Help please!!!!!!!!!!!!!

Answer:

Net force= 14 units

The object is unbalanced

Explanation:

The net force refers to the sum of all forces applied to an object. However, the direction of force applied determine the net force. In this question, a boy and girl is pulling a heavy crate at the same time.

This means that the force is in the same direction, hence, the net force will be:

F(N) = 7 + 7 = 14 unit

However, since the pull is occuring at the same direction. This means that the object has a net force, therefore, will move in a particular direction. This means that the OBJECT IS UNBALANCED

Answer:

Column 1 should be titled “Time,” and Column 2 should be titled “Velocity.”

Explanation:

Answer: D. 14 m/s west

Explanation:

I just did it on A p e x

Answer:

4.1 m/s²

Explanation:

Net force in the x direction equals the mass times the acceleration.

∑F = ma

91 cos 35° = (18 kg) a

a = 4.1 m/s²

Answer:

Explanation:

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Answer:

Wavelength = 0.15 m

Explanation:

The frequency of a microwave oven is 2.00 GHz or [tex]2\times 10^9\ Hz[/tex].

We need to find the wavelength of the radiation produced by this appliance. We know that the relationship between the frequency and wavelength is given by :

[tex]c=f\lambda[/tex]

Where,

[tex]\lambda[/tex] is the wavelength

So,

[tex]\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{2\times 10^9}\\\\=0.15\ m[/tex]

So, the wavelength of the radiation produced by this appliance is 0.15 m.

Answer:b

Explanation:

The final velocity of the basketball after it undergoes collision with the tennis ball is 6.49m/s.

The final velocity is a vector quantity which measures the speed and direction of a moving object after it has reached its maximum acceleration and distance.

Given data,

mass of basket ball (m₁) = 0.6kg

mass of tennis ball (m₂) = 0.04kg

velocity of basket ball (v₁) = 7.2m/s

velocity of  tennis ball (v₂) = 22m/s

velocity of basket ball (v₃) =?

velocity of  tennis ball (v₄) = 32.7m/s

We already know that the expression for elastic collision is given as

m₁v₁ +m₂v₂ = m₁v₃ + m₂v₄

Substituting these values, we get

0.6 × 7.2 + 0.04 × 22 = 0.6 × x + 0.04 × 32.7

4.32 + 0.88 = 0.6x + 1.308

Solving for x we have,

3.892 = 0.6x

x = 3.892 /0.6

x=6.49m/s

Therefore, the velocity of the basketball after the collision is 6.49m/s.

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Answer:

Fx = 32.14 [N]

Fy  = 38.3 [N]

Explanation:

To solve this problem we must decompose the force vector, for this we will use the angle of 50 degrees measured from the horizontal component.

F = 50 [N]

Fx = 50*cos(50) = 32.14 [N]

Fy = 50*sin(50) = 38.3 [N]

We can verify this result using the Pythagorean theorem.

[tex]F = \sqrt{(32.14)^{2}+ (38.3)^{2}} \\F = 50 [N][/tex]

Answer:

Claim: Heart Rate for Sarah and Matt (this would be the homeostasis AT REST and throughout the graph time)

Evidence: The Graph and the HR/S and its evidence towards the heart rate/beats every 15 seconds, due to the homeostasis being a specific time limit and due to the specific heart rate of Matt and Sarah ONLY.

Explanation: A/B Checkpoint throughout the homeostasis (this would be heart rate/trial throughout the time of the graph)

Conclusion: Matt was further away ONLY BECAUSE Sarah has a higher Heart Rate during the time on the graph, which can represent how long they did something to increase/decrease from and where the homeostasis would be located.

Answer:

Claim: Heart Rate for Sarah and Matt (this would be the homeostasis AT REST and throughout the graph time)

Evidence: The Graph and the HR/S and its evidence towards the heart rate/beats every 15 seconds, due to the homeostasis being a specific time limit and due to the specific heart rate of Matt and Sarah ONLY.

