Answer:
20 m per second
Step-by-step explanation:
100 / 5 = 20
A bag contains three different balls, one red (r), one blue(b), one white(w). TWO balls are drawn from the bag without replacement one after the other (at random without looking) and the colors recorded. This means once the first color is drawn, the first ball is kept out of the bag and only 2 colors remain when the second ball is drawn. List the sample space. [Use lower case letters for the colors, preserve the given order, commas separating pairs, no spaces.]
Answer:
The total sample list is 6
Step-by-step explanation:
The bag has following balls
Red - 1
Blue -1
White -1
Two balls are drawn from the bag without replacing the other -
The probability of drawing 1st ball of any color - 1/3
The probability of drawing 2nd ball of any color - 1/2
These two events are independent of each other
Hence, the probability of deriving two balls without replacement is 1/3*1/2 = 1/6
Hence, the total sample list is 6
The sample space is the list of possible outcomes of an experiment
The sample space is {rb, rw, br, bw, wr, wb}
The color of the three balls is represented as:
Red = r
Blue = b
White = w
Given that the selection is without replacement, the sample space would be:
rb, rw, br, bw, wr, wb
The count of the sample space represents the sample size.
Hence, the sample size of the experiment is 6, and the sample space is {rb, rw, br, bw, wr, wb}
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If we were to make a poset of the form (A, |), where is the symbol for divisibility, which of the following sets A would yield a poset that is a total ordering? O A- (1, 4, 16, 64) O A- (1.2,3, 4, 6, 12) O A 1,2,3, 4, 6, 12, 18, 24) OA+{1 , 2, 3, 6, 12)
The sets A {1.2,3,4,6,12}, A{1,2,3,4,6,12,18,24}, and A{1,2,3,6,12} all yield a poset that is a total ordering.
In order for a partially ordered set (poset) to be a total order, every pair of elements must be comparable, i.e., for every pair of elements x, y in A, either x | y or y | x must be true.
Therefore, we should choose a set A that satisfies this condition.Let us consider each set in turn:(1, 4, 16, 64)This set contains powers of 4, which are not all divisible by each other.
For example, 16 | 64, but 16 does not divide 4.
Hence, this set is not a total order.{1.2,3, 4, 6, 12}In this set, 1 divides every other element, so it satisfies the condition for being a total order. Therefore, this set yields a poset that is a total order.
(1, 2, 3, 4, 6, 12, 18, 24)This set has the same elements as the previous set, plus some more. Hence, it also satisfies the condition for being a total order.
Therefore, this set yields a poset that is a total order.{1 , 2, 3, 6, 12}In this set, 1 divides every other element, 2 divides 6 and 12, and 3 divides 6 and 12.
Therefore, it satisfies the condition for being a total order.
Hence, this set yields a poset that is a total order.In conclusion, the sets A {1.2,3,4,6,12}, A{1,2,3,4,6,12,18,24}, and A{1,2,3,6,12} all yield a poset that is a total ordering.
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241.78 divided by (-3.85)
Answer:
-62.8 is the Answer fot the equation, Hope this helped
Mr. Alberto Blanco is a 70 years-old widower. His wife of 44 years died two years ago. He has three sons aged 34, 38 and 41 and a daughter aged 43. He is a retired electrician. He lives alone in his own apartment. His relationship with his children is marked by a considerable degree of conflict. Mr. Blanco is currently hospitalized with gangrene of his right foot and lower leg. Problems with his foot began three years ago when he had an infection in one toe that became gangrenous. At that time it was discovered that he was diabetic. The toe was amputated. Last year he bruised his right foot while getting into a bus. The bruise developed into gangrene that resulted in an operation 6 months ago in which a portion of his right foot was amputated. At that time, an arterial bypass was done to decrease the likelihood that gangrene would recur. He went to a rehabilitation center where he remained for five months. Last week it was discovered that he had gangrene in the remainder of the right foot and part of the lower leg. He was readmitted to the hospital. He originally agreed to amputation of the leg but on the same morning the surgery was scheduled he verbally withdrew the consent. He discussed with some people the reason for his decision. He does not want to be a burden to his children. Mr. Blanco is discouraged by the failure of the earlier operations. He does not believe the operation will cure him and does not want to live as a dependent person or in a nursing home. Mr. Blanco assures that he does not fear death. Although quiet and stoic, he tends to be stubborn and somewhat irascible when pressured. Guide questions for case: Alberto Blanco 1. What are the ethical principles pertinent to this case? 2. Should Mr. Blanco have the right to refuse treatment even if the consequence may be that he will die? 3. Could he be seriously depressed and not mentally competent to make that decision? 4. May the doctor go ahead with the surgery, given the fact that Mr. Blanco had previously given his written consent for the procedure? 5. Would your decision be different if Mr. Blanco were refusing treatment for another condition such as terminal cancer or irreversible heart-failure?
