a,b)Find the phasor form of the following E-field, the polarization type, and plot the vector on the X-y axis (z-0) for one period a) E(z,t) = xZcos(wt kz) y4cos(wt kz) b) E(z,t) = R2cos(wt + kz) - 94sin(wt + kz)

Answers

Answer 1

a) The phasor form of E-field = xˆ 2cos(wt - kz) - yˆ 4cos(wt - kz) is 2√5 L(-63.43).

Polarization type is linearly polarised.

b) The phasor form of E-field = ?

E(z,t) = xˆ 2cos(wt + kz) - yˆ 4sin(wt + kz) is E(z,t) =2√5 L(-143.43). polarization type is elliptical.

We have given that

E⃗(z,t) =2xˆcos(wt - kz) - 4 yˆcos(wt - kz)

|r⃗ | = √((2cos(wt - kz))² + (- 4cos(wt - kz))²)

= √(4cos²(wt - kz) + 16cos²(wt - kz))

= √(20cos²(wt - kz))

= 2√5 cos(wt - kz)

φ = 4cos(wt - kz)/(2cos(wt - kz))

= tan⁻¹ 1(-2) = -63.43°

So, E(z,t) = 2√5 L(-63.43)

b) E(z,t) = xˆ 2cos(wt + kz) - yˆ 4sin(wt + kz)

= xˆ 2cos(wt + kz) - yˆ 4cos(wt + kz -π/2)

|r| = √((2cos(wt + kz))² + (- 4sin(wt -+kz))²)

= √20

phi = tan⁻¹(- 4cos(wt - kz)/(2cos(wt - kz)) - π/2

= tan⁻¹( -2) + π/2 = - 143.43

so, E(z,t) =2√5 L(-143.43)

E(z,t) = xˆ 2cos(wt - kz) - yˆ 4cos(wt - kz)

if wt = 0°

E(z,t) = xˆ 2cos(0 - kz) - yˆ 4cos(0- kz)

= 2xˆ - 4yˆ

wt = 30° , E(z,t) = xˆ 2cos( - kz) - yˆ 4cos(0- kz)

E(z,t) = √3/2(2) xˆ - √3/2(4) yˆ

= √3xˆ - 2√3yˆ

for wt = 45°

E(z,t) = √2 xˆ - 2√2 yˆ

for wt = 90° =>E(z,t) = 0

for wt = 60° , E(z,t) = xˆ - 2 yˆ as seen in above graph that is linear polarised

For part (b) ,

E(z,t) = 2 xˆcos(wt - kz) - 4yˆ sin(wt + kz)

From graph elliptical polarised,

for wt = 0 , E(0,t) = 2 xˆ

for wt = 90° , E(0,t) = -4yˆ

for wt =180° , E(0,t) = -2 xˆ

for wt = 270° , E(0,t) = -4yˆ

Hence, we get the answer of both parts.

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Step-by-step explanation:

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Answers

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What is the exact value of trigonometric function?

The exact values of trigonometric functions are values of trigonometric functions of certain angles that can be expressed exactly using expressions containing real numbers and roots of real numbers. These values are also called analytic values of trigonometric functions or trigonometric values of special angles.

What is trigonometric function?

The trigonometric functions are also called the angle functions, which relates the angles and the ratios of the sides of a right angle triangle.

According to the given question.

We have a trigonometric function

[tex]cos(\frac{11\pi }{8} )[/tex]

We have to find the exact value of the above trigonometric function.

since,

[tex]\frac{11\pi }{8}[/tex] can be written as [tex](\pi +\frac{3}{8\pi } )[/tex]

[tex]\implies cos(\frac{11\pi }{8} ) = cos(\pi +\frac{3}{8}\pi )[/tex]

And we know that,

Cos(π + θ) = -cosθ

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[tex]cos(\pi +\frac{3}{8} \pi )[/tex]

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[tex]= -cos(\frac{3}{2(4)} \pi )[/tex]

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[tex]= -\sqrt{\frac{1+\frac{1}{\sqrt{2} } }{2} }[/tex]

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[tex]= -\sqrt{\frac{2+\sqrt{2} }{4} }[/tex]

Hence, the exact value of [tex]cos(\frac{11\pi }{8} )[/tex] is [tex]-\sqrt{\frac{2+\sqrt{2} }{4} }[/tex].

Thus, option A is correct.

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Answers

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Answer:

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Step-by-step explanation:

2.83/1

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Answer:

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I will give Brainliest answer!

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Step-by-step explanation:

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jsjsjsjsjjsjsksksksksksksksksksjskkwjwjwjwkw

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