Answer:
≈ 9613.64 mph
Step-by-step explanation:
First we convert ft/s to ft/hr.
14100 ft/s*3600 = 50,760,000 ft/hr
Now we convert the feet to miles.
50,760,000 ft/hr ÷ 5280 ≈ 9613.64 mph
So in conclusion, 14100 ft/s is approximately 9613.64 mph.
The slope of the line graphed below is undefined. True or false
Answer:
False
Step-by-step explanation:
The slope is 0.
a) 11 pounds, 8 pounds
O Like terms
11 pounds - 8 pounds =
O Not like terms
Answer:
Like terms
Step-by-step explanation:
Both terms have the same unit, which is pounds.
HELP ASAP
What is the perimeter of rectangle MNOP, rounded to the nearest tenth of a meter?
M
60°
N
O
O
28 m
79.2 m
67.6 m
88.1 m
76.5 m
30°
Answer: 76.5 meters
Step-by-step explanation:
To find the side lengths you use trig ratios for 30,60,90 triangles. The ratio is n (attached to the opposite side of the 30-degree angle, or the smallest leg), n[tex]\sqrt{3}[/tex] (attached to the opposite side of the 60-degree angle, or the longest leg), 2n (attached to the hypotenuse). Using the inner triangle you can use 2n=28 to find the side opposite the 30-degree angle, 14. Then you plug 14 into every n and add the sides. the full answer is 76.4974226 but this problem said to round making your final answer 76.5 meters. always remember to give proper units.
12:00,10:00,6:00,4:00. What is the missing time?
Which inequality will have a shaded area below the boundary line?
A.
y – x > 5
B.
2x - 3y ≤ 3
C.
2x – 3y
D.
7x + 2y ≤ 2
E.
3x + 4y > 12
Option c) 2x-3y ≥ 3 is correct inequality which has a shaded area below the boundary line.
Attempting all the equation on the graph to get the solutions
Inequality can be define as the relation of equation contains the symbol of ( ≤, ≥, <, >) instead of equal sign in an equation.
Since, while attempting all the option on graph. The one equation that satisfies the condition is 2x-3y ≥ 3 of having shaded area below the boundary line.
Thus, the option c) 2x-3y ≥ 3 is correct implification on graph which shows the shaded area below the boundary line.
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Calculate the area of this triangle.
[tex] [/tex]
Answer: 30
Step-by-step explanation: Formula for Area of a triangle = 1/2 Base * Height. 12*5 = 60; 60/2 = 30.
Answer:
30 cm squared
Step-by-step explanation:
This is a right angle triangle. That means that the base and height will just be the perpendicular sides of the triangle.
Our base in this case is 12 and our height is 5.
Area of a Triangle = 1/2(base)(height)
=1/2(12)(5)
=1/2(60)
=30
So, the area of this triangle is 30 cm squared.
find the volume, show solution pls
The volume of the square prism shown is 1568 cubic meters
Volume of square prismThe formula for calculating the volume of square prism is expressed as;
V = Base area * height/3
Determine the base are
B = 14 * 14
B = 196 square meters
Determine the height
h = √25² - 7²
h = √625 - 49
h = 24m
Substitute
Volume = 196. * 24/3
Volume = 196 * 8
Volume = 1568 cubic meters
Hence the volume of the square prism shown is 1568 cubic meters
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1) (b + a) = 4; use a = 1 and b = 3
2) c(b + b); use b = 1 and c = 5
3) 4+ pm; use m = 4 and p =3
4) 5+ pm; use m = 4 and p = 2
5) m(p + 2); use m = 5 and p = 2
6) h+j²; use h = 1 and j = 4
7) y-(x - 5); use x = 5 and y = 6
8) 4xy; use x = 5 and y = 2
9) n(p + 3); use n = 2 and p = 2
10) y +x+x; use x = 3 and y=5
11) 6+ a-b; use a = 4 and b = 4
The equations will be solved by putting the values of the variables in the bracket.
How to calculate the values?1. (b + a) = 4; use a = 1 and b = 3
( 1 + 3) = 4
2) c(b + b); use b = 1 and c = 5
5(1 + 1)
= 5 × 2 = 10
3) 4+ pm; use m = 4 and p =3
= 4 + (4 × 3)
= 4 + 12
= 16
4) 5+ pm; use m = 4 and p = 2
= 5 + (2 × 4)
= 5 + 8
= 13
5) m(p + 2); use m = 5 and p = 2
= 5(2 + 2)
= 5 × 4
= 20
6) h+j²; use h = 1 and j = 4
= 1 + 4²
= 17
7) y-(x - 5); use x = 5 and y = 6
= 6 - (5 - 5)
= 6 - 0
= 6
8) 4xy; use x = 5 and y = 2
= 4 × 5 × 2
= 40
9) n(p + 3); use n = 2 and p = 2
= 2(2 + 3)
= 10
10) y +x+x; use x = 3 and y=5
= 5 + 3 + 3
= 11
11) 6+ a-b; use a = 4 and b = 4
= 6 + 4 - 4
= 6
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At the end of January 2003, the population of my town was 11,212. The population of my town increases by 322 every month. In what month does the population of my town first exceed 15,000?
