Answer:
Since the astronaut drops the rock, the initial velocity of the rock is 0 m/s
We are given:
initial velocity (u) = 0 m/s
final velocity (v) = v m/s
acceleration (a) = 1.62 m/s/s
height (h) = 1.25 m
Solving for v:
From the third equation of motion:
v²-u² = 2ah
replacing the variables
v² - (0)² =2 (1.62)(1.25)
v² = 1.62 * 2.5
v² = 4 (approx)
v = √4
v = 2 m/s
The speed of the rock just before it lands is 2 m/s
2.9030 has 4 significant digits.
TRUE OR FALSE
When light waves hit ice, most of them bounce off and radiate back into space. Because of this, ice is best described as which kind of surface?
Answer:
Reflective surface
Explanation:
Ice is a reflective surface because most the of the light waves that hits on it bounces off.
When a surface is smooth and polish, it acts a reflector. When a surface is jagged and not smooth light does not readily reflect. Reflection is through the incident angle of the light waves.Therefore, snow is a reflective surface.
Social science is a branch of science that deals with the nature of
A. human society
B. the physical world
C. animal societies
D. the medical field
Answer:
A. human society
Explanation:
A 0.6 kg basketball moving 7.2 m/s to the right collides with a 0.04 kg tennis
ball moving 22 m/s to the left. After the collision, the tennis ball is moving
32.7 m/s to the right. What is the velocity of the basketball after the collision?
Assume an elastic collision occurred.
A. 10.9 m/s to the right
B. 10.9 m/s to the left
C.3.6 m/s to the left
D. 3.6 m/s to the right
Answer:b
Explanation:
The final velocity of the basketball after it undergoes collision with the tennis ball is 6.49m/s.
What is Final velocity?The final velocity is a vector quantity which measures the speed and direction of a moving object after it has reached its maximum acceleration and distance.
Given data,
mass of basket ball (m₁) = 0.6kg
mass of tennis ball (m₂) = 0.04kg
velocity of basket ball (v₁) = 7.2m/s
velocity of tennis ball (v₂) = 22m/s
velocity of basket ball (v₃) =?
velocity of tennis ball (v₄) = 32.7m/s
We already know that the expression for elastic collision is given as
m₁v₁ +m₂v₂ = m₁v₃ + m₂v₄
Substituting these values, we get
0.6 × 7.2 + 0.04 × 22 = 0.6 × x + 0.04 × 32.7
4.32 + 0.88 = 0.6x + 1.308
Solving for x we have,
3.892 = 0.6x
x = 3.892 /0.6
x=6.49m/s
Therefore, the velocity of the basketball after the collision is 6.49m/s.
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Which statement is true of the electric field at a distance from the source charge?
A it is independent of the source charge
B It is directly proportional to the source charge
C it is inversely proportional to the source charge
D it is directly proportional to the distance
Answer:
It is directly proportional to the source charge.
Explanation:
I found it pretty sure it's right hit me up on my insta
desiignerjoe173
what is the acceleration of a cat who starts from rest and moves 11.5 m in 2.8 s?
Answer:
The acceleration is 4
Explanation:
use the formula v= change in position/change in time for vecter quantity's which will be in word problems that say acceleration or velocity.
Why is friction like applied force but different from gravity?
Answer:
Friction is when a force is applied or done by weight dragging onto something.
Explanation:
Gravity is when an object is getting pulled toward the center of what is attracting it. And applied force is when someone/sommething is applying force.
I need helpppppppppppppppppppppppppppppppppppppppppppppp
Answer:u
Laa c
Explanation:
a hole is punched at a height h in the side of a container of height h0. The container is full of water. If the water is to shoot as far as possible horizontally, (a) how far from the bottom of the container should the hole be punched? (b) Neglecting frictional losses, how far (initially) from the side of the container will the water land?
Calculate the magnetic field at the center of a circular current loop of radius R divided by the magnetic field at a distance R away from a very long straight wire carrying the same current value I. (Note the loop and wire are not in electrical contact.)
