The defined friction force allows you to find which is the correct result for what type of wax you should use:
B. One where the coefficient of static friction is larger.
The friction force is a macroscopic force that opposes the relative movement of bodies, it is the sum of many interactions at the microscope level.
In general for solid bodies the expression of the out of friction is
[tex]fr = \mu N[/tex]
Where fr is the friction force, μ the friction coefficient and N the normal.
The friction coefficient can be of two types:
Static for when the relative velocity between the two bodies is zero. Dynamic when the relative velocity between the two bodies is different from zero.
In general, the dynamic coefficient is less than the static one.
In this case, as the temperature increases, the friction coefficient decreases, so the skier begins to slide downwards. To prevent this sliding, he must use a wax with a higher friction coefficient.
If you only want to stand on the hill, a wax with a static coefficient must be used, while standing if you want to advance on the hill you must use a wax with a dynamic coefficient since there is a relative movement between the skier and the hill.
Let's examine the different alternatives:
A. False. The friction coefficient must be higher, so that there is more friction force.
B. True. The friction increases and can be stopped on the hill and move up the hill.
C. False In this case, you can go up the hill, but if you stop, you can go back.
D. False. The coefficient must be higher, to increase friction.
Consequently we see that the only type of wax that will allow you to stand or advance on the hill is
B. A wax with a higher statutory coefficient.
In conclusion, using the defined friction force we can find the correct result for what type of wax to use is:
B. One where the coefficient of static friction is larger.
Learn more here: brainly.com/question/4230804
Answer:
One where the coefficient of static friction is larger
Explanation:
Mr. Mangan runs 30 m north and 45 m south. What is his total distance
travelled? What is his displacement?
Explain how plate tectonics have changed Earth's surface over time. (This is a short writing and I need help. I will mark whoever answers first as Brainliest plus I will give 50 points.)
Answer:
Plate motions cause mountains to rise where plates push together, or converge, and continents to fracture and oceans to form where plates pull apart, or diverge. The continents are embedded in the plates and drift passively with them, which over millions of years results in significant changes in Earth's geography.
Explanation:
hope it helps ☺️✌️
An airplane flying upward at 39.6m/s and an angle of 30 degree relative to the horizontal releases a ball when it is 287m above the ground. Calculate the time it takes the ball to hit the ground? Calculate the maximum height of the ball? Calculate the horizontal distance the ball travels from the release point to the ground? Neglect any effects due to air resistance.
Answer:
Assuming the speed of the plane is 39.6 m/s
vy = 39.6 * sin 30 = 19.8 vertical speed
vx = 39.6 * cos 30 = 34.3 m/s
S = vy t - 1/2 a t^2 to calclulate vertical height
-287 = 19.8 t - 4.9 t^2
4.9 t^2 -19.8 t - 287 = 0
I get t = 9.93 for solving the quadratic for time for ball to hit ground
Horizontal distance = 34.3 m/s * 9.93 s = 341 m
With a vertical speed of 19.9 m/s it takes 19.8 / 9.8 = 2.02 s to reach max height
You can again solve a quadratic or use 19.8 / 2 * 2.02 for time to reach vertical height H = 287 + 20 = 307 m
As a check 307 = 1/2 g t^2 = 4.9 * (9/93 - 2/02)^2 = 307 m max height
After you know how long the ball is in the air there are several ways to calculate the other values.
Suppose an empty grocery cart starts at a rest and rolls downhill in a parking lot. The cart has a maximum speed of 2.2km/s when it hits the side of the store and comes to rest 1.5 min later. If an unbalanced force of 65 N stops the cart, what is the mass of the grocery cart?
Answer: i dont know
Explanation:
E
The potential energy U as a function of the position x of an object is given by U (x) = - 400/x, where U is in joules and x is in meters. The object is released from rest at position x = 30 m and is free to move along the x-axis. When the object has moved a distance of 10 m from its initial position, the magnitude of the force associated with this potential energy function is
Hi there!
We know that:
F = -dU/dx, so:
U = -400/x
dU/dx = 400/x² (Take the derivative)
F = -dU/dx = -400/x²
Finding the force at 10m away from the starting point (30m), means a position of 40m. So:
F = -400/(40²) = -0.25 N
A horse trainer records the distance a horse travels during three different trials.
What is the horse's average speed in kilometers per minute?
