a satellite with a mass of 100kg fires it’s engines to increase velocity, thereby increasing the size of its orbit around the earth. as a result it moves from a circular orbit if radius 7.5x10^6 m to an orbit of radius 7.7x10^6 m. what is the approximate change in gravitational force from the earth as a result of this change in the satellites orbit?

Answers

Answer 1

The approximate change in gravitational force from Earth as a result of the change in radius of the satellite's orbit is -95.07N

What is the universal law of gravitation?

The universal law of gravitation states that the particle of matter in the universe attracts another particle with a force directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

It is written thus;

F = G [tex]M_1M_2[/tex]÷ [tex]r^2[/tex]

Where

F = Gravitational force

G = Gravitational constant

[tex]M_1[/tex] and [tex]M_2[/tex] are the masses of the object

r = radius

How to calculate the gravitational force

Formula:

F = G [tex]M_1M_2[/tex]÷ [tex]r^2[/tex]

Given [tex]M_1[/tex] = 100kg

[tex]M_2[/tex] = 5.97 x[tex]10^{24}[/tex] kg

r = 7.5 x [tex]10^6[/tex] m

G =  6.67 x [tex]10^{-11}[/tex] N-m²/kg²

For the first orbit, substitute the values

F = 6.67 x [tex]10^{-11}[/tex]× 150 ×  5.97 x [tex]10^{24}[/tex] ÷ (7.5 x[tex]10^6[/tex])[tex]^2[/tex]

F = 5.95 × [tex]10^{16}[/tex] ÷ 56.25 × [tex]10^{12}[/tex]=  105.77 N

For the second orbit of radius 7.7 x 10^6 m

F =  6.67 x [tex]10^{-11}[/tex] × 100 ×  5.97 x [tex]10^{24}[/tex] ÷ (7.7 x [tex]10^6[/tex])2

F = 5.95 × [tex]10^{16}[/tex]÷ 59.25 × [tex]10^{12}[/tex] = 200. 84 N

The approximate change = 105. 77 - 200. 84 = -95.07N

Hence, the approximate change in gravitational force from Earth as a result of the change in radius of the satellite's orbit is -95.07N

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Related Questions

If the number is not a proper coefficient, how would you make it one?

Answers

i’m pretty sure you add, multiply, subtract, & divide

g at constant temperature, a sample of helium at 2 atm in a closed container was compressed from 5.00 L to 3.00 L. what was the new pressure exerted by the helium on its container

Answers

The new pressure exerted by helium on its container is 2533.33 torr.

Boyle's law: For a fixed amount of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional. so PV= constant.

At constant temperature and moles,

P1V1 = P2V2.

The original sample is at 2atm torr and volume 5.00 L and then helium gas was compressed to 3.00 L

∴ P₁V₁ = P₂V₂

 (2× 760 torr)(5.00 L ) = (3.00 L )(x torr),

 x = 2533.33 torr.

 P₂ = 2533.33 torr.

Therefore, the new pressure exerted by helium on its container is 2533.33 torr.

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What is the concentration of ammonia in a solution if 24.4 mL of a 0.117 M solution of HCl are needed to titrate a 100.0 mL sample of the solution

Answers

Answer: The concentration of ammonia is 0.0286M.

Explanation:

The diluted equation is presented as: [tex]M_{s} V_{s} =M_{d} V_{d}[/tex].

~M= Molarity (labeled as M)

~V= Volume (labeled in L)

~s= stock solution (what you started with)

~d= diluted solution (what you now have)

Now that we have our definitions, we can knowingly plug the information into the formula shown above.

[tex]0.117M*24.4mL=M_{d} *100mL[/tex]

We have the information plugged in, but the volume must be measured into liters, not milliliters. We can fix that by converting it. To convert milliliters to liters, you divide the milliliters by 1000.

[tex]24.4mL/1000=0.0244L[/tex]     [tex]100mL/1000=0.1L[/tex]

Now that the volumes are in liters, let's plug that into the equation.