In 11.76 months, the value of the population will be 15000.
We have given that,
At the end of January 2003, the population of my town was 11,212.
the population is increased by 322 every month
So at the end of the second-month population will be 11534.
suppose x represents the year and y represent the population
The population increased by 322 every month
Therefore the value of m =322
[tex](x_1,y_1)=(0,11212)[/tex]
We have m=332
[tex](x_2,y_2)=(x_2,15000)[/tex]
We have to determine the value of the x_2
What is the slope point form of the line?[tex](y_2-y_1)=m(x_2-x_1)[/tex]
[tex]322\left(x_2-0\right)=15000-11212[/tex]
[tex]322\left(x_2-0\right)=3788[/tex]
[tex]\frac{322\left(x_2-0\right)}{322}=\frac{3788}{322}[/tex]
[tex]x_2=\frac{1894}{161}[/tex]
[tex]x_2=11.76[/tex]
Therefore in 11.76 months, the value of the population will be 15000.
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Write the equation of a sine or cosine function to describe the graph.
The question is down below
also I home school and have permission to post this question
Answer:
960
Step-by-step explanation:
(if i made any typos, sorry it is kind of hard to type on computer over writing on paper.)
A=2AB+(a+b+c)h
AB=s(s﹣a)(s﹣b)(s﹣c)
s=(a+b+c)/2
Solving forA
A=ah+bh+ch+1/2 sqrt(﹣a^4+2(ab)^2+2(ac)^2﹣b4+2(bc)^2﹣c^4)=10·12+24·12+26·12+1
2·﹣104+2·(10·24)2+2·(10·26)2﹣244+2·(24·26)2﹣264=960
In the figure, two poles are 25 m and 30 m high. A cable 16 m long joins the tops of the poles. Find the distance between the poles. HELP PLEASE.
Answer:
The distance between the poles is approximately 15.2 m.
Step-by-step explanation:
GivenTwo poles of 25 m and 30 m height,Distance between tops of the poles is 16 m.To findThe distance between the polesSolutionThe distance between the poles is the segment d which connects the top of the shorter pole with the point at 5 m from the top of the longer pole, which is the difference of lengths of poles.
The three points form a right triangle, with hypotenuse of 16 m, and legs 5 m and d.
Use Pythagorean to find the value of d:
[tex]d=\sqrt{16^2-5^2} =\sqrt{256-25} =\sqrt{231} =15.2[/tex] m (rounded)will give brainliest
Answer:
f(x) = x^(1/2) + 3
Step-by-step explanation:
Translating to the right 3 units would change these:
0^(1/2) = 0 /// 3 units to the right would be (0,3)
1^(1/2) = 1 //// 3 units to the right would be (1,4)
4^(1/2) = 2 //// 3 units to the right would be (4,5) etc
Daniel wrote the following two-column proof for the given information.
The information given about the proof does that Daniel made an error on line 2.
How to illustrate the information?Given:
1. AB = 3x +2; BC = 4x + 8; AC = 38
2. AB + BC = AC incorrect (not an angle angle addition postulate)
3. 3x+2 + 4x + 8 = 38 correct
4. 7x + 10 = 38 correct
5. 7x = 28 correct
6. x = 4
Daniel made an error on line 2.
Here is the complete question:
Daniel wrote the following two-column proof for the given information. Given: AB = 3x + 2; BC = 4x + 8; AC = 38 Prove: x = 4 Statements Reason 1. AB = 3x + 2; BC = 4x + 8; AC = 38 1. Given 2. AB + BC = AC 2. Angle Addition Postulate 3. 3x + 2 + 4x + 8 = 38 3. Substitution Property of Equality 4. 7x + 10 = 38 4. Combining Like Terms 5. 7x = 28 5. Subtraction Property of Equality 6. x = 4 6. Division Property of Equality On which line, did Daniel make his error? line 2 line 3 line 4 line 5
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Use the ray tool to graph the function. f(x)=−|x+2|+1
The graph of the function. f(x)=−|x+2|+1 is illustrated.
How to illustrate the function?The given function is f(x)=−|x+2|+1.
We will have to draw the graph of the function.
