Answer:
The tensions in [tex]T_{BC}[/tex] is approximately 4,934.2 lb and the tension in [tex]T_{BD}[/tex] is approximately 6,035.7 lb
Explanation:
The given information are;
The angle formed by the two rope segments are;
The angle, Φ, formed by rope segment BC with the line AB extended to the center (midpoint) of the ship = 26.0°
The angle, θ, formed by rope segment BD with the line AB extended to the center (midpoint) of the ship = 21.0°
Therefore, we have;
The tension in rope segment BC = [tex]T_{BC}[/tex]
The tension in rope segment BD = [tex]T_{BD}[/tex]
The tension in rope segment AB = [tex]T_{AB}[/tex] = Pulling force of tugboat = 1200 lb
By resolution of forces acting along the line A_F gives;
[tex]T_{BC}[/tex] × cos(26.0°) + [tex]T_{BD}[/tex] × cos(21.0°) = [tex]T_{AB}[/tex] = 1200 lb
[tex]T_{BC}[/tex] × cos(26.0°) + [tex]T_{BD}[/tex] × cos(21.0°) = 1200 lb............(1)
Similarly, we have for equilibrium, the sum of the forces acting perpendicular to tow cable = 0, therefore, we have;
[tex]T_{BC}[/tex] × sin(26.0°) + [tex]T_{BD}[/tex] × sin(21.0°) = 0...........................(2)
Which gives;
[tex]T_{BC}[/tex] × sin(26.0°) = - [tex]T_{BD}[/tex] × sin(21.0°)
[tex]T_{BC}[/tex] = - [tex]T_{BD}[/tex] × sin(21.0°)/(sin(26.0°)) ≈ - [tex]T_{BD}[/tex] × 0.8175
Substituting the value of, [tex]T_{BC}[/tex], in equation (1), gives;
- [tex]T_{BD}[/tex] × 0.8175 × cos(26.0°) + [tex]T_{BD}[/tex] × cos(21.0°) = 1200 lb
- [tex]T_{BD}[/tex] × 0.7348 + [tex]T_{BD}[/tex] ×0.9336 = 1200 lb
[tex]T_{BD}[/tex] ×0.1988 = 1200 lb
[tex]T_{BD}[/tex] ≈ 1200 lb/0.1988 = 6,035.6938 lb
[tex]T_{BD}[/tex] ≈ 6,035.6938 lb
[tex]T_{BC}[/tex] ≈ - [tex]T_{BD}[/tex] × 0.8175 = 6,035.6938 × 0.8175 = -4934.1733 lb
[tex]T_{BC}[/tex] ≈ -4934.1733 lb
From which we have;
The tensions in [tex]T_{BC}[/tex] ≈ -4934.2 lb and [tex]T_{BD}[/tex] ≈ 6,035.7 lb.
Question 5
Thermal energy can increase even if the average kinetic energy is constant.
O True
O False
The statement "thermal energy can increase even if the average kinetic energy is constant" is definitely true.
What do you mean by Kinetic energy?Kinetic energy may be characterized as a type of energy that an object possesses due to its motion. It is defined as the work that is required to accelerate a body of a given mass from rest to its stated velocity. It measures the work an object can do by the virtue of its motion.
The thermal energy will still enhance even if the average kinetic energy remains constant. This is because it is based on the relationship between kinetic energy and thermal energy. Kinetic energy is defined as the energy possessed by an object or body as a result of its motion.
Therefore, the statement "thermal energy can increase even if the average kinetic energy is constant" is definitely true.
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how to find range with height and velocity
Answer:
[tex]R= \frac{ v_ i\: ^2\:\times sin\:20}{g}[/tex]
Explanation:
Explain How can you
use a distance-time graph
to calculate average
speed?
Explanation:
Average speed = change in distance / change in time
In other words, the average speed is the slope of the line connecting two points on the graph.
Which of the following statements about slope is NOT true?
Explanation:
did you upload a picture?
If you were told an atom was an ion, you would know the atom must have a ______?
O Neutral Charge
O Charge
O Negative Charge
O Positive Charge
(This is due Tonight, so please help me ASAP!!!)
Answer:
charge
Explanation:
7r0I and its etc. ,"!×_/;
If an automobile with a velocity of 4.0 m/s accelerates at a rate of 4.0 m/s2
for 2.5 s, what is the final velocity?