Explanation: A/B Checkpoint throughout the homeostasis (this would be heart rate/trial throughout the time of the graph)

Conclusion: Matt was further away ONLY BECAUSE Sarah has a higher Heart Rate during the time on the graph, which can represent how long they did something to increase/decrease from and where the homeostasis would be located.

Answer:

Friction is when a force is applied or done by weight dragging onto something.

Explanation:

Gravity is when an object is getting pulled toward the center of what is attracting it. And applied force is when someone/sommething is applying force.

Answer:

Axial and Appendicular Skeletons The axial skeleton forms the central axis of the body and consists of the skull, vertebral column, and thoracic cage. The appendicular skeleton consists of the pectoral and pelvic girdles, the limb bones, and the bones of the hands and feet. Figure 6.41.

Explanation:

Acceleration can be calculated by dividing the change in velocity by the change in time. If we have a mass and force that makes the acceleration, the divide the force by mass to get the acceleration.

Acceleration is a physical quantity which describes the rate of change in velocity. Like velocity, acceleration is a vector quantity having both magnitude and direction.

If both speed and direction are changing and  if we want to know the acceleration at any particular moment in time, calculating acceleration can be challenging.

However, since just speed is changing, it is quite simple to determine average acceleration over time. After then, acceleration is equal to the time change divided by the velocity change.

a = ΔV/Δt

Similarly if have the force which accelerates a body of mass m, then the acceleration is the ratio of that force to the mass.

a = F/m

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Answer:

Measure change in temperature after long call

Explanation:

Answer:

It is directly proportional to the source charge.

Explanation:

I found it pretty sure it's right hit me up on my insta

desiignerjoe173

Answer:

Yes

Explanation:

The star would have died over thousands of years ago but the light takes a long time for it to reach us on Earth.

Answer:

For number 1 no treatment available , number 2 cochlear hearing loss

Explanation:

nerve damage is permanent

Answer:

5.1 m

Explanation:

Given in the y direction:

v₀ = 10 m/s

v = 0 m/s

a = -9.8 m/s²

Find: Δy

v² = v₀² + 2aΔy

(0 m/s)² = (10 m/s)² + 2 (-9.8 m/s²) Δy

Δy = 5.1 m

Answer:

8 cents extra.

Explanation:

First find out how much one nail is for each of them. So, divide.

3.60 divided by 8 is 0.45.

3.18 divided by 6 is 0.53.

Subtract 0.45 from 0.53 and voila you have 0.08.

Answer:

5

Explanation:

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Answer:

Proving LHS=RHS

Explanation:

Given

p=dgh

Multiplying by 0 on both sides of the equations

p×0=dgh×0

0=0

:- Hence proved

Answer:

  19.  down

  20.  True

Explanation:

The examples I saw were projectiles launched at different angles and speeds. In each case, the only acceleration was ...

  19:  down

  20:  due to gravity (true)

Answer:

[tex]a=100\ m/s^2[/tex]

Explanation:

Given that,

Initial velocity, u = -2 m/s

Final velocity, v = =.5 m/s

Time, t = 0.025 s

We need to find the rate of acceleration of a hammer. Acceleration is equal to the change in velocity divided by the time taken.

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{0.5-(-2)}{0.025}\\\\a=100\ m/s^2[/tex]

So, the acceleration of the jet is [tex]100\ m/s^2[/tex].

Answer:

I'm pretty sure it's A

Explanation:

bc the crest is is the point on the wave

Answer:

Hyoid

Explanation:

The hyoid is located in the neck area, not the limbs.

Answer:

Reflective surface

Explanation:

Ice is a reflective surface because most the of the light waves that hits on it bounces off.

Therefore, snow is a reflective surface.

Answer:

Final velocity = 22

Explanation:

22-2/5= 4

20/5=4

so add to so it is not 18/5

Then you get your answer.