[tex]0.117M*0.0244L=M_{d} *0.1L[/tex]

We are now ready to solve the concentration with this equation!

[tex]M_{d} =\frac{0.117M*0.0244L}{0.1L}[/tex]      [tex]M_{d} =0.0286M[/tex]

With all of the steps shown above, we can conclude that the new concentration of ammonia is 0.0286M.

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For the reaction, Cl2(g)+3F2(g)→2ClF3(g) , determine the rate of change of ClF3 if the concentration of F2 decreases from 0.950 M to 0.865 M over 15 seconds.

Answers

3.73 x[tex]10^{-3}[/tex] the rate of change of [tex]ClF_3[/tex] if the concentration of [tex]F_2[/tex]decreases from 0.950 M to 0.865 M over 15 seconds.

What is the rate of change?

The rate of change is used to mathematically describe the percentage change in value over a defined period of time, and it represents the momentum of a variable.

[tex]Cl_2(g)+3F_2(g)[/tex]→[tex]2ClF_3(g)[/tex]

Rate of change of [tex]F_2[/tex] = [tex]\frac{Change \;in \;concemtration}{Time}[/tex]

Rate of change of[tex]F_2[/tex] = [tex]\frac{0.950 M-0.865 M}{15 seconds}[/tex]

Rate of change of [tex]F_2[/tex] = 5.6 x [tex]10^{-3}[/tex]

[tex]\frac{Rate of change of F_2}{3}[/tex] =[tex]\frac{Rate \;of c\;hange \;of\;ClF_3}{2}[/tex]

[tex]\frac{5.6 X 10^{-3}}{3}[/tex]=[tex]\frac{Rate \;of \;change \;of \;ClF_3}{2}[/tex]

Rate of change of [tex]ClF_3[/tex] =1.866666667 x2 x[tex]10^{-3}[/tex]

Rate of change of [tex]ClF_3[/tex]= 3.73 x [tex]10^{-3}[/tex]

Hence, 3.73 x[tex]10^{-3}[/tex] the rate of change of [tex]ClF_3[/tex] if the concentration of [tex]F_2[/tex]decreases from 0.950 M to 0.865 M over 15 seconds.

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Processed foods often contain large amounts of salt, but it is actually sodium (Na) that causes health concerns. If 6 g of salt (NaCl) should be an adult's daily maximum, what would the daily maximum of just sodium (Na) be? Give your answer in milligrams. (2 points)

Answers

The daily maximum of just sodium (Na) should be = 6000 mg

Calculation of adult daily salt consumption

The adult's daily maximum intake of salt = 6g

The major element of salt that causes health concerns is sodium (Na).

Therefore the quantity of sodium consumed in milligrammes= 6×1000

= 6000 mg

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The r value of the yellow dye = 0.60 the distance moved by the yellow dye = 5.7 cm calculate the distance moved by the solvent

Answers

The distance moved by the solvent is 9.5 cm.

Calculation:

Given,

Rf value of yellow dye = 0.60

Distance moved by yellow distance = 5.7 cm

To calculate,

Distance moved by the solvent =?

We know that the Rf value in chromatography is calculated as:

Rf = distance moved by the solute/ distance moved by the solvent

Putting the given values in the above formula, we get

0.60 = 5.7/ distance moved by solvent

Distance moved by the solvent = 5.7/0.60

Distance moved by solvent = 9.5 cm

What is the Rf value?

The ratio of the analyte's (solute) distance traveled to the solvent front on a chromatogram is known as the retention factor (Rf) value.

When using mobile solvents, analytes move differently depending on the type of chromatographic procedure used to transfer them to the stationary phases. The differences between analytes' affinity for stationary and mobile solvents are what cause this difference. The longer an analyte is in place, the lower its Rf value will be, and vice versa, depending on its relative affinity with a stationary phase.