The horse's average speed in kilometers per minute is equal to 0.3 kilometers per minute.
Given the following data:
Time 1 = 15 minutesTime 2 = 30 minutesTime 3 = 45 minutesDistance 1 = 4.5 kilometersDistance 2 = 9.0 kilometersDistance 3 = 13.5 kilometersTo determine the horse's average speed in kilometers per minute:
First of all, we would find the total time and total distance covered:
For total time:
[tex]Total \;time = 15 + 30+45[/tex]
Total time = 90 minutes
For total distance:
[tex]Total \;time = 4.5 + 9.0+13.5[/tex]
Total time = 27 kilometers.
Mathematically, average speed is given by the formula:
[tex]Average\;speed = \frac{Total\;distance}{Total\;time} \\\\Average\;speed = \frac{27}{90}[/tex]
Average speed = 0.3 kilometers per minute.
Read more on average speed here: https://brainly.com/question/17742679
A soccer ball accelerates as it rolls down a steep hill and then gradually comes to a stop at the bottom. According to Newton's laws which of the following statements could be
true?
Statement 1: While the ball was rolling down the hill the forces acting on it were unbalanced.
Statement 2: The ball was experiencing balanced forces as it rolled down the hill..
Statement 3: Balanced forces acted on the ball once it reached the botto by m of the hill causing it to stop.
O Statement 1 and 2 are both true.
All three statements are true.
Only Statement 1 is true.
Only Statement 3 is true.
0
Answer:
Statement 1: While the ball was rolling down the hill the forces acting on it were unbalanced.
Explanation:
what is the main features of RCCB?
Main features of RCCB are:
Both wires phase and neutral are connected through RCCB.Whenever there is any ground fault occurs, then it trips the circuit.The number of current supplies through the line should go back through neutral.These are a very effective type of shock protection.The three diagrams below show a block of mass m being pulled or pushed at constant acceleration ax along a table with a force P. The coefficient of kinetic friction is k. What is the friction force in each case? Give your answer in terms of the pushing force P, ax, m, and the angle .
Answer:
Explanation:
1) F = ma
P - Fk = ma
Fk = P - ma
2) F = ma
Pcosθ - Fk = ma
Fk = Pcosθ - ma
3) F = ma
Pcosθ - Fk = ma
Fk = Pcosθ - ma
These results are not very helpful.
If we are allowed to introduce gravity, more useful information comes out
1) Fk = kmg
2) Fk = k(mg + Fsinθ)
3) Fk = k(mg - Fsinθ)
In this exercise we have to use the decomposition of forces in the blocks, so
1) [tex]F_k = P - ma[/tex]
2) [tex]F_k = Pcos\theta - ma[/tex]
3) [tex]F_k = Pcos\theta - ma[/tex]
Thus, observing these blocks and their respective compositions we will find that:
1)
[tex]F = maP - F_k = maF_k = P - ma[/tex]
2)
[tex]F = maPcos\theta - F_k = maF_k = Pcos\theta - ma[/tex]
3)
[tex]F = maPcos\theta - F_k = maF_k = Pcos\theta - ma[/tex]
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Two objects, one of mass 17 kg and the other of mass 31 kg approach each other with the lighter one having a speed of 23 m/s. Determine the velocity of the heavier object if the total combined momentum of the objects is zero.
[tex]\bull\sf m_1=17kg[/tex]
[tex]\bull\sf m_2=31kg[/tex]
[tex]\bull\sf v_1=23m/s[/tex]
[tex]\bull\sf v_2=?[/tex]
According to law of conservation of momentum
[tex]\\ \sf\longmapsto \Delta P=P[/tex]
[tex]\\ \sf\longmapsto m_1v_1=m_2v_2[/tex]
[tex]\\ \sf\longmapsto v_2=\dfrac{m_1v_1}{m_2}[/tex]
[tex]\\ \sf\longmapsto v_2=\dfrac{17(23)}{31}[/tex]
[tex]\\ \sf\longmapsto v_2=\dfrac{391}{31}[/tex]
[tex]\\ \sf\longmapsto v_2=12.6m/s[/tex]
Do you think it wise to make a decision under the influence of an emotion?