Mr. Blanco has the right to refuse treatment, even if it means he will die. The doctor should respect Mr. Blanco's decision and engage in open and honest communication with him to understand his concerns.
1. The ethical principles pertinent to this case include autonomy, beneficence, non-maleficence, and respect for patient's wishes. Autonomy refers to Mr. Blanco's right to make decisions about his own healthcare. Beneficence and non-maleficence require the healthcare professionals to act in Mr. Blanco's best interest and do no harm. Respect for patient's wishes entails honoring his decision and preferences.
2. Yes, Mr. Blanco should have the right to refuse treatment even if the consequence may be that he will die. It is his autonomy and right to make decisions about his own body and medical treatment. As long as he is mentally competent, he has the right to make choices about his healthcare, even if they go against medical advice.
3. It is important to consider the possibility that Mr. Blanco may be seriously depressed and not mentally competent to make the decision. In such cases, a thorough evaluation of his mental capacity and emotional state should be conducted by healthcare professionals to ensure that he is able to make an informed decision. If he is found to lack mental competence, appropriate steps should be taken to protect his best interests.
4. Given that Mr. Blanco had previously given his written consent for the surgery but verbally withdrew it later, the doctor should respect his current decision. A patient's consent can be withdrawn at any time, and healthcare professionals should prioritize the patient's current wishes. It is essential to engage in open and honest communication with Mr. Blanco to understand his concerns and explore alternative options if available.
5. The decision may be different if Mr. Blanco were refusing treatment for another condition such as terminal cancer or irreversible heart failure. In such cases, the prognosis and potential outcomes may be different, and the balance between preserving life and respecting autonomy may shift. Each case should be evaluated individually, considering the patient's medical condition, prognosis, quality of life, and their values and preferences. Open discussions with the patient, their family, and the healthcare team are crucial in reaching the most ethically appropriate decision.
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assume that in blackjack, an ace is always worth 11, all face cards (jack, queen, king) are worth 10, and all number cards are worth the number they show. given a shuffled deck of cards:
a) Probability of drawing two cards summing to 21: 1/331
b) Probability of drawing two cards summing to 10: 28/1326
c) Probability of drawing a third card to make the sum strictly larger than 21: 2/25
a) To calculate the probability of drawing two cards that sum to 21, we need to determine the number of favorable outcomes and the total number of possible outcomes.
There are four ways to get a sum of 21 with two cards: drawing an Ace and a face card (4 possibilities).
The total number of possible outcomes is given by the combination of choosing two cards from a deck of 52 cards, which is C(52, 2) = 1326.
Therefore, the probability of drawing two cards that sum to 21 is 4/1326, which simplifies to 1/331 or approximately 0.0030.
b) To calculate the probability of drawing two cards that sum to 10, we need to determine the number of favorable outcomes.
There are several combinations that sum to 10: drawing a 4 and a 6, drawing a 5 and a 5, drawing a 6 and a 4, and drawing a face card and a 10.
The total number of possible outcomes remains the same, which is 1326.
Therefore, the probability of drawing two cards that sum to 10 is (4 + 4 + 4 + 16)/1326, which simplifies to 28/1326 or approximately 0.0211.
c) Given that you have already drawn the 10 of clubs and the 4 of hearts, the sum of these two cards is 10 + 4 = 14.
To find the probability that the sum of all three cards is strictly larger than 21, we need to consider the remaining cards in the deck. Since there are 50 cards left in the deck, we calculate the probability of drawing a card that makes the sum exceed 21.
The only way to exceed 21 is to draw an Ace, which is worth 11. There are four Aces in the deck.
Therefore, the probability of drawing a card that makes the sum strictly larger than 21 is 4/50, which simplifies to 2/25 or approximately 0.08.
Complete question:
Assume that in blackjack, an ace is always worth 11, all face cards (jack, queen, king) are worth 10, and all number cards are worth the number they show. given a shuffled deck of cards:
a) What is the probability that you draw two cards and they sum 21
b) What is the probability that you draw two cards and they sum 10
c) Suppose, you have drawn two cards: 10 of clubs and 4 of hearts. You now draw a third card from remaining 50. What is the probability that the sum of all three cards is strictly larger than 21?
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How many 6-digit numbers are there in all?
Answer:
900,000 6
∴ there are 900,000 6-digit numbers in all.
if y=4x^2 −3 , what is the minimum value of the product \displaystyle xyxy ?