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Explai how you would find out that carbondioxide and watervapor are formed when acandleburns.

Answers

Candle wax is made up of several hydrocarbons with the general formula [tex](CH_2)_n[/tex] , where n is a large number.

Hydrocarbon's on reaction with oxygen forms carbon-dioxide and water vapor. This is called combustion reaction.

                                   [tex](CH_2)_n + O_2 \rightarrow CO_2 + H_2O[/tex]

To find out that carbon-dioxide and water vapor are formed when a candle burns -With duct tape, you can secure the candle to the bowl's base.Water should be added to the bowl until it reaches the candle's top. Don't let the wick become submerged, please!Now you can cover the bowl with transparent lid.

After few minutes, you will observe that the transparent lid is now opaque and there are traces of water deposited on the surface of lid.

Conclusion -  the lid is opaque due to the carbon-dioxide formed and water vapors are condensed on the surface of lid.

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A thin sample of X is put between metal plates. A radio-frequency electric current is applied to the plates and passes through the sample. From the measured voltage across the plates the value of E may be calculated.
Is this a physical or chemical property ?

Answers

The value of E determined as shown in the question is a chemical property.

What are chemical property?

A chemical property has to do with the chemical changes that occur in a substance. Now we know that The value E refers to how easily a substance could accept or loose electrons.

Thus, the value of E determined as shown in the question is a chemical property.

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How many individual oxygen atoms are contained in a sample of P2O5 that also
contains 0.620 moles of P? (Input your answer with scientific notation using "e-
notation and report your answer to two places past the decimal point. Moodle is
looking for a number only, no units.)

Answers

Answer:

Explanation:

Equation with given

P2O5      ====> 2P^5 + 5O-2

                          0.620     x

Solution

What you are going to do first is find the molar amount of oxygen. Use a proportion to do this

2/0.620 = 5/x                    Cross Multiply

2x = 0.620 * 5                   Divide both sides by 2

2x/2 = 0.620 *5/2

x = 0.310 * 5                      Combine

x = 1.55                              moles of oxygen.

Now comes the answer. How many atoms are there in 1.55 moles of oxygen?

1 mole of anything contains 6.02 * 10^23 items of  that mole

1.55 moles of oxygen contains x  atoms of oxygen

1/1.55 = 6.02 * 10^23 / x                  Cross multiply

1*x = 1.55 * 6.02*10^23                    Combine

x = 9.331 e 23

Answer

9.33e23

The compound iron oxide can exist with either iron(II) ions or iron(III) ions. Conduct Internet research to learn about the differences between iron(II) oxide and iron(III) oxide. Give the chemical formula for each compound. Describe their appearance and uses. Based on your findings, are these two forms of the same compound, or are they two completely different compounds?

Answers

answer

Please add answer choice

Explanation:

Answer:

Explanation:

.........................................................      

in diamond carbon atoms are bonded together by extended covalent bonds? what type of solid is diamond?

Answers

Diamond is a network solid.

In diamond, carbon atoms are bonded together by extended covalent bonds. Each carbon atom forms four strong covalent bonds with its neighboring carbon atoms, creating a three-dimensional network of carbon-carbon bonds throughout the crystal lattice.

Diamond is a type of solid known as a covalent network solid. In covalent network solids, the atoms are held together by a network of strong covalent bonds, extending throughout the entire crystal structure. This results in a very rigid and hard material with high melting and boiling points.

Other examples of covalent network solids include graphite and quartz. Due to its strong and interconnected carbon-carbon bonds, diamond is renowned for its exceptional hardness and is one of the hardest known naturally occurring materials.

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A 8.06 g piece of solid CO2 is allowed to sublime in a balloon. The final volume of the balloon is 1.00 L at 300.0 K. What is the pressure of the gas

Answers

Answer: The pressure of the gas is 4.4334atm.

Explanation:

The ideal gas law for pressure is shown as: [tex]P=\frac{nRT}{V}[/tex].

