A uniform rod with a mass of m = 1.94 kg and a length of l = 2.10 m is attached to a horizontal surface with a hi=nge. The rod can rotate around the hi=nge without friction. (See figure.)
Initially the rod is held at rest at an angle of θ = 70.4° with respect to the horizontal surface. Then the rod is released.
What is the angular speed of the rod, when it lands on the horizontal surface?
1.61 rad/s is incorrect.
What is the angular acceleration of the rod, just before it touches the horizontal surface?
1.06 rad/s^2 is incorrect.

Answer:

A principle stating that energy cannot be created or destroyed, but can be altered from one form to another.

Explanation:

The fundamental forces in nature are strong force, weak force, electromagnetic force, and the gravitational force.

There are four fundamental forces at work in the universe. These fundamental forces include;

Thus, the fundamental forces in nature are strong force, weak force, electromagnetic force, and the gravitational force.

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Abraham Maslow was the person who studied highly successful people and developed the hierarchy of needs. Thus, option C is correct.

Abraham Maslow was one of the most influential psychologists of the twentieth century. His work on humanistic psychology and his development in the hierarchy of needs is very popular.

According to Abraham Maslow, humans have five tiers of needs and they are food and shelter, love and belonging, esteem, safety needs, and self-actualization.

The hierarchy of needs has five basic levels. The bottom level comprises the basic needs of people like food, and shelter. Top-level comprises esteem and self-actualization.

Maslow hierarchy of needs involves the model for understanding human behavior. Hence, Abraham Maslow developed the hierarchy of needs. Thus, the correct option is C.

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1)The centripetal acceleration will be 84622.360 km/h².

2)The time the turn take is 0.19 hour.

3)The distance the airplane cover during the turn is 505.54 km.

The acceleration needed to move a body in a curved way is understood as centripetal acceleration.

The direction of centripetal acceleration is always in the path of the center of the course. The total acceleration is the result of tangential and centripetal acceleration.

The given data in the problem;

R is the radius= 80.5 m

v is the linear speed = 2610 km/h

a is the total acceleration.

1)

The centripetal acceleration is found by

[tex]\rm a_c = \frac{v^2}{R} \\\\ a_c = \frac{(2610 \ km/h)^2}{80.5} \\\\ a_c = 84622.360 \ km/h^2[/tex]

2)

The time the turn take is;

[tex]\rm a= \frac{4 \pi^2R}{T^2} \\\\\ 84622.360 = \frac{4 \times (3.14)^2 \times 80.5}{T^2} \\\\\ T = 0.19 \ hr[/tex]

3)

The distance the airplane cover during the turn is;

C= 2πR

C=2 × 3.14 × 80.5 km

C= 505.54 km

Hence centripetal acceleration, time the turn take, and distance the airplane cover during the turn will be 84622.360 km/h²,0.19 sec, and 505.54 km respectively.

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Ben as a psychology student is most likely conducting a behavioral study.

What is psychology?

Psychology can simply be defined as the study of human mind, conscious and unconscious, thoughts and feelings.

In conclusion, Ben as a psychology student is most likely conducting a behavioral study.

Some few branches of psychology are:

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The equivalent capacitance in the circuit is 15.05 F.

The two parallel plates placed at a distance apart are used to store charge when the electric supply is on.

The capacitance of a capacitor in series is given by:

Series capacitance = 1/ capacitance 1 + 1/ Capacitance2

The capacitance of a capacitor in parallel series can be calculated as:

Parallel capacitance = Capacitance 1 + Capacitance 2

In the following circuit,

C1=10.0 F,

C2=2*10.0 F,

C3=2*10.0 F,

C4=2*9.4 F, and

C5=3*9.4.

