Given : Airplane is 0.68 kilometers long
We know that :
⊕ 1 km = 1000 meters
⊕ 1 m = 1000 millimeters
⇒ 1 km = (1000 × 1000) millimeters
⇒ 0.68 km = (0.68 × 1000 × 1000) millimeters
⇒ 0.68 km = 680,000 millimeters
Answer: Airplane is 680,000 millimeters long
If an airplane is 0.68 Kilometers long, the length of the airplane in millimeters would be 680000 Millimeters, therefore the correct answer is option D.
What is a unit of measurement?A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind.
As given in the problem, If an airplane is 0.68 Kilometers long, then we have to find out the length of the airplane in millimeters,
1 kilometers = 1000 meters
1 meter = 100 centimeters
1 centimeters = 10 millieters
As given the length of the plane is 0.68 Kilometers.
0.68 kilometers = 680 meters
0.68 kilometers = 680×100 centimeters
0.68 kilometers = 680×100×10 millimeters
= 680,000 millimeters
Thus, the correct answer is option C.
To learn more about the unit of measurement from here, refer to the link;
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Liana draws a diagram to show the direction of the electric force acting on a charged particle in a uniform electric field.
Which change would make the diagram correct?
A. Changing the charge to negative
B. Making the field lines point down
C. Changing the force to point right
D. Removing the force arrow
Answer:
changing the force to point right is the correct answer :)
The direction of the force acting on the field should be changed to point towards the right.
What is an electric field?An electric field is referred to as the region where the influence of charge is felt. Thus, the force acts in the direction of the electric field when the field is uniform.
Having said that, it follows that the direction of the force acting on the field should be changed to point towards the right.
Learn more about electric field:https://brainly.com/question/15800304
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Molten iron has a density of 7.0 g/cm. In its solid state, iron has a density of
8.0 g/cm?
Calculate the volume of 10 kg of molten iron.
Volume =
Please help me do this problem
Answer:
i) acceleration from B to D is 0, because the velocity is constant (stays the same)
ii) whatever units of distathat might be, we can calculate the number:
for 4 time-steps (2 to 6) the velocity is 6 per time step, that makes 24 distance units in these 4 time steps. it's the same the area underneath the graph.
there is also the vertical line from 0 to 2. we can calculate that distance like the area of a triangle with 2*6 / 2 = 6
the total distance from 0 to D is therefore 30
In Einstein’s analysis, a photon striking the surface of a conductor is absorbed by an electron. Which statement describes the set of energy transfers that could occur?
A. the electron receives either all or none of the photon's energy
B. The electron may receive any fraction of the photon's energy, including all or none of it
C. The electron may receive only certain quantized amounts of the photon's energy, including all or none of it
Answer:
the correct answer is A
Explanation:
In an Einstein-type analysis, the photon is absorbed, it loses all its energy, therefore the electron must receive all or none of the energy of the incident photon. In a type of inelastic shock.
Let's analyze the different answers
A) true. In photon it is completely absorbed or passes without interaction
B) False. The photon must change energy, but in this case there is no absorption of the photon
C) False. In the insistent analyzes, the quantization of the electron in discrete states is not mentioned.
Therefore the correct answer is A
Mrs. Botts applies brakes on a car help it to decelerate at the rate of -0.80m/s2. What distance is required to stop the car when it is moving 17 m/s.
Answer:
Explanation:
vf=0
vi = 17
a = -0.8
Δx = ?
vf^2 = vi^2 + 2 a Δx
Δx = (vf^2 - vi^2) / 2a
Δx = (0-17^2) / 2 (-0.8)
Δx = 180.625 m
Which of earths spheres are involved in the water cycle
Answer:
All of the major spheres of the Earth are involved in the water cycle. The four spheres are the atmosphere, hydrosphere, lithosphere, and biosphere....
Explanation:
pa follow thanks ☺️
Which of earths spheres are involved in the water cycle ?
Hydrosphere, atmosphere, lithosphere, and biosphere are all sphere involved in the water cycle.What is Hydrosphere ?
Hydrosphere is a discontinuous layer of water at or near Earth’s surface. It includes all liquid and frozen surface waters, groundwater held in soil and rock, and atmospheric water vapour.What is atmosphere?
Atmosphere refers to the gases surrounding a star or planetary body held in place by gravity. ... The composition of the Earth's atmosphere is about 78 percent nitrogen, 21 percent oxygen, 0.9 percent argon, with water vapor, carbon dioxide, and other gases.What is lithosphere?
A lithosphere is the rigid, outermost shell of a terrestrial-type planet or natural satellite. On Earth, it is composed of the crust and the portion of the upper mantle that behaves elastically on time scales of thousands of years or greater.What is Biosphere?
The biosphere, also known as the ecosphere, is the worldwide sum of all ecosystems. It can also be termed the zone of life on Earth. The biosphere is virtually a closed system with regards to matter, with minimal inputs and outputs.#CarryOnLearning
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A crate of mass 2 kg is being pulled to the right across a rough horizontal surface by constant force F. The force F is applied at an angle of 20° to the horizontal, as shown in the diagram. how can l draw a labelled free body showing all force
Explanation:
Finding the (maximum) respective prime powers would yield the answer. Also we need not ... Is perfectly divisible by 720^n? ... So we can say that for any positive value of n it not
divisible.