~n=number of moles (mol)

~R=ideal gas constant=[tex]0.0821\frac{L*atm}{mol*K}[/tex]

~T=temperature (K)

~V= volume (L)

We are not given the number of moles, but we can find that with the grams of CO₂ that we were given. This is also better because we have the compound as well, making it easier to find its molar mass on the periodic table.

[tex]8.06gCO_{2} *\frac{1molCO_{2} }{44.009gCO_{2} }=0.18molCO_{2}[/tex]

Now we are ready to plug our given information into the formula for the ideal gas law of pressure.

[tex]P=\frac{0.18mol*0.0821\frac{L*atm}{mol*K}*300K }{1.00L}[/tex]     [tex]P=4.4334atm[/tex]

Given the work above, the pressure of the gas is 4.4334 atmospheres.

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A Calorie unit used in food is equal to the amount of energy necessary to raise the temperature of 1 kilogram of water ________ degrees) Celsius.

Answers

A Calorie unit used in food is equal to the amount of energy necessary to raise the temperature of 1 kilogram of water by 1 degrees Celsius.

What is One Calorie ?

The amount of heat energy required to raise the temperature by 1 gram of water through 1°C is known as One Calorie.

1 Calorie = 4.18 J

Thus from the above conclusion we can say that A Calorie unit used in food is equal to the amount of energy necessary to raise the temperature of 1 kilogram of water by 1 degrees Celsius.

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An empty plastic or glass dish being removed from a microwave oven can be cool to the touch, even when food on an adjoining dish is hot. How is this phenom- enon possible?

Answers

Answer:

See explanation

Explanation:

Microwaves work by flipping water molecules upside down, then right side up again, and so on at very high speeds, and the friction generates heat. Some glass or plastic isn't affected by the microwaves, so the molecules don't get flipped, and so no friction occurs and no heat is produced, leading to the dish not being heated up.

What is the strongest type of intermolecular force between solute and solvent in each solution? (a) CH3OCH3(g) in H2O(l)

Answers

The strongest type of intermolecular force between solute and solvent in CH3OCH3(g) in H2O(l) is H-bond and ion-induced dipole.

What is H-bond?

Hydrogen bonding is a special type of dipole-dipole attraction between molecules, not a covalent bond to a hydrogen atom.

It comes about as a result of the attraction between a hydrogen atom that is covalently attached to a very electronegative atom, like an N, O, or F atom, and another extremely electronegative atom.

Hydrogen is covalently joined to the more electronegative oxygen atom in water molecules (H2O). Therefore, the dipole-dipole interactions between the hydrogen atom of one water molecule and the oxygen atom of another H2O molecule are what cause hydrogen bonding to form in water molecules.

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There are several ways to model a compound. One type of model is shown.

4 C's are connected in a line by 3 black lines. The C on the left has 3 H's attached to it each by a black line. The next C has 1 H attached by a black line and 1 O attached by 2 black lines. The next C has 2 H's attached to it by 1 black line each. The last C has 2 H's attached to it by 1 black line each and 1 O attached by a single black line. That O has an H attached to it by 1 black line.
What is the chemical formula for the molecule represented by the model?

CHO
C4H9O2
C4H8O
C3H8O2

Answers

The chemical formula will be  [tex]C_4H_9O_2[/tex].

Chemical formula

From the model, there are a total of 4 carbon atoms, 9 hydrogen atoms, and 2 oxygen atoms.

All the atoms are bonded to each other accordingly.

Thus, the only plausible chemical formula for the compound is [tex]C_4H_9O_2[/tex]

All other available options fall short in one way or the other as far as the number of atoms of each element in the compound is concerned.

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why do metals tend to lose electrons to form positive ions?

Answers

Answer:

metals tend to lose electrons to form positive ions because they have more protons than electrons.

Help! Help ASAP!