Answer:
The magnetic field at the center of a circular current loop of radius R divided by the magnetic field at a distance R away from a very long straight wire carrying the same current value I is [tex]\pi[/tex] or 3.14
Explanation:
The magnetic field at center of a circular loop is given by
[tex]B = \frac{\mu _{o}I }{2R}[/tex]
Where B is the magnetic field
[tex]\mu _{o}[/tex] is the free space permeability constant ( [tex]\mu _{o}[/tex] = 4π × 10⁻⁷ N/A²)
[tex]I[/tex] is the current
and [tex]R[/tex] is the radius
For the magnetic field of a long straight wire, it is given by
[tex]B = \frac{\mu _{o}I }{2\pi R}[/tex]
Where B is the magnetic field
[tex]\mu _{o}[/tex] is the free space permeability constant ( [tex]\mu _{o}[/tex] = 4π × 10⁻⁷ N/A²)
[tex]I[/tex] is the current
and [tex]R[/tex] is the distance from the wire
Then, to calculate the magnetic field at the center of a circular current loop of radius R divided by the magnetic field at a distance R away from a very long straight wire carrying the same current value I, that will be
[tex]\frac{\mu _{o}I }{2R} \div \frac{\mu _{o}I }{2\pi R}[/tex]
= [tex]\frac{\mu _{o}I }{2R} \times \frac{2\pi R }{\mu _{o}I}[/tex]
= [tex]\pi[/tex]
(NOTE: [tex]\pi[/tex] = 3.14)
Hence, the magnetic field at the center of a circular current loop of radius R divided by the magnetic field at a distance R away from a very long straight wire carrying the same current value I is [tex]\pi[/tex] or 3.14.
What is the takeoff distance for an airplane on a runway at
300km/hr with acceleration of 1 m/s 2
Answer:
x = 3472 [m]
Explanation:
To solve this problem we must use the following expression of kinematics:
[tex]v_{f}^{2}= v_{i}^{2}+(2*a*x)\\[/tex]
where:
Vi = initial velocity = 0
Vf = final velocity = 300 [km/h]
a = acceleration = 1 [m/s^2]
x = takeoff distance [m]
Note: The initial velocity is equal to zero as avion starts its movement from rest.
Now we have to convert units of kilometers per hour to meters per second, the final velocity.
[tex]300 [\frac{km}{h}]*[\frac{1h}{3600s} ]*\frac{1000m}{1km} \\= 83.33 [\frac{m}{s} ][/tex]
(83.33)^2 = 0 + (2*1*x)
2*x = 6943.88
x = 3472 [m]
What is the final velocity of a running back that is moving with an initial velocity of 2 m/s and accelerates at a rate of 4 m/s$$ in 5 seconds as he moves toward the defensive line?
Answer:
Final velocity = 22
Explanation:
22-2/5= 4
20/5=4
so add to so it is not 18/5
Then you get your answer.
Answer:
4. A sound wave moves towards a building at 5 m/s for 22 seconds.
Explanation:
4. State in words how acceleration is calculated.
Acceleration can be calculated by dividing the change in velocity by the change in time. If we have a mass and force that makes the acceleration, the divide the force by mass to get the acceleration.
What is acceleration ?Acceleration is a physical quantity which describes the rate of change in velocity. Like velocity, acceleration is a vector quantity having both magnitude and direction.
If both speed and direction are changing and if we want to know the acceleration at any particular moment in time, calculating acceleration can be challenging.
However, since just speed is changing, it is quite simple to determine average acceleration over time. After then, acceleration is equal to the time change divided by the velocity change.
a = ΔV/Δt
Similarly if have the force which accelerates a body of mass m, then the acceleration is the ratio of that force to the mass.
a = F/m
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A force of 50n is applied to an object at an angle of 50 degrees measured relative to the horizontal. Determine the horizontal and vertical components of the applied force?
Answer:
Fx = 32.14 [N]
Fy = 38.3 [N]
Explanation:
To solve this problem we must decompose the force vector, for this we will use the angle of 50 degrees measured from the horizontal component.