The minimum value of the product xyxy is -9, obtained when y equals -3.
To find the minimum value of the product xyxy, we need to first determine the minimum value of the expression y = 4x² - 3.
The given expression is a quadratic equation in the form of y = ax² + bx + c, where a = 4, b = 0, and c = -3.
To find the minimum value, we need to determine the x-coordinate of the vertex of the parabola, which corresponds to the minimum point.
The x-coordinate of the vertex can be found using the formula: x = -b / (2a).
In this case, b = 0 and a = 4, so the x-coordinate of the vertex is x = -0 / (2 × 4) = 0.
Substituting the x-coordinate back into the equation y = 4x² - 3, we can find the minimum value of y.
y = 4(0)² - 3 = -3.
Therefore, the minimum value of y is -3.
To find the minimum value of the product xyxy, we can substitute the minimum value of y (-3) back into the expression:
xyxy = x × (-3) × x × (-3) = -9x².
Since the coefficient is negative, the minimum value of the product xyxy is -9.
Hence, the minimum value of the product xyxy is -9.
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What is the result of subtracting the second equation from the first ? -7x-y=0 and 7x+8y=-6
Answer:
- 14x - 9y = 6
Step-by-step explanation:
- 7x - y = 0 → (1)
7x + 8y = - 6 → (2)
Subtracting (2) from (1) term by term
- 7x - 7x - y - 8y = 0 - (- 6)
- 14x - 9y = 0 + 6
- 14x - 9y = 6
What’s the answer???
Answer:
10 stickers on one sheet
Step-by-step explanation:
96 - 16 ÷ 8 =
80 ÷ 8 = 10
have a nice day! :)
1. This Question Is Compulsory (a) Find the following Laplace transform and verse Laplace transform (1) Llet+')} (1) L- [8 marks) (b) 18 = 1+k8-2+ 3+ 3k and 7 - 1 - 2k, obtain the following (1) ä. ax, (1) 6x5)-(ä xk), (iv) 2:a)3 +34 (12 marks) () Find the point at which the plane 22 - 5y + z = 5 and the line Ft) - (+1) + (24+ 1)3+ (t+1)! (where t is a real number) intersect. [3 marks) (d) Compute the curvature and principal unit normal vector for the curve rt) 2 sin(t)+ 2 con(e) { for t > 0. [6 marks] 2t? (e) For the two matrices A= 12 0 0-7 5 3 B= B=(- :) 0 Find (1) AT, (1) BT, (ii) B(AT) and (iv) (AB)". [8 marks) (t) Find the determinant and trace of the matrix 5-13 10 0 - 2 1 0 3 [6 marks) Solve the following system of simultaneous equations using Gauss-Jordan elimination: 2.11 + 12 = -2, -92+372 = 4. [7 marks] Page 2 of 4
Part a. Find the Laplace transform and inverse Laplace transform of Let+')} and L- [8 marks]Laplace transform of Let+')} is given as: L(et+')} = 1/s-(1/ s+2)Let's try to this.1/s-(1/ s+2) = (s+2-s)/s(s+2) = 2/s(s+2)L-1{2/s(s+2)}= L-1{(1/s)-(1/s+2)} = e^(-2t) - 1
Part b. 18 = 1+k8-2+ 3+ 3k and 7 - 1 - 2k, obtain the following: i) ä. ax, ii) (ä xk), iii) 2:a)3 +34 i) 18 = 1+k8-2+ 3+ 3k
Let's simplify this as follows.18 = 12 + k + 3k - 2k + 3k-1 - 4k+1/218 = 12 - k + 2k + 2k + 3(1/k) - 4k+1/2a=12, b=-1, c=2 and d=2Therefore,ä. ax = ad-bc = 24 + 2 = 26ii) (ä xk) = (cd - bc)i + (ab - ad)j + (ad - bc)k = 1i - 2j + 24kiii) 2:a)3 +34 = 2(ad-bc) + 3(ab-ad) + 4(cd-bc) + 3(bd - ac) = 52
Part c. Find the point at which the plane 22 - 5y + z = 5 and the line Ft) - (+1) + (24+ 1)3+ (t+1)! (where t is a real number) intersect. [3 marks]. Let's substitute the given line in the plane equation. 2(1+4t) - 5(3+1t) + z = 5 solving for z, we get
z = 12t - 13
Substitute this z in line equation to get the point of intersection.(1+t, 4+2t, 12t-13)
Part d. Compute the curvature and principal unit normal vector for the curve rt) 2 sin(t)+ 2 con(e) { for t > 0. [6 marks]. Given curve r(t) = 2 sin(t) + 2 cos(t).