Using bonding principles, describe why AlCl3 forms an ionic bond

Answers

if you look at AIF3 and AICI3, the F ion is smaller than a CI ion. that’s why AICI3 will make a covalent bond while AIF3 will make a ionic bond. explanation: AICI3 doesn’t have a complete transfer of electrons between the metal and the non-metal.

Simple

Look at Electronic configuration of Al

[Ne]3s²3p¹

It has valency as 3

So it can make 3 bonds

Chlorine has well known valency 1

So

Aluminium does bonding with 3 chlorine atoms

There is another reason

That's electronegativity

Chlorine is most electronegative elementAluminium has low electronegativity

As difference in electronegativity is higher they forms ionic bond

Calculate the pH of a solution that is 0.175M benzoic acid and 0.190M sodium benzoate, a salt whose anion is the conjugate base of benzoic acid.

Answers

4.235 is the pH of a solution that is 0.175M benzoic acid and 0.190M sodium benzoate, a salt whose anion is the conjugate base of benzoic acid.

What is Henderson Hasslbalch Equation ?

According to Henderson Hasslbalch Equation to calculate the pH of a solution is expressed as

[tex]pH = pK_{a} + \log \frac{[\text{Congujate base}]}{[\text{Weak acid}]}[/tex]

Benzoic acid (C₆H₅COOH) and its conjugate base is Benzoate (C₆H₅COO⁻) are considered as acidic buffer.    

Kₐ for benzoic acid = 6.3 × 10⁻⁵

So, pKₐ = -log Kₐ

             = - log [6.3 × 10⁻⁵]

             = 4.2

Now put the value in above expression we get

[tex]pH = pK_{a} + \log \frac{[\text{Congujate base}]}{[\text{Weak acid}]}[/tex]

[tex]pH = pK_{a} + \log \frac{C_6H_5COONa}{C_6H_5COOH}[/tex]

     [tex]= 4.2 + \log \frac{0.190}{0.175}[/tex]

     = 4.2 + 0.035

     = 4.235

Thus from the above conclusion we can say that 4.235 is the pH of a solution that is 0.175M benzoic acid and 0.190M sodium benzoate, a salt whose anion is the conjugate base of benzoic acid.

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The pressure in car tires is often measured in pounds per square inch (lb/in.2), with the recommended pressure being in the range of 25 to 45 lb/in.2. Suppose a tire has a pressure of 38.5lb/in.2 . Convert 38.5lb/in.2 to its equivalent in atmospheres.
Express the pressure numerically in atmospheres.
38.5lb/in.2 = atm

Answers

Answer:

2.62 atm

Explanation:

1 atm = 14.6959 psi

38.5 / 14.6959 = 2.62 atm

In the bohr model of the hydrogen atom, the energy required to excite an electron from n = 2 to n = 3 is _______________ the energy required to excite an electron from n = 3 to n = 4?

Answers

In the bohr model of the hydrogen atom, the energy required to excite an electron from n = 2 to n = 3 is greater than the energy required to excite an electron from n = 3 to n = 4

Bohr's energy levels:

The essential concept of Bohr's atomic model is that electrons occupy specified orbitals that call for the electron to have a certain amount of energy. An electron needs to be in one of the permitted orbitals and have the correct amount of energy needed for that orbit in order to be in the electron cloud of an atom. An electron would require less energy to orbit near the nucleus, while an electron would need more energy to orbit away from the nucleus. Energy levels are the potential orbits. One of Bohr's models' flaws was that he was unable to explain why just specific energy levels or orbits were permitted.

It is evident that the energy required to escape an electron from n=2 to n=3 is greater than the energy required to exit an electron from n=3 to n=4. This is because as n increases, the energy levels move closer to one another.

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Calculate the work (KJ) done during a reaction in which the internal volume contracts from 83 L to 13 L against an outside pressure of 4.4 atm.

Answers

-31.2 kJ is the work  done during a reaction in which the internal volume contracts from 83 L to 13 L against an outside pressure of 4.4 atm.