Answer:
V=u+at
=4+4*2.5
=14m/s
Explanation:
Initial velocity =4m/s
acceleration =4m/(second) squared
time =2.5 seconds
v=u+at
v=4+4*2.5
v=14m/s
three short square wood blocks measuring 3.5 per side support a machine weighing 29500 lbs. What is the compressive stress in the blocks
A. 798lbs
B. 421lbs
C. 1404lbs
D. 803lb
Answer:
D. 803 lbs
Explanation:
In order to find the compressive stress on all three blocks we first need to find the normal surface area of each:
Surface Area of 1 Block = 3.5 x 3.5
Surface Area of 1 Block = 12.25
Surface Area of all 3 Blocks = A = 3 x 12.25
Area = 36.75
Now, the stress is given by the following formula:
Stress = Force/Area
Stress = 29500 lbs/36.75
Stress = 802.72 lbs
Hence, the correct option will be:
D. 803 lbs
A box measures 3.12 ft in length, 0.0455 yd in width and 7.87 inches in height. Since volume can be found using length x width x height, find the volume in cubic centimeters. Now find the volume in gallons.
Explanation:
This problem is on units conversion
given the dimensions
3.12 ft in length,
0.0455 yd in width and
7.87 inches in height
we have to convert to cm first
3.12 ft to cm=
1 ft-------30.48cm
3.12--------x
x=95.09cm
0.0455 yd to cm
0.0455yd ft to cm=
1 yd-------91.44cm
0.0455--------x
x=4.16cm
7.87 in to cm
1 in-------2.54cm
7.87--------x
x=19.98cm
the volume is =95.09cm*4.16cm*19.98cm
volume= 7907.45cm^3
the volume in gallon is
1 cm^3------0.000264172gal
7907.45cm^3-------x
x=7907.45*0.000264172
x=2.088gallons
Jesse is swinging Miguel in a circle at a tangential speed of 3.50 m/s. If the radius of the circle is 0.600 m and Miguel has a mass of 11.0 kg, what is the centripetal force on Miguel? Round to the nearest whole number. N
Answer:
224.6 N
Explanation:
We can use first the formula to calculate the centripetal acceleration, given by:
[tex]a_c=\frac{v_t^2}{R}[/tex]
where the Vt is the tangential velocity, and R is the radius of the circular motion.
Then, for our case we have:
[tex]a_c=\frac{v_t^2}{R}=\frac{3.5^2}{0.6}\approx 20.42\,\,\frac{m}{s^2}[/tex]
And now we multiply this acceleration by Miguel's mass (11 kg) to obtain the centripetal force acting on him:
[tex]F_c=11 \,*\,20.42\,N = 224.6\,\,N[/tex]
Answer:
225 N
Explanation:
Just answered the question
The x vector component of a displacement vector has a magnitude of 94.8 m and points along the negative x axis. The y vector component has a magnitude of 149 m and points along the negative y axis. Find (a) the magnitude and (b) direction of . Specify the direction as a positive angle with respect to the negative x axis.
Answer:
We use pythagorean theorem
So that
r = √(x² + y²)
r = √(94.8)² + (-149)² )
r =√ 9682.6 + 22201
= 178.6
direction we use
စ = tan^-1(98.4/149)
= tan^-1 (0.6604)°
(b) If you decrease the length of the pendulum by 25%, how does the new period TN compare to the old period T?
Answer:
The new period will be reduced by 50%
Explanation:
The period of pendulum is given by;
[tex]T= 2\pi\sqrt{\frac{L}{g} }\\\\\frac{T}{2\pi} = \sqrt{\frac{L}{g} }\\\\(\frac{T}{2\pi} )^2 = {\frac{L}{g}}\\\\\frac{T^2}{4\pi ^2} = {\frac{L}{g}}\\\\T^2(\frac{g}{4\pi ^2}) = L\\\\ \frac{g}{4\pi ^2}= \frac{L}{T^2}\\\\\frac{L_1}{T_1^2} = \frac{L_2}{T_2^2}[/tex]
When the length is decreased by 25%, the new length L₂ is given by;
L₂ = 25/100(L₁)
L₂ = 0.25L₁
[tex]\frac{L_1}{T_1^2} = \frac{L_2}{T_2^2}\\\\T_2^2 = \frac{T_1^2L_2}{L_1} \\\\T_N^2 = \frac{T^2(0.25L_1)}{L_1}\\\\ T_N^2 =0.25T^2\\\\T_N = \sqrt{0.25T^2}}\\\\T_N = 0.5 T[/tex]
Thus, the new period will be reduced by 50%
Complete the sentence with the word "element" or "compound." O is a(n) and H2O2 is a(n)
Answer:
O is an element whilst H2O2 is a compound.
Explanation:
O is an element. You can find it on the periodic table. H2O2 is composed of both H and O. Thus, H2O2 is a compound.
The O is a(n) element and [tex]H_{2} O_{2}[/tex] is a(n) compound.
What is element?All facets of a species of atoms with a specific count of protons in its nuclei are referred to as chemical elements, such as the pure substance made exclusively of the that species.
What is compound?A compound comprises a substance created by the chemical fusion of two or more components.
Therefore, the O is a(n) element and [tex]H_{2} O_{2}[/tex] is a(n) compound.
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A car travels 82 meters do North and 14 seconds the car turns around and travels 44 m due south in four seconds what is the magnitude of the average velocity of the car during the full travel time?
Answer:
2.11 m/s
Explanation:
Take north to be positive and south to be negative.
Average velocity = displacement / time
v = (82 m + -44 m) / (14 s + 4 s)
v = 2.11 m/s
The velocity is positive, so it is 2.11 m/s north. The magnitude of the velocity is 2.11 m/s.
I'm confused, and I can't seem to get this question right. someone please help. Only two forces act on an object (mass = 5.00 kg), as in the drawing. (F = 55.0 N.) Find the magnitude and direction (relative to the x axis) of the acceleration of the object. (Drawing: 45 degrees, Fx is 40 N)
Answer:
17.6 m/s², 26.2° above x axis
Explanation:
Apply Newton's second law.
Sum of forces in the x direction:
∑Fₓ = ma
40 N + 55.0 N cos 45° = (5.00 kg) aₓ
aₓ = 15.8 m/s²
Sum of forces in the y direction:
∑Fᵧ = ma
55.0 N sin 45° = (5.00 kg) aᵧ
aᵧ = 7.78 m/s²
Use Pythagorean theorem to find the magnitude of the resultant.
a² = aₓ² + aᵧ²
a² = (15.8 m/s²)² + (7.78 m/s²)²
a = 17.6 m/s²
Use trigonometry to find the angle.
tan θ = aᵧ / aₓ
tan θ = (7.78 m/s²) / (15.8 m/s²)
θ = 26.2°
during which stage do you have sleepwalking and sleeptalking
A. stage 2
B. stage 4
C. REM
D. stage 1
What is the volume of a marble with a diameter of 3.0
Explanation:
You can solve for volume using radius or diameter.
Sphere Volume = 4/3 • π • r³ = ( π •d³)/6
We're given the diameter so let's use that.
Volume = PI * d^3 / 6
Volume = 3.14159 * 3.0^3 / 6
Volume = 3.14159 * 9 / 2
Volume = 14.137 cubic centimeters
The position of a particle
Answer:
vector
Explanation:
The position of a particle is vector
If you go 45 meters at a speed of 16 m/s, how long does the movement take? Exact answer, do NOT round.
Answer:
2 seconds
Explanation:
The time taken for the movement is 2.81 seconds.
To find the time, the given values are,
Distance = 45 meters
speed = 16 m/s.
What is distance?Distance is the total movement of an object without any regard to direction.Distance can be evaluated how much an object moves from starting point to the end point.The distance completely depends upon the speed and time, i,e., the object covering some area with some particular time interval with the particular speed.Distance will be measured in meter, kilometer, etc..Distance is a Scalar quantity.Formula of distance,
Distance = Speed × Time.
As we have to find the time, Formula can be rearranged as,
Time = Distance / Speed
Substituting the given datas in the formula,
Time = 45 / 16
= 2.81 seconds.
So, the time taken for the movement is 2.81 seconds.
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what role do control groups play
Answer:
Control groups let the one who is expermenting compare the effect of the varibles in the expermental group.
Explanation:
The foundation of psychology is?
Case Studies
O Experiments
O Research
O Analysis
Answer:
Case Studies
Explanation:
A case study in psychology is a descriptive research approach used to obtain in-depth information about a person, group, or phenomenon.Case studies use techniques such as personal interviews, direct observation, psychometric tests, and archival records to gather information.
A brick is lying on a table in a state of static equilibrium. If the mass of the brick is 7.52 kilograms, what is the normal force exerted by the table on the brick? A. -73.7 newtons B. 73.7 newtons C. 80.7 newtons D. 7.52 newtons E. 8.07 newtons
The answer is OPTION B : 73.7 N
Answer:
B
Explanation:
- When a mixture contains substances that are not evenly mixed, it is called?
Answer: Heterogenous mixture
Explanation:
A heterogeneous mixture in which the components of the mixture are not evenly mixed or uniform, allowing one to identify the different constituents of each components and enable the mixture to be separated physically.
Examples of heterogeneous mixtures includes
-- sand and nails
---rice and beans
--- water and oil
Another type of mixture is the homogeneous mixture in which all the components are evenly mixed causing that each components cannot be visible with the eye and therefore separated chemically.
Sound travels at a rate of 340 m/s in all directs through the air. Matt rings a very loud bell at one location, and Steve hears it some time later at his location 450 meters to the south. How long did it take the sound to travel from the bell to Steve’s location?
Answer:
It will take about 1.32 seconds to travel to his location.
Explanation:
Considering the sound travels at 340 m/s, then if a person is at a distance of 450 m m from the bell, we can use the velocity formula to find the answer;
[tex]velocity=\frac{distance}{time} \\340\,\frac{m}{s} =\frac{450\,\,m}{t} \\t=\frac{450}{340} \,s\\t\approx 1.32\,\,s[/tex]
Answer:
b
Explanation:
the graph shows position versus time for an object moving with the constant acceleration. what is the final velocity of the object at t=10s? assume the initial velocity at the origin is 1 m/s.
3.32 m/s
4.0 m/s
3.0 m/s
3.8 m/s
Answer:
3.0 m/s
Explanation:
The equation of motion for constant acceleration (a) is ...
[tex]x(t)=\dfrac{1}{2}at^2 +v_0t+x_0[/tex]
The problem statement tells us v₀ = 1, and we read from the graph that x₀=1. We also read from the graph that x(10) = 21. Filling these values into the equation, we can find a and x'(10).
[tex]21 = \dfrac{1}{2}a(10^2)+1(10)+1\\\\10=50a\qquad\text{subtract 11}\\\\a=\dfrac{1}{5}\\\\x'(t)=at+v_0\\\\x'(10)=\dfrac{1}{5}\cdot 10+1=3.0[/tex]
The final velocity of the object at t=10 s is about 3.0 m/s.
_____
Comment on the graph
We note this graph better represents increasing acceleration than it does constant acceleration. x(2) = 3.4 per the equation. It is graphed as about 4.
Answer:
thanks for de points
Explanation:
Aldis is swinging a ball tied to the end of a string over his head. Suddenly, the string breaks and the ball flies away. Arrow best represents the path the ball follows after the string breaks.
Answer:
Straight line in the direction of the tangential velocity the ball had at the moment the string broke
Explanation:
After the string breaks, the ball now disconnected from the centripetal force that was exerted via the string, continues its travel in a straight line in the direction of the tangential velocity it had at the moment the string broke.
Answer:
B
Explanation:
just took the test :)
what are two examples of population distribution?
is the
What is the tendency to move to a drive-free state?
O A. Homeostasis
OB. Equality
OC. Homogeneity
OD. Motivationless
What is the magnitude of the thrust force before the cart is released?Express your answer in newtons using three significant figures.
Answer:
Hello your question is incomplete below are missing parts
In this video, a small cart that has a mass of 600 grams rests on a table top. There is a fan on top of the cart, blowing air backwards at a steady rate. A stretched spring is attached to the back of the cart by a string, holding it in place. A scale, marked off in newtons, is positioned next to the spring and a small dot at the end of the spring indicates the magnitude of the spring force. The spring and scale together is called a “dynamometer.” Before the cart is released from the spring, the dynamometer reads approximately 1.9 newtons. The video is recorded at 60 frames per second, resulting in playback motion 2 times slower than normal. A frame counter indicates the current frame. A horizontal distance scale, marked off in centimeters, is also shown on the video. While the cart is at rest, the front edge of the front wheel is at the zero of the scale.
At frame 245, the string that attaches the cart to the spring is cut, releasing the cart, and it begins to roll forward. Using the distance scale, the position of the front edge of the front wheel can be tracked with
time. The following table indicates the position at different frames.
Frame Position (cm)
245 0.0
251 1.9
257 6.0
263 13.9
269 24.6
275 38.4
281 55.1
287 75.0
Answer : 1.9 N
Explanation:
The magnitude of the thrust force before the cart is released can be calculated as :
60 fbs = 1 frame = 1/60 secs
therefore 6 frames = 1 / 10 secs
F fam = F spring = 1.9 N
Note: F thrust = F fam = 1.9 N
Air conditioners operate on the same principle as refrigerators. Consider an air conditioner that has 7.00 kg of refrigerant flowing through its circuit each cycle. The refrigerant enters the evaporator coils in phase equilibrium, with 54.0 % of its mass as liquid and the rest as vapor. It flows through the evaporator at a constant pressure and when it reaches the compressor 95% of its mass is vapor. In each cycle, how much heat Qc is absorbed by the refrigerant while it is in the evaporator? The heat of vaporization of the refrigerant is 1.50×105 J/kg
Answer:
5.15J
Explanation:
First. 54% of the 7kg refrigerant is liquid
So we find mass of vapour at inlet generator
M1 = ( 1-0.54)*7= 3.2kg
At compressor mass of vapour will be
M2= 0.95*7= 6.7kg
So the Mass of vapour at exit generator is
M2-M1= 3.5kg
So to find heat absorbed by refrigerant in evaporation
Its using
Q= mh
°= 3.5x 1.50×10^5 J/kg
=5.15J
A runner completes the 300-meter dash in 38 seconds. What is the speed of the runner? Round your answer the answer to the nearest tenth.
Answer:
speed = 7.9 m/s
Explanation:
speed = total distance / time taken
speed = 300 / 38
speed = 7.89473684 m/s
to the nearest tenth
speed = 7.9 m/s