An object has a weight of 9 n when it is in air and 7.2 n when it is submerged into water. what is the specific gravity of the object’s material?

The student's path traces out a rectangle and she ends up at the same spot, so her displacement is 0 m.

On the other hand, she travels a total distance equal to the perimeter of that rectangle,

4.0 m + 8.0 m + 4.0 m + 8.0 m = 24 m

The term "latency" describes the 27 seconds that pass after someone has finished texting or conversing on the phone before they can concentrate again on driving. The given statement is true.

A measure of delay is latency. The amount of time it takes for some data to travel across a network is known as latency.

The amount of time it takes for information to travel from its source to its destination and back is often quantified as a round trip delay.

The 27 seconds that pass after someone has done texting or talking on the phone before they can focus on driving again are referred to as "latency." The assertion is accurate.

Hence, the given statement is true.

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The difference in weight  of a 117 kg person as measured at sea level and at the top of the Vinson Massif, the highest peak in Antarctica is -1.847 N

To find the difference in weight, we find the change in acceleration due to gravity.

The acceleration due to gravity is the acceleration exerted by the force of gravity on an object. It is given by

g = GM/r² where

Now, to find the change in g, we differentiate g with respect to r,

So, dg/dr = d(GM/r²)

= -2GM/r³

So, the change in acceleration due to gravity, Δg is

Δg = dg/dr × Δr

= -2GM/r³ × Δr

Now, Δr = height above sea level of Vinson Massif = 5.14 × 10³ m

Substituting the values of the variables into the equation, we have

Δg = -2GM/r³ × Δr

Δg = [(-2 × 3.99 × 10¹⁴ Nm²/kg)/(6.38 × 10⁶ m)³] × 5.14 × 10³ m

Δg =[ (-7.98 × 10¹⁴ Nm²/kg)/259.69 × 10¹⁸ m³] × 5.14 × 10³ m

Δg = -0.03073 × 10⁻⁴ N/mkg × 5.14 × 10³ m

Δg = -0.1579 × 10⁻¹ N/kg

Δg = -0.01579 N/kg

Since weight W = mg where

The difference in weight is dW = mdg

Since

dW = mdg

= 117 kg × -0.01579 N/kg

= -1.847 N

So, the difference in weight  of a 117 kg person as measured at sea level and at the top of the Vinson Massif, the highest peak in Antarctica is -1.847 N

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The maximum current in the resistor is determined by dividing root mean square current by 0.7071.

The maximum current in the resistor is calculated as follows;

I₀ = I(rms)/0.7071

where;

Thus, the maximum current in the resistor is determined by dividing root mean square current by 0.7071.

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The tension in the cable is mathematically given as

T =266.659 N

Generally, the equation for the angle of the boom with horizontal is  mathematically given as

A = tan-1(5 /10)

[tex]A= 26.57 \textdegree[/tex]

The angle of cable with horizontal

B = tan-1(4 / 10)

B= 21.80 degrees

Hence

175.5 * cos26.57 + 94.7 *cos26.57 * 1/2 = T (sin(26.57+21.80)) * 1

T =266.659 N

In conclusion, the tension in the cable.

T =266.659 N

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(a)The position at the end of 1 s of a point originally at the top of the wheel will be 9.425 radians.

(b)The magnitude and the direction of the acceleration at the end of 1 s will be 1.885 m/sec² clockwise.

Angular acceleration is defined as the pace of change of angular velocity concerning time.

Given data;

Diameter of the wheel,d = 0.2 m

Initial velocity,ω₀ = 0

Angular acceleration,α = c

n = 900 rev min¹

ω = 94.2478 rad /sec

Time of rolling,t = 5 s

From Newton's first equation of motion;

ω = ω₀ + αt

94.2478 rad /sec  = 0 + α(5 sec)

α  = 18.85 rad/sec²

The position at the end of 1 s of a point is found as;

Θ = ω₀t+1/2(αt²)

Θ = 0+1/2[(18.85 rad/sec²) × (1 sec)²]

Θ = 9.425 radian

The magnitude and the direction of the acceleration at the end of 1 s are found as;

a = αr

a= 18.85 rad/sec² × 0.1 m

a = 1.885 m/sec²

Hence the position at the end of 1 s and magnitude and the direction of the acceleration at the end of 1 s will be  18.85 rad/sec²and the magnitude and the direction of the acceleration at the end of 1 s will be 1.885 m/sec² clockwise.