How to calculate the work done on or by a gas ?

It is represented by the equation

W = PΔV

where,

W = Work done

P = Pressure

ΔV = Change in volume (V₂ - V₁)

Now put the values in above formula we get

W = PΔV

    = 4.4 atm × (13 L - 83 L)

    = 4.4 atm × (-70 L)

    = -308 atm L

Now change L atm into J

= -308 × 101.3 J     [L × atm = 101.3 J]

= -31200.4 J

= -31200.4 × 10⁻³ kJ

= -31.2 kJ

Thus from the above conclusion we can say that -31.2 kJ is the work  done during a reaction in which the internal volume contracts from 83 L to 13 L against an outside pressure of 4.4 atm.

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A 2.65 g sample of a salmon colored powder contains 0.70 g of chromium, 0.65 g of sulfur, and 1.30 g of oxygen. The molar mass is 392.2. What is the formula of the compound

Answers

The molecular formula of the compound is [tex]Cr_{2}S_{3}O_{12}[/tex].

Given:

Mass of Cr = 0.70 g

Mass of S = 0.65 g

Mass of O = 1.30 g

Molecular mass = 392.2 g

Moles of Cr = [tex]\frac{0.70}{52.0}[/tex]

                  = 0.01346 mol

Moles of S = [tex]\frac{0.65}{32.06}[/tex]

                  = 0.02025 mol

Moles of O = [tex]\frac{1.30}{16.0}[/tex]

                   = 0.08125 mol

Dividing both sides with lower quantity ;

[tex]Cr_{\frac{0.01346}{0.01346} } S_{\frac{0.2025}{0.01346} } O _{\frac{0.08125}{0.01346} }[/tex]≅ [tex]CS_{1.5} O_{6}[/tex]

And [tex](empirical formula )_{n} = molecular formula[/tex]

                        392.2 = n (52.0 + 6 × 16.0)

                                  n = 2

Therefore, the molecular formula of the compound is [tex]Cr_{2}S_{3}O_{12}[/tex].

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Molecular and empirical formulas

Answers

Answer:

See below

Explanation:

Molecular formula  ( just write down all of the elements )   C 4 H4 O4

Empiracle formual    CHO

"Molecular formulas tell you how many atoms of each element are in a compound, and empirical formulas tell you the simplest or most reduced ratio of elements in a compound"

A container contains a mixture of neon and argon gases at a uniform temperature. The argon gas has a rms speed of 1.20 km/s. How many Kelvin would the temperature need to change in order for the neon gas to be 39.0% faster than the rms speed of the argon

Answers

55.44 K is the temperature that need to change in order for the neon gas to be 39.0% faster than the RMS speed of the argon.

Given

RMS speed of argon = 1.20 km/sec = 1.20 ×[tex]10^{3}[/tex] m/sec

RMS speed of neon = 39% faster than the speed of argon

                                 = RMS speed of argon + [tex]\frac{39}{100}[/tex] RMS speed of argon

                                 = RMS speed of argon ( 1 +0.39)

RMS speed of neon = 1.39 times of RMS speed of argon

Hence   [tex]\frac{v_{ne} }{v_{ar} } = \frac{1.39}{1}[/tex] … (1)

The atomic mass of argon is 39.95 g/mol = 39.95×[tex]10^{-3}[/tex] Kg/mol

and  the atomic mass of neon is 20.18 g/mol = 20.18 ×[tex]10^{-3}[/tex] Kg/mol

According to the formula of root-mean-square velocities of gas molecules

[tex]v_{rms} = \sqrt{3RT/M}[/tex] where,

[tex]v_{rms}[/tex] = root-mean-square velocity

M = molar mass of gas (in kg per mole)

R = Molar gas constant = 8.314 J/mol/K

T = temperature (in kelvin)

[tex]v_{arg }[/tex] = [tex]\sqrt{3RT_{arg}/M }[/tex]