Answer:
no because It can be a disadvantage for us
Answer:
no
Explanation:
nop it isn't wise to make a decision under the influence of emotion because if you act and make decision From influence of emotion you will gonna regret so think before you make decision
Government has banned the use of plastic bags in some states. Why?
Answer:
people throw plastic into the oceon
Explanation:
.when people throw plastic into the ocean mother nature gets hurt because of waste if it continues the see we see today will be dirty if all of humanity throwed all of the plastic and waste in the ocean
What’s the atomic number for magnesium
Answer:
12
Explanation:
Symbol: Mg
Atomic mass: 24.305 u
Atomic number: 12
Density: 1.738 g/cm³
A speedboat with a mass of 511 kg (including the driver) is tethered to a fixed buoy by a strong 31.5 m cable. The boat's owner loves high speed, but does not really want to go anywhere. So the owner revs up the boat's engine, makes a lot of noise, and runs the boat in circles around the buoy with the cable supplying all the necessary centripetal force. When the tension of the cable is steady at 13300 N, with what force is the boat's engine pushing the boat? Different physics textbooks treat drag force somewhat differently and use different formulas. For the present purpose, take the water's drag force on the boat to be (450 kg/m)×2, where denotes the boat's speed. Ignore any drag force on the cable.
Answer:
its is 23.09 kb
Explanation:
i did this awsner
what would you want individuals and communities to understand to help them avoid negatively affecting climate
Answer:
ur
Explanation:
mom
HELP PLEASE
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A plane is traveling horizontally at a speed u = 40 m/s at a height h =
100m above ground when it drops a package, as shown in the figure.
How long it takes the dropped package to reach the ground and where?
Answer:
First get the time in the air from
h = gt2/2 ⇒
t = √(2h/g)
Plug in
h = 100 m
g = 9.8 m/s2
and get t in seconds. Then multiply t by the constant horizontal speed.
x = vt
Plug in
v = 40 m/s
t = ? (result from above)
and get x in meters.
(b)
Vertical speed:
v(t) = v0 + gt
Plug in
v0 = 0
g and t from above
and get v(t) in m/s.
(c) It is the same as the initial velocity when released, which is 40 m/s.
(d) The horizontal component is the same as the answer for part (c). The vertical component is the result for part (b), in the downward direction.
ball (100 grams) is attached by string (ignorable mass) oflength SOcm and is in a ircular motion: If the ball makes 20 round trips (complete oscillations) along the ircular path in 5 seconds (a) Calculate the time period (T) of the ball in S. units: (b) Calculate the angular velocity (0) of the ball in S lunits: (c) Calculate the linear velocity (v) of the ball in S.I units. (d) Calculate the centripetal force (Fc) on the ball in Newtons (N): Scm (e) Calculate the centrifugal force on the ball in Newtons (N) (0) Are the two forces equal
Answer:
Hdhjdj
Explanation:
Please answer quick!! if you're right I'll mark you brainliest!
the surface gravity on Jupiter Is 2.4 times the of earth what would your weight be on Jupiter if you weighed 110 pounds on earth
Answer:
The equation would be 2.4 x 110 which is 264
You would weigh 264 on Jupiter
Explanration:
If you ran at a rate of 300 m/min for 30 minutes, how far would you have run?
Answer:
9000 m
Explanation:
I multiplied 300 by 30!
Hope this helps :)
Pls make brainliest :3
And have an amazing day <3
An election accelerated through 1 kV possesses de - Broglie wavelength 1. What will be the wavelength of
the same electron, when accelerated through 16kV:
1) 161
2) 41
3) 1/4
4) 116
Answer:
Correct option is
B
1.7
A
˚
λ=
p
h
=
2mE
h
=
2mqV
h
λ=
2×9.1×10
−31
×1.6×10
−19
×50
6.6×10
−34
=1.72×10
−10
=1.72A
Option B
3. a) If the distance between two objects increases by a factor of 5 (5),
does the gravitational force between the objects increase or decrease?
By what factor does the gravitational force between the objects
change?
b) If the mass of one object decreases by a factor of 3 (*1/3), does the
gravitational force between them increase or decrease? By what factor
does the gravitational force between the objects change?
Answer:
Answer for A
Explanation:
F1=GmM/r1^2
If r2 becomes r2=5r
F2=GmM/(25r^2)
Multiply with 25 gives to maintain the same force
I.e.,25F2=F1
F2=G(25m)M/25r^2=F1
By the factor 25 would change to increase to same.