In the circuit C2 and C3 are in parallel, their equivalent capacitance is

= 2*10.0 F+2*10.0 F

= 4 *10.0 F

Then, C1 is in series with 4 *10.0 F,

So their equivalent capacitance is

=1 /{ 1/10.0 F + 1/ 4 *10.0 F}

=0.8*10.0 F

C4 and C5 are in series, their equivalent is

=1 /{ 1/2*9.4 F + 1/3*9.4 F}

=0.75*9.4 F

Now,0.8*10.0 F and 0.75*9.4 F are in parallel.

Total equivalent capacitance is Ceq = 0.8*10.0 F + 0.75*9.4 F

Ceq = 15.05 F

Thus, the equivalent capacitance in the circuit is  15.05 F.

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The velocity of the boat after the package is thrown is 0.36 m/s.

Apply the principle of conservation of linear momentum;

Pi = Pf

where;

v(74 + 135) = 15 x 5

v(209) = 75

v = 75/209

v = 0.36 m/s

Thus, the velocity of the boat after the package is thrown is 0.36 m/s.

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The gravitational force on block B is twice as much as the gravitational force on block A.

Force is the product of mass and acceleration. If the mass of A is 1Kg and the mass of B is 2Kg, In order to give the masses the same horizontal acceleration, the magnitude of the force on block B must be twice as much as the force on block A.

Given that the mass of A is 1Kg and the mass of B is 2Kg, the gravitational force on block B is twice as much as the gravitational force on block A.

If I hold block A with a mass of 1 kg in one hand and block B with a mass of 2 kg in the other  and release both from the same height above the ground at the same time, the two blocks hit the ground at the same time, because they both accelerate at the same rate while falling. The greater gravitational force on block B is compensated by its greater mass, giving it the same acceleration.

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Answer:

50+20=70

70÷5=14

Explanation:

50×20=1000

1000÷5=200

Answer:

Approximately [tex]20\; {\rm s}[/tex], assuming no energy loss and that [tex]g = 10\; {\rm N \cdot kg^{-1}}[/tex].

Explanation:

If the gravitational field strength is constantly [tex]g[/tex], lifting an object of mass [tex]m[/tex]  by a height of [tex]\Delta h[/tex] would increase the gravitational potential energy ([tex]\text{GPE}[/tex]) of that object by [tex]m\, g\, \Delta h[/tex].

In this question, [tex]m = 20\; {\rm kg}[/tex] and [tex]\Delta h = 5\; {\rm m}[/tex]. Assume that [tex]g = 10\; {\rm N \cdot kg^{-1}}[/tex]. Hence, the [tex]\text{GPE}[/tex] that this object would eventual gain would be:

[tex]\begin{aligned}m\, g\, \Delta h &= 20\; {\rm kg} \times 10\; {\rm N \cdot kg^{-1}} \times 5\; {\rm m} \\ &= 1000\; {\rm N \cdot m} \\ &= 1000\; {\rm J}\end{aligned}[/tex].

Thus, this motor would need to do (at least) [tex]1000\; {\rm J}[/tex] of work to lift this object up by [tex]5\; {\rm m}[/tex]. The power rating of this motor, [tex]P = 50\; {\rm W} = 50\; {\rm J \cdot s^{-1}}[/tex], means that (assuming no energy loss) this motor could do [tex]50\; {\rm J}[/tex] of work every second.

The time it would take for this motor to do [tex]1000\; {\rm J}[/tex] of work under these assumptions would be:

[tex]\begin{aligned}t &= \frac{\text{work}}{\text{power}} \\ &= \frac{1000\; {\rm J}}{50\; {\rm J \cdot s^{-1}}} \\ &= 20\; {\rm s}\end{aligned}[/tex].

Answer:

Probs paper cuz the rest are metals

The statement that best explains the movement of electric current is that the ground is positively charged and the clouds are negatively charged.

Lightning storm can be defined as the electrical outlet that occurs due to unsteadiness of the storm clouds and the ground.

Lightning storm occurs when opposite charges build up enough in the air leading to rapid discharge of electricity.

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Considering the Ohm's law, the resistance of the lightbulb is 144.58 Ω.