We need to find the first and second derivatives. r'(t) = 2 cos(t) - 2 sin(t)r''(t) = -2cos(t) - 2sin(t)
From these values, we get |r'(t)| = sqrt(8)K(t) = |r'(t)|/|r"(t)|^3/2K(t) = 2^(3/2)/8^(3/2)K(t) = 1/4^(1/2)K(t) = 1/2
Therefore the curvature is 1/2Now, let's find the principal unit normal vector. N(t) = r''(t)/|r"(t)|N(t) = <-1/sqrt(2),1/sqrt(2)>
Part e. For the two matrices A= 12 0 0-7 5 3 B= B=(- :) 0
Find i) AT, ii) BT, iii) B(AT) and iv) (AB)" [8 marks]
i) AT =Transpose of A = 1 -7 0 2 5 3
ii) BT =Transpose of B = 1 0 -3 0 2 1
iii) B(AT) =B(Transpose of A) = 1 -7 0 2 5 3(-1) 0 0 7 -5 -3= -1 7 0 -2 -5 -3
iv) (AB)" =(AB)^-1=Inverse of AB Let's calculate AB first. AB =12 0 0-7 5 3(-1) 0 0-5 2 -1= -1 0 0 1
Therefore, the inverse of AB is1 0 0-1
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Find the volume. I hate these questions!!
please give me brainiest i was working on it the whole time.
Answer: 4* 2 3/4* 8 1/2= 93 1/2
Can someone help me pls
Answer:
The answer would be C
Step-by-step explanation:
This is because 3/4 times two is 6/4 simplified is 1 1/2
*
4. HINT: Remember the "square" means 90 degrees
25 points
The circle with center O has a circumference of 36 units. What is
the length of minor arc AC?
A. 9 units
B. 12 units
C. 18 units
D. 36 units
Convert 73.5% to a fraction in lowest terms.
Answer:
147/200
Step-by-step explanation:
Use the Division Algorithm to show that the cube of any integer is of the form 9k, 9k + 1 or 9k + 8. (Hint: By the Division Algorithm, the integer a is of one of the forms 9q, 9q + 1, ..., 9q + 8; establish the result for 9q + 3 and 9q + 7 only.)
Using the Division Algorithm we have shown that the cube of any integer is of the form 9k, 9k + 1 or 9k + 8
To show that the cube of any integer is of the form 9k, 9k + 1, or 9k + 8, we will use the Division Algorithm. We will establish the result for the cases of 9q + 3 and 9q + 7.
Let's consider the case of 9q + 3, where q is an integer. We want to show that the cube of any integer of the form 9q + 3 is also of the form 9k, 9k + 1, or 9k + 8.
Let's choose an arbitrary integer, let's say n, such that n = 9q + 3.
Taking the cube of n:
n³ = (9q + 3)³
= 729q³ + 243q² + 27q + 27
Now, let's express this in terms of 9k, 9k + 1, or 9k + 8:
n³ = 729q³ + 243q² + 27q + 27
= 9(81q³ + 27q² + 3q + 3) + 18 + 9
= 9(81q³ + 27q² + 3q + 3 + 2) + 7
We can see that n³ can be expressed in the form 9k + 7, where k = 81q³ + 27q² + 3q + 3 + 2.
Therefore, we have shown that for the case of 9q + 3, the cube of any integer of that form is of the form 9k + 7.
Now, let's consider the case of 9q + 7, where q is an integer. We want to show that the cube of any integer of the form 9q + 7 is also of the form 9k, 9k + 1, or 9k + 8.
Similar to the previous case, let's choose an arbitrary integer, let's say n, such that n = 9q + 7.
Taking the cube of n:
n³ = (9q + 7)³
= 729q³ + 441q² + 147q + 49
Now, let's express this in terms of 9k, 9k + 1, or 9k + 8:
n³ = 729q³ + 441q² + 147q + 49
= 9(81q³ + 49q² + 16q + 5) + 4
We can see that n³ can be expressed in the form 9k + 4, where k = 81q³ + 49q² + 16q + 5.
Therefore, we have shown that for the case of 9q + 7, the cube of any integer of that form is of the form 9k + 4.
By using the Division Algorithm and establishing the results for the cases of 9q + 3 and 9q + 7, we have shown that the cube of any integer is of the form 9k, 9k + 1, or 9k + 8.
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Scientists were monitoring the temperature of a solution. It began at 63°F, and the temperature changed by 8°F over the course of 6 hours.
Use this information to complete this statement.
The final temperature of the solution was a minimum of
°F and a maximum of
°F.
