a simple motor is powered by a 5.00 v source and consists of a coil rotating in a uniform magnetic field. it is observed that the current in the motor decreases from 165 ma to 45.0 ma as the rotation rate goes from zero to a steady 125 rpm. determine the back emf as the motor turns at 125 rpm.

The frequency of light is 1.18 × 10^15Hz

Wavelength = 255m

The frequency of light is the number of cycles of the light wave that pass a given point in a specified amount of time. Light waves are electromagnetic waves that are characterized by their frequency, which is measured in hertz (Hz).

Calculating the frequency -

f = c/ λ

where c is the speed of light and λ is the wavelength

Thus,

c = 3 × 10^18 m/s

λ = 255 × 1/ 10^9

= 255 × 10^7

Substituting the values in the formula -

= 3 × 10^18 / 255 × 10^7

= 1.18 × 10^15

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Answer:To use these lenses to get the highest power telescopeFo=

Explanation:

The magnifier. Then we need only one lens. The angular exaggeration of the magnifier when the object is put veritably near to the focal point is given by the formula

M =

f

25 cm

where ff is the focal point. thus, the lower the focal length the larger the exaggeration therefore we should elect the lens with the shortest focal length which is the one with

f = 25 mm.

Step 2

2 of 4

{ The microscope.} The microscope. Then we need two lenses. The angular exaggeration of the microscope is given by

L ⋅ 25 cm

thus, lower the product of the focal lengths of the two lenses the larger the exaggeration. thus we should elect the two lenses with the lowest focal lengths i.e. boxed{f_0 = 25

= 25 mm and f

e

= 50 mm.

Step 3

3 of 4

{ The telescope.} The telescope. Then we need two lenses. The angular exaggeration of the telescope is given by

M = - frac{f_0}{f_e}

M = −

f

e

f

0

i.e. it's directly commensurable to the focal length of the objective lens and equally commensurable to the focal length of the eye piece lens. thus we should elect the objective lens with the loftiest possible focal length and the eyepiece lens with the lowest possible focal length

The average rate of change in concentration is calculated to be 0.00404 M/s.

Average rate of change is described as (change in concentration)/(change in time).

Given the concentrations of the reactant (A), we may first determine the average change in A.

Change in A = 0.14 - 0.395 = -0.51 M

Average rate = -0.51 M/252 s = -0.00202 M/s

The negative sign indicates the decreasing [A] over time.

The stoichiometry of the equation, which states that two Bs are produced for every A utilised, is used to determine the average rate of change of B.

So, average rate of change of B is 2 × 0.00202 = 0.00404 M/s

The question is incomplete. The complete question is 'A → 2B

Time(s)      Concentration of A (M)

0.                0.65

126.             0.395

252.            0.140'

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Th electric field at a point between 2 points is given by E =   [tex]\frac{4kQax}{(a^2 - x^2)^2}[/tex] (-i^)

Formula for electric field at a point on x-axis is given by:

E = [tex]\frac{kq}{r^2}[/tex]  ----(i)

where k is constant, q is magnitude of charge and r is the distance from charge where electric field is to be found.

   Q (-a,0)____________________(x,0)_____________________Q(a,0)

so we have to fing electric field at point (x,0) due to the both charges shown in the figure.

due to point charge at pont (-a,0) the electric field is in the positive x direction and due to charge at point (a,0) the electric field is in negative x direction.

let [tex]E_1[/tex] be the electric field due to charge at point (-a,0)

let [tex]E_2[/tex] be the electric field due to charge at point (a,0)

[tex]E_1[/tex] = [tex]\frac{kQ}{(a+x)^2}[/tex] (i^)

where i^ is unit vector along x- axis

[tex]E_2[/tex] = [tex]\frac{kQ}{(a-x)^2}[/tex] (-i^)

[tex]E_1+E_2 = \frac{kQ}{(x+a)^2}[/tex] i^  [tex]+ \frac{kQ}{(a-x)^2}[/tex] (-i^)

=>   [tex]\frac{-4kQax}{(a^2-x^2)^2}[/tex] i^

so [tex]E_1 + E_2 =[/tex] [tex]\frac{4kQax}{(a^2 - x^2)^2}[/tex] (-i^)

so for any point a < x < a .

Th electric field is given by E =   [tex]\frac{4kQax}{(a^2 - x^2)^2}[/tex] (-i^)

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She draws her arms close to her body, which causes her moment of inertia to fall by half. She moves at an angle that is faster by a factor of A. 2B. 1C. 4D. L=Iω

L=Iω

L is a constant that is inversely proportional to the rotational inertia and the angular speed due to the conservation of angular momentum.