The flow of electricity through an object, such as a wire, is known as current (I). Its unit of measure is amps (A). So the current is a measure of the speed at which the charge passes a given reference point in a specified direction.

The driving force (electrical pressure) behind the flow of a current is known as voltage and is measured in volts (V) (voltage can also be referred to as the potential difference or electromotive force). That is, voltage is a measure of the work required to move a charge from one point to another.

Resistance (R) is the difficulty that a circuit opposes to the flow of a current and it is measured in ohms (Ω).

Ohm's law establishes the relationship between current, voltage, and resistance in an electrical circuit.

This law establishes that the intensity of the current that passes through a circuit is directly proportional to the voltage of the same and inversely proportional to the resistance that it presents.

Mathematically, Ohm's law is expressed as:

[tex]I=\frac{V}{R}[/tex]

Where:

In this case, you know that the voltage between two points in a circuit is 120 V and there is a current of 0.83 A.

Replacing in the Ohm's Law:

[tex]0.83A=\frac{120 V}{R}[/tex]

Solving:

0.83 A× R=  120 V

[tex]R=\frac{120 V}{0.83A}[/tex]

R= 144.58 Ω

Finally, the resistance of the lightbulb is 144.58 Ω.

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1. The amount of work done during the lifting process is 8426.824 J

2. The average power used in the process is 80.26 Watts

Wd = mgh

Wd = 33. 2 × 9.8 × 25.9

Wd = 8426.824 J

P = Wd / t

P = 8426.824 / 105

P = 80.26 Watts

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Answer:motion

Explanation:

kinetic energy of an object that it possess due to its motion.

The amount of energy lost to air friction, given the data is 37.71 J

E₁ = ½mu²

E₁ = ½ × 0.45 × 15.1²

E₁ = 51.3 J

E₂ = ½mv²

E₂ = ½ × 0.45 × 19.89²

E₂ = 89.01 J

Energy lost = E₂ - E₁

Energy lost = 89.01 - 51.3

Energy lost = 37.71 J

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Answer:

c

Explanation:

the formula Torque = Force X Distance. While distance is measured in meters and force is measured in newton so torque is measured in newton ⋅ meter

Answer:

Probably competition with television news-

by 1953 television was becoming common in many houses and people could obtain news from television newscasts

Answer
Yes i will help u!

The velocity of the mass at time, t = 1 s, is determined as 20 m/s.

The magnitude of the force experienced by the body is calculated as follows;

|F| = √(8² + 6²)

|F| = 10 N

From Newton's second law of motion;

F = ma

where;

a = F/m

a = 10 /0.5

a = 20 m/s²

v = at

v = 20 x 1

v = 20 m/s

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Answer:

50

Explanation:

Use the Pythagorean theorem to find the length of the diagonal, or the hypotenuse of an imaginary triangle. 30^2 + 40^2 = 2500, which is 50^2. So, the magnitude is 50.

Brainliest, please :)

Answer:

86.47 V

Explanation:

It will be multiplied by the ratio of the windings

980/340 * 30 = 86.47 v

The statement that best explains the movement of electric current is that the ground is positively charged and the clouds are negatively charged.

Lightning storm can be defined as the electrical outlet that occurs due to unsteadiness of the storm clouds and the ground.

Lightning storm occurs when opposite charges build up enough in the air leading to rapid discharge of electricity.

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(a) The magnitude of acceleration in a vertical takeoff from the Moon will be 0.73 m/s².

(b)Option d is correct.

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

Given data;

Force, F =?

Mass of a fully loaded module,m = 10,600 kg

Acceleration due to gravity on moon,g = 1.67 m/s²

Thrust of its engines is,F= 25,500 N.

The net force is found as follows;

[tex]\rm F_{net} = F -W[/tex]

ma = F-W

(10,600) kg × a = 25,500 N - (10,600 kg )(1.67)

a = 0.73 m/s²

b)

Yes, it lifts off from Earth. Because the thrust of the module's engines is greater than its weight on Earth.

F>W

Hence option d is correct.