Scientists were monitoring the temperature of a solution. It began at 63°F, and the temperature changed by 8°F over the course of 6 hours.
Use this information to complete this statement.
The final temperature of the solution was a minimum of
°F and a maximum of
°F.
Answer:
minimum is 55
maximum is 71
Step-by-step explanation:
got this from another answer so i hope it helps you
please help i have a test tomorrow
Answer:
a
b
e
Step-by-step explanation:
remember length times width equals area
Given that the point P(6.-7) lies on the line 6x + ky = -20, find k Need Help? Let p be the function defined by g(x) = -x2 + Bx. Find g(a + h), g(-a), g(sqrt a) a + g(a), and 1/g(a)
The required solutions are:
[tex]g(a + h) = -(a + h)^2 + B(a + h)[/tex]
[tex]g(-a) = -(-a)^2 + B(-a)[/tex]
[tex]g(\sqrt{(a)}) = -(\sqrt{(a)})^2 + B(\sqrt{(a)})[/tex]
[tex]a + g(a) = a + (-a^2 + Ba)\\[/tex]
[tex]1/g(a) = 1/(-a^2 + Ba)[/tex]
To find the value of k, we can substitute the coordinates of the point P(6, -7) into the equation of the line and solve for k.
Given: P(6, -7) and the line equation 6x + ky = -20
Substituting the x and y values of P into the equation, we have:
6(6) + k(-7) = -20
36 - 7k = -20
Now, let's solve for k:
-7k = -20 - 36
-7k = -56
k = (-56)/(-7)
k = 8
Therefore, the value of k is 8.
To solve the second part of your question, let's work with the function [tex]g(x) = -x^2 + Bx.[/tex]
1. g(a + h):
Substitute (a + h) into the function:
[tex]g(a + h) = -(a + h)^2 + B(a + h)[/tex]
Simplify the expression as needed.
2. g(-a):
Substitute (-a) into the function:
[tex]g(-a) = -(-a)^2 + B(-a)[/tex]
Simplify the expression as needed.
3. [tex]g(\sqrt{(a)})[/tex]:
Substitute [tex]\sqrt{(a)}[/tex] into the function:
[tex]g(\sqrt{(a)}) = -(\sqrt{(a)})^2 + B(\sqrt{(a)})[/tex]
Simplify the expression as needed.
4. a + g(a):
Substitute 'a' into the function and add it to a:
[tex]a + g(a) = a + (-a^2 + Ba)[/tex]
Simplify the expression as needed.
5. 1/g(a):
Take the reciprocal of g(a):
[tex]1/g(a) = 1/(-a^2 + Ba)[/tex]
Simplify the expression as needed.
Please note that without the specific value of B or the variable a, we can only provide general expressions for each of the given calculations.
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I need help with my homework
Answer:
Step-by-step explanation:
1. b. Alt. Exterior angles
a. 7x + 8 = 6x + 18
c. x + 8 = 18
x = 10
d. 6(10) + 18 = 60 + 18 = 78
7(10) + 8 = 70 + 8 = 78
2. 15x + 10 + 12x + 8 = 180
same side angles
27x + 18 = 180
27x = 162
x = 6
15(6) + 10 = 90 + 10 = 100 degrees
12(6) + 8 = 72 + 8 = 80 degrees
3. 12x + 2 = 11x + 6
x + 2 = 6
x = 4
12(4) + 2 = 48 + 2 = 50 degrees
11(4) + 6 = 44 + 6 = 50 degrees
corresponding angles
Consider a random sample from a normally distributed population of large size. i. If the population variance o2 = 35, what sample size is needed to estimate the mean within +2 with 99% confidence? ii. If instead we would like to estimate some true proportion, what sample size is needed to estimate the true proportion within 22% with 99% confidence? Now consider a random sample from a population of large size with unknown distribution. iii. If the population variance o2 50, what sample size is needed to estimate the mean within +1 with 95% confidence (using the 22.5% value)? iv. Why is it the case that such estimating process is still legitimate?
i. a sample size of 138 is needed to estimate the mean within +2 with 99% confidence. Sample size needed: 138
ii. Sample size needed: 342
iii. Sample size needed: 193
iv. Estimating process is legitimate due to the Central Limit Theorem.
What is normal distribution?
