.22m/s.
With what speed must a ball be thrown vertically from ground level to rise to a maximum height of 50 m
The speed with which the ball must be thrown vertically from ground level to rise to a height of 50 m is 31.305 m/s.
Given values:
Maximum height reached from ground level, h_max = 50 m
Final velocity of the ball, v = 0 m/s
Calculation of initial speed of the ball:
Step 1:
Using Newton's third equation of motion, we get:
v² = u² + 2as
where, v is the final velocity of ball
u is initial velocity of the ball
a is acceleration of ball
s is the maximum height attained by the ball
Step 2:
Here, the acceleration of the ball will be given as:
a = -g
= -9.8 m/s²
where, g is acceleration due to gravity
Applying this value in above equation we get:
v² = u² - 2gh_max
Re-arranging above equation, we get:
u² = v² + 2gh_max
u =√(v² + 2gh_max)
Step 3:
Applying values in above equation we get:
u =√((0 m/s)² + 2(9.8 m/s²)(50 m)
=√980
= 31.305 m/s
Therefore, the speed with which the ball must be thrown from ground level is 31.305 m/s in order to reach a maximum vertical height of 50 m.
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If a baseball pitcher throws a fastball at a horizontal speed of 160 km/h, how long does the ball take to reach home plate 18.4 m away
Answer: 0.000115 seconds
Explanation: how I got this is by first converting the meters to kilometers then I had 160 km/h and 0.0184 km away so then you do 0.0184 divided by 160 (0.0184 / 160) and get 0.000115 seconds.
An object weighing 2.7n while in air and 1.2n when completely immersed in water.find the relative density of the object
Answer:
1.8 = relative density (there are no units for relative density)
Explanation:
It displaces water equal to it's volume and gets buoyancy equal to that amount of water
2.7 - 1.2 = 1.5 N of buoyancy
density of water = 1 gm /cc
1.5 N = m (9.81)
m of water displaced = .1529 kg
152.9 cc of water will produce this buoyancy....this is the volume of the object
find mass of object 2.7 = m (9.81) shows m = .2752 kg = 272.5 gm
density = mass/ volume = 272.5 / 152.9 = 1.8 gm / cc
Relative to water (which is 1 gm / cc) the relative density is 1.8
====> it is 1.8 times denser than water and will sink when in water....
Write an argument of any one
Do you think parallel universes exist?
or
Do you think portals exist?
A box weighing 660 N is sliding across a cement floor and the coefficient of sliding
friction between the box and the floor is 0.15. If the force pushing the box is 500 N, what
is the acceleration of the box?
O 6 m/s²
O 2 m/s²
O 10 m/s²
pts
O 9 m/s²
The acceleration of the box is 6 m/s²; option A.
What is the acceleration of the box?The acceleration of the box is determined as follows:
Frictional force = 660 * 0.15 = 99 N
Net force = 500 - 99 = 401 N
Force = mass * accelerationMass of the box = 660/9.8 = 67.3 kg
Acceleration = net force/mass
Acceleration = 401/67.3
Acceleration = 6 m/s²
In conclusion, the acceleration of the box is determined from the net force and the mass of the box.
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Consider a blimp that can be approximated as a 3-m diameter, 8-m long ellipsoid and is connected to the ground. On a windless day, the rope tension due to the net buoyancy effect is measured to be 120 N. Determine the rope tension when there are 50 km/h winds blowing along the blimp (parallel to the blimp axis).
Step 1 of 6
Diameter of the blimp,
Length of the blimp,
Rope tension,
The velocity of the wind,
Step 2 of 6
The drag force acting on the blimp can be calculated using the formula given below,
(1)
Where, is the drag coefficient is the density of air.
A is the frontal area of the blimp.
V is the velocity of the wind.
Step 3 of 6
The frontal area of the parachute,
Here,
Substitute the value in the above equation.
The drag coefficient for the balloon is,
Step 4 of 6
From the table properties of air,
The density of air at 1atm pressure and is,
The velocity of air,
Step 5 of 6
Now, substitute all the known values in equation (1)
Step 6 of 6
Now, rope tension is the sum of rope tension due to the buoyancy effect and the force due to the wind blowing.