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The net force on particle q3 is 112.11 N

The electrostatic force F between two charged objects placed distance apart is directly proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between them.

F = kq₁q₂/r²

where k = 9 x 10⁹ N.m²/C²

The Particles q1 = -53.0 uc, q2 = +105 uc, and q3 = -88.0 uc are in a line. Particles qı and q2 are separated by 0.50 m and particles q2 and q3 are separated by 0.95 m.

The net force F3 = F13 + F23

Substitute the values, we get the force F on q3 as

F3 = 9 x 10⁹x53.0 x 10⁻⁶x 88.0 x 10⁻⁶ / (0.5+0.95)² + 9 x 10⁹x105.0 x 10⁻⁶x 88.0 x 10⁻⁶ / (0.95)²

F3 = 112.11 N

Thus, the magnitude of the force on charge q3 is 112.11 N.

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The x and y components of  the vector is 31.59 m and 29.46 m respectively.

The x component is calculated as follows;

v(x) = v cos(43)

v(x) = 43.2 m x cos(43) = 31.59 m

The y component is calculated as follows;

v(y) = v sin(43)

v(y) = 43.2 m x sin(43) = 29.46 m

Thus, the x and y components of  the vector is 31.59 m and 29.46 m respectively.

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The speeds and velcity will be 0.020 m/sec and 0.0149 m/sec.

Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while V for the final speed. its si unit is m/sec.

Given data;

d1=50 m E

d2=95 m N
Time period,t = 12 min = 12 × 60 sec = 7200 sec

The displacement is the shortest distance found from the pythogorous theorem as;

Displacement = √[(50 )²+(95)²]

Displacement = 107.35 m

a)The speed is found as;

Speed = distance / time

Speed = 50 +95 / 7200

Speed = 0.020 m/sec

b)The velocity is found as;

Velocity = Displacement / time

Velocity = 107.35 / 7200

Velocity = 0.0149 m/sec

Hence the speed and the velcity will be 0.020 m/sec and 0.0149 m/sec.

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Hello!

The equation for the magnetic force experienced by a wire is:
[tex]F_B = B \times iL[/tex]

F = Magnetic force on wire (30 N)

B = Magnetic field strength (5.0i + 7.0j)

i = Current in wire (4.0 A)
L = Length of wire (? m)

This is a CROSS-PRODUCT. We can rewrite this as:
[tex]F_B = BiLsin\theta[/tex]

Where 'θ' is the angle between the magnetic field and the current carrying wire.

Therefore, we would NOT count any field that is parallel to the wire. The field does have a component (5.0i) that is along the x-axis, so we would NOT count it because the wire is along this same axis.

This leaves the 'j' component, which is PERPENDICULAR to the wire. θ would then be 90°, and sin(90) = 1.

[tex]F_B = B\hat{j} iL[/tex]

Solving for the length:
[tex]L = \frac{F_B}{B\hat{j} i}\\\\L = \frac{30}{7(4)} = \boxed{1.07 m}[/tex]

We can get water from the sweat and exhaled breath of the people present in the space station.

We can get water from the sweat and exhaled breath. The water we drink is recycled from the sweat and exhaled breath of the people present in the space station which was collected through  condensation on the Space Station's walls.

So we can conclude we can get water from the sweat and exhaled breath of the people present in the space station.

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Answer: See below

Explanation:

Given:

Mass of the Mercedes-Benz (m) = 1700 kg

Inclination of the road (θ) = 15.0

The free body diagram is shown in figure attached below

a) The normal force is equal to the cos component of the weight of the car.

[tex]\begin{aligned}&f=m g \cos \theta \\&f=1700 \times 9.81 \times \cos 15 \\&f=16108.74 \mathrm{~N}\end{aligned}[/tex]

b) The static force will be equal to the weight's sin component.

[tex]\begin{aligned}&f=m g \sin \theta \\&f=1700 \times 9.81 \times \sin 15 \\&f=4316.32 \mathrm{~N}\end{aligned}[/tex]