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The horizontal component of the vector is determined as 6i.

The horizontal component of the vector is calculated as follows;

V = (0 i, 0 j) + (6i, 8j)

V = (6i, 8j)

where;

Thus, the horizontal component of the vector is determined as 6i.

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(a) The maximum height reached by the projectile is 10.2 m and

(b) The horizontal distance traveled by the projectile is 40.8 m.

H = u²sin²θ/2g

H = (20²(sin(45))² / (2 x 9.8)

H = 10.2 m

T = (2u sinθ)/g

T = (2 x 20 x sin(45) )/(9.8)

T = 2.886 s

x = (v cos(45) x t

x = (20 x cos(45)) x 2.886

x = 40.8 m

Thus, the maximum height reached by the projectile is 10.2 m and the horizontal distance traveled by the projectile is 40.8 m.

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Hi there!

Let's break this problem up into two parts.

Part A: Solenoid

The magnetic field everywhere inside a solenoid is constant, and can be found using the equation:

[tex]B = \mu_0 nI[/tex]

B = Magnetic field strength (? T)
μ₀ = Permeability of Free Space (4π × 10⁻⁷ Tm/A)
n = number of turns/meter (900)

I = current (0.03 A)

We are given all of these values, so let's solve.

[tex]B = (4\pi \times 10^{-7})(900)(0.03) = 34\mu T[/tex]

However, we also have a long wire that produces a magnetic field perpendicular to that produced by the solenoid.

Part B: Long wire

The equation for the magnetic field produced by a long wire is found by:

[tex]B = \frac{\mu_0 I}{2\pi r}[/tex]

Where 'r' is the distance from the wire.

Plug in what we know:

[tex]B = \frac{(4\pi \times 10^{-7})(3)}{2\pi (0.02)} = \mu 30 T[/tex]

Now, we must do the vector sum of these two fields to find the total magnetic field. Since they are perpendicular (solenoid field points to the side, wire fire points in or out), we can use the Pythagorean Theorem.

[tex]B_T = \sqrt{B_s^2 + B_w^2}\\\\B_T = \sqrt{(34\mu T)^2 + (30\mu T)^2} \approx \boxed{45\mu T}[/tex]

And here's our answer!

The time  period of the pendulum is  0.65 second.

The time period is a period of time during which a behavior takes place or a condition persists. Depending on the type of activity or condition under consideration, it may be expressed either in seconds or in millions of years.

The mass of the object is = 0.10 kg

Length of the string is = 0.10 m.

Acceleration due to gravity is = 9.8 m/s²

Hence,  the time  period of the pendulum is = 2π√(0.10/9.8) sec

= 0.65 second.

Hence, the time period of the pendulum is  0.65 second.

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Lindsay should fly the plane in the direction [W 12.5° S] to get Hamilton.

Using Sine rule to solve this question

Sine rule => SinA/a = SinB/b = SinC/c = constant

The magnitude of wind is 50 with an angle of 60 degrees.

The magnitude of plane is 200 and the angle at which it should fly is unknown and should be θ.

One side is 50 km/hr at an angle of 60 degrees.

sin 60°/200 = sin θ / 50

50 × sin 60° = 200 × sin θ

√3/2 = 4 × sin θ

√3/8 = sin θ

sin θ = 0.2165

θ = sin⁻¹(0.2165)

θ = 12.5°

So Lindsay have to fly the plane in the direction of [W 12.5° S].

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The number of windings that would be needed to produce an output of 110V AC will be 2750.

Electromagnetic induction is what causes the induced voltage. Electromagnetic induction is the process of generating emf (induced voltage) by subjecting a conductor to a magnetic field.

Typically, a transformer's primary winding is attached to the input voltage source and changes electrical power into a magnetic field.

The secondary winding's role is to turn this alternating magnetic field into electricity, generating the necessary output voltage.

The relation between the primary and the secondary winding is;

[tex]\rm \frac{V_s}{V_p}= \frac{N_s}{N_p} \\\\ \frac{110}{12000}= \frac{N_S}{300000} \\\\ N_s = 2750 \[/tex]

Transformers can only operate on AC current, since a flux shift is required for the induction process.