Whenever "I" falls, rises proportionately (inversely related) A - Unless you meant increased, which you didn't, Part B is asking the same thing. B would follow from that. If not, Part C proceeds as in Part A: That key equation indicates that they are inversely proportional. In terms of, we solve for ω

I=L/ω

The moment of inertia of a rigid body, also known as the mass moment of inertia, angular mass, second moment of mass, or more precisely, rotational inertia, is a property that establishes the torque required for the desired angular acceleration about a rotational axis, much like mass establishes the force required for the desired acceleration. Depending on the axis selected and the distribution of the body's mass, it may take more torque to modify the body's rate of rotation for bigger moments.

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The potential (in v) of the power supply 6 Volt.

Calculation :

The energy formula ,

H = VIT

Where,

H=energy dissipated the lamp

I=current through the lamp

V = potential difference

t=time during which the current flows through the lamp

From the question we have,

Current(I)=0.3A

The Energy supplied(E)=216 j

Time during which the current flows(t)=2 minutes=2×60 seconds

H = VIT  

216 j = v * 0.3 A *120 sec

V = 216/( 0.3 A *120 sec)

V = 6 Volt

Scientists define energy as the ability to do work. Modern civilization is possible because humans have learned to convert energy from one form to another and use it for work.

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AutoLFADS is a framework for large-scale neural network training for generalised estimate of single-trial population dynamics.

What is neural network ?

Deep learning techniques are based on neural networks, sometimes referred to as artificial neural networks (ANNs) or simulated neural networks (SNNs), which are a subset of machine learning. Their structure and nomenclature are modelled after the human brain, mirroring the communication between organic neurons.

Deep neural network of population dynamics models require considerable hyperparameter adjustment for each dataset to function at the cutting edge. Without using behavioural or task information, AutoLFADS is a model-tuning framework that generates high-performing autoencoding models automatically using data from a range of brain regions and activities.

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A spectrum of seven colors ( red, orange, yellow, green, blue, indigo, and violet) is created when white light travels through a glass prism and is dispersed.

When white light travels through a prism, dispersion is the breaking of the light into its individual colors. The seven colors that make up the spectrum are produced. White light experiences varying degrees of color bending when it passes through a prism.

The longest wavelength and least bending color are red, yet violet bends the most. A red light would therefore be at the apex of the created spectrum, violet would be at the bottom, and the remaining hues or colors would be in between.

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The masses accelerate at a speed of 3g13 m/s2 after being released from rest.

m1 is 2 kilogram, while m2 is 5 kg. Because the pulley has no friction and no mass, the tension force on both sides of the string will be the same. [An inactive state for the Law of Motion] Both masses accelerate at the same rate. Let's say it is a m/s2.

Remember that 2 kg of mass is flowing downhill while 5 kg of mass is traveling upward, or the opposite is true.

Let's begin writing equations.

m1 g - T = m1a for a mass of 2 kg.

2g - T = 2a ————— (I) For a mass of 5 kg, T - m2g = m2a

T - 5g = 5a ————— (II) By combining the two equations, we arrive at 2g - 5g = 13a a = 3g13 m/s2.

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Type of separation methods described in the recipe  are: A. decantation and screening.

Process for the separation of mixtures of immiscible liquids or of a liquid and a solid mixture such as a suspension is called decantation. In this process, the precipitated liquid is separated from solid. According to the given instruction for the recipe, fat which is in liquid state is separated from the meat.

Practice of taking granulated ore material and separating it into multiple grades by particle size is called screening. In the process of screening, more liquid is separated by placing mixture on the screen. In this, gravity plays an important role for the process of separation.

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Note: The question given on the portal is incomplete. Here is the complete question.

Question: A recipe gives the instructions below

After browning the meat pour off fat from the pan to further reduce fat use a strainer.

what type of separation methods are described in the recipe

A decantation and screening

B distillation and screening

C decantation and centrifugation

D distillation and filtration

A mass m object travels along a circular path with a radius r at a constant speed v. The object is subjected to a net force of f. The mass stays unchanged if the object's acceleration is cut in half.

An item moving in a circle at a consistent speed is known as uniform circular motion. An object constantly changes its direction as it moves in a circle. The object is always traveling tangent to the circle.

Given that an object experiences centripetal force as it moves in a circular motion.

So, Force (f) is = mv2/r, where m is an object's mass, v is its speed, and r is its path's radius.

In this case, centripetal acceleration is equal to (ac) = v2/r.

Given that when acceleration is halved:

ac' = ac/2 = v^2/2r

There is no effect on mass as it will remain constant throughout the circular motion of the object but net force will be effected.

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The speeds and the direction of each after the collision:

The proton = -1.692 x 10⁷m/s to the left.

The carbon = 0.3076 x 10⁷ m/s to the right.

If there are two object each with masses m₁ and m₂ move with speed v₁ and v₂, then the two objects collide, so after colliding the speed of each object becomes v₁’ and v₂'.

Since there are no external forces acting on the system, then the momentum of the system is conserved, meaning the momentum before and after the same collision.

The equation is:

(m₁)(v₁) + (m₂)(v₂) = (m₁v₁)' + (m₂v₂)'

We have,

velocity of the proton = 2.0 x 10⁷ m/s ⇒ v₁

Mass of the proton = m₁

The velocity of a carbon atom = 0 ⇒ v₂  

The mass of the carbon atom = 12 m₁

So, the speeds of proton after the collision:

(m₁)(v₁) + (m₂)(v₂) = (m₁v₁)' + (m₂v₂)'

v₁’ = (m₁ - m₂) / (m₁ + m₂) (v₁)

= (m₁ - 12m₁) / (m₁ + 12m₁) (2.0 x 10⁷)

= (-11 m₁) / (13m₁) (2.0 x 10⁷)

= -1.692 x 10⁷m/s ⇒ it's negative, so to the left.

Now, the speed of the carbon atom after collision:

V₂’ = (2m₁) / (m₁ + m₂)v₁

= 2/13 (2 x 10⁷)

=  0.3076 x 10⁷ m/s ⇒ it's positive, so to the right.

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a) The index of refraction for Jell-O is  1.027.

b) The angle of refraction is 38.28°.

The index of refraction measures how a light beam bends when it travels through different media. The refractive index n is defined as the ratio of the sine of the angle of incidence to the sine of the angle of refraction.

if i is the angle of incidence of a ray in vacuum (angle between the incoming ray and the perpendicular to the surface of a medium, known as the normal), and r is the angle of refraction (angle between the ray in the medium and the normal). Then:

[tex]n = \frac{sini}{sinr}[/tex]

a)   the index of refraction for Jell-O is = speed of light in air/speed of the light in the medium

=   3.00x 10^8 m/s /2.92 x 10^8 m/s

= 1.027

b) the angle of refraction is = sin⁻¹(1.027sin37.1°)

= 38.28°

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The true statement of the magnitudes of tensions T₁, T2, and T3 in the

ropes in the diagram shown is the sum of the y-components of T₁ and

T₂ is equal to 20 N.

Option C is correct.

Tension is described as the pulling force transmitted axially by the means of a string, a rope, chain, or similar object, or by each end of a rod, truss member, or similar three-dimensional object.

Tension might also be described as the action-reaction pair of forces acting at each end of said elements.

We know that the block remains in equilibrium, so the forces must balance themselves in each direction at all points.

Consider the forces acting at the intersection of the three strings.

Here T3 =W=20N

The forces at the point must balance in vertical direction.

Therefore T3= Sum of y-components of T1 and T2 =20N

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42 Hz is the frequency of a photon that is emitted when the dipole moment of a proton flips in a magnetic field of 2.1 t, the energy of a photon is related to its frequency by the equation e.

The magnetic influence on moving electric charges, electric currents and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field. The magnetic field of a permanent magnet pulls on ferromagnetic substances like iron and attracts or repels other magnets. Paramagnetism, diamagnetism, and antiferromagnetism are three additional magnetic effects that a nonuniform magnetic field can have on "nonmagnetic" materials, albeit these forces are often so minute that they can only be detected by laboratory equipment. Electric currents, like those utilized in electromagnets, and electric fields that change in time produce magnetic fields that surround magnetized things. Electric charges in motion and the intrinsic magnetic moments of elementary particles, which are connected to their spin, a fundamental quantum feature, create magnetic fields. As parts of the electromagnetic force, one of the four fundamental forces of nature, magnetic and electric fields are interdependent.

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The wavelength of an electromagnetic wave that has a frequency of 1 hertz  more than 1 m.

In a vacuum, electromagnetic waves move at a constant speed of 3.00 x 108 ms-1. Both the magnetic and electric fields have no effect on them. However, they can exhibit diffraction or interference. Any medium, including air, a solid, or a vacuum, can be traversed by an electromagnetic wave. It is not dependent on a medium to spread or move from one location to another. The opposite is true for mechanical waves, which require a medium to propagate (like sound or water waves). Transverse waves are electromagnetic waves. Thus, they are evaluated based on their amplitude (height) and wavelength (distance between the highest and lowest points of two successive waves).

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The highest frequency ultrasound devices have frequencies around 20 mhz. 5 m lambda to 15 m lambda is the wavelength of these sound waves inside the body.

Formula for sound wave = sound wavelength (λ) = sound velocity (v) / Sound frequency (F).

After calculating sound wavelength by the above formula we get the wavelength in between 5 to 15.

A periodic wave's wavelength is its spatial period, or the length over which its shape repeats. It is a property of both traveling waves and standing waves, as well as other spatial wave patterns. It is the distance between two successive corresponding locations of the same phase on the wave, such as two neighboring crests, troughs, or zero crossings.  The spatial frequency is the reciprocal of wavelength. The Greek letter lambda is frequently used to represent wavelength. The term wavelength is also occasionally used to refer to modulated waves, their sinusoidal envelopes, or waves created by the interference of several sinusoids. Wavelength and frequency are inversely related, with shorter wavelengths for higher frequencies and longer wavelengths for lower frequencies, assuming a sinusoidal wave travelling at a constant wave speed. The medium (such as a vacuum, air, or body of water) through which a wave travels determines its wavelength. Waves can be anything from music to light to water to periodic electrical signals in a conductor.

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The impulse of is the product of the average force and the duration it is excreted. The impulse of the net force exerted to the ball during the impact with the floor was 4.28 N-s in magnitude and direction.

The ball weighs 0.500 kg, according to the information provided.

The floor is 1.2 meters high.

The force of impulse

The impulse of is the product of the average force and the duration it is excreted.

One instant before the collision, the velocity is 4.852 meters per second.

One instant after the collision with the floor, the velocity was 3.71 meters per second squared.

The magnitude and direction of the ball's net force impulse during the collision with the floor.

4.28N-s.

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A body of mass 2.64 kg is pushed straight upward by a 32.9 N vertical force, then its acceleration is 2.67m/s^2

Given the mass of body (m) = 2.64kg

Force acting on the body (F) = 32.9N

We know that F = ma where a is the acceleration on the body.

Here when body is thrown upwards acceleration acts upwards along with the force but in the opposite direction the gravitational acceleration acts downwards.

Then Fg force due to gravity is = mg where g is the gravitational acceleration = 9.8m/s^2

Fnet = F - Fg

ma = F- mg

a = 32.9 - (2.64x9.8)/2.64 = 2.66

Hence the acceleration acting on the body is 2.67m/s^2

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The effect is similar to a car colliding with a wall at a velocity  of 50 km/h.

The principle of conservation of linear momentum states that the sum of the initial momentum is equal to sum of the final momentum, provided that the system is Isolated.

Mathematically, the law of conservation of linear momentum is given as;

Pi = Pf

where;

m₁u₁ = m₂u₂

where;

Based on Newton's third law of motion, action and reaction are equal and opposite.

If the car collides with a stationary wall, the wall will exert equal and opposite reaction to the car. If a car hits a wall with a velocity of 50 km/h, the wall will move at a velocity of 50 km/h provided it has equal mass with the car.

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The potential differences is ΔV12=V2−V1=0V

ΔV23=V3−V2=5V

ΔV34=V4−V3= 0V

and ΔV41=V1−V4=-5V

From the figure, there is no connection between the points 1 and 4 . Hence, the potential at the points 4 and 3 is same and is equal to zero.

[tex]\Delta V_{34} & =V_4-V_3 \\& =0[/tex]

Similarly, the potential at the points 1 and 2 is same and is equal to zero.

[tex]\Delta V_{12} & =V_2-V_1 \\& =0[/tex]

The potential difference between the points 4 and 1 is equal to potential difference between the points 3 and 2.

Given that the potential difference across the points 3 and 2 is,

[tex]\Delta V_{23} & =V_3-V_2 \\& =5 \mathrm{~V}[/tex]

The potential difference between the points 4 and 1 is also 5V.

[tex]\Delta V_{41} & =-\Delta V_{23} \quad\left(\because \Delta V_{23}=\Delta V_{14}\right) \\& =-5 \mathrm{~V}[/tex]

Therefore, the required answer is 0,5V, 0,-5V.