Wire B has twice the length and twice the radius of wire A. both wires are made from the same material. if wire A has a resistance R, what is the resistance of wire B?
Answer:
Hello There!!
Explanation:
1/2R because wire B has twice the radius,it has four times the cross-sectional area of wire A.
hope this helps,have a great day!!
~Pinky~
An object of mass 3kg was released from 40m above the ground. Using the conservation of energy, determine the velocity of the object right before hitting the ground.
Answer:
v=28m/s
Explanation:
Conservation of Energy
Ei=Ef
mgh= 1/2mv^2
9.8*40*2= v^2
784= v^2
v= 28m/s
1 kg of rice is weighed by
Answer:
beam balance
Explanation:
A beam balance compares the sample mass with a standard reference mass
Can someone help me :)
Answer:
undergone a chemical change
Explanation:
Answer:
undergone a chemical change
The volume of a gas is halved during an adiabatic compression that increases the pressure by a factor of 2.5. By what factor does the temperature increase?
Answer: 1.24
Explanation:
Given
Volume becomes half and pressure increases by a factor of 2.5
In adiabatic process [tex]PV^{\gamma}=\text{constant}\ \text{or}\ TV^{\gamma}=\text{constant}[/tex]
Finding out [tex]\gamma[/tex] first
[tex]\Rightarrow PV^{\gamma}=2.5P(0.5V)^{\gamma}\\\\\Rightarrow \left(\dfrac{V}{0.5V}\right)^{\gamma}=2.5\\\\\Rightarrow 2^{\gamma}=2.5\\\\\text{Taking log both side}\\\\\Rightarrow \gamma=\dfrac{\ln (2.5)}{\ln (2)}\\\\\Rightarrow \gamma=1.32[/tex]
Applying same principle for Temperature
[tex]\Rightarrow TV^{1.32-1}=T'(0.5V)^{1.32-1}\\\\\Rightarrow T'=(2)^{0.32}T\\\\\Rightarrow T'=1.24T[/tex]
Thus, the temperature increases by a factor of [tex]1.24[/tex]
The factor by which the temperature increases is; 1.24
How to find increase in temperature in an adiabatic process?
In thermodynamics, an adiabatic process is one that happens when there is zero heat transfer between the system and its environment. Thereafter, the internal energy change becomes the total work done by the system. The formula associated with this process for an ideal gas is;
[tex]PV^{\gamma }[/tex] = Constant
We are told that there is an increase in pressure by a factor of 2.5 and that the volume is halved. Thus, we will have;
[tex]PV^{\gamma} = 2.5P(0.5V)^{\gamma}[/tex]
This will be simplified to;
[tex](\frac{1}{0.5})^{\gamma} = 2.5[/tex]
⇒ [tex]\gamma = \frac{In2.5}{In 2}[/tex]
γ = 1.32
Now, If the volume expands in an adiabatic process, then the volume temperature relation is expressed as:
[tex]T_{1}V_{1}^{\gamma - 1 } = T_{2}V_{2}^{\gamma - 1 }[/tex]
[tex]T_{1}V_{1}^{1.32 - 1 } = T_{2}(0.5V_{1})^{1.32 - 1 }[/tex]
Simplifying this gives;
T₁ = 1.24T₂
Read more about Adiabatic Process at; https://brainly.com/question/3962272
can someone please help me with this question... thank u ❤️
Answer:
Which of the following... : constant velocity horizontal motion
A ball is thrown at certain... : 0 m/s
A light ray strikes a reflective plane surface at an angle of 65º with the surface.
Answer the following questions (show your work)
1) Determine the angle of incidence.
2)Determine the angle made by the incident and reflected rays.
Answer:
65degrees
130degrees
Explanation:
In reflection, the angle of incidence(i) is the same as the angle of reflection (r)
Given that
Angle of reflection is 65degrees
Hence
i=r = 65degrees
Angle that angle made by the incident and reflected rays = i+r = 65+65
Angle that angle made by the incident and reflected rays = i+r = 130degrees
A trip is taken that passes through the following points in order
Point A Om
Point B 15.0 m
Point C -30.0 m
Point D 20.0 m
Point E -10.0 m
Point F 5.0 m
What is the displacement from Point B to Point E?
A) 5.0 m right
B) 85 m right
C) 25.0 m left
D) 85 m left
Answer:
The displacement from point B to point E is 25.0 m left
When do we say that work is done?
Answer:
Work is said to be done when a force applied to an object moves that object. We can calculate work by multiplying the force by the movement of the object.
Answer:
Work is done by a force on an object if (i) a force acts on the object and (ii) the object is displaced from its original position
Using dimensional analysis prove that work = force x displacement
please answer to correct answer i will give 50 points
Answer:
Work = M1 L2 T^-2
Force =M1 L1 T^-2
displacement = L1
Work = F.ds
Work = M1 L1 T^-2 L1
work = M1 L2 T^-2
How much pressure is created by a circular piston that is 0.24 meter in diameter
with a Force of 200.0 N? N/m2 ... (round answer to nearest ones place -no decimal)
Answer:
4000 N/m²
Explanation:
Area = πr²
Area = π x 0.12² (diameter/2)
Area = 0.05 m²
Pressure = force/area
Pressure = 200/0.05
Pressure = 4000 N/m²
Hope this helps!