Additionally, since there won't be any flux change phenomena in the DC supply, the induction process can't take place. Transformers are utilized in AC supplies because of this.

Hence, the number of windings that would be needed to produce an output of 110V AC will be, 2750 and a transformer only works with AC.

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The tension in the rope B is determined as 10.9 N.

tanθ = (6 - 4)/(5 - 0)

tan θ = (2)/(5)

tan θ = 0.4

θ = arc tan(0.4) = 21.8 ⁰

θ = 21.8 ⁰ + 21.8 ⁰ = 43.6⁰

Apply cosine rule to determine the tension in rope B;

A² = B² + C² - 2BC(cos A)

B = C

A² = B² + B² - (2B²)(cos A)

A² = 2B² - 2B²(cos 43.6)

A² = 0.55B²

B² = A²/0.55

B² = 65.3/0.55

B² = 118.73

B = √(118.73)

B = 10.9 N

Thus, the tension in the rope B is determined as 10.9 N.

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A magnetic field is a field explaining the magnetic influence on an object in space.

A electric field is a field defined by the magnitude of the electric force at any given point in space.

A magnetic field is a field explaining the magnetic influence on an object in space.

A electric field is a field defined by the magnitude of the electric force at any given point in space.

The difference between magnetic fields and electric filed are:

Electric Filed

Magnetic Filed:

Similarities between Electric and Magnetic Field

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The magnitude of the force on the left-hand pole is mathematically given as

f'=0.167N

[tex]Q=45 \textdegree[/tex]

Generally, the equation for Force is  mathematically given as

[tex]F=\frac{mg}{sin\theta}[/tex]

Therefore

[tex]F=\frac{17.1*10^{-3}*9.8}{sin45}[/tex]

F=0.237N

Considering horizontal

f'-fcos=0

Therefore

f'=0.237*cos45

f'=0.167N

In conclusion, the slope

[tex]tan\theta=lv/ln\\\\tan\theta=30/30\\\\\theta=tan^{-1}\\\\[/tex]

[tex]Q=45 \textdegree[/tex]

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The answer to the question is that the vertical distance the ball clear the cross bar is 1.465 metres.

We have horizontal distance as 28 m, and velocity as 18 m/s and the angle of projection 46.8 degree.

so, we can say that

In horizontal direction,

28 = (18 cos 46°) t

t = 2.2723 seconds

Now, in vertical direction,

Let be the height of the ball

h = (18 sin 46°)t - (1/2)gt²

h = (18 sin 46°)t - 4.9t²

h = ( (13.1214) × (2.2723) ) - ( (4.9) × (2.2723)² )

h = 4.5154 metre

Vertical distance the ball clear the cross bar = h - 3.05

Vertical distance the ball clear the cross bar = 4.5154 - 3.05

Vertical distance the ball clear the cross bar = 1.465

Thus, we can conclude that after solving and applying the concepts of projectile motion we find out the vertical distance the ball will clear the cross bar is 1.465 metres.

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I don't think the provided solution is correct because it's not dimensionally consistent. The quantity [tex]8h-1[/tex] in particular doesn't make sense since it's mixing a distance with a dimensionless constant.

Here's how I think the proper answer should look:

The net force on the box acting perpendicular to the ramp is

[tex]\sum F_\perp = F_{\rm normal} - mg \cos(\theta) = 0[/tex]

where [tex]F_{\rm normal}[/tex] is the magnitude of the normal force due to contact with the ramp and [tex]mg\cos(\theta)[/tex] is the magnitude of the box's weight acting in this direction. The net force is zero since the box doesn't move up or down relative to the plane of motion.

The net force acting parallel the ramp is

[tex]\sum F_\| = mg\sin(\theta) - F_{\rm friction} = ma[/tex]

where [tex]mg\sin(\theta)[/tex] is the magnitude of the parallel component of the box's weight, [tex]F_{\rm friction}[/tex] is the magnitude of kinetic friction, and [tex]a[/tex] is the acceleration of the box.