[tex]v_{arg} ^{2}[/tex] = [tex]3RT_{arg} /M[/tex]

1.20 ×1.20 ×[tex]10^{6\\[/tex] = 3 ×8.314×[tex]T_{arg}[/tex] /39.95 ×[tex]10^{-3}[/tex]

[tex]T_{arg}[/tex] = 1.44 × 39.95 ×[tex]10^{3}[/tex] / 24.942

[tex]T_{arg}[/tex] = 2306.47 K

Now,

RMS velocity is directly proportional to [tex]\sqrt{T}[/tex] and inversely proportional to [tex]\sqrt{M}[/tex]

[tex]v_{rms}[/tex] [tex]\alpha[/tex] [tex]\sqrt{T}[/tex]   and  [tex]v_{rms} \frac{1}{\alpha } \sqrt{M}[/tex]

[tex]\frac{v_{ne} }{v_{ar} }[/tex] =  [tex]\sqrt{\frac{T_{ne} }{T_{ar} } }[/tex]× [tex]\sqrt{\frac{M_{ar} }{M_{ne} } }[/tex]

According to equation 1

[tex]\sqrt{\frac{T_{ne} }{T_{ar} } }[/tex] × [tex]\sqrt{\frac{M_{ar} }{M_{ne} } }[/tex] = 1.39

[tex]T_{ne}[/tex] = 1.39 ×1.39 × 2306.47 × 20.18 / 39.95

[tex]T_{ne}[/tex] = 2251.03K

Change in temp ΔT = 2306.47-2251.03= 55.44 K

Hence, 55.44 K is the temperature that need to change in order for the neon gas to be 39.0% faster than the RMS speed of the argon.

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What scientist first developed an equation to calculate the wavelengths of lines in the emission spectrum of hydrogen atoms?.

Answers

Answer:

Swedish physicist Johannes Rydberg

Explanation:

Six-membered cyclic hemiacetals and five-membered cyclic hemiacetals are called, respectively, ________.

Answers

Answer:

Six-membered cyclic hemiacetals and five-membered cyclic hemiacetals are called, respectively, mannoses and xyloses.

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Magnesium has an HCP crystal structure, a c/a ratio of 1.635, an atomic weight of 24.305 g/mol, and a density of 1.74 g/cm3. Compute the atomic radius for Mg.

Answers

Atomic radius is1.349*10-23

hcp unit cell you can see that that the spheres touch each other along

so 2rMg = a where rMg is the radius of a Mg ion and = 0.6745*10^-23

There are three levels of atoms in the hcp structure.

Six atoms form a hexagonal arrangement in the top and bottom layers, while a seventh atom sits in the centre of the hexagonal arrangement.

Three atoms in the intermediate layer are tucked away in the top and bottom plane's triangular grooves.

Mg hcp c/a = 1.635

hcp is close-packed example ABABAB etc

V = sin(60)*a*a*1.635 a

V = 1.635 *0.866*a^3

V = 1.887*a^3 cm3

Z = 2 (atoms inside unit cell)

Mass inside unit cell is = (2 * 24.305)/(6.022*10^23) = 8.071*10^-23 g

D =M/V

1.74 = 8.071*10^-23/1.887*a^3

a^3 = 8.071*10^-23/1.887*1.74 = 2.458*10^-23

a = 1.349*10^-23

Hence Atomic radius is 1.349*10^-23

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Hana fills a cup with sandy ocean water. She pours the mixture through a filter. What does she collect that passes through the filter?

a sample of pure water
a solution of salt in water
a suspension of sand in water
a colloid of salt in water

Answers

Answer:-
A Solution of salt in Water
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Answer: B) a solution of salt in water

Explanation:

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What term or terms correctly describes the following pair? Look at the picture pls

Answers

Answer:

Different elements

Explanation:

The variable, the bottom number, and the top number all reveal something about each other. The number at the bottom is the element's atomic number, and because both of these pairs have different atomic numbers, they are different elements in general.

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