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Note:- The correct question could be,

5 V battery with metal wires attached to each end.

The figure shows two wires connected to a battery’s positive and negative terminals. These wires stop short of completing a circuit. Four points are marked on the wires. Point 1 is at the end of the wire connected to the positive terminal. Point 2 is at the negative terminal. Point 3 is at the positive terminal. Point 4 is at the end of the wire connected to the negative terminal.

What are the potential differences ΔV12=V2−V1, ΔV23=V3−V2, ΔV34=V4−V3, and ΔV41=V1−V4?

Enter your answers numerically separated by commas

The group that will make the car travel closest to 5 m/s when it is at the bottom of the first will is of:

Group C.

The velocity that each car will assume at the bottom of the hill is given by the equation presented as follows:

v = square root (2gh + kx²/m).

The parameters are given as follows:

The parameters are given by the table in this problem, hence the velocities of each car are given as follows:

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Answer: group C

Explanation:

Due to the alignment of the earth, moon, and sun, the moon and sun's gravitational pulls work in the same direction, producing the highest high tides and the lowest low tides.

Location in relation to another object is referred to as direction. Relative terminology, such as up, down, out, left, right, forward, backward, or sideways, can be used to express direction by comparing the position of one item to another.

Direction can refer to the way something moves, the way you must go to get somewhere, the way something is beginning to take shape, or the direction you are facing.

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We have to go above 2651 kilometres of the earth for our weight to decrease to half of what it was at the surface.

Geophysics applies the concepts of physics to take a look at the Earth. It deals with things like the motion of the Earth's crust and the temperatures of its interior.

Geology is the scientific study of the earth, including the elements that make it up, the processes that shape it, how it was formed, and information about the planet's past and how it has been ever since. Today, geology also encompasses an examination of distant worlds.

We define the earth via thinking about other people as our enemies, outsiders and foreigners; by dividing our earth into international locations and by developing enmity in opposition to any other institution of people.

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Answer:

32 A.

Explanation:

In a transformer, the ratio of the voltage across the primary coil to the voltage across the secondary coil is equal to the ratio of the current in the primary coil to the current in the secondary coil. This relationship is known as the transformer equation, and it can be written as follows:

Vp / Vs = Is / Ip

Where Vp is the voltage across the primary coil, Vs is the voltage across the secondary coil, Is is the current in the secondary coil, and Ip is the current in the primary coil.

Given the values provided in the problem, we can substitute them into the transformer equation to find the current in the primary coil:

Ip = (Vp * Is) / Vs

= (132 kV * 8 A) / 33 kV

= 32 A

Therefore, the current in the primary coil of the transformer is 32 A.

The tennis ball is 2.15 metre above the court.

The tennis ball departs from the racket horizontally with a speed of 29m/s and it hits the court at a horizontal distance of 19.3 m from the racket.

The vertical height of the tennis ball before it leave the racket can be found by using the relation,

R = V√(2H/g)

Where,

R is the horizontal range,

V is the initial speed of the tennis ball,

H is the vertical height of the tennis ball from the court,

g is the gravitational acceleration.

Putting all the values,

We get,

19.3 = 29√(2H/9.8)

H = 2.15 m.

So, the height of the tennis ball is 2.15m

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The distance from the hole must be 2.244 × 10⁻²⁷ m to detect a 1.0 cm diameter spread in the beam of pellets.

Given that,

Mass of the pellet m = 2 g

Speed of the pellet v = 120 m/s

Diameter of the hole d = 1.5 mm = 1.5 × 10⁻³ m

Distance between the pellet and the hole D = 1 cm = 1 × 10⁻² m

Let us find the wavelength,

λ = h/mv = (6.626 × 10⁻³⁶)/(2 × 120) = 2.76 × 10⁻³³ m

So, y = (1.22 λD)/d = (1.22 × 2.76 × 10⁻³³ × 1 × 10⁻²)/(1.5 × 10⁻³) = 2.244 × 10⁻²⁷ m

Thus, the distance from the hole must be 2.244 × 10⁻²⁷ m to detect a 1.0 cm diameter spread in the beam of pellets.

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The gravitational force exerted on the moon of mass 1×10²² kg  is 1×10¹⁹ N. And the right option is b. 1×10¹⁹ N

Gravitational force is the most prevalent force in the universe, pulling together on any two objects with mass in the universe.

To calculate the gravitational force exerted on the moon, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the gravitational force exerted on the moon is 1×10¹⁹ N.

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