What is a photon?
A. A package of a specific amount of energy
B. A single light wave
C. A subatomic particle in an atom
D. An electron that has been removed from its atom
Answer:
B
Explanation:
The reason its B is because.
What's scientific notation
What are the units for impulse?
m/s
Kg
Ns
Newtons
Answer:
Kg.m/s is the unit for impulse
Explanation:
If i were wrong please correct me.
hhhhhhhhhhhhhhhheeeeeeeeeeeeeeeeeeeeellllllllllllllllllllllllllllllllllpppppppppppp
Answer:
I'm pretty sure the answer is broken
Explanation:
A rock from the top of a hill is falling from rest.
Object name?
Starting energy form?
Conversion?
Final energy form?
Non usable form of energy?
Object name:- Rock
Starting energy:- Kinetic energy
Conversion:- Potential to kinetic energy
Final energy form:- Potential energy
Non usable form if energy:- Nil [ As it has potential & kinetic both]
What is a sound wave?
A ball at rest has a mass of 2.5 kg. Determine the force required to accelerate the ball to 2.5 m/s?
Answer:
6.25 N
Explanation:
F = ma
F = 2.5 × 2.5
F = 6.25 Newtons
Cuatro contenedores idénticos tienen la misma cantidad de gas helio a la misma temperatura inicial. Los recipientes también cuentan con un émbolo móvil que no permite que el helio escape. Cada muestra de gas sigue un proceso distinto como se describe a continuación: Muestra 1: 500 J de calor salen del gas y este realiza 300 J de trabajo. Muestra 2: 500 J de calor entran al gas y este realiza 300 J de trabajo. Muestra 3: 500 J de calor salen del gas y se hace un trabajo de 300 J sobre él. Muestra 4: 500 J de calor entran al gas y se hace un trabajo de 300 J sobre él.
Answer:
1) ΔE = -800 J, 2) ΔE = 200 J, 3) ΔE = -200 J, 4) ΔE = 800 J
Explanation:
For this exercise let's use the first law of thermodynamics
ΔE = Q + W
Where we will apply this expression to several cases
1) output Q = 500 J and does work of W = 300 J.
The two processes involve an energy output
ΔE = - 500 - 300
ΔE = -800 J
Therefore, the internal energy of the gas decreases by this amount,
2) enter Q = 500J and do work of W = 300 J
Positive heat is added and does negative work
ΔE = 500 - 300
ΔE = 200 J
3) they leave Q = 500 J and do (work on the gas) W = 300J
negative heat and positive work come out
ΔE = -500 + 300
ΔE = -200 J
4) heat enters Q = 500 J, work on gas W = 300 J
both positive
ΔE = 500 + 300
ΔE = 800 J
HELP ME WITH THIS FOR A BRAINLIEST
Option C: Runs up the slipway 5 s
hope this helped :)
What nuclear reaction is shown in the equation below
Answer:
nuclear fission
Explanation:
nuclear fission
Answer: Nuclear fission
Explanation:
1. Do you think that hand signals are important in officiating games? why?
Yeah, hand signals are important in officiating games. The hand signals are given by the referee who first signals the fault and then indicates which team has won the point. A point is indicated by one finger at the side of the court to indicate the winner of the rally.
Tom is throwing an baseball at an aluminum can,
present an argument about the likely kinetic energy of the ball before and after.
describe the evidence that would support the argument.
present an argument about the likely kinetic energy of the can before and after.
describe the evidence that would support the argument.
Answer:
The question relates to the conservation of energy principle, the conservation of the linear momentum, and Newton's Laws of motion
Part A
1) Tom throwing a baseball at a can
The initial velocity of the baseball = v₂
The initial kinetic energy of the baseball, K.E.₂ = (1/2)·m₂·v₂²
∴ The final kinetic energy of the baseball, K.E.₂' = (1/2)·m₂·v₂'² < (1/2)·m₂·v₂²
Therefore, the energy of the ball before the collision is lesser than the energy of the ball after the collision
2) The evidence that would likely support the claim is that the baseball's height above the ground reduces rapidly immediately after the collision which is due to the reduced velocity, and therefore, the reduced (kinetic) energy
The final velocity of the baseball v₂' < v₂
Part B
1) The argument
The initial velocity of the can = v₁ = 0 (The can is initially at rest)
The initial kinetic energy of the can, K.E.₁ = (1/2)·m₁·v₁² = 0
The final velocity of the can v₁' > v₁ = 0
∴ The final kinetic energy of the can, K.E.₁ = (1/2)·m₁·v₁² > 0
Given that the velocity of the can increases from zero to a positive value after collision with the baseball, the kinetic energy of the can is increased from zero before the collision to a positive value after the collision
2) An evidence in support of the argument is the motion of the can which was initially at rest which is an indication of increase in energy podded by the can
Explanation: