A truck with mass m has a brake failure while going down an icy mountain road of constant downward slope angle α (Figure 1). Initially the truck is moving downhill at speed v0. After careening downhill a distance L with negligible friction, the truck driver steers the runaway vehicle onto a runaway truck ramp of constant upward slope angle β. The truck ramp has a soft sand surface for which the coefficient of rolling friction is μr.
What is the distance that the truck moves up the ramp before coming to a halt? Solve using energy methods.
Express your answer in terms of m , α , v0 , L , g , β and μr .
Answers
((v² ÷ 2g) + LSinα) ÷ (Sinβ + µcosβ) is the distance that the truck moves up the ramp before coming to a halt.
Let the distance the truck moves up the ramp be by x.
The kinetic energy of the truck on an icy road is given by,
K1 = (1÷2)mv²
The potential energy of the truck on an icy road is given by,
U1 = mgLSinα
The kinetic energy of the truck on the tuck ramp is given by,
K2 = 0
The potential Energy of the truck-on-truck ramp is given by,
U2 = mgxSinβ
Work done is given by,
W(others) = -µ×mg×cosФ
Hence, by using the work-energy theorem,
W(others) = (K2 + U2)(K1 + U1)
Therefore, by putting the values we get,
((1÷2)mv² + mgLSinα)(0 + mgxSinβ) = -µ×mg×cosФ
x = (K1 + mgLSinα) ÷ (mg(Sinβ + µcosβ))
x = ((v² ÷ 2g) + LSinα) ÷ (Sinβ + µcosβ)
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Related Questions
When light is reflected, the incident rays are bent and change direction.
Answers
Given
When light is reflected, the incident rays are bent and change direction
To find
Whether the given statement is true
Explanation
When we flash a light on the mirror, the light changes its direction and move in another way. So the incident light changes direction when reflected
Conclusion
The given statement is TRUE
if may 20 is a last quarter moon, when could you expect the first quarter moon to occur?
Answers
In the early afternoon or high in the sky around the time, the sun is setting.
The crescent moon rises around noon and sets around midnight. It can be seen near the horizon in the evening or high in the sky as the sun sets. If you live in the northern hemisphere, the first quarter moon appears as the right half of the illuminated surface. Occurs when the moon is at right angles to the sun as seen from Earth.
The right half of the moon appears bright and the left half appears dark. During the period from the new moon to the first quarter moon, the illuminated part of the moon grows larger day by day and continues to grow until the full moon. The first quarter is also called the crescent moon because 50% of its surface is briefly illuminated by the sun. Usually, he takes 3 nights. Each phase of the moon has a profound effect on humans and the earth.
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What is the force between two protons that are separated by 1.0 mm? The
charge of a proton is 1.6 x 10-19 C
5.3 x 10^-50 N
2.3X10^-25 N
2.3 X 10^-22 N
1.4 X 10^-3 N
Answers
The charge of a proton is 2.3 X 10^-22 N. Option C.
The force between two protons is the electrostatic repulsion. The electrostatic force is the force that develops between electric charges. This is called the strong nuclear force. It is one of the basic strengths. The amount of strong nuclear force acting between two protons is the same as the amount of strong nuclear force acting between two neutrons.
The nuclear force is the force acting between the protons and neutrons of an atom. The nuclear force is the force that binds protons and neutrons within the nucleus. This force can exist between protons and protons neutrons and protons or neutrons and neutrons. This force holds the core together. nuclear power. Nuclear forces act between all particles in the nucleus between two neutrons between two protons and between neutrons and protons.
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A train car with a mass of 14 kg and speed of 30 m/s is traveling to the right. Another train car with a mass of 26kg is moving with an unknown velocity. After the collision, the 14 kg train car is stuck to the 26 kg train car with a combined velocity of 12 m/s
Answers
From the Law of Conservation of Linear Momentum, when two particles get stuck together after a collision, it follows that:
[tex]m_1v_1+m_2v_2=(m_1+m_2)v_f[/tex]In this case, the initial velocity of the second particle is unknown. Isolate it from the equation:
[tex]v_2=\frac{(m_1+m_2)v_f-m_1v_1}{m_2}[/tex]Replace the given data to find the value of v₂:
[tex]\begin{gathered} m_1=14kg \\ v_1=30\frac{m}{s} \\ \\ m_2=26kg \\ v_2=\text{ unknown} \\ \\ v_f=12\frac{m}{s} \\ \\ \Rightarrow v_2=\frac{(14kg+26kg)(12\frac{m}{s})-(14kg)(30\frac{m}{s})}{26kg}=2.3077...\frac{m}{s} \\ \\ \therefore v_2\approx2.3\frac{m}{s} \end{gathered}[/tex]Therefore, the initial velocity of the 26-kg car is approximately 2.3m/s.
A car of mass 1101 kg traveling at 18.39 m/s collides and sticks to a car with a mass of 1050 kg initially at rest. What is the resulting velocity of the two cars right after the collision, assuming that there's no friction present?
Answers
Answer: the resulting velocity of the two cars right after the collision is 9.41 m/s
Explanation:
The formula for calculating momentum is expressed as
momentum = mass x velocity
According to the law of conservation of momentum, initial momentum = final momentum
The formula for initial momentum is
m1u1 + m2u2
where
m1 = mass of first car
u1 = initial velocity of first car
m2 = mass of second car
u2 = initial velocity of second car
From the information given,
m1 = 1101
u1 = 18.39
m2 = 1050
u2 = 0 because it is at rest
Initial momentum = 1101 x 18.39 + 1050 x 0 = 20247.39
Since the cars stick together after collision, they would have a common velocity, V. Thus,
final momentum = (m1 + m2)V
final momentum = (1101 + 1050)V = 2151 V
Thus,
20247.39 = 2151 V
V = 20247.39/2151
V = 9.41
the resulting velocity of the two cars right after the collision is 9.41 m/s
The steeper the slope of a current vs voltage graph, the _________ the resistance.A. Not enough infoB. LowerC. The sameD. Greater
Answers
The slope of the graph current vs voltage can be explained with the next
[tex]\begin{gathered} V=IR \\ I=\frac{V}{R} \end{gathered}[/tex]In this case, current vs voltage means that current is y axis, and voltage is x axis. Based n that, the equation is the second one
[tex]I=\frac{V}{R}[/tex]And the slope is the inverse of the resistance. Dont forget that current - voltage is different to voltage - current
Alyse runs to her classroom which is 20 meters away. She forgets her physics book in her locker and must return 20 meters in the direction from whence she came. If her total trip takes 3 minutes, what is Alyse’s average velocity? NEED HELPP ASAPPPP!!!!!
Answers
The average velocity of Alyse is 0 m/s.
What is the average velocity of an object or a person?The average velocity of a person is the average of all the velocities of moving as it moves.
Velocity on its own is the ratio of the displacement of a body and the time taken for that displacement.
Mathematically:
Average velocity = total displacement / time takenDisplacement is a vector quantity that measures the distance traveled by a moving body in a specific direction.
Hence, average velocity and velocity are both vector quantities.
Displacement takes a measure of the shortest possible distance along a straight line from the beginning of the motion until the end of the motion.
Calculating the average velocity of Alyse:
Assuming the initial direction is positive and n=backeard direction is negative:
Total displacement = 20 m + - (20 m)
Total displacement = 0 m
total time = 3 minutes
Average velocity = 0 m/ 3
Average velocity = 0 m/s
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A car goes from rest to velocity of 108 km/h north in 0.2 hours. What is the car's acceleration?
Answers
Answer:
21.6
Explanation:
bc acceleration is equal to 108 times 0.2
A marble is rolled down a ramp. The ramp has a slope of 0.2 for the first meter and then 0.1 for the second meter. Describe how the acceleration and velocity of the marble will be different when it has traveled 1.5 meters as compared to when it has traveled 0.5 meters
Answers
The velocity and acceleration of the marble will be greater when it travels 1.5 m compared to 0.5 m.
What is velocity?
The velocity of an object is the rate of change of displacement with time.
The velocity of the marble after it has travelled the given distance is calculated as follows;
v² = u² + 2as
where;
v is the final velocity of the marbleu is the initial velocity of the marbles is the distance travelled by the marblea is the acceleration of the marbleAssuming the marble started from rest, without initial velocity, our final equation becomes.
v² = 0² + 2as
v² = 2as
v = √2as
From the final equation, the velocity of the marble increases with increase in the distance travelled by the marble.
Also, since acceleration is defined as the rate of change of velocity with time. As the velocity increases, the acceleration of the marble increases as well.
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I need help with this practice I’m struggling to solve it
Answers
The blades on the turbines transform the energy coming from the wind into rotational kinetic energy.
The blades convert wind energy into rotational energy.
To get a flat, uniform cylindrical satellite spinning at the correct rate, engineers fire four tangential rockets as shown in the figure (Figure 1). Suppose that the satellite has a mass of 1300 kg and a radius of 4.8 m , and that the rockets each add a mass of 250 kg.
a) What is the steady force required of each rocket if the satellite is to reach 46 rpm in 7.0 min , starting from rest?
Answers
The steady force required of each rocket is 27,875 N.
What is the steady force required for each rocket?
The steady force required by each rocket along the circular path is calculated as follows;
F = ma
where;
m is the mass of the each rocketa is the centripetal acceleration of each rocketThe centripetal acceleration of each rocket is calculated as follows;
a = ω²r
where;
ω is the angular velocity of the rocketr is the radius of the circular pathω = 46 rpm = 46 rev/min x 2π rad/rev x 1 min/60s = 4.82 rad/s
t = 7 min = 7 x 60 s = 420 s
a = ω²r
a = (4.82²) x 4.8 m
a = 111.5 m/s²
The steady force is calculated as follows;
F = ma
F = 250 x 111.5
F = 27,875 N
Thus, the steady force required of each rocket is determined by applying the concept of centripetal force.
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Two ice skaters stand facing each other at rest on a frozen pond. They push off against one another and the 49 kg skater acquires a speed of 2.10 m/s. If the other skater acquires a speed of 3.81 m/s, what is her mass in kilograms?
Answers
The mass of the second skater is equal to 27 Kg, which acquires a speed of 3.81 m/s.
What is law of conservation of linear momentum?According to the law of conservation of momentum, the sum of the momentum of the two objects before and after the collision must be equal.
m₁ u₁ + m₂u₂ = m₁ v₁ + m₂ v₂
where m₁ and m₂ is the mass of the collided bodies, u₁ and u₂ are the initial speed while v₁ & v₂ is their final speed.
The linear momentum can be described as the product of the mass times the velocity of the object. Conservation of momentum is a characteristic held by an object where the total amount of momentum remains the same.
Given the initial speed of the skaters is equal to zero so u₁ = u₂ =0
The mass of the one skater, m₁ = 49 Kg
The first skater acquires the speed, v₁ = 2.10 m/s
The speed acquired by the second skater, v₂ = -3.81 m/s
From the law of conservation of momentum, we can find the mass of another skater:
m₁ u₁ + m₂ u₂ = m₁v₁ + m₂ v₂
49 × 0 + m₂ ×0 = 49 × (2.10) + m₂ × (- 3.81)
m₂ = -49 × (2.10)/ (- 3.81)
m₂ = 27 Kg
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A converging lens has a focal point of 3.93 cm. If you place an apple 19.24 cm away from the lens, where would the image be formed? Submit your answer in meter.
Answers
Given
The focal length , f=3.93 cm
The object distance, u=-19.24cm
To find
The image distance
Explanation
By lens formula we have,
[tex]\begin{gathered} \frac{1}{v}-\frac{1}{u}=\frac{1}{f} \\ \Rightarrow\frac{1}{v}-\frac{1}{(-19.24)}=\frac{1}{3.93} \\ \Rightarrow\frac{1}{v}=0.202 \\ \Rightarrow v=4.95cm=0.0495\text{ m} \end{gathered}[/tex]Conclusion
The image distance is 0.0495 m
Which statement below best describes how scientists explain gravity's role in the formation of
our Solar System? and Why?
A. The combined gravitational attraction between our planets was so large that it pulled the
Sun away from a nearby star cluster into the center of our Solar System.
B.The eight planets in our Solar System were originally orbiting a nearby star, and the Sun's
gravity was large enough to pull those planets into orbit around the Sun.
C. Due to the expansion of neighboring solar systems, the gravitational attraction of our
planets to those solar systems forced the formation of the planets around our Sun.
D.As the Sun was forming, the force of gravity caused surrounding dust grains to collide and
stick together, forming dust granules into increasingly larger bodies that became planets.
Answers
D. As the Sun was forming, the force of gravity caused surrounding dust grains to collide and stick together, forming dust granules into increasingly larger bodies that became planets.
About 4.6 billion years ago, the Solar System was a cloud of dust and gas known as the Solar Nebula.
The gravitational forces of the planets push gases out of their atmospheres and form a star at the center of the solar system.Gravity compresses the gases in the center of the solar nebula until temperatures are high enough for nuclear fusion to occur.It collapsed the material in on itself as it began to rotate, forming the sun at the center of the nebula.As the sun rose, the remaining material began to clump together.Gravity is the force that pulls a body toward the center of the Earth or any other physical body that has mass.
Therefore "As the Sun was forming, the force of gravity caused surrounding dust grains to collide and stick together, forming dust granules into increasingly larger bodies that became planets", best describes scientists explain gravity's role in the formation of our Solar System.
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A chemical reaction separates water into hydrogen gas and oxygen gas. Which of the following statements is true about the mass of the water and the combined mass of the two gases
Answers
Answer:
The mass of the water is greater than the combined mass of the two gases
Hint: first convert the given final speed (in mph) to find ft/s, then solve for the distance and acceleration.
Answers
ANSWER
[tex]\begin{gathered} Dis\tan ce=149.56ft \\ Acceleration=4.14ft/s^2 \end{gathered}[/tex]EXPLANATION
First, we have to find the acceleration of the bicyclist.
To do that, we apply the formula:
[tex]a=\frac{v-u}{t}[/tex]where u = initial velocity
v = final velocity
t = time
Let us convert the speed given to feet per second. To do that, multiply the speed by 1.46667:
[tex]\begin{gathered} 24\cdot1.46667 \\ \Rightarrow35.2mph \end{gathered}[/tex]The bicyclist started from rest, so the initial speed is 0 ft/s.
Therefore, the acceleration is:
[tex]\begin{gathered} a=\frac{35.2-0}{8.5} \\ a=4.14ft/s^2 \end{gathered}[/tex]Now, to find the distance traveled, apply the formula:
[tex]s=ut+\frac{1}{2}at^2[/tex]Therefore, the distance traveled is:
[tex]\begin{gathered} s=(0\cdot8.5)+\frac{1}{2}\cdot4.14\cdot8.5^2 \\ s=\frac{1}{2}\cdot4.14\cdot8.5^2 \\ s=149.56ft \end{gathered}[/tex]An egg test dummy is fitted with a helmet, sealed in a plastic bag, and attached to a swing with a clamp. These items have a mass of 0.090 kg. This mass is pulled back to a height of 0.55m. The mass is then released and allowed to swing down and collide with a cement block. What is the speed of the mass at the moment before impact?
Answers
The speed of the mass at the moment before impact is 3.28 m/s.
What is the final speed of the egg?
The speed of the mass at the moment before impact is calculated from the principle of conservation of energy as shown below.
K.E(bottom) = P.E(top)
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
v is the speed of the egg before the impacth is the height of the fall of the eggSubstitute the given parameters and solve for the speed of the egg before the impact.
v = √2gh
v = √(2 x 9.8 x 0.55)
v = 3.28 m/s
Thus, the speed of the mass at the moment before impact is determined by applying the principle of conservation of energy.
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Joshua rode his bicycle from his school to home. The total distance covered in this journey was 800 meters and the total time taken was 7 minutes. What is the average speed of joshuas bicycle in this journey
Answers
Answer: 6,857.14m/h (6.86km/h or 1.90m/s)
Explanation:
A 55 kg skater rolls along a U-shaped half pipe starting at rest from a height of 15 m. The skater rolls to the other side of the half pipe at a height of 12 m before stopping. What is the work done by friction?
Answers
The work done by friction is -1617 J
What is work done?Work done is the product of force and distance moved in the direction of the force.
What is friction?Friction is the opposition to motion between two surfaces
What is the work done by friction?From the lwa of conservation of energy, the work done by friction, W equals the change in potential energy of the skater, ΔU.
So, ΔU = W
mgΔh = W
mg(h₂ - h₁) = W where
m = mass of skater = 55 kg, g = acceleration due to gravity = 9.8 m/s², h₁ = initial height of skater = 15 m and h₂ = final height of skater = 12 m.So, substituting the values of the variables into the equation for the work done, we have
W = mg(h₂ - h₁)
= 55 kg × 9.8 m/s²(12 m - 15 m)
= 55 kg × 9.8 m/s² × (-3 m)
= 539 kgm/s² × (-3 m)
= -1617 J
So, the work done is -1617 J
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Explain why planets orbit the sun instead of traveling off into space
Answers
Answer:
gravity
Explanation:
The gravity of the Sun keeps the planets in their orbits. They stay in their orbits because there is no other force in the Solar System which can stop them.
what is the acceleration of a car, moving along a straight line, that increases its velocity from 0 to 15 m/s in 10s?
Answers
Acceleration = Change in Velocity / Time Interval
So,
A=15/10
A=1.5m/s.
Acceleration is defined as the rate of change of velocity over time. Acceleration is a vector quantity because it has both magnitude and direction. It is also the second derivative of position with respect to time or the first derivative of velocity with respect to time. Acceleration is the name we give to the process of changing velocity. Because speed is speed and direction.
There are only two ways to accelerate. Either change speed change direction or change both. Acceleration is the rate of change of velocity. At any point in the orbit, the magnitude of the acceleration is given by the rate of change of magnitude and direction of velocity at that point. Velocity is the primary measure of object position and velocity. It can be defined as the distance traveled by an object in a unit of time.
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How does a ramp make it easier to move a heavy object a certain distance?A by decreasing the distance the object movesB by decreasing the amount of work required to move the objectC by changing the direction in which the object movesDby decreasing the amount of force required to move the object
Answers
When lifting an object we are required to produce a force that is greater or equal than the weight of the object in order to be lifted:
When we use a ramp we have the following distribution of forces:
In the ramp, the force decomposes into two components. A component that is parallel to the ramp and a component that is perpendicular to the ramp. Now the force must be greater or equal to the parallel component of the ramp therefore, the amount of force required must be less. Therefore, the ramp makes it easier by decreasing the amount of force required to move the object.
By Decreasing the amount of force required to move an objectExplanation:
Objects, especially simple machines, make work easier. They do not decrease the amount of work done, but actually decrease the amount of force applied. The less force applied, the easier it is to do work. Simple machines and other objects that help make work easier decrease the amount of force required to move an object.
So the answer is-
A ramp makes work easier by decreasing the amount of force required to move an object
on landing the plane touches a runaway with a speed of 65 m/s the figure shows the of the speed of the plane after one second. calculate the acceleration of the plane during its landing
Answers
Answer:
Correct option is B)
Given, initial velocity is u=0m/s
Final velocity is v=88.3m/s and traveled distance, d=1365m
Let a be the acceleration of the plane.
Using v
2
−u
2
=2ad
∴ (88.3)
2
−0
2
=2a(1365)
⟹ a=2.86m/s
2
Solve any question of Motion in a Straight Line with:-
Explanation:
hope it helps
To solve this we must be knowing each and every concept related to acceleration. Therefore, the correct option is option B. The acceleration of the plane during its landing is 2.86m/s².
What is acceleration?Acceleration is the rate during which velocity varies over time, both in terms of speed and direction. A point or object travelling in a straight path is accelerated if something accelerates or decelerates.
Regardless of whether the speed remains constant, motion on such a circle gets accelerated because of direction is always changing. Both tangential to acceleration in all other types of motion.
initial velocity u=0m/s
Final velocity v=88.3m/s
distance, d=1365m
v²-u²=2as
substituting all the given values in the above equation, we get
88.3²-0²=2×1365×a
a=2.86m/s²
Therefore, the correct option is option B. The acceleration of the plane during its landing is 2.86m/s².
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The graph below shows the number of sunspots observed between 1750 and 2000.
Based on the graph, which of these statements is most likely correct about the periods 1800 to 1850 and 1900 to 1950?
A) There was decrease in global temperatures.
B) There was increase in global temperatures.
C) There was no significant change in solar activity.
D) There was no significant change in global climate.
Answers
Based on the graph, during the periods 1800-1850 and 1900-1950, there was a increase in global temperature.
Sunspots is an activity on the surface of the Sun that manifest as transient, darker-than-the-neighboring-areas spots. These parts on which it occurs have lower surface temperatures because magnetic flux concentrations there prevent convection from occurring.
Sunspot can increase the temperature of earth but by only a margin of about 0.05 to 0.1 Celsius.
As we can see from the graph that during the year 1800-1850 and 1900-1950 that number of sunspots is increasing continuously. So, there will a slight increase will be noticed in the global temperature.
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Two audio speakers are placed on a vertical rail. Speaker A is placed at head-level while Speaker B is place at some variable height, Δy, above Speaker A. Both speakers receive simultaneous input from a sine-wave generator so the speakers each produce a pure sinusoidal sound wave with a wavelength of 0.880 meters. Calculate the lowest height that Speaker B can be placed above Speaker A to produce a minimum of sound heard by person standing Δx=6.38 meters directly in front of Speaker A.
Answers
The lowest height at which speaker B can be placed above speaker A to produce the lowest sound to the person standing in front of A by superposition and wave interference is ∆y ≈ 2.41 m.
What is the superposition principle?The superposition principle states that the magnitude of the resulting wave when two waves overlap is the sum of the disturbance of the individual waves.
The given parameters are;
Height of speaker B above speaker A = ∆y
Wavelength of the wave = 0.880 meters
Distance between the person standing directly in front of speaker A and speaker A, ∆x = 6.38 meters
Required;
The minimum height of speaker B above speaker A that produces the minimum sound to the person in front of speaker A
Solution;
The minimum sound is given when there is destructive interference of the waves produced by the speakers
When there is destructive interference, the peak of the wave from speaker A coincides with the through of the wave from speaker B which gives;
Distance between a peak and the through of a wave = 0.5 × The wavelength
Therefore, for minimum sound, we have;
Distance from the person to speaker B = 6.38 m + 0.5 × (The wavelength)
Which gives;
Distance from the person to speaker B = 6.38 m + 0.5 × 0.88 m = 6.82 m
Pythagorean theorem is used to find the height of speaker B above speaker A as; ∆y = √(6.82² - 6.38²) ≈ 2.41
The height of speaker B above A is approximately 2.41 meters
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The lowest height that Speaker B can be placed above Speaker A to produce a minimum of sound heard by a person standing Δx=6.38 meters directly in front of Speaker A is
[tex]\Delta y=1.62m[/tex]
This is further explained below.
What is the lowest height?Generally, For a person, to hear sound minimum, sound waves from speakers A and B should meet at point P, in opposite phases, so path diff. should be
[tex]x=(2 n+1) \frac{\lambda}{2},[/tex]
[tex]\lambda[/tex]= wavelength
[tex]for $\Delta y$ to be minimum $\Rightarrow x=\frac{\lambda}{2}$ \\\\from figure, in $\triangle A B P$$$\Delta x^2+\Delta y^2=\Delta x^{\prime 2}=\text { (2) }$$[/tex]
Path diff. will be x=B P-A P
[tex]\begin{aligned}& \quad x=\Delta x^{\prime}-\Delta x \\\\&\Delta x^{\prime}-\Delta x=\frac{\lambda}{2} \quad x=\frac{\lambda}{2} \quad \text { from eq (1) } \\\\&\left.\Delta x^2+\Delta y^2-3.01=0.41 \quad \quad \quad \quad \lambda=0.820 \mathrm{~m}\right] \\\\&\Delta x^2+\Delta y^2=3.42 \\\\&\Delta y^2=(3.42)^2-(3.01)^2 \quad \Delta x=3.01 \mathrm{~m} \\\\&\Delta y=1.62 \mathrm{~m}\end{aligned}[/tex]
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What is the resistance (in Ω) of a 17.5 m long piece of 17 gauge copper wire having a 1.150 mm diameter?
Answers
In order to calculate the resistance of this wire, we can use the formula below:
[tex]R=\frac{\rho d}{A}[/tex]Where p is the resistivity, d is the length and A is the cross-sectional area of the wire.
The resistivity of the copper is 1.72 * 10^-8 ohms*m, so we have:
[tex]\begin{gathered} R=\frac{1.72\cdot10^{-8}\cdot17.5}{\frac{\pi\cdot(1.15\cdot10^{-3})^2}{4}}\\ \\ R=\frac{30.1\cdot10^{-8}\cdot4}{\pi\cdot1.3225\cdot10^{-6}}\\ \\ R=\frac{120.4\cdot10^{-8}}{4.1547563\cdot10^{-6}}\\ \\ R=28.98\cdot10^{-2}\text{ ohms}\\ \\ R=0.2898\text{ ohms} \end{gathered}[/tex]Misrepresentations of physical stimuli are known as
Answers
Misrepresentations of physical stimuli are known as Absolute Threshold
What is stimulus?
A stimulus is a measurable change in the physical or chemical structure of an organism's internal or external environment in physiology. Sensitivity refers to an organism's or organ's ability to perceive external stimuli and respond appropriately (excitability). Sensory receptors can receive information from both inside and outside the body, such as touch receptors in the skin or light receptors in the eye, as well as chemoreceptors and mechanoreceptors. When a sensory receptor detects a stimulus, it can generate a reflex via stimulus transduction. A homeostatic control system's first component is frequently an internal stimulus. External stimuli, such as the fight-or-flight response, are capable of eliciting systemic responses throughout the body.
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A 5.9 x 104-kg space probe is traveling at a speed of 14000 m/s through deep space. Retrorockets are fired along the line of motion to
reduce the probe's speed. The retrorockets generate a force of 1.4 x 104 N over a distance of 3700 km. What is the final speed of the
probe?
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Answer:
there are 6 circles and 2 triangles. what is the simplelest ratio of triangles to circles
Calculate the area of the plates of a 1 pF parallel plate capacitor in a vacuum if the separation of the plates is 0.1 mm. [ε0=8.85×10-12C2N-1m-2 ]
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For parallel plate capacitors the capacitance C=Aϵ0/d
dAϵ 0
Area, A Cd/ ϵ0 = 1 * 1×[tex]10^{-3}[/tex]/8.85× [tex]10^{-12}[/tex]
= 1.13×10 8 m 2.
The capacitance depending on geometry is given by the formula C=ϵ⋅Ad C = ϵAd. where C is the capacitance value A is the area of each plate, and d is the distance between the plates. plates, and ϵ is the dielectric constant of the material between the plates of the parallel capacitor.
The governing equations for capacitor design are C = εA/d where C is the capacitance. ε is the permittivity, a term that describes how well a dielectric holds an electric field. A is the area of the parallel plates. d is the distance between the two conductive plates. This is shown below. To calculate the total capacitance of multiple capacitors connected in this way, sum the individual capacitances.
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how can earthquakes be more destructive than tsunamis
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Buildings can be destroyed by earthquakes or knocked down, trapping people underneath.
Only regions close to the water are susceptible to tsunamis, but anybody may be affected anywhere by earthquakes. Buildings can be destroyed by earthquakes or knocked down, trapping people underneath. Uneven surfaces and damaged roadways can result from the shifting and cracking of the Earth during earthquakes. When two chunks of the ground abruptly slide past one another, an earthquake results. The fault or fault plane is the area where they slide. Sudden movement along Earth's fault lines causes earthquakes. The motion releases "elastic strain" energy that has been accumulated in the form of seismic waves, which travel through the Earth and cause the earth to tremble.
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