From the first equation, we find

[tex]F_{\rm normal} = mg \cos(\theta)[/tex]

and since [tex]F_{\rm friction} = \mu F_{\rm normal}[/tex], we get from the second equation

[tex]mg\sin(\theta) - \mu mg\cos(\theta) = ma[/tex]

and with [tex]\mu = 0.25[/tex] and [tex]\theta=60^\circ[/tex], we get

[tex]a = g\sin(60^\circ) - 0.25g \cos(60^\circ) = \left(\dfrac{\sqrt3}2 - \dfrac18\right) g[/tex]

Let [tex]x[/tex] be the length of the ramp, i.e. the distance that the box covers as it slides down it. Then the box attains a final velocity [tex]v[/tex] such that

[tex]v^2 = 2ax[/tex]

From the diagram, we see that

[tex]\sin(\theta) = \dfrac hx \implies x = \dfrac h{\sin(60^\circ)} = \dfrac{2h}{\sqrt3}[/tex]

and so

[tex]v^2 = \dfrac{4ah}{\sqrt3} = \left(2 - \dfrac1{2\sqrt3}\right) hg = \dfrac14 \left(8 - \dfrac2{\sqrt3}\right) hg[/tex]

[tex]\implies v = \dfrac12 \sqrt{\left(8 - \dfrac2{\sqrt3}\right) hg}[/tex]

The speed of the longitudinal waves along the spring is 1.5 m/s.

The wavelength of the longitudinal waves produced when the free end is moved to and fro is 0.6 m.

The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave. The wavelength is the reciprocal of the frequency of the wave.

Wavelength λ = c/f

where c is the speed of light in vacuum = 3*10⁸ m/s

A slinky spring 3m long rests on a horizontal bench with one end fixed. When the free end is suddenly pushed forward, the compression pulse travels to the fixed end and back in 2 secs.

λ = v/f

v =fλ =λ /T where T is the time period = 2sec

Put the values we get

v = 3/2 =1.5 m/s

Thus, the speed of wave is 1.5 m/s.

Using the same expression for frequency 2.5Hz, wavelength is

λ = v/f

λ = 1.5 /2.5 = 0.6 m

Thus,  the wavelength is 0.6m.

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The magnitude and direction of the resultant force will be 7.65 units and 40.2°.

Force is explained as the multiplication of mass and acceleration. Its unit is N. It is the external agent which helps to change the shape and size of an object.

Force is used to push and pull the object and sometimes changes the direction of motion. The net force acting on an object is equal to the sum of all forces acting upon it.

F = F1 + F2 + F3

Given data;

Megnitude of force 1, F₁ =  5.90 units

Megnitude of force 2, F₂ = 5.00 units

α is the angle between the two forces=36.0°

Θ is the angle of the resultant force

The megnitude of the resultant force is;

[tex]\rm F =\sqrt{ F_{1}+F_{2}+2F_{1}F_{2}cos \alpha }\\\\ F = \sqrt{5.90 + 5.00 +2 \times 5.90 \times 5 \times cos 36^0 } \\\\ F = 7.65 \ units[/tex]

The direction of the resultant force is;

[tex]\rm \theta = tan^{-1}(\frac{F_{2}}{F_{1}} )[/tex]

[tex]\rm \theta = tan^{-1}(\frac{5.00}{5.90})\\\\ \theta = 40.2 ^0[/tex]

Hence the magnitude and direction of the resultant force will be 7.65 units and 40.2°.

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The acceleration due to gravity of the asteroid is 833.85 N.

F = mg

where;

Assuming the acceleration due to gravity of the asteroid = 9.81 m/s²

F = 85 x 9.81

F = 833.85 N

Thus, the acceleration due to gravity of the asteroid is 833.85 N.

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A. The angle at which the arrow must be released to hit the bull's-eye is 20.7 °

B. The arrow will go over the branch.

R = u²Sine(2θ) / g

74 = 33² × Sine (2θ) / 9.8

Cross multiply

74 × 9.8 = 33² × Sine (2θ)

725.2 = 1098 × Sine (2θ)

Divide both sides by 1098

Sine (2θ) = 725.2 / 1098

Sine (2θ) = 0.6605

Take the inverse of sine

2θ = Sine⁻¹ 0.6605

2θ = 41.3

Divide both sides by 2

θ = 41.3 / 2

θ = 20.7 °

To determine if the arrow will go over or under the branch situated mid way, we shall determine the maximum height attained by the arrow. This can be obtained as follow:

H = u²Sine²θ / 2g

H = [33² × (Sine 20.7)²] / (2 ×9.8)

H = 6.94 m

Thus, the maximum height attained by the arrow is 6.94 m which is greater than the height of the branch (i.e 3.50 m).