When x = 1, f(1) will be -2. When x = 2, f(2,) will be -3
The points are illustrated based on the information given and the appropriate graph is illustrated and attached.
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Mr. Chan’s lawn grows 2 1/8 inches every 2 week. He mows his lawn every 2 weeks and cuts off the top 1 3/4 inches of lawn. If Mr. Chan’s lawn was 4 inches tall at the beginning of the season, how many inches tall, in decimal form, is Mr. Chan’s lawn after 8 weeks.
Answer:
5.5 in
Step-by-step explanation:
First we will calculate the total lawn grown after 8 weeks.
Grow Rate = [tex]2\frac{1}{8} in/2 weeks[/tex]
Total lawn grown after 8 weeks = [tex]2\frac{1}{8} *4\\=8.5 in[/tex]
Next we will calculate the total lawn mown after 8 weeks.
Mowing Rate = [tex]1\frac{3}{4} in/2weeks[/tex]
Total lawn mown after 8 weeks = [tex]1\frac{3}{4} *4\\=7 in[/tex]
Lawn Height after 8 weeks = Initial Lawn Height + Total lawn grown - Total lawn mown
= 4 in + 8.5 in - 7 in
= 5.5 in
Wxyz is a dilation image of wxyz. Wich is the correct description of the dilation?
Can a function ever have 2 y-
intercepts?
Answer:
yes I think I'm new to this but I think that's a yes
0.3(8-2x) - 1.2(2-3x) < -21
Answer:
x=-7
Step-by-step explanation:
0.3(8-2x) - 1.2(2-3x) < -21
2.4 - 0.6x - 2.4 + 3.6x < -21
3x < -21
x < -7
Hay 20% mas duendes que magos en el club de magia. Hay 120 duendes en el club de magia.
¿Cuántos magos hay en el club de magia?
Answer:
Hay 600 en el club de magia.
Part E
Christopher Columbus set sail from Spain in 1492. In what year did the Civil War end?
I know he died 1865 but you explain the answer
Bailand Company purchased a building for $148,000 that had an estimated residual value of $8,000 and an estimated service life of 10 years. Bailand purchased the building 4 years ago and has used straight-line depreciation. At the beginning of the fifth year (before it records depreciation expense for the year), the following independent situations occur:
The journal entries relating to the building for the fifth year is: Debit Depreciation expense $10,500; Credit To accumulated depreciation $10,500.
Journal entriesBailand Company
1. Dec 31
Debit Depreciation expense $10,500
Credit Accumulated depreciation $10,500
(Being the depreciation expense recorded)
Book value=$148,000-($148,000-$8,000/10×4)]
Book value=$148,000-$56,000
Book value=$92,000
Depreciation=$92,000-$8,000/8
Depreciation=$10,500
2. Dec 31
Debit Depreciation expense $24,000.00
Credit Accumulated depreciation a/c $24,000.00
[($92,000-$8,000)×6/21]
(Being the depreciation expense recorded)
3. Dec 31
Debit Accumulated depreciation $3,200.00
[($8,000×4)/10]
Credit Retained earnings $3,200.00
(Being prior year adjustment for depreciation expense)
Dec 31
Debit Depreciation expense $10,000.00
Credit Accumulated depreciation $10,000.00
[($148,000-$8,000)/10]
(Being the depreciation expense recorded)
Therefore the journal entries relating to the building for the fifth year is: Debit Depreciation expense $10,500; Credit To accumulated depreciation $10,500.
The complete question is:
Bailand Company purchased a building for $148,000 that had an estimated residual value of $8,000 and an estimated service life of 10 years. Bailand purchased the building 4 years ago and has used straight-line depreciation. At the beginning of the fifth year (before it records depreciation expense for the year), the following independent situations occur:
1. Bailand estimates that the asset has 8 years’ life remaining (for a total of 12 years).
2. Bailand changes to the sum-of-the-years’-digits method.
3. Bailand discovers that the estimated residual value has been ignored in the computation of depreciation expense.
Required: For each of the independent situations, prepare all the journal entries relating to the building for the fifth year. Ignore income taxes.
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Calculate, to four decimal places, the first ten terms of the sequence. an = 1 +(−4/9)^n
The first ten terms of the sequence [tex]a_n=1 + (-\frac{4}{9} )^n[/tex] is 0.5556, 1.1975, 0.9122, 1.039, 0.9827, 1.0077, 0.9966, 1.0015, 0.9993 and 1.0003
What is an equation?An equation is an expression that shows the relationship between two or more variables and numbers.