Normal distribution, also known as the Gaussian distribution or bell curve, is a continuous probability distribution that is symmetric and characterized by its mean and standard deviation.
i. To estimate the mean within +2 with 99% confidence, we can use the formula for the sample size needed for estimating the population mean:
[tex]n = (Z * \sigma / E)^2[/tex]
Where:
n = sample size
Z = Z-score corresponding to the desired confidence level (99% confidence corresponds to a Z-score of approximately 2.576)
σ = population standard deviation (given as √35 since [tex]o^2[/tex] = 35)
E = maximum error tolerance (+2 in this case)
Substituting the values into the formula:
[tex]n = (2.576 * \sqrt{35} / 2)^2 = 137.13[/tex] (approx)
Since the sample size needs to be a whole number, we round up to the nearest integer. Therefore, a sample size of 138 is needed to estimate the mean within +2 with 99% confidence.
ii. To estimate the true proportion within 22% with 99% confidence, we can use the formula for the sample size needed for estimating the population proportion:
[tex]n = (Z^2 * p * (1 - p)) / E^2[/tex]
Where:
n = sample size
Z = Z-score corresponding to the desired confidence level (99% confidence corresponds to a Z-score of approximately 2.576)
p = estimated proportion (0.5 is commonly used for unknown proportions)
E = maximum error tolerance (22% in this case, which is 0.22)
Substituting the values into the formula:
[tex]n = (2.576^2 * 0.5 * (1 - 0.5)) / 0.22^2 = 341.28[/tex]
Since the sample size needs to be a whole number, we round up to the nearest integer. Therefore, a sample size of 342 is needed to estimate the true proportion within 22% with 99% confidence.
iii. When the population variance [tex]o^2[/tex] is unknown, we can use the t-distribution instead of the Z-distribution for estimating the mean. The formula for the sample size needed for estimating the population mean with an unknown variance is:
[tex]n = (t * \sigma / E)^2[/tex]
Where:
n = sample size
t = t-score corresponding to the desired confidence level and degrees of freedom (in this case, for 95% confidence and a large sample size, t can be approximated as 1.96)
σ = estimated standard deviation (given as √50 since [tex]o^2[/tex] = 50)
E = maximum error tolerance (+1 in this case)
Substituting the values into the formula:
[tex]n = (1.96 * √50 / 1)^2 = 192.08[/tex]
Since the sample size needs to be a whole number, we round up to the nearest integer. Therefore, a sample size of 193 is needed to estimate the mean within +1 with 95% confidence using the 22.5% value.
iv. The estimating process is still legitimate in this case because the sample size is large and the Central Limit Theorem applies. The Central Limit Theorem states that for a large enough sample size, the sampling distribution of the mean (or proportion) will be approximately normally distributed, regardless of the shape of the population distribution. This allows us to make inferences about the population mean or proportion using sample statistics. Additionally, the use of the t-distribution accounts for the uncertainty introduced by using the sample standard deviation instead of the population standard deviation.
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Pls help, question on picture, will do brainliest if right
no links!!!!!
Answer:
[tex]\boxed {\boxed {\sf sin(\theta)=\frac {16}{20}}}[/tex]
Step-by-step explanation:
We are asked to find the sine for the angle indicated. Remember that sine is equal to the opposite over the hypotenuse.
sin(θ)= opposite/hypotenuseAnalyze the triangle given. We have the 2 legs (16 and 12), but we do not have the hypotenuse (the longest side). We must solve for it.
Since this is a right triangle, we can use the Pythagorean Theorem.
[tex]a^2+b^2=c^2[/tex]
Where a and b are the legs and c is the hypotenuse. We know 16 and 12 are the legs.
[tex](16)^2+(12)^2=c^2[/tex]
Solve the exponents.
16²= 16*16=25612²= 12*12= 144[tex]256+144=c^2[/tex]
[tex]400=c^2[/tex]
Since we are solving for c, we must isolate the variable. It is being squared, so we take the inverse: a square root.
[tex]\sqrt{400}=\sqrt{c^2} \\20=c[/tex]
Now we know the hypotenuse is 20. The side opposite of the angle θ is 16.
opposite= 16 hypotenuse=20[tex]sin (\theta)= \frac {opposite}{hypotenuse} \\sin (\theta)= \frac{16}{20}[/tex]
The sine of the angle is equal to 16/20. This can be reduced to 4/5 if necessary (by dividing the numerator and denominator by 4).
we compute the deviation of the second observation in the data set from the mean, and find that the result is a negative number. this tells us that
When we compute the deviation of the second observation in the data set from the mean, and find that the result is a negative number, this tells us that there is good reason to use the median as opposed to the mean as a measure of central tendency.
Computing the deviationIn computing deviations, it is important to note that extremely skewed deviations can increase the normal distributions and make it difficult to use the standard deviation as a measure of central tendency.
So, when the deviation of the second observation is a negative number, the distribution will be affected and it may become better to use the median as a measure of central tendency.