Therefore, we can conclude that the arrow will go over the branch

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Answer:

B. why you must push harder to move a car farther.

Explanation:

acceleration (gaining speed) happens when a force acts on a mass (object). FORCE=MASSxACCELERATION

The option above which most directly shows how society affects physics is that physicists work on projects that will get them nominated for Nobel prize.

A physicist is a person who who studies physics.

Physics is one of the branches of science which involves the study of matter, light, mechanics...

In conclusion: the option below which most directly shows how society affects physics is that physicists work on projects that will get them nominated for Nobel prize.

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The tension in rope A is 740.88 N, the tension carried by rope B is 751.4 N and the tension carried by rope C is -124 N.

tan θ = Δy/Δx

tan θ = (10 - 4)/(5 - 4)

tan θ = 6

θ = arc tan (6) = 80.53

C sin(0) + B sin(80.53)  = A sin(90)

C sin(0) + B sin(80.53)  = (75.6 x 9.8)

0 + 0.986 B = 740.88

0.986 B = 740.88

B = 740.88/0.986

B = 751.4 N

C cos(0) + B cos(80.53) = (75.6 x 9.8) cos(90)

C + 0.165 B = 0

C + 0.165(751.4) = 0

C + 124 = 0

C = - 124 N

Thus, the tension in rope A is 740.88 N, the tension carried by rope B is 751.4 N and the tension carried by rope C is -124 N.

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Answer:

B) Quickly understanding something without needing mental reasoning

Answer:

[tex]\huge\boxed{\sf Option \ B}[/tex]

Explanation:

So, Intuition actually means quickly understanding something without needing mental reasoning.

[tex]\rule[225]{225}{2}[/tex]

Answer:

A

Explanation:

ggtytryofttytrtuuyytyuygy

The magnitude of the current in the third wire is 8 A.

E₁ + E₂ + E₃ = 0

Equidistance from the two wires = 0.5 m

Apply Biot Savart rule to determine the magnitude of the magnetic field.

μI/2πr₁ + μI/2πr₂ + μI/2πr₃ = 0

(4π x 10⁻⁷ x 4)/(2π x 0.5) + (4π x 10⁻⁷ x 4)/(2π x 0.5) + (4π x 10⁻⁷ x I₃)/(2π x 0.5) = 0

4 x 10⁻⁷ I₃ = -3.2 x 10⁻⁶

I₃  = (-3.2 x 10⁻⁶)/(4 x 10⁻⁷)

I₃ = - 8 A

Thus, the magnitude of the current in the third wire is 8 A.

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Two mirrors are arranged such that they are parallel to each and perpendicular to the third mirror.

Also, the light is placed at the center of the three mirrors to produce multiple images by reflection.

Reflection is the bouncing back of light waves of a reflective surface when light shines on that surface.

The knowledge of reflection of light can be used by the Barber to set up a good salon.

The mirrors are arranged in the salon such that two of the mirrors are parallel to each and perpendicular to the third mirror. Also, the light is placed at the center of the three mirrors.

The parallel arrangement of the mirror will ensure that the clients will be able to have a full frontal and back view of themselves.

The parallel and perpendicular arrangement of the mirrors will also ensure that the light placed at the center will produce reflected to produce infinite images thus lighting up the salon.

In conclusion, the reflective properties of the mirrors as well as the angle between mirrors is used to create a well-lit salon by the barber.

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Newton thinks that object falls due to gravity whereas Einstein thinks gravity is not the reason behind it.

Newton concluded that objects fall because they are pulled by Earth's gravity. Einstein's thinks that these objects do not fall due to gravity. According to Einstein, these objects and Earth just freely move in a curved spacetime

So we can conclude that Newton thinks that object falls due to gravity whereas Einstein thinks gravity is not the reason behind it.

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