F = 50 [N]
Fx = 50*cos(50) = 32.14 [N]
Fy = 50*sin(50) = 38.3 [N]
We can verify this result using the Pythagorean theorem.
[tex]F = \sqrt{(32.14)^{2}+ (38.3)^{2}} \\F = 50 [N][/tex]
1) Which of the following is considered an effective treatment for someone with hearing loss based on nerve damage?
TAD
Cochlear implant
Hearing aid
OBI
No treatment available
2) Sylvester is dealing with hearing loss. The doctor informs him that his basilar membrane is damaged. What type of hearing loss is Sylvester experiencing?
Nerve deafness
Conduction hearing loss
Cochlear hearing loss
Conduction deafness
Sensory hearing loss
Answer:
For number 1 no treatment available , number 2 cochlear hearing loss
Explanation:
nerve damage is permanent
Part D
Which two kinds of energy are associated with flames?
Answer:
Thermal energy and electrical energy
Explanation:
Answer:
Hello!!! Princess Sakura here ^^
Explanation:
The two kinds of energy are thermal and electrical.
Atoms tend to be stable and nonreactive if they have six valence electrons.
Select one:
O True
O False
Answer:
True
Explanation:
What is the acceleration along the ground of a 18 kg wagon when it is pulled with a force of 91 N at an angle of 35° Above the horizontal?
Answer:
4.1 m/s²
Explanation:
Net force in the x direction equals the mass times the acceleration.
∑F = ma
91 cos 35° = (18 kg) a
a = 4.1 m/s²
Answer:
Explanation:
bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb
The table represents the speed of a car in a northern direction over several seconds. Column 1 would be on the x-axis, and Column 2 would be on the y-axis. Which best lists the titles of each column? Column 1 0 2. 4 6 8 10 Column 2 5 10 15 20 25 30 O Column 1 should be titled "Time," and Column 2 should be titled "Velocity." O Column 1 should be titled "Velocity," and Column 2 should be titled "Time." O Column 1 should be titled "Time," and Column 2 should be titled "Acceleration." O Column 1 should be titled "Acceleration," and Column 2 should be titled "Time."
Answer:
Column 1 should be titled “Time,” and Column 2 should be titled “Velocity.”
Explanation:
electromagnetic waves and sound waves can have the same frequency. what is the wavelength of a 1.00kHz electromagnetic wave
The diagram below represents an electromagnetic wave. Please Help
Answer:
I'm pretty sure it's A
Explanation:
bc the crest is is the point on the wave
A shot-putter exerts an unbalanced force of 128 N on a shot giving it an acceleration of 19
m/s2. What is the mass of the shot?
Answer:
128 is the ans cuz N is also lnown as mass
Explanation:
128
1.What is the mass of an object that weighs 98 N?
Answer:
10 kg
Explanation:
A microwave oven operates at 2.00 GHz . What is the wavelength of the radiation produced by this appliance?
Answer:
Wavelength = 0.15 m
Explanation:
The frequency of a microwave oven is 2.00 GHz or [tex]2\times 10^9\ Hz[/tex].
We need to find the wavelength of the radiation produced by this appliance. We know that the relationship between the frequency and wavelength is given by :
[tex]c=f\lambda[/tex]
Where,
[tex]\lambda[/tex] is the wavelength
So,
[tex]\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{2\times 10^9}\\\\=0.15\ m[/tex]
So, the wavelength of the radiation produced by this appliance is 0.15 m.
As part of a carnival game, a 5.00 kg target is freely hanging from a very long and very light wire. Contestants can use one of two 1.5 kg balls to try to hit the target and deflect it high enough to win a prize. Ball A will have an elastic collision and bounce back toward you while ball B will have a nearly perfectly inelastic collision, but rather than sticking to the target, the ball will just drop straight downward to the ground after the collision. You can throw each ball with a velocity of 12 m/s. You are the first to try the game and which ball should you throw? Calculate the expected height the target will reach after each is thrown.