Given that:
[tex]a_n=1 + (-\frac{4}{9} )^n\\\\When\ n=1:a_1=1 + (-\frac{4}{9} )^1=0.5556\\\\When\ n=2:a_2=1 + (-\frac{4}{9} )^2=1.1975\\\\When\ n=3:a_3=1 + (-\frac{4}{9} )^3=0.9122\\\\When\ n=4:a_4=1 + (-\frac{4}{9} )^4=1.039\\\\When\ n=5:a_5=1 + (-\frac{4}{9} )^5=0.9827\\\\When\ n=6:a_6=1 + (-\frac{4}{9} )^6=1.0077\\\\When\ n=7:a_7=1 + (-\frac{4}{9} )^7=0.9966\\\\When\ n=8:a_8=1 + (-\frac{4}{9} )^8=1.0015\\\\When\ n=9:a_9=1 + (-\frac{4}{9} )^9=0.9993\\\\[/tex]
[tex]When\ n=10:a_{10}=1 + (-\frac{4}{9} )^{10}=1.0003\\[/tex]
The first ten terms of the sequence [tex]a_n=1 + (-\frac{4}{9} )^n[/tex] is 0.5556, 1.1975, 0.9122, 1.039, 0.9827, 1.0077, 0.9966, 1.0015, 0.9993 and 1.0003
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what should be added to 4x²-3x²+1 to make it a perfect square
[tex]im \: guessing \: its \: 4x {}^{2} - 3x + 1 \\ (correct \: me \: if \: im \: wrong)[/tex]
[tex](a - b) {}^{2} = a {}^{2} - 2ab + {b}^{2} [/tex]
[tex]4x {}^{2} = a {}^{2} \: \: \: \: \: \: \: \: \: \: \: b {}^{2} = 1 \\ a = 2x \: \: \: \: \: \: \: \: \: \: \: \: \: \: b = 1[/tex]
[tex](2x - 1) {}^{2} = 4x {}^{2} -4x + 1[/tex]
[tex]we \: need \: to \: add \: a \: - x \\ \: to \: the \: original \: equation[/tex]
Note that this problem can be approached in many ways. For instance, we can add to the b² term instead of changing the middle term...Really confused don’t understand please help me
Answer:
62cm²Step-by-step explanation:
Surface Area Formula
SA = 2lw + 2lh + 2hw
2 * 2 * 5 + 2 * 2 * 3 + 2 * 3 * 5 =
62cm²
Solve for ×:
X/5+3y=-7
Solve 2w2 + 12w + 10 = 0 by completing the square
A)
w = –15, w = 5
B)
w = –5, w = –1
C)
w = –5, w = 1
D)
w = 5, w = 1
The value of w is -1 and -5.
The correct option is (B)
What is equation?
A mathematical statement consisting of an equal symbol between two algebraic expressions that have the same value.
Given:
2w² + 12w + 10 = 0
First, divide through by 2
2w²/2 + 12w /2 + 10/2 =0/2
w² + 6w + 5 = 0
now, Take half of the w term and add - subtract the square of it
w² + 6w + 5 + 3² - 3² = 0
w² + 2*3w + 3² + 5 - 9 = 0
(w+3)² = 4
w+3 = ±2
w = +2 - 3, -2-2
w= -1 and -5.
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Solve for x 3x – 2(3x – 2) = 2(4 – x) + 3
Answer:
x = -7Step-by-step explanation:
First, lets open up the parentheses.
3x - 6x + 4 = 8 - 2x + 3
Combine like terms.
-3x + 4 = 11 - 2x
Add 2x to both sides
-x + 4 = 11
Subtract 4 from both sides
-x + 4 -4 = 11 -4
Simplify
-x = 7
Divide both sides by -1
x = -7
Hope this helps! (:
Answer:
x = -7
Step-by-step explanation:
3x – 2(3x – 2) = 2(4 – x) + 3
The first step is to distribute when solving for x
3x – 6x +4 = 8 – 2x + 3
Then combine like terms
-3x+4=-2x+11
Add 3x to each side
-3x+3x+4=-2x+3x+11
4 = x+11
Subtract 11 from each side
4-11 = x+11-11
-7 = x
A desk is on sale for $123.20, which is 72% less than the regular price.
What is the regular price?
Answer:
170.833
Step-by-step explanation:
we have to find real value which has to be find.
let take it as x,
in the question they said reduction percentage is equal to $123
then x*72/100=$123
x=$123*100/72
x=12300/72
x=170.8333
Answer:
I believe it's 211.90$.
In the diagram below of AACT, BE | AT.
C
F
If CB = 3, CA = 10, and CE = 6, what is the length
of ET?
1)
5
2)
14
3)
20
4)
26
Answer:
14
Step-by-step explanation:
CB/AB = CE/ET
3/7 = 6/ET
ET = 14