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Nora's hair dryer is 64% efficient. If 1000 J of energy is supplied to the hair dryer, how much energy will it transfer usefully to Nora's hair?
Answer:
The hair dryer will transfer 640J of energy usefully to Nora’s hair.
Explanation:
Efficiency = output/input × 100%
Data
Efficiency = 64%
Energy input = 1000J
Energy output = ?
Efficiency = Energy output/Energy input × 100%
64% = Energy output /1000J × 100%
Divide both sides by 100%
0.64 = Energy output/1000J
Energy output = 0.64 × 1000J
Efficiency output = 640J
Therefore the hair dryer will transfer 640J of energy usefully to Nora’s hair.
What is the net force (magnitude and direction) of the system below?
The net force (magnitude and direction) of the system given in the question is 40 N horizontal to the right
How to determine the net forceCase 1 (Net force between up and downward force)
Force up (Fu) = 50 NForce down (Fd) = 30 NNet force 1 (F1) = ?F1 = Fu - Fd
F1 = 50 - 30
F1 = 20 N up
Case 2 (Net force between right and left)
Force right (Fr) = 60 NForce left (Fl) = 20 NNet force 2 (F2) = ?F2 = Fr - Fl
F2 = 60 - 20
F2 = 40 N right
SUMMARY
Net force between up and down = 20 N upNet force between right and left = 40 N rightFrom the above, the net force between right and left (i.e 40 N) is greater than the net force between up and down (i.e 20 N)
Thus, the net force of the system will be 40 N horizontal to the right
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What is weight??????????????????
Answer:
Weight is a body's relative mass, or the quantity of matter contained by it.
Explanation:
Hope this helps
25 points please help PLEASE
Journal prompt to be answered in 2 fully developed paragraphs
Prompt: What are some products (or programs) that you could purchase to help your performance in your current physical activity? How would the product (or program help)? Do you really think it is effective? Use specific examples from your experience.
Answer:
você tem um camping de em Rio do Rio de Janeiro ou em lojas em SP e SP e RJ e região metropolitana de Porto Velho de Porto Velho Rio
Long distance running is the physical activity I engage in now, and there are a number of items and programs that can greatly improve my performance.
A GPS powered watch is one such item which I think is quite useful. I can monitor my speed, distance, heart rate and other important information while running with this device. This data lets me change my pace, track my effort, and make sure I stay within my desired heart rate range. The watch also provides post-run analysis, which I can use to identify my weaknesses and modify my training appropriately. In my opinion, GPS running watches have changed the game by allowing me to run harder and push my physical limits.
A strength training program designed for runners has also been very helpful in enhancing my performance. The program's primary emphasis is on functional workouts that target the major running muscle groups, such as the core, glutes and legs.
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A 450-kg sports car accelerates from rest to 100 m/s in 20.0 s. What magnitude force does a 90.0 kg passenger experience during the acceleration
Magnitude of force experienced by the 90Kg passenger is 450N.
To find the answer, we need to know about the pseudo force.
What's the pseudo force experienced by a passenger traveling in a vehicle?When a passenger inside a vehicle, it experiences pseudo force in the opposite direction of motion of the vehicle.The pseudo force= mass of the passenger × acceleration of the vehicleWhat's the acceleration of the vehicle when it achieves a speed of 100 m/s from rest in 20s?Acceleration= Change in velocity/timeHere, change in velocity= 100m/s and time = 20sSo, acceleration= 100/20= 5m/s²What's the pseudo force experienced by the 90Kg passenger?Pseudo force= 90×5=450N.
Thus, we can conclude that the force experienced by the passenger is 450N.
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A cord of mass 0.65 kg is stretched between two supports 8.0 m apart. If the tension in the cord is 120 N, how long will it take a pulse to travel from one support to the other
The time taken by the pulse to travel from one support to the other is 0.208 s.
Given:The mass of the cord is m = 0.65 kg.
The distance between the supports is, d = 8.0 m.
The tension in the cord is T = 120 N.
The time taken by the pulse to travel from one support to the other is given as,
[tex]v=\frac{d}{t}[/tex]
[tex]t=\frac{d}{v}[/tex]
Here, v is the linear velocity of a pulse. Its value is,
[tex]v=\sqrt{\frac{T d }{m} }[/tex]
[tex]v=\sqrt{\frac{120 * 8}{0.65} }[/tex]
[tex]v= 38.43 m/s[/tex]
Then,
[tex]t=\frac{8}{38.43}[/tex]
[tex]t=0.208 s[/tex]
Thus, the time taken by the pulse to travel from one support to the other is 0.208 s.