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Complete Question:
We compute the deviation of the second observation in the data set from the mean, and find that the result is a positive number. This tells us that:
there is a positive overall skewness in the data set.
there is good reason to use the median as opposed to the mean as a measure of central tendency.
the first deviation must also be positive.
the second observation is greater than the sample average.
if fis a differentiable function of rand g(x,y) = f(xy), show that x (dx)/(dg) - y (dg)/(dy) = 0
To prove that x(dx/dg) - y(dg/dy) = 0, we'll start by finding the derivatives of the functions involved.
Given that g(x, y) = f(xy), we can find the partial derivatives of g with respect to x and y using the chain rule:
∂g/∂x = ∂f/∂u * ∂(xy)/∂x = y * ∂f/∂u
∂g/∂y = ∂f/∂u * ∂(xy)/∂y = x * ∂f/∂u
Now, let's differentiate the equation x(dx/dg) - y(dg/dy) = 0:
d/dg (x(dx/dg) - y(dg/dy)) = d/dg (x(dx/dg)) - d/dg (y(dg/dy))
Using the chain rule, we can rewrite the derivatives:
d/dg (x(dx/dg)) = d/dx (x(dx/dg)) * dx/dg = x * d/dx (dx/dg)
d/dg (y(dg/dy)) = d/dy (y(dg/dy)) * dg/dy = y * d/dy (dg/dy)
Substituting these expressions back into the equation, we have:
x * d/dx (dx/dg) - y * d/dy (dg/dy) = 0
Now, let's simplify the equation further. Since dx/dg represents the derivative of x with respect to g, it is essentially the reciprocal of dg/dx, which represents the derivative of g with respect to x:
dx/dg = 1 / (dg/dx)
Similarly, dg/dy represents the derivative of g with respect to y. Therefore, we can rewrite the equation as:
x * d/dx (1/(dg/dx)) - y * d/dy (dg/dy) = 0
Taking the derivatives with respect to x and y, we have:
[tex]x * (-1/(dg/dx)^2) * (d^2g/dx^2) - y * (d^2g/dy^2) = 0[/tex]
Since dg/dx and dg/dy are partial derivatives of g, we can simplify further:
x * (-1/(∂g/∂x)^2) * (∂^2g/∂x^2) - y * (∂^2g/∂y^2) = 0
Finally, using the expressions we found for the partial derivatives of g earlier, we can substitute them into the equation:
x * (-1/(y * ∂f/∂u)^2) * (∂^2f/∂u^2 [tex]* y^2[/tex]) - y * (∂^2f/∂u^2 * [tex]x^2[/tex]) = 0
Canceling out the common factors, we are left with:
∂^2f/∂u^2 * x + ∂^2f/∂u^2 * y = 0
Since ∂^2f/∂u^2 is a constant (it does not depend on x or y), we can factor it out:
∂^2f/∂u^2 * (y - x) = 0
For the equation to hold, we must have either ∂^2f/∂u^2 = 0 or (y - x) = 0. However, the second condition (y - x) = 0 implies that y = x, which is not a necessary condition for the given equation to be true.
Therefore, the only possibility is ∂^2f/∂u^2 = 0, which implies that the equation x(dx/dg) - y(dg/dy) = 0 holds.
In conclusion, we have shown that x(dx/dg) - y(dg/dy) = 0 under the assumption that f is a differentiable function of r and g(x, y) = f(xy).
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I manage to run a mile in 6 minutes. What is my average speed in miles per hour.
Answer:
10 miles per hour
Step-by-step explanation:
If you run a mile in 6 minutes...
10miles x 6minutes is 60 minutes. An hour.
You can run 10 miles in the hour at that rate. Does that make sense?
Please help ASAP!
Find the area of the figure.
Number 5.
Answer:
70 ft squared
Step-by-step explanation:
Separate into rectangle and triangle then add the found areas together for total area.
rectangle...
10×4=40
triangle...
[tex] \frac{bh}{2} = [/tex]
(12×5)/2=
60/2=30
add area for rectangle and triangle...
40+30=70
A sample of 92 one-year-old spotted flounder had a mean length of 123.47 millimeters with a sample standard deviation of 18.72 millimeters, and a sample of 138 two-year-old spotted flounder had a mean length of 129.96 millimeters with a sample standard deviation of 31.60 millimeters. Construct an 80% confidence interval for the mean length difference between two-year-old founder and one-year-old flounder. Let µ_1, denote the mean tength of two-year-old flounder and round the answers to at least two decimal places.