Answer:
Height ball A will deflect the target is 2.65 m
Height ball A will deflectthe target is 2.2 m
Ball A, will deflect the target to greater height, thus i will throw ball A
Explanation:
Given;
mass of the target, m₁ = 5.00 kg
mass of the ball, m₂ = 1.5 kg
initial velocity of each throw, u = 12 m/s
Throwing ball A; apply the principle of conservation linear momentum for elastic collision;
m₁u₁ + m₂u₂ = v₁m₁ + v₂m₂
The initial velocity of the target, u₁ = 0
The ball bounced back at the same speed, v₂ = -12 m/s
the velocity of the target after collision, = v₁
0 + 1.5 x 12 = v₁(5) + (-12 x 1.5)
18 = 5v₁ - 18
18 + 18 = 5v₁
36 = 5v₁
v₁ = 36/5
v₁ = 7.2 m/s
The vertical height reached by the target is given by;
v₁² = u₁² + 2gh
v₁² = 0 + 2gh
v₁² = 2gh
h = v₁² / 2g
h = (7.2)² / (2 x 9.8)
h = 2.65 m
Throwing ball B; apply the principle of conservation energy for the inelastic collision;
the kinetic energy of the ball will be converted to the potential energy of the target.
¹/₂m₁u₂² = mgh
¹/₂(1.5)(12)² = (5 x 9.8)h
108 = 49h
h = 108 / 49
h = 2.2 m
Ball A will deflect the target to greater height, thus i will throw ball A.
Which of the following would be useful to show the growth rate of plants at varying temperatures?
bar graph
circle graph
line graph
frequency table
Answer:
line graph
Explanation:
Ik im late but i hope this helps lol
answer
prove that p = d g h
Answer:
Proving LHS=RHS
Explanation:
Given
p=dgh
Multiplying by 0 on both sides of the equations
p×0=dgh×0
0=0
:- Hence proved
What is the formula for speed?
गतत का सूत्र क्या है?
A : Distance covered/Time | तय की गई
दरूी/समय
B : Change in velocity/Time | वेग में
पररवतषन/समय
C : Distance in definite direction /Time |
तनजचचत टदशा में दरूी/समय
D : Change in momentum/Time | संवेग में
पररवतषन/समय
Ans:
A : Distance covered/Time | तय की गई
दरूी/समय
Explanation:
Formula for speed = Distance covered/Time
Therefore,
Option A is correct.
Answer:
a.distance÷timetaken
Explanation:
The formula for speed is speed = distance ÷ time. To work out what the units are for speed, you need to know the units for distance and time. In this example, distance is in metres (m) and time is in seconds (s), so the units will be in metres per second (m/s).
Can someone please help me
Answer:
grams= 4.8e-5
kilograms= 4.8e-8
centigrams= 0.0048
dekagrams= 4.8e-6
Explanation:
A projectile is fired into the air at an angle of 50° above ground level and hits a target downrange. Neglecting air drag, it will also hit the target if fired at the same speed at an angle of
Answer:
18 m/s
Explanation:
Range of a projectile on level ground is:
R = v₀² sin(2θ) / g
14.3 m = v₀² sin(2×13°) / 9.8 m/s²
v₀ = 17.9 m/s
Rounded to two significant figures, the launch speed was 18 m/s.
If the bullet is launched at an angle of 50 degrees above ground level, the target will be struck. The angle remains the same. The launch angle obtained is 50 degrees.
Given:
The initial shot was fired at an angle of 50 degrees above ground.
The projectile's starting velocity (v) and magnitude of velocity will remain constant if it is shot at the same pace.
Let the angle of the projectile is x,
The horizontal component of velocity can be calculated as follows:
[tex]v(x) = v * cos(x)[/tex]
We can write:
since the horizontal part of velocity remains constant:
[tex]v(x1) = v(x2)[/tex]
[tex]cos(50) = cos(x)[/tex]
[tex]50 = x[/tex]
Therefore, if the projectile is launched at the same speed at a 50° angle above ground level, it will strike the target.
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The correct response is given when the angle is asked a question.