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In a test run, a rocket-powered car is driving down a test track at a constant speed when the rockets are fired. it then accelerates at 4 m/s2 for 8.0 s covering a distance of 224 m. at what speed was the car travelling when the rockets were fired?
With the use of the second equation of motion formula, the speed the car travelled when the rockets were fired is 12 m/s.
Speed in a Linear MotionLinear motion depicts movement in a straight line. While speed is the distance travelled per time taken.
Given that In a test run, a rocket-powered car is driving down a test track at a constant speed when the rockets are fired. it then accelerates at 4 m/s2 for 8.0 s covering a distance of 224 m.
The given parameters are;
Accelerates a = 4 m/s2Time t = 8sDistance s = 224m
The speed the car travelled when the rockets were fired can be calculated by using the below formula
s = ut + 1/2a[tex]t^{2}[/tex]
Substitute all the parameters into the formula
224 = 8u + 1/2 x 4 x [tex]8^{2}[/tex]
224 =8u + 2 x 64
224 = 8u + 128
224 - 128 = 8u
8u = 96
u = 96/8
u = 12 m/s
Therefore, the speed the car travelled when the rockets were fired is 12 m/s.
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What was the initial speed of a car if its speed is 40 m/s after 5 seconds of accelerating at -4 m/s²?
A. 50 m/s
B. 60 m/s
C. 25 m/s
D. 20 m/s
Answer:
[tex]\huge\boxed{\sf V_i=60 \ m/s}[/tex]
Explanation:
Given Data:Final speed = [tex]V_f[/tex] = 40 m/s
Time = t = 5 s
Acceleration = a = -4 m/s²
Required:Initial velocity = [tex]V_i[/tex] = ?
Formula:[tex]\displaystyle a = \frac{V_f-V_i}{t}[/tex]
Solution:Put the givens in the above formula
[tex]\displaystyle -4=\frac{40 - V_i}{5} \\\\Multiply \ -5 \ to \ both \ sides\\\\-4 \times 5 = 40 - V_i\\\\-20 =40-V_i\\\\Subtract \ 40 \ to \ both \ sides\\\\-20-40=-V_i\\\\-60\ m/s=-V_i\\\\60 \ m/s = V_i\\\\V_i=60 \ m/s\\\\\rule[225]{225}{2}[/tex]
A rocket takes off from Earth's surface, accelerating straight up at 31.2 m/s2. Calculate the normal force (in N) acting on an astronaut of mass 90.4 kg, including her space suit.
The normal force is 2820.48N in the negative y direction.
According to Newton's second law of motion,
Force = mass × acceleration
F = m×A
Note that rocket takes off from Earth's surface, accelerating straight up at 31.2 m/s² .
The rocket accelerates upwards, hence the acceleration will be negative because it defies gravity's law (it keeps going into space without coming down)
Acceleration of the rocket = -31.2m/s²
Mass of the astronaut = 90.4kg
Normal force acting on the astronaut = -31.2 × 90.4kg
= -2820.48N
Therefore, the normal force is 2820.48N in the negative y direction.
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Different asteroids reflect different percentages of the light falling on them. This is due to the fact that they have different:
Due to the Composition, different asteroids reflect different percentages of the light falling on them.
What are Asteroids:
Asteroids are small, rocky objects that orbit the Sun. Although asteroids orbit the Sun like planets, they are much smaller than planets. Asteroids are generally made up of rocky material, metals and their size are large in comparison to comets. Asteroid belt is found between Jupiter and Mars.Composition of Asteroids:
Most of the asteroids in the Main Belt are made of rock and stone. The remaining asteroids are made up of a mix of these, along with carbon-rich materials. Some of the more distant asteroids tend to contain more ices.We determine reflectivity of asteroids by comparing the brightness of light in the visible spectrum to the brightness of light in the infrared spectrum. The light shining from asteroids is reflected sunlight.
Hence we can say that,
Due to the Composition, different asteroids reflect different percentages of the light falling on them.
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