If a car is traveling at 10m/s and then accelerates for 10s at a rate of 0.5m/s^2,what will be final velocity?
Answer:
[tex]u= 10 \frac{m}{s} \\ t = 10 \: s \\ a = .5 \frac{m}{ {s}^{2} } \\ v = x \\ v = u + at \\ x = 10 + .5 \times 10 \\ x = 10 + 5 \\ x = 15 \frac{m}{s} \\ thank \: you[/tex]
Answer:
15m/s
Explanation:
a=(Vf-Vi)/t
0.5m/s^2=(Vf-10m/s)/10s
when we solve this Vf=15m/s^2
A 50 kg boy on ice skates throws a 5 kg ball to the left. If the ball ends up going 20 m/s. How fast is the boy going?
Answer:
2 m/s
Explanation:
A 50 kg boy on ice skates throws a 5 kg ball to the left. If the ball ends up going 20 m/s. Velocity of boy is 2 m/sec.
What is velocity?When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.
Uniform motion an object is said to have uniform motion when object cover equal distance in equal interval of time within exact fixed direction. For a body in uniform motion, the magnitude of its velocity remains constant over time.
Given in the question, a 50 kg boy on ice skates throws a 5 kg ball to the left. If the ball ends up going 20 m/s.
Using conservation of momentum, velocity = (20*5)/50 = 2 m/sec.
A 50 kg boy on ice skates throws a 5 kg ball to the left. If the ball ends up going 20 m/s. Velocity of boy is 2 m/sec.
To learn more about velocity refer the link:
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Một chất điểm chuyển động trong mặt phẳng Oxy với phương trình :
{ = 2 + 10
Answer:
plz write your questions in English
16. If "team A has 3 of its bocce balls closer to the pallino than any of their opponent's balls, who wins the
frame
How many points do they get for that frame?
How many do their opponents get for that frame?
Answer:
Team A wins the frame with three points. The opposing team gets zero points for the frame.
Explanation:
A 0.15-kg object is projected vertically into the air with a
velocity of 30. m/s. How high above the ground is the
object after 3.3 seconds?
A 46 m
B 53 m
C 110 m
D 150 m
Answer:
A
Explanation:
y = 30(3.3) - .5(9.8)(3.3^2)
Random sampling is used by researchers to obtain an).
control group
population of interest
representative sample
experimental sample
Plz help
Answer:
hey there
the correct answer is option ( B ) population of interest
Explanation
A random sample is a subset of individuals randomly selected by researchers to represent an entire group as a whole. The goal is to get a sample of people that is representative of the larger population.
Explanation:
Hope it helps
Have a nice day : )
Which term best describes a question that can be tested?
A. Phenomenon
B. Hypothesis
C. Experiment
D. Observation
Answer:
Hypothesis
Explanation:
because in science a hypothesis is a guess/question that you test. it can be changed many times
Answer:
C) experiment. Is the answer.
hypothesis is the educated guess about what the result of the experiment is before conducting the experiment.
Observation is what you see and record during the experiment.
Calculate the potential energy of a 1.5 kg hammer that is located at a height of 2 m
Answer: 29.43 Joules
Explanation:
PE=mgh
PE=potential energy
M=1.5kg
G=9.81m/s^2
H=2m
PE=29.43J
Answer:
[tex]\boxed {\boxed {\sf 29.4 \ J}}[/tex]
Explanation:
Potential energy is the energy an object possesses due to its position. It is calculated using the following formula:
[tex]PE=mgh[/tex]
The mass of the hammer is 1.5 kilograms and its height is 2 meters. Assuming this is on Earth, the acceleration due to gravity is 9.8 meters per second squared.
m= 1.5 kg g= 9.8 m/s² h= 2 mSubstitute these values into the formula.
[tex]PE= (1.5 \ kg)(9.8 \ m/s^2)(2 \ m)[/tex]
Multiply the numbers together.
[tex]PE=(14.7 \ kg *m/s^2)(2 \ m)[/tex]
[tex]PE=29.4 \ kg*m^2/s^2[/tex]
Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule. Our answer of 29.4 kg*m²/s² is equal to 29.4 J.
[tex]PE= 29.4 \ J[/tex]
The potential energy of the hammer is 29.4 Joules.