Answer:

4. A sound wave moves towards a building at 5 m/s for 22 seconds.

Explanation:

Answer:

A.) 17.04 N

B.) 10.76 m/s^2

Explanation:

Given that a 2kg block is acted on by two forces F1 and F2 as shown in the diagram. If the magnitude of F1 = 13N and F2 = 11N. If the coefficient of kinetic friction is .23,

A.) To find the normal force exerted on it by the floor, we need to first calculate the vertical forces of the ropes.

The vertical force on F1 = 13 sin 30

F1 = -6.5 N

The vertical force on F2 = 11 sin 21

F2 = 3.94

The resultant force = - 6.5 + 3.94

Resultant force = - 2.56

The normal force = mg - 2.56

The normal force = 2 × 9.8 - 2.56

The normal force = 19.6 - 2.56

The normal force = 17.04 N

(B) The acceleration on of the block will be achieved by first calculating the horizontal force.

For F1 = 13Cos 30

F1 = 11.26N

For F2 = 11 cos 21

F2 = 10.27

the resultant force = 11.26 + 10.27

Horizontal force = 21.53N

Force = mass × acceleration

21.53 = 2 × a

a = 21.53 / 2

Acceleration a = 10.76 m/s^2

Answer:

letter b

Explanation:

30 degrees Celsius equals 86 degrees Fahrenheit add me plesse mark brainiest

Answer:

The angular speed   [tex]w = 0.5813 \ rad/s[/tex]

Explanation:

From the question we are told that

  The diameter is  d =  58.0 m    

Generally for the occupants feel that they have the same weight as they do on Earth then the centripetal acceleration of the circular ring must be  equal to the acceleration due to gravity this can be mathematically represented as

      [tex]a_c = g[/tex]

Here [tex]a_c[/tex] is the centripetal acceleration which is mathematically represented as

       [tex]a_c = w^2 * r[/tex]

Here r is the radius of the circular ring

=>    [tex]w^2 * r = g[/tex]

=>    [tex]w = \sqrt{\frac{g}{r} }[/tex]

=>   [tex]w = \sqrt{\frac{9.8}{ \frac{d}{2} } }[/tex]

=>   [tex]w = \sqrt{\frac{9.8}{ \frac{58.0 }{2} } }[/tex]

=>   [tex]w = 0.5813 \ rad/s[/tex]

Answer:

  6.23 mm

Explanation:

The vertical acceleration at the bottom of the dip (in addition to that required to counter gravity) is ...

  a = v²/r = (23 m/s)²/(600 m) = 529/600 m/s²

Then the force on the car (in addition to that required to counter gravity) is ...

  F = Ma = (1300 kg)(529/600 m/s²) = 1146 1/6 N

The additional force supplied by each of the 4 springs is 1/4 of this, so the additional spring compression is ...

  ((1146 1/6 N)/4)/(4.6×10^4 N/m) ≈ 0.00623 m = 6.23 mm

The springs are compressed an additional 6.23 mm to provide the required vertical acceleration.

_____

We have to assume that the path followed by the car's center of mass has a radius of 600 m. We're also assuming that the rotational motion of the car about its center of mass does not require any differential force between front and back springs, as it will be at a constant rate for a constant speed through the dip. And, we assume that the mass of the car is evenly among the four springs (often not the case).

Answer:

Explanation:

Given this 1300 kg car is driven at 23 m/s through a circular dip in the road of radius of 600m,

its centrifugal acceleration = speed^2 / radius

= 23^2 / 600

= 0.8817 m/s^2

The centrifugal force in turn = mass * acceleration

= 1300 * 0.8817

= 1146.17 N

This force is absorbed by suspension springs of the four wheels.

Given spring constant of 4.6 x 10^4 N/m and 4 springs total,

the extra compression = Force / number of springs / spring constant

= 1146.17 / 4 / 4.6 x 10^4

= 0.006229 m

= 6.23 mm

Note that this is the extra compression on springs during drive-through of the dip compared to when the car is driven on a flat road. There is a constant compression on springs due to weight of the car which is the same whether the car is driving through a dip or on a flat road.