An 80% confidence interval for the mean length difference, in millimeters, between two-year-old founder and one-year old flounder is___<µ_1-µ_2<_____
The 80% confidence interval for the mean length difference between two-year-old and one-year-old spotted flounder is [5.15, 7.83] millimeters.
How to calculate the valueFor an 80% confidence interval, we need to find the critical value associated with a two-tailed test. Since the sample sizes are large, we can use the z-distribution. The critical value for an 80% confidence interval is approximately 1.282.
ME = 1.282 * 1.0466 ≈ 1.3426
Confidence interval = Point estimate ± Margin of error
Confidence interval = 6.49 ± 1.3426
Finally, rounding to at least two decimal places:
Confidence interval = [5.15, 7.83]
Therefore, the 80% confidence interval for the mean length difference between two-year-old and one-year-old spotted flounder is [5.15, 7.83] millimeters.
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If the ratio of shirts to jeans is 5 : 3 and the no. of shirts are 15, what is the no. of jeans?
Answer:
9
Step-by-step explanation:
let x be number of jeans
3/5 = x/15
x=(3/5)15
x=9
Answer:
9 jeans
Step-by-step explanation:
The 5 part of the ratio relates to 15 shirts , then
15 ÷ 5 = 3 ← value of 1 part of the ratio , then
3 parts = 3 × 3 = 9 ← number of jeans
Find all solutions of the equation in the interval [0°, 360°). cos(x) = -1
Answer:
180°
Step-by-step explanation:
cos(x) = - 1 has only 1 solution in the required interval , that is
x = [tex]cos^{-1}[/tex] (- 1) = 180°
6(y - 2) = -18
What is y?
Answer:
-1
Step-by-step explanation:
6 (y - 2) = -18
6y - 12 = -18
6y = -18 + 12
6y = -6
y = -1
Boilermaker House Painting Company incurs the following transactions for September.
1. September 3 Paint houses in the current month for $16,000 on account.
2. September 8 Purchase painting equipment for $17,000 cash.
3. September 12 Purchase office supplies on account for $2,700.
4. September 15 Pay employee salaries of $3,400 for the current month.
5. September 19 Purchase advertising to appear in the current month for $1,100 cash.
6. September 22 Pay office rent of $4,600 for the current month.
7. September 26 Receive $11,000 from customers in (1) above.
8. September 30 Receive cash of $5,200 in advance from a customer who plans to have his house painted in the following month.
BOILERMAKER HOUSE PAINTING COMPANY
Trial Balance
Accounts Debit Credit
Cash $11,300selected answer incorrect not attempted
Accounts Receivable 6,200selected answer incorrect not attempted
Supplies 2,900selected answer incorrect not attempted
Equipment 22,400selected answer incorrect not attempted
Accounts Payable not attempted 3,600selected answer incorrect
Deferred Revenue not attempted 5,000selected answer incorrect
Common Stock not attempted 20,000selected answer incorrect
Retained Earnings not attempted 8,000selected answer incorrect
Service Revenue not attempted 15,000selected answer incorrect
Salaries Expense 3,200selected answer incorrect not attempted
Advertising Expense 1,200selected answer incorrect not attempted
Rent Expense 4,400selected answer incorrect not attempted
Totals $51,600 $51,600
The trial balance provides a summary of Boilermaker House Painting Company's financial transactions for the month of September. The company engaged in several activities during the month, including providing painting services, purchasing equipment and office supplies, paying salaries, renting office space, and receiving cash from customers.
In the first transaction, the company painted houses for customers in the current month, generating service revenue of $16,000 on account. This resulted in an increase in the Accounts Receivable balance, representing the amount owed by customers.
The second transaction involved the purchase of painting equipment for $17,000 in cash. This expenditure was recorded as an increase in the Equipment account, which reflects the company's tangible assets.
Next, the company purchased office supplies on account for $2,700. This transaction increased the Supplies account and created an obligation in the form of an Accounts Payable.
The fourth transaction involved paying employee salaries of $3,400 for the current month. This expense was recorded in the Salaries Expense account, which represents the cost of labor incurred by the company.
In the fifth transaction, the company spent $1,100 in cash to purchase advertising, which was intended to appear in the current month. This expense was recorded in the Advertising Expense account.
The sixth transaction involved paying office rent of $4,600 for the current month. This expense was recorded in the Rent Expense account, representing the cost of utilizing office space.
In the seventh transaction, the company received $11,000 in cash from customers who had previously been billed for the painting services provided. This increased the Cash balance, reflecting the inflow of funds.
Lastly, the company received $5,200 in advance cash from a customer who planned to have their house painted in the following month. This created a liability in the form of Deferred Revenue, as the company had not yet provided the corresponding service.
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